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  • MySQL Group By and bracketing according to age.

    - by text
    Is that possible that MySQL can handle grouping of data according to age bracket? In my users table, age value is their actual age. I want to group them according to age bracket. For example: ages below 1 year old as age1, 1-4 yrs as age2, 5-9 yrs. old as age3 and so on.

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  • Change date format (in DB or output) to dd/mm/yyyy - PHP MySQL

    - by Jess
    MySQL stores the date in my database (by default) as 'YYYY-MM-DD' The field type for my date is 'DATE' (I do not need any time storage).. Is there a simple way to change it by default to DD/MM/YYYY ? I call up different dates in 2 different tables, and no where in any of my code do I have anything resembling a date variable or anything! Hopefully this is a straight forward change?

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  • Mysql Syntax Error

    - by tarnfeld
    Any idea why this is popping up :( ? You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CREATE TABLE `clocks` ( `id` int(11) NOT NULL AUTO_INCREMENT, ' at line 6

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  • CakePHP - Paginate / Query: find lowest of multiple fields & order by it

    - by Atea
    I am using CakePHP for a price-comparison website. I have a table products with fields: id, pride_regular, price_action. I would like to combine the fields price_regular and price_action into a dynamic field: price. The lowest value of these two fields should be the value of the new price field. Also I want to order on it Ascending. Should I use a custom MySQL-query?

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  • Using <input type=file /> with J2EE/MySQL Backend

    - by Mark Hazlett
    Hey everyone, I'm wondering how I can hook up an input type=file to send a picture back to a backend servlet that will eventually be stored in a MySQL database as a BLOB? In other words, how can I upload a picture using the input and send that back to the servlet to insert into the database as a BLOB type? Thanks

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  • Splitting data from MySQL using PHP & Javascript works in IE but not in FF

