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  • Template Sort In C++

    - by wdow88
    Hey all, I'm trying to write a sort function but am having trouble figuring out how to initialize a value, and making this function work as a generic template. The sort works by: Find a pair =(ii,jj)= with a minimum value = ii+jj = such at A[ii]A[jj] If such a pair exists, then swap A[ii] and A[jj] else break; The function I have written is as follows: template <typename T> void sort(T *A, int size) { T min =453; T temp=0; bool swapper = true; while(swapper) { swapper = false; int index1 = 0, index2 = 0; for (int ii = 0; ii < size-1; ii++){ for (int jj = ii + 1; jj < size; jj++){ if((min >= (A[ii]+A[jj])) && (A[ii] > A[jj])){ min = (A[ii]+A[jj]); index1 = ii; index2 = jj; swapper = true; } } } if (!swapper) return; else { temp = A[index1]; A[index1] = A[index2]; A[index2] = temp; sort(A,size); } } } This function will successfully sort an array of integers, but not an array of chars. I do not know how to properly initialize the min value for the start of the comparison. I tried initializing the value by simply adding the first two elements of the array together (min = A[0] + A[1]), but it looks to me like for this algorithm it will fail. I know this is sort of a strange type of sort, but it is practice for a test, so thanks for any input.

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  • Accelerated C++, problem 5-6 (copying values from inside a vector to the front)

    - by Darel
    Hello, I'm working through the exercises in Accelerated C++ and I'm stuck on question 5-6. Here's the problem description: (somewhat abbreviated, I've removed extraneous info.) 5-6. Write the extract_fails function so that it copies the records for the passing students to the beginning of students, and then uses the resize function to remove the extra elements from the end of students. (students is a vector of student structures. student structures contain an individual student's name and grades.) More specifically, I'm having trouble getting the vector.insert function to properly copy the passing student structures to the start of the vector students. Here's the extract_fails function as I have it so far (note it doesn't resize the vector yet, as directed by the problem description; that should be trivial once I get past my current issue.) // Extract the students who failed from the "students" vector. void extract_fails(vector<Student_info>& students) { typedef vector<Student_info>::size_type str_sz; typedef vector<Student_info>::iterator iter; iter it = students.begin(); str_sz i = 0, count = 0; while (it != students.end()) { // fgrade tests wether or not the student failed if (!fgrade(*it)) { // if student passed, copy to front of vector students.insert(students.begin(), it, it); // tracks of the number of passing students(so we can properly resize the array) count++; } cout << it->name << endl; // output to verify that each student is iterated to it++; } } The code compiles and runs, but the students vector isn't adding any student structures to its front. My program's output displays that the students vector is unchanged. Here's my complete source code, followed by a sample input file (I redirect input from the console by typing " < grades" after the compiled program name at the command prompt.) #include <iostream> #include <string> #include <algorithm> // to get the declaration of `sort' #include <stdexcept> // to get the declaration of `domain_error' #include <vector> // to get the declaration of `vector' //driver program for grade partitioning examples using std::cin; using std::cout; using std::endl; using std::string; using std::domain_error; using std::sort; using std::vector; using std::max; using std::istream; struct Student_info { std::string name; double midterm, final; std::vector<double> homework; }; bool compare(const Student_info&, const Student_info&); std::istream& read(std::istream&, Student_info&); std::istream& read_hw(std::istream&, std::vector<double>&); double median(std::vector<double>); double grade(double, double, double); double grade(double, double, const std::vector<double>&); double grade(const Student_info&); bool fgrade(const Student_info&); void extract_fails(vector<Student_info>& v); int main() { vector<Student_info> vs; Student_info s; string::size_type maxlen = 0; while (read(cin, s)) { maxlen = max(maxlen, s.name.size()); vs.push_back(s); } sort(vs.begin(), vs.end(), compare); extract_fails(vs); // display the new, modified vector - it should be larger than // the input vector, due to some student structures being // added to the front of the vector. cout << "count: " << vs.size() << endl << endl; vector<Student_info>::iterator it = vs.begin(); while (it != vs.end()) cout << it++->name << endl; return 0; } // Extract the students who failed from the "students" vector. void extract_fails(vector<Student_info>& students) { typedef vector<Student_info>::size_type str_sz; typedef vector<Student_info>::iterator iter; iter it = students.begin(); str_sz i = 0, count = 0; while (it != students.end()) { // fgrade tests wether or not the student failed if (!fgrade(*it)) { // if student passed, copy to front of vector students.insert(students.begin(), it, it); // tracks of the number of passing students(so we can properly resize the array) count++; } cout << it->name << endl; // output to verify that each student is iterated to it++; } } bool compare(const Student_info& x, const Student_info& y) { return x.name < y.name; } istream& read(istream& is, Student_info& s) { // read and store the student's name and midterm and final exam grades is >> s.name >> s.midterm >> s.final; read_hw(is, s.homework); // read and store all the student's homework grades return is; } // read homework grades from an input stream into a `vector<double>' istream& read_hw(istream& in, vector<double>& hw) { if (in) { // get rid of previous contents hw.clear(); // read homework grades double x; while (in >> x) hw.push_back(x); // clear the stream so that input will work for the next student in.clear(); } return in; } // compute the median of a `vector<double>' // note that calling this function copies the entire argument `vector' double median(vector<double> vec) { typedef vector<double>::size_type vec_sz; vec_sz size = vec.size(); if (size == 0) throw domain_error("median of an empty vector"); sort(vec.begin(), vec.end()); vec_sz mid = size/2; return size % 2 == 0 ? (vec[mid] + vec[mid-1]) / 2 : vec[mid]; } // compute a student's overall grade from midterm and final exam grades and homework grade double grade(double midterm, double final, double homework) { return 0.2 * midterm + 0.4 * final + 0.4 * homework; } // compute a student's overall grade from midterm and final exam grades // and vector of homework grades. // this function does not copy its argument, because `median' does so for us. double grade(double midterm, double final, const vector<double>& hw) { if (hw.size() == 0) throw domain_error("student has done no homework"); return grade(midterm, final, median(hw)); } double grade(const Student_info& s) { return grade(s.midterm, s.final, s.homework); } // predicate to determine whether a student failed bool fgrade(const Student_info& s) { return grade(s) < 60; } Sample input file: Moo 100 100 100 100 100 100 100 100 Fail1 45 55 65 80 90 70 65 60 Moore 75 85 77 59 0 85 75 89 Norman 57 78 73 66 78 70 88 89 Olson 89 86 70 90 55 73 80 84 Peerson 47 70 82 73 50 87 73 71 Baker 67 72 73 40 0 78 55 70 Davis 77 70 82 65 70 77 83 81 Edwards 77 72 73 80 90 93 75 90 Fail2 55 55 65 50 55 60 65 60 Thanks to anyone who takes the time to look at this!

