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  • user is being created with Membership.CreateUser and when I pass the line it is being automatically

    - by Assaf
    Hi Guys, I'm trying to create a user using Membership.CreateUser. After I pass the following line: MembershipUser newUser = Membership.CreateUser(_UserName, _Password, _UserName); I check the 'aspnet_Membership' table and I find out that the user is indeed created. At that point I stop the application and I check the table again. Mysteriously the user that has just been created is dissapeared. Does anyone understands what's going on? Thanks a lot, Assaf.

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  • How do I run .class files on windows from command line?

    - by AndrejaKo
    Hi! I'm trying to run .class file from command line. It works when I manually move to the directory it's stored in, but when I try something like this: java C:\Peter\Michael\Lazarus\Main it says it can't find the main class. Is there any solution to this other than making a .jar file (I know that .jar is the best solution, but at this moment isn't the one I'm looking for)?

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  • Is there any "modern" text editor with command-line/minibuffer?

    - by Pedro Morte Rolo
    A command line in a text editor is a wonderful feature. It allows the user to explore the editor's functionality and learn it's shortcuts in a textual way. It's much faster than using the mouse, and it is much easier to memorise "shortcuts" this way. Emacs and VI provide this, though, emacs and vi are not "modern". By "modern", I mean one that is original built to cope with the modern de-facto standards of selecting, copying, pasting, cutting, undoing, redoing and auto-completing. Cream/vi or Emacs/CUA are not valid options, since there are loads of things built over them that conflict with the mentioned stuff. It would be nice if there was an editor that would cope with the modern de-facto standards out-off-the-box, but still provide a command-line/minibuffer to perform/explore the commands and learn its shortcuts. Is there such a thing? I do not intend to use the "modern" term as derrogatory. I love both Emacs and VI, but I hate their keyboard-shortcut historical baggage. When I reffer to de-facto standards, I am not talking about Windows vs Whatever. Kate, gedit, Eclipse, Intelij or Textmate also follow the norm I am talking about and are not Windows editors. Please do not advertise Vim and Emacs, that's not answering the question. I am asking for alternatives. Why don't I like emacs and vi: Emacs: Despite CUA mode, emacs has loads of modes that conflict with this (e.g. slime, ruby-mode, etc...) It would be nice to have something that would work out-off-the-box. VI: I do not like that it is Visual/Insert-based. I do not know how to browse the text-editor's commands. I do not like that it is so much tought for the terminal. I believe that it has the same problem that I mentioned for emacs. This question is starting to look like requirement analysis.. As de-facto standards I mean: Ctrol-XCV for cut-copy-paste Ctrol-A for select-all Contrl-Z for Undo Ctrol-Y for Redo Control-F for Searching Contrl-Space for auto-complete Shift-arrow for selection Control-arrow for word-navigation Alt-Arrow for moving

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  • how do I convert if else to one line if else?

    - by roozbeh heydari
    how do i convert follow code to one line if else if (data.BaseCompareId == 2) report.Load(Server.MapPath("~/Content/StimulReports/MonthGroup.mrt")); else report.Load(Server.MapPath("~/Content/StimulReports/YearGroup.mrt")); i try this code but did not work data.BaseCompareId == 2 ? report.Load(Server.MapPath("~/Content/StimulReports/MonthGroup.mrt")) : report.Load(Server.MapPath("~/Content/StimulReports/YearGroup.mrt"));

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  • Basis for claim that the number of bugs per line of code is constant regardless of the language used

    - by Matt R
    I've heard people say (although I can't recall who in particular) that the number of bugs per line of code is roughly constant regardless of what language is used. What is the research that backs this up? Edited to add: I don't have access to it, but apparently the authors of this paper "asked the question whether the number of bugs per lines of code (LOC) is the same for programs written in different programming languages or not."

