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  • PHPFOG and MySql

    - by jim dif
    I am playing around with PHPFog and as a result I ended up with a MySql database. I am trying to figure out how to connect to it with a success message. PHPFog says use this: mysql_connect( $server = getenv('MYSQL_DB_HOST'), $username = getenv('MYSQL_USERNAME'), $password = getenv('MYSQL_PASSWORD')); mysql_select_db(getenv('MYSQL_DB_NAME')); So I basically plug my variables into the above? Or Do I do something different? Thanks, Jim

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  • MySQL Problems......

    - by Kovu
    With the tool "mysql administrator" i get a complete connection to my database, I can change userthings and so on. But not PHPMyAdmin nor Joomly Installation will get a connection, they timed out. Any Ideas?

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  • MySQL: Combining multiple where conditions

    - by Karl
    I'm working on a menu system that takes a url and then queries the db to build the menu. My menu table is: +---------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | node_id | int(11) | YES | | NULL | | | parent | int(11) | YES | | NULL | | | weight | int(11) | YES | | NULL | | | title | varchar(250) | YES | | NULL | | | alias | varchar(250) | YES | | NULL | | | exclude | int(11) | YES | | NULL | | +---------+--------------+------+-----+---------+----------------+ The relevant columns for my question are alias, parent and node_id. So for a url like: http://example.com/folder1/folder2/filename Alias would potentially = "filename", "folder1", "folder2" Parent = the node_id of the parent folder. What I know is how to split the url up into an array and check the alias for a match to each part. What I don't know is how to have it then filter by parent whose alias matches "folder2" and whose parent alias matches "folder1". I'm imagining a query like so: select * from menu where alias='filename' and where parent = node_id where alias='folder2' and parent = node_id where alias='folder1' Except I know that the above is wrong. I'm hoping this can be done in a single query. Thanks for any help in advance!

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  • Connect to MySQL in Ruby using NetBeans

    - by Varun
    I've downloaded the "dbd-mysql-0.4.4.zip" and linked it to my project. While I try to run a demo code from NetBeans the very first line require "dbi" gives me an error. Is there a different way to do it? I also tried jruby setup.rb config --with=dbi,dbd_mysql from the command prompt and it gave me the following error: config: unknown option --with=dbi,dbd_mysql Try 'ruby setup.rb --help' for detailed usage. Any suggestions please?

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  • How do I generate site map from MySQL database

    - by mathew
    Hi all I am new to Php and working on a project which needs to generate sitemaps from URLS which stored in MySQL database. how can I do this?? Is there any one have any idea?? site maps can be in php extension too and only requirement is list of sites display in each page

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  • passing LIMIT as parameters to MySQL sproc

    - by Kyle
    I'm creating a paging class and need to pass in two parameters to my MySQL stored procedure for the LIMIT clause. I'm passing them in as INTs and trying something like this SELECT * FROM `MyTable` LIMIT MyFirstParamInt, MySecondParamInt it gives me an error when I try and save the sproc though. Is there a way to do this that I'm just missing? Or am I going to have to EVAL the whole query and EXECUTE it?

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  • How to kill locked mysql queries

    - by jcure
    Hi, I am creating and testing a mysql join query but each time so far it causes the database tables to lockup and the site hangs. I have to then call the host and they kill the locked queries. Is this something I can do from phpmyadmin so not to bother them while I tweak the script to work? Thanks for any reply.

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  • php date will not insert into mysql database

    - by Piers Blinco
    this is a strange one. I have a date, that is converted to mm-dd-yyyy when posting it to mysql i have re-ordered it to yyyy-mm-dd but yet it still will not insert $date = date("Y-m-d", strtotime($_POST['leaving_date']) ); any advice? Cheers EDIT The actual query: mysql_query("INSERT INTO booking_info (customer_id, booking_ref, date_of_travel) VALUES (".mysql_real_escape_string($_POST['customer_id']).", ".mysql_real_escape_string($rnd).", ".mysql_real_escape_string($date).")");

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  • When is porting data from MySQL to CouchDB NOT advisable? Seeking cautionary tales

    - by dan
    I've dabbled in CouchDB and I have pretty good MySQL experience. I've also created one production application that uses both. I like MySQL but I've run into scaling/concurrency issues with MySQL that CouchDB advertises itself as a general solution for. The problem is that I have MySQL based applications that are pretty huge, and I don't really know whether it would be a good idea or not to try to port them over to a CouchDB datastore. I don't want to put in a lot of time and effort only to find out that my application is really not a good fit for CouchDB. Is there any sort of informed consensus on when porting a MySQL based app to CouchDB is NOT advisable? Any cautionary tales? I think CouchDB is really cool and want to use it more. I'd also like to know ahead of time what specific types of data querying scenarios CouchDB is really not good for, or if CouchDB can really replace MySQL for all the applications I create going forward.

