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  • Choosing between YUI Charts or Google Visualization API

    - by r2b2
    Hello , I'm a bit stuck with which charting library I will use in my project. Im stuck with this two (but also open for other suggestions) For YUI Charts : Pro : - Very robust and configurable Cons : - Uses flash 9 , which might potentially be inaccessible for users without up to date flash version - Does not support export to image (for flash versions < 10 only) For Google Visualization API pros: - small file size for the libraries, - can be exported to static image charts (via separate API call) Cons - limited configuration options So there, please help me decide. YUI charts has the edge over configuration options but Google Visualization API has the edge in terms of accessibility as it uses SVG to render the grapsh instead of Flash. For users that are hand-cuffed by corporate IT prohibitions , they cant just upgrade their Flash version and the page will not work. Thanks!

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  • Building a Monopoly Board with GridBagLayout

    - by Oetzi
    I have been building a Java version of Monopoly in my spare time and am having some trouble understanding layouts etc for Swing. Each one of my spaces on the board is a essentially a custom JButton and I have been trying to lay them around the edge of a frame (like on the monopoly board itself). I can't seem to find a useful explanation of how the layout system works and so am having trouble do so. Could someone please give me an example of how they would lay the buttons around the edge of the frame? Should I be using a different layout?

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  • Formula for producing a CGRect for a UIScrollView, that displays a UIImage in scaled to fit way

    - by RickiG
    Hi I am loading in images with varying sizes and putting them in UIScrollViews, all the images are larger than the UIScrollView. The user can scroll and zoom as they please, but initially I would like for the image to be centered and scaled so the largest side of the image aligns with the edge of the scrollView, i.e. if the picture is in landscape I would like to size and scale it so that the left and right side goes all the way to the edge of the UIScrollVIew and vice versa I found a formula in a utility function in the Programming guide but it does not quite fit my needs. My approach is to use: CGrect initialPos = ? [self.scrollView zoomToRect:initialPos animated:YES]; I know the size of my scrollView and the size of my image, what I need to figure out is the scale and CGRect to apply to the scrollView to center and size my image. Hope someone can help out:) Thanks

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  • Qt: Styling QTabWidget

    - by Martin
    I'm using Qt and I have a QTabWidget setup in the Qt Designer Editor, you can see it in picture 1. As you can see after Tab4 there is an empty space all the way to the right edge, in someway I need to fill that space with a color, like in picture 2. Or another solution would be that the tabs float out to cover the whole screen. I use the following stylesheet right now: QTabWidget::tab-bar { } QTabBar::tab { background: gray; color: white; padding: 10px; } QTabBar::tab:selected { background: lightgray; } Is there a way to set the background color of the QTabBar using Qt stylesheets? Or can I get the tabs floating out to the edge using Qt stylesheets? Thanks!

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  • Resize AIR app window while dragging

    - by matt lohkamp
    So I've noticed Windows 7 has a disturbing tendency to prevent you from dragging the title bar of windows off the top of the screen. If you try - in this case, using an air app with a draggable area at the bottom of the window, allowing you to push the top of the window up past the screen - it just kicks the window back down far enough that the title bar is at the top of what it considers the 'visible area.' One solution would be to resize the app window as it moves, so that the title bar is always where windows wants it. How would you resize the window while you're dragging it, though? Would you do it like this? dragHitArea.addEventListener(MouseEvent.MOUSE_DOWN, function(e:MouseEvent):void{ stage.nativeWindow.height += 50; stage.nativeWindow.startMove(); stage.nativeWindow.height -= 50; }); see what's going on there? When I click, I'm doing startMove(), which is hooking into the OS' function for dragging a window around. I'm also increasing and decreasing the height of the window by 50 pixels - which should give me no net increase, right? Wrong - the first '.height +=' gets executed, but the '.height -=' after the .startMove() never runs. Why? update - If you're curious, I'm programming an air widget with fly-out menus which expand rightwards and upwards - and since those element can only be displayed within the boundaries of the application window itself (even though the window is set to be chromeless and transparent) I have to expand the application's borders to include the area that the menu 'pops up' into. In the extreme case, with the widget positioned bottom left, and the menus expanded completely across to the right side and top edge of the screen, the application area could very well cover the entire desktop. The problem is, when it's expanded like this, if the user drags it up and to the right, it causes the 'title bar' area of the application window to move above the top edge of the desktop area, where it would normally be unreachable; and Windows automatically re-positions the window back below that edge once the .startMove() operation is completed. So what I want to do is continually resize the height of the application so that the visual effect will be the same for the user, but for the benefit of the operating system the window's title bar will never be above that top boundary of the desktop area.

