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  • Iphone -- maintaining a list of strings and a corresponding typedef enum

    - by William Jockusch
    Suppose I have the following: typedef enum functionType {ln, sin, sqrt} functionType; NSArray *functions = [NSArray arrayWithObjects: @"ln", @"sin", @"sqrt", nil]; Suppose further that *functions will not change at runtime. Question -- is there any way to set up a single structure which updates both of these? So that I only have to keep track of one list, instead of two. To explain what is going on -- the idea is that string input from the user will be stored in a variable of type functionType. Later on, I will have code like this: double valueOfFunction: (functionType) function withInput: (double) input switch (function) { case ln: return ln(input); case sin: return sin(input); case sqrt: return sqrt(input); //etc . . . could grow to include a lot of functions. } And valueOfFunction needs to be fast. So I don't want to be doing string comparisons there.

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  • Allowing Xform controls for optional XML elements

    - by Cam
    Hi, In designing an XForm interface to an XML database (using eXist and XSLTForms), I'd like to include an input control for an optional element. The XML data records already exist and while some contain the optional element, others don't. To update a record, I'm using the existing XML record as the model instance. The problem is that the form control is not displayed when the optional element is not present, which is logical, but presents a problem when a user wants to add data to the optional element. To be more explicit, here's an example data record, data.xml: <a> <b>content</b> </a> with RNC schema: start = element a { element b { text }, element notes { text }? } XForms model: <xf:model> <xf:instance xmlns="" src="data.xml"/> <xf:submission id="save" method="post" action="update.xq" /> </xf:model> And control: <xf:input ref="/a/notes"> <xf:label>Notes (optional): </xf:label> </xf:input> The problem is that the 'Notes' input control is simply not displayed. An obvious solution is to add a trigger button to allow the user to insert the element if needed, but it is preferable to just have the input control appear, and be empty. My question is: is there some subtle combination of lesser-know attributes/binds/multiple instances/xpath expressions that will cause the control to always be displayed? Thanks

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  • Having onFocus do several things.

    - by Jakob
    So I have this input tag <input ... onFocus=...> and what I want is for a warning popup to come up if somebody clicks to write in the input field. After the person has read the warning he/she closes the popup and can continue to write in the field. I have managed to implement the popup just fine but my problem is that I lose focus on the input field when the popup comes up so the next time I click the field the popup comes back again and im back on square one. The system I work on uses php and javascript so and I cannot use anything other than that to solve the problem and my experience with both php and javascript is limited.

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  • How to find if a file is an exe in C# ?

    - by Praveen
    Hi All, How can I be sure that a file passed to my program is a valid exe file ? actually my program takes a file as input and runs it, but user can input any file so I have to make sure that the input is a valid exe. Thanks in advance for any guidance...

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  • Regular expression (PCRE) for url matching

    - by zerkms
    The input: we get some plain text as input string and we have to highlighight all urls there with {url For some time i've used regex taken from http://flanders.co.nz/2009/11/08/a-good-url-regular-expression-repost/, which i modified several times, but it's built for another issue - to check whether the whole input string is an url or no. So, what regex do you use in such issues?

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  • Is catching NumberFormatException a bad practice?

    - by integeruser
    I have to parse a String that can assume hex values or other non-hex values 0xff, 0x31 or A, PC, label, and so on. I use this code to divide the two cases: String input = readInput(); try { int hex = Integer.decode(input); // use hex ... } catch (NumberFormatException e) { // input is not a hex, continue parsing } Can this code be considered "ugly" or difficult to read? Are there other (maybe more elegant) solutions? EDIT : I want to clarify that (in my case) a wrong input doesn't exist: i just need to distinguish if it is a hex number, or not. And just for completeness, i'm making a simple assebler for DCPU-16.

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  • Javascript - Simple form script to hide/show fields

    - by danit
    Im looking for a simple script in javascript that i can extend, at a basic level Im looking to show 1 field based on which option from a <select> the user chooses. <select id="options"> <option value="spoon">Spoon</option> <option value="form">Fork</option> </select> if select=spoon { <input>enter your favorite soup</input> } else { <input>Your gonna need a knife</input> } Simple JS is the key!

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  • Is it possible to use .data() as a search criteria?

