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  • How i find the greatest number from six or more digit number?

    - by Rajendra Bhole
    Hi,thanks in advance, I have the code in which i want to find out the greatest number from six numbers, the code as follows, if( (pixels->r == 244 || pixels->g == 242 || pixels->b == 245) || (pixels->r == 236 || pixels->g == 235 || pixels->b == 233) || (pixels->r == 250 || pixels->g == 249 || pixels->b == 247) || (pixels->r == 253 || pixels->g == 251 || pixels->b == 230) || (pixels->r == 253 || pixels->g == 246 || pixels->b == 230) || (pixels->r == 254 || pixels->g == 247 || pixels->b == 229)) { numberOfPixels1++; NSLog( @"Pixel data1 %d", numberOfPixels1); } if( (pixels->r == 250 || pixels->g == 240 || pixels->b == 239) ||(pixels->r == 243 || pixels->g == 234 || pixels->b == 229) || (pixels->r == 244 || pixels->g == 241 || pixels->b == 234) || (pixels->r == 251 || pixels->g == 252 || pixels->b == 244) || (pixels->r == 252 || pixels->g == 248 || pixels->b == 237) || (pixels->r == 254 || pixels->g == 246 || pixels->b == 225)) { numberOfPixels2++; NSLog( @"Pixel data2 %d", numberOfPixels2); } if( (pixels->r == 255 || pixels->g == 249 || pixels->b == 225) ||(pixels->r == 255 || pixels->g == 249 || pixels->b == 225) || (pixels->r == 241 || pixels->g == 231 || pixels->b == 195) || (pixels->r == 239 || pixels->g == 226 || pixels->b == 173) || (pixels->r == 224 || pixels->g == 210 || pixels->b == 147) || (pixels->r == 242 || pixels->g == 226 || pixels->b == 151)) { numberOfPixels3++; NSLog( @"Pixel data3 %d", numberOfPixels3); } if( (pixels->r == 235 || pixels->g == 214 || pixels->b == 159) ||(pixels->r == 235 || pixels->g == 217 || pixels->b == 133) || (pixels->r == 227 || pixels->g == 196 || pixels->b == 103) || (pixels->r == 225 || pixels->g == 193 || pixels->b == 106) || (pixels->r == 223 || pixels->g == 193 || pixels->b == 123) || (pixels->r == 222 || pixels->g == 184 || pixels->b == 119)) { numberOfPixels4++; NSLog( @"Pixel data4 %d", numberOfPixels4); } if( (pixels->r == 199 || pixels->g == 164 || pixels->b == 100) ||(pixels->r == 188 || pixels->g == 151 || pixels->b == 98) || (pixels->r == 156 || pixels->g == 107 || pixels->b == 67) || (pixels->r == 142 || pixels->g == 88 || pixels->b == 62) || (pixels->r == 121 || pixels->g == 77 || pixels->b == 48) || (pixels->r == 100 || pixels->g == 49 || pixels->b == 22)) { numberOfPixels5++; NSLog( @"Pixel data5 %d", numberOfPixels5); } if( (pixels->r == 101 || pixels->g == 48 || pixels->b == 32) ||(pixels->r == 96 || pixels->g == 49 || pixels->b == 33) || (pixels->r == 87 || pixels->g == 50 || pixels->b == 41) || (pixels->r == 64 || pixels->g == 32 || pixels->b == 21) || (pixels->r == 49 || pixels->g == 37 || pixels->b == 41) || (pixels->r == 27 || pixels->g == 28 || pixels->b == 46)) { numberOfPixels6++; NSLog( @"Pixel data6 %d", numberOfPixels6); } I have to find out greatest from numberOfPixels1....numberOfPixels6 from above code. There are any optimum way to find out the greatest number?

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  • CreatePatternBrush and screen color depth

    - by Carlos Alloatti
    I am creating a brush using CreatePatternBrush with a bitmap created with CreateBitmap. The bitmap is 1 pixel wide and 24 pixels tall, I have the RGB value for each pixel, so I create an array of rgbquads and pass that to CreateBitmap. This works fine when the screen color depth is 32bpp, since the bitmap I create is also 32bpp. When the screen color depth is not 32bpp, this fails, and I understand why it does, since I should be creating a compatible bitmap instead. It seems I should use CreateCompatibleBitmap instead, but how do I put the pixel data I have into that bitmap? I have also read about CreateDIBPatternBrushPt, CreateDIBitmap, CreateDIBSection, etc. I don´t understand what is a DIBSection, and find the subject generally confusing. I do understand that I need a bitmap with the same color depth as the screen, but how do I create it having only the 32bpp pixel data?