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  • Eliminating cyclic flows from a graph

    - by Jon Harrop
    I have a directed graph with flow volumes along edges and I would like to simplify it by removing all cyclic flows. This can be done by finding the minimum of the flow volumes along each edge in any given cycle and reducing the flows of every edge in the cycle by that minimum volume, deleting edges with zero flow. When all cyclic flows have been removed the graph will be acyclic. For example, if I have a graph with vertices A, B and C with flows of 1 from A?B, 2 from B?C and 3 from C?A then I can rewrite this with no flow from A?B, 1 from B?C and 2 from C?A. The number of edges in the graph has reduced from 3 to 2 and the resulting graph is acyclic. Which algorithm(s), if any, solve this problem?

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  • c# with asp.net

    - by indu
    i need to place a panel in the screen with border color blue, border type solid and the panel should have a rounded corner in all four edge of the panel

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  • PHP: creating a smooth edged circle, image or font?

    - by Chad Whitaker
    I'm making a PHP image script that will create circles at a given radius. I used: <?php imagefilledellipse ( $image, $cx, $cy, $w, $h, $color ); ?> but hate the rough edges it produces. So I was thinking of making or using a circle font that I will output using: <?php imagettftext ( $image, $size, $angle, $x, $y, $color, 'fontfile.ttf', $text ); ?> So that the font will produce a circle that has a smooth edge. My problem is making the "font size" match the "radius size". Any ideas? Or maybe a PHP class that will produce a smooth edge on a circle would be great! Thank you.

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  • AspectFit Not Working for Transformed UIImageView

    - by Dex
    I have a UIImageView inside a subview and I'm trying to get an AspectFit content mode working how I want for a 90 degree transformation. Here is a demo app of what I mean https://github.com/rdetert/image-scale-test If you run the app and hold it in a landscape orientation (app runs in landscape) you'll see that the image does not stretch from left edge to right edge. What seems to be happening is that the AspectFit works correctly for the portrait/default orientation, but then the image simply gets rotated the image after the fact. How can I make it auto stretch? I think the fact that it is inside a subview may have something to do with it?

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  • Writing the code by dividing it into more files in cocoatouch.

    - by srikanth rongali
    My problem is, I need a background image, a sprite(with animation) on left edge, another sprite(with animation) at other edge, a number count animation 1-2-3 at middle. I got all these when I wrote all in same file.(like [self addChild:label], [self addChild:sprite].., But in this it needs touch enables for both sprites separately, and touchDisabled to the remaining screen. So thought of writing in different files. But now it is not working. I kept one sprite, background image, numbercount in one file and another spritr in other file. Either I am getting the second sprite or the (sprite+background+numberCount) is displayed. This is my problem. plz give me solution. Thank You

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  • Writing the code iby dividing it into more files.

    - by srikanth rongali
    My problem is, I need a background image, a sprite(with animation) on left edge, another sprite(with animation) at other edge, a number count animation 1-2-3 at middle. I got all these when I wrote all in same file.(like [self addChild:label], [self addChild:sprite].., But in this it needs touch enables for both sprites separately, and touchDisabled to the remaining screen. So thought of writing in different files. But now it is not working. I kept one sprite, background image, numbercount in one file and another spritr in other file. Either I am getting the second sprite or the (sprite+background+numberCount) is displayed. This is my problem. plz give me solution. Thank You

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  • Stuck on solving the Minimal Spanning Tree problem.

    - by kunjaan
    I have reduced my problem to finding the minimal spanning tree in the graph. But I want to have one more constraint which is that the total degree for each vertex shouldnt exceed a certain constant factor. How do I model my problem? Is MST the wrong path? Do you know any algorithms that will help me? One more problem: My graph has duplicate edge weights so is there a way to count the number of unique MSTs? Are there algorithms that do this? Thank You. Edit: By degree, I mean the total number of edges connecting the vertex. By duplicate edge weight I mean that two edges have the same weight.

