Search Results

Search found 7240 results on 290 pages for 'natural join'.

Page 163/290 | < Previous Page | 159 160 161 162 163 164 165 166 167 168 169 170  | Next Page >

• How can this SQL be wrong? What am I not seeing?

  - by ropstah

  Can anybody please spot my error, this should be a legal query in SQL shouldn't it?? Unknown column u.usr_auto_key in the ON clause This is the database schema: User: (usr_auto_key, name, etc...) Setting: (set_auto_key, name etc..) User_Setting: (usr_auto_key, set_auto_key, value) And this is the query... SELECT `u`.`usr_auto_key` AS `u__usr_auto_key`, `s`.`set_auto_key` AS `s__set_auto_key`, `u2`.`usr_auto_key` AS `u2__usr_auto_key`, `u2`.`set_auto_key` AS `u2__set_auto_key`, `u2`.`value` AS `u2__value` FROM `User` `u`, `Setting` `s` LEFT JOIN `User_Setting` `u2` ON `u`.`usr_auto_key` = `u2`.`usr_auto_key` WHERE (`s`.`sct_auto_key` = 1 AND `u`.`usr_auto_key` = 1 AND admin_property is null)

  Read the article

• Returning Null values with COUNT

  - by Randy B.

  With this query, I get a result that is two short of the table because they are not included in count, and I would like get the NULL values in the result. To do this, I am pretty sure I need to use a subquery of some kind, but I am not sure how, since the attribute in question is an aggregate. SELECT Equipment.SerialNo , Name, COUNT(Assignment.SerialNo) FROM Equipment INNER JOIN Assignment ON Assignment.SerialNo = Equipment.SerialNo GROUP BY Equipment.SerialNo, Name

  Read the article

• Parsing complicated query parameters

  - by Will

  My Python server receives jobs that contain a list of the items to act against, rather like a search query term; an example input: (Customer:24 OR Customer:24 OR (Group:NW NOT Customer:26)) To complicate matters, customers can join and leave groups at any time, and the job should be updated live when this happens. How is best to parse, apply and store (in my RDBMS) this kind of list of constraints?

  Read the article

• Getting a substring in Ruby by x number of chars

  - by wotaskd

  I'm trying to produce some Ruby code that will take a string and return a new one, with a number x number of characters removed from its end - these can be actual letters, numbers, spaces etc. Ex: given the following string a_string = "a1wer4zx" I need a simple way to get the same string, minus - say - the 3 last digits. In the case above, that would be "a1wer". The way I'm doing it right now seems very convoluted: an_array = a_string.split(//,(a_string.length-2)) an_array.pop new_string = an_array.join Any ideas?

  Read the article

• MySql mutliple tables

  - by Chris Harrison

  I've been looking into JOIN, subqueries and other ways of doing this, but I can't work out the best way to do this is... I have a table (ps_category_product): id_product, id_category I want to perform a query on it like: SELECT id_product FROM ps_category_product WHERE id_category='$this_cat' BUT, I only want to perform this query where the ID's are returned by a query on another table (ps_product): id_product, active SELECT id_product FROM ps_product WHERE active='1' Can anyone help me with getting these two queries working together?

  Read the article

• Why does this SQL work in VS but not in code?

  - by acidzombie24

  The line cmd.ExecuteNonQuery(); cmd.CommandText CREATE TRIGGER subscription_trig_0 ON subscription AFTER INSERT AS UPDATE user_data SET msg_count = msg_count + 1 FROM user_data JOIN INSERTED ON user_data.id = INSERTED.recipient; The exception: Incorrect syntax near the keyword 'TRIGGER'. Then using VS 2010, connected to the very same file (a mdf file) i run the query above and i get a success message.

