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  • What are the interets of synthetic methods?

    - by romaintaz
    Problem One friend suggested an interesting problem. Given the following code: public class OuterClass { private String message = "Hello World"; private class InnerClass { private String getMessage() { return message; } } } From an external class, how may I print the message variable content? Of course, changing the accessibility of methods or fields is not allowed. (the source here, but it is a french blog) Solution The code to solve this problem is the following: try { Method m = OuterClass.class.getDeclaredMethod("access$000", OuterClass.class); OuterClass outerClass = new OuterClass(); System.out.println(m.invoke(outerClass, outerClass)); } catch (Exception e) { e.printStackTrace(); } Note that the access$000 method name is not really standard (even if this format is the one that is strongly recommanded), and some JVM will name this method access$0. Thus, a better solution is to check for synthetic methods: Method method = null; int i = 0; while ((method == null) && (i < OuterClass.class.getDeclaredMethods().length)) { if (OuterClass.class.getDeclaredMethods()[i].isSynthetic()) { method = OuterClass.class.getDeclaredMethods()[i]; } i++; } if (method != null) { try { System.out.println(method.invoke(null, new OuterClass())); } catch (Exception e) { e.printStackTrace(); } } So the interesting point in this problem is to highlight the use of synthetic methods. With these methods, I can access a private field as it was done in the solution. Of course, I need to use reflection, and I think that the use of this kind of thing can be quite dangerous... Question What is the interest - for me, as a developer - of a synthetic method? What can be a good situation where using the synthetic can be useful?

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  • FLEX, how to specify parent html item, when I call external functions ?

    - by Patrick
    hi, I'm calling a javascript function from my flex application to set width and height of my html wrapper according to application size. However, I've many flex applications on my page and the wrappers have not id attribute. I'm using a unique javascript function and passing it the parameters. How could I specify the "parent" html element in these parameters ? Following is the code: Actionscript: if (ExternalInterface.available) ExternalInterface.call("changeSize",id, width, height); Javascript: <script type="text/JavaScript"> function changeSize(id, width, height) { console.log(id); console.log(width); console.log(height); } Wrapper: <div class="filefield-file clear-block"> <div class="filefield-icon field-icon-video-x-flv"> <img class="field-icon-video-x-flv" alt="video/x-flv icon" src="http://localhost/drupal/sites/all/modules/filefield/icons/protocons/16x16/mimetypes/video-x-generic.png"></div> <div style="background-color: rgb(255, 255, 255); width: 400px;"> <embed style="display: block;" src="/drupal/videoPlayer.swf?file=http://localhost/drupal/sites/default/files/files/projects/Project3/videos/9565274.flv" type="application/x-shockwave-flash" pluginspage="http://www.adobe.com/go/getflashplayer" bgcolor="#ffffff" allowfullscreen="true" autoplay="true" flashvars="file=http://localhost/drupal/sites/default/files/files/projects/Project3/videos/9565274.flv" height="400" width="400"> <div>Scheduling Video</div> </div> </div>

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  • Get Object from memory using memory adresse

    - by Hamza Karmouda
    I want to know how to get an Object from memory, in my case a MediaRecorder. Here's my class: Mymic class: public class MyMic { MediaRecorder recorder2; File file; private Context c; public MyMic(Context context){ this.c=context; } private void stopRecord() throws IOException { recorder2.stop(); recorder2.reset(); recorder2.release(); } private void startRecord() { recorder2= new MediaRecorder(); recorder2.setAudioSource(MediaRecorder.AudioSource.MIC); recorder2.setOutputFormat(MediaRecorder.OutputFormat.THREE_GPP); recorder2.setAudioEncoder(MediaRecorder.AudioEncoder.AMR_NB); recorder2.setOutputFile(file.getPath()); try { recorder2.prepare(); recorder2.start(); } catch (IllegalStateException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } } my Receiver Class: public class MyReceiver extends BroadcastReceiver { private Context c; private MyMic myMic; @Override public void onReceive(Context context, Intent intent) { this.c=context; myMic = new MyMic(c); if(my condition = true){ myMic.startRecord(); }else myMic.stopRecord(); } } So when I'm calling startRecord() it create a new MediaRecorder but when i instantiate my class a second time i can't retrieve my Object. Can i retrieve my MediaRecorder with his addresse

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  • IE8: weird border around HTML button element