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  • HTML Calendar form and input arrays

    - by Christopher Ickes
    Hello. Looking for the best practice here... Have a form that consists of a calendar. Each day of the calendar has 2 text input fields - customer and check-in. What would be the best & most efficient way to send this form to PHP for processing? <form action="post"> <div class="day"> Day 1<br /> <label for="customer['.$current['date'].']">Customer</label> <input type="text" name="customer['.$current['date'].']" value="" size="20" /> <label for="check-in['.$current['date'].']">Check-In</label> <input type="text" name="check-in['.$current['date'].']" value="" size="20" /> <input type="submit" name="submit" value="Update" /> </day> <div class="day"> Day 2<br /> <label for="customer['.$current['date'].']">Customer</label> <input type="text" name="customer['.$current['date'].']" value="" size="20" /> <label for="check-in['.$current['date'].']">Check-In</label> <input type="text" name="check-in['.$current['date'].']" value="" size="20" /> <input type="submit" name="submit" value="Update" /> </day> </form> Is my current setup good? I feel there has to be a better option. My concern involves processing a whole year at once (which can happen) and adding additional text input fields.

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  • Select part of text in a tag

    - by atlantis
    The DOM structure looks like this (existing website ... cant modify it): <table> <tr><td> <br><hr size="1"><strong>some heading 1</strong><br> <br>some text 1<br> <br><hr size="1"><strong>some heading 2</strong><br> <br>some text 2<br> </td></tr> </table> I want to manipulate it so that it looks like this <table> <tr><td> <br><hr size="1"><strong>some heading 1</strong><br> <br>some text 1<br> </td></tr> <tr><td> <br><hr size="1"><strong>some heading 2</strong><br> <br>some text 2<br> </td></tr> </table> Using the solution posted here, I am able to get hold of the hr, strong, br tags and move them into new td elements. However, I am not able to get hold of "some text 1" since it is directly contained within the td and using .text() on td will give me both "some text 1" as well as "some text 2". Any idea?

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  • How can I order by the result of a recursive SQL query

    - by Tony
    I have the following method I need to ORDER BY: def has_attachments? attachments.size > 0 || (!parent.nil? && parent.has_attachments?) end I have gotten this far: ORDER BY CASE WHEN attachments.size > 0 THEN 1 ELSE (CASE WHEN parent_id IS NULL THEN 0 ELSE (CASE message.parent ...what goes here ) END END END I may be looking at this wrong because I don't have experience with recursive SQL. Essentially I want to ORDER by whether a message or any of its parents has attachments. If it's attachment size is 0, I can stop and return a 1. If the message has an attachment size of 0, I now check to see if it has a parent. If it has no parent then there is no attachment, however if it does have a parent then I essentially have to do the same query case logic for the parent. UPDATE The table looks like this +---------------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------------------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | message_type_id | int(11) | NO | MUL | | | | message_priority_id | int(11) | NO | MUL | | | | message_status_id | int(11) | NO | MUL | | | | message_subject_id | int(11) | NO | MUL | | | | from_user_id | int(11) | YES | MUL | NULL | | | parent_id | int(11) | YES | MUL | NULL | | | expires_at | datetime | YES | MUL | NULL | | | subject_other | varchar(255) | YES | | NULL | | | body | text | YES | | NULL | | | created_at | datetime | NO | MUL | | | | updated_at | datetime | NO | | | | | lock_version | int(11) | NO | | 0 | | +---------------------+--------------+------+-----+---------+----------------+ Where the parent_id refers to the parent message, if it exists. Thanks!

