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  • How can I determine/use $(this) in js callback script

    - by Rabbott
    I am using Rails and jQuery, making an ajax call initiated by clicking a link. I setup my application.js file to look like the one proposed here and it works great. The problem I'm having is how can I use $(this) in my say.. update.js.erb file to represent the link I clicked? I don't want to have to assign an ID to every one, then recompile that id in the callback script.. EDIT To give a simple example of something similar to what I'm trying to do (and much easier to explain): If a user clicks on a link, that deletes that element from a list, the controller would handle the callback, and the callback (which is in question here) would delete the element I clicked on, so in the callback delete.js.erb would just say $(this).fadeOut(); This is why I want to use $(this) so that I dont have to assign an ID to every element (which would be the end of the world, just more verbose markup) application.js jQuery.ajaxSetup({ 'beforeSend': function(xhr) {xhr.setRequestHeader("Accept", "text/javascript,application/javascript,text/html")} }) function _ajax_request(url, data, callback, type, method) { if (jQuery.isFunction(data)) { callback = data; data = {}; } return jQuery.ajax({ type: method, url: url, data: data, success: callback, dataType: type }); } jQuery.extend({ put: function(url, data, callback, type) { return _ajax_request(url, data, callback, type, 'PUT'); }, delete_: function(url, data, callback, type) { return _ajax_request(url, data, callback, type, 'DELETE'); } }); jQuery.fn.submitWithAjax = function() { this.unbind('submit', false); this.submit(function() { $.post(this.action, $(this).serialize(), null, "script"); return false; }) return this; }; // Send data via get if <acronym title="JavaScript">JS</acronym> enabled jQuery.fn.getWithAjax = function() { this.unbind('click', false); this.click(function() { $.get($(this).attr("href"), $(this).serialize(), null, "script"); return false; }) return this; }; // Send data via Post if <acronym title="JavaScript">JS</acronym> enabled jQuery.fn.postWithAjax = function() { this.unbind('click', false); this.click(function() { $.post($(this).attr("href"), $(this).serialize(), null, "script"); return false; }) return this; }; jQuery.fn.putWithAjax = function() { this.unbind('click', false); this.click(function() { $.put($(this).attr("href"), $(this).serialize(), null, "script"); return false; }) return this; }; jQuery.fn.deleteWithAjax = function() { this.removeAttr('onclick'); this.unbind('click', false); this.click(function() { $.delete_($(this).attr("href"), $(this).serialize(), null, "script"); return false; }) return this; }; // This will "ajaxify" the links function ajaxLinks(){ $('.ajaxForm').submitWithAjax(); $('a.get').getWithAjax(); $('a.post').postWithAjax(); $('a.put').putWithAjax(); $('a.delete').deleteWithAjax(); } show.html.erb <%= link_to 'Link Title', article_path(a, :sentiment => Article::Sentiment['Neutral']), :class => 'put' %> The combination of the two things will call update.js.erb in rails, the code in that file is used as the callback of the ajax ($.put in this case) update.js.erb // user feedback $("#notice").html('<%= flash[:notice] %>'); // update the background color $(this OR e.target).attr("color", "red");

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  • Adjust parameters of serial port reading

    - by clinisbut
    Hello. I'm facing a particular issue that regards serial communication under win32. I'm communicating with a device can only accept frames when it is not already communicating. So I must find a valid frame and then inmediatelly send my request. I developed a class named Serial that handles basic operations on serial port (open, close, read, write) and then a Thread calls inside a loop read and write functions. Thread loop //Device is an object of class Serial while( device->isOpen() && !terminate ) { unsigned int readed = 0; unsigned long error = ERROR_SUCCESS; unsigned char* data = device->read( &readed, &error ); if( error==ERROR_SUCCESS ) { //If data received, deliver to upper level if( readed>0 ) { QByteArray output( (const char*)data, (signed int)readed ); emit dataArrived( output, readed ); } } else { //unrelated stuff } //Here I manage the writting issue //Only when nothing is received, and Upper layer wants to send a frame //(Upper layer only will mark as something to send when it detects a valid frame) if( readed==0 ) { out_lock.lock(); //If something to send... if( something_to_send > 0 ) { if( device->write( output_buffer, output_size, &error ) ) { //things... } } } } The Thread basically keeps reading, and when nothing is received, sees if somebody has signaled to send a frame (this means that a valid frame is just received). When this happens, it writes the frame through serial port. Here comes my problem. Inside the Serial::read() function: I use the overlapped way of reading: ::ClearCommError( handle, &dwErrors, &stat); if( stat.cbInQue ) { //If there's something to read, read it, please note the bytes to read parameter, here 1. bool ok = ::ReadFile( handle, buffer_in, 1, &bytes_read, &ov_reader ); if( !ok ) { DWORD _error = ::GetLastError(); if( _error == ERROR_IO_PENDING ) { DWORD result = ::WaitForMultipleObjects( 2, waiters, FALSE,INFINITE ); switch( result ) { //Eventshutdown case WAIT_OBJECT_0: /*code omitted*/break; case WAIT_OBJECT_0+1: ok = ::GetOverlappedResult( handle, &ov_reader, &bytes_read, true ); //check ok value omitted break; } } } } if( bytes_read>0 ) { *size = bytes_read; } Here starts my problem. When device sends me small frames (around 30 bytes) everything works fine, but when larger frames are sent, the code is not able to find any free time between frames causing the thread to never be able send any frame because readed is never 0. If I increase the number of bytes to read inside the read() function, lose the ability to detect when the device "listens": bool ok = ::ReadFile(handle, buffer_in, 50, &bytes_read, &ov_reader ); This happens because my app can receive the end of a frame together with the start of the next one. This behaviour is very common. In the other hand, if I change the INFINITE argument by a valid timeout in the WaitForMultipleObjects function, I lose data. So my question basically is... what I'm doing wrong? Why when reading 1 byte each time I don't find any free time to send my own frames? Thank you

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  • Linux/Apache performance very slow even on local network

    - by klausch
    I have an Ubuntu server machine running Apache and MYSQL. System and version info is as follows: Linux kernel 3.0.0.-12 Apache/2.2.20 MySQL Ver 14.14.Distrib 5.1.58 I am running a few websites on this server, some HTML only, some PHP/MySQL. THe [problem is that response time is very slow, both on static as well as the dynamic sites. Sometimes it takes more than 10 seconds before a response is given, this makes the sites very slow and almost unusable. The problem occurs even when requesting from the local network. I have added the involved subdomains to my /etc/hosts file, and abolve all the problem is not solved by using IP numbers instead of URL's. So there is no DNS lookup issue. I have modified the log format by showing the response times and sometimes a files takes 12 seconds to be served, see the jquery~.js file in the example screenshot. I have no explanation for this extremely long response time, but is is not even the only issue here, some other files takes a long time to be served too, but do not show a long response time in the log file. So probably different tissues are involved here. I cannot find a solution until now, any suggestions??? THanx in advance, Klaas link to screenshot picture from access logfile Some extra configuration info: apache2.conf (comment is removed) LockFile ${APACHE_LOCK_DIR}/accept.lock PidFile ${APACHE_PID_FILE} Timeout 300 KeepAlive On MaxKeepAliveRequests 100 KeepAliveTimeout 5 <IfModule mpm_prefork_module> StartServers 5 MinSpareServers 5 MaxSpareServers 10 MaxClients 150 MaxRequestsPerChild 0 </IfModule> <IfModule mpm_worker_module> StartServers 2 MinSpareThreads 25 MaxSpareThreads 75 ThreadLimit 64 ThreadsPerChild 25 MaxClients 150 MaxRequestsPerChild 0 </IfModule> <IfModule mpm_event_module> StartServers 2 MinSpareThreads 25 MaxSpareThreads 75 ThreadLimit 64 ThreadsPerChild 25 MaxClients 150 MaxRequestsPerChild 0 </IfModule> User ${APACHE_RUN_USER} Group ${APACHE_RUN_GROUP} AccessFileName .htaccess <Files ~ "^\.ht"> Order allow,deny Deny from all Satisfy all </Files> DefaultType text/plain HostnameLookups Off ErrorLog ${APACHE_LOG_DIR}/error.log LogLevel warn Include mods-enabled/*.load Include mods-enabled/*.conf Include httpd.conf Include ports.conf LogFormat "%v:%p %h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\"" vhost_combined LogFormat "%h %l %u %t \"%r\" %>s %O \"%{Referer}i\" \"%{User-Agent}i\" %T/%D" combined LogFormat "%h %l %u %t \"%r\" %>s %O" common LogFormat "%{Referer}i -> %U" referer LogFormat "%{User-agent}i" agent Include conf.d/ Include sites-enabled/ And the virtual hostfile for one of the slow sites, in fact it is pretty straightforward... <VirtualHost *:80> ServerAdmin [email protected] ServerSignature EMail ServerName toenjoy.drsklaus.nl DocumentRoot /var/www/toenjoy.drsklaus.nl <Directory /> Options FollowSymLinks AllowOverride None </Directory> <Directory /var/www/toenjoy.drsklaus.nl/> Options Indexes FollowSymLinks MultiViews AllowOverride AuthConfig AuthType Basic AuthName "To Enjoy" AuthUserFile /etc/.htpasswd Require user petraaa Order allow,deny allow from all </Directory> ScriptAlias /cgi-bin/ /usr/lib/cgi-bin/ <Directory "/usr/lib/cgi-bin"> AllowOverride None Options +ExecCGI -MultiViews +SymLinksIfOwnerMatch Order allow,deny Allow from all </Directory> ErrorLog /var/log/apache2/error.log # Possible values include: debug, info, notice, warn, error, crit, # alert, emerg. LogLevel warn CustomLog /var/log/apache2/access.log combined Alias /doc/ "/usr/share/doc/" <Directory "/usr/share/doc/"> Options Indexes MultiViews FollowSymLinks AllowOverride None Order deny,allow Deny from all Allow from 127.0.0.0/255.0.0.0 ::1/128 </Directory> </VirtualHost> And the output of free -m: klaas@ubuntu-server:/etc/apache2$ free -m total used free shared buffers cached Mem: 1997 1401 595 0 144 1017 -/+ buffers/cache: 238 1758 Swap: 2035 0 2035 and I have no indication that swapping occurs on the moments the site is slow. I have runned top and it does not appear to be a CPU issue. I have the impression that the spawning of a apache thread could maybe be the bottleneck but it is just a suggestion. Maybe this gives some extra information! EDIT: The problem seemed to be gone for some time but occurs again! And not only with Apache, also connecting using SSH takes a tremendous time, sometimes it takes up to 15 seconds before the keyphrase is asked for. Also scp works very slowly. The behavious is really unpredoctable and makes the server very hard to use. Any ideas...?

