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  • Spring's JdbcDaoSupport (using MySQL Connector/J) fails after executing sql that adds FK

    - by John
    I am using Spring's JdbcDaoSupport class with a DriverManagerDataSource using the MySQL Connector/J 5.0 driver (driverClassName=com.mysql.jdbc.driver). allowMultiQueries is set to true in the url. My application is an in-house tool we recently developed that executes sql scripts in a directory one-by-one (allows us to re-create our schema and reference table data for a given date, etc, but I digress). The sql scripts sometime contain multiple statements (hence allowMultiQueries), so one script can create a table, add indexes for that table, etc. The problem happens when including a statement to add a foreign key constraint in one of these files. If I have a file that looks like... --(column/constraint names are examples) CREATE TABLE myTable ( fk1 BIGINT(19) NOT NULL, fk2 BIGINT(19) NOT NULL, PRIMARY KEY (fk1, fk2) ); ALTER TABLE myTable ADD CONSTRAINT myTable_fk1 FOREIGN KEY (fk1) REFERENCES myOtherTable (id) ; ALTER TABLE myTable ADD CONSTRAINT myTable_fk2 FOREIGN KEY (fk2) REFERENCES myOtherOtherTable (id) ; then JdbcTemplate.execute throws an UncategorizedSqlException with the following error message and stack trace: Exception in thread "main" org.springframework.jdbc.UncategorizedSQLException: StatementCallback; uncategorized SQLException for SQL [ THE SQL YOU SEE ABOVE LISTED HERE ]; SQL state [HY000]; error code [1005]; Can't create table 'myDatabase.myTable' (errno: 150); nested exception is java.sql.SQLException: Can't create table 'myDatabase.myTable' (errno: 150) at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java:83) at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java:80) at org.springframework.jdbc.support.AbstractFallbackSQLExceptionTranslator.translate(AbstractFallbackSQLExceptionTranslator.java:80) and the table and foreign keys are not inserted. Also, especially weird: if I take the foreign key statements out of the script I showed above and then place them in their own script that executes after (so I now have 1 script with just the create table statement, and 1 script with the add foreign key statements that executes after that) then what happens is: tool executes create table script, works fine, table is created tool executes add fk script, throws the same exception as seen above (except errno=121 this time), but the FKs actually get added (!!!) In other words, when the create table/FK statements are in the same script then the exception is thrown and nothing is created, but when they are different scripts a nearly identical exception is thrown but both things get created. Any help on this would be greatly appreciated. Please let me know if you'd like me to clarify anything more.

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  • kohana quotes in query.

    - by peter
    hey, i want to format a date in mysql using DATE_FORMAT(tblnews.datead, '%M %e, %Y, %l:%i%p') i cant seem to get the quotes right , so i keep getting errors. how would you put this in a query?

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  • combine lines from 2 prints to single line and insert into mysql database

    - by bleomycin
    Hello everyone i currently have this: import feedparser d = feedparser.parse('http://store.steampowered.com/feeds/news.xml') for i in range(10): print d.entries[i].title print d.entries[i].date How would i go about making it so that the title and date are on the same line? Also it doesn't need to print i just have that in there for testing, i would like to dump this output into a mysql db with the title and date, any help is greatly appreciated!

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  • Using <input type=file /> with J2EE/MySQL Backend

    - by Mark Hazlett
    Hey everyone, I'm wondering how I can hook up an input type=file to send a picture back to a backend servlet that will eventually be stored in a MySQL database as a BLOB? In other words, how can I upload a picture using the input and send that back to the servlet to insert into the database as a BLOB type? Thanks

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  • php mysql search

    - by mckenzie
    Hello, My code contain SELECT * FROM newchap WHERE company LIKE '%$company%' OR Category LIKE '%$cat%' It works perfectly however, when the field $company contain empty, it return all result in MYSQL. How to prevent it?

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  • CakePHP - Paginate / Query: find lowest of multiple fields & order by it

    - by Atea
    I am using CakePHP for a price-comparison website. I have a table products with fields: id, pride_regular, price_action. I would like to combine the fields price_regular and price_action into a dynamic field: price. The lowest value of these two fields should be the value of the new price field. Also I want to order on it Ascending. Should I use a custom MySQL-query?