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  • Trouble with applying a nested loop on a list

    - by user1665355
    I have a list consisting of 3 elements: datalist=list(a=datanew1,b=datanew2,c=datanew3) datalist$a : Inv_ret Firm size leverage Risk Liquidity Equity 17 0.04555968 17.34834 0.1323199 0.011292273 0.02471489 0 48 0.01405835 15.86315 0.6931730 0.002491093 0.12054914 0 109 0.04556252 16.91602 0.1714068 0.006235836 0.01194579 0 159 0.04753472 14.77039 0.3885720 0.007126830 0.06373028 0 301 0.03941040 16.94377 0.1805346 0.005450653 0.01723319 0 datalist$b : Inv_ret Firm size leverage Risk Liquidity Equity 31 0.04020832 18.13300 0.09326265 0.015235240 0.01579559 0.005025379 62 0.04439078 17.84086 0.11016402 0.005486982 0.01266566 0.006559096 123 0.04543250 18.00517 0.12215307 0.011154742 0.01531451 0.002282790 173 0.03960613 16.45457 0.10828643 0.011506857 0.02385191 0.009003780 180 0.03139643 17.57671 0.40063094 0.003447233 0.04530395 0.000000000 datalist$c : Inv_ret Firm size leverage Risk Liquidity Equity 92 0.03081029 19.25359 0.10513159 0.01635201 0.025760806 0.000119744 153 0.03280746 19.90229 0.11731517 0.01443786 0.006769735 0.011999005 210 0.04655847 20.12543 0.11622403 0.01418010 0.003125632 0.003802365 250 0.03301018 20.67197 0.13208234 0.01262499 0.009418828 0.021400052 282 0.04355975 20.03012 0.08588316 0.01918129 0.004213846 0.023657440 I am trying to create a cor.test on the datalist above : Cor.tests=sapply(datalist,function(x){ for(h in 1:length(names(x))){ for(i in 1:length(names(x$h[i]))){ for(j in 1:length(names(x$h[j]))){ cor.test(x$h[,i],x$h[,j])$p.value }}}}) But I get an error : Error in cor.test.default(x$h[, i], x$h[, j]) : 'x' must be a numeric vector Any suggestions about what I am doing wrong? P.S. If I simply have one dataframe, datanew1 : Inv_ret Firm size leverage Risk Liquidity Equity 17 0.04555968 17.34834 0.1323199 0.011292273 0.02471489 0 48 0.01405835 15.86315 0.6931730 0.002491093 0.12054914 0 109 0.04556252 16.91602 0.1714068 0.006235836 0.01194579 0 159 0.04753472 14.77039 0.3885720 0.007126830 0.06373028 0 301 0.03941040 16.94377 0.1805346 0.005450653 0.01723319 0 I use this loop : results=matrix(NA,nrow=6,ncol=6) for(i in 1:length(names(datanew1))){ for(j in 1:length(names(datanew1))){ results[i,j]<-cor.test(datanew1[,i],datanew1[,j])$p.value }} And the output is: results : [,1] [,2] [,3] [,4] [,5] [,6] [1,] 0.000000e+00 7.085663e-09 3.128975e-10 3.018239e-02 4.806400e-10 0.475139526 [2,] 7.085663e-09 0.000000e+00 2.141581e-21 0.000000e+00 2.247825e-20 0.454032499 [3,] 3.128975e-10 2.141581e-21 0.000000e+00 2.485924e-25 2.220446e-16 0.108643838 [4,] 3.018239e-02 0.000000e+00 2.485924e-25 0.000000e+00 5.870007e-15 0.006783324 [5,] 4.806400e-10 2.247825e-20 2.220446e-16 5.870007e-15 0.000000e+00 0.558827862 [6,] 4.751395e-01 4.540325e-01 1.086438e-01 6.783324e-03 5.588279e-01 0.000000000 Which is exactly what I want. But I want to get 3 matrices, one for each element of the datalist above.

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  • How to play animation in order in ipad

    - by juliet
    I have two animations for two layers, layer1 and layer2, each has different path. So, I want to know how can play them in order. first play layer1's animation, and then layer2. here is my two animation code! layer1 CALayer *layer1 = [CALayer layer]; [self.layer addSublayer:layer1]; CAKeyframeAnimation *animation1 = [CAKeyframeAnimation animationWithKeyPath:@"position"]; layer1.contents = (id)image1.CGImage; layer1.anchorPoint = CGPointZero; layer1.frame = CGRectMake(0.0f, 0.0f, image1.size.width, image1.size.height); animation1.path = path1; animation1.duration = 2.0f; animation1.calculationMode = kCAAnimationLinear; [layer1 addAnimation:animation1 forKey:@"position"]; layer2 CALayer *layer2 = [CALayer layer]; [self.layer addSublayer:layer2]; CAKeyframeAnimation *animation2 = [CAKeyframeAnimation animationWithKeyPath:@"position"]; layer2.contents = (id)image2.CGImage; layer2.anchorPoint = CGPointZero; layer2.frame = CGRectMake(0.0f, 0.0f, image2.size.width, image2.size.height); animation2.path = path2; animation2.duration = 2.0f; animation2.calculationMode = kCAAnimationLinear; [layer2 addAnimation:animation2 forKey:@"position"];

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  • Java: Efficiency of the readLine method of the BufferedReader and possible alternatives

    - by Luhar
    We are working to reduce the latency and increase the performance of a process written in Java that consumes data (xml strings) from a socket via the readLine() method of the BufferedReader class. The data is delimited by the end of line separater (\n), and each line can be of a variable length (6KBits - 32KBits). Our code looks like: Socket sock = connection; InputStream in = sock.getInputStream(); BufferedReader inputReader = new BufferedReader(new InputStreamReader(in)); ... do { String input = inputReader.readLine(); // Executor call to parse the input thread in a seperate thread }while(true) So I have a couple of questions: Will the inputReader.readLine() method return as soon as it hits the \n character or will it wait till the buffer is full? Is there a faster of picking up data from the socket than using a BufferedReader? What happens when the size of the input string is smaller than the size of the Socket's receive buffer? What happens when the size of the input string is bigger than the size of the Socket's receive buffer? I am getting to grips (slowly) with Java's IO libraries, so any pointers are much appreciated. Thank you!

