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  • ViewPager and Fragment Pager adapter implementation

    - by Rohit Deshmukh
    So I am trying to implement sliding views/fragments using viewpager and fragment pager adapter. convert_home is my main xml file that has android.support.v4.view.PagerTitleStrip and temperature.xml and velocity.xml are my two other views. I have no clue where I am going wrong. package app.converto; import android.os.Bundle; import android.support.v4.app.Fragment; import android.support.v4.app.FragmentActivity; import android.support.v4.app.FragmentManager; import android.support.v4.app.FragmentPagerAdapter; import android.support.v4.view.ViewPager; import android.view.LayoutInflater; import android.view.Menu; import android.view.View; import android.view.ViewGroup; import android.widget.TextView; public class ConverTo extends FragmentActivity { SectionsPagerAdapter mSectionsPagerAdapter; ViewPager mViewPager; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); mSectionsPagerAdapter = new SectionsPagerAdapter(getSupportFragmentManager()); mViewPager.setAdapter(mSectionsPagerAdapter); setContentView(R.layout.converto_home); mViewPager = (ViewPager) findViewById(R.id.pager); } @Override public boolean onCreateOptionsMenu(Menu menu) { getMenuInflater().inflate(R.menu.converto_home, menu); return true; } public class SectionsPagerAdapter extends FragmentPagerAdapter { public SectionsPagerAdapter(FragmentManager fm) { super(fm); } @Override public Fragment getItem(int i) { switch(i){ case 0: Fragment1 fragment = new Fragment1(); return fragment; case 1: Fragment2 fragment2 = new Fragment2(); return fragment2; } defaultFragment fragment3 = new defaultFragment(); return fragment3; } @Override public int getCount() { return 2; } // // @Override // public CharSequence getPageTitle(int position) { // switch (position) { // case 0: return getString(R.string.velocity); // case 1: return getString(R.string.temperature); // case 2: return getString(R.string.distance); // } // return null; // } } public static class Fragment1 extends Fragment{ public Fragment1(){ } @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); } @Override public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { //return inflater.inflate(R.layout.temperature, container, false); View view = inflater.inflate(R.layout.temperature, container, false); TextView textView = (TextView) view.findViewById(R.id.sample); textView.setText(getArguments().getString("title")); return view; } } public static class Fragment2 extends Fragment{ public Fragment2(){ } @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); } @Override public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { //return inflater.inflate(R.layout.velocity, container, false); View view = inflater.inflate(R.layout.temperature, container, false); TextView textView = (TextView) view.findViewById(R.id.sample); textView.setText(getArguments().getString("title")); return view; } } public static class defaultFragment extends Fragment{ public defaultFragment(){ }//end constructor @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); } @Override public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { // return inflater.inflate(R.layout.temperature, container, false); View view = inflater.inflate(R.layout.temperature, container, false); TextView textView = (TextView) view.findViewById(R.id.sample); textView.setText(getArguments().getString("title")); return view; }//end oncreate }//end default fragment }

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  • Returning HTML in the JS portion of a respond_to block throws errors in IE

    - by Horace Loeb
    Here's a common pattern in my controller actions: respond_to do |format| format.html {} format.js { render :layout => false } end I.e., if the request is non-AJAX, I'll send the HTML content in a layout on a brand new page. If the request is AJAX, I'll send down the same content, but without a layout (so that it can be inserted into the existing page or put into a lightbox or whatever). So I'm always returning HTML in the format.js portion, yet Rails sets the Content-Type response header to text/javascript. This causes IE to throw this fun little error message: Of course I could set the content-type of the response every time I did this (or use an after_filter or whatever), but it seems like I'm trying to do something relatively standard and I don't want to add additional boilerplate code. How do I fix this problem? Alternatively, if the only way to fix the problem is to change the content-type of the response, what's the best way to achieve the behavior I want (i.e., sending down content with layout for non-AJAX and the same content without a layout for AJAX) without having to deal with these errors? Edit: This blog post has some more info

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  • Interchange structured data between Haskell and C