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  • How to use AutoLayout to position UIButtons in horizontal lines?

    - by thomers
    I need to create a couple of UIButtons programmatically in my app (iOS 6.0 and above). Each button should have the optimal width to display button label text (of various lenghts). I want to display the buttons in a "wrap around" style: Starting from the left edge, each button should be positioned next to each other horizontally (in a defined order), and if a button does not fit in the current "line", it should start a new line on the left edge below the previous line. I could manually calculate the frame of each button in my code, but should I use AutoLayout (with programmatically creates NSLayoutConstraints) instead? How exactly would I need to set it up?

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  • Shortest distance between points on a toroidally wrapped (x- and y- wrapping) map?

    - by mstksg
    I have a toroidal-ish Euclidean-ish map. That is the surface is a flat, Euclidean rectangle, but when a point moves to the right boundary, it will appear at the left boundary (at the same y value), given by x_new = x_old % width Basically, points are plotted based on: (x_new, y_new) = ( x_old % width, y_old % height) Think Pac Man -- walking off one edge of the screen will make you appear on the opposite edge. What's the best way to calculate the shortest distance between two points? The typical implementation suggests a large distance for points on opposite corners of the map, when in reality, the real wrapped distance is very close. The best way I can think of is calculating Classical Delta X and Wrapped Delta X, and Classical Delta Y and Wrapped Delta Y, and using the lower of each pair in the Sqrt(x^2+y^2) distance formula. But that would involve many checks, calculations, operations -- some that I feel might be unnecessary. Is there a better way?

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  • Weakly connected balanced digraph

    - by user1074557
    How can I prove that if a balanced digraph is weakly connected, then it is also strongly connected? (balanced digraph means that for every node, it's indegree and outdegree is the same and weakly connected means the non-directed version of this graph is connected). What I can think of so far is: if the graph is balanced, it means it is a union of directed cycles. So if I remove any cycle, it will stay balanced. Also each vertex in the cycle has one edge coming into it and one edge leading out of it.. Then I guess I need to use some contradiction or induction to prove that the graph is strongly connected.. That's where I confused.

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  • OpenGL ES perspective projection

    - by TimeManx
    I'm having a hard time understanding how glFrustum & gluPerspective work. I understand the concept of perspective projection but the functions aren't behaving how I expect them to. For example, if I set the frustum this way glFrustumf(0, 10, 0, 10, 1, 100) and have a rectangle at points 0, 0, 1, 0, 10, 1, 10, 10, 1, 10, 0, 1 then the rectangle is drawn with its left edge at -5 & right edge at 5, so the left half of the rectangle isn't visible. And if x is translated, I'd expect y to be too. But that doesn't happen either. In whatever examples I've seen, the coordinates for the projection matrix are taken as glFrustumf(-10, 10, -10, 10, 1, 100) but either way, whatever part is shown should be dependent on the rectangle's coordinates, right?

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  • Make graphics on left and right side of text change width depending on the amount of text?

    - by Dustin McGrew
    I need to have an H1 tag centered between two graphics on the left and right of the text. The H1 text will be various widths depending on what page you are on. The dot on the left should stay on the left edge of the site and the line should extend until it reaches the edge of the text. Same for the right side. Is there a way to accomplish this by using CSS or even some jquery/javascript? In the attached graphic, if the text was just "WHO YOU ARE" I'd need the bars on the left and right to grow wider to bump up against the edges of the text.