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  • PHP & MySQL Undefined variable problem

    - by comma
    I keep getting the following error Undefined variable: id on line 91 can some one help me correct this problem? The error is on this line. $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; MySQL database tables. CREATE TABLE tags ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill VARCHAR(255) NOT NULL, experience VARCHAR(255) NOT NULL, years VARCHAR(255) NOT NULL, PRIMARY KEY (id) ); CREATE TABLE users_skills ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill_id INT UNSIGNED NOT NULL, user_id INT UNSIGNED NOT NULL, date_created DATETIME UNSIGNED NOT NULL, PRIMARY KEY (id) ); Here is the PHP & MySQL code. if (isset($_POST['info_submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); if (!$dbc) { print mysqli_error($mysqli); return; } $user_id = '5'; $skill = $_POST['skill']; $experience = $_POST['experience']; $years = $_POST['years']; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON users_skills.skill_id = learned_skills.id WHERE users_skills.user_id='$user_id'"); if (mysqli_num_rows($dbc) == 0) { if (isset($_POST['skill']) && trim($_POST['skill'])!=='') { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $skill . "', '" . $experience . "', '" . $years . "')"); if (mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT id FROM learned_skills WHERE id='" . $skill . "' AND experience='" . $experience . "' AND years='" . $years . "'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $id = $row["id"]; } } $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; } }

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  • Splitting data from MySQL using PHP & Javascript works in IE but not in FF