    - by Andrew
    I have a pretty complex chat application going on, and there are multiple chat panes, chat entries, chat submits, etc. going on in the same window. At first I was going to do something like.... <input type="text" class="chattext" id="chattext-42"> <input type="text" class="chattext" id="chattext-93"> <input type="button" class="chatsubmit" id="chatsubmit-42"> <input type="button" class="chatsubmit" id="chatsubmit-93"> ... etc. (of course this is vastly simplified, they'd be in separate divs, separate visibilities, etc) So, when they clicked on a .chatsubmit, it would then get the id of that and find the last two characters for the chat ID. This presents some problems, as it would require rewrites if IDs changed lengths, and seems just plain inelegant to me. I then remembered the .data() facility in jQuery... I thought, maybe I could do it more like this: <input type="text" class="chattext"> ... and add a .data("id", 42) to this one <input type="button" class="chatsubmit"> ... and add a .data("id", 42) So that when they click chatsubmit, it gets the ID, and then finds the chattext with that ID and processes it. But looking at the documentation, I don't see an easy way to search by this. For example, let's say the event target in this case is the chatsubmit with the data('id') of 42... var ID = $(event.target).data('id'); // Sets it to 42 var chattext = ... And here I run into the trouble. How do I find which DOM element matches a class of chattext and a data('id') of 42? Is there any easy method, or do I have to search every .chattext for the one with an id of 42? Or is there another easy way of doing this? I did consider the possibility of the container div having the ID, which would make it, I think,? slightly easier to get. But if this works, it could be dealing with things in other container divs as well, making that not a long-term solution. Edit: Literally seconds after posting this, I found this: http://james.padolsey.com/javascript/extending-jquerys-selector-capabilities/ which includes information on extending the selector to data. So I'll try that out, and in the meantime, is this a completely foolhardy way of handling this?

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  • How do I make a daemon into a stream in PHP

    - by Itay Moav
    I have a daemon (written in C, but I assume it does not really matter) which outputs messages with printf, and can get input and do stuff with this input (again, not really important what, but he sends those messages to a different machine to be saved there in the DB). My question, how can I make this daemon to be a stream in PHP, so I can hook the input/output of, for example, file_put_contents to this stream.

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  • Getting information from servlet created html

    - by user541597
    I have a servlet that creates an html text box and then redirects to another servlet on submit. How can I access the value of the html text box from the new servlet? I am able to access servlet variables from the new servlet but I am not aware of how to access the value of the html generated code. thanks, Here is the servlet that gets the text input public class ServletB extends HttpServlet { public void doGet(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { response.setContentType("text/html"); String value = System.getProperty("card"); PrintWriter out = response.getWriter(); out.println("<center><h1>Your preffered method of payment is "+value+"</h1><br />"); out.println("Please Enter Card Number<input type =\"text\" name = \"number\"/><form action=\"http://codd.cs.gsu.edu:9999/cpereyra183/servlet/ServletC\"><input type =\"submit\" value=\"Continue\" /><input type=\"button\" value=\"Cancel\" /></center>"); } }} This is the servlet the first servlet redirects to all I do is try to do is output the text input public class ServletC extends HttpServlet { public void doGet(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException { response.setContentType("text/html"); String value = System.getProperty("card"); PrintWriter out = response.getWriter(); out.println(request.getParameter("number")); } }

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  • Send multi message using jquery plugin in multi-row data?

    - by Agus Puryanto
    i use jquery.form to send a form, but in may case below how use this jquery plugin $('#htmlForm').ajaxForm({ target: '#htmlExampleTarget', success: function() { $('#htmlExampleTarget').fadeIn('slow'); $('#htmlForm').hide(); } }); for($i=1;$i<= 10;$i++){ //form $1 form name="form$i" action="blabla.php" input type="text" name="name$i" / input type="text" name="name$i" / input type="submit" name="submit" / }

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  • Make any posible combination of one string with php

    - by Johan
    I need an algorithm that return all possible combination of all characters in one string. I've tried: $langd = strlen($input); for($i = 0;$i < $langd; $i++){ $tempStrang = NULL; $tempStrang .= substr($input, $i, 1); for($j = $i+1, $k=0; $k < $langd; $k++, $j++){ if($j > $langd) $j = 0; $tempStrang .= substr($input, $j, 1); } $myarray[] = $tempStrang; } But that only returns the same amount combination as the length of the string. Say the $input is = "hey", the result would be: hey, hye, eyh, ehy, yhe, yeh.

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  • Radio button how to?