    - by Eonil
    First, I'm a Haskell beginner. I'm planning integrating Haskell into C for realtime game. Haskell does logic, C does rendering. To do this, I have to pass huge complexly structured data (game state) from/to each other for each tick (at least 30 times per second). So the passing data should be lightweight. This state data may laid on sequential space on memory. Both of Haskell and C parts should access every area of the states freely. In best case, the cost of passing data can be copying a pointer to a memory. In worst case, copying whole data with conversion. I'm reading Haskell's FFI(http://www.haskell.org/haskellwiki/FFICookBook#Working_with_structs) The Haskell code look specifying memory layout explicitly. I have a few questions. Can Haskell specify memory layout explicitly? (to be matched exactly with C struct) Is this real memory layout? Or any kind of conversion required? (performance penalty) If Q#2 is true, Any performance penalty when the memory layout specified explicitly? What's the syntax #{alignment foo}? Where can I find the document about this? If I want to pass huge data with best performance, how should I do that? *PS Explicit memory layout feature which I said is just C#'s [StructLayout] attribute. Which is specifying in-memory position and size explicitly. http://www.developerfusion.com/article/84519/mastering-structs-in-c/ I'm not sure Haskell has matching linguistic construct matching with fields of C struct.

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  • How to disable log4j logging from Java code

    - by Erel Segal Halevi
    I use a legacy library that writes logs using log4j. My default log4j.properties file directs the log to the console, but in some specific functions of my main program, I would like to disable logging altogether (from all classes). I tried this: Logger.getLogger(BasicImplementation.class.getName()).setLevel(Level.OFF); where "BasicImplementation" is one of the main classes that does logging, but it didn't work - the logs are still written to the console. Here is my log4j.properties: log4j.rootLogger=warn, stdout log4j.logger.ac.biu.nlp.nlp.engineml=info, logfile log4j.logger.org.BIU.utils.logging.ExperimentLogger=warn log4j.appender.stdout = org.apache.log4j.ConsoleAppender log4j.appender.stdout.layout = org.apache.log4j.PatternLayout log4j.appender.stdout.layout.ConversionPattern = %-5p %d{HH:mm:ss} [%t]: %m%n log4j.appender.logfile = ac.biu.nlp.nlp.log.BackupOlderFileAppender log4j.appender.logfile.append=false log4j.appender.logfile.layout = org.apache.log4j.PatternLayout log4j.appender.logfile.layout.ConversionPattern = %-5p %d{HH:mm:ss} [%t]: %m%n log4j.appender.logfile.File = logfile.log

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  • Need to add WHERE condition to query

    - by Angel Carlson
    I am trying to modify edit_orders.php in Zen Cart. Hoping someone might be able to help me add a condition to a query. I need the queries below to specify that the items selected from TABLE_PRODUCTS_DESCRIPTION and TABLE_CATEGORIES_DESCRIPTION must have a language_id = 1. Would be so grateful for any help you could provide. // ############################################################################ // Get List of All Products // ############################################################################ //$result = zen_db_query("SELECT products_name, p.products_id, x.categories_name, ptc.categories_id FROM " . TABLE_PRODUCTS . " p LEFT JOIN " . TABLE_PRODUCTS_DESCRIPTION . " pd ON pd.products_id=p.products_id LEFT JOIN " . TABLE_PRODUCTS_TO_CATEGORIES . " ptc ON ptc.products_id=p.products_id LEFT JOIN " . TABLE_CATEGORIES_DESCRIPTION . " cd ON cd.categories_id=ptc.categories_id LEFT JOIN " . TABLE_CATEGORIES_DESCRIPTION . " x ON x.categories_id=ptc.categories_id ORDER BY categories_id"); $result = $db -> Execute("SELECT products_name, p.products_id, categories_name, ptc.categories_id FROM " . TABLE_PRODUCTS . " p LEFT JOIN " . TABLE_PRODUCTS_DESCRIPTION . " pd ON pd.products_id=p.products_id LEFT JOIN " . TABLE_PRODUCTS_TO_CATEGORIES . " ptc ON ptc.products_id=p.products_id LEFT JOIN " . TABLE_CATEGORIES_DESCRIPTION . " cd ON cd.categories_id=ptc.categories_id ORDER BY categories_name");

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  • Binding for MinWidth property does not work in Silverlight

    - by Akash Kava
    I have noticed something very unusual today, I need to bind "MinWidth" property of TextBlock to some value, however following example does not work. It only accepts MinWidth at a time of creation, but after that it is not affected at all if LeftWidth property is changed at runtime, however if I bind LeftWidth property to WidthProperty it works well. Binding b = new Binding("LeftWidth"); // following never changes layout of control tb.SetBinding(TextBlock.MinWidthProperty,b); However, this one works correctly, // following never changes layout of control tb.SetBinding(TextBlock.WidthProperty,b); Now I also did hook events and tried to do InvalidateMeasure and InvalidateArrange on TextBlock, but it has no effect. Seems like Changing MinWidth Property after layout pass does not work at all. Can it be a bug in Silverlight? or Does anyone have any idea at all why MinWidth does not redo the layout?