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  • Custom InputIterator for Boost graph (BGL)

    - by Shadow
    Hi, I have a graph with custom properties to the vertices and edges. I now want to create a copy of this graph, but I don't want the vertices to be as complex as in the original. By this I mean that it would suffice that the vertices have the same indices (vertex_index_t) as they do in the original graph. Instead of doing the copying by hand I wanted to use the copy-functionality of boost::adjacency_list (s. http://www.boost.org/doc/libs/1_37_0/libs/graph/doc/adjacency_list.html): template <class EdgeIterator> adjacency_list(EdgeIterator first, EdgeIterator last, vertices_size_type n, edges_size_type m = 0, const GraphProperty& p = GraphProperty()) The description there says: The EdgeIterator must be a model of InputIterator. The value type of the EdgeIterator must be a std::pair, where the type in the pair is an integer type. The integers will correspond to vertices, and they must all fall in the range of [0, n). Unfortunately I have to admit that I don't quite get it how to define an EdgeIterator that is a model of InputIterator. Here's what I've succeded so far: template< class EdgeIterator, class Edge > class MyEdgeIterator// : public input_iterator< std::pair<int, int> > { public: MyEdgeIterator() {}; MyEdgeIterator(EdgeIterator& rhs) : actual_edge_it_(rhs) {}; MyEdgeIterator(const MyEdgeIterator& to_copy) {}; bool operator==(const MyEdgeIterator& to_compare) { return actual_edge_it_ == to_compare.actual_edge_it_; } bool operator!=(const MyEdgeIterator& to_compare) { return !(*this == to_compare); } Edge operator*() const { return *actual_edge_it_; } const MyEdgeIterator* operator->() const; MyEdgeIterator& operator ++() { ++actual_edge_it_; return *this; } MyEdgeIterator operator ++(int) { MyEdgeIterator<EdgeIterator, Edge> tmp = *this; ++*this; return tmp; } private: EdgeIterator& actual_edge_it_; } However, this doesn't work as it is supposed to and I ran out of clues. So, how do I define the appropriate InputIterator?

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  • Disable Opera Thumbnail Previews on Windows 7 Taskbar

    - by Asian Angel
    If you are one of the people who does not care for the Taskbar Thumbnail Previews in Windows 7 then we have a quick and easy way for you to turn them off in Opera Browser. Before Here is our Opera Browser with four tabs full of HTG Network goodness… Hovering the mouse over the Taskbar Icon gives a nice preview of each tabs content. Looking closer you can see the fanned edge on the Taskbar Icon indicating that there are multiple tabs open. This is all good but what if you just want something simpler? Disabling the Previews If you want to disable the Taskbar Thumbnail Previews in Opera you will need to type opera:config in the Address Bar and press Enter. Once you have done that, you will see a condensed listing for all of Opera’s preferences. There is one Preference Category that we need to look for…User Prefs. Note: While a Quick Find Search could be conducted for the entry that needs to be modified, we have chosen to show the full method here. After scrolling down and finding the User Prefs category you will need to expand the section. Notice the size of the scrollbar in comparison with the screenshot above…there is quite a lot that you can look at and finesse in Opera if desired. Scroll down until you find the Use Windows 7 Taskbar Thumbnails entry. Uncheck the box but do not close the opera:config Tab yet…or your changes will not take effect. Scroll down once more until you reach the end of the User Prefs category and click Save. With this particular modification you will need to restart Opera after clicking OK. After restarting Opera the Taskbar Icon and Taskbar Thumbnail Preview will revert to the minimal Windows 7 default as shown here. You can see Opera’s Tab Bar in the thumbnail and the Taskbar Icon no longer has a “fanned edge”. Conclusion If you want to disable Opera’s Taskbar Thumbnail Previews on your Windows 7 system, then this quick modification will help get it sorted out in just a few moments. Similar Articles Productive Geek Tips Disable IE 8 Thumbnail Previews on Windows 7 TaskbarIncrease the size of Taskbar Preview Thumbnails in Windows 7Vista Style Popup Previews for Firefox TabsEnable Thumbnail Previews for Firefox in Windows 7 TaskbarWorkaround for Vista Taskbar Thumbnail Previews Not Showing Correctly TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips All My Movies 5.9 CloudBerry Online Backup 1.5 for Windows Home Server Snagit 10 VMware Workstation 7 10 Superb Firefox Wallpapers OpenDNS Guide Google TV The iPod Revolution Ultimate Boot CD can help when disaster strikes Windows Firewall with Advanced Security – How To Guides

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  • Applied Security for Oracle Business Intelligence Podcast

    - by Tim Dexter
    Listen to BI Security Meister, Bryan Wise talk about his recent book Applied Oracle Security and learn about the cutting edge techniques for Oracle Business Intelligence from a leading security expert. http://www.oracle.com/podcasts/author-podcasts.html - Applied Security for Oracle Business Intelligence Well worth the listen and of course the book is available at all discerning bookstores!