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  • Failed to load resource: the server responded with a status of 406 (Not Acceptable)

    - by skip
    I am trying to send json data and get back json data as well. I've <annotation-driven /> configured in my servlet-context.xml and I am using Spring framework version 3.1.0.RELEASE. When I send the request the browser tells me that it is not happy with the data returned from the server and gives me 406 error. And when I see the response from the server I see the whole 406 page returned by tomcat 6 server. I have got following in my pom for Jackson/Jackson processor: <!-- Jackson --> <dependency> <groupId>org.codehaus.jackson</groupId> <artifactId>jackson-core-asl</artifactId> <version>1.9.4</version> </dependency> <dependency> <groupId>org.codehaus.jackson</groupId> <artifactId>jackson-mapper-asl</artifactId> <version>1.9.4</version> </dependency> <dependency> <groupId>org.codehaus.jackson</groupId> <artifactId>jackson-xc</artifactId> <version>1.9.4</version> </dependency> <!-- Jackson JSON Processor --> <dependency> <groupId>org.codehaus.jackson</groupId> <artifactId>jackson-mapper-asl</artifactId> <version>1.8.1</version> </dependency> Following is the jquery code I am using to send the json request: $(function(){$(".sutmit-button").click(function(){ var dataString=$("#app-form").serialize(); $.ajax({ type:"POST", url:"apply.json", data:dataString, success:function(data, textStatus, jqXHR){ console.log(jqXHR.status); console.log(data); $('.postcontent').html("<div id='message'></div>"); $('#message').html("<h3>Request Submitted</h3>").append("<p>Thank you for submiting your request.</p>").hide().fadeIn(1500,function(){$('#message');}); }, error:function(jqXHR, textStatus, errorThrown) { console.log(jqXHR.status); $('.postcontent').html("<div id='message'></div>"); $('#message').html("<h3>Request failed.</h3>").hide().fadeIn(1500,function(){$('#message');}); }, dataType: "json" }); return false;});}); Following is the Controller that is handling the request: @RequestMapping(method = RequestMethod.POST, value="apply", headers="Accept=application/json") public @ResponseBody Application processFranchiseeApplicationForm(HttpServletRequest request) { //... Application application = new Application(...); //... logger.debug(application); return application; } I am not able to figure out the reason why I might be getting this error. Could someone help me understand why am I getting the given error? Thanks.

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  • Code only runs properly if debugging step-by-step

    - by Cornwell
    Hello, I'm making a webserver and I've come up with some very strange problems. My server was running as expected yesterday when I turned off my laptop, but today it only sends the http headers (I didn't change anything) When a user requests a file, if I send them using the following code, it works perfectly: while ((n = fread(data, 1, sizeof(data), file)) > 0) send(ts, data, n, 0); but if I change it to this, it only sends ~2% of the file. And that's not a random number, it actually only sends about 2% of the file. while ((n = fread(data, 1, sizeof(data), file)) > 0) web.Send(data); int WEB::Send(string data) { return send(TempSocket, data.c_str(), data.size(), 0); } changing string to char* doesn't solve the problem. I'm using visual studio2010. If I run my code step-by-step, I am able to solve problem #1, everything gets sent. And that is my main problem. I do not understand why it happens. Hopefully someone can explain it to me. Thanks in advance. EDIT: int APIENTRY WinMain( HINSTANCE hInstance, HINSTANCE hPrev, LPSTR lpCmd,int nShow) { SOCKET MainSocket=0; MSG msg; RedirectIOToConsole(); CreateThread(NULL, NULL, ListenThread, NULL, NULL, NULL); while (GetMessage(&msg, NULL, 0, 0)) { TranslateMessage(&msg); DispatchMessage(&msg); } WSACleanup(); closesocket(MainSocket); MainSocket = INVALID_SOCKET; return msg.wParam; } DWORD WINAPI ListenThread(LPVOID lparam) { SOCKET MainSocket; WSADATA wsaData; SOCKET tmpsock; struct sockaddr_in local, from; int fromlen=sizeof(from); WSAStartup(MAKEWORD(2, 2), &wsaData); local.sin_family=AF_INET; local.sin_addr.s_addr=INADDR_ANY; local.sin_port=htons(PORT); MainSocket=socket(AF_INET,SOCK_STREAM,0); if(MainSocket==INVALID_SOCKET) { return 0; } if(bind(MainSocket,(struct sockaddr*)&local,sizeof(local))!=0) { return 0; } if(listen(MainSocket,10)!=0) { return 0; } while(1) { tmpsock = accept(MainSocket,(struct sockaddr*)&from,&fromlen); CreateThread(NULL, NULL, SlaveThread, (LPVOID)tmpsock, NULL, NULL); } } DWORD WINAPI SlaveThread(LPVOID lparam) { SOCKET ts = (SOCKET)lparam;//temporary socket ...... char data[4096]; int n; unsigned long int length = statbuf.st_size; web.SendHeaders(200, "OK", format("Content-Disposition: attachment; filename=\"%s\"", FileName.c_str()).c_str(), web.GetMimeType(ReqPath.c_str()), length, statbuf.st_mtime); unsigned long int i=0,d=0; while ((n = fread(data, 1, sizeof(data), file)) > 0) { d+=send(ts, data, n, 0); i+=n; } printf("%i=%i=%i\n", length,i,d); fclose(file);

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  • Problem with Json in Jquery

    - by Davidslv
    Hi everyone, I have a small survey, but when i submit it says that the msg is null, i don't see where is my error. If you could help me i apreciate it. Thank you My Form with Jquery and Ajax Function <!DOCTYPE HTML> <hmtl lang="pt-PT"> <head> <title>Formul&aacute;rio</title> <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script> </head> <body> <hr /> <h3>Formulario</h3> <script type="text/javascript" charset="utf-8"> $(function () { $('#submiter').click( function() { $.ajax({ type: "POST", url: 'validar.php', dataType: 'json', success: function(msg) { alert('Mensagem '+ msg.mensagem); }, error : function () { alert('Ocorreu um erro'); } }); }); }); </script> <form id="formulario" action="" method="post" accept-charset="utf-8"> <p>Pergunta 1</p> <label for="pergunta1">sim</label><input type="radio" id="p1" name="pergunta1" value="1" /><br /> <label for="pergunta1">n&atilde;o</label><input type="radio" id="p1" name="pergunta1" value="0" /> <br /> <p>Pergunta 2</p> <label for="pergunta2">sim</label><input type="radio" name="pergunta2" value="0" /><br /> <label for="pergunta2">n&atilde;o</label><input type="radio" name="pergunta2" value="1" /> <br /> <p>Pergunta 3</p> <label for="pergunta3">sim</label><input type="radio" name="pergunta3" value="0" /><br /> <label for="pergunta3">n&atilde;o</label><input type="radio" name="pergunta3" value="1" /> <br /> <p>Pergunta 4</p> <label for="pergunta4">sim</label><input type="radio" name="pergunta4" value="0" /><br /> <label for="pergunta4">n&atilde;o</label><input type="radio" name="pergunta4" value="1" /> <br /> <p><input type="submit" id="submiter" value="Continue &rarr;"></p> </form> </body> </html> My PHP <?php if($_POST) { $pergunta1 = $_POST['pergunta1']; $pergunta2 = $_POST['pergunta2']; $pergunta3 = $_POST['pergunta3']; $pergunta4 = $_POST['pergunta4']; $calcular = $pergunta1 + $pergunta2 + $pergunta3 + $pergunta4; $var = array ('mensagem' => $calcular); echo json_encode($var); } else { $var2 = array('mensagem' => 'sem resultado'); echo json_encode($var2); } ?>

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  • First time using select(), maybe a basic question?