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  • C++ converting binary(P5) image to ascii(P2) image (.pgm)

    - by tubby
    I am writing a simple program to convert grayscale binary (P5) to grayscale ascii (P2) but am having trouble reading in the binary and converting it to int. #include <iostream> #include <fstream> #include <sstream> using namespace::std; int usage(char* arg) { // exit program cout << arg << ": Error" << endl; return -1; } int main(int argc, char* argv[]) { int rows, cols, size, greylevels; string filetype; // open stream in binary mode ifstream istr(argv[1], ios::in | ios::binary); if(istr.fail()) return usage(argv[1]); // parse header istr >> filetype >> rows >> cols >> greylevels; size = rows * cols; // check data cout << "filetype: " << filetype << endl; cout << "rows: " << rows << endl; cout << "cols: " << cols << endl; cout << "greylevels: " << greylevels << endl; cout << "size: " << size << endl; // parse data values int* data = new int[size]; int fail_tracker = 0; // find which pixel failing on for(int* ptr = data; ptr < data+size; ptr++) { char t_ch; // read in binary char istr.read(&t_ch, sizeof(char)); // convert to integer int t_data = static_cast<int>(t_ch); // check if legal pixel if(t_data < 0 || t_data > greylevels) { cout << "Failed on pixel: " << fail_tracker << endl; cout << "Pixel value: " << t_data << endl; return usage(argv[1]); } // if passes add value to data array *ptr = t_data; fail_tracker++; } // close the stream istr.close(); // write a new P2 binary ascii image ofstream ostr("greyscale_ascii_version.pgm"); // write header ostr << "P2 " << rows << cols << greylevels << endl; // write data int line_ctr = 0; for(int* ptr = data; ptr < data+size; ptr++) { // print pixel value ostr << *ptr << " "; // endl every ~20 pixels for some readability if(++line_ctr % 20 == 0) ostr << endl; } ostr.close(); // clean up delete [] data; return 0; } sample image - Pulled this from an old post. Removed the comment within the image file as I am not worried about this functionality now. When compiled with g++ I get output: $> ./a.out a.pgm filetype: P5 rows: 1024 cols: 768 greylevels: 255 size: 786432 Failed on pixel: 1 Pixel value: -110 a.pgm: Error The image is a little duck and there's no way the pixel value can be -110...where am I going wrong? Thanks.

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  • How i store the images pixels in matrix form?

    - by Rajendra Bhole
    Hi, I developing an application in which the pixelize image i want to be store in matrix format. The code is as follows. struct pixel { //unsigned char r, g, b,a; Byte r, g, b; int count; }; (NSInteger) processImage1: (UIImage*) image { // Allocate a buffer big enough to hold all the pixels struct pixel* pixels = (struct pixel*) calloc(1, image.size.width * image.size.height * sizeof(struct pixel)); if (pixels != nil) { // Create a new bitmap CGContextRef context = CGBitmapContextCreate( (void*) pixels, image.size.width, image.size.height, 8, image.size.width * 4, CGImageGetColorSpace(image.CGImage), kCGImageAlphaPremultipliedLast ); NSLog(@"1=%d, 2=%d, 3=%d", CGImageGetBitsPerComponent(image), CGImageGetBitsPerPixel(image),CGImageGetBytesPerRow(image)); if (context != NULL) { // Draw the image in the bitmap CGContextDrawImage(context, CGRectMake(0.0f, 0.0f, image.size.width, image.size.height), image.CGImage); NSUInteger numberOfPixels = image.size.width * image.size.height; I confusing about how to initialize the 2-D matrix in which the matrix store data of pixels.

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  • The C vs. C++ way

    - by amc
    Hi, So I have to write a program that will iterate through an image and record the pixel locations corresponding to each color pixel that appears in it. For example, given http://www.socuteurl.com/fishywishykissy I need to find the coordinates of all yellow, purple, dark pink, etc pixels. In C++ I would use a hash table to do this. I would iterate through the image, check each pixel's value, look up that value and either add to a vector of pixel coordinates if it were found or add a new entry to the table if the value were not already there. The problem is that I may need to write this program in pure C instead of C++. How would I go about doing this in C? I feel like implementing a hash table would be pretty obnoxious and error-prone: should I avoid doing that? I'm pretty inexperienced with C and have a fair amount of C++ experience, if that matters. Thanks.

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  • Why won't my images align properly?

    I'm trying to make a dynamically sizable title banner, using fairly simple image tricks. I place the banner image in a table cell, and set the background-image of the table row to a one-pixel-wide repeat of the banner's right-most pixel column. Thus, the banner image appears to stretch to fit the screen width without stretching the logo. The code below is my entire page so far, and the problem is shown in a red circle in the screenshot. This is the transition where the main image ends and the one-pixel-wide background image begins. It appears that the one-pixel-wide bar at the end is compressed by one pixel - making the tops align properly, while the bottoms are one pixel off. I should add that I have checked the images more than once to make cure they the image data is correct. They are %100 accurate as far as MSPaint is concerned. <%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> </head> <body bgcolor="#000000"> <form id="form1" runat="server"> <div> <table style="width:100%; "> <tr style="background-image: url('Images/Banners/WebBannerWideBar.png')"> <!--WebBannerWideBar is 1x100 px--> <td> <img alt="Angry Octopus" src="Images/Banners/WebBannerWide.png" /> <!--WebBannerWide is 760x100 px--> </td> </tr> </table> </div> </form> </body> </html>

