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  • Fixing VBSCRIPT inaccurate mathematical results due to rounding

    - by jay
    Try running this in a .VBS file MsgBox(545.14-544.94) You get a neat little answer of 0.199999999999932! This rounding issue also occurs unfortunately in Sin(2 * pi) since VB can only ever see the (user defined) variable pi as accurate as 3.14159265358979. Is rounding it manually (and loosing accuracy) the only way to improve the result? What is the most effective way of dealing with this kind of problem?

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  • half-sine pulse shaping

    - by kos
    hi, i wanted to know what is the pulse shape of the modem.oqpskmod? and if it is not half-sine pulse shape, how is it possible to make it half-sine pulse shape as it is stated in ieee 802.15.4(zigbee) standard where it shows it as follows p(t)=sin(pi*t/2*Tc) if 0<=t<=2Tc p(t)=0 if otherwise ? thanks a lot!

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  • Equation parsing in Python

    - by MikeCroucher
    How can I (easily) take a string such as 'sin(x)*x^2' which might be entered by a user at runtime and produce a python function that could be evaluated for any value of x? Does anyone know of any libraries or modules that takes care of this sort of thing?

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  • How to find relation between change in latitudes at centre of map and top/bottom

    - by Imran
    Hi, Im having little trouble finding a relation between the movement at centre and edge of a circle, Im doing for panning world map,my map extent is 180,89:-180,-89, my map pans by adding change(dx,dY) to its extents and not its centre. Now a situation has arrrised where I have to move the map to a specific centre, to calculate the change in longitudes is very easy and simple, but its the change in lattitudes that has caused problem. It seems the change in centreY of map is more than the change at edge of the mapY, or simply if I have to move the map centre from 0long,0lat to 73long,33lat, for dX I simply get 73, but for dY apparently it looks 33 but if i add 33 to top of map that is 89 , it will be 122 which is incorrect since Latitudes are between 90 and -90 . It seems a case a projection of a circle on 2D plane where the edge of circle since is moving backward due to angle expereinces less change and the centre expereinces more change, now is there a relation between these two factors? I tried converting the difference between OriginY and destinationY into radians and then add to Top and Bottom of Map, but it did'nt really work for me. Please note that the map is project on a virtual canvas whose width starts from 256 and increases by 256*2^z , z=0 is default and whole world is visible at that extent of canvas code: public void moveMapTo(double destinationLongitude,double destinationLattitude) // moves map to the new centre { double dXLong=destinationLongitude-centreLongitude; double atanhsinO = atanh(Math.sin(destinationLattitude * Math.PI / 180.00)); double atanhsinD = atanh(Math.sin(centreLatitude * Math.PI / 180.00)); double atanhCentre = (atanhsinD + atanhsinO) / 2; double latitudeSpan =destinationLattitude - centreLatitude; double radianOfCentreLatitude = Math.atan(Math.sinh(atanhCentre)); double dXLat=latitudeSpan / Math.cos(radianOfCentreLatitude); dXLat*=getLattitudeSpan()*(Math.PI/180); <--- HERE IS THE PORBLEM System.out.println("dxLong:"+dXLong+"_dxLat:"+dXLat); mapLeft+=dXLong; mapRight+=dXLong; mapTop+=dXLat; mapBottom+=dXLat; } ////latitude span function private double getLattitudeSpan() { double latitudeSpan = mapTop - mapBottom; latitudeSpan = latitudeSpan / Math.cos(radianOfCentreLatitude); return Math.abs(latitudeSpan); } //ht

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  • How to get visible size of DisplayObject with perspective projection

    - by Ain
    The following is entirely a math question. As we know, PerspectiveProjection delivers perspective transformations in 3D represented by the interdependent values of fieldOfView and focalLength according to the following formula: focalLength = stageWidth/2 * (cos(fieldOfView/2) / sin(fieldOfView/2) Bjørn Gunnar Staal has prepared a good image to illustrate the situation. Q: How to get the visible on-screen size of the DisplayObject (Cube on the above-linked image) to which PerspectiveProjection has been applied?

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  • Gaps In Plot Of Piecewise Function in Matlab

    - by eng_sub
    Hello, I want to plot a piecewise function, but I don't want any gaps to appear at the junctures, for example: t=[1:8784]; b=(26.045792 + 13.075558*sin(0.0008531214*t - 2.7773943)).*((heaviside(t-2184))-(heaviside(t-7440))); plot(b,'r','LineWidth', 1.5);grid on there should not be any gaps appearing in the plot between the three intervals , but they do. I want the graph to be continueous without gaps. Any suggestions on how to achieve that. Thanks in advance.

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  • Polar and Cartesian calculations not completely working?

    - by Smoka
    double testx, testy, testdeg, testrad, endx, endy; testx = 1; testy = 1; testdeg = atan2( testx, testy) / Math::PI* 180; testrad = sqrt(pow(testx,2) + pow(testy,2)); endx = testrad * cos(testdeg); endy = testrad * sin(testdeg); All parts of this seem to equate properly, except endx and endy should = testx and testy they do when calculating by hand.

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  • Is it necessary to look, website same in all browser?

    - by metal-gear-solid
    Is it necessary to look, website same in all browser? are some client mad? isn't it need of pixel perfection ( to inch to inch match with Design) a madness? isn't it asking IE6 Pixel perfection, as of now, is a madness? Is it sin to to use JavaScript for visual enhancement, like to enable border radius in IE using Javascript and from CSS in other browsers?

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  • Fixing VB6 inaccurate mathmetical results due to rounding

    - by jay
    Try running this in a .VBS file MsgBox(545.14-544.94) You get a neat little answer of 0.199999999999932! This rounding issue also occurs unfortunately in Sin(2 * pi) since VB can only ever see the (user defined) variable pi as accurate as 3.14159265358979. Is rounding it manually (and loosing accuracy) the only way to improve the result? What is the most effective way of dealing with this kind of problem?