    - by darkletter
    Hello people, i've been working for a few days with this server using select(). What it does, is that, i have two arrays of clients (one is "suppliers", and the other is "consumers"), and the mission of the server is to check whether the suppliers have something to send to the consumers, and in case affirmative, send it. The second part of the server is that, when the consumers have received the suppliers' info, they send a confirmation message to the same suppliers that sent the info. When a client connects, it gets recognized as "undefined", until it sends a message with the word "supplier" or "consumer" (in Spanish, as i'm from there), when the server puts it in the correct clients array. Well, what the server does is not very important here. What's important is that, i'm doing both parts with two different "for" loops, and that's where i'm getting the problems. When the first user connects to the server (be it a supplier or a consumer), the server gets stuck in the first or second loop, instead of just continuing its execution. As it's the first time i'm using select(), i may be missing something. Could you guys give me any sort of help? Thanks a lot in advance. for(;;) { rset=allset; nready=select(maxfd+1,&rset,NULL,NULL,NULL); if (FD_ISSET(sockfd, &rset)){ clilen=sizeof(cliente); if((connfd=accept(sockfd,(struct sockaddr *)&cliente,&clilen))<0) printf("Error"); IP=inet_ntoa(cliente.sin_addr); for(i=0;i<COLA;i++){if(indef[i]<0){indef[i]=connfd;IPind[i]=IP;break;}} FD_SET(connfd,&allset); if(connfd > maxfd) maxfd=connfd; if(i>maxii) maxii=i; if(--nready<=0) continue; }// Fin ISSET(sockfd) for(i=0;i<=maxii;i++){ if((sockfd1=indef[i])<0){ continue;} //! if(FD_ISSET(sockfd1,&rset)){ if((n=read(sockfd1,comp,MAXLINE))==0){close(sockfd1);FD_CLR(sockfd1,&allset);indef[i]=-1;printf("Cliente indefinido desconectado \n");} else{ comp[n]='\0'; if(strcmp(comp,"suministrador")==0){ for(j=0;j<=limite;j++){if(sumi[j]<0){IPsum[j]=IPind[i];sumi[j]=indef[i]; indef[i]=-1;if(j>maxis) {maxis=j;}break; } } } else if(strcmp(comp,"consumidor")==0){ for(o=0;j<=limite;j++){if(consum[o]<0){IPcons[o]=IPind[i];consum[o]=indef[i]; indef[o]=-1;if(o>maxic) {maxic=o;}break; } } } if(--nready <=0)break; } } }//fin bucle for maxii for(i=0;i<=maxis;i++){ if((sockfd2=sumi[i])<0){continue;} if(FD_ISSET(sockfd2,&rset)){ if((n=read(sockfd2,buffer2,MAXLINE))==0){close(sockfd2);FD_CLR(sockfd2,&allset);sumi[i]=-1;printf("Suministrador desconectado \n");} else{ buffer2[n]='\0'; for(j=0;j<=maxic;j++){ if((sockfd3=consum[j])<0){ continue;} else {strcpy(final,IPsum[i]);strcat(final,":");strcat(final,buffer2);write(sockfd3,final,sizeof(final));respuesta[i]=1;} } break; // ? } } }//fin for maxis for(i=miniic;i<=maxic;i++){ if((sockfd4=consum[i])<0){continue;} if(FD_ISSET(sockfd4,&rset)){ if((n=read(sockfd4,buffer3,MAXLINE))==0){close(sockfd4);FD_CLR(sockfd4,&allset);consum[i]=-1;printf("Consumidor desconectado \n");} else{ buffer3[n]='\0'; IP2=strtok(buffer3,":"); obj=strtok(NULL,":"); for(j=0;j<100;j++){ if((strcmp(IPsum[j],IP2)==0) && (respuesta[j]==1)) {write(sumi[j],obj,sizeof(obj)); miniic=i+1; respuesta[j]=0; break; } } } } }

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  • TCP client in C and server in Java

    - by faldren
    I would like to communicate with 2 applications : a client in C which send a message to the server in TCP and the server in Java which receive it and send an acknowledgement. Here is the client (the code is a thread) : static void *tcp_client(void *p_data) { if (p_data != NULL) { char const *message = p_data; int sockfd, n; struct sockaddr_in serv_addr; struct hostent *server; char buffer[256]; sockfd = socket(AF_INET, SOCK_STREAM, 0); if (sockfd < 0) { error("ERROR opening socket"); } server = gethostbyname(ALARM_PC_IP); if (server == NULL) { fprintf(stderr,"ERROR, no such host\n"); exit(0); } bzero((char *) &serv_addr, sizeof(serv_addr)); serv_addr.sin_family = AF_INET; bcopy((char *)server->h_addr, (char *)&serv_addr.sin_addr.s_addr, server->h_length); serv_addr.sin_port = htons(TCP_PORT); if (connect(sockfd,(struct sockaddr *) &serv_addr,sizeof(serv_addr)) < 0) { error("ERROR connecting"); } n = write(sockfd,message,strlen(message)); if (n < 0) { error("ERROR writing to socket"); } bzero(buffer,256); n = read(sockfd,buffer,255); if (n < 0) { error("ERROR reading from socket"); } printf("Message from the server : %s\n",buffer); close(sockfd); } return 0; } And the java server : try { int port = 9015; ServerSocket server=new ServerSocket(port); System.out.println("Server binded at "+((server.getInetAddress()).getLocalHost()).getHostAddress()+":"+port); System.out.println("Run the Client"); while (true) { Socket socket=server.accept(); BufferedReader in= new BufferedReader(new InputStreamReader(socket.getInputStream())); System.out.println(in.readLine()); PrintStream out=new PrintStream(socket.getOutputStream()); out.print("Welcome by server\n"); out.flush(); out.close(); in.close(); System.out.println("finished"); } } catch(Exception err) { System.err.println("* err"+err); } With n = read(sockfd,buffer,255); the client is waiting a response and for the server, the message is never ended so it doesn't send a response with PrintStream. If I remove these lines : bzero(buffer,256); n = read(sockfd,buffer,255); if (n < 0) { error("ERROR reading from socket"); } printf("Message from the server : %s\n",buffer); The server knows that the message is finished but the client can't receive the response. How solve that ? Thank you

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  • Strange thing on IPv6 multicast program on Windows

    - by zhanglistar
    I have written an ipv6 multicast program on windows xp sp3. But a problem bothers me a lot. The sendto function implies no error, but I can't capture the packet using wireshark. I am sure the filter is right. Thanks in advance. And the code is as follows: #include "stdafx.h" #include <stdio.h> /* for printf() and fprintf() */ #include <winsock2.h> /* for socket(), connect(), sendto(), and recvfrom() */ #include <ws2tcpip.h> /* for ip_mreq */ #include <stdlib.h> /* for atoi() and exit() */ #include <string.h> /* for memset() */ #include <time.h> /* for timestamps */ #include <pcap.h> #include <Iphlpapi.h> #pragma comment(lib, "Ws2_32.lib") #pragma comment(lib, "wpcap.lib") #pragma comment(lib, "Iphlpapi.lib") int _tmain(int argc, _TCHAR* argv[]) { int sfd; int on, length, iResult; WSADATA wsaData; struct addrinfo Hints; struct addrinfo *multicastAddr, *localAddr; char buf[46]; // Initialize Winsock iResult = WSAStartup(MAKEWORD(2, 2), &wsaData); if (iResult != 0) { printf("WSAStartup failed: %d\n", iResult); return 1; } /* Resolve destination address for multicast datagrams */ memset(&Hints, 0, sizeof (Hints)); Hints.ai_family = AF_INET6; Hints.ai_socktype = SOCK_DGRAM; Hints.ai_protocol = IPPROTO_UDP; Hints.ai_flags = AI_NUMERICHOST; iResult = getaddrinfo("FF02::1:2", "547", &Hints, &multicastAddr); if (iResult != 0) { /* error handling */ printf("socket error: %d\n", WSAGetLastError()); return -1; } /* Get a local address with the same family (IPv4 or IPv6) as our multicast group */ Hints.ai_family = multicastAddr->ai_family; Hints.ai_socktype = SOCK_DGRAM; Hints.ai_flags = AI_PASSIVE; /* Return an address we can bind to */ if ( getaddrinfo(NULL, "546", &Hints, &localAddr) != 0 ) { printf("getaddrinfo() failed: %d\n", WSAGetLastError()); exit(-1); } // Create sending socket //sfd = socket (multicastAddr->ai_family, multicastAddr->ai_socktype, multicastAddr->ai_protocol); sfd = socket(AF_INET6, SOCK_DGRAM, IPPROTO_UDP); if (sfd == -1) { printf("socket error: %d\n", WSAGetLastError()); return 0; } /* Bind to the multicast port */ if ( bind(sfd, localAddr->ai_addr, localAddr->ai_addrlen) != 0 ) { printf("bind() failed: %d\n", WSAGetLastError()); exit(-1); } if (multicastAddr->ai_family == AF_INET6 && multicastAddr->ai_addrlen == sizeof(struct sockaddr_in6)) /* IPv6 */ { on = 1; if (setsockopt (sfd, IPPROTO_IPV6, IPV6_MULTICAST_IF, (char *)&on, sizeof (on) /*(char *)&interface_addr, sizeof(interface_addr)*/) == -1) { printf("setsockopt error:%d\n", WSAGetLastError()); return -1; } if (setsockopt (sfd, IPPROTO_IPV6, IPV6_MULTICAST_LOOP, (char *)&on, sizeof (on) /*(char *)&interface_addr, sizeof(interface_addr)*/) == -1) { printf("setsockopt error:%d\n", WSAGetLastError()); return -1; } struct ipv6_mreq multicastRequest; /* Multicast address join structure */ /* Specify the multicast group */ memcpy(&multicastRequest.ipv6mr_multiaddr, &((struct sockaddr_in6*)(multicastAddr->ai_addr))->sin6_addr, sizeof(struct in6_addr)); /* Accept multicast from any interface */ multicastRequest.ipv6mr_interface = 0; /* Join the multicast address */ if ( setsockopt(sfd, IPPROTO_IPV6, IPV6_JOIN_GROUP, (char*) &multicastRequest, sizeof(multicastRequest)) != 0 ) { printf("setsockopt() failed: %d\n", WSAGetLastError()); return -1; } on = 1; if (setsockopt (sfd, IPPROTO_IPV6, IPV6_MULTICAST_IF, (char *)&on, sizeof (on)) == -1) { printf("setsockopt error:%d\n", WSAGetLastError()); return 0; } } memset(buf, 0, sizeof(buf)); strcpy(buf, "hello world"); iResult = sendto(sfd, buf, strlen(buf), 0, (LPSOCKADDR) multicastAddr->ai_addr, multicastAddr->ai_addrlen); if (iResult == SOCKET_ERROR) { printf("setsockopt error:%d\n", WSAGetLastError()); return -1; /* Error handling */ } return 0; }