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  • Java for loop with multiple incrementers

    - by user2517280
    Im writing a program which combines the RGB pixel values for 3 images, e.g. red pixel of image 1, green pixel of image 2 and blue pixel of image 3 and I want to then create a final image of it. Im using the code below, but this seems to be incrementing x2 and x3 whilst x1 is the same, i.e. not giving the right pixel value for same co-ordinate for each image. for (int x = 0; x < image.getWidth(); x++) { for (int x2 = 0; x2 < image2.getWidth(); x2++) { for (int x3 = 0; x3 < image3.getWidth(); x3++) { for (int y = 0; y < image.getHeight(); y++) { for (int y2 = 0; y2 < image2.getHeight(); y2++) { for (int y3 = 0; y3 < image3.getHeight(); y3++) { So I was wondering if anyone can tell me how to iterate through each of the 3 images on the same co-ordinate, so for example read 1, 1 of each image and record the red, green and blue value accordingly. Apologies if it doesnt make complete sense, its a bit hard to explain. I can iterate the values for one image fine but when I add in another, things start to go a bit wrong as obviously its quite a bit more complicated! I was thinking it might be easier to create an array and replace the according values in that just not sure how to do that effectively either. Thanks

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  • what is the relation between actual pixels and html(css) pixels in blackberry?

    - by HelpMeToHelpYou
    I am implementing one phonegap application. here everything going fine but when i am talking device specifications like 1)BlackBerry Bold Touch 9900 Screen specifications are as following Body Dimensions 115 x 66 x 10.5 mm (4.53 x 2.60 x 0.41 in) Weight 130 g (4.59 oz) Keyboard QWERTY Display Type TFT capacitive touchscreen, 16M colors Size 640 x 480 pixels, 2.8 inches (~286 ppi pixel density) But when i test following function in java script function findScreenSize() { alert("width:"+window.innerWidth +"Height:"+ window.innerHeight); } it displaying SIZE width : 356 Height : 267 (356 x 267) 2)BlackBerry Bold Touch 9930 Screen specifications are as following Body Dimensions 115 x 66 x 10.5 mm (4.53 x 2.60 x 0.41 in) Weight 130 g (4.59 oz) Keyboard QWERTY - Touch-sensitive controls Display Type TFT capacitive touchscreen, 16M colors Size 640 x 480 pixels, 2.8 inches (~286 ppi pixel density) then i run same javaScript function i got following output it displaying SIZE width : 417 Height : 313 (417 x 313) why it is behaving like this ? Can anybody know relation between core pixel and HTML pixel please give answer

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  • c++ template and its element type

    - by David
    This is my template matrix class: template<typename T> class Matrix { public: .... Matrix<T> operator / (const T &num); } However, in my Pixel class, I didn't define the Pixel/Pixel operator at all! Why in this case, the compiler still compiles?

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  • Java swing center JDialog over parent

    - by Chris Drappier
    I have a Java swing application with a button that produces a popup window when a certain action is performed. I'd like to align the center point of the popup window with the center point of the parent window when it is rendered. How can I calculate the x,y coordinates to plug into setLocation() for the popup window? EDIT: just to clarify. I do not want the behavior of setLocationRelativeTo() because that sets the top-left pixel of the popup over the center pixel of the parent frame. I want to set the center pixel of the popup over the center pixel of the parent frame. Also, I'm not interested in whether or not a popup window is good practice. I'm past that now. thanks

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  • How to obtain a random sub-datatable from another data table

