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  • MySQL More Tables or More Rows

    - by Pez Cuckow
    I am working on a game that I am going to open to the public to have on their game. The game stores lots of information (about 300 rows) per website and spends a lot of time updating values within this MySQL database. Is it better (faster/efficient) to add a new table for every website or to just have 1000's of rows in one table and add a column "website_id" or similar?

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  • MySQL optimised code for 2 tables?

    - by David19801
    Hi, I have 2 tables, Table1: id,int1,int2,int3,int4,int5 Table2: integers (autoincrement),blobdata The query I want to use is given the id I want to get the blobdata from table2 associated with the 5 integers in table1. I've only ever used one table in mysql so have no idea how to do this properly. Is it possible? EDIT: id is username, integers in table2 is just integers. but have not built the tables yet, so can change if need to.

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  • Check if row exists, if not add it [MySQL]

    - by Steven
    I need to add a row to a MySQL database table but only if the row doesn't already exist. My database server just went down so I can't test this, but will this work as expected? INSERT INTO `blocks` (`block_file`,`settings_group`) VALUES ('announcements','announcement_settings') WHERE NOT EXISTS (SELECT `block_file`,`settings_group` FROM `blocks` WHERE `block_file`='announcements' AND `settings_group`='announcement_settings') It seems like sound logic. Is this a valid query or is there a better way of doing this?

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  • Creating tables and inserting data (MySQL Dump) using PHP Doctrine 1.2

    - by Dimitry
    Hello. I got a script that create a new database, now I need to fill that database with tables and values (from a MySQL dump file). I'm using PHP - Doctrine 1.2. Here is how I create the database: $manager = Doctrine_Manager::getInstance(); $newConn = $manager->openConnection($customer->Config->db_connection_string); $newConn->createDatabase(); How I do this? Thanks!

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  • build SQL query string using user input

    - by user175084
    i have to make a string by using the values which the user selects on the webpage suppose i need to display files for multiple machines with differnt search criteria.. i currently use this code: DataTable dt = new DataTable(); SqlConnection connection = new SqlConnection(); connection.ConnectionString = ConfigurationManager.ConnectionStrings["DBConnectionString"].ConnectionString; connection.Open(); SqlCommand sqlCmd = new SqlCommand("SELECT FileID FROM Files WHERE MachineID=@machineID and date= @date", connection); SqlDataAdapter sqlDa = new SqlDataAdapter(sqlCmd); sqlCmd.Parameters.AddWithValue("@machineID", machineID); sqlCmd.Parameters.AddWithValue("@date", date); sqlDa.Fill(dt); now this is fixed query where the user just has one machine and just selects one date... i want to make a query in which the user has multiple search options like type or size if he wants depending on what he selects also if he can select multiple machines.. SELECT FileID FROM Files WHERE (MachineID=@machineID1 or MachineID = @machineID2...) and (date= @date and size=@size and type=@type... ) all of this happens in runtime... other wise i have to create a for loop to put multiple machines one by one... and have multiple queries depending on the case the user selected... this is quiet interesting and i could use some help... thanks

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  • Memcache vs MySQL in memory

    - by TimK
    I have a database that won't grow much in size. It's current size is about 1 GB. Achieving the fastest performance is desired. Question: When should I use Memcache vs simply using MySQL Innodb ability to store all my content within RAM (innodb_buffer_pool_size)?

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  • MySQL query returning mysql_error

    - by Sebastian
    This returns mysql_error: <?php $name = $_POST['inputName2']; $email = $_POST['inputEmail2']; $instruments = $_POST['instruments']; $city = $_POST['inputCity']; $country = $_POST['inputCountry']; $distance = $_POST['distance']; // ^^ These all echo properly ^^ // CONNECT TO DB $dbhost = "xxx"; $dbname = "xxx"; $dbuser = "xxx"; $dbpass = "xxx"; $con = mysqli_connect("$dbhost", "$dbuser", "$dbpass", "$dbname"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } $query = "INSERT INTO depfinder (name, email, instrument1, instrument2, instrument3, instrument4, instrument5, city, country, max_distance) VALUES ($name, $email, $instruments[0], $instruments[1], $instruments[2], $instruments[3], $instruments[4], $city, $country, $max_distance)"; $result = mysqli_query($con, $query) or die(mysqli_error($con)); // script fails here if (!$result) { echo "There was a problem with the signup process. Please try again later."; } else { echo "Success"; } } ?> N.B. I'm not sure whether it's relevant, but the user may not choose five instruments so some $instrument[] array values may be empty. Bonus question: is my script secure enough or is there more I could do?

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  • PHPFOG and MySql

    - by jim dif
    I am playing around with PHPFog and as a result I ended up with a MySql database. I am trying to figure out how to connect to it with a success message. PHPFog says use this: mysql_connect( $server = getenv('MYSQL_DB_HOST'), $username = getenv('MYSQL_USERNAME'), $password = getenv('MYSQL_PASSWORD')); mysql_select_db(getenv('MYSQL_DB_NAME')); So I basically plug my variables into the above? Or Do I do something different? Thanks, Jim

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  • MySQL specifying exact order with WHERE `id` IN (...)