    - by Azzyh
    what i want to do is that when you vote Y or N (two different radio buttons) and then it inserts into the "vote" column(in database) = Y or N(what you pickd), if nothing then echo error. I know how to do this like halfway, i never worked with radiobuttons before so i need you guys. Here's a two radio button right: Yes: <input type="radio" value="Y" id="voteYes" name="vote"></input> <br> No: <input type="radio" value="N" id="voteNo" name="vote"> </input> I gave the value N and Y, not the same ID, but the same name. I think its right, but how should i do with the PHP part of what i want to do? I mean shall i call for "vote"? ($_GET["vote"]) i dont think so.. here's where im stuck

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  • is it safe to refactor my django models?

    - by Johnd
    My model is similar to this. Is this ok or should I make the common base class abstract? What are the differcenes between this or makeing it abstract and not having an extra table? It seems odd that there is only one primary key now that I have factored stuff out. class Input(models.Model): details = models.CharField(max_length=1000) user = models.ForeignKey(User) pub_date = models.DateTimeField('date published') rating = models.IntegerField() def __unicode__(self): return self.details class Case(Input): title = models.CharField(max_length=200) views = models.IntegerField() class Argument(Input): case = models.ForeignKey(Case) side = models.BooleanField() is this ok to factor stuff out intpu Input? I noticed Cases and Arguments share a primary Key. like this: CREATE TABLE "cases_input" ( "id" integer NOT NULL PRIMARY KEY, "details" varchar(1000) NOT NULL, "user_id" integer NOT NULL REFERENCES "auth_user" ("id"), "pub_date" datetime NOT NULL, "rating" integer NOT NULL ) ; CREATE TABLE "cases_case" ( "input_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "cases_input" ("id"), "title" varchar(200) NOT NULL, "views" integer NOT NULL ) ; CREATE TABLE "cases_argument" ( "input_ptr_id" integer NOT NULL PRIMARY KEY REFERENCES "cases_input" ("id"), "case_id" integer NOT NULL REFERENCES "cases_case" ("input_ptr_id"), "side" bool NOT NULL )

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  • Very Urgent :How to start a new session if a user click on the new tab in IE or mozilla on websphere

    - by ha22109
    Hi, I have one "user search" portlet on the home page of one application running on websphere portal server.Which display the matching user records as per the search criteria filled in the search form.I have requirement to have a "back to search input" link on the results page which onclick should show the filled form on the input jsp. The issue which i am facing is if i open the application in two diff tab of same IE browser and start giving some search criteria and submit and same time search for some other input from other IE tab (in the same browser)and then go back to previous tab and click on "back to search input" link then instead of showing me the first input it will show me the imput which i entered in the next IE tab. I am setting and getting the bean(form bean) through portlet session.but in the two diff tab of same IE it will be the sae user session (and may be the same portlet session..) Please tell me solution for this. The one thing to be notice here is i can access this "user search" application even without doing login also.so it must be taking the default portlet session in this case. what wil happen once i login and then search,will it going to overwrite the portlet session and http session or howz is that?

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  • change div text on radion button click

    - by pisi
    I want to put the radio button value in the status div. The text of status div should change, according to the radio button selected by the user. The code that I used bellow is not working. Please help. Thanks! HTML code: <form action=""> <input type="radio" name="sex" value="male">Male<br> <input type="radio" name="sex" value="female">Female<br> <div id="status"></div> </form>? JS code: $(document).ready(function () { RadioStatus=""; $("input[type='radio']:checked").each( function() { if ($(this).attr('checked');) RadioStatus=$(this).val(); $("#status").text(RadioStatus); }); $("input[type='radio']").change(function() { RadioStatus= $('input[type='radio']:checked').val() $('#status').text(RadioStatus); }); });

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  • jquery .click function not getting triggered

    - by aakashbhowmick
    I have the following HTML and Javascript code. I am trying to make a search suggestion system. The list-items in the unordered-list 'search_suggest' are retrieved dynamically using ajax as the user types in the input box 'site_search' and inserted. <form name="search_site_form" method="get" action="search.php"> <input id="site_search" name="q" class="search_input input" autocomplete="off" value="Search the site" type="text"/> <ul id="search_suggest"> </ul> <input value=" " type="submit" class="search_submit"/> <script type="text/javascript"> <!-- $("ul#search_suggest>li").click(function(){ alert('123'); }); //--> </script> </form> Clicking on the list items in search_suggest however is not triggering the click function. Any idea why?