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  • Event problems with FF

    - by s4v10r
    Hi all :) Made this sweet little script to auto change fields after input. Works nicely in IE, Chrome and Safari, but not in FF or opera. JS code: function fieldChange(id, e){ var keyID = (window.event) ? event.keyCode : e.keyCode; if (document.getElementById(id).value.length >= 2){ if (keyID >= 48 && keyID <= 57 || keyID >= 96 && keyID <= 105){ switch(id){ case "textf1": document.getElementById("textf2").focus(); break; case "textf2": document.getElementById("textf3").focus(); break; case "textf3": if (document.getElementById(id).value.length >= 4){ document.getElementById("nubPcode").focus(); } break; } } } HTML: <div class="privateOrderSchema"> <input type="text" id="textf1" name="textf1" maxlength="2" size="4" onKeyUp="fieldChange('textf1')"/>- <input type="text" id="textf2" name="textf2" maxlength="2" size="4" onKeyUp="fieldChange('textf2')" />- <input type="text" id="textf3" name="textf3" maxlength="4" size="5" onKeyUp="fieldChange('textf3')" /> </div> <div class="privateOrderSchema"> <input type="text" id="nubPcode" name="nubPcode" size="4" maxlength="4" /> <br /> </div> Does anybody know how to send the "e" var in this scenario? Tnx all :D ur gr8!

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  • movie does not start in full screen in flash video player

    - by jodeci
    We have this legacy code of a flash video player that functions well enough but still has some loose ends I need to tighten up. It can do the basic "switch to full screen and back to normal size" stunts, however with one exception. On the first fresh load of the app, if I switch to full screen mode first, and then click to play the movie, the player would be in full screen, yet the movie itself would remain in it's original size. //trigger if (stage.displayState == StageDisplayState.NORMAL) { stage.addEventListener('fullScreen', procFullScreen); stage.scaleMode = StageScaleMode.NO_SCALE; stage.displayState = StageDisplayState.FULL_SCREEN; //mv:VideoDisplay mv.percentHeight = 100; mv.percentWidth = 100; mv.x = 0; mv.y = 0; } // event handler if (event.fullScreen) { mv.smoothing = true; this.height = stage.height; this.width = stage.width; //videoCanvas:Canvas videoCanvas.height = Application.application.height; videoCanvas.width = Application.application.width; fullScreenViewStack.selectedIndex = 1; } The VideoDisplay object even returns the expected width/height, but the movie just plays in it's original size. If I switch screen sizes during movie playback, then the movie size will shrink or stretch as it should. I'm running out of ideas, any suggestions? Thanks in advance!

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  • How to determine Scale of Line Graph based on Pixels/Height?

    - by Dexter
    I have a problem due to my terrible math abilities, that I cannot figure out how to scale a graph based on the maximum and minimum values so that the whole graph will fit onto the graph-area (400x420) without parts of it being off the screen (based on a given equation by user). Let's say I have this code, and it automatically draws squares and then the line graph based on these values. What is the formula (what do I multiply) to scale it so that it fits into the small graphing area? vector<int> m_x; vector<int> m_y; // gets automatically filled by user equation or values int HeightInPixels = 420;// Graphing area size!! int WidthInPixels = 400; int best_max_y = GetMaxOfVector(m_y); int best_min_y = GetMinOfVector(m_y); m_row = 0; m_col = 0; y_magnitude = (HeightInPixels/(best_max_y+best_min_y)); // probably won't work magnitude = (WidthInPixels/(int)m_x.size()); m_col = m_row = best_max_y; // number of vertical/horizontal lines to draw ////x_magnitude = (WidthInPixels/(int)m_x.size())/2; Doesn't work well ////y_magnitude = (HeightInPixels/(int)m_y.size())/2; Doesn't work well ready = true; // we have values, graph it Invalidate(); // uses WM_PAINT

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  • Making an owner-draw button transparent against its arbitrary background in WINCE

    - by EndsOfInvention
    Hi I am trying to place an owner-draw button transparently onto a background. I have no trouble doing this when the background is a solid colour but if the background is an image I cannot seem to get the correct HDC (handle to device context) to Bitblt() the area that button covers. The HDC that is passed as part of the DRAWITEMSTRUCT gives me a button-default-grey area. If I attempt to get the parent of the HWND and then the device context of that i.e pdc = GetDC(GetParent(hWnd)); then the background that gets BitBlt'd is the background of the last painted window. I hope this question makes sense. this is the code I have: pdis = (LPDRAWITEMSTRUCT)(lParam); hdc = pdis->hDC; button = pdis->CtlID - IDC_BUTOFFSET; //pdc = GetDC((hWnd)); pdc = GetDC(GetParent(hWnd)); hbm = CreateCompatibleBitmap(pdc, Buttons_[button]->bc.Size.cx, Buttons_[button]->bc.Size.cy); SelectObject(hdc, hbm); BitBlt(hdc, 0, 0, Buttons_[button]->bc.Size.cx, Buttons_[button]->bc.Size.cy, pdc, Buttons_[button]->bc.Position.x, Buttons_[button]->bc.Position.y, SRCCOPY); TIA Best regards Ends

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  • wxpython: adding panel to wx.Frame disables/conflicts with wx.Frame's OnPaint?!