    - by Gray Fox
    Is there an easy way to order MySQL results respectively by WHERE id IN (...) clause? Example: SELECT * FROM articles WHERE articles.id IN (4, 2, 5, 9, 3) to return Article with id = 4 Article with id = 2 Article with id = 5 Article with id = 9 Article with id = 3 and also SELECT * FROM articles WHERE articles.id IN (4, 2, 5, 9, 3) LIMIT 2,2 to return Article with id = 5 Article with id = 9

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  • Connecting to remote mysql database with API

    - by Ajay
    I am designing a desktop application in C#, which needs to be connected to my online mysql database. I tried to give access in control panel a "%" which means from any IP, but it is not working. May be the hosting provider (bigrock) not allowing that. Alternatively, I am trying to write some code in online on PHP which will get the "sql" as parameter and returns the output as JSON format using json_encode. Is there any alternate methods which is better approach.

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  • MySQL : Insert Exactly Same Data Multiple Rows Without PHP Loop

    - by Robert Hanson
    I need to insert same data to my MySQL table without having PHP loop. The reason why I'm doing this is that because I have a column with Auto_Increment feature and that column associates with other table. So, I just need to insert some exactly same data and it's multiple rows (dynamic) but by using single INSERT syntax below : INSERT INTO outbox_multipart (TextDecoded) VALUES ('$SMSMessage') how to have this single INSERT syntax, but produce n number of rows?

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  • PHP, MySQL: Display only required parts of my website in sister website

    - by Devner
    Hi all, Now I have my website built on PHP & Mysql. Consider this like a forum. Now when a user posts a reply in my website 1 (ex. www.website1.com), I want to be able to show the starting thread and it's related replies in a sister website of mine. I want to do this in a way that it does not show the rest of the page & other page contents (like logo etc.). I don't think iframe would be a solution because an iframe would embed the whole page and the users visiting my sister website (totally different domain i.e. www.website2.com) would be able to see all the page contents, like logo etc. I want to avoid that. I want to make them see only limited information from website 1 and only the info. that I intend. I hope that makes sense. In a way, you could say that I am trying to replicate my 1 website, and show only a limited part of it. Users browsing 2nd website can post a reply in the 2nd website and it should automatically be posted & visible to the visitors of the website 1. Users of website 1 should not know that a user of website 2 has posted it. They would feel that some user from website 1 has posted it. Do I have to use 2 separate mysql DB or just 1? I think it would be problematic if I am trying to use different DB. I also feel I might have to face DB connectivity issues as I can connect to only 1 DB at a time. It's basically like users of website1.com should feel that they are replying to users of website1.com & users of website2.com should feel that they are replying to users of website2.com. (I need it this way to bridge the gap between them). At the same time I want to make the front end of the websites different so that they don't feel that they are replying to some other users outside the domain. These websites would be under my control and I will have access to the source code at any time. If I need to change the source code, these changes are welcome. Is this really possible? Thank you in advance.

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  • how to implement single sign on for asp.net,mysql websites

    - by kranthi
    Hi, I am using mysql database for my asp.net website.I need to implement to single sign on for multiple instances of my website.Currently to check if a user has logged in I am using a user control which checks for a "loggedin" cookie with single instance of the website.Now I need to extend the logic to achieve single signon for multiple instances of the same site. Could someone please help. Thanks.

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  • Change date format (in DB or output) to dd/mm/yyyy - PHP MySQL

    - by Jess
    MySQL stores the date in my database (by default) as 'YYYY-MM-DD' The field type for my date is 'DATE' (I do not need any time storage).. Is there a simple way to change it by default to DD/MM/YYYY ? I call up different dates in 2 different tables, and no where in any of my code do I have anything resembling a date variable or anything! Hopefully this is a straight forward change?

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  • Using array instead of lots of db queries in PHP

    - by Tural Teyyuboglu
    My function looks like that. It works but does lots of work (recursively calls itself and does lots of db queries.). There must be another way to do same thing but with array (with one query). I can't figure out how to modify this function to get it work with array. Please help. function genMenu($parent, $level, $menu, $utype) { global $db; $stmt=$db->prepare("select id, name FROM navigation WHERE parent = ? AND menu=? AND user_type=?") or die($db->error); $stmt->bind_param("iii", $parent, $menu, $utype) or die($stmt->error); $stmt->execute() or die($stmt->error); $stmt->store_result(); /* bind variables to prepared statement */ $stmt->bind_result($id, $name) or die($stmt->error); if ($level > 0 && $stmt->num_rows > 0) { echo "\n<ul>\n"; } while ($stmt->fetch()) { echo "<li>"; echo '<a href="?page=' . $id . '">' . $name . '</a>'; //display this level's children genMenu($id, $level+1, $menu, $utype); echo "</li>\n\n"; } if ($level > 0 && $stmt->num_rows > 0) { echo "</ul>\n"; } $stmt->close(); }

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