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  • Php + mysql transactions examples

    - by Donator
    I really haven't found normal example of php file where mysql transactions are being used. Can you show me simple example of that? And one more question. I've already created a lot of programming and didn't use transaction, maybe I can put any php function or smth to header.php that if one mysql_query fails, then others too? Thank you.

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  • Saving images in database mysql

    - by xRobot
    My client have created a script in php+mysql that saves images directly in the database and every images has url like this: www.example.com/image.php?id=421 In your opinion this is a very wrong solution ? Should I rebuild all the site ? There are about 1000 visits per day and about 600 images in the database. This is the site: http://tinyurl.com/3xkxdsw

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  • Efficient way to build a MySQL update query in Python

    - by ensnare
    I have a class variable called attributes which lists the instance variables I want to update in a database: attributes = ['id', 'first_name', 'last_name', 'name', 'name_url', 'email', 'password', 'password_salt', 'picture_id'] Each of the class attributes are updated upon instantiation. I would like to loop through each of the attributes and build a MySQL update query in the form of: UPDATE members SET id = self._id, first_name = self._first name ... Thanks.

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  • Migrate MySQL database to Sql Server

    - by RPK
    I recently encountered a problem in my production database due to MySQL bug. The bug is in the TimeStamp column. To avoid any inconvenience, I want to migrate the database to either Sql Server. Is there any FREE tool to easily and reliably migrate data and table structures?

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  • mysql command for update

    - by Mac Taylor
    hey guys i need to add a special text to all rows in my mysql table , how to add some text to the end of all rows' content in a table just for one field i used this code : UPDATE `blogs` SET `title`= `title`+ 'mytext'; but didnt work for me

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  • changing mysql password via java

    - by Osama Abukmail
    I'm trying to change a user's password on mysql using java, i successfully changed it on phpmyadmin but same command doesnt work on java SET PASSWORD = PASSWORD('12345') this command will change the current logged in user, i have tried it on java like this statement = connect.createStatement(); statement.executeUpdate("SET PASSWORD = PASSWORD('12345')"); but nothing happened i also tried this with root logged in statement = connect.createStatement(); statement.executeUpdate("SET PASSWORD FOR 'username'@'localhost' = PASSWORD('123456')"); and nothing work,, any help please

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  • Unique text field in MySQL and php

    - by Jonathan
    I've created a salt using; md5(rand(0,10000000)); (there is probably a better way?) There doesn't seem to be possible to make a text field unique in MYSQL. So how do I check if the salt has already been used for a previous user? Or should I generate the salt based on the current date/time? as it is impossible for 2 users to register at exactly the same time correct?

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  • How to get the exact string within the brackets in mysql

    - by sreenath
    In my mysql table a field values are as follows: table name - "clients" field name - "accent" values are - "Eastern(Northern,Southern),Scottish(East Coast)" "Eastern(South,North,Southern),Scottish(East Coast)" If I give select accent from clients where accent like '%north%' if more than 100 records not in the same order. Strings with in the brackets are not in the same order means. It will give above two values. How should i get only second value? Please help me, thanks.

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  • MYSQL and Array with PHP for create Tag Cloud

    - by asilloo
    Hi, I'm trying to make a Tag cloud for every user in own page, I'm using PHP5 and Mysql, My table named "tags" and I want to make a array but in short way. The table like below, The array can be like for user1 array={[car,1],[cat,null],[pen,1],[dvd,1],[cd,null]} Username totaltag tag1 tag2 tag3 tag4 tag5 admin 5 car cat pen dvd cd user1 1 1 1 user2 1 2 12 1 user3 3 2 10 1

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  • easy mysql query question

    - by Ahmet vardar
    Hi, here is the "msg" table on mysql sent_to customer msg read ------- -------- ------ ----- 45 3 bla 0 34 4 bla 1 34 6 bla 0 45 3 bla 0 56 7 bla 1 45 8 bla 0 for example user whose id number is 45 logs in, i want him to see this, you have 2 unread msg to your "number 3" customer you have 1 unread msg to your "number 8" customer like a news feed what query should i use for this ? thx

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  • MySQL friends table

    - by asmo
    I have a MySQL DB in which I store data about each user. I would like to add a list of friends for each user. Should I create a table of friends for each user in the DB or is there a better way?

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  • ORDERING A MYSQL QUERY WITH JOINS AND GROUPS

    - by Oliver
    I have this mysql query: SELECT * FROM Customer c JOIN eHRDemographic ehD ON ehD.CxID = c.CustomerID JOIN CustPrimaryWeight cpW ON cpW.CxID = c.CustomerID WHERE c.CustomerID =22703 GROUP BY c.CustomerID ORDER BY cpW.CustPrimaryWeightID DESC This doesn't really work correctly as the CustPrimaryWeight table has multiple enteries and it's simply joining the first entry and not the more recent one as the ORDER statement doesn't seem to do anything. Any ideas?

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  • MySQL connection timeout

    - by NikolayGS
    I'm running program at apache tomcat server, that should be on permanently, but every morning(the client part isn't accessible at night) i receive error message (in apache tomcat console) that MySQL server is off. So is there any way to prevent this? Thanks in advance!

