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  • List comprehension from multiple sources in Python?

    - by Noah
    Is it possible to replace the following with a list comprehension? res = [] for a, _, c in myList: for i in c: res.append((a, i)) For example: # Input myList = [("Foo", None, [1, 2, 3]), ("Bar", None, ["i", "j"])] # Output res = [("Foo", 1), ("Foo", 2), ("Foo", 3), ("Bar", "i"), ("Bar", "j")]

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  • python class decorator question?

    - by nsharish
    decorator 1: def dec(f): def wrap(obj, *args, **kwargs): f(obj, *args,**kwargs) return wrap decorator 2: class dec: def __init__(self, f): self.f = f def __call__(self, obj, *args, **kwargs): self.f(obj, *args, **kwargs) A sample class, class Test: @dec def disp(self, *args, **kwargs): print(*args,**kwargs) The follwing code works with decorator 1 but not with decorator 2. a = Test() a.disp("Message") I dont understand why decorator 2 is not working here. Can someone help me with this?

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  • Python: Access dictionary value inside of tuple and sort quickly by dict value

    - by Aquat33nfan
    I know that wasn't clear. Here's what I'm doing specifically. I have my list of dictionaries here: dict = [{int=0, value=A}, {int=1, value=B}, ... n] and I want to take them in combinations, so I used itertools and it gave me a tuple (Well, okay it gave me a memory object that I then used enumerate on so I could loop over it and enumerate gave ma tuple): for (index, tuple) in enumerate(combinations(dict, 2)): and this is where I have my problem. I want to identify which of the two items in the combination has the bigger 'int' value and which has the smaller value and assign them to variables (I'm actually using more than 2 in the combination so I can't just say if tuple[0]['int'] tuple[1]['int'] and do the assignment because I'd have to list this out a bunch of times and that's hard to manage). I was going to assign each 'int' value to a variable, sort it in a list, index the 'int' value in the list by 1, 2, 3, 4, 5 ... etc., then go back and access the dictionary I wanted by the int value and then assign the dictionary to a variable so I knew which was bigger. But I have a big list and lists and variable assignments are resource intensive and this is taking a long time (I had only a little bit of that written and it was taking forever to run). So I was hoping someone knew a fast way to do this. I actually could list out every possible combination of assignmnets using the if/thens but it's just like 5 pages of if/thens and assignments and is hard to read and manage when I want to change it. You've probably gathered this, but I"m new at programming. thx

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  • Python named print?

    - by Mark
    I know it's a really simple question, but I have no idea how to google it. how can I do print '<a href="%s">%s</a>' % (my_url) So that my_url is used twice? I assume I have to "name" the %s and then use a dict in the params, but I'm not sure of the proper syntax? just FYI, I'm aware I can just use my_url twice in the params, but that's not the point :)

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  • Problem with for-loop in python

    - by Protean
    This code is supposed to be able to sort the items in self.array based upon the order of the characters in self.order. The method sort runs properly until the third iteration, unil for some reason the for loop seems to repeat indefinitely. What is going on here? class sorting_class: def __init__(self): self.array = ['ca', 'bd', 'ac', 'ab'] #An array of strings self.arrayt = [] self.globali = 0 self.globalii = 0 self.order = ['a', 'b', 'c', 'd'] #Order of characters self.orderi = 0 self.carry = [] self.leave = [] self.sortedlist = [] def sort(self): for arrayi in self.arrayt: #This should only loop for the number items in self.arrayt. However, the third time this is run it seems to loop indefinitely. print ('run', arrayi) #Shows the problem if self.order[self.orderi] == arrayi[self.globali]: self.carry.append(arrayi) else: if self.globali != 0: self.leave.append(arrayi) def srt(self): self.arrayt = self.array my.sort() #First this runs the first time. while len(self.sortedlist) != len(self.array): if len(self.carry) == 1: self.sortedlist.append(self.carry) self.arrayt = self.leave self.leave = [] self.carry = [] self.globali = 1 self.orderi = 0 my.sort() elif len(self.carry) == 0: if len(self.leave) != 0: #Because nothing matches 'aa' during the second iteration, this code runs the third time" self.arrayt = self.leave self.globali = 1 self.orderi += 1 my.sort() else: self.arrayt = self.array self.globalii += 1 self.orderi = self.globalii self.globali = 0 my.sort() self.orderi = 0 else: #This is what runs the second time. self.arrayt = self.carry self.carry = [] self.globali += 1 my.sort() my = sorting_class() my.srt()

