Search Results

Search found 45836 results on 1834 pages for 'right to left layout'.

Page 158/1834 | < Previous Page | 154 155 156 157 158 159 160 161 162 163 164 165  | Next Page >

  • Moving Computer Player in Xcode

    - by user1631497
    I am working on a 2d game using xcode and objective-c. I am trying to make my enemy player move left if I am left of him, until he is touching my character. The same will go when I am right of him. Basically just trying to get him to move towards me. But my code to do so is not working. So I have my code that says the following -(void)moveTowardsCharacter { enemyLeftTimer = [NSTimer scheduledTimerWithTimeInterval:0.05 target:self selector:@selector(goEnemyLeft) userInfo:nil repeats:YES]; if (enemyLeftTimer == nil){ enemyLeftTimer = [NSTimer scheduledTimerWithTimeInterval:0.05 target:self selector:@selector(goEnemyLeft) userInfo:nil repeats:YES]; } } -(IBAction)enemyStopLeft { if (CGRectIntersectsRect(bluebox.frame, redbox.frame)) { [enemyLeftTimer invalidate]; enemyLeftTimer = nil; } } -(void)goEnemyLeft { if (redbox.center.x + [self getRedboxWidthLeft] > bluebox.center.x + [self getBlueboxWidthRight]) { redbox.center = CGPointMake(redbox.center.x -5, redbox.center.y); } } So the first bit is saying for it to set up a timer to continue moving left. The next will stop the timer if my player(bluebox) and the Computer player(redbox) collide. Finally, the thing that actually tells it to go left, but only if the bluebox is left of the redbox. The getRedBoxWidth Left and getBlueBoxWidthRight are just voids that get, well, the left and right edges. If you could, please help try and solve this code. Thank You.

    Read the article

  • How i can block calling onCreate while rotating device when My AsyncTask start?

    - by Labeeb P
    Hi, Me testing in Samsung Galaxy tab. In that i have made two layout folder for both ORIENTATION_LANDSCAPE and ORIENTATION_PORTRAIT with specific layout xml in it. In that layout i have a button and on clicking it start a progress dialog (doing some stuff using AsyncTask, after that going to new intent) But when the device is rotated when the progress dialog is working, that dialog and AsyncTask stop and new layout is loaded. If i understood correctly, I think the onCreate is called when device is rotated How i can block calling onCreate while rotating device when My AsyncTask start? Thank you

    Read the article

  • will destroyed() be emitted if the constructor of a class derived from QObject throws?

    - by PorkyBrain
    Ive seen Qt GUI syntax like the following all over the place: myDialog::myDialog(QWidget *parent, Qt::WFlags flags):QDialog(parent, flags) { QPushButton *button = new QPushButton("&Download", this); QVBoxLayout *layout = new QVBoxLayout(this); //something that can throw here layout ->addWidget(button ); setLayout(layout); } I've always wondered if this can leak in the event of an exception because the "this" I'm giving as a parent to button and layout is not fully constructed so it might not destroy its children. I tried it out in MSVC2010 Qt4.8.3 and it looks like as soon as the base QObject class is fully created (which is done first of course) it is ok to pass "this" to other objects in the constructor, they will destroyed correctly. I haven't found the spot in the Qt docs guaranteeing this though, can someone point me to it so I have assurance that this will not change in the future?

    Read the article

  • Align two columns with CSS

    - by user1853172
    I have markup like <div> <label for="a" class="float-left">column 1 row 1</label> <input type="text" value="column 2 row 1" id="a" class="float-left"/> <div class="float-clear"></div> <div> <label for="b" class="float-left">longer column 1 row 2</label> <input class="float-left" type="text" value="column 2 row 2" id="b" /> <div class="float-clear"></div> <div> <label class="float-left" for="c">column 1 row 2</label> <input class="float-left" type="checkbox" id="c" /> How can I make column two rows to be aligned on the left, currently they are positioned depending on the length of the the text in the label? I don't want a full CSS grid just for this one place where I need alignment.

    Read the article

  • map kind of asp.net application

    - by stackoverflowuser
    I want to create a asp.net application which can show directions in a layout from room A to room B. So layout would be a grid of rooms and if the user wants to get directions from room A to room B the application to highlight the path in blue. I have no idea how to begin with this? What can i use to create a floor layout and then highlight the required path. Any pointers ? Thanks.

    Read the article

  • How do I determine the coordinates of controls in a WM_INITDIALOG message?