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  • how to use summation in matlab???

    - by lucky
    i have a randomly generated vector say A of length M say A=rand(M,1) and also i have function X(k)=sin(2*pi*k) how would i find Y(k) which is summation of A(l)*X(k-l) as l goes from 0 to M ... assume any value of k... but answer should be summation of all M+1 terms

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  • How to get colliding effect or bouncy when ball hits the track.

    - by Chandan Shetty SP
    I am using below formula to move the ball circular, where accelX and accelY are the values from accelerometer, it is working fine. But the problem in this code is mRadius (I fixed its value to 50), i need to change mRadius according to accelerometer values and also i need bouncing effect when it touches the track. Currently i am developing code by assuming only one ball is on the board. float degrees = -atan2(accelX, accelY) * 180 / 3.14159; int x = cCentrePoint.x + mRadius * cos(degreesToRadians(degrees)); int y = cCentrePoint.y + mRadius * sin(degreesToRadians(degrees)); Here is the snap of the game i want to develop: Updated: I am sending the updated code... mRadius = 5; mRange = NSMakeRange(0,60); -(void) updateBall: (UIAccelerationValue) accelX withY:(UIAccelerationValue)accelY { float degrees = -atan2(accelX, accelY) * 180 / 3.14159; int x = cCentrePoint.x + mRadius * cos(degreesToRadians(degrees)); int y = cCentrePoint.y + mRadius * sin(degreesToRadians(degrees)); //self.targetRect is rect of ball Object self.targetRect = CGRectMake(newX, newY, 8, 9); self.currentRect = self.targetRect; //http://books.google.co.in/books?id=WV9glgdrrrUC&pg=PA455#v=onepage&q=&f=false static NSDate *lastDrawTime; if(lastDrawTime!=nil) { NSTimeInterval secondsSinceLastDraw = -([lastDrawTime timeIntervalSinceNow]); ballXVelocity = ballXVelocity + (accelX * secondsSinceLastDraw) * [self isTouchedTrack:mRadius andRange:mRange]; ballYVelocity = ballYVelocity + -(accelY * secondsSinceLastDraw) * [self isTouchedTrack:mRadius andRange:mRange]; distXTravelled = distXTravelled + secondsSinceLastDraw * ballXVelocity * 50; distYTravelled = distYTravelled + secondsSinceLastDraw * ballYVelocity * 50; CGRect temp = self.targetRect; temp.origin.x += distXTravelled; temp.origin.y += distYTravelled; int radius = (temp.origin.x - cCentrePoint.x) / cos(degreesToRadians(degrees)); if( !NSLocationInRange(abs(radius),mRange)) { //Colided with the tracks...Need a better logic here ballXVelocity = -ballXVelocity; } else { // Need a better logic here self.targetRect = temp; } //NSLog(@"angle = %f",degrees); } [lastDrawTime release]; lastDrawTime = [ [NSDate alloc] init]; } In the above code i have initialized mRadius and mRange(indicate track) to some constant for testing, i am not getting the moving of the ball as i expected( bouncing effect when Collided with track ) with respect to accelerometer. Help me to recognize where i went wrong or send some code snippets or links which does the similar job. I am searching for better logic than my code, if you found share with me.

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  • algorithm to make easy my job

    - by gcc
    Iwill tell part of study material task but, dont afraid, I dont want write all of them , I will ask just specific question.okey; User will give me a function with three unknown. example: sin(a+b)+ln(5)*(log(ab)-32/sqrt(abc)) another example for function atan(23/a)-exp(a,b)*(123+asin(ac)) and there are some another input with funtion but in all input a,b and c, are doesnot determined, Anyway,I wont tell the other part,I just asking how I should take the fuction such that I can do my job with easy?

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  • question about function derivatives

    - by davit-datuashvili
    hi i have question for example i have some function int sumefunction(//parameters here let say int x){ return something let say x*x+2*x+3 or does not matter } i am interesting how find derivative of this function ?if i have int f(int x){ return sin(x); } after derivative it must return cos(x) thanks

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  • ??Database Replay Capture????