    - by MTSzabo
    I have the following JavaScript function on a page: function setFields(){ var menu = document.getElementById('EditLocation'); var itemDataArray = menu[menu.selectedIndex].value.split('|'); form.LocationShortName.value = itemDataArray[0]; form.LocationLongName.value = itemDataArray[1]; form.Phone.value = itemDataArray[2]; form.Address1.value = itemDataArray[3]; form.CityStateZip.value = itemDataArray[4]; form.MapLink.value = itemDataArray[5]; } Down on the Form, I have the following: <select class="input2" name="EditLocation" id="EditLocation" onchange = "setFields();"> <option value="-Add New-"<?php if($editlocation=='-Add New-'){echo(' selected="selected"');} ?>>-Add New-</option> <?php require_once('connection.php'); $connection = mysql_connect($hostname,$username,$password) or die (mysql_errno().": ".mysql_error()."<BR />"); mysql_select_db($database); $sql = "SELECT * FROM directions ORDER BY dirshortname"; $query = mysql_query($sql); while ($row = mysql_fetch_array($query)) { echo('<option value="'.stripslashes($row['dirshortname']).'|'.stripslashes($row['dirlongname']).'|'.stripslashes($row['dirphone']).'|'.stripslashes($row['dirstreet']).'|'.stripslashes($row['dircsz']).'|'.stripslashes($row['dirmaplink']).'"'); if ($editlocation==stripslashes($row['dirshortname'])) { echo(' selected="selected"'); } echo('>'.stripslashes($row['dirshortname']).'</option>'); } ?> In essence, the PHP is supposed to pack the data elements pulled from MySQL into the OPTION VALUE portion of the SELECT box. Once the user selects a record, the JavaScript pulls the packed data apart and populates the other data elements on the FORM. It all works wonderfully in IE, but in FF the fields do not populate with data. The form is somewhat long, but I'll include it anyway for the sake of completeness. <form action="admin-dirs.php" method="post" enctype="multipart/form-data" style="margin:0px; padding:0px " id="form"> <table width="587" border="0" cellspacing="0" cellpadding="0"> <tr> <td width="60">&nbsp;</td> <td width="185">Select Location to Edit: </td> <td width="342"><select class="input2" name="EditLocation" id="EditLocation" onchange = "setFields();"> <option value="-Add New-"<?php if($editlocation=='-Add New-'){echo(' selected="selected"');} ?>>-Add New-</option> <?php require_once('connection.php'); $connection = mysql_connect($hostname,$username,$password) or die (mysql_errno().": ".mysql_error()."<BR />"); mysql_select_db($database); $sql = "SELECT * FROM directions ORDER BY dirshortname"; $query = mysql_query($sql); while ($row = mysql_fetch_array($query)) { echo('<option value="'.stripslashes($row['dirshortname']).'|'.stripslashes($row['dirlongname']).'|'.stripslashes($row['dirphone']).'|'.stripslashes($row['dirstreet']).'|'.stripslashes($row['dircsz']).'|'.stripslashes($row['dirmaplink']).'"'); if ($editlocation==stripslashes($row['dirshortname'])) { echo(' selected="selected"'); } echo('>'.stripslashes($row['dirshortname']).'</option>'); } ?> </select></td> </tr> <tr> <td width="60">&nbsp;</td> <td colspan="2"><span class="main" style=" padding-left:12px; padding-right:12px; padding-top:6px"><br /> (Note: Leaving the Long Name blank will duplicate the Short Name.)</span></td> </tr> <?php if(!$errlocationshortname=='' ){echo(' <tr> <td width="60">&nbsp;</td> <td width="185">&nbsp;</td> <td width="342"><span class="redtxterror">'.$errlocationshortname.'</span></td> </tr>');} ?> <tr> <td>&nbsp;</td> <td>Location Short Name: <span class="red_star">*</span> </td> <td><input name="LocationShortName" id="LocationShortName" type="text" class="input2<?php if(!$errlocationshortname==''){echo('r');} ?>" value="<?php echo($locationshortname); ?>" maxlength="50"></td> </tr> <?php if(!$errlocationlongname=='' ){echo(' <tr> <td width="60">&nbsp;</td> <td width="185">&nbsp;</td> <td width="342"><span class="redtxterror">'.$errlocationlongname.'</span></td> </tr>');} ?> <tr> <td>&nbsp;</td> <td>Location Long Name: <span class="red_star">*</span> </td> <td><input name="LocationLongName" id="LocationLongName" type="text" class="input2<?php if(!$errlocationlongname==''){echo('r');} ?>" value="<?php echo($locationlongname); ?>" maxlength="50"></td> </tr> <?php if(!$erraddress=='' ){echo(' <tr> <td width="60">&nbsp;</td> <td width="185">&nbsp;</td> <td width="342"><span class="redtxterror">'.$erraddress.'</span></td> </tr>');} ?> <tr> <td>&nbsp;</td> <td>Street Address: <span class="red_star">*</span> </td> <td><input name="Address1" id="Address1" type="text" class="input2<?php if(!$erraddress==''){echo('r');} ?>" value="<?php echo($address); ?>"></td> </tr> <?php if(!$errcsz=='' ){echo(' <tr> <td width="60">&nbsp;</td> <td width="185">&nbsp;</td> <td width="342"><span class="redtxterror">'.$errcsz.'</span></td> </tr>');} ?> <tr> <td>&nbsp;</td> <td>City, State, Zip: <span class="red_star">*</span> </td> <td><input name="CityStateZip" id="CityStateZip" type="text" class="input2<?php if(!$errcsz==''){echo('r');} ?>" value="<?php echo($csz); ?>"></td> </tr> <?php if(!$errphone=='' ){echo(' <tr> <td width="60">&nbsp;</td> <td width="185">&nbsp;</td> <td width="342"><span class="redtxterror">'.$errphone.'</span></td> </tr>');} ?> <tr> <td>&nbsp;</td> <td>Location Phone Number: <span class="red_star">*</span> </td> <td><input name="Phone" id="Phone" type="text" class="input2<?php if(!$errphone==''){echo('r');} ?>" value="<?php echo($phone); ?>" maxlength="20"></td> </tr> <?php if(!$errmaplink=='' ){echo(' <tr> <td width="60">&nbsp;</td> <td width="185">&nbsp;</td> <td width="342"><span class="redtxterror">'.$errmaplink.'</span></td> </tr>');} ?> <tr> <td>&nbsp;</td> <td>Paste Link to Map: <span class="red_star">*</span> </td> <td><input name="MapLink" id="MapLink" type="text" class="input2<?php if(!$errmaplink==''){echo('r');} ?>" value="<?php echo($maplink); ?>" maxlength="125"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><div align="right" style="padding-right:25px"> <input type="hidden" id="action" name="action" value="submitform" /> <input type="submit" id="savenew" name="savenew" value="Save & New" /> <input type="submit" id="submit" name="submit" value="Save & Close" /> <?php if(!isset($_POST['action'])) {?> <input type="reset" id="reset" name="reset" value="Reset" /> <?php } ?> </div></td> </tr><tr> <td>&nbsp;</td> <td>&nbsp;</td> <td class="main_d"><div align="right" style="padding-right:25px">Your IP Address is Logged as: <?php echo($ip); ?></div></td> </tr> </table> </form>

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  • MySQL optimised code for 2 tables?

    - by David19801
    Hi, I have 2 tables, Table1: id,int1,int2,int3,int4,int5 Table2: integers (autoincrement),blobdata The query I want to use is given the id I want to get the blobdata from table2 associated with the 5 integers in table1. I've only ever used one table in mysql so have no idea how to do this properly. Is it possible? EDIT: id is username, integers in table2 is just integers. but have not built the tables yet, so can change if need to.