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  • Emacs, Linux and international keyboard layouts

    - by sabof
    Is there an easy way to use emacs key-bindings when you are using a not-English (Russian) keyboard layout? Whenever an international layout is on, all keystrokes are interpreted literally, M-? instead of M-a. As a result I can't use commands. It would also be nice if Linux could interpret non-prefixed and shift-prefixed keys according according to an international layout, while keeping the rest English.

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  • How to determine loading status of images not attached to the DOM

    - by Rookwood
    I am working on a bit of javascript to plot data on a <canvas. The data points are marked by one of several different (small) image files. I am attempting to have the plot method wait until all the images are loaded. My best attempt thus far is such: var icon = { left : { air : new Image(), bone : new Image(), }, right : { air: new Image(), bone : new Image(), }, }; icon.left.air.src = option.imgPath + 'left.air.png'; icon.right.air.src = option.imgPath + 'right.air.png'; icon.left.bone.src = option.imgPath + 'left.bone.png'; icon.right.bone.src = option.imgPath + 'right.bone.png'; function main() { Canvas.draw(); // Make sure our image icons are loaded before we try to plot $(icon.left.air).load(function() { $(icon.right.air).load(function() { $(icon.left.bone).load(function() { $(icon.right.bone).load(function() { Data.plot(); }); }); }); }); } This works as expected most of the time. On occasion, it will fail and no data will be plotted. Inserting several console.log() statements shows that the script will silently stop working through the series of .load() statements, though code that comes after will be executed. My questions are as follows: Am I approaching this the right way? Is there a way to attach an event to my icon object that will fire once all of the images inside are loaded? This is a jquery plugin, so obviously jquery-based solutions are just as acceptable as vanilla javascript.

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  • PHP Object Oriented Web Application

    - by Sev
    I have a class called "Layout" for the layout of the page, another class called "User" for the user. Every page I create, I instantiate a new Layout. When a user logs in, there is a new User instantiated. How do I get an instance of the layout class to know about the instantiated user? I could also save the entire instance of the User in a session variable. I assume that's a bad idea though. What are the best practices for this?

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  • position of View on asp.net mvc site master page

    - by ognjenb
    How fix data table to open only in Main Content Frame? Structure of my site.master page is: left content, main content and right content. When open View page in main content she goes to the right content if it is large. Is this CSS problem? My problem is similar to this http://www.inq.me/post/ASPNet-MVC-Extension-method-to-create-a-Security-Aware-HtmlActionLink.aspx This is my CSS(come with template): /*~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ PRIMARY LAYOUT STYLES ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~*/ .content-container { position:relative; _height:1px; min-height:1px; width:900px; /* background:url(images/bg-column-left.png) repeat-y;*/ } .content-container-inner { /*background:url(images/bg-column-right.png) repeat-y right;*/ _height:1px; min-height:1px; /*padding:0 200px;*/ position:relative; /*width:900px;*/ } .content-main { padding :15px 0% 0px 2%; /*position:relative;*/ min-height:1px; _height:1px; float:left; position:relative; /*width:96%;*/ /*width:900px;*/ } .content-left { padding:20px 10px; float:left; width:180px; margin-top:-1px; position:relative; margin-left:-100%; right:200px; _left:200px; border-top:1px dotted #797979; } .content-right { padding :15px 10px 10px 10px; float:left; width:160px; position:relative; margin-right:-200px; } .ads { text-align:center; margin:20px 0; } /*~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

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  • Clearing block affects wrong floating