    - by s427
    I have a button element with a custom background (image+color) and no borders except for a 2px border-bottom (and a bunch of other properties --code below) which renders quite differently in Firefox and in IE8. The problem is, this is a work for a company that uses IE8 as their only browser, so it's important that the button renders well in IE8. Here's a visual comparison between the two: My question here is not about the padding difference (I'm looking into that), but about the weird border that is visible on IE8 in addition to the regular border (border-bottom). Can anyone explain to me where it comes from and how to get rid of it? Thanks in advance. Here is the HTML code: <button class="btn" id="c_edit"> <span>Annuler</span> </button> And here is the CSS: .btn { display: inline-block; margin: 0 0 7px 5px; padding: 0; color: #ddd; font-size: 14px; font-family: FrutigerLTStd55Roman, sans-serif; text-decoration: none; border: none; border-bottom: 2px solid #222; background-color: #999; background-image: url('img/btn_bg.gif'); background-position: 0 bottom; background-repeat: repeat-x; cursor: pointer; transition: all .5s ease-out; } .btn span { display: inline-block; margin: 0; padding: 8px 10px 6px 40px; background-color: transparent; background-position: 4px 0; background-repeat: no-repeat; }

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  • How to run an async task afor every x mins in android?

    - by Shan
    how to run the async task at specific time? (I want to run it every 2 mins) I tried using post delayed but it's not working? tvData.postDelayed(new Runnable(){ @Override public void run() { readWebpage(); }}, 100); In the above code readwebpage is function which calls the async task for me.. Right now below is the method which I am using public void onCreate(Bundle savedInstanceState) { readwebapage(); } public void readWebpage() { DownloadWebPageTask task = new DownloadWebPageTask(); task.execute("http://www.google.com"); } private class DownloadWebPageTask extends AsyncTask<String, Void, String> { @Override protected String doInBackground(String... urls) { String response1 = ""; response1=read(); //read is my another function which does the real work response1=read(); super.onPostExecute(response1); return response1; } protected void onPostExecute(String result) { try { Thread.sleep(100); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); } TextView tvData = (TextView) findViewById(R.id.TextView01); tvData.setText(result); DownloadWebPageTask task = new DownloadWebPageTask(); task.execute(new String[] { "http://www.google.com" }); } } This is what I my code is and it works perfectly fine but the big problem I drains my battery?

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  • Sort ranges in an array in google apps script

    - by user1637113
    I have a timesheet spreadsheet for our company and I need to sort the employees by each timesheet block (15 rows by 20 columns). I have the following code which I had help with, but the array quits sorting once it comes to a block without an employee name (I would like these to be shuffled to the bottom). Another complication I am having is there are numerous formulas in these cells and when I run it as is, it removes them. I would like to keep these intact if at all possible. Here's the code: function sortSections() { var activeSheet = SpreadsheetApp.getActiveSheet(); //SETTINGS var sheetName = activeSheet.getSheetName(); //name of sheet to be sorted var headerRows = 53; //number of header rows var pageHeaderRows = 5; //page totals to top of next emp section var sortColumn = 11; //index of column to be sorted by; 1 = column A var pageSize = 65; var sectionSize = 15; //number of rows in each section var col = sortColumn-1; var sheet = SpreadsheetApp.getActive().getSheetByName(sheetName); var data = sheet.getRange(headerRows+1, 1, sheet.getMaxRows()-headerRows, sheet.getLastColumn()).getValues(); var data3d = []; var dataLength = data.length/sectionSize; for (var i = 0; i < dataLength; i++) { data3d[i] = data.splice(0, sectionSize); } data3d.sort(function(a,b){return(((a[0][col]<b[0][col])&&a[0][col])?-1:((a[0][col]>b[0][col])?1:0))}); var sortedData = []; for (var k in data3d) { for (var l in data3d[k]) { sortedData.push(data3d[k][l]); } } sheet.getRange(headerRows+1, 1, sortedData.length, sortedData[0].length).setValues(sortedData);

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  • how to add data in Table of Jasper Report using Java

    - by Areeb Gillani
    i am here to ask you just a simple question that i am trying to pass data to a jasper report using java but i dont know how to to, because the table data is very dynamic thats y cannot pass sql query. any idea for this. i have a 2D array of object type, where i have all the data... so how can i pass that... Thanx in advance...!:) ConnectionManager con = new ConnectionManager(); con.establishConnection(); String fileName = "Pmc_Bill.jrxml"; String outFileName = "OutputReport.pdf"; HashMap params = new HashMap(); params.put("PName", pname); params.put("PSerial", psrl); params.put("PGender",pgen); params.put("PPhone",pph); params.put("PAge",page); params.put("PRefer",pref); params.put("PDateR",dateNow); try { JasperReport jasperReport = JasperCompileManager.compileReport(fileName); if(jasperReport != null ) System.out.println("so far so good "); // Fill the report using an empty data source JasperPrint jasperPrint = JasperFillManager.fillReport(jasperReport, params, new JRTableModelDataSource(tbl.getModel()));//con.connection); try{ JasperExportManager.exportReportToPdfFile(jasperPrint, outFileName); System.out.printf("File exported sucessfully"); }catch(Exception e){ e.printStackTrace(); } JasperViewer.viewReport(jasperPrint); } catch (JRException e) { JOptionPane.showMessageDialog(null, e); e.printStackTrace(); System.exit(1); }