    - by sdaau
    Hi all, I just encountered this strange situation: I found an example, where wx.Frame's OnPaint is overridden, and a circle is drawn. Funnily, as soon as I add even a single panel to the frame, the circle is not drawn anymore - in fact, OnPaint is not called at all anymore ! Can anyone explain me if this is the expected behavior, and how to correctly handle a wx.Frame's OnPaint, if the wx.Frame has child panels ? Small code example is below.. Thanks in advance for any answers, Cheers! The code: #!/usr/bin/env python # http://www.linuxquestions.org/questions/programming-9/wxwidgets-wxpython-drawing-problems-with-onpaint-event-703946/ import wx class MainWindow(wx.Frame): def __init__(self, parent, title, size=wx.DefaultSize): wx.Frame.__init__(self, parent, wx.ID_ANY, title, wx.DefaultPosition, size) self.circles = list() self.displaceX = 30 self.displaceY = 30 circlePos = (self.displaceX, self.displaceY) self.circles.append(circlePos) ## uncommenting either only first, or both of ## the commands below, causes OnPaint *not* to be called anymore! #~ self.panel = wx.Panel(self, wx.ID_ANY) #~ self.mpanelA = wx.Panel(self.panel, -1, size=(200,50)) self.Bind(wx.EVT_PAINT, self.OnPaint) def OnPaint(self, e): print "OnPaint called" dc = wx.PaintDC(self) dc.SetPen(wx.Pen(wx.BLUE)) dc.SetBrush(wx.Brush(wx.BLUE)) # Go through the list of circles to draw all of them for circle in self.circles: dc.DrawCircle(circle[0], circle[1], 10) def main(): app = wx.App() win = MainWindow(None, "Draw delayed circles", size=(620,460)) win.Show() app.MainLoop() if __name__ == "__main__": main()

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  • Mixing c++ standard strings and windows API

    - by JB
    Many windows APIs take a pointer to a buffer and a size element but the result needs to go into a c++ string. (I'm using windows unicode here so they are wstrings) Here is an example :- #include <iostream> #include <string> #include <vector> #include <windows.h> using namespace std; // This is the method I'm interested in improving ... wstring getComputerName() { vector<wchar_t> buffer; buffer.resize(MAX_COMPUTERNAME_LENGTH+1); DWORD size = MAX_COMPUTERNAME_LENGTH; GetComputerNameW(&buffer[0], &size); return wstring(&buffer[0], size); } int main() { wcout << getComputerName() << "\n"; } My question really is, is this the best way to write the getComputerName function so that it fits into C++ better, or is there a better way? I don't see any way to use a string directly without going via a vector unless I missed something? It works fine, but somehow seems a little ugly. The question isn't about that particular API, it's just a convenient example.

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  • An array of LPWSTR pointers, not working right.

    - by BigBirdy
    Declare: LPWSTR** lines= new LPWSTR*[totalLines]; then i set using: lines[totalLines]=&totalText; SetWindowText(totalChat,(LPWSTR)lines[totalLines]); totalLines++; Now I know totalText is right, cause if i SetWindowText using totalText it works fine. I need the text in totalLines too. I'm also doing: //accolating more memory. int orgSize=size; LPWSTR** tempArray; if (totalLines == size) { size *= 2; tempArray = new LPWSTR*[size]; memcpy(tempArray, lines,sizeof(LPWSTR)*orgSize); delete [] lines; lines = tempArray; } to allocate more memory when needed. My problem is that the lines is not getting the right data. It works for the first time around then it get corrupted. I thought at first i was overwriting but totalLines is increase. Hopefully this is enough information.

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  • Generating two thumbnails from the same image in Django

    - by Titus
    Hello, this seems like quite an easy problem but I can't figure out what is going on here. Basically, what I'd like to do is create two different thumbnails from one image on a Django model. What ends up happening is that it seems to be looping and recreating the same image (while appending an underscore to it each time) until it throws up an error that the filename is to big. So, you end up something like: OSError: [Errno 36] File name too long: 'someimg________________etc.jpg' Here is the code: def save(self, *args, **kwargs): if self.image: iname = os.path.split(self.image.name)[-1] fname, ext = os.path.splitext(iname) tlname, tsname = fname + '_thumb_l' + ext, fname + '_thumb_s' + ext self.thumb_large.save(tlname, make_thumb(self.image, size=(250,250))) self.thumb_small.save(tsname, make_thumb(self.image, size=(100,100))) super(Artist, self).save(*args, **kwargs) def make_thumb(infile, size=(100,100)): infile.seek(0) image = Image.open(infile) if image.mode not in ('L', 'RGB'): image.convert('RGB') image.thumbnail(size, Image.ANTIALIAS) temp = StringIO() image.save(temp, 'png') return ContentFile(temp.getvalue()) I didn't show imports for the sake of brevity. Assume there are two ImageFields on the Artist model: thumb_large, and thumb_small. If this isn't the correct way to do it, I'd appreciate any feedback. Thanks!

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  • Dynamic stack allocation in C++

    - by Poni
    I want to allocate memory on the stack. Heard of _alloca / alloca and I understand that these are compiler-specific stuff, which I don't like. So, I came-up with my own solution (which might have it's own flaws) and I want you to review/improve it so for once and for all we'll have this code working: /*#define allocate_on_stack(pointer, size) \ __asm \ { \ mov [pointer], esp; \ sub esp, [size]; \ }*/ /*#define deallocate_from_stack(size) \ __asm \ { \ add esp, [size]; \ }*/ void test() { int buff_size = 4 * 2; char *buff = 0; __asm { // allocate mov [buff], esp; sub esp, [buff_size]; } // playing with the stack-allocated memory for(int i = 0; i < buff_size; i++) buff[i] = 0x11; __asm { // deallocate add esp, [buff_size]; } } void main() { __asm int 3h; test(); } Compiled with VC9. What flaws do you see in it? Me for example, not sure that subtracting from ESP is the solution for "any kind of CPU". Also, I'd like to make the commented-out macros work but for some reason I can't.