  Read the article

• How do I achieve virtual attributes in CakePHP (using code, not SQL) as implemented in Ruby on Rails

  - by ash

  Source: http://asciicasts.com/episodes/16-virtual-attributes I'd like to achieve a similar setup as below, but in CakePHP and where the virtual attributes are created using code, not SQL (as documented at http://book.cakephp.org/view/1070/Additional-Methods-and-Properties#Using-virtualFields-1590). class User < ActiveRecord::Base # Getter def full_name [first_name, last_name].join(' ') end # Setter def full_name=(name) split = name.split(' ', 2) self.first_name = split.first self.last_name = split.last end end

  Read the article

• SQL Query to return both distinct and total logins from a login table in sql2005

  - by Prescott

  Hey all, I have a table Logins { Id, AccessTime }, I'd like to write a query that returns 3 columns, Total Logins during a time period, Unique Logins for a time period, and the Id of the user. I know I could do this with two passes and a join, is there a better way to do it in a single pass? Thanks, ~P

  Read the article

• [C#] RegEx search for two pattern strings and cut what's between

  - by gsharp

  I'm trying to write a little SQL Helper. I have a query like this stored in a string: DECLARE @V1 INT --ignore DECLARE @V11 INT DECLARE @V12 INT --endignore DECLARE @V2 INT --ignore SELECT * FROM SampleTable INNER JOIN AnotherSampleTable ...... --endignore SELECT * From Employee ORDER BY LastName My helper method should cut everything what's between --ignore and --endignore The result string should look like: DECLARE @V1 INT DECLARE @V2 INT SELECT * From Employee ORDER BY LastName How can achieve my result with RegEx?

  Read the article

• MySQL One to Many order by number found in joined table

  - by Finbarr

  Two tables: table_a ------- table_a_id: (primary, int) table_b ------- table_a_id: (index, int, from table_a) table_b_value: (varchar) A one to many relationship between table_a_id and table_b_value. Given a query like this: SELECT DISTINCT(table_a_id) FROM table_a JOIN table_b ON table_a.table_a_id=table_b.table_a_id I want to order by the number of occurrences of table_a_id in table_b. I'm not really sure how to write this in MySQL.

  Read the article

• Python 3: list atributes within a class object

  - by MadSc13ntist

  is there a way that if the following class is created; I can grab a list of attributes that exist. (this class is just an bland example, it is not my task at hand) class new_class(): def __init__(self, number): self.multi = int(number) * 2 self.str = str(number) a = new_class(2) print(', '.join(a.SOMETHING)) * the attempt is that "multi, str" will print. the point here is that if a class object has attributes added at different parts of a script that I can grab a quick listing of the attributes which are defined.

  Read the article

• Set the right two characters (if there are any) to capitals?

  - by Hyflex

  Below is my data: Data Here 94/452O Data more 94/4522i Data bla 94/111 Data bla 94/459es Data bla 94/444 items is automatically generated by some previous code but it could come out like: items = ["Data Here 94/452O", "Data more 94/4522i", "Data bla 94/111", "Data bla 94/459es", "Data bla 94/444"] Now currently I'm appending the following: "\n".join(items).replace("4ke", "9") with a few other .replaces however I want it to replace/change the characters on the end of the numbers with a capital letter instead of lowercase... Output: Data Here 94/452O Data more 94/4522I Data bla 94/111 Data bla 94/459ES Data bla 94/444

  Read the article

• Conversion failed when converting the varchar value to data type int

  - by desi

  *I have a varchar(1000) column declared as field that contains all numbers, as shown below. And I want to execute the following script. I need this to work please Declare @PostalCode varchar(1000)=0 set @PostalCode ='7005036,7004168,7002314,7001188,6998955' Select hl.* From CountryLocation cl INNER JOIN refPostalCodes pc ON pc.PostalCode = hl.PostalCode where pc.Postalcode in (@PostalCode) and pc.notDeleted = 1

  Read the article

• Django. Invalid keyword argument for this function. ManyToMany

  - by sagem_tetra

  I have this error: 'people' is an invalid keyword argument for this function class Passage(models.Model): name= models.CharField(max_length = 255) who = models.ForeignKey(UserProfil) class UserPassage(models.Model): passage = models.ForeignKey(Passage) people = models.ManyToManyField(UserProfil, null=True) class UserProfil(models.Model): user = models.OneToOneField(User) name = models.CharField(max_length=50) I try: def join(request): user = request.user user_profil = UserProfil.objects.get(user=user) passage = Passage.objects.get(id=2) #line with error up = UserPassage.objects.create(people= user_profil, passage=passage) return render_to_response('thanks.html') How to do correctly? Thanks!