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  • mysql insert with auto-increment column

    - by czuroski
    Hello, I am trying to insert data into a mysql table from a csv file. I am using the infile sql command, but I am having trouble because the first column of the table is an id that is set as an auto increment field. what do I have to set my first column value to in order to get this to work, or can I do it at all? Thanks

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  • help with delete where not in query

    - by kralco626
    I have a lookup table (##lookup). I know it's bad design because I'm duplicating data, but it speeds up my queries tremendously. I have a query that populates this table insert into ##lookup select distinct col1,col2,... from table1...join...etc... I would like to simulate this behavior: delete from ##lookup insert into ##lookup select distinct col1,col2,... from table1...join...etc... This would clearly update the table correctly. But this is a lot of inserting and deleting. It messes with my indexes and locks up the table for selecting from. This table could also be updated by something like: delete from ##lookup where not in (select distinct col1,col2,... from table1...join...etc...) insert into ##lookup (select distinct col1,col2,... from table1...join...etc...) except if it is already in the table The second way may take longer, but I can say "with no lock" and I will be able to select from the table. Any ideas on how to write the query the second way?

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  • finding missing values, mysql??

    - by praveenmon
    i am using mysql database i have a table called sales its primary key is sales_id ------------------------------------- sales_id | invoice_id | ------------------------------------- 1 | 147 2 | 148 3 | 150 for sales-id 3 the invoice is supposed to be 149. i want to know which numbers are missing from invoice_id (i start invoice_id is 147 and end invoice_id is 4497). The invoice_id had no relation with sales_id is it possible to know which numbers are missing from invoice_id, using some queries??

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  • multiple-to-one relationship mysql, submissions

    - by Yulia
    Hello, I have the following problem. Basically I have a form with an option to submit up to 3 images. Right now, after each submission it creates 3 records for album table and 3 records for images. I need it to be one record for album and 3 for images, plus to link images to the album. I hope it all makes sense... Here is my structure. TABLE `albums` ( `id` int(11) NOT NULL auto_increment, `title` varchar(50) NOT NULL, `fullname` varchar(40) NOT NULL, `email` varchar(100) NOT NULL, `created_at` datetime NOT NULL, `theme_id` int(11) NOT NULL, `description` int(11) NOT NULL, `vote_cache` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ; TABLE `images` ( `id` int(11) NOT NULL auto_increment, `album_id` int(11) NOT NULL, `name` varchar(30) NOT NULL, and my code function create_album($params) { db_connect(); $query = sprintf("INSERT INTO albums set albums.title = '%s', albums.email = '%s', albums.discuss_url = '%s', albums.theme_id = '%s', albums.fullname = '%s', albums.description = '%s', created_at = NOW()", mysql_real_escape_string($params['title']), mysql_real_escape_string($params['email']), mysql_real_escape_string($params['theme_id']), mysql_real_escape_string($params['fullname']), mysql_real_escape_string($params['description']) ); $result = mysql_query($query); if(!$result) { return false; } $album_id = mysql_insert_id(); return $album_id; } if(!is_uploaded_file($_FILES['userfile']['tmp_name'][$i])) { $warning = 'No file uploaded'; } elseif is_valid_file_size($_FILES['userfile']['size'][$i])) { $_POST['album']['theme_id'] = $theme['id']; create_album($_POST['album']); mysql_query("INSERT INTO images(name) VALUES('$newName')"); copy($_FILES['userfile']['tmp_name'][$i], './photos/'.$original_dir.'/' .$newName.'.jpg');

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  • MySQL get variable from SELECT

    - by rlb.usa
    MySQL keeps saying my syntax is incorrect. I want to do this: DELIMITER $$ DROP PROCEDURE IF EXISTS `myprocedure` $$ CREATE DEFINER=`db`@`%` PROCEDURE `myprocedure`( var_name varchar(10) ) BEGIN /* syntax errors below */ DECLARE countTemp integer; SET countTemp=(SELECT COUNT(Name) FROM mytable WHERE Name= var_name); /* more stuff */ END $$ DELIMITER ; What's the correct syntax?

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  • mysql php problem: no error message despite error_reporting(E_ALL) line

    - by herrturtur
    index.php <html> <head> <title>Josh's Online Playground</title> </head> <body> <form method="POST" action="action.php"> <table> <tr> <td>"data for stuff"</td> <td><input type="text" ?></td> </tr> <tr> <td><input type="submit"></td> </tr> </table> </form> </body> </html> action.php <?php error_reporting(E_ALL); ini_sit("display_errors", 1); $mysqli = new mysqli('localhost', 'root', 'password', 'website'); $result = $mysqli->query("insert into stuff (data) values (' .$_POST['data'] ."'); echo $mysqli->error(); if($result = $mysqli->query("select data from stuff")){ echo 'There are '.$result->num_rows.' results.'; } while ($row = $result->fetch_object()){ echo 'stuff' . $row->data; } ?> Despite the first two lines in action.php, I get no error or warning messages. Instead I get a blank page after clicking the submit button. Do I have to do something differently to insert data?

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