    - by developerit
    Introduction In this article, I’ll show how to get a random subset of data from a DataTable. This is useful when you already have queries that are filtered correctly but returns all the rows. Analysis I came across this situation when I wanted to display a random tag cloud. I already had the query to get the keywords ordered by number of clicks and I wanted to created a tag cloud. Tags that are the most popular should have more chance to get picked and should be displayed larger than less popular ones. Implementation In this code snippet, there is everything you need. ' Min size, in pixel for the tag Private Const MIN_FONT_SIZE As Integer = 9 ' Max size, in pixel for the tag Private Const MAX_FONT_SIZE As Integer = 14 ' Basic function that retreives Tags from a DataBase Public Shared Function GetTags() As MediasTagsDataTable ' Simple call to the TableAdapter, to get the Tags ordered by number of clicks Dim dt As MediasTagsDataTable = taMediasTags.GetDataValide ' If the query returned no result, return an empty DataTable If dt Is Nothing OrElse dt.Rows.Count < 1 Then Return New MediasTagsDataTable End If ' Set the font-size of the group of data ' We are dividing our results into sub set, according to their number of clicks ' Example: 10 results -> [0,2] will get font size 9, [3,5] will get font size 10, [6,8] wil get 11, ... ' This is the number of elements in one group Dim groupLenth As Integer = CType(Math.Floor(dt.Rows.Count / (MAX_FONT_SIZE - MIN_FONT_SIZE)), Integer) ' Counter of elements in the same group Dim counter As Integer = 0 ' Counter of groups Dim groupCounter As Integer = 0 ' Loop througt the list For Each row As MediasTagsRow In dt ' Set the font-size in a custom column row.c_FontSize = MIN_FONT_SIZE + groupCounter ' Increment the counter counter += 1 ' If the group counter is less than the counter If groupLenth <= counter Then ' Start a new group counter = 0 groupCounter += 1 End If Next ' Return the new DataTable with font-size Return dt End Function ' Function that generate the random sub set Public Shared Function GetRandomSampleTags(ByVal KeyCount As Integer) As MediasTagsDataTable ' Get the data Dim dt As MediasTagsDataTable = GetTags() ' Create a new DataTable that will contains the random set Dim rep As MediasTagsDataTable = New MediasTagsDataTable ' Count the number of row in the new DataTable Dim count As Integer = 0 ' Random number generator Dim rand As New Random() While count < KeyCount Randomize() ' Pick a random row Dim r As Integer = rand.Next(0, dt.Rows.Count - 1) Dim tmpRow As MediasTagsRow = dt(r) ' Import it into the new DataTable rep.ImportRow(tmpRow) ' Remove it from the old one, to be sure not to pick it again dt.Rows.RemoveAt(r) ' Increment the counter count += 1 End While ' Return the new sub set Return rep End Function Pro’s This method is good because it doesn’t require much work to get it work fast. It is a good concept when you are working with small tables, let says less than 100 records. Con’s If you have more than 100 records, out of memory exception may occur since we are coping and duplicating rows. I would consider using a stored procedure instead.

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  • NGinx Best Practices

    - by The Pixel Developer
    What best practices do you use while using NGinx? try_files in Subdirectory Credits go to Igor for helping me with this one. location /wordpress { try_files $uri $uri/ @wordpress; } location @wordpress { fastcgi_pass 127.0.0.1:9000; fastcgi_split_path_info ^(/wordpress)(/.*)$; fastcgi_param SCRIPT_FILENAME /var/www/wordpress/index.php; fastcgi_param PATH_INFO $fastcgi_path_info; } Normally PATH_INFO would include the "/wordpress", so we use the "split_path_info" command to grab the part of the URI after "/wordpress". This allows us to wordpress with and without the index.php file.

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  • What are the GPU requirements for XNA 4.0?

    - by Nate Koppenhaver
    I tried to build a sample application using XNA, but I got an error saying that Pixel Shader 1.1 was required, so I got a used Radeon X300 GPU that supports Pixel Shader. I tried to build it again, but I got another error saying that "Your current graphics card does not support the XNA HiDef profile" and would not build. Since that card seems to not be compatible, I guess I need to buy another one. What features should I look for to make sure that it's compatible with XNA?

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  • iPad2 - Yet Another Fundamental Defect in an Apple product

    - by Kit Ong
    First it was antenna defect in iPhone4 now it has been reported that some iPad 2 have display issues, Apple really needs to look at their manufacturing process. It doesn't help that workers are working like robots in their main supplier's factory Foxconn. More info on reported display light bleeding http://www.cultofmac.com/if-your-ipad-2-has-display-problems-do-not-return-it-heres-why/87197   How to check your iPad for dead pixel / light leak / bleed http://www.theipadguide.com/content/ipad-dead-pixel-test-how/7171269

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  • When does depth testing happen?

    - by Utkarsh Sinha
    I'm working with 2D sprites - and I want to do 3D style depth testing with them. When writing a pixel shader for them, I get access to the semantic DEPTH0. Would writing to this value help? It seems it doesn't. Maybe it's done before the pixel shader step? Or is depth testing only done when drawing 3D things (I'm using SpriteBatch)? Any links/articles/topics to read/search for would be appreciated.

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  • HTML5 Canvas Game Timer

    - by zghyh
    How to create good timer for HTML5 Canvas games? I am using RequestAnimationFrame( http://paulirish.com/2011/requestanimationframe-for-smart-animating/ ) But object's move too fast. Something like my code is: http://pastebin.com/bSHCTMmq But if I press UP_ARROW player don't move one pixel, but move 5, 8, or 10 or more or less pixels. How to do if I press UP_ARROW player move 1 pixel? Thanks for help.