    - by René Nyffenegger
    I am having troubles to determine the (what I believe to be the) client coordinates of a (radio button) control in the WM_INITDIALOG message of a DlgProc. Here's what I try: // Retrieve coordinates of Control with respect to the screen. RECT rectOrthoButton; GetWindowRect(GetDlgItem(hWnd, IDC_ORTHO), &rectOrthoButton); // Translate coordinates to more useful coordinates: those that // are used on the dialog. // In order to do the translation we have to find the top left // point (coordinates) of the dialog's client: POINT dlgTopLeft; ClientToScreen(hWnd, &dlgTopLeft); // With these coordinates we can do the translation. // We're only interested in top and left, so we skip // bottom and right: rectOrthoButton.top -= dlgTopLeft.y; rectOrthoButton.left -= dlgTopLeft.x; use_top_and_left(rectOrthoButton.top, rectOrthoButton.left); I expected rectOrthoButton.top and .left to be the top left coordinates of my control with respect to the dialog's client area. It turns out they aren't and I am not sure what they point to as rectOrthoButton.left is equal to -40.

    Read the article

  • Reporting Services - It's a Wrap!

    - by smisner
    If you have any experience at all with Reporting Services, you have probably developed a report using the matrix data region. It's handy when you want to generate columns dynamically based on data. If users view a matrix report online, they can scroll horizontally to view all columns and all is well. But if they want to print the report, the experience is completely different and you'll have to decide how you want to handle dynamic columns. By default, when a user prints a matrix report for which the number of columns exceeds the width of the page, Reporting Services determines how many columns can fit on the page and renders one or more separate pages for the additional columns. In this post, I'll explain two techniques for managing dynamic columns. First, I'll show how to use the RepeatRowHeaders property to make it easier to read a report when columns span multiple pages, and then I'll show you how to "wrap" columns so that you can avoid the horizontal page break. Included with this post are the sample RDLs for download. First, let's look at the default behavior of a matrix. A matrix that has too many columns for one printed page (or output to page-based renderer like PDF or Word) will be rendered such that the first page with the row group headers and the inital set of columns, as shown in Figure 1. The second page continues by rendering the next set of columns that can fit on the page, as shown in Figure 2.This pattern continues until all columns are rendered. The problem with the default behavior is that you've lost the context of employee and sales order - the row headers - on the second page. That makes it hard for users to read this report because the layout requires them to flip back and forth between the current page and the first page of the report. You can fix this behavior by finding the RepeatRowHeaders of the tablix report item and changing its value to True. The second (and subsequent pages) of the matrix now look like the image shown in Figure 3. The problem with this approach is that the number of printed pages to flip through is unpredictable when you have a large number of potential columns. What if you want to include all columns on the same page? You can take advantage of the repeating behavior of a tablix and get repeating columns by embedding one tablix inside of another. For this example, I'm using SQL Server 2008 R2 Reporting Services. You can get similar results with SQL Server 2008. (In fact, you could probably do something similar in SQL Server 2005, but I haven't tested it. The steps would be slightly different because you would be working with the old-style matrix as compared to the new-style tablix discussed in this post.) I created a dataset that queries AdventureWorksDW2008 tables: SELECT TOP (100) e.LastName + ', ' + e.FirstName AS EmployeeName, d.FullDateAlternateKey, f.SalesOrderNumber, p.EnglishProductName, sum(SalesAmount) as SalesAmount FROM FactResellerSales AS f INNER JOIN DimProduct AS p ON p.ProductKey = f.ProductKey INNER JOIN DimDate AS d ON d.DateKey = f.OrderDateKey INNER JOIN DimEmployee AS e ON e.EmployeeKey = f.EmployeeKey GROUP BY p.EnglishProductName, d.FullDateAlternateKey, e.LastName + ', ' + e.FirstName, f.SalesOrderNumber ORDER BY EmployeeName, f.SalesOrderNumber, p.EnglishProductName To start the report: Add a matrix to the report body and drag Employee Name to the row header, which also creates a group. Next drag SalesOrderNumber below Employee Name in the Row Groups panel, which creates a second group and a second column in the row header section of the matrix, as shown in Figure 4. Now for some trickiness. Add another column to the row headers. This new column will be associated with the existing EmployeeName group rather than causing BIDS to create a new group. To do this, right-click on the EmployeeName textbox in the bottom row, point to Insert Column, and then click Inside Group-Right. Then add the SalesOrderNumber field to this new column. By doing this, you're creating a report that repeats a set of columns for each EmployeeName/SalesOrderNumber combination that appears in the data. Next, modify the first row group's expression to group on both EmployeeName and SalesOrderNumber. In the Row Groups section, right-click EmployeeName, click Group Properties, click the Add button, and select [SalesOrderNumber]. Now you need to configure the columns to repeat. Rather than use the Columns group of the matrix like you might expect, you're going to use the textbox that belongs to the second group of the tablix as a location for embedding other report items. First, clear out the text that's currently in the third column - SalesOrderNumber - because it's already added as a separate textbox in this report design. Then drag and drop a matrix into that textbox, as shown in Figure 5. Again, you need to do some tricks here to get the appearance and behavior right. We don't really want repeating rows in the embedded matrix, so follow these steps: Click on the Rows label which then displays RowGroup in the Row Groups pane below the report body. Right-click on RowGroup,click Delete Group, and select the option to delete associated rows and columns. As a result, you get a modified matrix which has only a ColumnGroup in it, with a row above a double-dashed line for the column group and a row below the line for the aggregated data. Let's continue: Drag EnglishProductName to the data textbox (below the line). Add a second data row by right-clicking EnglishProductName, pointing to Insert Row, and clicking Below. Add the SalesAmount field to the new data textbox. Now eliminate the column group row without eliminating the group. To do this, right-click the row above the double-dashed line, click Delete Rows, and then select Delete Rows Only in the message box. Now you're ready for the fit and finish phase: Resize the column containing the embedded matrix so that it fits completely. Also, the final column in the matrix is for the column group. You can't delete this column, but you can make it as small as possible. Just click on the matrix to display the row and column handles, and then drag the right edge of the rightmost column to the left to make the column virtually disappear. Next, configure the groups so that the columns of the embedded matrix will wrap. In the Column Groups pane, right-click ColumnGroup1 and click on the expression button (labeled fx) to the right of Group On [EnglishProductName]. Replace the expression with the following: =RowNumber("SalesOrderNumber" ). We use SalesOrderNumber here because that is the name of the group that "contains" the embedded matrix. The next step is to configure the number of columns to display before wrapping. Click any cell in the matrix that is not inside the embedded matrix, and then double-click the second group in the Row Groups pane - SalesOrderNumber. Change the group expression to the following expression: =Ceiling(RowNumber("EmployeeName")/3) The last step is to apply formatting. In my example, I set the SalesAmount textbox's Format property to C2 and also right-aligned the text in both the EnglishProductName and the SalesAmount textboxes. And voila - Figure 6 shows a matrix report with wrapping columns. Share this post: email it! | bookmark it! | digg it! | reddit! | kick it! | live it!