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  • This should be real easy. How to find a button through its Value (Jquery Selector)

    - by Raja
    I have this HTML: <div id='grid'> <input type="button" value="edit"/> <input type='button' value='update'/> </div> How to I attach a click event only to Update button. I know I could add a class to it or specity an id but both are not possible since it is in gridview. I tried this: $("input:button[@value='update']").click(function(){alert('test');}); but it displays an alert for both buttons. I know I must be doing something silly. Any help is much appreciated. Thanks Kobi for helping me out. Given below is the right answer. $("input[value='update']").click(function(){alert('test');});

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  • Send multiple fields with the same name via jQuery

    - by Swell
    Hi, how to send multiple fields with the same name via jQuery like this: <input type="file" name="file[]" /> <input type="file" name="file[]" /> <input type="file" name="file[]" /> jQuery: function upload() { $.post('upload.php', { file[]: uplaodForm.file[].value }, function(output) { $('#result').html(output).show(); }); } upload.php: $file[$i] = $_FILES['file']['name'][$i]; thank you,

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  • PHP radio button check if null

    - by Dallox
    So in class we get this school task where we need to check if one of the fields in unfilled and display an error. No we did this but for some strange reason it doesnt display a error when a radio button is unchecked. (textfield null check works fine) I've tried with a friend many possabilities but they all doesnt seem to work. We have been stuck at this task for 2 hours. Now we have tried making seperate if's but that doesnt seem to work too. These are the important parts: <p> <input type="hidden" name="taal" value="false"> Choose a language <input type="radio" name="taal" value="N"> Dutch <input type="radio" name="taal" value="E"> English <input type="radio" name="taal" value="S"> Spanish if (@$_POST['taal'] == null){ echo "No Language gotten"; return; }

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  • finding middle element of an array

    - by senthil
    Hi all, I came cross a question in my interview. Question: Array of integers will be given as the input and you should find out the middle element when sorted , but without sorting. For Example. Input: 1,3,5,4,2 Output: 3 When you sort the given input array, it will be 1,2,3,4,5 where middle element is 3. You should find this in one pass without sorting. Any solutions for this?

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  • Handling text menu in Python

    - by PulpFiction
    Hi all. I am trying to create a text based menu in Python. Here is the code: #!/usr/bin/env python def testcaseOutput(): print '1. Add. 2. Subtract. 3. Divide. 4. Multiply' try: answer = int(raw_input('Enter a value (1 - 4) >. ')) except ValueError: print 'Invalid input. Enter a value between 1 -4 .' testcaseOutput() if answer in range(1, 5): return answer else: print 'Invalid input. Enter a value between 1 - 4.' testcaseOutput() My question: When the user enters an invalid input, i.e. not a number, I want this function to get called again. So I used the recursive approach which I think is bad design. I use that approach again in the if answer in range(1, 5). Is there any other way to handle this? I need the prompt called again when there is an invalid input. Also, is there any way I can club the two constraints: check whether input is a number and check whether the number is in the range(1,5) together? As you can see, I am checking that individually.

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  • manipulating radio box selection with javascript

    - by Crays
    Hi guys, i'm trying to do a poll but i designed it without any radio box in it. So i decided to make the selection being highlighted with a different background color, all is done with jquery. I set the display of the radio box to none so that it wouldn't show, gave each a unique ID. Here's the script. <form action="v_poll.php" method="post"> <ul class="voting"> <li class="voting votetext"><input type="radio" name="voting" value="a1" style="display:none;" id="a1"><a onClick="vote('a1')"Answer 1</a></li> <li class="voting votetext"><input type="radio" name="voting" value="a2" style="display:none;" id="a2"><a onClick="vote('a2')">Answer 2</a></li> <li class="voting votetext"><input type="radio" name="voting" value="a3" style="display:none;" id="a3"><a onClick="vote('a3')">Answer 3</a></li> <input type="hidden" value="1" name="id" /> <input type="submit" value="submit"> </ul> </form> <script type="text/javascript"> function vote(TheValue) { GetElementById(TheValue).checked=true; } </script> But when i checked the value of the radio box with $_POST['voting'], it is blank. Not the value assigned to the radio box. Anything i'm doing wrong? Please help. Thanks.

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  • error in python d not defined.

    - by dtechie
    Hi I am learning python and have this error . I can figure out where\what the error is in the code. File "<string>", line 1, in <module>. Name = "" Desc = "" Gender = "" Race = "" # Prompt user for user-defined information Name = input('What is your Name? ') Desc = input('Describe yourself: ') When i run the program it outputs What is your Name? (i input d ) this gives the error Traceback (most recent call last): File "/python/chargen.py", line 19, in <module> Name = input('What is your Name? ') File "<string>", line 1, in <module> NameError: name 'd' is not defined This is an example code from Python 3 for Absolute Beginners Thank you for your help :)

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