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  • connection between two android phones

    - by user1770346
    I m not able to connect my android device to other device(either android or non-android)via bluetooth.After detecting the devices from my android phone,i m not able to connect it to selected device from the list.The main problem is it not showing connectivity conformation message in selected device from list.How can i recover from this problem. please help me.Thanks My code for searching device is:(BluetoothSearchActivity.java) public class BluetoothSearchActivity extends Activity { ArrayAdapter<String> btArrayAdapter; BluetoothAdapter mBluetoothAdapter; TextView stateBluetooth; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); ImageView BluetoothSearchImageView=new ImageView(this); BluetoothSearchImageView.setImageResource(R.drawable.inner1); setContentView(BluetoothSearchImageView); setContentView(R.layout.activity_bluetooth_search); mBluetoothAdapter=BluetoothAdapter.getDefaultAdapter(); ListView listDevicesFound=(ListView) findViewById(R.id.myList); btArrayAdapter=new ArrayAdapter<String> (BluetoothSearchActivity.this,android.R.layout.simple_list_item_1); listDevicesFound.setAdapter(btArrayAdapter); registerReceiver(ActionFoundReceiver,new IntentFilter(BluetoothDevice.ACTION_FOUND)); btArrayAdapter.clear(); mBluetoothAdapter.startDiscovery(); listDevicesFound.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView<?> parent,View view,int position,long id) { Intent i6=new Intent(getApplicationContext(),AcceptThread.class); startActivity(i6); } }); } private final BroadcastReceiver ActionFoundReceiver=new BroadcastReceiver() { @Override public void onReceive(Context context, Intent intent) { // TODO Auto-generated method stub String action=intent.getAction(); if(BluetoothDevice.ACTION_FOUND.equals(action)) { BluetoothDevice device=intent.getParcelableExtra(BluetoothDevice.EXTRA_DEVICE); btArrayAdapter.add(device.getName()+"\n"+device.getAddress()); btArrayAdapter.notifyDataSetChanged(); Log.d("BluetoothSearchActivity",device.getName()+"\n"+device.getAddress()); } } }; @Override protected void onDestroy() { super.onDestroy(); unregisterReceiver(ActionFoundReceiver); } @Override public boolean onCreateOptionsMenu(Menu menu) { getMenuInflater().inflate(R.menu.activity_bluetooth_search, menu); return true; } } and my connectivity code is:(AcceptThread.java) class ConnectThread extends Thread { private static final UUID MY_UUID=UUID.fromString("fa87c0d0-afac-11de-8a39-0800200c9a66"); private static final String ConnectThread = null; BluetoothSocket mSocket; BluetoothDevice mDevice; BluetoothAdapter mBluetoothAdapter; public ConnectThread(BluetoothDevice device) { BluetoothSocket temp=null; mDevice=device; try{ temp=mDevice.createRfcommSocketToServiceRecord(MY_UUID); }catch(IOException e) { } mSocket=temp; } public void run() { mBluetoothAdapter.cancelDiscovery(); try{ Log.i(ConnectThread,"starting to connect"); mSocket.connect(); }catch(IOException connectException) { Log.e(ConnectThread,"connection Failed"); try{ mSocket.close(); }catch(IOException closeException){ } return; } } public void cancel() { try{ mSocket.close(); }catch(IOException e) { } } } public class AcceptThread extends Thread{ private static final String NAME="BluetoothAcceptThread"; private static final UUID MY_UUID=UUID.fromString("fa87c0d0-afac-11de-8a39-0800200c9a66"); BluetoothServerSocket mServerSocket; BluetoothAdapter mBluetoothAdapter; public AcceptThread() { BluetoothServerSocket temp=null; try{ temp=mBluetoothAdapter.listenUsingRfcommWithServiceRecord(NAME,MY_UUID); }catch(IOException e){ } mServerSocket=temp; } public void run() { BluetoothSocket socket=null; while(true) { try{ socket=mServerSocket.accept(); }catch(IOException e) { break; } if(socket!=null) { try { mServerSocket.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } break; } } } public void cancel() { try{ mServerSocket.close(); }catch(IOException e) { } } }

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  • Ajax post not posting email address ?

    - by jeitjet
    UPDATE: It will not work in Firefox, but will work on any other browser. I even tried loading Firefox in safe mode (disabling all plugins, etc.) and still no worky. :( I'm trying to do an AJAX post (on form submission) to a separate PHP file, which works fine without trying to send an email address through the post. I'm fairly new to AJAX and pretty familiar with PHP. Here's my form and ajax call <form class="form" method="POST" name="settingsNotificationsForm"> <div class="clearfix"> <label>Email <em>*</em><small>A valid email address</small></label><input type="email" required="required" name="email" id="email" /> </div> <div class="clearfix"> <label>Email Notification<small>...when a new subscriber joins</small></label><input type="checkbox" name="subscribe_notifications" id="subscribe_notifications"> Receive an email notification with phone number when someone new subscribes to 'BIZDEMO' </div> <div class="clearfix"> <label>Email Notification<small>...when a subscriber cancels</small></label><input type="checkbox" name="unsubscribe_notifications" id="unsubscribe_notifications"> Receive an email notification with phone number when someone new unsubscribes to 'BIZDEMO' </div> <div class="action clearfix top-margin"> <button class="button button-gray" type="submit" id="notifications_submit"><span class="accept"></span>Save</button> </div> </form> and AJAX call: <script type="text/javascript"> jQuery(document).ready(function () { $("#notifications_submit").click(function() { var keyword_value = '<?php echo $keyword; ?>'; var email_address = $("input#email").val(); var subscribe_notifications_value = $("input#subscribe_notifications").attr('checked'); var unsubscribe_notifications_value = $("input#unsubscribe_notifications").attr('checked'); var data_values = { keyword : keyword_value, email : email_address, subscribe_notifications : subscribe_notifications_value, unsubscribe_notifications : unsubscribe_notifications_value }; $.ajax({ type: "POST", url: "../includes/ajax/update_settings.php", data: data_values, success: alert('Settings updated successfully!'), }); }); }); and receiving page: <?php include_once ("../db/db_connect.php"); $keyword = FILTER_INPUT(INPUT_POST, 'keyword' ,FILTER_SANITIZE_STRING); $email = FILTER_INPUT(INPUT_POST, 'email' ,FILTER_SANITIZE_EMAIL); $subscribe_notifications = FILTER_INPUT(INPUT_POST, 'subscribe_notifications' ,FILTER_SANITIZE_STRING); $unsubscribe_notifications = FILTER_INPUT(INPUT_POST, 'unsubscribe_notifications' ,FILTER_SANITIZE_STRING); $table = 'keyword_options'; $data_values = array('email' => $email, 'sub_notify' => $subscribe_notifications, 'unsub_notify' => $unsubscribe_notifications); foreach ($data_values as $name=>$value) { // See if keyword is already in database table $filter = array('keyword' => $keyword); $result = $db->find($table, $filter); if (count($result) > 0 && $new != true) { $where = array('keyword' => $keyword, 'keyword_meta' => $name); $data = array('keyword_value' => $value); $db->update($table, $where, $data); } else { $data = array('keyword' => $keyword, 'keyword_meta' => $name, 'keyword_value' => $value); $db->create($table, $data); $new = true; // If this is a new record, always go to else statement } } unset($value); Here are some weird things that happen: When I only enter text into the email field, (i.e. - abc), it works fine, posts correctly, etc. When I enter a bogus email address with the "." before the "@", it works fine When I enter a validated email address (with the "." after the "@"), the post fails. Ideas?