    Read the article

  • My SSD stopped working as it ends up in blue death right after windows 7 launches, how can I reset it for new windows install?

    - by HattoriHanzo
    As I mentioned in the title my SSD suddenly started to fail as after launching Windows 7 it goes straight to completely idle and after a few minutes it goes to blue death and restarts. I have an another HD with a windows xp on it and it works fine and I can also see the SSD and can access everything on it. Windows 7 on the SSD does work in safe mode though yet I didn't manage to find out what causes the problem. Since I can sill access the files and save them to another HD I'm looking for the best way to wipe and reinstall Windows 7. I have yet failed to find an easy to follow (or even understand) guide, different sources on the internet recommend different ways of doing this. And some guides are just simply full of terms I have no clue about. It's an OCZ Vertex 2 120GB. I"d very much appreciate if someone could give me an advice on what I should do, preferably in a way so I could regain the best possible performance as well. it doesn't matter if I don't understand the science behind it as long as I can follow the steps. Thanks!

    Read the article

  • Local user vs. domain user? What is the right way here?

    - by ebeeb
    I'm a software developer in a company with 6 employees. Everyone has a machine for him-/herself, so none of the machines is shared. I'm currently setting up my machine with Windows 8 and was experimenting a bit with domain and local user accounts. Correct me please if I'm wrong, but I think the idea behind is, that domain users generally should not be able to modify the configuration of a machine (like installing software), since they are able to login on every single machine in the domain. The local user (usually just one local administrator per machine) is the one who cares about the configuration of the machine. But in my case the login into the domain is just for being able to access directories/servers in the domain (I do not really know the details, all I know is, that loggin into the domain user account is necessary). So overall I've got a local admin account and a domain account used on my machine. While working I'm logged in to my domain user account. But it annoys me, that I always need to enter the credentials of my local user account when I'm about to update/install something, which happens quite often as a software developer. I fixed this with adding the domain account into the user accounts in my control panel and putting it into the Administrators group. The only thing I wanted to know about this: is there something REALLY bad about doing this? Or is there maybe a more common way to be able to act like a local admin, while logged in as a domain user? PS: I'm sorry about the tags, but I don't know the proper ones. I'd be glad if some of the superuser experts could fix this :-)

    Read the article

  • LAMP Stack Version Help -- Is there a website or version tracker source to help suggest the right versions of each part of a platform stack?