    - by Liu Maclean(???)
    Database Replay?11g??????,??workload capture??????????????,???????? ??Workload Capture???????: ???????????????,???????2????,??????,???????????OLTP???????capture 10????1G???? ?????: ????????????????????? ??startup restrict????,?????????? ??capture???restrict?? ????????????? ???????????????: ??scn???????? ???????? ???????? Capture???????????workload????? ???????SYSDBA?SYSOPER????OS?? ????: ?TPCC???capture??????4.5% ????session????64KB??? ???Workload Capture?????????? ????????2?, ??RAC????workload capture  file??????????????,??start_capture????? ????session????64KB???,??????????????workload  capture file????Server Process??????,?????????parse???execution????,Server Process??LOGON?LOGOFF?SQL??????????PGA?,???WCR Capture PG?WCR Capture PGA?,?PGA?????????????????,Server Process???????????WCR???,?????WCR???Server Process??’WCR: capture file IO write’????? ?WCR?????????: SQL> select * from v$version; BANNER -------------------------------------------------------------------------------- Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production PL/SQL Release 11.2.0.3.0 - Production CORE 11.2.0.3.0 Production TNS for Linux: Version 11.2.0.3.0 - Production NLSRTL Version 11.2.0.3.0 - Production SQL> select name from v$event_name where name like '%WCR%'; NAME ---------------------------------------------------------------- WCR: replay client notify WCR: replay clock WCR: replay lock order WCR: replay paused WCR: RAC message context busy WCR: capture file IO write WCR: Sync context busy latch: WCR: sync latch: WCR: processes HT 11g????????WCR???LATCH 1* select name,gets from v$latch where name like '%WCR%' SQL> / NAME GETS ------------------------------ ---------- WCR: kecu cas mem 3 WCR: kecr File Count 37 WCR: MMON Create dir 1 WCR: ticker cache 0 WCR: sync 495 WCR: processes HT 0 WCR: MTS VC queue 0 7 rows selected. ????????????Database Replay Capture????? 1. ????capture dbms_workload_capture.start_capture CREATE OR REPLACE DIRECTORY dbcapture AS '/home/oracle/dbcapture'; execute dbms_workload_capture.start_capture('CAPTURE','DBCAPTURE',default_action=>'INCLUDE'); SQL> select id,name,status,start_time,end_time,connects,user_calls,dir_path from dba_workload_captures where id = (select max(id) from dba_workload_captures) ; ID ---------- NAME -------------------------------------------------------------------------------- STATUS START_TIM END_TIME CONNECTS ---------------------------------------- --------- --------- ---------- USER_CALLS ---------- DIR_PATH -------------------------------------------------------------------------------- 1 CAPTURE IN PROGRESS 08-DEC-12 11 ID ---------- NAME -------------------------------------------------------------------------------- STATUS START_TIM END_TIME CONNECTS ---------------------------------------- --------- --------- ---------- USER_CALLS ---------- DIR_PATH -------------------------------------------------------------------------------- 167 /home/oracle/dbcapture 2. ?? capture file?? [oracle@mlab2 dbcapture]$ ls -lR .: total 8 drwxr-xr-x 2 oracle oinstall 4096 Dec 8 07:24 cap drwxr-xr-x 3 oracle oinstall 4096 Dec 8 07:24 capfiles -rw-r--r-- 1 oracle oinstall 0 Dec 8 07:24 wcr_cap_00001.start ./cap: total 4 -rw-r--r-- 1 oracle oinstall 91 Dec 8 07:24 wcr_scapture.wmd ./capfiles: total 4 drwxr-xr-x 12 oracle oinstall 4096 Dec 8 07:24 inst1 ./capfiles/inst1: total 40 drwxr-xr-x 2 oracle oinstall 4096 Dec 8 08:31 aa drwxr-xr-x 2 oracle oinstall 4096 Dec 8 07:24 ab drwxr-xr-x 2 oracle oinstall 4096 Dec 8 07:24 ac drwxr-xr-x 2 oracle oinstall 4096 Dec 8 07:24 ad drwxr-xr-x 2 oracle oinstall 4096 Dec 8 07:24 ae drwxr-xr-x 2 oracle oinstall 4096 Dec 8 07:24 af drwxr-xr-x 2 oracle oinstall 4096 Dec 8 07:24 ag drwxr-xr-x 2 oracle oinstall 4096 Dec 8 07:24 ah drwxr-xr-x 2 oracle oinstall 4096 Dec 8 07:24 ai drwxr-xr-x 2 oracle oinstall 4096 Dec 8 07:24 aj ./capfiles/inst1/aa: total 316 -rw-r--r-- 1 oracle oinstall 1762 Dec 8 07:25 wcr_c6cdah0000001.rec -rw-r--r-- 1 oracle oinstall 16478 Dec 8 07:28 wcr_c6cf1h0000002.rec -rw-r--r-- 1 oracle oinstall 1772 Dec 8 07:29 wcr_c6cjdh0000004.rec -rw-r--r-- 1 oracle oinstall 1535 Dec 8 07:29 wcr_c6cnah0000005.rec -rw-r--r-- 1 oracle oinstall 1821 Dec 8 07:41 wcr_c6cpfh0000007.rec -rw-r--r-- 1 oracle oinstall 1815 Dec 8 07:33 wcr_c6cq6h000000a.rec -rw-r--r-- 1 oracle oinstall 1535 Dec 8 07:34 wcr_c6cxmh000000h.rec -rw-r--r-- 1 oracle oinstall 1427 Dec 8 07:41 wcr_c6cxvh000000j.rec -rw-r--r-- 1 oracle oinstall 1425 Dec 8 07:41 wcr_c6czph000000k.rec -rw-r--r-- 1 oracle oinstall 2398 Dec 8 07:49 wcr_c6dqfh000000q.rec -rw-r--r-- 1 oracle oinstall 259321 Dec 8 08:35 wcr_c6du7h000000r.rec -rw-r--r-- 1 oracle oinstall 0 Dec 8 07:55 wcr_c6f6yh000000t.rec -rw-r--r-- 1 oracle oinstall 0 Dec 8 08:28 wcr_c6h3qh0000013.rec ./capfiles/inst1/ab: total 0 ./capfiles/inst1/ac: total 0 ./capfiles/inst1/ad: total 0 ./capfiles/inst1/ae: total 0 ./capfiles/inst1/af: total 0 ./capfiles/inst1/ag: total 0 ./capfiles/inst1/ah: total 0 ./capfiles/inst1/ai: total 0 ./capfiles/inst1/aj: total 0 [oracle@mlab2 dbcapture]$ cd ./capfiles/inst1/aa [oracle@mlab2 aa]$ ls -l total 316 -rw-r--r-- 1 oracle oinstall 1762 Dec 8 07:25 wcr_c6cdah0000001.rec -rw-r--r-- 1 oracle oinstall 16478 Dec 8 07:28 wcr_c6cf1h0000002.rec -rw-r--r-- 1 oracle oinstall 1772 Dec 8 07:29 wcr_c6cjdh0000004.rec -rw-r--r-- 1 oracle oinstall 1535 Dec 8 07:29 wcr_c6cnah0000005.rec -rw-r--r-- 1 oracle oinstall 1821 Dec 8 07:41 wcr_c6cpfh0000007.rec -rw-r--r-- 1 oracle oinstall 1815 Dec 8 07:33 wcr_c6cq6h000000a.rec -rw-r--r-- 1 oracle oinstall 1535 Dec 8 07:34 wcr_c6cxmh000000h.rec -rw-r--r-- 1 oracle oinstall 1427 Dec 8 07:41 wcr_c6cxvh000000j.rec -rw-r--r-- 1 oracle oinstall 1425 Dec 8 07:41 wcr_c6czph000000k.rec -rw-r--r-- 1 oracle oinstall 2398 Dec 8 07:49 wcr_c6dqfh000000q.rec -rw-r--r-- 1 oracle oinstall 259321 Dec 8 08:35 wcr_c6du7h000000r.rec -rw-r--r-- 1 oracle oinstall 0 Dec 8 07:55 wcr_c6f6yh000000t.rec -rw-r--r-- 1 oracle oinstall 0 Dec 8 08:28 wcr_c6h3qh0000013.rec [oracle@mlab2 aa]$ ls -l |wc -l 14 ???????14??? 3. ??LOGON????Server Process [oracle@mlab2 ~]$ sqlplus / as sysdba SQL*Plus: Release 11.2.0.3.0 Production on Sat Dec 8 08:37:40 2012 Copyright (c) 1982, 2011, Oracle. All rights reserved. Connected to: Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production With the Partitioning, Automatic Storage Management, OLAP, Data Mining and Real Application Testing options ?????wcr?? [oracle@mlab2 aa]$ ls -ltr total 316 -rw-r--r-- 1 oracle oinstall 1762 Dec 8 07:25 wcr_c6cdah0000001.rec -rw-r--r-- 1 oracle oinstall 16478 Dec 8 07:28 wcr_c6cf1h0000002.rec -rw-r--r-- 1 oracle oinstall 1772 Dec 8 07:29 wcr_c6cjdh0000004.rec -rw-r--r-- 1 oracle oinstall 1535 Dec 8 07:29 wcr_c6cnah0000005.rec -rw-r--r-- 1 oracle oinstall 1815 Dec 8 07:33 wcr_c6cq6h000000a.rec -rw-r--r-- 1 oracle oinstall 1535 Dec 8 07:34 wcr_c6cxmh000000h.rec -rw-r--r-- 1 oracle oinstall 1425 Dec 8 07:41 wcr_c6czph000000k.rec -rw-r--r-- 1 oracle oinstall 1427 Dec 8 07:41 wcr_c6cxvh000000j.rec -rw-r--r-- 1 oracle oinstall 1821 Dec 8 07:41 wcr_c6cpfh0000007.rec -rw-r--r-- 1 oracle oinstall 2398 Dec 8 07:49 wcr_c6dqfh000000q.rec -rw-r--r-- 1 oracle oinstall 0 Dec 8 07:55 wcr_c6f6yh000000t.rec -rw-r--r-- 1 oracle oinstall 0 Dec 8 08:28 wcr_c6h3qh0000013.rec -rw-r--r-- 1 oracle oinstall 259321 Dec 8 08:35 wcr_c6du7h000000r.rec -rw-r--r-- 1 oracle oinstall 0 Dec 8 08:37 wcr_c6hp4h0000018.rec ??????wcr_c6hp4h0000018.rec ??? SQL> select spid from v$process where addr = ( select paddr from v$session where sid=(select distinct sid from v$mystat)); SPID ------------------------ 14293 ????????????????14293, ???????????????,??????wcr_c6hp4h0000018.rec [oracle@mlab2 ~]$ ls -l /proc/14293/fd total 0 lr-x------ 1 oracle oinstall 64 Dec 8 08:39 0 -> /dev/null l-wx------ 1 oracle oinstall 64 Dec 8 08:39 1 -> /dev/null lrwx------ 1 oracle oinstall 64 Dec 8 08:39 10 -> /u01/app/oracle/product/11201/db_1/rdbms/audit/CRMV_ora_14293_1.aud l-wx------ 1 oracle oinstall 64 Dec 8 08:39 11 -> /u01/app/oracle/diag/rdbms/crmv/CRMV/trace/CRMV_ora_14293.trc l-wx------ 1 oracle oinstall 64 Dec 8 08:39 12 -> pipe:[34585895] l-wx------ 1 oracle oinstall 64 Dec 8 08:39 13 -> /u01/app/oracle/diag/rdbms/crmv/CRMV/trace/CRMV_ora_14293.trm l-wx------ 1 oracle oinstall 64 Dec 8 08:39 2 -> /dev/null lr-x------ 1 oracle oinstall 64 Dec 8 08:39 3 -> /dev/null lr-x------ 1 oracle oinstall 64 Dec 8 08:39 4 -> /dev/null lr-x------ 1 oracle oinstall 64 Dec 8 08:39 5 -> /u01/app/oracle/product/11201/db_1/rdbms/mesg/oraus.msb lr-x------ 1 oracle oinstall 64 Dec 8 08:39 6 -> /proc/14293/fd lr-x------ 1 oracle oinstall 64 Dec 8 08:39 7 -> /dev/zero lrwx------ 1 oracle oinstall 64 Dec 8 08:39 8 -> /home/oracle/dbcapture/capfiles/inst1/aa/wcr_c6hp4h0000018.rec lr-x------ 1 oracle oinstall 64 Dec 8 08:39 9 -> pipe:[34585894] ?????lsof?? [root@mlab2 ~]# lsof|grep wcr_c6hp4h0000018.rec oracle 14293 oracle 8u REG 8,1 0 17629644 /home/oracle/dbcapture/capfiles/inst1/aa/wcr_c6hp4h0000018.rec ????????,??Server Process????WCR REC??,?Server Process LOGON?????? 