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  • CakePHP 1.3.4: EmailComponent error - Undefined property: EmailComponent::$Controller

    - by Kevin S.
    I'm trying to develop an invitation system for my website which runs on CakePHP 1.3.4. I am trying to use the built in EmailComponent to send an email. I'm getting this error (expanded): Notice (8): Undefined property: EmailComponent::$Controller [CORE/cake/libs/controller/components/email.php, line 428] Code | Context */ function _render($content) { $viewClass = $this-Controller-view; $content = array( "", "" ) EmailComponent::_render() - CORE/cake/libs/controller/components/email.php, line 428 EmailComponent::send() - CORE/cake/libs/controller/components/email.php, line 368 UsersController::send_quick_add_email() - APP/controllers/users_controller.php, line 77 UsersController::quick_add() - APP/controllers/users_controller.php, line 104 SinglesResultsController::quick_add() - APP/controllers/singles_results_controller.php, line 63 Dispatcher::_invoke() - CORE/cake/dispatcher.php, line 204 Dispatcher::dispatch() - CORE/cake/dispatcher.php, line 171 [main] - APP/webroot/index.php, line 83 I also get the following, which I can expand if necessary: Notice (8): Trying to get property of non-object [CORE/cake/libs/controller/components/email.php, line 428] Notice (8): Undefined property: EmailComponent::$Controller [CORE/cake/libs/controller/components/email.php, line 433] Notice (8): Trying to get property of non-object [CORE/cake/libs/controller/components/email.php, line 433] Notice (8): Undefined property: View::$webroot [CORE/cake/libs/view/view.php, line 805] Warning (2): Cannot modify header information - headers already sent by (output started at /Applications/MAMP/htdocs/cake/cake/libs/debugger.php:673) [CORE/cake/libs/controller/controller.php, line 746] I think that the EmailComponent object holds a reference to the controller it's being called from. I don't know why it's undefined in this case. Here is the code that fails (specifically, it errors on the call to $this-Email-send()): function send_quick_add_email($email) { if($email) { $this->Email->reset(); $this->Email->to = $email; $this->Email->subject = 'Some subject text'; $this->Email->from = '[email protected]'; $this->Email->template = 'email_template'; $this->set('user', $user); $this->set('token', $token); $this->Email->delivery = 'debug'; $this->Email->send(); } } Ok, for more clarification: The main data I am collecting on the site is results of a game played in meatspace. SinglesResultsController has an action, quick_add, which expects email addresses of people not already registered on the site. If the email addresses aren't associated with Users, UsersController::quick_add is called, which creates an inactive user, and sends an invitation email in UsersController::send_quick_add_email() I think the problem is related to the fact that the email isn't being sent in the first controller initialized (SinglesResultsController). Any thoughts on how to make it work? The Email component is declared at the top of both Controllers.

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  • Am I right in thinking there is no way to put an if statement and an else statement on line in Python?

    - by Louise
    Am I right in thinking I can't put an if-statement and the corresponding else-statement on one line in Python? NB: variable = value1 if condition else value2 is NOT two statements. It's one statement which can take the value of one of two expressions. I want to do something like if condition a=value else b=value Am I right in thinking this requires a full if-else in Python? Like if condition: a=value else: b=value Thanks, Louise

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  • How to setup Android sdk from command-line on headless server ?

    - by Eno
    So far Ive managed to download and install the SDK and its in my PATH. Problem now is that I can't run "android update sdk" since it expects to be connected to a display and Im connected to a remote headless server through ssh (its a build server so there's no desktop env). Is there a command-line option for the android tool that tells it to run without X ?

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  • Hide the Emacs echo area when not in use

    - by Baldur
    The echo area is the line at the bottom of Emacs below the mode line: ~ ~ | | +-----------------------+ |-U:--- mode-line | +-----------------------+ | M-x echo-area | +-----------------------+ Now the mode line is highly customizable while the echo area is more rigid (and unused a lot of the time). The question is pretty simple: is it possible to hide the echo area during inactivity and redisplay it once it needs your attention: ~ ~ ~ ~ | | | | | | +-----------------------+ | | |-U:--- mode-line | +-----------------------+ +-----------------------+ |-U:--- mode-line | | M-x echo-area | +-----------------------+ +-----------------------+ Inactive Active This is similar to the way Google Chrome displays URLs when you hover your mose over a link and the Firefox addon Pentadactyl where the command-line is hidden by default.