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  • No Method Error in Ruby

    - by JayG
    Hi, I currently have a Rails Apps that lets users drag and drop certain elements of the webpage and updates the application based on the users choice. This is done with the help of the Rails helpers and AJAX. However I keep running into a "NoMethodError" in Ruby. NoMethodError in ProjectsController#member_change undefined method `symbolize_keys' for nil:NilClass Here is the method that is being called. My trace says that error is occurring in this line: before = u.functions_for(r.authorizable_id) u.roles << r unless u.roles.include? r u.save flag_changed = true after = u.functions_for(r.authorizable_id) And here is the function being called def member_change flag_changed = false params['u'] =~ /role_(\d+)_user_(\d+)/ drag_role_id = $1 user_id = $2 params['r'] =~ /role_(\d+)/ drop_role_id = $1 if u=User.find(user_id) if r=Role.find(drop_role_id) if drag_role_id.to_i !=0 and old_r=Role.find(drag_role_id) if drag_role_id == drop_role_id #fom A to A => nothing happen flash.now[:warning] = _('No Operation...') elsif r.authorizable_id == old_r.authorizable_id #the same project? old_r.users.delete(u) unless old_r.valid? flash.now[:warning] = _('Group "Admin" CAN NOT be EMPTY.') old_r.users << u #TODO: better recovery member_edit #if flag_changed render :action => :member_edit, :layout => 'module_with_flash' return end old_r.save r.users << u unless r.users.include? u r.save flag_changed = true before = u.functions_for(r.authorizable_id) after = u.functions_for(r.authorizable_id) added = after - before removed = before - after added.each do |f| ApplicationController::send_msg(:function,:create, {:function_name => f.name, :user_id => u.id, :project_id => r.authorizable_id }) end removed.each do |f| ApplicationController::send_msg(:function,:delete, {:function_name => f.name, :user_id => u.id, :project_id => r.authorizable_id }) end flash.now[:notice] = _( 'Move User to Group' ) + " #{ r.name }" else flash.now[:warning] = _('You can\'t move User between Groups that belong to different Projects.') end else before = u.functions_for(r.authorizable_id) u.roles << r unless u.roles.include? r u.save flag_changed = true after = u.functions_for(r.authorizable_id) added = after - before added.each do |f| ApplicationController::send_msg(:function,:create, {:function_name => f.name, :user_id => u.id, :project_id => r.authorizable_id }) end flash.now[:notice] = _( 'Add User into Group' ) + " #{ r.name }" end else flash.now[:warn] = _( 'Group doesn\'t exist!' ) + ": #{ r.name }" end else flash.now[:warning] = _( 'User doesn\'t exist!' ) + ": #{ u.login }" end member_edit #if flag_changed render :action => :member_edit, :layout => 'module_with_flash' end and the JavaScript used to call the function jQuery('#RemoveThisMember').droppable({accept:'.RolesUsersSelection', drop:function(ev,ui){ if (confirm("This will remove User from this Group, are you sure?")) {jQuery.ajax({data:'u=' + encodeURIComponent(jQuery(ui.draggable).attr('id')), success:function(request){jQuery('#module_content').html(request);}, type:'post', url:'/of/projects/11/member_delete'});} }, hoverClass:'ProjectRoleDropDelete_active'}) Any ideas? Thanks,

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  • Java deadlock problem....

    - by markovuksanovic
    I am using java sockets for communication. On the client side I have some processing and at this point I send an object to the cient. The code is as follows: while (true) { try { Socket server = new Socket("localhost", 3000); OutputStream os = server.getOutputStream(); InputStream is = server.getInputStream(); CommMessage commMessage = new CommMessageImpl(); ByteArrayOutputStream bos = new ByteArrayOutputStream(); ObjectOutputStream oos = new ObjectOutputStream(bos); oos.writeObject(commMessage); os.write(bos.toByteArray()); os.flush(); byte[] buff = new byte[512]; int bytesRead = 0; ByteArrayOutputStream receivedObject = new ByteArrayOutputStream(); while ((bytesRead = is.read(buff)) > -1) { receivedObject.write(buff, 0, bytesRead); System.out.println(receivedObject); } os.close(); Thread.sleep(10000); } catch (IOException e) { } catch (InterruptedException e) { } } Next on the server side I have the following code to read the object and write the response (Which is just an echo message) public void startServer() { Socket client = null; try { server = new ServerSocket(3000); logger.log(Level.INFO, "Waiting for connections."); client = server.accept(); logger.log(Level.INFO, "Accepted a connection from: " + client.getInetAddress()); os = new ObjectOutputStream(client.getOutputStream()); is = new ObjectInputStream(client.getInputStream()); // Read contents of the stream and store it into a byte array. byte[] buff = new byte[512]; int bytesRead = 0; ByteArrayOutputStream receivedObject = new ByteArrayOutputStream(); while ((bytesRead = is.read(buff)) > -1) { receivedObject.write(buff, 0, bytesRead); } // Check if received stream is CommMessage or not contents. CommMessage commMessage = getCommMessage(receivedObject); if (commMessage != null) { commMessage.setSessionState(this.sessionManager.getState().getState()); ByteArrayOutputStream bos = new ByteArrayOutputStream(); ObjectOutputStream oos = new ObjectOutputStream(bos); oos.writeObject(commMessage); os.write(bos.toByteArray()); System.out.println(commMessage.getCommMessageType()); } else { processData(receivedObject, this.sessionManager); } os.flush(); } catch (IOException e) { } finally { try { is.close(); os.close(); client.close(); server.close(); } catch (IOException e) { } } } The above code works ok if I do not try to read data on the client side (If i exclude the code related to reading). But if I have that code, for some reason, I get some kind of deadlock when accessing input streams. Any ideas what I might have done wrong? Thanks in advance.

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  • Is this a reasonable way to handle getters/setters in a PHP class?

    - by Mark Biek
    I'm going to try something with the format of this question and I'm very open to suggestions about a better way to handle it. I didn't want to just dump a bunch of code in the question so I've posted the code for the class on refactormycode. base-class-for-easy-class-property-handling My thought was that people can either post code snippets here or make changes on refactormycode and post links back to their refactorings. I'll make upvotes and accept an answer (assuming there's a clear "winner") based on that. At any rate, on to the class itself: I see a lot of debate about getter/setter class methods and is it better to just access simple property variables directly or should every class have explicit get/set methods defined, blah blah blah. I like the idea of having explicit methods in case you have to add more logic later. Then you don't have to modify any code that uses the class. However I hate having a million functions that look like this: public function getFirstName() { return $this->firstName; } public function setFirstName($firstName) { return $this->firstName; } Now I'm sure I'm not the first person to do this (I'm hoping that there's a better way of doing it that someone can suggest to me). Basically, the PropertyHandler class has a __call magic method. Any methods that come through __call that start with "get" or "set" are then routed to functions that set or retrieve values into an associative array. The key into the array is the name of the calling method after get or set. So, if the method coming into __call is "getFirstName", the array key is "FirstName". I liked using __call because it will automatically take care of the case where the subclass already has a "getFirstName" method defined. My impression (and I may be wrong) is that the __get & __set magic methods don't do that. So here's an example of how it would work: class PropTest extends PropertyHandler { public function __construct() { parent::__construct(); } } $props = new PropTest(); $props->setFirstName("Mark"); echo $props->getFirstName(); Notice that PropTest doesn't actually have "setFirstName" or "getFirstName" methods and neither does PropertyHandler. All that's doing is manipulating array values. The other case would be where your subclass is already extending something else. Since you can't have true multiple inheritance in PHP, you can make your subclass have a PropertyHandler instance as a private variable. You have to add one more function but then things behave in exactly the same way. class PropTest2 { private $props; public function __construct() { $this->props = new PropertyHandler(); } public function __call($method, $arguments) { return $this->props->__call($method, $arguments); } } $props2 = new PropTest2(); $props2->setFirstName('Mark'); echo $props2->getFirstName(); Notice how the subclass has a __call method that just passes everything along to the PropertyHandler __call method. Another good argument against handling getters and setters this way is that it makes it really hard to document. In fact, it's basically impossible to use any sort of document generation tool since the explicit methods to be don't documented don't exist. I've pretty much abandoned this approach for now. It was an interesting learning exercise but I think it sacrifices too much clarity.