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  • Access is denied. Javascript error on request to secured page

    - by ihorko
    On SomePage.aspx page by javascript (XMLHttpRequest) I call SecuredPage.aspx used next code: var httpRequest = GetXmlHttp(); var url = "https://myhost.com/SecuredPage.aspx"; var params = "param1=" + document.getElementById('param1').value + "&param2=" + document.getElementById('param2').value; httpRequest.open("POST", url, true); httpRequest.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); httpRequest.onreadystatechange = function() { //Call a function when the state changes. if (httpRequest.readyState == 4 && httpRequest.status == 200) { alert(httpRequest.responseText); } } httpRequest.send(params); // HERE ACCESS IS DENIED //--------------------------------------------- function GetXmlHttp() { var xmlhttp = false; if (window.XMLHttpRequest) { xmlhttp = new XMLHttpRequest(); } else if (window.ActiveXObject) // code for IE { try { xmlhttp = new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { try { xmlhttp = new ActiveXObject("Microsoft.XMLHTTP"); } catch (E) { xmlhttp = false; } } } return xmlhttp; } It throws Access is denied error. if send to http (http://myhost.com/SecuredPage.aspx), it works fine. How is it possible to resolve that problem. Thanks!

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  • Elegant way to import XHTML nodes from xhr.responseXML into HTML document in IE?

    - by Weston Ruter
    While navigating through a site, I'm dynamically loading pages via Ajax and then only updating the elements of the page that are changed, such as the navigation state and main content area. This is similar to Lala. I am serving the site as XHTML in order to be able to have access to xhr.responseXML which I then traverse in parallel with the current document and copy the nodes over. This works very well in browsers other than IE. For IE, I have to iterate over all of the properties of each XML element I want to import into the HTML document to create it from scratch (using a function convertXMLElementToHTML()). Here's the code I'm currently using: try { nodeB = document.importNode(nodeB, true); } catch(e){ nodeB = nodeB.cloneNode(true); if(document.adoptNode) document.adoptNode(nodeB); } try { //This works in all browsers other than IE nodeA.parentNode.replaceChild(nodeB, nodeA); } //Manually clone the nodes into HTML; required for IE catch(e){ nodeA.parentNode.replaceChild(convertXMLElementToHTML(nodeB), nodeA); } Is there a more elegant solution to mirror-translating XML nodes into HTML?

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  • How to encrypt a RSAKey using another RSAKey?

    - by Tom Brito
    I know its not the usual thing to do. But the specification I'm implementing is discribed this way, and I cannot run out. I was trying to encrypt the modulus and exponent of the private key, but the following test code raises an exception because the byte array is 1 byte larger then the maximum allowed by RSA block: import java.security.KeyPair; import java.security.KeyPairGenerator; import java.security.NoSuchAlgorithmException; import java.security.NoSuchProviderException; import java.security.interfaces.RSAPrivateKey; import java.security.interfaces.RSAPublicKey; import javax.crypto.Cipher; import org.apache.commons.lang.ArrayUtils; public class TEST { public static KeyPair generateKeyPair() throws NoSuchAlgorithmException, NoSuchProviderException { KeyPairGenerator keyPairGenerator = KeyPairGenerator.getInstance("RSA", "BC"); keyPairGenerator.initialize(1024); return keyPairGenerator.generateKeyPair(); } public static void main(String[] args) throws Exception { KeyPair keyPair = generateKeyPair(); RSAPrivateKey privateKey = (RSAPrivateKey) keyPair.getPrivate(); System.out.println("Priv modulus len = " + privateKey.getModulus().bitLength()); System.out.println("Priv exponent len = " + privateKey.getPrivateExponent().bitLength()); System.out.println("Priv modulus toByteArray len = " + privateKey.getModulus().toByteArray().length); byte[] byteArray = privateKey.getModulus().toByteArray(); // the byte at index 0 have no value (in every generation it is always zero) byteArray = ArrayUtils.subarray(byteArray, 1, byteArray.length); System.out.println("byteArray size: " + byteArray.length); RSAPublicKey publicKey = (RSAPublicKey) keyPair.getPublic(); Cipher cipher = Cipher.getInstance("RSA", "BC"); cipher.init(Cipher.ENCRYPT_MODE, publicKey); byte[] encryptedBytes = cipher.doFinal(byteArray); System.out.println("Success!"); } } (obs. its just a test, i would never encrypt the private key with its pair public key) The byte array is 128 bytes, the exactly maximum allowed by a RSA block, so why the exception? And how to fix it?