    - by Chris Adragna
    Taken singly, it's easy to research versions and compatibility. Version information is readily available on each single part of a platform stack, such as MySQL. You can find out the latest version, stable version, and sometimes even the percentage of people adopting it by version (personally, I like seeing numbers on adoption rates). However, when trying to find the best possible mix of versions, I have a harder time. For example, "if you're using MySQL 5.5, you'll need PHP version XX or higher." It gets even more difficult to mitigate when you throw higher level platforms into the mix such as Drupal, Joomla, etc. I do consider "wizard" like installers to be beneficial, such as the Bitnami installers. However, I always wonder if those solutions cater more to the least common denominator -- be all to many -- and as such, I think I'd be better to install things on my own. Such solutions do seem kind of slow to adopt new versions, slower than necessary, I suspect. Is there a website or tool that consolidates versioning data in order to help a webmaster choose which versions to deploy or which upgrades to install, in consideration of all the other parts of the stack?

    Read the article

  • How can I determine the first visible tile in an isometric perspective?

    - by alekop
    I am trying to render the visible portion of a diamond-shaped isometric map. The "world" coordinate system is a 2D Cartesian system, with the coordinates increasing diagonally (in terms of the view coordinate system) along the axes. The "view" coordinates are simply mouse offsets relative to the upper left corner of the view. My rendering algorithm works by drawing diagonal spans, starting from the upper right corner of the view and moving diagonally to the right and down, advancing to the next row when it reaches the right view edge. When the rendering loop reaches the lower left corner, it stops. There are functions to convert a point from view coordinates to world coordinates and then to map coordinates. Everything works when rendering from tile 0,0, but as the view scrolls around the rendering needs to start from a different tile. I can't figure out how to determine which tile is closest to the upper right corner. At the moment I am simply converting the coordinates of the upper right corner to map coordinates. This works as long as the view origin (upper right corner) is inside the world, but when approaching the edges of the map the starting tile coordinate obviously become invalid. I guess this boils down to asking "how can I find the intersection between the world X axis and the view X axis?"

    Read the article

  • Combining two operators in Evil-mode Emacs

    - by Dyslexic Tangent
    In vim I've remapped > and < when in visual mode to >gv and <gv respectively, like so: vnoremap > >gv vnoremap < <gv Since my target for this question are folks experienced with emacs and not vim, what > and < do is indent/dedent visually selected text. What gv does is reselect the previously selected text. These maps cause > and < to indent/dedent and then reselect the previously selected text. I'm trying out emacs with evil-mode and I'd like to do the same, but I'm having some difficulty figuring out how, exactly, to accomplish the automatic reselection. It looks like I need to somehow call evil-shift-right and evil-visual-restore sequentially, but I don't know how to create a map that will do both, so I tried creating my own function which would call both sequentially and map that instead, but it didn't work, possibly due to the fact that both of them are defined, not as functions with defun but instead as operators with evil-define-operator. I tried creating my own operators: (evil-define-operator shift-left-reselect (beg end) (evil-shift-left beg end) (evil-visual-restore)) (evil-define-operator shift-right-reselect (beg end) (evil-shift-right beg end) (evil-visual-restore)) but that doesn't restore visual as expected. A stab in the dark gave me this: (evil-define-operator shift-left-reselect (beg end) (evil-shift-left beg end) ('evil-visual-restore)) (evil-define-operator shift-right-reselect (beg end) (evil-shift-right beg end) ('evil-visual-restore)) but that selects one additional line whenever it is supposed to reselect. For now I've been using the following, which only has the problem where it reselects an additional line in the < operator. (evil-define-operator shift-right-reselect (beg end) (evil-shift-right beg end) (evil-visual-make-selection beg end)) (evil-define-operator shift-left-reselect (beg end) (evil-shift-left beg end) (evil-visual-make-selection beg end)) and I've mapped them: (define-key evil-visual-state-map ">" 'shift-right-reselect) (define-key evil-visual-state-map "<" 'shift-left-reselect) any help / pointers / tips would be greatly appreciated. Thanks in advance.