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  • Partial Shader Signatures HLSL D3D11 C++

    - by ThePhD
    I had been debugging a problem I was having in a single shader file with 2 functions in it. I'm using DirectX 11, vs_5_0 and ps_5_0. I have stripped it down to its basic components to understand what was going wrong with the shaders, because the different named components of the Pixel and Vertex shaders were swapping the data being input: void QuadVertex ( inout float4 position : SV_Position, inout float4 color : COLOR0, inout float2 tex : TEXCOORD0 ) { // ViewProject is a 4x4 matrix, // just included here to show the simple passthrough of the data position = mul(position, ViewProjection); } And a Pixel Shader: float4 QuadPixel ( float4 color : COLOR0, float2 tex : TEXCOORD0 ) : SV_Target0 { // Color is filled with position data and tex is // filled with color values from the Vertex Shader return color; } The ID3D11InputLayout and associated C++ code correctly compiles the shaders and sets them up with some simple primitive data: data[0].Position.x = 0.0f * 210; data[0].Position.y = 1.0f * 160; data[0].Position.z = 0.0f; data[1].Position.x = 0.0f * 210; data[1].Position.y = 0.0f * 160; data[1].Position.z = 0.0f; data[2].Position.x = 1.0f * 210; data[2].Position.y = 1.0f * 160; data[2].Position.z = 0.0f; data[0].Colour = Colors::Red; data[1].Colour = Colors::Red; data[2].Colour = Colors::Red; data[0].Texture = Vector2::Zero; data[1].Texture = Vector2::Zero; data[2].Texture = Vector2::Zero; When used with the shader, the float4 color always ended up with the position data, and the float2 tex always ended up with the color data. After a moment, I figured out that the shader's input and output signatures needed to be in the correct order and the correct format and be laid out in the exact order of the output from the Vertex Shader, regardless of the semantics: float4 QuadPixel ( float4 pos : SV_Position, float4 color : COLOR0, float2 tex : TEXCOORD0 ) : SV_Target0 { return color; } After finding this out, My question is: Why don't the semantics map the appropriate components when going from Vertex Shader to Pixel Shader? Is there any way that I can make it so certain semantics are always mapped to other semantics, or do I always have to follow the rigid Shader Signature (in this case, Position, Color, and Texture) ? As a side note for why I'm asking: I know that when using XNA, my shader signatures for functions could differ in position and even drop items from Vertex Shader to Pixel Shader function parameters, having only the COLOR0 and TEXCOORD0 components being used (and it would still match up correctly). However, I also know that XNA relied on DX9 (and maybe a little DX10) implementation, and that maybe this kind of flexibility no longer exists in DX11?

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  • How to Stich to Image objects in Java

    - by Imran
    Hi, I have a scenario in which i`m getting a number of tiles (e.g.12) from my mapping server. Now for buffering and offline functions I need to join them all back again so that we have to deal with 1 single image object instead of 12. I ve tried to do it without JAI my code is below. package imagemerge; import java.awt.*; import java.awt.image.*; import java.awt.event.*; public class ImageSticher extends WindowAdapter { Image tile1; Image tile2; Image result; ColorModel colorModel; int width,height,widthr,heightr; //int t1,t2; int t12[]; public ImageSticher() { } public ImageSticher (Image img1,Image img2,int w,int h) { tile1=img1; tile2=img2; width=w; height=h; colorModel=ColorModel.getRGBdefault(); } public Image horizontalStich() throws Exception { widthr=width*2; heightr=height; t12=new int[widthr * heightr]; int t1[]=new int[width*height]; PixelGrabber p1 =new PixelGrabber(tile1, 0, 0, width, height, t1, 0, width); p1.grabPixels(); int t2[]=new int[width*height]; PixelGrabber p2 =new PixelGrabber(tile2, 0, 0, width, height, t1, 0, width); p2.grabPixels(); int y, x, rp, rpi; int red1, red2, redr; int green1, green2, greenr; int blue1, blue2, bluer; int alpha1, alpha2, alphar; for(y=0;y<heightr;y++) { for(x=0;x<widthr;x++) { //System.out.println(x); rpi=y*widthr+x; // index of resulting pixel; rp=0; //initializing resulting pixel System.out.println(rpi); if(x<(widthr/2)) // x is less than width , copy first tile { //System.out.println("tile1="+x); blue1 = t1[rpi] & 0x00ff; // ERROR occurs here green1=(t1[rpi] >> 8) & 0x00ff; red1=(t1[rpi] >> 16) & 0x00ff; alpha1 = (t1[rpi] >> 24) & 0x00ff; redr = (int)(red1 * 1.0); // copying red band pixel into redresult,,,,1.0 is the alpha valye redr = (redr < 0)?(0):((redr>255)?(255):(redr)); greenr = (int)(green1 * 1.0); // redr = (int)(red1 * 1.0); // greenr = (greenr < 0)?(0):((greenr>255)?(255):(greenr)); bluer = (int)(blue1 * 1.0); bluer = (bluer < 0)?(0):((bluer>255)?(255):(bluer)); alphar = 255; //resulting pixel computed rp = (((((alphar << 8) + (redr & 0x0ff)) << 8) + (greenr & 0x0ff)) << 8) + (bluer & 0x0ff); } else // index is ahead of half way...copy second tile { blue2 = t2[rpi] & 0x00ff; // blue band bit of first tile green2=(t2[rpi] >> 8) & 0x00ff; red2=(t2[rpi] >> 16) & 0x00ff; alpha2 = (t2[rpi] >> 24) & 0x00ff; redr = (int)(red2 * 1.0); // copying red band pixel into redresult,,,,1.0 is the alpha valye redr = (redr < 0)?(0):((redr>255)?(255):(redr)); greenr = (int)(green2 * 1.0); // redr = (int)(red2 * 1.0); // greenr = (greenr < 0)?(0):((greenr>255)?(255):(greenr)); bluer = (int)(blue2 * 1.0); bluer = (bluer < 0)?(0):((bluer>255)?(255):(bluer)); alphar = 255; //resulting pixel computed rp = (((((alphar << 8) + (redr & 0x0ff)) << 8) + (greenr & 0x0ff)) << 8) + (bluer & 0x0ff); } t12[rpi] = rp; // copying resulting pixel in the result int array which will be converted to image } } MemoryImageSource mis; if (t12!=null) { mis = new MemoryImageSource(widthr, heightr, colorModel, t12, 0, widthr); result = Toolkit.getDefaultToolkit().createImage(mis); return result; } return null; } } now to check the my theory Im trying to join or stich two tiles horizontaly but im getting the error : java.lang.ArrayIndexOutOfBoundsException: 90000 at imagemerge.ImageSticher.horizontalStich(ImageSticher.java:69) at imageStream.ImageStream.getImage(ImageStream.java:75) at imageStream.ImageStream.main(ImageStream.java:28) is there some kind of limitation because when stiching two images of 300 x 300 horizontally it means the resulting image will be 600 x 300 ... that would make 180000 index size but its giving error at 90000, what am I doing wrong here