    - by MTSzabo
    I have the following JavaScript function on a page: function setFields(){ var menu = document.getElementById('EditLocation'); var itemDataArray = menu[menu.selectedIndex].value.split('|'); form.LocationShortName.value = itemDataArray[0]; form.LocationLongName.value = itemDataArray[1]; form.Phone.value = itemDataArray[2]; form.Address1.value = itemDataArray[3]; form.CityStateZip.value = itemDataArray[4]; form.MapLink.value = itemDataArray[5]; } Down on the Form, I have the following: <select class="input2" name="EditLocation" id="EditLocation" onchange = "setFields();"> <option value="-Add New-"<?php if($editlocation=='-Add New-'){echo(' selected="selected"');} ?>>-Add New-</option> <?php require_once('connection.php'); $connection = mysql_connect($hostname,$username,$password) or die (mysql_errno().": ".mysql_error()."<BR />"); mysql_select_db($database); $sql = "SELECT * FROM directions ORDER BY dirshortname"; $query = mysql_query($sql); while ($row = mysql_fetch_array($query)) { echo('<option value="'.stripslashes($row['dirshortname']).'|'.stripslashes($row['dirlongname']).'|'.stripslashes($row['dirphone']).'|'.stripslashes($row['dirstreet']).'|'.stripslashes($row['dircsz']).'|'.stripslashes($row['dirmaplink']).'"'); if ($editlocation==stripslashes($row['dirshortname'])) { echo(' selected="selected"'); } echo('>'.stripslashes($row['dirshortname']).'</option>'); } ?> In essence, the PHP is supposed to pack the data elements pulled from MySQL into the OPTION VALUE portion of the SELECT box. Once the user selects a record, the JavaScript pulls the packed data apart and populates the other data elements on the FORM. It all works wonderfully in IE, but in FF the fields do not populate with data. The form is somewhat long, but I'll include it anyway for the sake of completeness. <form action="admin-dirs.php" method="post" enctype="multipart/form-data" style="margin:0px; padding:0px " id="form"> <table width="587" border="0" cellspacing="0" cellpadding="0"> <tr> <td width="60">&nbsp;</td> <td width="185">Select Location to Edit: </td> <td width="342"><select class="input2" name="EditLocation" id="EditLocation" onchange = "setFields();"> <option value="-Add New-"<?php if($editlocation=='-Add New-'){echo(' selected="selected"');} ?>>-Add New-</option> <?php require_once('connection.php'); $connection = mysql_connect($hostname,$username,$password) or die (mysql_errno().": ".mysql_error()."<BR />"); mysql_select_db($database); $sql = "SELECT * FROM directions ORDER BY dirshortname"; $query = mysql_query($sql); while ($row = mysql_fetch_array($query)) { echo('<option value="'.stripslashes($row['dirshortname']).'|'.stripslashes($row['dirlongname']).'|'.stripslashes($row['dirphone']).'|'.stripslashes($row['dirstreet']).'|'.stripslashes($row['dircsz']).'|'.stripslashes($row['dirmaplink']).'"'); if ($editlocation==stripslashes($row['dirshortname'])) { echo(' selected="selected"'); } echo('>'.stripslashes($row['dirshortname']).'</option>'); } ?> </select></td> </tr> <tr> <td width="60">&nbsp;</td> <td colspan="2"><span class="main" style=" padding-left:12px; padding-right:12px; padding-top:6px"><br /> (Note: Leaving the Long Name blank will duplicate the Short Name.)</span></td> </tr> <?php if(!$errlocationshortname=='' ){echo(' <tr> <td width="60">&nbsp;</td> <td width="185">&nbsp;</td> <td width="342"><span class="redtxterror">'.$errlocationshortname.'</span></td> </tr>');} ?> <tr> <td>&nbsp;</td> <td>Location Short Name: <span class="red_star">*</span> </td> <td><input name="LocationShortName" id="LocationShortName" type="text" class="input2<?php if(!$errlocationshortname==''){echo('r');} ?>" value="<?php echo($locationshortname); ?>" maxlength="50"></td> </tr> <?php if(!$errlocationlongname=='' ){echo(' <tr> <td width="60">&nbsp;</td> <td width="185">&nbsp;</td> <td width="342"><span class="redtxterror">'.$errlocationlongname.'</span></td> </tr>');} ?> <tr> <td>&nbsp;</td> <td>Location Long Name: <span class="red_star">*</span> </td> <td><input name="LocationLongName" id="LocationLongName" type="text" class="input2<?php if(!$errlocationlongname==''){echo('r');} ?>" value="<?php echo($locationlongname); ?>" maxlength="50"></td> </tr> <?php if(!$erraddress=='' ){echo(' <tr> <td width="60">&nbsp;</td> <td width="185">&nbsp;</td> <td width="342"><span class="redtxterror">'.$erraddress.'</span></td> </tr>');} ?> <tr> <td>&nbsp;</td> <td>Street Address: <span class="red_star">*</span> </td> <td><input name="Address1" id="Address1" type="text" class="input2<?php if(!$erraddress==''){echo('r');} ?>" value="<?php echo($address); ?>"></td> </tr> <?php if(!$errcsz=='' ){echo(' <tr> <td width="60">&nbsp;</td> <td width="185">&nbsp;</td> <td width="342"><span class="redtxterror">'.$errcsz.'</span></td> </tr>');} ?> <tr> <td>&nbsp;</td> <td>City, State, Zip: <span class="red_star">*</span> </td> <td><input name="CityStateZip" id="CityStateZip" type="text" class="input2<?php if(!$errcsz==''){echo('r');} ?>" value="<?php echo($csz); ?>"></td> </tr> <?php if(!$errphone=='' ){echo(' <tr> <td width="60">&nbsp;</td> <td width="185">&nbsp;</td> <td width="342"><span class="redtxterror">'.$errphone.'</span></td> </tr>');} ?> <tr> <td>&nbsp;</td> <td>Location Phone Number: <span class="red_star">*</span> </td> <td><input name="Phone" id="Phone" type="text" class="input2<?php if(!$errphone==''){echo('r');} ?>" value="<?php echo($phone); ?>" maxlength="20"></td> </tr> <?php if(!$errmaplink=='' ){echo(' <tr> <td width="60">&nbsp;</td> <td width="185">&nbsp;</td> <td width="342"><span class="redtxterror">'.$errmaplink.'</span></td> </tr>');} ?> <tr> <td>&nbsp;</td> <td>Paste Link to Map: <span class="red_star">*</span> </td> <td><input name="MapLink" id="MapLink" type="text" class="input2<?php if(!$errmaplink==''){echo('r');} ?>" value="<?php echo($maplink); ?>" maxlength="125"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><div align="right" style="padding-right:25px"> <input type="hidden" id="action" name="action" value="submitform" /> <input type="submit" id="savenew" name="savenew" value="Save & New" /> <input type="submit" id="submit" name="submit" value="Save & Close" /> <?php if(!isset($_POST['action'])) {?> <input type="reset" id="reset" name="reset" value="Reset" /> <?php } ?> </div></td> </tr><tr> <td>&nbsp;</td> <td>&nbsp;</td> <td class="main_d"><div align="right" style="padding-right:25px">Your IP Address is Logged as: <?php echo($ip); ?></div></td> </tr> </table> </form>