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  • Why SetMinimumSize sets the minimal heights but not width?

    - by Roman
    Here is my code: import javax.swing.*; import java.awt.*; public class PanelModel { public static void main(String[] args) { JFrame frame = new JFrame("Colored Trails"); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); JPanel mainPanel = new JPanel(); mainPanel.setLayout(new BoxLayout(mainPanel, BoxLayout.Y_AXIS)); JPanel firstPanel = new JPanel(); firstPanel.setLayout(new GridLayout(4, 4)); firstPanel.setMaximumSize(new Dimension(4*100, 4*100)); firstPanel.setMinimumSize(new Dimension(4*100, 4*100)); JButton btn; for (int i=1; i<=4; i++) { for (int j=1; j<=4; j++) { btn = new JButton(); btn.setPreferredSize(new Dimension(100, 100)); firstPanel.add(btn); } } mainPanel.add(firstPanel); frame.add(mainPanel); frame.setSize(520,600); //frame.setMinimumSize(new Dimension(520,600)); frame.setVisible(true); } } When I increase the size of the window (by mouse) I see that my panel does not increase its size. It is the expected behavior (because I set the maximal size of the panel). However, when I decrease the size of the window, I see that width of the panel is decreased too (while the height is constant). So, the setMinimumSize works only partially. Why is that?

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  • how to compare the checksums in a list corresponding to a file path with the file path in the operat

    - by surab
    Hi all, how to compare the checksums in a list corresponding to a file path with the file path in the operating system In Python? import os,sys,libxml2 files=[] sha1s=[] doc = libxml2.parseFile('files.xml') for path in doc.xpathEval('//File/Path'): files.append(path.content) for sha1 in doc.xpathEval('//File/Hash'): sha1s.append(sha1.content) for entry in zip(files,sha1s): print entry the files.xml contains <Files> <File> <Path>usr/share/doc/dialog/samples/form1</Path> <Type>doc</Type> <Size>1222</Size> <Uid>0</Uid> <Gid>0</Gid> <Mode>0755</Mode> <Hash>49744d73e8667d0e353923c0241891d46ebb9032</Hash> </File> <File> <Path>usr/share/doc/dialog/samples/form3</Path> <Type>doc</Type> <Size>1294</Size> <Uid>0</Uid> <Gid>0</Gid> <Mode>0755</Mode> <Hash>f30277f73e468232c59a526baf3a5ce49519b959</Hash> </File> </Files> I need to compare the sha1 checksum in between tags corresponding to the file specified in between the tags, with the same file path in base Operating system.

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  • Changing the <input> type in IE with JavaScript

    - by MrEnder
    The line <input type="text" name="passwordLogin" value="Password" onfocus="if(this.value=='Password'){this.value=''; this.type='password'};" onblur="if(this.value==''){this.value='Password'; this.type='text'};" size="25" /> works in all web browsers except IE... How can I fix it for IE? Ok made some changes to still have an error I want it to work like this like here <input type="text" name="usernameLogin" value="Email" onfocus="if(this.value=='Email'){this.value=''};" onblur="if(this.value==''){this.value='Email'};" size="25" /> if I dont enter anything it will put the value back So I tried this <td colspan="2" id="passwordLoginTd"> <input id="passwordLoginInput1" type="text" name="passwordLogin" value="Password" onfocus="passwordFocus()" size="25" /> <input id="passwordLoginInput2" style="display: none;" type="password" name="passwordLogin" value="" onblur="passwordBlur()" size="25" /> </td> <script type="text/javascript"> //<![CDATA[ passwordElement1 = document.getElementById('passwordLoginInput1'); passwordElement2 = document.getElementById('passwordLoginInput2'); function passwordFocus() { passwordElement1.style.display = "none"; passwordElement2.style.display = "inline"; passwordElement2.focus(); } function passwordBlur() { if(passwordElement2.value=='') { passwordElement2.style.display = "none"; passwordElement1.style.display = "inline"; passwordElement1.focus(); } } //]]> </script> as you can see the blur does not work =[ ok finally got it thanks to the help needed to remove passwordElement1.focus();

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  • how to Compute the average probe length for success and failure - Linear probe (Hash Tables)

    - by fang_dejavu
    hi everyone, I'm doing an assignment for my Data Structures class. we were asked to to study linear probing with load factors of .1, .2 , .3, ...., and .9. The formula for testing is: The average probe length using linear probing is roughly Success-- ( 1 + 1/(1-L)**2)/2 or Failure-- (1+1(1-L))/2. we are required to find the theoretical using the formula above which I did(just plug the load factor in the formula), then we have to calculate the empirical (which I not quite sure how to do). here is the rest of the requirements **For each load factor, 10,000 randomly generated positive ints between 1 and 50000 (inclusive) will be inserted into a table of the "right" size, where "right" is strictly based upon the load factor you are testing. Repeats are allowed. Be sure that your formula for randomly generated ints is correct. There is a class called Random in java.util. USE it! After a table of the right (based upon L) size is loaded with 10,000 ints, do 100 searches of newly generated random ints from the range of 1 to 50000. Compute the average probe length for each of the two formulas and indicate the denominators used in each calculationSo, for example, each test for a .5 load would have a table of size approximately 20,000 (adjusted to be prime) and similarly each test for a .9 load would have a table of approximate size 10,000/.9 (again adjusted to be prime). The program should run displaying the various load factors tested, the average probe for each search (the two denominators used to compute the averages will add to 100), and the theoretical answers using the formula above. .** how do I calculate the empirical success?