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  • What is the significance of these different width, height and resolution parameters?

    - by ??????? ???????????
    An image with a pixel resolution of 640 x 480 has additional dimension and resolution parameters according to exiftool. I'm unsure what they mean. Why are the X / Y Resolution parameters the same?Should they not reflect the pixel dimensions of the image? What does Exif Image Size mean and how is it different from the pixel dimensions? What is the focal plane? Does it have any relation to the device used to capture this image? $ exiftool evil1.jpg | egrep 'Width|Height|Resolution' X Resolution : 180 Y Resolution : 180 Resolution Unit : inches Exif Image Width : 400 Exif Image Height : 300 Focal Plane X Resolution : 8114.285714 Focal Plane Y Resolution : 8114.285714 Focal Plane Resolution Unit : inches Image Width : 640 Image Height : 480 If needed, the original image can be obtained from: here=http://www.pythonchallenge.com/pc/return/evil1.jpg wget --user=huge --password=file $here

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  • image processing algorithm in MATLAB

    - by user261002
    I am trying to reconstruct an algorithm belong to this paper: Decomposition of biospeckle images in temporary spectral bands Here is an explanation of the algorithm: We recorded a sequence of N successive speckle images with a sampling frequency fs. In this way it was possible to observe how a pixel evolves through the N images. That evolution can be treated as a time series and can be processed in the following way: Each signal corresponding to the evolution of every pixel was used as input to a bank of filters. The intensity values were previously divided by their temporal mean value to minimize local differences in reflectivity or illumination of the object. The maximum frequency that can be adequately analyzed is determined by the sampling theorem and s half of sampling frequency fs. The latter is set by the CCD camera, the size of the image, and the frame grabber. The bank of filters is outlined in Fig. 1. In our case, ten 5° order Butterworth11 filters were used, but this number can be varied according to the required discrimination. The bank was implemented in a computer using MATLAB software. We chose the Butter-worth filter because, in addition to its simplicity, it is maximally flat. Other filters, an infinite impulse response, or a finite impulse response could be used. By means of this bank of filters, ten corresponding signals of each filter of each temporary pixel evolution were obtained as output. Average energy Eb in each signal was then calculated: where pb(n) is the intensity of the filtered pixel in the nth image for filter b divided by its mean value and N is the total number of images. In this way, en values of energy for each pixel were obtained, each of hem belonging to one of the frequency bands in Fig. 1. With these values it is possible to build ten images of the active object, each one of which shows how much energy of time-varying speckle there is in a certain frequency band. False color assignment to the gray levels in the results would help in discrimination. and here is my MATLAB code base on that : clear all for i=0:39 str = num2str(i); str1 = strcat(str,'.mat'); load(str1); D{i+1}=A; end new_max = max(max(A)); new_min = min(min(A)); for i=20:180 for j=20:140 ts = []; for k=1:40 ts = [ts D{k}(i,j)]; %%% kth image pixel i,j --- ts is time series end ts = double(ts); temp = mean(ts); ts = ts-temp; ts = ts/temp; N = 5; % filter order W = [0.00001 0.05;0.05 0.1;0.1 0.15;0.15 0.20;0.20 0.25;0.25 0.30;0.30 0.35;0.35 0.40;0.40 0.45;0.45 0.50]; N1 = 5; for ind = 1:10 Wn = W(ind,:); [B,A] = butter(N1,Wn); ts_f(ind,:) = filter(B,A,ts); end for ind=1:10 imag_test1{ind}(i,j) =sum((ts_f(ind,:)./mean(ts_f(ind,:))).^2); end end end for i=1:10 temp_imag = imag_test1{i}(:,:); x=isnan(temp_imag); temp_imag(x)=0; temp_imag=medfilt2(temp_imag); t_max = max(max(temp_imag)); t_min = min(min(temp_imag)); temp_imag = (temp_imag-t_min).*(double(new_max-new_min)/double(t_max-t_min))+double(new_min); imag_test2{i}(:,:) = temp_imag; end for i=1:10 A=imag_test2{i}(:,:); B=A/max(max(A)); B=histeq(B); figure,imshow(B) colorbar end but I am not getting the same result as paper. has anybody has aby idea why? or where I have gone wrong? Refrence Link to the paper