3.????SQL??: SQL> select 1 from dual; 1 ---------- 1 SQL> / 1 ---------- 1 [oracle@mlab2 aa]$ strings wcr_c6hp4h0000018.rec ==»????SQL????, ??????? ??????SQL???,???????????????WCR??????,LOGON???????????SQL????,????????? [oracle@mlab2 aa]$ strings wcr_c6hp4h0000018.rec 11.2.0.3.0 *File header info. (Shadow process='14293') D0576B5D710A34F4E043B201A8C0ECFE SYS; NLS_LANGUAGE? AMERICAN> NLS_TERRITORY? AMERICA> NLS_CURRENCY? NLS_ISO_CURRENCY? AMERICA> NLS_NUMERIC_CHARACTERS? NLS_CALENDAR? GREGORIAN> NLS_DATE_FORMAT? DD-MON-RR> NLS_DATE_LANGUAGE? AMERICAN> NLS_CHARACTERSET? AL32UTF8> NLS_SORT? BINARY> NLS_TIME_FORMAT? HH.MI.SSXFF AM> NLS_TIMESTAMP_FORMAT? DD-MON-RR HH.MI.SSXFF AM> NLS_TIME_TZ_FORMAT? HH.MI.SSXFF AM TZR> NLS_TIMESTAMP_TZ_FORMAT? DD-MON-RR HH.MI.SSXFF AM TZR> NLS_DUAL_CURRENCY? NLS_SPECIAL_CHARS? NLS_NCHAR_CHARACTERSET? UTF8> NLS_COMP? BINARY> NLS_LENGTH_SEMANTICS? BYTE> NLS_NCHAR_CONV_EXCP? FALSE (DESCRIPTION=(ADDRESS=(PROTOCOL=beq)(PROGRAM=/u01/app/oracle/product/11201/db_1/bin/oracle)(ARGV0=oracleCRMV)(ARGS='(DESCRIPTION=(LOCAL=YES)(ADDRESS=(PROTOCOL=beq)))')(DETACH=NO))(CONNECT_DATA=(CID=(PROGRAM=sqlplus)(HOST=mlab2.oracle.com)(USER=oracle)))) ,[email protected] (TNS V1-V3)U tselect spid from v$process where addr = ( select paddr from v$session where sid=(select distinct sid from v$mystat)) ` _ select 1 from dual select 1 from dual ??????????????????? [oracle@mlab2 aa]$ strings wcr_c6hp4h0000018.rec 9`9_^B create table vva(t1 int) `:_i :`:_iB `;_^ ;`;_^B create table vva(t1 int) `_i >`>_iB FusC `?_^ ?`?_^B FvWC _begin for i in 1..50000 loop execute immediate 'select 1 from dual where 2='||i; end loop; end; ?SERVER PROCESS LOGOFF ??????? C`E_ B k^2C ????Server Process????parse?execution???WCR??,??????????PGA?,????????????,????????,?????WCR???????????,???????? 4. ?????? SQL> oradebug setmypid Statement processed. SQL> oradebug dump processstate 10; Statement processed. SQL> oradebug tracefile_name /u01/app/oracle/diag/rdbms/crmv/CRMV/trace/CRMV_ora_14293.trc ?processstate ??????????????? WCR: capture file IO write,??Server process??WCR ?? 3: waited for 'SQL*Net message to client' driver id=0x62657100, #bytes=0x1, =0x0 wait_id=139 seq_num=140 snap_id=1 wait times: snap=0.000007 sec, exc=0.000007 sec, total=0.000007 sec wait times: max=infinite wait counts: calls=0 os=0 occurred after 0.934091 sec of elapsed time 4: waited for 'latch: shared pool' address=0x60106b20, number=0x133, tries=0x0 wait_id=138 seq_num=139 snap_id=1 wait times: snap=0.000066 sec, exc=0.000066 sec, total=0.000066 sec wait times: max=infinite wait counts: calls=0 os=0 occurred after 1.180690 sec of elapsed time 5: waited for 'WCR: capture file IO write' =0x0, =0x0, =0x0 wait_id=137 seq_num=138 snap_id=1 wait times: snap=0.000189 sec, exc=0.000189 sec, total=0.000189 sec wait times: max=infinite wait counts: calls=0 os=0 occurred after 3.122783 sec of elapsed time 6: waited for 'WCR: capture file IO write' =0x0, =0x0, =0x0 wait_id=136 seq_num=137 snap_id=1 wait times: snap=0.000191 sec, exc=0.000191 sec, total=0.000191 sec wait times: max=infinite wait counts: calls=0 os=0 occurred after 3.053132 sec of elapsed time 7: waited for 'WCR: capture file IO write' 5.??PGA???? SQL> oradebug dump heapdump 536870917; Statement processed. grep WCR /u01/app/oracle/diag/rdbms/crmv/CRMV/trace/CRMV_ora_14293.trc Chunk 7fb1b606bfc0 sz= 65600 freeable "WCR Capture PG " ds=0x7fb1b6115f90 Chunk 7fb1b6111e18 sz= 4224 freeable "WCR Capture PG " ds=0x7fb1b6115f90 Chunk 7fb1b6112e98 sz= 4184 freeable "WCR Capture PG " ds=0x7fb1b6115f90 Chunk 7fb1b6113ef0 sz= 4224 freeable "WCR Capture PG " ds=0x7fb1b6115f90 Chunk 7fb1b6114f70 sz= 4104 recreate "WCR Capture PG " latch=(nil) Chunk 7fb1b6115f78 sz= 160 freeable "WCR Capture PGA" Chunk 7fb1b6116018 sz= 3248 freeable "WCR Capture PGA" Subheap ds=0x7fb1b6115f90 heap name= WCR Capture PG size= 82336 HEAP DUMP heap name="WCR Capture PG" desc=0x7fb1b6115f90 FIVE LARGEST SUB HEAPS for heap name="WCR Capture PG" desc=0x7fb1b6115f9 PGA???WCR Capture PG ?WCR Capture PGA?freeable or recreate??chunk,???????Server Process???OS Chunk 7fb1b606bfc0 sz= 65600 freeable "WCR Capture PG " ds=0x7fb1b6115f90 sz= 65600=» 64k ??????????64k??,???????????????64k WCR????????????:)! 6.???? ??WCR CAPTURE????????2? SQL> SELECT x.ksppinm NAME, y.ksppstvl VALUE, x.ksppdesc describ 2 FROM SYS.x$ksppi x, SYS.x$ksppcv y 3 WHERE x.inst_id = USERENV ('Instance') 4 AND y.inst_id = USERENV ('Instance') 5 AND x.indx = y.indx 6 AND x.ksppinm in ('_capture_buffer_size','_wcr_control'); NAME VALUE DESCRIB -------------------- -------------------- ------------------------------------------------------------ _wcr_control 0 Oracle internal test WCR parameter used ONLY for testing! _capture_buffer_size 65536 To set the size of the PGA I/O recording buffers ??_capture_buffer_size ??PGA?WCR BUFFER?SIZE,???64k _wcr_control ??WCR?????,?????? ????,??????: 1. ???WCR WORKLOAD CAPTURE???????????,??Server Process????(????)2. ???server process????WCR??3. Server Proess???LOGON?LOGOFF?SQL?????????WCR???4. Server Process????????Immediate mode,????????PGA?(WCR Capture) subheap?,??????????????(timeout?????)5. ????, Server Process????????Immediate mode,?capture????parse??execution??(?????capture???parse?????????????,parse????capture???),?????LOGON?SQL??(???????)??PGA?WCR Capture?????,???????,????????,??tpcc??????4.5%6. ????_capture_buffer_size ??PGA?WCR BUFFER?SIZE,???64k7. WCR Capture?????binrary 2????,?????,????????????????WCR capture file8. WCR: capture file IO write?????Server Process??WCR??