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  • Trouble passing a template function as an argument to another function in C++

    - by Darel
    Source of the problem -Accelerated C++, problem 8-5 I've written a small program that examines lines of string input, and tallies the number of times a word appears on a given line. The following code accomplishes this: #include <map> #include <iostream> #include <string> #include <vector> #include <list> #include <cctype> #include <iterator> using std::vector; using std::string; using std::cin; using std::cout; using std::endl; using std::getline; using std::istream; using std::string; using std::list; using std::map; using std::isspace; using std::ostream_iterator; using std::allocator; inline void keep_window_open() { cin.clear(); cout << "Please enter EOF to exit\n"; char ch; cin >> ch; return; } template <class Out> void split(const string& s, Out os) { vector<string> ret; typedef string::size_type string_size; string_size i = 0; // invariant: we have processed characters `['original value of `i', `i)' while (i != s.size()) { // ignore leading blanks // invariant: characters in range `['original `i', current `i)' are all spaces while (i != s.size() && isspace(s[i])) ++i; // find end of next word string_size j = i; // invariant: none of the characters in range `['original `j', current `j)' is a space while (j != s.size() && !isspace(s[j])) ++j; // if we found some nonwhitespace characters if (i != j) { // copy from `s' starting at `i' and taking `j' `\-' `i' chars *os++ = (s.substr(i, j - i)); i = j; } } } // find all the lines that refer to each word in the input map<string, vector<int> > xref(istream& in) // works // now try to pass the template function as an argument to function - what do i put for templated type? //map<string, vector<int> > xref(istream& in, void find_words(vector<string, typedef Out) = split) #LINE 1# { string line; int line_number = 0; map<string, vector<int> > ret; // read the next line while (getline(in, line)) { ++line_number; // break the input line into words vector<string> words; // works // #LINE 2# split(line, back_inserter(words)); // #LINE 3# //find_words(line, back_inserter(words)); // #LINE 4# attempting to use find_words as an argument to function // remember that each word occurs on the current line for (vector<string>::const_iterator it = words.begin(); it != words.end(); ++it) ret[*it].push_back(line_number); } return ret; } int main() { cout << endl << "Enter lines of text, followed by EOF (^Z):" << endl; // call `xref' using `split' by default map<string, vector<int> > ret = xref(cin); // write the results for (map<string, vector<int> >::const_iterator it = ret.begin(); it != ret.end(); ++it) { // write the word cout << it->first << " occurs on line(s): "; // followed by one or more line numbers vector<int>::const_iterator line_it = it->second.begin(); cout << *line_it; // write the first line number ++line_it; // write the rest of the line numbers, if any while (line_it != it->second.end()) { cout << ", " << *line_it; ++line_it; } // write a new line to separate each word from the next cout << endl; } keep_window_open(); return 0; } As you can see, the split function is a template function to handle various types of output iterators as desired. My problem comes when I try to generalize the xref function by passing in the templated split function as an argument. I can't seem to get the type correct. So my question is, can you pass a template function to another function as an argument, and if so, do you have to declare all types before passing it? Or can the compiler infer the types from the way the templated function is used in the body? To demonstrate the errors I get, comment out the existing xref function header, and uncomment the alternate header I'm trying to get working (just below the following commment line.) Also comment the lines tagged LINE 2 and LINE 3 and uncomment LINE 4, which is attempting to use the argument find_words (which defaults to split.) Thanks for any feedback!

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  • How to find the php.ini file used by the command line?

    - by Amokrane
    Hi I need to enable pdo_mysql in my EasyPhp environment, so I went to php.ini file and uncommented the following line: extension=php_pdo_mysql.dll Unfortunately I still have the same problem. I'm using the CLI so I suppose I need to locate the php.ini file used by the CLI. How can I find it? Thank you

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  • Can you authenticate Facebook Graph entirely from command line with Python?

    - by Sebastian
    I'm writing a (tabbed) application for Facebook that requires a background process to run on a server and, periodically, upload images to an album on this application's page. What I'm trying to do is create a script that will: a) authenticate me with the program b) upload an image to a specific album All of this entirely from the command line and completely with the new Graph API. My problem right now is trying to locate the documentation that will allow me to get a token without a pop-up window of sorts. Thoughts?

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