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  • Need help with re for matching and getting the value python

    - by laspal
    Hi, Need help regarding re. file = 'file No.WR79050107006 from files' So what I am trying to do is validate if file string contains WR + 11 digit. result = re.match('^(\S| )*(?P<sr>(\d){11})(\S| )*', file) Its validate only 11 digit but not WR before it. How can I do that? Using re after matching how can I get the match value ( WR79050107006) I can do string find index = file.find('file No.') and then get the value of next 13 char. thanks

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  • Python sorting problem

    - by matt
    I'm sure this is simple but I can't figure it out. I have a list of strings like this(after using sorted on it): Season 2, Episode 1: A Flight to Remember Season 2, Episode 20: Anthology of Interest I Season 2, Episode 2: Mars University Season 2, Episode 3: When Aliens Attack .... Season 3, Episode 10: The Luck of the Fryrish Season 3, Episode 11: The Cyber House Rules Season 3, Episode 12: Insane in the Mainframe Season 3, Episode 1: The Honking Season 3, Episode 2: War Is the H-Word How can I make them sort out properly? (by episode #, ascending)

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  • Make dictionary from list with python

    - by prosseek
    I need to transform a list into dictionary as follows. The odd elements has the key, and even number elements has the value. x = (1,'a',2,'b',3,'c') - {1: 'a', 2: 'b', 3: 'c'} def set(self, val_): i = 0 for val in val_: if i == 0: i = 1 key = val else: i = 0 self.dict[key] = val My solution seems to long, is there a better way to get the same results?

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  • python json_encode throws KeyError exception

    - by MattM
    In a unit test case that I am running, I get a KeyError exception on the 4th json object in the json text below. I went through the sub-objects and found that it was the "cpuid" object that is the offending object, but I am completely at a loss as to what is wrong with the formatting. response = self.app.post( '/machinestats', params=dict(record=self.json_encode([ {"type": "crash", "instance_id": "xxx", "version": "0.2.0", "build_id": "unknown", "crash_text": "Gah!"}, {"type": "machine_info", "machine_info": "I'm awesome.", "version": "0.2.0", "build_id": "unknown", "instance_id": "yyy"}, {"machine_info": "Soup", "crash_text": "boom!", "version": "0.2.0", "build_id": "unknown", "instance_id": "zzz", "type": "crash"}, {"build_id" : "unknown", "cpu_brand" : "intel", "cpu_count" : 4, "cpuid": { "00000000": {"eax" :123,"ebx" :456, "ecx" :789,"edx" :321}, "00000001": {"eax" :123,"ebx" :456, "ecx" :789,"edx" :321}}, "driver_installed" : True, "instance_id" : "yyy", "version" : "0.2.0", "machine_info" : "I'm awesome.", "os_version" : "linux", "physical_memory_mib" : 1024, "product_loaded" : True, "type" : "machine_info", "virtualization_advertised" : True} ])))

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  • crashing out in a while loop python

    - by Edward
    How to solve this error? i want to pass the values from get_robotxya() and get_ballxya() and use it in a loop but it seems that it will crash after awhile how do i fix this? i want to get the values whithout it crashing out of the while loop import socket import os,sys import time from threading import Thread HOST = '59.191.193.59' PORT = 5555 COORDINATES = [] def connect(): globals()['client_socket'] = socket.socket(socket.AF_INET, socket.SOCK_STREAM) client_socket.connect((HOST,PORT)) def update_coordinates(): connect() screen_width = 0 screen_height = 0 while True: try: client_socket.send("loc\n") data = client_socket.recv(8192) except: connect(); continue; globals()['COORDINATES'] = data.split() if(not(COORDINATES[-1] == "eom" and COORDINATES[0] == "start")): continue if (screen_width != int(COORDINATES[2])): screen_width = int(COORDINATES[2]) screen_height = int(COORDINATES[3]) return def get_ballxy(): update_coordinates() ballx = int(COORDINATES[8]) bally = int(COORDINATES[9]) return ballx,bally def get_robotxya(): update_coordinates() robotx = int(COORDINATES[12]) roboty = int(COORDINATES[13]) angle = int(COORDINATES[14]) return robotx,roboty,angle def print_ballxy(bx,by): print bx print by def print_robotxya(rx,ry,a): print rx print ry print a def activate(): bx,by = get_ballxy() rx,ry,a = get_robotxya() print_ballxy(bx,by) print_robotxya(rx,ry,a) Thread(target=update_coordinates).start() while True: activate() this is the error i get:

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  • Python - counting sign changes

    - by dadashek
    I have a list of numbers I am reading left to right. Anytime I encounter a sign change when reading the sequence I want to count it. X = [-3,2,7,-4,1,-1,1,6,-1,0,-2,1] X = [-, +, +, -, +, -, +, +, -, -,-,+] So, in this list there are 8 sign changes. When Item [0] (in this case -3) is negative it is considered a sign change. Also, any 0 in the list is considered [-]. Any help would be greatly appreciated.