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  • uploading database file in assets not returning a record

    - by Alexander
    I have a problem with a database file not being read I have added the database file in assets called mydb but when i run my code it says its not being located. It is calling this toast Toast.makeText(this, "No contact found", Toast.LENGTH_LONG).show(); This is being called because no records are being returned. This is an example form Android Application Development book. public class DatabaseActivity extends Activity { /** Called when the activity is first created. */ TextView quest, response1, response2; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); TextView quest = (TextView) findViewById(R.id.quest); try { String destPath = "/data/data/" + getPackageName() + "/databases/MyDB"; File f = new File(destPath); if (!f.exists()) { CopyDB( getBaseContext().getAssets().open("mydb"), new FileOutputStream(destPath)); } } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } DBAdapter db = new DBAdapter(this); //---get a contact--- db.open(); Cursor c = db.getContact(2); if (c.moveToFirst()) DisplayContact(c); else Toast.makeText(this, "No contact found", Toast.LENGTH_LONG).show(); db.close(); } public void CopyDB(InputStream inputStream, OutputStream outputStream) throws IOException { //---copy 1K bytes at a time--- byte[] buffer = new byte[1024]; int length; while ((length = inputStream.read(buffer)) > 0) { outputStream.write(buffer, 0, length); } inputStream.close(); outputStream.close(); } public void DisplayContact(Cursor c) { quest.setText(String.valueOf(c.getString(1))); //quest.setText(String.valueOf("this is a text string")); } }

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  • VB.NET CInt(Long) behaving differently in 32- and 64-bit environments

    - by LocoDelAssembly
    Hello everybody, this is my first message here. Today I had a problem converting a Long (Int64) to an Integer (Int32). The problem is that my code was always working in 32-bit environments, but when I try THE SAME executable in a 64-bit computer it crashes with a System.OverflowException exception. I've prepared this test code in VS2008 in a new project with default settings: Module Module1 Sub Main() Dim alpha As Long = -1 Dim delta As Integer Try delta = CInt(alpha And UInteger.MaxValue) Console.WriteLine("CINT OK") delta = Convert.ToInt32(alpha And UInteger.MaxValue) Console.WriteLine("Convert.ToInt32 OK") Catch ex As Exception Console.WriteLine(ex.GetType().ToString()) Finally Console.ReadLine() End Try End Sub End Module On my 32-bit setups (Windows XP SP3 32-bit and Windows 7 32-bit) it prints "CINT OK", but in the 64-bit computer (Windows 7 64-bit) that I've tested THE SAME executable it prints the exception name only. Is this behavior documented? I tried to find a reference but failed miserably. For reference I leave the MSIL code too: .method public static void Main() cil managed { .entrypoint .custom instance void [mscorlib]System.STAThreadAttribute::.ctor() = ( 01 00 00 00 ) // Code size 88 (0x58) .maxstack 2 .locals init ([0] int64 alpha, [1] int32 delta, [2] class [mscorlib]System.Exception ex) IL_0000: nop IL_0001: ldc.i4.m1 IL_0002: conv.i8 IL_0003: stloc.0 IL_0004: nop .try { .try { IL_0005: ldloc.0 IL_0006: ldc.i4.m1 IL_0007: conv.u8 IL_0008: and IL_0009: conv.ovf.i4 IL_000a: stloc.1 IL_000b: ldstr "CINT OK" IL_0010: call void [mscorlib]System.Console::WriteLine(string) IL_0015: nop IL_0016: ldloc.0 IL_0017: ldc.i4.m1 IL_0018: conv.u8 IL_0019: and IL_001a: call int32 [mscorlib]System.Convert::ToInt32(int64) IL_001f: stloc.1 IL_0020: ldstr "Convert.ToInt32 OK" IL_0025: call void [mscorlib]System.Console::WriteLine(string) IL_002a: nop IL_002b: leave.s IL_0055 } // end .try catch [mscorlib]System.Exception { IL_002d: dup IL_002e: call void [Microsoft.VisualBasic]Microsoft.VisualBasic.CompilerServices.ProjectData::SetProjectError(class [mscorlib]System.Exception) IL_0033: stloc.2 IL_0034: nop IL_0035: ldloc.2 IL_0036: callvirt instance class [mscorlib]System.Type [mscorlib]System.Exception::GetType() IL_003b: callvirt instance string [mscorlib]System.Type::ToString() IL_0040: call void [mscorlib]System.Console::WriteLine(string) IL_0045: nop IL_0046: call void [Microsoft.VisualBasic]Microsoft.VisualBasic.CompilerServices.ProjectData::ClearProjectError() IL_004b: leave.s IL_0055 } // end handler } // end .try finally { IL_004d: nop IL_004e: call string [mscorlib]System.Console::ReadLine() IL_0053: pop IL_0054: endfinally } // end handler IL_0055: nop IL_0056: nop IL_0057: ret } // end of method Module1::Main I suspect that the instruction that is behaving differently is either conv.ovf.i4 or the ldc.i4.m1/conv.u8 pair. If you know what is going on here please let me know Thanks