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  • "Expected initializer before '<' token" in header file

    - by Sarah
    I'm pretty new to programming and am generally confused by header files and includes. I would like help with an immediate compile problem and would appreciate general suggestions about cleaner, safer, slicker ways to write my code. I'm currently repackaging a lot of code that used to be in main() into a Simulation class. I'm getting a compile error with the header file for this class. I'm compiling with gcc version 4.2.1. // Simulation.h #ifndef SIMULATION_H #define SIMULATION_H #include <cstdlib> #include <iostream> #include <cmath> #include <string> #include <fstream> #include <set> #include <boost/multi_index_container.hpp> #include <boost/multi_index/hashed_index.hpp> #include <boost/multi_index/member.hpp> #include <boost/multi_index/ordered_index.hpp> #include <boost/multi_index/mem_fun.hpp> #include <boost/multi_index/composite_key.hpp> #include <boost/shared_ptr.hpp> #include <boost/tuple/tuple_comparison.hpp> #include <boost/tuple/tuple_io.hpp> #include "Parameters.h" #include "Host.h" #include "rng.h" #include "Event.h" #include "Rdraws.h" typedef multi_index_container< // line 33 - first error boost::shared_ptr< Host >, indexed_by< hashed_unique< const_mem_fun<Host,int,&Host::getID> >, // 0 - ID index ordered_non_unique< tag<age>,const_mem_fun<Host,int,&Host::getAgeInY> >, // 1 - Age index hashed_non_unique< tag<household>,const_mem_fun<Host,int,&Host::getHousehold> >, // 2 - Household index ordered_non_unique< // 3 - Eligible by age & household tag<aeh>, composite_key< Host, const_mem_fun<Host,int,&Host::getAgeInY>, const_mem_fun<Host,bool,&Host::isEligible>, const_mem_fun<Host,int,&Host::getHousehold> > >, ordered_non_unique< // 4 - Eligible by household (all single adults) tag<eh>, composite_key< Host, const_mem_fun<Host,bool,&Host::isEligible>, const_mem_fun<Host,int,&Host::getHousehold> > >, ordered_non_unique< // 5 - Household & age tag<ah>, composite_key< Host, const_mem_fun<Host,int,&Host::getHousehold>, const_mem_fun<Host,int,&Host::getAgeInY> > > > // end indexed_by > HostContainer; typedef std::set<int> HHSet; class Simulation { public: Simulation( int sid ); ~Simulation(); // MEMBER FUNCTION PROTOTYPES void runDemSim( void ); void runEpidSim( void ); void ageHost( int id ); int calcPartnerAge( int a ); void executeEvent( Event & te ); void killHost( int id ); void pairHost( int id ); void partner2Hosts( int id1, int id2 ); void fledgeHost( int id ); void birthHost( int id ); void calcSI( void ); double beta_ij_h( int ai, int aj, int s ); double beta_ij_nh( int ai, int aj, int s ); private: // SIMULATION OBJECTS double t; double outputStrobe; int idCtr; int hholdCtr; int simID; RNG rgen; HostContainer allHosts; // shared_ptr to Hosts - line 102 - second error HHSet allHouseholds; int numInfecteds[ INIT_NUM_AGE_CATS ][ INIT_NUM_STYPES ]; EventPQ currentEvents; // STREAM MANAGEMENT void writeOutput(); void initOutput(); void closeOutput(); std::ofstream ageDistStream; std::ofstream ageDistTStream; std::ofstream hhDistStream; std::ofstream hhDistTStream; std::string ageDistFile; std::string ageDistTFile; std::string hhDistFile; std::string hhDistTFile; }; #endif I'm hoping the other files aren't so relevant to this problem. When I compile with g++ -g -o -c a.out -I /Applications/boost_1_42_0/ Host.cpp Simulation.cpp rng.cpp main.cpp Rdraws.cpp I get Simulation.h:33: error: expected initializer before '<' token Simulation.h:102: error: 'HostContainer' does not name a type and then a bunch of other errors related to not recognizing the HostContainer. It seems like I have all the right Boost #includes for the HostContainer to be understood. What else could be going wrong? I would appreciate immediate suggestions, troubleshooting tips, and other advice about my code. My plan is to create a "HostContainer.h" file that includes the typedef and structs that define its tags, similar to what I'm doing in "Event.h" for the EventPQ container. I'm assuming this is legal and good form.