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  • Assign to a slice of a Python list from a lambda

    - by Bushman
    I know that there are certain "special" methods of various objects that represent operations that would normally be performed with operators (i.e. int.__add__ for +, object.__eq__ for ==, etc.), and that one of them is list.__setitem, which can assign a value to a list element. However, I need a function that can assign a list into a slice of another list. Basically, I'm looking for the expression equivalent of some_list[2:4] = [2, 3].

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  • python sending incomplete data over socket

    - by tipu
    I have this socket server script, import SocketServer import shelve import zlib class MyTCPHandler(SocketServer.BaseRequestHandler): def handle(self): self.words = shelve.open('/home/tipu/Dropbox/dev/workspace/search/words.db', 'r'); self.tweets = shelve.open('/home/tipu/Dropbox/dev/workspace/search/tweets.db', 'r'); param = self.request.recv(1024).strip() try: result = str(self.words[param]) except KeyError: result = "set()" self.request.send(str(result)) if __name__ == "__main__": HOST, PORT = "localhost", 50007 SocketServer.TCPServer.allow_reuse_address = True server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler) server.serve_forever() And this receiver, from django.http import HttpResponse from django.template import Context, loader import shelve import zlib import socket def index(req, param = ''): HOST = 'localhost' PORT = 50007 s = socket.socket(socket.AF_INET, socket.SOCK_STREAM) s.connect((HOST, PORT)) s.send(param) data = zlib.decompress(s.recv(131072)) s.close() print 'Received', repr(data) t = loader.get_template('index.html') c = Context({ 'foo' : data }) return HttpResponse(t.render(c)) I am sending strings to the receiver that are in the hundreds of kilobytes. I end up only receiving a portion of it. Is there a way that I can fix that so that the whole string is sent?

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  • Python and urllib2: how to make a GET request with parameters

    - by Infinity
    I'm building an "API API", it basically a wrapper for a in house REST web service that the web app will be making a lot of requests to. Some of the web service calls need to be GET rather than post, but passing parameters. Is there a "best practice" way to encode a dictionary into a query string? e.g.: ?foo=bar&bla=blah I'm looking at the urllib2 docs, and it looks like it decides by itself wether to use POST or GET based on if you pass params or not, but maybe someone knows how to make it transform the params dictionary into a GET request. Maybe there's a package for something like this out there? It would be great if it supported keep-alive, as the web server will be constantly requesting things from the REST service. Thanks!

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  • Python New-style Classes and the Super Function

    - by sfjedi
    This is not the result I expect to see: class A(dict): def __init__(self, *args, **kwargs): self['args'] = args self['kwargs'] = kwargs class B(A): def __init__(self, *args, **kwargs): super(B, self).__init__(args, kwargs) print 'Instance A:', A('monkey', banana=True) #Instance A: {'args': ('monkey',), 'kwargs': {'banana': True}} print 'Instance B:', B('monkey', banana=True) #Instance B: {'args': (('monkey',), {'banana': True}), 'kwargs': {}} I'm just trying to get classes A and B to have consistent values set. I'm not sure why the kwargs are being inserted into the args, but I'm to presume I am either calling init() wrong from the subclass or I'm trying to do something that you just can't do. Any tips?

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  • Best practice for string substition with gettext using Python

    - by Malcolm
    Looking for best practice advice on what string substitution technique to use when using gettext(). Or do all techniques apply equally? I can think of at least 3 string techniques: Classic "%" based formatting: "My name is %(name)s" % locals() .format() based formatting: "My name is {name}".format( locals() ) string.Template.safe_substitute() import string template = string.Template( "My name is ${name}" ) template.safe_substitute( locals() ) The advantage of the string.Template technique is that a translated string with with an incorrectly spelled variable reference can still yield a usable string value while the other techniques unconditionally raise an exception. The downside of the string.Template technique appears to be the inability for one to customize how a variable is formatted (padding, justification, width, etc).