    Read the article

  • Binding a wpf listbox to a combobox

    - by user293545
    Hi there, I have created a very basic wpf application that I want to use to record time entries against different projects. I havent used mvvm for this as I think its an overkill. I have a form that contains a combobox and a listbox. I have created a basic entity model like this What I am trying to do is bind the combobox to Project and whenever I select an item from the combobox it updates the listview with the available tasks associated with that project. This is my xaml so far. I dont have any code behind as I have simply clicked on that Data menu and then datasources and dragged and dropped the items over. The application loads ok and the combobox is been populated however nothing is displaying in the listbox. Can anyone tell me what I have missed? <Window.Resources> <CollectionViewSource x:Key="tasksViewSource" d:DesignSource="{d:DesignInstance l:Task, CreateList=True}" /> <CollectionViewSource x:Key="projectsViewSource" d:DesignSource="{d:DesignInstance l:Project, CreateList=True}" /> </Window.Resources> <Grid DataContext="{StaticResource tasksViewSource}"> <l:NotificationAreaIcon Text="Time Management" Icon="Resources\NotificationAreaIcon.ico" MouseDoubleClick="OnNotificationAreaIconDoubleClick"> <l:NotificationAreaIcon.MenuItems> <forms:MenuItem Text="Open" Click="OnMenuItemOpenClick" DefaultItem="True" /> <forms:MenuItem Text="-" /> <forms:MenuItem Text="Exit" Click="OnMenuItemExitClick" /> </l:NotificationAreaIcon.MenuItems> </l:NotificationAreaIcon> <Button Content="Insert" Height="23" HorizontalAlignment="Left" Margin="150,223,0,0" Name="btnInsert" VerticalAlignment="Top" Width="46" Click="btnInsert_Click" /> <ComboBox Height="23" HorizontalAlignment="Left" Margin="70,16,0,0" Name="comProjects" VerticalAlignment="Top" Width="177" DisplayMemberPath="Project1" ItemsSource="{Binding Source={StaticResource projectsViewSource}}" SelectedValuePath="ProjectID" /> <Label Content="Projects" Height="28" HorizontalAlignment="Left" Margin="12,12,0,0" Name="label1" VerticalAlignment="Top" IsEnabled="False" /> <Label Content="Tasks" Height="28" HorizontalAlignment="Left" Margin="16,61,0,0" Name="label2" VerticalAlignment="Top" /> <ListBox Height="112" HorizontalAlignment="Left" Margin="16,87,0,0" Name="lstTasks" VerticalAlignment="Top" Width="231" DisplayMemberPath="Task1" ItemsSource="{Binding Path=ProjectID, Source=comProjects}" SelectedValuePath="TaskID" /> <TextBox Height="23" HorizontalAlignment="Left" Margin="101,224,0,0" Name="txtMinutes" VerticalAlignment="Top" Width="42" /> <Label Content="Mins to Insert" Height="28" HorizontalAlignment="Left" Margin="12,224,0,0" Name="label3" VerticalAlignment="Top" /> <Button Content="None" Height="23" HorizontalAlignment="Left" Margin="203,223,0,0" Name="btnNone" VerticalAlignment="Top" Width="44" /> </Grid>

    Read the article

  • set difference in SQL query

    - by TheObserver
    I'm trying to select records with a statement SELECT * FROM A WHERE LEFT(B, 5) IN (SELECT * FROM (SELECT LEFT(A.B,5), COUNT(DISTINCT A.C) c_count FROM A GROUP BY LEFT(B,5) ) p1 WHERE p1.c_count = 1 ) AND C IN (SELECT * FROM (SELECT A.C , COUNT(DISTINCT LEFT(A.B,5)) b_count FROM A GROUP BY C ) p2 WHERE p2.b_count = 1) which takes a long time to run ~15 sec. Is there a better way of writing this SQL?

    Read the article

  • Why does this JSON.parse code not work?

    - by SuZi
    I am trying to pass json encoded values from a php script to a, GnuBookTest.js, javascript file that initiates a Bookreader object and use the values i have passed in via the variable i named "result". The php script is sending the values like: <div id="bookreader"> <div id="BookReader" style="left:10px; right:10px; top:30px; bottom:30px;">x</div> <script type="text/javascript">var result = {"istack":"zi94sm65\/BUCY\/BUCY200707170530PM","leafCount":"14","wArr":"[893,893,893,893,893,893,893,893,893,893,893,893,893,893]","hArr":"[1155,1155,1155,1155,1155,1155,1155,1155,1155,1155,1155,1155,1155,1155]","leafArr":"[0,1,2,3,4,5,6,7,8,9,10,11,12,13]","sd":"[\"RIGHT\",\"LEFT\",\"RIGHT\",\"LEFT\",\"RIGHT\",\"LEFT\",\"RIGHT\",\"LEFT\",\"RIGHT\",\"LEFT\",\"RIGHT\",\"LEFT\",\"RIGHT\",\"LEFT\"]"}</script> <script type="text/javascript" src="http://localhost:8080/application/js/GnuBookTest.js"></script> </div> </div> and in the GnuBookTest.js file i am trying to use the values like: br = new BookReader(); // Return the width of a given page. br.getPageWidth = function(index) { return this.pageW[index]; } // Return the height of a given page. br.getPageHeight = function(index) { return this.pageH[index]; } br.pageW = JSON.parse(result.wArr); br.pageH = JSON.parse(result.hArr); br.leafMap = JSON.parse(result.leafArr); //istack is an url fragment for location of image files var istack = result.istack; . . . Using JSON.parse as i have written it above loads the Bookreader and uses my values correctly in a few web-browsers: Firefox, IE8, and desktop-Safari; but does not work at all in mac-Chrome, mobile-Safari, plus older versions of IE. Mobile safari keeps giving me a reference error msg: can't find variable: JSON. The other browsers just do not load the Bookreader and show the "x" instead, like they did not get the values from the php script. Where is the problem?