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  • Use MySQL trigger to update another table when duplicate key found

    - by Jason
    Been scratching my head on this one, hoping one of you kind people and direct me towards solving this problem. I have a mysql table of customers, it contains a lot of data, but for the purpose of this question, we only need to worry about 4 columns 'ID', 'Firstname', 'Lastname', 'Postcode' Problem is, the table contains a lot of duplicated customers. A new table is being created where each customer is unique and for us, we decide a unique customer is based on 'Firstname', 'Lastname' and 'Postcode' However, (this is the important bit) we need to ensure each new "unique" customer record also can be matched to the original multiple entries of that customer in the original table. I believe the best way to do this is to have a third table, that has 'NewUniqueID', 'OldCustomerID'. So we can search this table for 'NewUniqueID' = '123' and it would return multiple 'OldCustomerID' values where appropriate. I am hoping to make this work using a trigger and the on duplicate key syntax. So what would happen is as follows: An query is run taking the old customer table and inserting it in to the new unique table. (A standard Insert Select query) On duplicate key continue adding records, but add one entry in to the third table noting the 'NewUniqueID' that duped along with the 'OldCustomerID' of the record we were trying to insert. Hope this makes sense, my apologies if it isn't clear. I welcome and appreciate any thoughts on this one! Many thanks Jason

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  • Check if row exists, if not add it [MySQL]

    - by Steven
    I need to add a row to a MySQL database table but only if the row doesn't already exist. My database server just went down so I can't test this, but will this work as expected? INSERT INTO `blocks` (`block_file`,`settings_group`) VALUES ('announcements','announcement_settings') WHERE NOT EXISTS (SELECT `block_file`,`settings_group` FROM `blocks` WHERE `block_file`='announcements' AND `settings_group`='announcement_settings') It seems like sound logic. Is this a valid query or is there a better way of doing this?

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  • how to implement single sign on for asp.net,mysql websites

    - by kranthi
    Hi, I am using mysql database for my asp.net website.I need to implement to single sign on for multiple instances of my website.Currently to check if a user has logged in I am using a user control which checks for a "loggedin" cookie with single instance of the website.Now I need to extend the logic to achieve single signon for multiple instances of the same site. Could someone please help. Thanks.

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  • MySQL optimised code for 2 tables?

    - by David19801
    Hi, I have 2 tables, Table1: id,int1,int2,int3,int4,int5 Table2: integers (autoincrement),blobdata The query I want to use is given the id I want to get the blobdata from table2 associated with the 5 integers in table1. I've only ever used one table in mysql so have no idea how to do this properly. Is it possible? EDIT: id is username, integers in table2 is just integers. but have not built the tables yet, so can change if need to.

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  • Creating tables and inserting data (MySQL Dump) using PHP Doctrine 1.2

    - by Dimitry
    Hello. I got a script that create a new database, now I need to fill that database with tables and values (from a MySQL dump file). I'm using PHP - Doctrine 1.2. Here is how I create the database: $manager = Doctrine_Manager::getInstance(); $newConn = $manager->openConnection($customer->Config->db_connection_string); $newConn->createDatabase(); How I do this? Thanks!

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  • MySQL crash. Unknown cause. Signal 11