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  • fastest way to copy a table in mysql

    - by Anon
    which one is the fastest way to completely copy a table on mysql ? CREATE TABLE copy LIKE original; INSERT INTO copy SELECT * FROM original; or CREATE TABLE copy SELECT * FROM original; ALTER TABLE copy ADD PRIMARY KEY (id); or theres another way ? PS. can't use command-line tools like mysqldump, must be on-the-fly.

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  • MySQL function to compare values in a db table against the previous

    - by Stuart
    Iam quite new to functions in SQL and I would like to create a function to compare values in a MySQL table against previous and I am not sure how to do this. For example (iId is the input value) DECLARE pVal INT(20); DECLARE val INT(20); SELECT price INTO pVal FROM products WHERE Id=iId; SELECT price FROM products; IF price == pVal THEN SET val = price; END IF; Thanks

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  • make VIEW of SHOW TABLE query

    - by cneeds
    Is there a way to make a VIEW of this SHOW TABLE query? SHOW FULL TABLES FROM `db_name` WHERE `Table_type` = "Base table" When I save this as a view (using phpMyAdmin) I get #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SHOW FULL TABLES FROM `db_name` WHERE `Table_type` = "Base table"' at line 4 when phpMyAdmin tries to execute this CREATE ALGORITHM = UNDEFINED VIEW `Tables` AS SHOW FULL TABLES FROM `db_name` WHERE `Table_type` = "Base table"

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  • PHP MySQL JavaScript or AJAX Image Slideshow

    - by medoix
    Hi all, i have searched Google and also searched Stack Overflow to no avail. I am looking for a PHP / MySQL driven dynamic image slideshow. One similar to 'lightcyclers.com', i have information stored in the DB and i just want to display random or popular content etc. I am also not interested in coding one myself as i am busy working on other features. Any links or help would be much appreciated.

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  • how to decrease queries in php/mysql array selection loop

    - by Mac Taylor
    hey guys i need to show stories details and tags' names in my php/mysql project . for every story row, there is a filed named : tags that save tags id as an array Table name: stories table filed : tags example of tags filed : 1 5 6 space between them and i have a tag table that looks like this Table name : bt_tags Table fileds : tid,tag now problem : when using while loop to fetch all fields in story table , the page uses 1 query to show every stories' detail but for showing tag's names , i should query another table to find names , we have ids stored in story table now i used for loop between while loop to show tag names but im sure there is a better way to decrease page queries $result = $db->sql_query("SELECT * FROM ".STORY_TABLE." "); while ($row = $db->sql_fetchrow($result)) { //fetching other $vars ---- $tags_id = explode(" ",$row['tags']); $c = count($tags_id); for($i=1;$i<$c-1;$i++){ list($tag_name,$slug) = $db->sql_fetchrow($db->sql_query( 'SELECT `tag`,`slug` FROM `bt_tags` WHERE `tid` = "'.tags_id[$i].'" LIMIT 1' )); $sow_tags = '$tag_name,'; } im not allowed to change anything in database table how can i improve this script and show tag's names without using *for loop ?*

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  • Using array instead of lots of db queries in PHP

    - by Tural Teyyuboglu
    My function looks like that. It works but does lots of work (recursively calls itself and does lots of db queries.). There must be another way to do same thing but with array (with one query). I can't figure out how to modify this function to get it work with array. Please help. function genMenu($parent, $level, $menu, $utype) { global $db; $stmt=$db->prepare("select id, name FROM navigation WHERE parent = ? AND menu=? AND user_type=?") or die($db->error); $stmt->bind_param("iii", $parent, $menu, $utype) or die($stmt->error); $stmt->execute() or die($stmt->error); $stmt->store_result(); /* bind variables to prepared statement */ $stmt->bind_result($id, $name) or die($stmt->error); if ($level > 0 && $stmt->num_rows > 0) { echo "\n<ul>\n"; } while ($stmt->fetch()) { echo "<li>"; echo '<a href="?page=' . $id . '">' . $name . '</a>'; //display this level's children genMenu($id, $level+1, $menu, $utype); echo "</li>\n\n"; } if ($level > 0 && $stmt->num_rows > 0) { echo "</ul>\n"; } $stmt->close(); }

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