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  • Friday Fun: Factory Balls – Christmas Edition

    - by Asian Angel
    Your weekend is almost here, but until the work day is over we have another fun holiday game for you. This week your job is to correctly decorate/paint the ornaments that go on the Christmas tree. Simple you say? Maybe, but maybe not! Factory Balls – Christmas Edition The object of the game is to correctly decorate/paint each Christmas ornament exactly as shown in the “sample image” provided for each level. What starts off as simple will quickly have you working to figure out the correct combination or sequence to complete each ornament. Are you ready? The first level serves as a tutorial to help you become comfortable with how to decorate/paint the ornaments. To move an ornament to a paint bucket or cover part of it with one of the helper items simply drag the ornament towards that area. The ornament will automatically move back to its’ starting position when the action is complete. First, a nice coat of red paint followed by covering the middle area with a horizontal belt. Once the belt is on move the ornament to the bucket of yellow paint. Next, you will need to remove the belt, so move the ornament back to the belt’s original position. One ornament finished! As soon as you complete decorating/painting an ornament, you move on to the next level and will be shown the next “sample Image” in the upper right corner. Starting with a coat of orange paint sounds good… Pop the little serrated edge cap on top… Add some blue paint… Almost have it… Place the large serrated edge cap on top… Another dip in the orange paint… And the second ornament is finished. Level three looks a little bit tougher…just work out your pattern of helper items & colors and you will definitely get it! Have fun decorating/painting those ornaments! Note: Starting with level four you will need to start using a combination of two helper items combined at times to properly complete the ornaments. Play Factory Balls – Christmas Edition Latest Features How-To Geek ETC The Complete List of iPad Tips, Tricks, and Tutorials The 50 Best Registry Hacks that Make Windows Better The How-To Geek Holiday Gift Guide (Geeky Stuff We Like) LCD? LED? Plasma? The How-To Geek Guide to HDTV Technology The How-To Geek Guide to Learning Photoshop, Part 8: Filters Improve Digital Photography by Calibrating Your Monitor Exploring the Jungle Ruins Wallpaper Protect Your Privacy When Browsing with Chrome and Iron Browser Free Shipping Day is Friday, December 17, 2010 – National Free Shipping Day Find an Applicable Quote for Any Programming Situation Winter Theme for Windows 7 from Microsoft Score Free In-Flight Wi-Fi Courtesy of Google Chrome

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  • Move penetrating OBB out of another OBB to resolve collision