    - by fortmac
    This is a database that I installed ~6 months ago and had been running fine. This is currently running in Ubuntu 12.04. Attempting to connect to MySQL causes this error: ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (111) Then theres: $ sudo mysqld which returns: 130702 15:38:54 [Note] Plugin 'FEDERATED' is disabled. 130702 15:38:54 InnoDB: The InnoDB memory heap is disabled 130702 15:38:54 InnoDB: Mutexes and rw_locks use GCC atomic builtins 130702 15:38:54 InnoDB: Compressed tables use zlib 1.2.3.4 130702 15:38:54 InnoDB: Initializing buffer pool, size = 128.0M 130702 15:38:54 InnoDB: Completed initialization of buffer pool 130702 15:38:54 InnoDB: highest supported file format is Barracuda. InnoDB: The log sequence number in ibdata files does not match InnoDB: the log sequence number in the ib_logfiles! 130702 15:38:54 InnoDB: Database was not shut down normally! InnoDB: Starting crash recovery. InnoDB: Reading tablespace information from the .ibd files... InnoDB: Restoring possible half-written data pages from the doublewrite InnoDB: buffer... 130702 15:38:55 InnoDB: Waiting for the background threads to start 130702 15:38:56 InnoDB: 1.1.8 started; log sequence number 5201901917 130702 15:38:56 [Note] Server hostname (bind-address): '127.0.0.1'; port: 3306 130702 15:38:56 [Note] - '127.0.0.1' resolves to '127.0.0.1'; 130702 15:38:56 [Note] Server socket created on IP: '127.0.0.1'. 130702 15:38:56 [Note] Event Scheduler: Loaded 0 events 130702 15:38:56 [Note] mysqld: ready for connections. Version: '5.5.28-0ubuntu0.12.04.3' socket: '/var/run/mysqld/mysqld.sock' port: 3306 (Ubuntu) 19:39:02 UTC - mysqld got signal 11 ; This could be because you hit a bug. It is also possible that this binary or one of the libraries it was linked against is corrupt, improperly built, or misconfigured. This error can also be caused by malfunctioning hardware. We will try our best to scrape up some info that will hopefully help diagnose the problem, but since we have already crashed, something is definitely wrong and this may fail. key_buffer_size=16777216 read_buffer_size=131072 max_used_connections=1 max_threads=151 thread_count=1 connection_count=1 It is possible that mysqld could use up to key_buffer_size + (read_buffer_size + sort_buffer_size)*max_threads = 346681 K bytes of memory Hope that's ok; if not, decrease some variables in the equation. Thread pointer: 0x7f9509e51530 Attempting backtrace. You can use the following information to find out where mysqld died. If you see no messages after this, something went terribly wrong... stack_bottom = 7f94f1d3de60 thread_stack 0x30000 mysqld(my_print_stacktrace+0x29)[0x7f95083427b9] mysqld(handle_fatal_signal+0x483)[0x7f9508209b43] /lib/x86_64-linux-gnu/libpthread.so.0(+0xfcb0)[0x7f9506f5bcb0] mysqld(+0x320e1c)[0x7f9508113e1c] mysqld(_ZN4JOIN15alloc_func_listEv+0x9c)[0x7f950812391c] mysqld(_ZN4JOIN7prepareEPPP4ItemP10TABLE_LISTjS1_jP8st_orderS7_S1_S7_P13st_select_lexP18st_select_lex_unit+0x918)[0x7f9508124658] mysqld(_Z12mysql_selectP3THDPPP4ItemP10TABLE_LISTjR4ListIS1_ES2_jP8st_orderSB_S2_SB_yP13select_resultP18st_select_lex_unitP13st_select_lex+0x130)[0x7f950812d060] mysqld(_Z13handle_selectP3THDP3LEXP13select_resultm+0x17c)[0x7f9508132fbc] mysqld(+0x2f6714)[0x7f95080e9714] mysqld(_Z21mysql_execute_commandP3THD+0x16d8)[0x7f95080f1178] mysqld(_Z11mysql_parseP3THDPcjP12Parser_state+0x10f)[0x7f95080f5e0f] mysqld(_Z16dispatch_command19enum_server_commandP3THDPcj+0x1380)[0x7f95080f7260] mysqld(_Z24do_handle_one_connectionP3THD+0x1bd)[0x7f950819b80d] mysqld(handle_one_connection+0x50)[0x7f950819b870] /lib/x86_64-linux-gnu/libpthread.so.0(+0x7e9a)[0x7f9506f53e9a] /lib/x86_64-linux-gnu/libc.so.6(clone+0x6d)[0x7f9506684cbd] Trying to get some variables. Some pointers may be invalid and cause the dump to abort. Query (7f94e0004b80): is an invalid pointer Connection ID (thread ID): 1 Status: NOT_KILLED The manual page at http://dev.mysql.com/doc/mysql/en/crashing.html contains information that should help you find out what is causing the crash. I'm at a loss. What other reports would be useful in diagnosing this? /var/log/mysql.err & /var/log/mysql.log are empty.