    Read the article

  • jquery if statement animate back

    - by user295292
    how do i add a if statement when the right image is at +400px then animate back to -400px... when hovering the right image? $('#left img').mouseenter(function() { $('#right img').animate({ left: '+=400px' }, 700); }); $('#right img').mouseenter(function() { $('#left img').animate({ left: '-=400px' }, 700); }); something similar to this - http://www.hyundaiusa.com/ (the two main images on the site)

    Read the article

  • How do I control the direction of the scroll on my coda slider?

    - by lightingwrist
    Hello, I have a coda slider and am unable to determine the direction of the scroll. I have 3 panels that I want to scroll left to right. Sometimes it scrolls left to right, sometimes up and down, and sometimes horizontally. How do I lock it down to go the direction I want? Here is the HTML: <body> <div id="slider_home" class="round_10px"> <ul class="navigation_home"> <li><a href="#scroll_Parents" class="round_10px">Information For Parents</a></li> <li><a href="#scroll_Materials" class="round_10px">Print Materials</a></li> <li><a href="#scroll_Resources" class="round_10px">Online Resources</a></li> </ul> <div id="scroll_bg_home"> <div class="scroll_home"> <div class="scrollContainer_home"> <div class="panel_home" id="scroll_Parents"> content </div> <div class="panel_home" id="scroll_Materials"> content </div> <div class="panel_home" id="scroll_Resources"> content </div> </div> </div> </div> </div> </body> Here is the CSS: #wrapper {width:550px;margin:0px auto;} #intro {padding-bottom:10px;} h2 {margin:0;margin-bottom:14px;padding:0;} #slider {width:631px;margin:10px auto 0px auto;position:relative;} #scroll_bg{height:360px;width:590px;overflow:hidden;position:relative;clear:left;background:#FFFFFF url(images/) no-repeat; margin:0px auto 0px auto} .scroll{ background:transparent; width:550px; height:370px; padding:0px; margin:0px auto; overflow:hidden; } .scrollContainer div.panel {padding:20px 0px;height:330px; width:550px;margin:0px;float:left;} #shade {background:#EDEDEC url(images/shade.jpg) no-repeat 0 0;height:50px;} ul.navigation {list-style:none;margin:0px 0px 0px 23px;padding:0px;padding-bottom:0px;} ul.navigation li {display:inline; margin-right:5px;} ul.navigation li a { background:#FFFFFF;font-family:Arial, Helvetica, sans-serif; font-size:16px; font-weight:bold; color:#CCCCCC;padding:5px 5px 5px 5px;border:1px #F4F4F4 solid;text-decoration: none;} ul.navigation a:hover { color:#EDEDEC;border:1px #E6E6E6 solid;} ul.navigation a.selected {color:#333333;} ul.navigation a:focus {outline:none;} .scrollButtons {position:absolute;top:150px;cursor:pointer;} .scrollButtons.left {left:-37px;top:20px} .scrollButtons.right {right:-32px;top:20px;} .hide {display:none;} And here is the Jquery includes file: // when the DOM is ready... $(document).ready(function () { var $panels = $('#slider_home .scrollContainer_home > div.panel_home'); var $container = $('#slider_home .scrollContainer_home'); // if true, we'll float all the panels left and fix the width // of the container var horizontal = true; // float the panels left if we're going horizontal if (horizontal) { $panels.css({ 'float' : 'left', 'position' : 'relative' // IE fix to ensure overflow is hidden }); // calculate a new width for the container (so it holds all panels) $container.css('width', $panels[0].offsetWidth * $panels.length); } // collect the scroll object, at the same time apply the hidden overflow // to remove the default scrollbars that will appear var $scroll_bg = $('#scroll_bg_home'); var $scroll = $('#slider_home .scroll_home').css('overflow', 'hidden'); // apply our left + right buttons $scroll_bg .before('<img class="scrollButtons_home left" src="styles/images/BackFlip.jpg" />') .after('<img class="scrollButtons_home right" src="styles/images/flipForward.jpg" />'); // handle nav selection function selectNav() { $(this) .parents('ul:first') .find('a') .removeClass('selected') .end() .end() .addClass('selected'); } $('.navigation_home').find('a').click(selectNav); // go find the navigation link that has this target and select the nav function trigger(data) { var el = $('.navigation_home').find('a[href$="' + data.id + '"]').get(0); selectNav.call(el); } if (window.location.hash) { trigger({ id : window.location.hash.substr(1) }); } else { $('.navigation_home a:first').click(); } // offset is used to move to *exactly* the right place, since I'm using // padding on my example, I need to subtract the amount of padding to // the offset. Try removing this to get a good idea of the effect var offset = parseInt((horizontal ? $container.css('paddingTop') : $container.css('paddingLeft')) || 0) * -1; var scrollOptions = { target: $scroll, // the element that has the overflow // can be a selector which will be relative to the target items: $panels, navigation: '.navigation_home a', // selectors are NOT relative to document, i.e. make sure they're unique prev: 'img.left', next: 'img.right', // allow the scroll effect to run both directions axis: 'xy', onAfter: trigger, // our final callback offset: offset, // duration of the sliding effect duration: 500, // easing - can be used with the easing plugin: // http://gsgd.co.uk/sandbox/jquery/easing/ easing: 'swing' }; // apply serialScroll to the slider - we chose this plugin because it // supports// the indexed next and previous scroll along with hooking // in to our navigation. $('#slider_home').serialScroll(scrollOptions); // now apply localScroll to hook any other arbitrary links to trigger // the effect $.localScroll(scrollOptions); // finally, if the URL has a hash, move the slider in to position, // setting the duration to 1 because I don't want it to scroll in the // very first page load. We don't always need this, but it ensures // the positioning is absolutely spot on when the pages loads. scrollOptions.duration = 1; $.localScroll.hash(scrollOptions); });