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  • ANDROID: inside Service class, executing a method for Toast (or Status Bar notification) from schedu

    - by Peter SHINe ???
    I am trying to execute a {public void} method in Service, from scheduled TimerTask which is periodically executing. This TimerTask periodically checks a condition. If it's true, it calls method via {className}.{methodName}; However, as Java requires, the method needs to be {pubic static} method, if I want to use {className} with {.dot} The problem is this method is for notification using Toast(Android pop-up notification) and Status Bar To use these notifications, one must use Context context = getApplicationContext(); But for this to work, the method must not have {static} modifier and resides in Service class. So, basically, I want background Service to evaluate condition from scheduled TimerTask, and execute a method in Service class. Can anyone help me what's the right way to use Service, invoking a method when certain condition is satisfied while looping evaluation? Here are the actually lines of codes: The TimerTask class (WatchClipboard.java) : public class WatchClipboard extends TimerTask { //DECLARATION private static GetDefinition getDefinition = new GetDefinition(); @Override public void run() { if (WordUp.clipboard.hasText()) { WordUp.newCopied = WordUp.clipboard.getText().toString().trim().toLowerCase(); if (!(WordUp.currentCopied.equals(WordUp.newCopied))) { WordUp.currentCopied = WordUp.newCopied; Log.v(WordUp.TAG, WordUp.currentCopied); getDefinition.apiCall_Wordnik(); FetchService.instantNotification(); //it requires this method to have {static} modifier, if I want call in this way. } } } } And the Service class (FetchService.java) : If I change the modifier to static, {Context} related problems occur public class FetchService extends Service { public static final String TAG = "WordUp"; //for Logcat filtering //DECLARATION private static Timer runningTimer; private static final boolean THIS_IS_DAEMON = true; private static WatchClipboard watchClipboard; private static final long DELAY = 0; private static final long PERIOD = 100; @Override public IBinder onBind(Intent arg0) { // TODO Auto-generated method stub return null; } @Override public void onCreate() { Log.v(WordUp.TAG, "FetchService.onCreate()"); super.onCreate(); //TESTING SERVICE RUNNING watchClipboard = new WatchClipboard(); runningTimer = new Timer("runningTimer", THIS_IS_DAEMON); runningTimer.schedule(watchClipboard, DELAY, PERIOD); } @Override public void onDestroy() { super.onDestroy(); runningTimer.cancel(); stopSelf(); Log.v(WordUp.TAG, "FetchService.onCreate().stopSelf()"); } public void instantNotification() { //If I change the modifier to static, {Context} related problems occur Context context = getApplicationContext(); // application Context //use Toast notification: Need to accept user interaction, and change the duration of show Toast toast = Toast.makeText(context, WordUp.newCopied+": "+WordUp.newDefinition, Toast.LENGTH_LONG); toast.show(); //use Status notification: need to automatically expand to show lines of definitions NotificationManager mNotificationManager = (NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE); int icon = R.drawable.icon; // icon from resources CharSequence tickerText = WordUp.newCopied; // ticker-text long when = System.currentTimeMillis(); // notification time CharSequence contentTitle = WordUp.newCopied; //expanded message title CharSequence contentText = WordUp.newDefinition; //expanded message text Intent notificationIntent = new Intent(this, WordUp.class); PendingIntent contentIntent = PendingIntent.getActivity(this, 0, notificationIntent, 0); // the next two lines initialize the Notification, using the configurations above Notification notification = new Notification(icon, tickerText, when); notification.setLatestEventInfo(context, contentTitle, contentText, contentIntent); mNotificationManager.notify(WordUp.WORDUP_STATUS, notification); } }

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  • Why can't I sort this container?

    - by Knowing me knowing you
    Please don't mind that there is no insert fnc and that data are hardcoded. The main purpouse of it is to correctly implement iterator for this container. //file Set.h #pragma once template<class T> class Set { template<class T> friend ostream& operator<<(ostream& out, const Set<T>& obj); private: T** myData_; std::size_t mySize_; std::size_t myIndex_; public: Set(); class iterator : public std::iterator<std::random_access_iterator_tag, T*> { private: T** itData_; public: iterator(T** obj) { itData_ = obj; } T operator*() const { return **itData_; } /*Comparing values of two iterators*/ bool operator<(const iterator& obj) { return **itData_ < **obj.itData_; } /*Substracting two iterators*/ difference_type operator-(const iterator& obj) { return itData_ - obj.itData_; } /*Moving iterator backward for value*/ iterator operator-(const int value) { return itData_ - value; } /*Adding two iterators*/ difference_type operator+(const iterator& obj) { return itData_ + obj.itData_; } /*Moving iterator forward for value*/ iterator operator+(const int value) { return itData_ + value; } bool operator!=(const iterator& obj) { return (itData_ != obj.itData_); } bool operator==(const iterator& obj) { return (itData_ == obj.itData_); } T** operator++() { return ++itData_; } T** operator--() { return --itData_; } }; iterator begin() const { return myData_; } iterator end() const { return myData_ + myIndex_; } }; template<class T> ostream& operator<<(ostream& out, const Set<T>& obj) { for (int i = 0;i < 3; ++i) { out << *obj.myData_[i] << "\n"; } return out; } //file Set_impl.h #pragma once #include "stdafx.h" #include "Set.h" template<class T> Set<T>::Set() { mySize_ = 3; myIndex_ = 3; myData_ = new T*[mySize_]; myData_[0] = new T(3); myData_[1] = new T(1); myData_[2] = new T(2); } //main include "stdafx.h" #include "Set_impl.h" int _tmain(int argc, _TCHAR* argv[]) { Set<int> a; Set<int>::iterator beg_ = a.begin(); Set<int>::iterator end_ = a.end(); std::sort(beg_,end_);//WONT SORT THIS RANGE cin.get(); return 0; } Why sort can't accept this iterators even though I've provided all operators needed for sort to work? I think the best way to check what's going on is to paste this code and run it first. Thanks

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  • SOAP Service Request C#

    - by user3728352
    I have this code that tries to send a request to a soap server, I'm new to soap so i am not sure if the terms i am using are correct or not please correct me I am wrong. Basically i am accessing a web service method named getUserDomain via soap request Here is the code: public void CallWebService() { var _url = "https://....com/QcXmlWebService/QcXmlWebService.asmx?wsdl"; var _action = "https://....com/QcXmlWebService/QcXmlWebService.asmx?op=GetUserDomains"; XmlDocument soapEnvelopeXml = CreateSoapEnvelope(); HttpWebRequest webRequest = CreateWebRequest(_url, _action); InsertSoapEnvelopeIntoWebRequest(soapEnvelopeXml, webRequest); webRequest.BeginGetResponse(null, null); // begin async call to web request. IAsyncResult asyncResult = webRequest.BeginGetResponse(null, null); // suspend this thread until call is complete. You might want to // do something usefull here like update your UI. asyncResult.AsyncWaitHandle.WaitOne(); // get the response from the completed web request. string soapResult; using (WebResponse webResponse = webRequest.EndGetResponse(asyncResult)) { using (StreamReader rd = new StreamReader(webResponse.GetResponseStream())) { soapResult = rd.ReadToEnd(); } Console.Write(soapResult); } } private HttpWebRequest CreateWebRequest(string url, string action) { HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url); webRequest.Headers.Add("SOAPAction", action); webRequest.ContentType = "text/xml;charset=\"utf-8\""; webRequest.Accept = "text/xml"; webRequest.Method = "POST"; return webRequest; } private XmlDocument CreateSoapEnvelope() { XmlDocument soapEnvelop = new XmlDocument(); string oRequest = ""; oRequest = @"<soap:Envelope xmlns:soap=""http://www.w3.org/2003/05/soap-envelope"" xmlns:qcx=""http://smething.com/QCXML"">"; oRequest = oRequest + "<soap:Header/>"; oRequest = oRequest + "<soap:Body>"; oRequest = oRequest + "<qcx:GetUserDomains>"; oRequest = oRequest + "<qcx:inputXml><![CDATA["; oRequest = oRequest + "<GetUserDomains>"; oRequest = oRequest + "<login>"; oRequest = oRequest + "<domain_name>MBB_BTS</domain_name>"; oRequest = oRequest + "<project_name>WCDMA_BTS_IV</project_name>"; oRequest = oRequest + "<user_name>user</user_name>"; oRequest = oRequest + "<password>pass</password>"; oRequest = oRequest + "</login>"; oRequest = oRequest + "</GetUserDomains>"; oRequest = oRequest + " ]]>"; oRequest = oRequest + "</qcx:inputXml>"; oRequest = oRequest + "</qcx:GetUserDomains>"; oRequest = oRequest + "</soap:Body>"; oRequest = oRequest + "</soap:Envelope>"; soapEnvelop.LoadXml(oRequest); return soapEnvelop; } private void InsertSoapEnvelopeIntoWebRequest(XmlDocument soapEnvelopeXml, HttpWebRequest webRequest) { using (Stream stream = webRequest.GetRequestStream()) { soapEnvelopeXml.Save(stream); } } This code i have seen somewhere in stack overflow before as an answer but i couldn't get it to work... The error im getting is threw exception System.net.webexception. the remote server returned an error :(500) internal server Thanks

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  • How can I share Perl data structures through a socket?