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  • selenium and firefox timeout behavior

    - by Md. Reazul Karim
    I am facing this strange timeout behavior. I tried to load some page using: WebDriver drv = new FirefoxDriver(); drv.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS); drv.get(url); String email = ""; try { WebElement aElem = Util.safeFindElementByXpath(drv, "//p[1]/a[1]"); if (aElem != null) { email = aElem.getAttribute("href"); } } catch (Exception e) { } drv.quit(); return email; The safeFindElementByXpath is: static WebElement safeFindElementByXpath(WebDriver driver, String xpath) { try { return driver.findElement(By.xpath(xpath)); } catch (NoSuchElementException e) { return null; } } Now I set the firefox network.http.connection-timeout and network.http.connection-retry-timeout both to 10. Now if I restart the firefox I can see the new values. But if I try to run the above code - the firefox window opens and it waits for a particular website for a long time. Hence I open another tab in the same firefox window and check the values of timeout and find them to be 90 and 250. If I change the values on that same window, the selenium code immediately finishes requesting for the page (ie it goes after the exception block). So the thing is that the same code will work on many sites and I don't know beforehand which site is invalid/down and I was thinking of putting this code in a separate thread and kill the thread after some time from the calling thread. But that is not possible I guess because the child thread has no way to poll anything as it is stuck at page request and can't go to the polling code afterwards. Now the thing is that I want any kind of hack/workaround to accomplish this: try getting the emails for good sites and if there are bad sites just give up after a certain period (press the panic button sorta thing). Thanks

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  • Loading user controls programatically into a placeholder (asp.net)

    - by Phil
    In my .aspx page I have; <%@ Page Language="VB" AutoEventWireup="false" CodeFile="Default.aspx.vb" Inherits="_Default" AspCompat="True" %> <%@ Register src="Modules/Content.ascx" tagname="Content" tagprefix="uc1" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> </head> <body> <form id="form1" runat="server"> <div> <asp:PlaceHolder ID="Modulecontainer" runat="server"></asp:PlaceHolder> </div> </form> </body> </html> In my aspx.vb I have; Try Dim loadmodule As UserControl loadmodule = Me.LoadControl("~/modules/content.ascx") Modulecontainer.Controls.Add(loadmodule) Catch ex As Exception Response.Write(ex.ToString & "<br />") End Try The result is an empty placeholder and no errors. Thanks a lot for any assistance P.S after Fat_Tony's answer I changed the code to; Try Dim loadmodule As ASP.ContentModule loadmodule = CType(LoadControl("~\Modules\Content.ascx"), ASP.ContentModule) Modulecontainer.Controls.Add(loadmodule) Catch ex As Exception Response.Write(ex.ToString & "<br />") End Try But still no results unfortunately.

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  • In Ruby, why is a method invocation not able to be treated as a unit when "do" and "end" is used?

    - by Jian Lin
    The following question is related to the question "Ruby Print Inject Do Syntax". My question is, can we insist on using do and end and make it work with puts or p? This works: a = [1,2,3,4] b = a.inject do |sum, x| sum + x end puts b # prints out 10 so, is it correct to say, inject is an instance method of the Array object, and this instance method takes a block of code, and then returns a number. If so, then it should be no different from calling a function or method and getting back a return value: b = foo(3) puts b or b = circle.getRadius() puts b In the above two cases, we can directly say puts foo(3) puts circle.getRadius() so, there is no way to make it work directly by using the following 2 ways: a = [1,2,3,4] puts a.inject do |sum, x| sum + x end but it gives ch01q2.rb:7:in `inject': no block given (LocalJumpError) from ch01q2.rb:4:in `each' from ch01q2.rb:4:in `inject' from ch01q2.rb:4 grouping the method call using ( ) doesn't work either: a = [1,2,3,4] puts (a.inject do |sum, x| sum + x end) and this gives: ch01q3.rb:4: syntax error, unexpected kDO_BLOCK, expecting ')' puts (a.inject do |sum, x| ^ ch01q3.rb:4: syntax error, unexpected '|', expecting '=' puts (a.inject do |sum, x| ^ ch01q3.rb:6: syntax error, unexpected kEND, expecting $end end) ^ finally, the following version works: a = [1,2,3,4] puts a.inject { |sum, x| sum + x } but why doesn't the grouping of the method invocation using ( ) work in the earlier example? What if a programmer insist that he uses do and end, can it be made to work?