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  • Drawing outlines around organic shapes

    - by ThunderChunky_SF
    One thing that seems particularly easy to do in the Flash IDE but difficult to do with code is to outline an organic shape. In the IDE you can just use the inkbucket tool to draw a stroke around something. Using nothing but code it seems much trickier. One method I've seen is to add a glow filter to the shape in question and just mess with the strength. But what if i want to only show the outline? What I'd like to do is to collect all of the points that make up the edge of the shape and then just connect the dots. I've actually gotten so far as to collect all of the points with a quick and dirty edge detection script that I wrote. So now I have a Vector of all the points that makeup my shape. How do I connect them in the proper sequence so it actually looks like the original object? For anyone who is interested here is my edge detection script: // Create a new sprite which we'll use for our outline var sp:Sprite = new Sprite(); var radius:int = 50; sp.graphics.beginFill(0x00FF00, 1); sp.graphics.drawCircle(0, 0, radius); sp.graphics.endFill(); sp.x = stage.stageWidth / 2; sp.y = stage.stageHeight / 2; // Create a bitmap data object to draw our vector data var bmd:BitmapData = new BitmapData(sp.width, sp.height, true, 0); // Use a transform matrix to translate the drawn clip so that none of its // pixels reside in negative space. The draw method will only draw starting // at 0,0 var mat:Matrix = new Matrix(1, 0, 0, 1, radius, radius); bmd.draw(sp, mat); // Pass the bitmap data to an actual bitmap var bmp:Bitmap = new Bitmap(bmd); // Add the bitmap to the stage addChild(bmp); // Grab all of the pixel data from the bitmap data object var pixels:Vector.<uint> = bmd.getVector(bmd.rect); // Setup a vector to hold our stroke points var points:Vector.<Point> = new Vector.<Point>; // Loop through all of the pixels of the bitmap data object and // create a point instance for each pixel location that isn't // transparent. var l:int = pixels.length; for(var i:int = 0; i < l; ++i) { // Check to see if the pixel is transparent if(pixels[i] != 0) { var pt:Point; // Check to see if the pixel is on the first or last // row. We'll grab everything from these rows to close the outline if(i <= bmp.width || i >= (bmp.width * bmp.height) - bmp.width) { pt = new Point(); pt.x = int(i % bmp.width); pt.y = int(i / bmp.width); points.push(pt); continue; } // Check to see if the current pixel is on either extreme edge if(int(i % bmp.width) == 0 || int(i % bmp.width) == bmp.width - 1) { pt = new Point(); pt.x = int(i % bmp.width); pt.y = int(i / bmp.width); points.push(pt); continue; } // Check to see if the previous or next pixel are transparent, // if so save the current one. if(i > 0 && i < bmp.width * bmp.height) { if(pixels[i - 1] == 0 || pixels[i + 1] == 0) { pt = new Point(); pt.x = int(i % bmp.width); pt.y = int(i / bmp.width); points.push(pt); } } } }

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  • Fastest way to read data from a lot of ASCII files