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  • How to access private static target field in aspect in AspectJ?

    - by LihO
    I have a simple class Main with private static int x and an aspect that should output the old value of x before it is reassigned: public class Main { private static int x; public static void main(String[] args) { foo(7); } public static void foo(int y) { x = y; } } and MonitorX.aj: public aspect MonitorX { before() : set(static int Main.x){ System.out.println(Main.x); } } which doesn't work since I can't access private x using Main.x. I've also tried: before(int t) : set(static int Main.x) && target(t){ System.out.println(t); } which doesn't work either (nothing is outputted, if I try to output string, it seems that the aspect isn't invoked at all). However printing out the new value that is being assigned works: before(int newVal) : set(static int Main.x) && args(newVal){ System.out.println(newVal); } What am I missing?

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  • List of fundamental data structures - what am I missing?

    - by jboxer
    I've been studying my fundamental data structures a bunch recently, trying to make sure I've got them down cold. By "fundamental", I mean the real basic ones. Fancy ones like Red-Black Trees and Bloom Filters are clearly worth knowing, but they're usually either enhancements of fundamental ones (Red-Black Trees are binary search trees with special properties to keep them balanced) or they're only useful in very specific situations (Bloom Filters). So far, I'm "fluent" in the following data structures: Arrays Linked Lists Stacks/Queues Binary Search Trees Heaps/Priority Queues Hash Tables However, I feel like I'm missing something. Are there any fundamental ones that I'm forgetting about? EDIT: Added these after posting the question Strings (suggested by catchmeifyoutry) Sets (suggested by Peter) Graphs (suggested by Nick D and aJ) B-Trees (Suggested by tloach) I'm a little on-the-fence about whether these are too fancy or not, but I think they're different enough from the fundamental structures (and important enough) to be worth studying as fundamental.

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  • Introducción a ENUM (E.164 Number Mapping)