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  • Absolute Centering Not Working in IE

    - by Vikas Ghodke
    I have a div which is centered in parent div, it working on all browser but not in ie, can you help me out with this. JSFIDDLE span.qbg3 { display: block; text-align: center; background: url(http://powerblanket.com/may2014/wp-content/uploads/2014/05/qbg3.png) no-repeat center center; background-size:cover; padding: 50px 20px; color: #fff; font-weight: 400; font-size: 30px; position: relative; margin-top: -20px; min-height: 350px; } span.inqbg3 { max-height: 100px; display: block; text-align: center; color: #fff; font-weight: 400; font-size: 40px; position: absolute; margin: auto; top: 0px; right: 0; left: 0; bottom: 0px; background: rgba(0, 0, 0, 0.5); max-width: 700px; padding: 35px 0; } span.inqbg3 a { color: #fff; }

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  • Elegant solution to retrieve custom date and time?

    - by kefs
    I am currently using a date and time picker to retrieve a user-submitted date and time, and then I set a control's text to the date and time selected. I am using the following code: new DatePickerDialog(newlog3.this, d, calDT.get(Calendar.YEAR), calDT.get(Calendar.MONTH), calDT.get(Calendar.DAY_OF_MONTH)).show(); new TimePickerDialog(newlog3.this, t, calDT.get(Calendar.HOUR_OF_DAY), calDT.get(Calendar.MINUTE), true).show(); optCustom.setText(fmtDT.format(calDT.getTime())); Now, while the above code block does bring up the date and time widgets and sets the text, the code block is being executed in full before the user can select the date.. ie: It brings up the date box first, then the time box over that, and then updates the text, all without any user interaction. I would like the date widget to wait to execute the time selector until the date selection is done, and i would like the settext to execute only after the time widget is done. How is this possible? Or is there is a more elegant solution that is escaping me? Edit: This is the code for DatePickerDialog/TimePickerDialog which is located within the class: DatePickerDialog.OnDateSetListener d=new DatePickerDialog.OnDateSetListener() { public void onDateSet(DatePicker view, int year, int monthOfYear, int dayOfMonth) { calDT.set(Calendar.YEAR, year); calDT.set(Calendar.MONTH, monthOfYear); calDT.set(Calendar.DAY_OF_MONTH, dayOfMonth); //updateLabel(); } }; TimePickerDialog.OnTimeSetListener t=new TimePickerDialog.OnTimeSetListener() { public void onTimeSet(TimePicker view, int hourOfDay, int minute) { calDT.set(Calendar.HOUR_OF_DAY, hourOfDay); calDT.set(Calendar.MINUTE, minute); //updateLabel(); } }; Thanks in advance

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  • Consecutive calls/evaulations in a form?

    - by Dave
    Hey guys, simple question... Working with XLISP to write a program, but I've seemed to run into a simple fundamental problem that I can't seem to work around: perhaps someone has a quick fix. I'm trying to write an if statement who's then-clause evaluates multiple forms and returns the value of the last. In example: (setq POSITION 'DINING-ROOM) (defun LOOK (DIRECTION ROOM) ... ) (defun SETPOS (ROOM) ... ) (defun WHERE () ... ) (defun MOVE (DIRECTION) (if (not(equal nil (LOOK DIRECTION POSITION))) ; If there is a room in that direction ( ; Then-block: Go to that room. Return where you are. (SETPOS (LOOK DIRECTION ROOM)) (WHERE) ) ( ; Else-block: Return error (list 'CANT 'GO 'THERE) ) ) The logical equivalent intended is: function Move (Direction) { if(Look(Direction, Room) != null) { SetPos(Look(Direction,Room)); return Where(); } else { return "Can't go there"; } } (Apologies for the poor web-formatting.) The problem I have is with: ( (SETPOS (LOOK DIRECTION ROOM)) (WHERE) ) I simply want to return the evaluation of WHERE, but I need to execute the SETPOS function first. XLISP doesn't like the extra parentheses: if I remove the outer set, my WHERE list becomes my else (I don't want that). If I remove the sets around SETPOS and WHERE, it treats WHERE like an argument for SETPOS; I also don't want that. So, how do I simply evaluate the first, then the second and then return the values of the last evaluated?

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  • When Creating a Reference for an Object Where from where that class is Loaded?