  Read the article

• mysql extra columns with same name from two tables

  - by salmane

  Table 1 has columns : entry_id user_id ... Table 2 has columns : entry_id user_id ... the user_id entry is not always the same so I would like to extract both of them so I can later on compare them in my script SELECT * FROM table1 as t1 INNER JOIN table2 as t2 on t1.entry_id=t2.entry_id WHERE t1.user_id='%s' I would like to extract t1.user_id and t2.user_id ...the problem is the result array has only user_id thank you

  Read the article

• I want to read a big text file

  - by Rozer

  I want to read a big text file, what i decided to create four threads and read 25% of file by each one. and then join them. but its not more impressive. can any one tell me can i use concurrent programming for the same. as my file structure have some data as name contact compnay policyname policynumber uniqueno and I want to put all data in hashmap at last. thanks

  Read the article

• help with sql query - in access 2007

  - by Gold

  hi i have 2 tables table items has 144602 records table A has 27721 records code in items = BAR8 in A i want to show all records that equal i try this: SELECT Items.Code, A.BAR8 FROM Items INNER JOIN A ON Items.Code = A.BAR8; and i get 28048 records !!! i need to get 27721 , how to do it ? thank's in advance

  Read the article

• "Ambiguous column name" error on one particular server

  - by jazbit

  This simple query throws the "Ambiguous column name TaskID" error on one db-server only. This is ridiculous. We tested this with the same database structure on different servers and different versions of ms sql (2005/2008), and it's only THIS particular client's server that throws the error. I'm actually frustrated. SELECT Tasks.TaskID FROM Tasks INNER JOIN TaskHelpers ON TaskHelpers.TaskID = Tasks.TaskID order by TaskID Yes, I know I can put "Tasks.TaskID" into the order by clause, but for some reasons I can't.

  Read the article

• Sql string adding problem

  - by Woland

  SELECT a.one + ' test ' +b.two from table1 a right join table1 on a.id =b.id The problem is that when one is null then it the whole string is null, is there some kind of trick to bypass this problem msSQL 2005

  Read the article

• difference between where and nested queries

  - by Chris H

  I'm not able to figure out the difference between these queries. I'm pretty sure that the first one is an equi-join. I'm not sure how the second one ISN'T the same as the first. The sub query in #2 selects all Ids from S, and then it returns all R's that also have those ID's, no? SELECT R.cname FROM R, S, WHERE R.Id = S.Id SELECT R.cname FROM R WHERE R.Id IN (SELECT S.Id FROM S)

  Read the article

• Using Joins vs Entity associations

  - by shivesh

  I am learning Entity framework and linq-to-entities. It's possible to get cross values from multiple tables using JOINS (join keyword) or using the navigation fields ( associations) in which case the framework knows how to reference the cross data. My question is what to use when?

  Read the article

• Detecting Completion of an Array of Threads

  - by Harsha

  I have created an array of threads and started all of them. How to know whether all threads have completed work. I don't want to use thread.wait or thread.join.

  Read the article

• What would be better, (1 database + 4 tables) or (2 databases + 2 tables each) ?

  - by griseldas

  Hi there, I would like to be advised on what would be better (in regards to performance) A) 1 DATABASE with 4 tables or B) 2 DATABASES (same server), each with 2 tables. The tables size and usage are more or less similar, so the 2 tables on Database 1 would be similar usage/size to the 2 tables on database 2 The tables could have +500,000 records and the 2 tables on each database are not related (no join queries etc between them) Thanks in advance for your comments

  Read the article

• has any gae code like 'tribes' in this site .

  - by zjm1126

  in this site : http://cloud27.com/tribes/ you can join other's tribe, and create own tribe if you login. so has some open-source code do this ? thanks

  Read the article

• How to select distinct in SQl Server 2008 but for only one field out of many?

  - by bakerjr

  I have a query: SELECT Content.content_name, Language2.Name, Language2.language_id, Content.id, Content.content_description, FROM Language AS Language2 LEFT JOIN contents AS Content ON (Language2.language_id = Content.language_id) How do I select only the distinct content_name?

  Read the article

< Previous Page | 159 160 161 162 163 164 165 166 167 168 169 170  | Next Page >