    - by Milo
    I'm working on collision resolution for my game. I just need a good way to get an object out of another object if it gets stuck. In this case a car. Here is a typical scenario. The red car is in the green object. How do I correctly get it out so the car can slide along the edge of the object as it should. I tried: if(buildings.size() > 0) { Entity e = buildings.get(0); Vector2D vel = new Vector2D(); vel.x = vehicle.getVelocity().x; vel.y = vehicle.getVelocity().y; vel.normalize(); while(vehicle.getRect().overlaps(e.getRect())) { vehicle.setCenter(vehicle.getCenterX() - vel.x * 0.1f, vehicle.getCenterY() - vel.y * 0.1f); } colided = true; } But that does not work too well. Is there some sort of vector I could calculate to use as the vector to move the car away from the object? Thanks Here is my OBB2D class: public class OBB2D { // Corners of the box, where 0 is the lower left. private Vector2D corner[] = new Vector2D[4]; private Vector2D center = new Vector2D(); private Vector2D extents = new Vector2D(); private RectF boundingRect = new RectF(); private float angle; //Two edges of the box extended away from corner[0]. private Vector2D axis[] = new Vector2D[2]; private double origin[] = new double[2]; public OBB2D(Vector2D center, float w, float h, float angle) { set(center,w,h,angle); } public OBB2D(float left, float top, float width, float height) { set(new Vector2D(left + (width / 2), top + (height / 2)),width,height,0.0f); } public void set(Vector2D center,float w, float h,float angle) { Vector2D X = new Vector2D( (float)Math.cos(angle), (float)Math.sin(angle)); Vector2D Y = new Vector2D((float)-Math.sin(angle), (float)Math.cos(angle)); X = X.multiply( w / 2); Y = Y.multiply( h / 2); corner[0] = center.subtract(X).subtract(Y); corner[1] = center.add(X).subtract(Y); corner[2] = center.add(X).add(Y); corner[3] = center.subtract(X).add(Y); computeAxes(); extents.x = w / 2; extents.y = h / 2; computeDimensions(center,angle); } private void computeDimensions(Vector2D center,float angle) { this.center.x = center.x; this.center.y = center.y; this.angle = angle; boundingRect.left = Math.min(Math.min(corner[0].x, corner[3].x), Math.min(corner[1].x, corner[2].x)); boundingRect.top = Math.min(Math.min(corner[0].y, corner[1].y),Math.min(corner[2].y, corner[3].y)); boundingRect.right = Math.max(Math.max(corner[1].x, corner[2].x), Math.max(corner[0].x, corner[3].x)); boundingRect.bottom = Math.max(Math.max(corner[2].y, corner[3].y),Math.max(corner[0].y, corner[1].y)); } public void set(RectF rect) { set(new Vector2D(rect.centerX(),rect.centerY()),rect.width(),rect.height(),0.0f); } // Returns true if other overlaps one dimension of this. private boolean overlaps1Way(OBB2D other) { for (int a = 0; a < axis.length; ++a) { double t = other.corner[0].dot(axis[a]); // Find the extent of box 2 on axis a double tMin = t; double tMax = t; for (int c = 1; c < corner.length; ++c) { t = other.corner[c].dot(axis[a]); if (t < tMin) { tMin = t; } else if (t > tMax) { tMax = t; } } // We have to subtract off the origin // See if [tMin, tMax] intersects [0, 1] if ((tMin > 1 + origin[a]) || (tMax < origin[a])) { // There was no intersection along this dimension; // the boxes cannot possibly overlap. return false; } } // There was no dimension along which there is no intersection. // Therefore the boxes overlap. return true; } //Updates the axes after the corners move. Assumes the //corners actually form a rectangle. private void computeAxes() { axis[0] = corner[1].subtract(corner[0]); axis[1] = corner[3].subtract(corner[0]); // Make the length of each axis 1/edge length so we know any // dot product must be less than 1 to fall within the edge. for (int a = 0; a < axis.length; ++a) { axis[a] = axis[a].divide((axis[a].length() * axis[a].length())); origin[a] = corner[0].dot(axis[a]); } } public void moveTo(Vector2D center) { Vector2D centroid = (corner[0].add(corner[1]).add(corner[2]).add(corner[3])).divide(4.0f); Vector2D translation = center.subtract(centroid); for (int c = 0; c < 4; ++c) { corner[c] = corner[c].add(translation); } computeAxes(); computeDimensions(center,angle); } // Returns true if the intersection of the boxes is non-empty. public boolean overlaps(OBB2D other) { if(right() < other.left()) { return false; } if(bottom() < other.top()) { return false; } if(left() > other.right()) { return false; } if(top() > other.bottom()) { return false; } if(other.getAngle() == 0.0f && getAngle() == 0.0f) { return true; } return overlaps1Way(other) && other.overlaps1Way(this); } public Vector2D getCenter() { return center; } public float getWidth() { return extents.x * 2; } public float getHeight() { return extents.y * 2; } public void setAngle(float angle) { set(center,getWidth(),getHeight(),angle); } public float getAngle() { return angle; } public void setSize(float w,float h) { set(center,w,h,angle); } public float left() { return boundingRect.left; } public float right() { return boundingRect.right; } public float bottom() { return boundingRect.bottom; } public float top() { return boundingRect.top; } public RectF getBoundingRect() { return boundingRect; } public boolean overlaps(float left, float top, float right, float bottom) { if(right() < left) { return false; } if(bottom() < top) { return false; } if(left() > right) { return false; } if(top() > bottom) { return false; } return true; } };

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