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  • How do I target a div without a class or id but with all these specific style-attributes

    - by Ben
    I'm restyling a certain page where I don't have access to all the source-HTML. So I'm left over with some hard to target elements within a page I need removed. For example the page is swamped with <div style="float: left; width: 10.25px; height: 284px;"></div>. To get rid of them I tried this in CSS: div[style="float: left; width: 10.25px; height: 284px;"] { display:none !important; } I'd like to fix this using CSS, because the the HTML that needs to be removed is updated using ajax. How do I target a div without a class or id but with all these specific style-attributes? Some more of the source-code (took a while to organize the parsed source): <div> <span class="Block BigPhotoList_Block"> <span class="Photo BigPhotoList_Photo" style="height: 200px"> <a href="/Webwinkel-Product-83760187/Le-Coq-Sportif-Angers-Low.html.html"> <span style="background-image:url(http://61955.static.securearea.eu/Files/2/61000/61955/ProductPhotos/MaxContent/144036303.jpg);" class="Canvas BigPhotoList_Canvas" title="Le-Coq-Sportif-Angers-Low"></span> </a> </span> <span class="Title BigPhotoList_Title"> <a href="/Webwinkel-Product-83760187/Le-Coq-Sportif-Angers-Low.html.html"> Le Coq Sportif Angers Low </a> </span> <span class="Price BigPhotoList_Price" style="font-size: 120%;"> € 89,95 </span> </span> <div style="float: left; width: 10.25px; height: 284px; border-right: 1px dashed #A0A0A0;" class="BigPhotoList_Stippel"></div> <div style="float: left; width: 10.25px; height: 284px;"></div> <span class="Block BigPhotoList_Block"> <span class="Photo BigPhotoList_Photo" style="height: 200px"> <a href="/Webwinkel-Product-83760185/Le-Coq-Sportif-Auveurne-Low.html"> <span style="background-image:url(http://61955.static.securearea.eu/Files/2/61000/61955/ProductPhotos/MaxContent/144036301.jpg);" class="Canvas BigPhotoList_Canvas" title="Le-Coq-Sportif-Auveurne-Low"></span> </a> </span> <span class="Title BigPhotoList_Title"> <a href="/Webwinkel-Product-83760185/Le-Coq-Sportif-Auveurne-Low.html"> Le Coq Sportif Auveurne Low </a> </span> <span class="Price BigPhotoList_Price" style="font-size: 120%;"> € 79,95 </span> </span> <div style="float: left; width: 10.25px; height: 284px; border-right: 1px dashed #A0A0A0;" class="BigPhotoList_Stippel"></div> <div style="float: left; width: 10.25px; height: 284px;"></div> <span class="Block BigPhotoList_Block"> <span class="Photo BigPhotoList_Photo" style="height: 200px"> <a href="/Webwinkel-Product-83760191/Le-Coq-Sportif-Bordeaux-Low.html"> <span style="background-image:url(http://61955.static.securearea.eu/Files/2/61000/61955/ProductPhotos/MaxContent/144036307.jpg);" class="Canvas BigPhotoList_Canvas" title="Le-Coq-Sportif-Bordeaux-Low"></span> </a> </span> <span class="Title BigPhotoList_Title"> <a href="/Webwinkel-Product-83760191/Le-Coq-Sportif-Bordeaux-Low.html"> Le Coq Sportif Bordeaux Low </a> </span> <span class="Price BigPhotoList_Price" style="font-size: 120%;"> € 99,95 </span> </span> <span class="Block BigPhotoList_Block"> <span class="Photo BigPhotoList_Photo" style="height: 200px"> <a href="/Webwinkel-Product-83760181/Le-Coq-Sportif-Cannet-Low.html"> <span style="background-image:url(http://61955.static.securearea.eu/Files/2/61000/61955/ProductPhotos/MaxContent/144036297.jpg);" class="Canvas BigPhotoList_Canvas" title="Le-Coq-Sportif-Cannet-Low"></span> </a> </span> <span class="Title BigPhotoList_Title"> <a href="/Webwinkel-Product-83760181/Le-Coq-Sportif-Cannet-Low.html"> Le Coq Sportif Cannet Low </a> </span> <span class="Discount BigPhotoList_Discount" style="font-size: 120%;"> € 99,95 </span> <span class="Price BigPhotoList_Price" style="font-size: 120%;"> € 94,95 </span> </span> <div style="float: left; width: 10.25px; height: 284px; border-right: 1px dashed #A0A0A0;" class="BigPhotoList_Stippel"></div> <div style="float: left; width: 10.25px; height: 284px;"></div> <span class="Block BigPhotoList_Block"> <span class="Photo BigPhotoList_Photo" style="height: 200px"> <a href="/Webwinkel-Product-83760183/Le-Coq-Sportif-Rodez-Low.html"> <span style="background-image:url(http://61955.static.securearea.eu/Files/2/61000/61955/ProductPhotos/MaxContent/144036299.jpg);" class="Canvas BigPhotoList_Canvas" title="Le-Coq-Sportif-Rodez-Low"></span> </a> </span> <span class="Title BigPhotoList_Title"> <a href="/Webwinkel-Product-83760183/Le-Coq-Sportif-Rodez-Low.html"> Le Coq Sportif Rodez Low </a> </span> <span class="Price BigPhotoList_Price" style="font-size: 120%;"> € 99,95 </span> </span> <div style="float: left; width: 10.25px; height: 284px; border-right: 1px dashed #A0A0A0;" class="BigPhotoList_Stippel"></div> <div style="float: left; width: 10.25px; height: 284px;"></div> <span class="Block BigPhotoList_Block"> <span class="Photo BigPhotoList_Photo" style="height: 200px"> <a href="/Webwinkel-Product-83760189/Le-Coq-Sportif-Sedan-Low.html"> <span style="background-image:url(http://61955.static.securearea.eu/Files/2/61000/61955/ProductPhotos/MaxContent/144036305.jpg);" class="Canvas BigPhotoList_Canvas" title="Le-Coq-Sportif-Sedan-Low"></span> </a> </span> <span class="Title BigPhotoList_Title"> <a href="/Webwinkel-Product-83760189/Le-Coq-Sportif-Sedan-Low.html"> Le Coq Sportif Sedan Low </a> </span> <span class="Discount BigPhotoList_Discount" style="font-size: 120%;"> € 109,95 </span> <span class="Price BigPhotoList_Price" style="font-size: 120%;"> € 99,95 </span> </span> </div>