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  • MySql TABLE data type

    - by Neil Aitken
    MS SQL Server has a TABLE data type which can be used in stored procedures, Does anybody know if MySQL has an equivalent data type? I've had a look over the docs but can't seem to find anything, so I presume it doesn't exist, but perhaps somebody has created a workaround

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  • how to implement single sign on for asp.net,mysql websites

    - by kranthi
    Hi, I am using mysql database for my asp.net website.I need to implement to single sign on for multiple instances of my website.Currently to check if a user has logged in I am using a user control which checks for a "loggedin" cookie with single instance of the website.Now I need to extend the logic to achieve single signon for multiple instances of the same site. Could someone please help. Thanks.

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  • connect to mysql server using realbasic

    - by Gbolahan
    Hello, tried connecting to mysql server in realbasic using the folowing code: dim db as MySQLCommunityServer db=New MySQLCommunityServer db.host="192.168.240.129" db.port=3306 db.databaseName="test" db.userName="test" db.Password="test" If db.Connect() then txt1.Text = "Connected" else txt1.Text = "Connection failed!"+ chr(13)+db.ErrorMessage end if and i get the following message connection failed! any suggestions.. Thanks

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  • Mysql Syntax Error

    - by tarnfeld
    Any idea why this is popping up :( ? You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CREATE TABLE `clocks` ( `id` int(11) NOT NULL AUTO_INCREMENT, ' at line 6

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  • mysql query timer for .net

    - by acidzombie24
    Is there something i can use to track how long my mysql queries take? perhaps log them if they take a certain amount of time? or track all queries but only hold the longest query time? using this with C# .NET with ASP.NET. I'd like to use this to occasionally check if my queries are getting slow.

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  • MySQL specifying exact order with WHERE `id` IN (...)

    - by Gray Fox
    Is there an easy way to order MySQL results respectively by WHERE id IN (...) clause? Example: SELECT * FROM articles WHERE articles.id IN (4, 2, 5, 9, 3) to return Article with id = 4 Article with id = 2 Article with id = 5 Article with id = 9 Article with id = 3 and also SELECT * FROM articles WHERE articles.id IN (4, 2, 5, 9, 3) LIMIT 2,2 to return Article with id = 5 Article with id = 9

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  • Creating tables and inserting data (MySQL Dump) using PHP Doctrine 1.2

    - by Dimitry
    Hello. I got a script that create a new database, now I need to fill that database with tables and values (from a MySQL dump file). I'm using PHP - Doctrine 1.2. Here is how I create the database: $manager = Doctrine_Manager::getInstance(); $newConn = $manager->openConnection($customer->Config->db_connection_string); $newConn->createDatabase(); How I do this? Thanks!

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  • MySQL from Silverlight on Linux Server

    - by cam
    I'm trying to access a MySQL database through Silverlight, and I know you can't do it directly, but the only way I know of is to use a WCF service. This won't run on the server I have, is there any other way to access the database (through PHP maybe)?

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  • PHP, MySQL: Display only required parts of my website in sister website

    - by Devner
    Hi all, Now I have my website built on PHP & Mysql. Consider this like a forum. Now when a user posts a reply in my website 1 (ex. www.website1.com), I want to be able to show the starting thread and it's related replies in a sister website of mine. I want to do this in a way that it does not show the rest of the page & other page contents (like logo etc.). I don't think iframe would be a solution because an iframe would embed the whole page and the users visiting my sister website (totally different domain i.e. www.website2.com) would be able to see all the page contents, like logo etc. I want to avoid that. I want to make them see only limited information from website 1 and only the info. that I intend. I hope that makes sense. In a way, you could say that I am trying to replicate my 1 website, and show only a limited part of it. Users browsing 2nd website can post a reply in the 2nd website and it should automatically be posted & visible to the visitors of the website 1. Users of website 1 should not know that a user of website 2 has posted it. They would feel that some user from website 1 has posted it. Do I have to use 2 separate mysql DB or just 1? I think it would be problematic if I am trying to use different DB. I also feel I might have to face DB connectivity issues as I can connect to only 1 DB at a time. It's basically like users of website1.com should feel that they are replying to users of website1.com & users of website2.com should feel that they are replying to users of website2.com. (I need it this way to bridge the gap between them). At the same time I want to make the front end of the websites different so that they don't feel that they are replying to some other users outside the domain. These websites would be under my control and I will have access to the source code at any time. If I need to change the source code, these changes are welcome. Is this really possible? Thank you in advance.

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  • mysql IN parameter

    - by proyb2
    When the user check more than one (checkbox) option which are then combine into a string of "apple,orange,pear" SELECT id, pos, FROM $db WHERE dtime>='$now' AND jsub IN ('$arr[1]') ; When I pass the string to $arr[1], it won't work correctly, how do I split into array and get mysql IN function to process correctly?

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