    - by pavun_cool
    In sockets I have written the client server program. First I tried to send the normal string among them it sends fine. After that I tried to send the hash and array values from client to server and server to client. When I print the values using Dumper, it gives me only the reference value. What should I do to get the actual values in client server? Server Program: use IO::Socket; use strict; use warnings; my %hash = ( "name" => "pavunkumar " , "age" => 20 ) ; my $new = \%hash ; #Turn on System variable for Buffering output $| = 1; # Creating a a new socket my $socket= IO::Socket::INET->new(LocalPort=>5000,Proto=>'tcp',Localhost => 'localhost','Listen' => 5 , 'Reuse' => 1 ); die "could not create $! \n" unless ( $socket ); print "\nUDPServer Waiting port 5000\n"; my $new_sock = $socket->accept(); my $host = $new_sock->peerhost(); while(<$new_sock>) { #my $line = <$new_sock>; print Dumper "$host $_"; print $new_sock $new . "\n"; } print "$host is closed \n" ; Client Program use IO::Socket; use Data::Dumper ; use warnings ; use strict ; my %hash = ( "file" =>"log.txt" , size => "1000kb") ; my $ref = \%hash ; # This client for connecting the specified below address and port # INET function will create the socket file and establish the connection with # server my $port = shift || 5000 ; my $host = shift || 'localhost'; my $recv_data ; my $send_data; my $socket = new IO::Socket::INET ( PeerAddr => $host , PeerPort => $port , Proto => 'tcp', ) or die "Couldn't connect to Server\n"; while (1) { my $line = <stdin> ; print $socket $ref."\n"; if ( $line = <$socket> ) { print Dumper $line ; } else { print "Server is closed \n"; last ; } } I have given my sample program about what I am doing. Can any one tell me what I am doing wrong in this code? And what I need to do for accessing the hash values?

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  • Client/Server app

    - by Knowing me knowing you
    Guys could anyone tell me what's wrong am I doing here? Below are four files Client, main, Server, main. I'm getting an error on Client side after trying to fromServer.readLine(). Error: Error in Client Software caused connection abort: recv failed package client; import java.io.*; import java.net.*; import java.util.Scanner; public class Client { private PrintWriter toServer; private BufferedReader fromServer; private Socket socket; public Client( )throws IOException { socket = new Socket("127.0.0.1",3000); } public void openStreams() throws IOException { // // InputStream is = socket.getInputStream(); // OutputStream os = socket.getOutputStream(); // fromServer = new BufferedReader(new InputStreamReader(is)); // toServer = new PrintWriter(os, true); toServer = new PrintWriter(socket.getOutputStream(),true); fromServer = new BufferedReader(new InputStreamReader(socket.getInputStream())); } public void closeStreams() throws IOException { fromServer.close(); toServer.close(); socket.close(); } public void run()throws IOException { openStreams(); String msg = ""; Scanner scanner = new Scanner(System.in); toServer.println("Hello from Client."); // msg = scanner.nextLine(); while (msg != "exit") { System.out.println(">"); // msg = scanner.nextLine(); toServer.println("msg"); String tmp = fromServer.readLine(); System.out.println("Server said: " + tmp); } closeStreams(); } } package server; import java.net.*; import java.io.*; public class Server { private ServerSocket serverSocket; private Socket socket; private PrintWriter toClient; private BufferedReader fromClient; public void run() throws IOException { System.out.println("Server is waiting for connections..."); while (true) { openStreams(); processClient(); closeStreams(); } } public void openStreams() throws IOException { serverSocket = new ServerSocket(3000); socket = serverSocket.accept(); toClient = new PrintWriter(socket.getOutputStream(),true); fromClient = new BufferedReader(new InputStreamReader(socket.getInputStream())); } public void closeStreams() throws IOException { fromClient.close(); toClient.close(); socket.close(); serverSocket.close(); } public void processClient()throws IOException { System.out.println("Connection established."); String msg = fromClient.readLine(); toClient.println("Client said " + msg); } } package client; import java.io.IOException; public class Main { /** * @param args the command line arguments */ public static void main(String[] args) { // TODO code application logic here try { Client client = new Client(); client.run(); } catch(IOException e) { System.err.println("Error in Client " + e.getMessage()); } } } package server; import java.io.IOException; public class Main { /** * @param args the command line arguments */ public static void main(String[] args) { // TODO code application logic here Server server = new Server(); try { server.run(); } catch(IOException e) { System.err.println("Error in Server " + e.getMessage()); } } }

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  • FineUploader multiple instances and dynamic naming

    - by RichieMN
    I am using FineUploader 4.0.8 within a MVC4 project using the jquery wrapper. Here is an example of my js code that creates a single instance of the fineUploader and is working just fine. At this time, I have the need for more than one instance of fineUploader, but each individual control doesn't know anything about the other and they're rendered as needed on a page (I've seen previous questions using a jQuery .each, which won't work here). Currently, I can't seem to correctly render any upload buttons, probably due to having an ID duplicated or something. See below for how I'm using MVC's Razor to create unique variables and html IDs for that individual instance. Here's my current implementation where I've added the dynamic values (places where you see _@Model.{PropertyName}): // Uploader control setup var [email protected] = $('#[email protected]').fineUploader({ debug: true, template: '[email protected]', button: $("#[email protected]"), request: { endpoint: '@Url.Action("UploadFile", "Survey")', customHeaders: { Accept: 'application/json' }, params: { [email protected]: (function () { return instance; }), [email protected]: (function () { return surveyItemResultId; }), [email protected]: (function () { return itemId; }), [email protected]: (function () { return loopingCounter++; }) } }, validation: { acceptFiles: ['image/*', 'application/xls', 'application/pdf', 'text/csv', 'application/vnd.openxmlformats-officedocument.spreadsheetml.template', 'application/vnd.openxmlformats-officedocument.spreadsheetml.sheet', 'application/vnd.ms-excel'], allowedExtensions: ['jpeg', 'jpg', 'gif', 'png', 'bmp', 'csv', 'xls', 'xlsx', 'pdf', 'xlt', 'xltx', 'txt'], sizeLimit: 1024 * 1024 * 2.5, // 2.5MB stopOnFirstInvalidFile: false }, failedUploadTextDisplay: { mode: 'custom' }, multiple: true, text: { uploadButton: 'Select your upload file(s)' } }).on('submitted', function (event, id, filename) { $("#modal-overlay").fadeIn(); $("#modal-box").fadeIn(); [email protected]++; $(':input[type=button], :input[type=submit], :input[type=reset]').attr('disabled', 'disabled'); }).on('complete', function (event, id, filename, responseJSON) { [email protected]++; if ([email protected] == [email protected]) { $(':input[type=button], :input[type=submit], :input[type=reset]').removeAttr('disabled'); //$("#overlay").fadeOut(); $("#modal-box").fadeOut(); $("#modal-overlay").fadeOut(); } }).on('error', function (event, id, name, errorReason, xhr) { //$("#overlay").fadeOut(); alert('error: ' + errorReason); $("#modal-box").fadeOut(); $("#modal-overlay").fadeOut(); }); }); Using the same principle as above, I've added this logic to the template too. Here's part of my template: <script type="text/template" id="[email protected]"> <div class="qq-uploader-selector qq-uploader"> <div class="qq-upload-drop-area-selector qq-upload-drop-area qq-hide-dropzone"> <span>Drop files here to upload</span> What I see when I use the above code is only the drag and drop section visible, and no button. There are no js errors either. I do have an example that only has one instance of this control on it and the results are the same visible drag and drop section and no button). Any thought as to what's going on? I'll gladly update the question if you find I'm missing something helpful. Please don't just -1 me if it's something I can easily improve or fix.

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  • C++ Problem resolution - is it the best way to simulate a "tuple"?

    - by fbin
    Hi everyone! I've got the following problem: "Write a template function vectorMAXMIN() that will accept a vector and a number indicating the size of the vector and will return the max and the min values of the vector"... So i think in it... Create a class vector to avoid the "size" passing value and control the insertions and can get from this the max and min values... ( dunno if it's a good idea ) The problem is "how to return a tuple?" When i read the problem, i thought in a tuple to return "max, min values" is it correct? The code: #include <iostream> template < typename T > class _tuple { public: T _Max; T _Min; }; template < typename T > class _vector { public: _vector( int cnt = 0); ~_vector(); _tuple< T > get_tuple( void ); void insert( const T ); private: T *ptr; int cnt; int MAX; }; template < typename T > _vector< T >::_vector( int N ) { ptr = new T [N] ; MAX = N; cnt = 0; } template < typename T > _tuple<T> _vector< T >::get_tuple( void ) { _tuple< T > _mytuple; _mytuple._Max = ptr[0]; _mytuple._Min = ptr[0]; for( int i = 1; i < cnt; i++) { if( _mytuple._Max > ptr[i] ) _mytuple._Max = ptr[i]; if( _mytuple._Min < ptr[i] ) _mytuple._Min = ptr[i]; } return _mytuple; } template < typename T > void _vector< T >::insert( const T element) { if( cnt == MAX ) std::cerr << "Error: Out of range!" << std::endl; else { ptr[cnt] = element; cnt++; } } template < typename T > _vector< T >::~_vector() { delete [] ptr; } int main() { _vector< int > v; _tuple < int > t; v.insert(2); v.insert(1); v.insert(5); v.insert(0); v.insert(4); t = v.get_tuple(); std::cout << "MAX:" << t._Max; std::cout << " MIN:" << t._Min; return 0; }

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  • Keeping socket open to send files on timer calls?