    - by Alsenes
    Hi guys, for a college exercise that I've already submitted I needed to read a .txt file wich contained a lot of names of images(1 in each line). Then I needed to open each image as an ascii file, and read their data(images where in ppm format), and do a series of things with them. The things is, I noticed my program was taking 70% of the time in the reading the data from the file part, instead of in the other calculations that I was doing (finding number of repetitions of each pixel with a hash table, finding diferents pixels beetween 2 images etc..), which I found quite odd to say the least. This is how the ppm format looks like: P3 //This value can be ignored when reading the file, because all image will be correctly formatted 4 4 255 //This value can be also ignored, will be always 255. 0 0 0 0 0 0 0 0 0 15 0 15 0 0 0 0 15 7 0 0 0 0 0 0 0 0 0 0 0 0 0 15 7 0 0 0 15 0 15 0 0 0 0 0 0 0 0 0 This is how I was reading the data from the files: ifstream fdatos; fdatos.open(argv[1]); //Open file with the name of all the images const int size = 128; char file[size]; //Where I'll get the image name Image *img; while (fdatos >> file) { //While there's still images anmes left, continue ifstream fimagen; fimagen.open(file); //Open image file img = new Image(fimagen); //Create new image object with it's data file ……… //Rest of the calculations whith that image ……… delete img; //Delete image object after done fimagen.close(); //Close image file after done } fdatos.close(); And inside the image object read the data like this: const int tallafirma = 100; char firma[tallafirma]; fich_in >> std::setw(100) >> firma; // Read the P3 part, can be ignored int maxvalue, numpixels; fich_in >> height >> width >> maxvalue; // Read the next three values numpixels = height*width; datos = new Pixel[numpixels]; int r,g,b; //Don't need to be ints, max value is 256, so an unsigned char would be ok. for (int i=0; i<numpixels; i++) { fich_in >> r >> g >> b; datos[i] = Pixel( r, g ,b); } //This last part is the slow one, //I thing I should be able to read all this data in one single read //to buffer or something which would be stored in an array of unsigned chars, //and then I'd only need to to do: //buffer[0] -> //Pixel 1 - Red data //buffer[1] -> //Pixel 1 - Green data //buffer[2] -> //Pixel 1 - Blue data So, any Ideas? I think I can improve it quite a bit reading all to an array in one single call, I just don't know how that is done. Also, is it posible to know how many images will be in the "index file"? Is it posiible to know the number of lines a file has?(because there's one file name per line..) Thanks!!

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  • Are there any font rendering libraries for games development that support hinting?

    - by Richard Fabian
    I've used angel code's bitmap font generator quite a bit and though it's very good, I wondered if there would be a way of using the hinting information to provide a better readable result by using hinting to provide differing thickness based on size/pixel coverage. I imagine any solution would have to use the distance field tech presented in the valve paper on smoothing fonts while maintaining or reducing asset size. (http://www.gamedev.net/community/forums/topic.asp?topic_id=494612) but I haven't found any demos of it being used with hinting information turned on or included in the field gradients in any way. Another way of looking at this is whether there are any font bitmap generators that will output mipmaps that still maintain their readability in the face of pixel size. I think the lower mip levels would try to guarantee fill and space where it is necessary to maintain readability/topology over maintaining style/form (the point of hinting). In response to "Is there a reason you can't just render the size you want", the problem lies in the fact that font rasterisers currently don't render in 3D, and hinting information would be important in different amounts due to the pixel density being different along different axes, even differing in importance along the length of a string due to the size reducing over distance. For example, I only want horizontal hinting in a texture that is viewed from the side, and only really want vertical hinting in a font that is viewed from below or above. This isn't meant to be a renderer that tries to render a perfect outline as accurately as possible, as hinting distorts the reality of the font, instead this is meant to be a rendering solution for quite static scenes, but scenes that have 3D transformed and warped text layout. In this case the legibility is important, more important than the accuracy of representation of the polygon shape.

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  • How do graphics programmers deal with rendering vertices that don't change the image?

    - by canisrufus
    So, the title is a little awkward. I'll give some background, and then ask my question. Background: I work as a web GIS application developer, but in my spare time I've been playing with map rendering and improving data interchange formats. I work only in 2D space. One interesting issue I've encountered is that when you're rendering a polygon at a small scale (zoomed way out), many of the vertices are redundant. An extreme case would be that you have a polygon with 500,000 vertices that only takes up a single pixel. If you're sending this data to the browser, it would make sense to omit ~499,999 of those vertices. One way we achieve that is by rendering an image on a server and and sending it as a PNG: voila, it's a point. Sometimes, though, we want data sent to the browser where it can be rendered with SVG (or canvas, or webgl) so that it can be interactive. The problem: It turns out that, using modern geographic data sets, it's very easy to overload SVG's rendering abilities. In an effort to cope with those limitations, I'm trying to figure out how to visually losslessly reduce a data set for a given scale and map extent (and, if necessary, for a known map pixel width and height). I got a great reduction in data size just using the Douglas-Peucker algorithm, and I believe I was able to get it to keep the polygons true to within one pixel. Unfortunately, Douglas-Peucker doesn't preserve topology, so it changed how borders between polygons got rendered. I couldn't readily find other algorithms to try out and adapt to the purpose, but I don't have much CS/algorithm background and might not recognize them if I saw them.

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