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  • build SQL query string using user input

    - by user175084
    i have to make a string by using the values which the user selects on the webpage suppose i need to display files for multiple machines with differnt search criteria.. i currently use this code: DataTable dt = new DataTable(); SqlConnection connection = new SqlConnection(); connection.ConnectionString = ConfigurationManager.ConnectionStrings["DBConnectionString"].ConnectionString; connection.Open(); SqlCommand sqlCmd = new SqlCommand("SELECT FileID FROM Files WHERE MachineID=@machineID and date= @date", connection); SqlDataAdapter sqlDa = new SqlDataAdapter(sqlCmd); sqlCmd.Parameters.AddWithValue("@machineID", machineID); sqlCmd.Parameters.AddWithValue("@date", date); sqlDa.Fill(dt); now this is fixed query where the user just has one machine and just selects one date... i want to make a query in which the user has multiple search options like type or size if he wants depending on what he selects also if he can select multiple machines.. SELECT FileID FROM Files WHERE (MachineID=@machineID1 or MachineID = @machineID2...) and (date= @date and size=@size and type=@type... ) all of this happens in runtime... other wise i have to create a for loop to put multiple machines one by one... and have multiple queries depending on the case the user selected... this is quiet interesting and i could use some help... thanks

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  • connect to mysql server using realbasic

    - by Gbolahan
    Hello, tried connecting to mysql server in realbasic using the folowing code: dim db as MySQLCommunityServer db=New MySQLCommunityServer db.host="192.168.240.129" db.port=3306 db.databaseName="test" db.userName="test" db.Password="test" If db.Connect() then txt1.Text = "Connected" else txt1.Text = "Connection failed!"+ chr(13)+db.ErrorMessage end if and i get the following message connection failed! any suggestions.. Thanks

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  • MySql TABLE data type

    - by Neil Aitken
    MS SQL Server has a TABLE data type which can be used in stored procedures, Does anybody know if MySQL has an equivalent data type? I've had a look over the docs but can't seem to find anything, so I presume it doesn't exist, but perhaps somebody has created a workaround

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  • kohana quotes in query.

    - by peter
    hey, i want to format a date in mysql using DATE_FORMAT(tblnews.datead, '%M %e, %Y, %l:%i%p') i cant seem to get the quotes right , so i keep getting errors. how would you put this in a query?

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  • PHP, MySQL: Display only required parts of my website in sister website

    - by Devner
    Hi all, Now I have my website built on PHP & Mysql. Consider this like a forum. Now when a user posts a reply in my website 1 (ex. www.website1.com), I want to be able to show the starting thread and it's related replies in a sister website of mine. I want to do this in a way that it does not show the rest of the page & other page contents (like logo etc.). I don't think iframe would be a solution because an iframe would embed the whole page and the users visiting my sister website (totally different domain i.e. www.website2.com) would be able to see all the page contents, like logo etc. I want to avoid that. I want to make them see only limited information from website 1 and only the info. that I intend. I hope that makes sense. In a way, you could say that I am trying to replicate my 1 website, and show only a limited part of it. Users browsing 2nd website can post a reply in the 2nd website and it should automatically be posted & visible to the visitors of the website 1. Users of website 1 should not know that a user of website 2 has posted it. They would feel that some user from website 1 has posted it. Do I have to use 2 separate mysql DB or just 1? I think it would be problematic if I am trying to use different DB. I also feel I might have to face DB connectivity issues as I can connect to only 1 DB at a time. It's basically like users of website1.com should feel that they are replying to users of website1.com & users of website2.com should feel that they are replying to users of website2.com. (I need it this way to bridge the gap between them). At the same time I want to make the front end of the websites different so that they don't feel that they are replying to some other users outside the domain. These websites would be under my control and I will have access to the source code at any time. If I need to change the source code, these changes are welcome. Is this really possible? Thank you in advance.

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  • how to fetch data from multiple tables MySQL

    - by faisal
    hi all, I am looking some help in php+MySQL+jquery I have 2 tables table1 table 1 have 4 colume (id, title, desc, thumb_img) tabel2 table 2 have 3 colume(id, table1id, img) I just want to compare 2 table with the value of $_get['QS']; and show the records from both (title, desc, img) Looking forward for the help.:)

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  • Copying MYSQL backup to another server

    - by Yeti
    I'm new to SSH. How to copy a .gz file from one server to another using SSH? I'm using cron to backup mysql databases and want to also automate the process of copying the .gz files a different web host. Any information on the limit of file size that can be copied would also be great. The backup file size range from 100 MB to few GB.

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