    Read the article

  • How to assert certain method is called with Ruby minitest framework?

    - by steven.yang
    I want to test whether a function invokes other functions properly with minitest Ruby, but I cannot find a proper assert to test from the doc. The source code class SomeClass def invoke_function(name) name == "right" ? right () : wrong () end def right #... end def wrong #... end end The test code: describe SomeClass do it "should invoke right function" do # assert right() is called end it "should invoke other function" do # assert wrong() is called end end

    Read the article

  • Multiple instances of this carousel on a single page - can't get it to work

    - by Andy
    This code comes from a tutorial so it's not originally my own work. What I am trying to do is implement this several times on a single page. I have tried and so far failed - by numbering the id "carousel" and so forth. Any help would be seriously appreciated. I'm tearing my hair out. http://jsfiddle.net/AndyMP/zcKDV/5/ For completeness.. this is the carousel JQuery as it stands. //rotation speed and timer var speed = 5000; var run = setInterval('rotate()', speed); //grab the width and calculate left value var item_width = $('#slides li').outerWidth(); var left_value = item_width * (-1); //move the last item before first item, just in case user click prev button $('#slides li:first').before($('#slides li:last')); //set the default item to the correct position $('#slides ul').css({'left' : left_value}); //if user clicked on prev button $('#prev').click(function() { //get the right position var left_indent = parseInt($('#slides ul').css('left')) + item_width; //slide the item $('#slides ul').animate({'left' : left_indent}, 200,function(){ //move the last item and put it as first item $('#slides li:first').before($('#slides li:last')); //set the default item to correct position $('#slides ul').css({'left' : left_value}); }); //cancel the link behavior return false; }); //if user clicked on next button $('#next').click(function() { //get the right position var left_indent = parseInt($('#slides ul').css('left')) - item_width; //slide the item $('#slides ul').animate({'left' : left_indent}, 200, function () { //move the first item and put it as last item $('#slides li:last').after($('#slides li:first')); //set the default item to correct position $('#slides ul').css({'left' : left_value}); }); //cancel the link behavior return false; }); //if mouse hover, pause the auto rotation, otherwise rotate it $('#slides').hover( function() { clearInterval(run); }, function() { run = setInterval('rotate()', speed); } ); //a simple function to click next link //a timer will call this function, and the rotation will begin :) function rotate() { $('#next').click(); }