    - by HiveHicks
    I've got two-column layout <div class="left-pane"> Left pane </div> <div class="central-pane"> <div> <ul class="customers-types-tabs"> <li>item 1</li> <li>item 2</li> <li>item 3</li> </ul> </div> <div>Main content</div> </div> and the stylesheet: .left-pane { width: 248px; float: left; background-color: #f6f6f6; border: 1px solid #e6e6e6; padding: 20px 5px; } .central-pane { margin-left: 270px; } .customers-types-tabs li { background-color: #f6f6f6; border: 1px solid #d5d5d5; line-height: 38px; padding: 0 20px; float: left; margin-right: 10px; position: relative; top: 1px; } The problem is that I want "Main content" to appear right below the div with ul inside it (that represents tabs control), but if I set Main content's div's style to clear: both, it appears below the left pane, which is taller than the ul. What should I do to get correct position of main content?

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  • My list item's child label elements disappear in IE on accordion menu opening

    - by Scott B
    I've got an app that's working pretty flawlessly in Chrome and FF, however, when I view it in IE, all is well until I click on a header element to activate it (jQuery accordion). What happens then is that I see a brief flash where the content is there, then suddenly the entire left column disappears. This column is generated by a floated label element with a class of ".left" as seen below... <ul class="menu collapsible"> <li class='expand sectionTitle'><a href='#'>General Settings</a> <ul class='acitem'> <li class="section"> <label class="left">This item if floated left with a defined width of 190px via css. This is the item that's disappearing after a brief display</label> <input class="input" value="input element here" /> <label class="description">This element has a margin-left:212px; set via css in order to be positioned to the right of the label element as if in an adjacent table cell. When I add a max-width property to this element, it disappears in IE too!</label> </li> </ul> </li> </ul> As you can see from the comments in the code above (for the two label elements) the description label disappears once I set a max-width on it (I don't have a max-width on the left label element, but it disappears nonetheless). The initial view of this UL menu is fine (note the expand class declaration which makes this part of the accordion open at startup. Its not until I click the "General Settings" to toggle it closed, then back open, that the left class elements disappear (and only in IE)

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  • Why is my quick sort so slow?

    - by user513075
    Hello, I am practicing writing sorting algorithms as part of some interview preparation, and I am wondering if anybody can help me spot why this quick sort is not very fast? It appears to have the correct runtime complexity, but it is slower than my merge sort by a constant factor of about 2. I would also appreciate any comments that would improve my code that don't necessarily answer the question. Thanks a lot for your help! Please don't hesitate to let me know if I have made any etiquette mistakes. This is my first question here. private class QuickSort implements Sort { @Override public int[] sortItems(int[] ts) { List<Integer> toSort = new ArrayList<Integer>(); for (int i : ts) { toSort.add(i); } toSort = partition(toSort); int[] ret = new int[ts.length]; for (int i = 0; i < toSort.size(); i++) { ret[i] = toSort.get(i); } return ret; } private List<Integer> partition(List<Integer> toSort) { if (toSort.size() <= 1) return toSort; int pivotIndex = myRandom.nextInt(toSort.size()); Integer pivot = toSort.get(pivotIndex); toSort.remove(pivotIndex); List<Integer> left = new ArrayList<Integer>(); List<Integer> right = new ArrayList<Integer>(); for (int i : toSort) { if (i > pivot) right.add(i); else left.add(i); } left = partition(left); right = partition(right); left.add(pivot); left.addAll(right); return left; } }

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  • OpenGL and layouts

    - by Hnefi
    I'm using OpenGL to render a game view in my android application. The game is turn based and I wish to add some buttons to the interface. I'd prefer to use standard Android widgets, structured in an XML-generated layout (or, if I have to, a hardcoded layout) and put the OpenGL view in its own window as part of that layout. So in regards to this, I have 3 questions: 1: Is such a thing possible? I've done a few half-hearted tries, but have had no luck so far. 2: Is such a thing advisable? Does it carry a significant performance penalty, for example, over using OpenGL-based homebrew widgetry? 3: Is it possible to pass particular arguments to instances created in XML layouts? For example, my current OpenGL view has three arguments in its constructor; is it somehow possible for me to invoke that particular constructor with particular parameters when it's part of a layout?