    - by user3704768
    I'm writing a program that requires an image to be fetched from a remote server every 10 milliseconds or so, as that's how often the image is updated. My current method calls a timer to grab the image, but it encounters Socket Closed errors all the time, and sometimes does not work at all. How can I fix my methods to keep the socket open the whole time, so no reconnecting is needed? Here is the full class: import java.awt.event.ActionEvent; import java.awt.event.ActionListener; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import java.net.InetAddress; import java.net.InetSocketAddress; import java.net.ServerSocket; import java.net.Socket; import java.net.UnknownHostException; import javax.swing.Timer; public class Connection { public static void createServer() throws IOException { Capture.getScreen(); ServerSocket socket = null; try { socket = new ServerSocket(12345, 0, InetAddress.getByName("127.0.0.1")); } catch (UnknownHostException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } System.out.println("Server started on " + socket.getInetAddress().getHostAddress() + ":" + socket.getLocalPort() + ",\nWaiting for client to connect."); final Socket clientConnection = socket.accept(); System.out.println("Client accepted from " + clientConnection.getInetAddress().getHostAddress() + ", sending file"); ActionListener taskPerformer = new ActionListener() { public void actionPerformed(ActionEvent evt) { System.out.println("Sending File"); try { pipeStreams(new FileInputStream(new File( "captures/sCap.png")), clientConnection.getOutputStream(), 1024); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } }; System.out.println("closing out connection"); try { clientConnection.close(); } catch (IOException e) { e.printStackTrace(); } try { socket.close(); } catch (IOException e) { e.printStackTrace(); } Timer timer = new Timer(10, taskPerformer); timer.setRepeats(true); timer.start(); } public static void createClient() throws IOException { System.out.println("Connecting to server."); final Socket socket = new Socket(); try { socket.connect(new InetSocketAddress(InetAddress .getByName("127.0.0.1"), 12345)); } catch (UnknownHostException e) { e.printStackTrace(); } catch (IOException e) { } ActionListener taskPerformer = new ActionListener() { public void actionPerformed(ActionEvent evt) { System.out.println("Success, retreiving file."); try { pipeStreams(socket.getInputStream(), new FileOutputStream( new File("captures/rCap.png")), 1024); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { } } }; System.out.println("Closing connection"); try { socket.close(); } catch (IOException e) { e.printStackTrace(); } Timer timer = new Timer(10, taskPerformer); timer.setRepeats(true); timer.start(); } public static void pipeStreams(java.io.InputStream source, java.io.OutputStream destination, int bufferSize) throws IOException { byte[] buffer = new byte[bufferSize]; int read = 0; while ((read = source.read(buffer)) != -1) { destination.write(buffer, 0, read); } destination.flush(); destination.close(); source.close(); } }

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  • Remotely Schedule and Stream Recorded TV in Windows 7 Media Center

    - by DigitalGeekery
    Have you ever been away from home and suddenly realized you forgot to record your favorite program? Now Windows 7 Media Center, users can schedule recordings remotely from their phones or mobile devices with Remote Potato. How it Works Remote Potato installs server software on the host computer running Windows 7 Media Center. Once the software is installed, we’ll need to do some port forwarding on the router and setup an optional dynamic DNS address. When setup is completed, we will access the application through a web based interface. Silverlight is required for Streaming recorded TV, but scheduling recordings can be done through an HTML interface. Installing Remote Potato Download and install Remote Potato on the Media Center PC. (See download link below) If you plan to stream any Recorded TV, you’ll also want to install the streaming pack located on the same page. It isn’t required to stream all shows, only shows that require the AC3 audio codec. Click Yes to allow Remote Potato to add rules to the Windows Firewall for remote access. You’ll likely need to accept a few UAC prompts. When notified that the rules were added, click OK. Remote Potato will then prompt you to allow administrator privileges to reserve a URL for it’s web server. Click Yes. Remote Potato server will start. Click on the configuration button at the right to to reveal the settings tabs.   One the General tab, you’ll have the option to run Remote Potato on startup and minimized in the System Tray. If you’re running Media Center on a dedicated HTPC, you’ll probably want to enable both startup options. Forwarding Ports on Your Router You’ll need to forward a couple ports on your router. By default, these will be ports 9080 and 9081. In this example we’re using a Linksys WRT54GL router, however, the steps for port forwarding will vary from router to router. On the Linksys configuration page, click on the Applications & Gaming Tab, and then the Port Range Forward tab. Under Application, type in a name of your choosing. In both the Start and End boxes, type the port number 9080. Enter the local IP address of your Media Center computer in the IP address column. Click the check box under Enable. Repeat the process on the next line, but this time use port 9081. When finished, click the Save Settings button. Note: It’s highly recommended that you configure the home computer running Media Center & Remote Potato with a static IP address.   Find your IP Address You’ll need to find the IP address assigned to your router from your ISP. There are many ways to do this but a quick and easy way is to visit a site like checkip.dyndns.org (link available below) The current external IP address of your router will be displayed in the browser.   Dynamic DNS This is an optional step, but  it’s highly recommended. Many routers, such as the Linksys WRT54GL we are using, support Dynamic DNS (DDNS). What Dynamic DNS allows you to do is affiliate your home router’s external IP address to a domain name. Every time your home router is assigned a a new IP address by your ISP, the domain name is updated to point to your new IP address. Remote Potato’s user interface is accessed over the Internet is by connecting to your router’s IP address followed by a colon and the port number. (Ex: XXX.XXX.XXX.XXX:9080) Instead of constantly having to look up and remember an IP address, you can use DDNS along with a 3rd party provider like DynDNS.com, to sign up for a free domain name and configure it to be updated each time your router is assigned a new IP address. Go to the DynDNS.com website (See link at the end of the article) and sign up for a free Domain name. You’ll need to register and confirm by email.   Once you’ve signed in and selected your domain name click Activate Services. You’ll get a confirmation message that your domain name has been activated.    On the Linksys WRT54GL click on the Setup tab an then DDNS. Select DynDNS.org, or TZO.com if you prefer to use their service, from the drop down list.   With DynDNS, you’ll need to fill in your username and password you signed up with at the DynDNS website and the hostname you chose. Note: You can connect over your local network with the IP Address of the computer running Remote Potato followed by a colon and the port number. Ex: 192.168.1.2:9080 Logging in Remote Potato and Recording a Show Once you connect, you’ll see the start page. To view the TV listings, click on TV Guide. You’ll then see your guide listings. There are a few ways to navigate the listings. At the top left, you can click on any of the preset time buttons to jump to  the listings at that time of the day.  Click on the arrows to the right and left of the day and date at the top center to proceed to the previous or next day. Or, jump to a specific day with the date and date buttons at the top right.   To setup a recording, click on a program.   You can choose to record the individual show or the entire series by clicking on Record Show or Record Series.   Remote Potato on Mobile Devices Perhaps the coolest feature of Remote Potato is the ability to schedule recording from your phone or mobile device. Note: For any devices or computers without Silverlight, you will be prompted to view the HTML page. Select Browse Listings. Select your program to record. In the Program Details, select Record Show to record the single episode or Record Series to record all instances of the series. You will then see a red dot on the program listing to indicate that the show is scheduled for recording.   Streaming Recorded TV Click on Recorded TV from the home screen to access your previously recorded TV programs. Click on the selection you wish to stream. Click on Play. If you receive this error message, you’ll need to install the streaming pack for Remote Potato. This is found on the same download page as installation files. (See link below) The Begin from slider allows you to start playback from the start (by default) or a different time of the program by moving the slider. The Quality (bitrate) setting  allows you to choose the quality of the playback. We found the video quality on the Normal setting to be pretty lousy, and Low was just pointless. High was the best overall viewing experience as it provided smooth quality video playback. We experienced significant stuttering during playback using the Ultra High setting.   Click Start when you are ready to begin. When playback begins you’ll see a slider at the top right.   Move the slider left or right to increase or decrease the size of the video. There’s also a button to switch to full screen.   Media Center users who travel frequently or are always on the go will likely find Remote Potato to be a blessing. Since being released earlier this year, updates for Remote Potato have come fast and furious. The latest beta release includes support for streaming music and photos. If you like those nice network TV logos, check out our article on adding TV channel logos to Windows Media Center. Downloads and Links Download Remote Potato and Streaming Pack Find your IP address Sign Up for a Domain Name at DynDNS.com Similar Articles Productive Geek Tips Schedule Updates for Windows Media CenterUsing Netflix Watchnow in Windows Vista Media Center (Gmedia)Add a Sleep Timer to Windows 7 Media CenterStartup Customizations for Media Center in Windows 7Enable Media Streaming in Windows Home Server to Windows Media Player TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 FoxClocks adds World Times in your Statusbar (Firefox) Have Fun Editing Photo Editing with Citrify Outlook Connector Upgrade Error Gadfly is a cool Twitter/Silverlight app Enable DreamScene in Windows 7 Microsoft’s “How Do I ?” Videos

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  • How To Run XP Mode in VirtualBox on Windows 7 (sort of)

    - by Matthew Guay
    A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

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  • How To Run XP Mode in VirtualBox on Windows 7 (sort of)

    - by Matthew Guay
    A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. 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