    Read the article

  • How to replicate this button in CSS

    - by jasondavis
    I am trying to create a CSS theme switcher button like below. The top image shows what I have so far and the bottom image shows what I am trying to create. I am not the best at this stuff I am more of a back-end coder. I could really use some help. I have a live demo of the code here http://dabblet.com/gist/2230656 Just looking at what I have and the goal image, some differences. I need to add a gradient The border is not right on mine Radius is a little off Possibly some other stuff? Also here is the code...it can be changed anyway to improve this, the naming and stuff could be improved I am sure but I can use any help I can get. HTML <div class="switch-wrapper"> <div class="switcher left selected"> <span id="left">....</span> </div> <div class="switcher right"> <span id="right">....</span> </div> </div> CSS /* begin button styles */ .switch-wrapper{ width:400px; margin:220px; } .switcher { background:#507190; display: inline-block; max-width: 100%; box-shadow: 1px 1px 1px rgba(0,0,0,.3); position:relative; } #left, #right{ width:17px; height:11px; overflow:hidden; position:absolute; top:50%; left:50%; margin-top:-5px; margin-left:-8px; font: 0/0 a; } #left{ background-image: url(http://www.codedevelopr.com/assets/images/switcher.png); background-position: 0px px; } #right{ background-image: url(http://www.codedevelopr.com/assets/images/switcher.png); background-position: -0px -19px; } .left, .right{ width: 30px; height: 25px; border: 1px solid #3C5D7E; } .left{ border-radius: 6px 0px 0px 6px; } .right{ border-radius: 0 6px 6px 0; margin: 0 0 0 -6px } .switcher:hover, .selected { background: #27394b; box-shadow: -1px 1px 0px rgba(255,255,255,.4), inset 0 4px 5px rgba(0,0,0,.6), inset 0 1px 2px rgba(0,0,0,.6); }

    Read the article

  • Update multiple table column values using single query

    - by Dave Jarvis
    How would you update data in multiple tables using a single query? In MySQL it would be: UPDATE party p LEFT JOIN party_name n ON p.party_id = n.party_id LEFT JOIN party_details d ON p.party_id = d.party_id LEFT JOIN incident_participant ip ON ip.party_id = p.party_id LEFT JOIN incident i ON ip.incident_id = i.incident_id SET p.employee_id = NULL, c.em_address = '[email protected]', c.ad_postal = 'x', n.first_name = 'x', n.last_name = 'x' WHERE i.confidential_dt IS NOT NULL What is the equivalent SQL statement using Oracle 11g? (Is ANSI SQL possible?) Thank you!

    Read the article

  • IE7 and IE8: Float clearing without adding empty elements

    - by tk-421
    Hello, I'm having a problem similar to the one described here (without a resolution): http://stackoverflow.com/questions/2467745/ie7-float-and-clear-on-the-same-element The following HTML renders as intended in Firefox but not in (both) IE7 and IE8: <html> <head> <style> ul { list-style-type: none; } li { clear: both; padding: 5px; } .left { clear: left; float: left; } .middle { clear: none; float: left; } .right { clear: right; float: left; } </style> </head> <body> <ul> <li>1</li> <li class="left">2</li> <li class="right">3</li> <li class="left">4</li> <li class="middle">5</li> <li class="right">6</li> <li>7</li> </ul> </body> </html> This is a form layout, and in Firefox the results appear like: 1 2 3 4 5 6 7 That's what I'm going for. In IE7 and IE8 however, the results are: 1 2 3 5 6 4 7 [Note: I don't want to float anything to the right because I want the fields on my form to left-align correctly, without a giant space in-between the floated fields to account for the parent container's width.] Apparently I need a full clear, and can probably add an empty list-item element to the list to force clearing, but that seems like a dumb solution and sort of defeats the purpose. Any ideas? I've spent a few hours reading and trying different options without success.

    Read the article

  • positioning image using css

    - by TomBs
    hi, i really need to place an image somewhere in the page (100 pixels from the left side for example) but i want to control where the center of the image will be, when i use left:100px; , the image is positioned 100px from its left edge and not from its center... is there a way i can choose where the center of the image will be and not the left/right edge?

    Read the article

  • IOS-Fixed content in UIScrollview

    - by heaven
    I have a problem with UIScrollView and UILabel. I'm adding UILabel using addSubview inside UIScrollView, one UILabel on the top set Width: 3000 - height: 20; other UILabel on the left: set height: 1000 - width: 50; In the middle UISCrollView is here I wanna When scroll horizontal the UILabel on the top move to left or right (doesn't move to up or down) When scroll vertical the UILabel on the left move to up or down (doesn't move right or left)

    Read the article

< Previous Page | 154 155 156 157 158 159 160 161 162 163 164 165  | Next Page >