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  • Using formLabel in FormPanel for Localization

    - by user1782712
    I am trying to implement Localization within a panel, so to make the fieldLabel accessable from another file I am defining it like this Ext.define('Ext.app.detailForm', { extend: 'Ext.form.Panel', id: 'cscForm', // frame: true, uncomment this to show blue frame background title: 'CSC Details :', //trying cscCode: 'CSC Code', bodyPadding: 5, layout: 'anchor', // Specifies that the items will now be arranged in columns autoScroll: true, //width:1200, //height: 300, collapsible: true, fieldDefaults: { labelAlign: 'left', msgTarget: 'side' }, items: [{ columnWidth: 0.4, xtype: 'container', layout:'anchor', defaults: { labelWidth: 150 }, defaultType: 'textfield', items: [{ xtype: 'container', layout: 'hbox', items:[{ xtype: 'fieldset', columnWidth:1.5, layout: 'column', width:1050, defaultType: 'textfield', defaults: { labelWidth: 150, margin: '3 0 0 10' }, items: [{ fieldLabel: this.cscCode, name: 'CSCCode', width: 500 }, {..... but when I try to render this panel, the formLabel for cscCode does not display, is there some thing which I am doing wrong here? I am basically not able to access "this.cscCode"

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  • How to restrict bounds for Translate Animation for a view in Android?

    - by Kiran Parmar
    Hello All. Let me explain the scenario that I want to achieve:- Consider the below as the Layout I have inside a Parent_Linearlayout: [Linear Layout] (Fill_Parent, Wrap_Content) [ScrollView] Activity's setContentView is set to the Parent_Linearlayout In the application, when a condition is met, I want the Scrollview to be removed from the screen and instead put another View in its place.<br> I've been able to do this, When I remove the ScrollView, I'm applying translate Animation to it so that it seems as if the View has gone to the top, before removing it. But when the animation occurs, the ScrollView translates OVER the Linear layout present above it. How do I restrict it, so that the scrollview does not go over the linear layout, but disappears at the base of the Linearlayout. I want the linearlayout to always stay visible.. I've been trying to do this from quite some time, but I've not been able to get desired results.. Could someone kindly help me out here??

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  • Multiple Rails forks with separate designs and layouts

    - by mettadore
    I have a Rails project that is basically a simple web app for a membership-based organization. We've open sourced the code on Github for the web app so that others can use it, but have a licensed design/layout that the original organization is going to use. This layout cannot be open sourced. I was wondering if others have run into the situation where you have an open-source Rails app with a non-OS design. My initial thought is to put app/views in .gitignore, and to have anyone forking the code add their own views directory, perhaps including an app/views_default directory with a web-app-theme layout or something else to get people running. Is this the best option (realizing that there are other files such as JavaScript, CSS, etc that come with the layout that must also be ignored). Does anyone have some good thoughts or pointers on this?

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  • How do I (or should I?) access the service layer from a SiteMesh template (views/layouts/main.gsp) in Grails?

    - by knorv
    I need to create a toplist in the page footer on a site that I'm building. The footer is created in the default SiteMesh layout template (views/layouts/main.gsp). In order to create the toplist access to the database is needed, so I've encapsulated all logic needed for the toplist creation in a service class (services/FooService). Please note that while services are usually accessed from the controller layer, in this case the default layout template (views/layouts/main.gsp) is not generated from a controller. Can the layout view (views/layouts/main.gsp) access a service class? How? Is this the correct design decision? If not, what is a better encapsulation and how do I interact with said encapsulation from the layout view (views/layouts/main.gsp)?

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  • Spinner activity not working

    - by user1696863
    I'm trying to create an activity, RateCardActivity, which has a spinner in it. My layout file for RateCardActivity is rate_card. My RateCardActivity looks like the following. public class RateCardActivity { public void onCreate(Bundle bundle) { super.onCreate(bundle); setContentView(R.layout.rate_card); Spinner spinner = (Spinner) findViewById(R.id.select_city); ArrayAdapter<CharSequence> adapter = ArrayAdapter.createFromResource(this, R.array.select_city, android.R.layout.simple_spinner_item); adapter.setDropDownViewResource(android.R.layout.simple_spinner_dropdown_item); spinner.setAdapter(adapter); } } The layout file rate_card is: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:custom="http://schemas.android.com/apk/res/com.olacabs.customer" android:layout_width="fill_parent" android:layout_height="fill_parent" android:orientation="vertical" > <TextView android:id="@+id/textView1" android:layout_width="fill_parent" android:layout_height="wrap_content" android:background="@android:color/darker_gray" android:gravity="center" android:paddingBottom="4dp" android:paddingTop="4dp" android:text="@string/rate_card" android:textColor="@color/white" android:textSize="20dp" custom:customFont="litera_bold.ttf" /> <Spinner android:id="@+id/select_city" android:layout_width="fill_parent" android:layout_height="wrap_content" /> </LinearLayout> The RateCardActivity is called from another activity using an intent (I'm sure there is nothing wrong with that part of the code as when I substitute RateCardActivity with another activity, the application works fine). When I try to open the RateCardActivity in the application in emulator, the application crashes and I got the message "The application has stopped unexpectedly. Please try again later." I can't seem to understand what I'm doing wrong, and want to know how to correct this?