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  • How do I perform a flip and grow animation like in iPhoto 09?

    - by Austin
    I'm developing a Cocoa application and want to be able to click a button in one of the views in my NSCollectionView and have a details view flip open and position to the middle of the screen like it does in iPhoto 09 when you click the "i" in the bottom-right hand corner of a photo. The photo "flips" and grows, centered on the window to reveal details about the photo. I'm guessing they're using Core Animation to achieve this. I've been looking at the Lemur Flip example, but when I try to modify it to add repositioning code to the animation, it throws off the flip. Here is the positioning code I've added to the - (IBAction)flip:(id)sender; code of LemurFlip: ... [CATransaction begin]; { NSSize supersize = contentView.frame.size; // Size of window content view NSSize subsize = frontView.frame.size; // Size of view we're flipping out if(!frontView.isHidden) { // Move views to middle of the window [[backView animator] setFrameOrigin:NSMakePoint((supersize.width / 2) - (subsize.width / 2), (supersize.height / 2) - (subsize.height / 2))]; [[frontView animator] setFrameOrigin:NSMakePoint((supersize.width / 2) - (subsize.width / 2), (supersize.height / 2) - (subsize.height / 2))]; } else { // Return views to point of origin [[backView animator] setFrameOrigin:NSMakePoint(0, 0)]; [[frontView animator] setFrameOrigin:NSMakePoint(0, 0)]; } [hiddenLayer addAnimation:[self _flipAnimationWithDuration:flipDuration isFront:NO] forKey:@"flipGroup"]; [visibleLayer addAnimation:[self _flipAnimationWithDuration:flipDuration isFront:YES] forKey:@"flipGroup"]; } [CATransaction commit]; ... Is there a good example of how to do this or some rules for combining these sort of animations?

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  • Can I connect to SQL from JavaScript MVC?

    - by user54197
    I am populating a list of names that will be added to my Sql Database. In this simple case, how do I send the information to SQL server without my page being refreshed? <script type="text/javascript"> function addNewRow() { $('#displayPropertyTable tr:last').after('<tr><td style="font-size:smaller;" class="name"></td><td style="font-size:smaller;" class="address"></td></tr>'); var $tr = $('#displayPropertyTable tr:last'); var propertyCondition = $('#txtPropAddress').val(); if (propertyCondition != "") { $tr.find('.name').text($('#txtPropName').val()); $tr.find('.address').text($('#txtPropAddress').val()); } } </script> ... <table id="displayPropertyTable" width= "100%"> <tr> <td style="font-size:smaller;" class="name"></td> <td style="font-size:smaller;" class="address"></td> </tr> </table> ... <table> <tr> <td><b>Name</b></td> <td colspan="2"><input id="txtPropName" type="text" /></td> </tr> <tr> <td><b>Address</b></td> <td colspan="2"><input id="txtPropAddress" type="text" /></td> </tr> </table> ... <button onclick="addNewRow();">Add</button>

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  • Dynamically changing background color of a UIView

    - by EricM
    Hello- Here's my setup. I have a viewcontroller that I'm creating and adding as a subview. The viewcontroller presents some options that a user can chose from. The viewcontroller is being pushed in response to a "long press" gesture. Within the viewcontroller, I added a child UIView to group some other controls together so I can move them around the screen as a unit and, when they are displayed, center them on the location of the long press. Here is the code that instantiates the view controller, changes its location, and adds it as a subview: UserOptions *opts = [[UserOptions alloc] initWithNibName:@"UserOptions" bundle:nil]; [opts recenterOptions:location]; [self.view addSubview:opts.view]; That bit of code does create and push the viewcontroller, but the call to recenterOptions doesn't do anything. Here is that method: - (void) recenterOptions:(CGPoint)location { CGRect oldFrame = self.optionsView.frame; CGFloat newX = location.x; // + oldFrame.size.width / 2.0; CGFloat newY = location.y; // + oldFrame.size.height / 2.0; CGRect newFrame = CGRectMake(newX, newY, oldFrame.size.width, oldFrame.size.height); self.optionsView.frame = newFrame; } Note that self.optionsView is the child UIView that I added to the viewcontroller's nib. Does anyone know why I'm unable to change the location of the UIView? Regards, Eric

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