    - by asela38
    When doing some sample codings with Java I came crosss ClassCast Exception, from where I cast the object to StaticClass. Can any explaing the what has happened here. public void test5() throws Exception { System.out.println(StaticClass.obj); Object newInstance = ClassLoader.getSystemClassLoader().loadClass("com.StaticClass").newInstance(); System.out.println(newInstance.getClass().getDeclaredField("obj").get(newInstance)); Object newInstance2 = new ILoader().loadClass("com//StaticClass.class").newInstance(); System.out.println(newInstance2.getClass().getDeclaredField("obj").get(newInstance2)); StaticClass s = (StaticClass)newInstance2; System.out.println(s.obj); System.out.println(newInstance.getClass().getClassLoader()); System.out.println(newInstance2.getClass().getClassLoader()); } package com; public class StaticClass { public static final Object obj = new Object(); } package com; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; public class ILoader extends ClassLoader { public ILoader() { super(null); } @Override protected Class<?> findClass(String name) throws ClassNotFoundException { File file = new File(name); byte[] bytes = new byte[(int)file.length()]; try { new FileInputStream(file).read(bytes); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return super.defineClass("com.StaticClass",bytes, 0, bytes.length); } } output which was given by last sysout's when the casting part of the code not existed is as belows. sun.misc.Launcher$AppClassLoader@133056f com.ILoader@1ac3c08

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  • hover buttons background image change not working

    - by Brae
    Background I'm trying to make a menu, you hover over the button and the background image shifts its Y position to give you the 'over' effect for each button. CSS .menu {float: left;} .menu span {display: none;} .menu a {display: block; margin: 10px; width: 200px; height: 50px;} #itemA {background: url('images/btnA.png') no-repeat 0 0;} #itemB {background: url('images/btnB.png') no-repeat 0 0;} #itemC {background: url('images/btnC.png') no-repeat 0 0;} #itemD {background: url('images/btnD.png') no-repeat 0 0;} HTML <div class="menu"> <a id="itemA" href="#"><span>AAAAA</span></a> <a id="itemB" href="#"><span>BBBBB</span></a> <a id="itemC" href="#"><span>CCCCC</span></a> <a id="itemD" href="#"><span>DDDDD</span></a> </div> Problem why do none of these work? /*** - test A a.menu:link {background-position: 0 -51px;} a.menu:visited {display: block; margin: 10px; width: 200px; height: 32px;} ***/ /*** - test B a.menu:hover {background-position: 0 -51px;} ***/ /*** - test C .menu a:hover {background-position: 0 -51px;} ***/ /*** - test D .menu:hover a {background-position: 0 -51px;} ***/ /*** - test E a:hover .menu {background-position: 0 -51px;} ***/ Notes images are 200x101px (50px high with a 1px seperator) Question why do none of these work, should any of them work, is there a solution im missing? thanks in advance!

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  • CSS/IE7: The Case of the Extending Background-Image

    - by dmr
    The situation: There a collapsible advanced search box. It is made up of a search box div that contains a boxhead div and a boxbody div. Inside the boxbody div, there is a searchToggle div. When the user clicks "Show/Hide", the display style property of the searchToggle div is toggled between block and none. (The search fields are hidden and the search boxbody gets much smaller). The 2 background-images for the body of the search box are set via the css of the searchBox div and the boxbody div. In IE7, when the searchToggle div is hidden, the background-image from the searchBox div extends on the left more than it should (see Here). It shows up correctly when the display of the searchToggle div is block (see Here). Everything show up correctly, in both cases, in IE8 and FF. The relevant HTML: <div class="searchBox"> <div class="boxhead"> <h2></h2> </div> <div class="boxbody"> <div id="searchToggle" name="searchToggle"> </div> </div> </div> The relevant CSS: .searchBox { margin: 0 auto; width: 700px; background: url(/images/myImageRight-r.gif) no-repeat bottom right; font-size: 100%; text-align: left; overflow: hidden; } .boxbody { margin: 0; padding: 5px 30px 31px; background-image: url(/images/myImageLeft.gif); background-repeat: no-repeat; background-position: left bottom; }

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  • Android - save/restore state of custom class

    - by user1209216
    I have some class for ssh support - it uses jsch internally. I use this class on main activity, this way: public class MainActivity extends Activity { SshSupport ssh = new SshSupport(); ..... @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //Handle events for ssh ssh.eventHandler = new ISshEvents() { @Override public void SshCommandExecuted(SshCommandsEnum commandType, String result) { } //other overrides here } //Ssh operations on gui item click @Override public void onItemClick(AdapterView<?> arg0, View v, int position, long arg3) { if (ssh.IsConnected() == false) { try { ssh.ConnectAsync(/*parameters*/); } catch (Exception e) { e.printStackTrace(); } } try { ssh.ExecuteCommandAsync(SshCommandsEnum.values()[position]); } catch (Exception e) { e.printStackTrace(); } } }); } It works very well. My application connects to ssh, performs all needed operation in background thread and results are reported to gui, via events as shown above. But nothing works after user change device orientation. It's clear for me - activity is re-created and all state is lost. Unfortunately, my SshSupport class object is lost as well. It's pretty easy to store gui state for dynamically changed/added objects (using put/get serializable etc methods). But I have no idea how to prevent my ssh object, ssh connected session being lost. Since my class is not serializable, I can't save it to bundle. Also, even if I make my SshSupport class serializable, jsch objects it uses still are not serializable. So what is the best way to solve this?