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  • inflate vs findViewById

    - by Cedric
    Hi all, Suppose I have a simple layout xml like the following: button.xml: Are there any differences in the following calls? and which one should i use? button = (Button) getLayoutInflater().inflate(R.layout.button, null); and View v = getLayoutInflater().inflate(R.layout.button, null); button = (Button) v.findViewById(R.id.button01);

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  • Android ListView in Activity

    - by Dev.Android
    My layout is like this Title Layout Listview BottomLayout. I have an 150 item which i have custom layout which i want to add in listview. So my main problem is i want to add slowly slowly one by one that customlayouts in listview. So whenever the first screen is displayed i want load 10 items from server and add it to listview.then onscroll down i want to load the remaining 10 items from 150 cutom layouts. So how can I do this activity?

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  • Create a simple automatic image switcher using jQuery

    - by Kim Andersen
    Hi all. I need to create a very simple image switcher that changes my images automatically. I have the following code: <div class="imgCarousel"> <div class="imgC1 left"><img src="/media/1614/1_1.jpg" alt="img1" /></div> <div class="imgC2 left"><img src="/media/1615/2_1.jpg" alt="img2" /></div> <div class="imgC3 left"><img src="/media/1616/3_1.gif" alt="img3" /></div> <div class="imgC4 left"><img src="/media/1617/4_1.jpg" alt="img4" /></div> <div class="imgC5 left"><img src="/media/1618/5_1.jpg" alt="img5a" /></div> <div class="imgC6 left"><img src="/media/1620/6_1.jpg" alt="img6a" /></div> <div class="imgC7 left"><img src="/media/1622/7.jpg" alt="img7" /></div> </div> Two of the above images should be switched automatically after a certain amount of time (every 3-4 sec.). This means that after 4 seconds, I'd like to change the image called /media/1618/5_1.jpg with another image. And after another 4 seconds, I'd switch back again. The same shold be made for one of my other images. How can I acomplish this with some jQuery?

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  • jQuery relative positioned hover

    - by danixd
    I want a link to the next or previous image to appear when hovering over the main image, only I want the next link to appear when hovered over the right hand side, and previous on the left. I have looked at jQuery's .position() and I don't think I am understanding it very well. At the moment all I have is general mouseenter/mouseleave events, which show both links when the image is hovered. jQuery(document).ready(function($) { $('.nav-controls a').hide(); $('#slideshow').mouseenter(function() { $('.nav-controls a').fadeIn(500); }); $('#slideshow').mouseleave(function() { $('.nav-controls a').fadeOut(500); }); }); I'd image it to be something like: jQuery(document).ready(function($) { $('.nav-controls a').hide(); var image = $('#slideshow'); var left = image.position().left(0); var right = image.position().left(50%); left.mouseenter(function() { $('.nav-controls a.previous').fadeIn(500); }); left.mouseleave(function() { $('.nav-controls a.previous').fadeOut(500); }); right.mouseenter(function() { $('.nav-controls a.next').fadeIn(500); }); right.mouseleave(function() { $('.nav-controls a.next').fadeOut(500); }); }); Not sure if I should be using position, if I am using it correctly. Any tips would be great. Edit: I do not want to add unnecessary markup in the form of divs, for the left/right selectors.

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  • Checkbox Context Menu

    - by MostafaEweda
    I have a ListView and an adapter in whick I create a linear layout and return as my created element. When this linear layout is just TextViews, the context menu appears normally, When I add a checkbox to the layout, the context menu isn't shown. Is there any solution to this problem ?

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