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  • Sending http headers with python

    - by Niklas R
    I've set up a little script that should feed a client with html. import socket sock = socket.socket() sock.bind(('', 8080)) sock.listen(5) client, adress = sock.accept() print "Incoming:", adress print client.recv(1024) print client.send("Content-Type: text/html\n\n") client.send('<html><body></body></html>') print "Answering ..." print "Finished." import os os.system("pause") But it is shown as plain text in the browser. Can you please tell what I need to do ? I just can't find something in google that helps me.. Thanks.

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  • python gui events out of order

    - by dave
    from Tkinter import * from tkMessageBox import * class Gui: def __init__(self, root): self.container = Frame(root) self.container.grid() self.inputText = Text(self.container, width=50, height=8) self.outputText = Text(self.container, width=50, height=8, bg='#E0E0E0', state=DISABLED) self.inputText.grid(row=0, column=0) self.outputText.grid(row=0, column=1) self.inputText.bind("<Key>", self.translate) def translate(self, event): input = self.inputText.get(0.0, END) output = self.outputText.get(0.0, END) self.outputText.config(state=NORMAL) self.outputText.delete(0.0, END) self.outputText.insert(INSERT, input) self.outputText.config(state=DISABLED) showinfo(message="Input: %s characters\nOutput: %s characters" % (len(input), len(input))) root = Tk() #toplevel object app = Gui(root) #call to the class where gui is defined root.mainloop() #enter event loop Working on a gui in tkinter I'm a little confused as to the sequence the event handlers are run. If you run the above code you'll hopefully see... 1) Editing the text widget triggers the event handler but it seems to fire it off without registering the actual change, 2) Even when the text widget is cleared (ie, keep pressing BackSpace) it still seems to have a one character length string, 3) The output widget only receives its update when the NEXT event trigger is fired despite the fact the data came on the previous event. Is this just how bindings work in tkinter or am i missing something here? The behaviour i would like when updating the input widget is: 1) Show the change, 2) Enter event handler, 3) Update output widget, 4) Show message box.

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  • A list vs. tuple situation in Python

    - by Alphonse
    Is there a situation where the use of a list leads to an error, and you must use a tuple instead? I know something about the properties of both tuples and lists, but not enough to find out the answer to this question. If the question would be the other way around, it would be that lists can be adjusted but tuples don't.

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  • super() in Python 2.x without args

    - by Slava Vishnyakov
    Trying to convert super(B, self).method() into a simple nice bubble() call. Did it, see below! Is it possible to get reference to class B in this example? class A(object): pass class B(A): def test(self): test2() class C(B): pass import inspect def test2(): frame = inspect.currentframe().f_back cls = frame.[?something here?] # cls here should == B (class) c = C() c.test() Basically, C is child of B, B is child of A. Then we create c of type C. Then the call to c.test() actually calls B.test() (via inheritance), which calls to test2(). test2() can get the parent frame frame; code reference to method via frame.f_code; self via frame.f_locals['self']; but type(frame.f_locals['self']) is C (of course), but not B, where method is defined. Any way to get B?

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  • Working with OAuth on Google with Python

    - by Dan Loewenherz
    I'm having a very frustrating time creating a valid signature for Google's OAuth implementation. I have narrowed it all down to the fact that my signature-generation code has an error of some sort; what it is I have no idea. This is the signature base string in its entirety: GET&https%3A%2F%2Fwww.google.com%2Faccounts%2FOAuthGetAccessToken&oauth_consumer_key%3Ddlosplayground.appspot.com%26oauth_nonce%3D72815d55697cb24301fab03e1f7f1d66%26oauth_signature_method%3DHMAC-SHA1%26oauth_timestamp%3D1274327867%26oauth_token%3D4%252FX2cZ54JuseQbgRwzTBzZ7lqIwqof%26oauth_verifier%3Dihf0F2Fx%252FpnCmwbVQnk2xMre%26oauth_version%3D1.0 The OAuth Playground returns an oauth_signature of gF8qAfWjpdKjKb4KR%2FvA2Gy0vhU%3D. My code gives me ikMpIKJQJ58jseg%2BKPBTecjmYPE%3D, so obviously I'm doing something wrong. Here's my signature generation code (equivalent to that of the standard oauth.py library): binascii.b2a_base64(hmac.new(CONSUMER_SECRET, BASE_STRING, hashlib.sha1).digest())[:-1] Any thoughts?

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