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  • a simple program that counts and sums digits. How can I make it work?

    - by user1710386
    So I've to write a simple program(that loops) where you can enter an int and it spews out the number count and the sum of the numbers. Since I am such a tard when it comes to programming, I just scavanged the code online and tried to piece it together. I guess the sum block screws with n, but I am not really sure. Anyway, I would really appreciate it if somebody could point out mistakes and show me how can I make it work. #include <iostream> using namespace std; int main() { while(1) { int i,p,n,sum=0; //sum block cout<<"enter an int: "; cin>>n; { while(n!=0) { p=n % 10; sum+=p; n=n/10; } cout<<"int digit sum: "<<sum <<endl; } { int count = 0; while(n) { n /= 10; ++count; } cout <<"number of digits: " << count << '\n';} } }

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  • Write to PDF using PHP from android device

    - by Brent Mitchell
    I am trying to write to a pdf file on php server. I have sent variables to the server, create the pdf document, then have my phone download the document to view on device. The variables seem not to write on the php file. I have my code below public void postData() { try { Calculate calc = new Calculate(); HttpClient mClient = new DefaultHttpClient(); StringBuilder sb=new StringBuilder("myurl.com/pdf.php"); HttpPost mpost = new HttpPost(sb.toString()); String value = "1234"; List nameValuepairs = new ArrayList(1); nameValuepairs.add(new BasicNameValuePair("id",value)); mpost.setEntity(new UrlEncodedFormEntity(nameValuepairs)); } catch (UnsupportedEncodingException e) { Log.w(" error ", e.toString()); } catch (Exception e) { Log.w(" error ", e.toString()); } } And my php code to write the variable "value" onto the pdf document: //code to reverse the string if($_POST[] != null) { $reversed = strrev($_POST["value"]); $this->SetFont('Arial','u',50); $this->Text(52,68,$reversed); } I am just trying to write the variable in a random spot, but the variable the if statement is always null and I do not know why. Thanks. Sorry if it is a little sloppy.

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  • MidiSystem.getSequencer() returns Audio Device Unavailable

    - by ksemeks
    I've keep having an exception thrown, on and on. When i try to make a new Sequencer object, i keep getting the javax.sound.midi.MidiUnavailableException: Audio Device Unavailable exception. So, here's the code: import javax.sound.midi.*; public class MiniMusicPlayer1 { public static void main(String[] args) { try { Sequencer sequencer = MidiSystem.getSequencer(); sequencer.open(); Sequence seq = new Sequence(Sequence.PPQ, 4); Track track = seq.createTrack(); for (int i = 5; i < 61; i += 4) { track.add(makeEvent(144, 1, i, 100, i)); track.add(makeEvent(128, 1, i, 100, (i+2))); } sequencer.setSequence(seq); sequencer.setTempoInBPM(220); sequencer.start(); } catch (Exception e) { e.printStackTrace(); } } public static MidiEvent makeEvent(int comd, int chan, int one, int two, int tick) { MidiEvent event = null; try { ShortMessage a = new ShortMessage(); a.setMessage(comd, chan, one, two); event = new MidiEvent(a, tick); } catch (Exception e) { e.printStackTrace(); } return event; } } And here's the complete error (at compile): javax.sound.midi.MidiUnavailableException: Audio Device Unavailable at com.sun.media.sound.MixerSynth.implOpen(MixerSynth.java:165) at com.sun.media.sound.AbstractMidiDevice.doOpen(AbstractMidiDevice.java:144) at com.sun.media.sound.AbstractMidiDevice.openInternal(AbstractMidiDevice.java:134) at com.sun.media.sound.AbstractMidiDevice.getReceiverReferenceCounting(AbstractMidiDevice.java:339) at javax.sound.midi.MidiSystem.getReceiver(MidiSystem.java:243) at javax.sound.midi.MidiSystem.getSequencer(MidiSystem.java:442) at javax.sound.midi.MidiSystem.getSequencer(MidiSystem.java:348) at MiniMusicPlayer1.main(MiniMusicPlayer1.java:9) First i was unable to play MIDI files on my pc, but then i got it to work, so now i can play MIDI files, that's okay. I tried even to close every process which uses my sound card, but the error is still there. Anyone can help me?

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