    - by raul.goycoolea
    E.164 Number Mapping (ENUM o Enum) se diseñó para resolver la cuestión de como se pueden encontrar servicios de internet mediante un número telefónico, es decir cómo se pueden usar los los teléfonos, que solamente tienen 12 teclas, para acceder a servicios de Internet. La parte más básica de ENUM es por tanto la convergencia de las redes del STDP y la IP; ENUM hace que pueda haber una correspondencia entre un número telefónico y un identificador de Internet. En síntesis, Enum es un conjunto de protocolos para convertir números E.164 en URIs, y viceversa, de modo que el sistema de numeración E.164 tenga una función de correspondencia con las direcciones URI en Internet. Esta función es necesaria porque un número telefónico no tiene sentido en el mundo IP, ni una dirección IP tiene sentido en las redes telefónicas. Así, mediante esta técnica, las comunicaciones cuyo destino se marque con un número E.164, puedan terminar en el identificador correcto (número E.164 si termina en el STDP, o URI si termina en redes IP). La solución técnica de mirar en una base de datos cual es el identificador de destino tiene consecuencias muy interesantes, como que la llamada se pueda terminar donde desee el abonado llamado. Esta es una de las características que ofrece ENUM : el destino concreto, el terminal o terminales de terminación, no lo decide quien inicia la llamada o envía el mensaje sino la persona que es llamada o recibe el mensaje, que ha escrito sus preferencias en una base de datos. En otras palabras, el destinatario de la llamada decide cómo quiere ser contactado, tanto si lo que se le comunica es un email, o un sms, o telefax, o una llamada de voz. Cuando alguien quiera llamarle a usted, lo que tiene que hacer el llamante es seleccionar su nombre (el del llamado) en la libreta de direcciones del terminal o marcar su número ENUM. Una aplicación informática obtendrá de una base de datos los datos de contacto y disponibilidad que usted decidió. Y el mensaje le será remitido tal como usted especificó en dicha base de datos. Esto es algo nuevo que permite que usted, como persona llamada, defina sus preferencias de terminación para cualquier tipo de contenido. Por ejemplo, usted puede querer que todos los emails le sean enviados como sms o que los mensajes de voz se le remitan como emails; las comunicaciones ya no dependen de donde esté usted o deque tipo de terminal utiliza (teléfono, pda, internet). Además, con ENUM usted puede gestionar la portabilidad de sus números fijos y móviles. ENUM emplea una técnica de búsqueda indirecta en una base de datos que tiene los registros NAPTR ("Naming Authority Pointer Resource Records" tal como lo define el RFC 2915), y que utiliza el número telefónico Enum como clave de búsqueda, para obtener qué URIs corresponden a cada número telefónico. La base de datos que almacena estos registros es del tipo DNS.Si bien en uno de sus diversos usos sirve para facilitar las llamadas de usuarios de VoIP entre redes tradicionales del STDP y redes IP, debe tenerse en cuenta que ENUM no es una función de VoIP sino que es un mecanismo de conversión entre números/identificadores. Por tanto no debe ser confundido con el uso normal de enrutar las llamadas de VoIP mediante los protocolos SIP y H.323. ENUM puede ser muy útil para aquellas organizaciones que quieran tener normalizada la manera en que las aplicaciones acceden a los datos de comunicación de cada usuario. FundamentosPara que la convergencia entre el Sistema Telefónico Disponible al Público (STDP) y la Telefonía por Internet o Voz sobre IP (VoIP) y que el desarrollo de nuevos servicios multimedia tengan menos obstáculos, es fundamental que los usuarios puedan realizar sus llamadas tal como están acostumbrados a hacerlo, marcando números. Para eso, es preciso que haya un sistema universal de correspondencia de número a direcciones IP (y viceversa) y que las diferentes redes se puedan interconectar. Hay varias fórmulas que permiten que un número telefónico sirva para establecer comunicación con múltiples servicios. Una de estas fórmulas es el Electronic Number Mapping System ENUM, normalizado por el grupo de tareas especiales de ingeniería en Internet (IETF, Internet engineering task force), del que trata este artículo, que emplea la numeración E.164, los protocolos y la infraestructura telefónica para acceder indirectamente a diferentes servicios. Por tanto, se accede a un servicio mediante un identificador numérico universal: un número telefónico tradicional. ENUM permite comunicar las direcciones del mundo IP con las del mundo telefónico, y viceversa, sin problemas. Antes de entrar en mayores profundidades, conviene dar una breve pincelada para aclarar cómo se organiza la correspondencia entre números o URI. Para ello imaginemos una llamada que se inicia desde el servicio telefónico tradicional con destino a un número Enum. En ENUM Público, el abonado o usuario Enum a quien va destinada lallamada, habrá decidido incluir en la base de datos Enum uno o varios URI o números E.164, que forman una lista con sus preferencias para terminar la llamada. Y el sistema como se explica más adelante, elegirá cual es el número o URI adecuado para dicha terminación. Por tanto como resultado de la consulta a la base dedatos Enum siempre se da una relación unívoca entre el número Enum marcado y el de terminación, conforme a los deseos de la persona llamada.Variedades de ENUMUna posible fuente de confusión cuando se trata sobre ENUM es la variedad de soluciones o sistemas que emplean este calificativo. Lo habitual es que cuando se haga una referencia a ENUM se trate de uno de los siguientes casos: ENUM Público: Es la visión original de ENUM, como base de datos pública, parecida a un directorio, donde el abonado "opta" a ser incluido en la base de datos, que está gestionada en el dominio e164.arpa, delegando a cada país la gestión de la base de datos y la numeración. También se conoce como ENUM de usuario. Carrier ENUM, o ENUM Infraestructura, o de Operador: Cuando grupos de operadores proveedores de servicios de comunicaciones electrónicas acuerdan compartir la información de los abonados por medio de ENUM mediante acuerdos privados. En este caso son los operadores quienes controlan la información del abonado en vez de hacerlo (optar) los propios abonados. Carrier ENUM o ENUM de Operador también se conoce como Infrastructure ENUM o ENUM Infraestructura, y está siendo normalizado por IETF para la interconexión de VoIP (mediante acuerdos de peering). Como se explicará en la correspondiente sección, también se puede utilizar para la portabilidad o conservación de número. ENUM Privado: Un operador de telefonía o de VoIP, o un ISP, o un gran usuario, puede utilizar las técnicas de ENUM en sus redes y en las de sus clientes sin emplear DNS públicos, con DNS privados o internos. Resulta fácil imaginar como puede utilizarse esta técnica para que compañías multinacionales, o bancos, o agencias de viajes, tengan planes de numeración muy coherentes y eficaces. Cómo funciona ENUMPara conocer cómo funciona Enum, le remitimos a la página correspondiente a ENUM Público, puesto que esa variedad de Enum es la típica, la que dió lugar a todos los procedimientos y normas de IETF .Más detalles sobre: @page { margin: 0.79in } P { margin-bottom: 0.08in } H4 { margin-bottom: 0.08in } H4.ctl { font-family: "Lohit Hindi" } A:link { so-language: zxx } -- ENUM Público. En esta página se explica con cierto detalle como funciona Enum Carrier ENUM o ENUM de Operador ENUM Privado Normas técnicas: RFC 2915: NAPTR RR. The Naming Authority Pointer (NAPTR) DNS Resource Record RFC 3761: ENUM Protocol. The E.164 to Uniform Resource Identifiers (URI) Dynamic Delegation Discovery System (DDDS) Application (ENUM). (obsoletes RFC 2916). RFC 3762: Usage of H323 addresses in ENUM Protocol RFC 3764: Usage of SIP addresses in ENUM Protocol RFC 3824: Using E.164 numbers with SIP RFC 4769: IANA Registration for an Enumservice Containing Public Switched Telephone Network (PSTN) Signaling Information RFC 3026: Berlin Liaison Statement RFC 3953: Telephone Number Mapping (ENUM) Service Registration for Presence Services RFC 2870: Root Name Server Operational Requirements RFC 3482: Number Portability in the Global Switched Telephone Network (GSTN): An Overview RFC 2168: Resolution of Uniform Resource Identifiers using the Domain Name System Organizaciones relacionadas con ENUM RIPE - Adimistrador del nivel 0 de ENUM e164.arpa. ITU-T TSB - Unión Internacional de Telecomunicaciones ETSI - European Telecommunications Standards Institute VisionNG - Administrador del rango ENUM 878-10 IETF ENUM Chapter

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