Search Results

Search found 4842 results on 194 pages for 'computation expression'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 17/194 | < Previous Page | 13 14 15 16 17 18 19 20 21 22 23 24  | Next Page >

  • simple method that checks text is email with regular expression

    - by user223863
    Can't believe how difficult this seems to be all I want to is to validate a user inout using javascript to make sure that it is an email address. But can't get it to work: I am using: //validates a regulaer expression Utilities2.prototype.validateEmail = function(stringToValidateArg) { alert('about to check regexp'); var regExpPattern = /^[a-zA-Z0-9._-]+@[a-zA-Z0-9.-]+\.[a-zA-Z]{2,4}$/; alert(regExpPattern.test(stringToValidateArg)); } But this always returns false, any ideas why is it because of the regular expression?

    Read the article

  • Help needed in writing regular expression using TCL

    - by user330727
    Hello Everyone, Just seeking a favour to write a regular expression to match the following set of strings. I want to write an expression which matches all the following strings TCL ( XYZ XZZ XVZ XWZ ) Clue : Starting string is X and Z ending string is same for all the pairs. Only the middle string is differs Y Z V W. My trial: [regexp {^X([Y|Z|V|W]*)Z$}

    Read the article

  • Help needed in writing regular expression -- TCL

    - by user330727
    Hello Everyone, Just seeking a favour to write a regular expression to match the following set of strings. I want to write an expression which matches all the following strings TCL i) ( XYZ XZZ XVZ XWZ ) Clue : Starting string is X and Z ending string is same for all the pairs. Only the middle string is differs Y Z V W. My trial: [regexp {^X([Y|Z|V|W]*)Z$}] I want to write an another regexp which catches/matches only the following string wherever comes ii) (XYZ) My trial: [regexp {^X([Y]*)Z$}]

    Read the article

  • nginx dynamic servername with regular expression doesn't work for co.uk

    - by redn0x
    I'm trying to setup a nginx server which dynamically loads content from a folder for a domain. To do this I'm using regular expressions in the server name like so: server_name ((?<subdomain>.+)\.)?(?<domain>.+)\.(?<tld>.*); This will create a 3 variables for nginx to use later on, for example when using the following url: test.foo.example.com this will evaluate to: $subdomain = test.foo $domain = example $tld = com The problem arises when the co.uk top-level domain is used. In this case when using the url test.foo.example.co.ukit will evaluate to: $subdomain = test.foo.cedira $domain = co $tld = uk How can I edit the regular expression so that it will also work for co.uk?

    Read the article

  • String manipulation of type String substitution in mathematical expression

    - by Peterstone
    Imagine something like exp(49/200)+(x-49/200) I want to pass as argument of the function "roundn" whatever operation that is not a addtion or a subtraction So my expresion became roundn(exp(roundn(49/200,n)),n)+(x - roundn(49/200,n) Well the expression I want to manipulate is this: exp(49/200)+exp(49/200)*(x-49/200)+1/2*exp(49/200)*(x-49/200)^2+1/6*exp(49/200)*(x- 49/200)^3+1/24*exp(49/200)*(x-49/200)^4+1/120*exp(49/200)*(x-49/200)^5+1/720*exp(49/200)*(x-49/200)^6+1/5040*exp(49/200)*(x-49/200)^7+1/40320*exp(49/200)*(x-49/200)^8+1/362880*exp(49/200)*(x-49/200)^9+1/3628800*exp(49/200)*(x-49/200)^10+1/39916800*exp(49/200)*(x-49/200)^11 I´m looking for a method (That include whatever program) not based in lenguage programming, as much batch or somithing like that... Thank you!

    Read the article

  • Regular Expression to replace part of URL in XML file

    - by Richie086
    I need a regular expression in Notepad++ to search/replace a string. My document (xml) has serveral thousand lines that look similar to this: <Url Source="Output/username/project/Content/Volume1VolumeName/TopicFileName.htm" /> I need to replace everything starting from Volume1 to .htm" / to replaced with X's or some other character to mask the actual file names in this file. So the resulting string would look like this after the search/replace was performed: <Url Source="Output/username/project/Content/Volume1XxxxxxXxxx/XxxxxXxxxXxxx.htm" /> I am working with confidential information that I cannot release to people outside of my company, but i need to send an example log file to a 3rd party for troubleshooting purposes. FYI the X's do not need to follow the upper/lower case after the replacement, i was just using different case X's for the hell of it :)

    Read the article

  • Misbehavior in regular expression in VIM

    - by poissonbreaker
    I am having a problem with a regular expression on vim. I have a pattern as follows: http:\/\/\(\w\+\.\?\)\+ [matches http://(AS MANY WORDS FOLLOWED BY DOT OR NOT ENCOUNTERS) e.g. http://wd1.wd2.com] I have a text as follows: http://wd1.wd2.com/wd3 I am trying to make this substitution on it: s/\(http:\/\/\)\(\w\+\.\?\)\+/\1wd4.wd5.com and the result is http://wd4.wd5.com /wd3 (Notice the white space inserted at the end of the replacement) How can I avoid having this inserted space? I am afraid is a bug in the regexp engine but I am not sure.

    Read the article

  • Convert Dynamic to Type and convert Type to Dynamic

    - by Jon Canning
    public static class DynamicExtensions     {         public static T FromDynamic<T>(this IDictionary<string, object> dictionary)         {             var bindings = new List<MemberBinding>();             foreach (var sourceProperty in typeof(T).GetProperties().Where(x => x.CanWrite))             {                 var key = dictionary.Keys.SingleOrDefault(x => x.Equals(sourceProperty.Name, StringComparison.OrdinalIgnoreCase));                 if (string.IsNullOrEmpty(key)) continue;                 var propertyValue = dictionary[key];                 bindings.Add(Expression.Bind(sourceProperty, Expression.Constant(propertyValue)));             }             Expression memberInit = Expression.MemberInit(Expression.New(typeof(T)), bindings);             return Expression.Lambda<Func<T>>(memberInit).Compile().Invoke();         }         public static dynamic ToDynamic<T>(this T obj)         {             IDictionary<string, object> expando = new ExpandoObject();             foreach (var propertyInfo in typeof(T).GetProperties())             {                 var propertyExpression = Expression.Property(Expression.Constant(obj), propertyInfo);                 var currentValue = Expression.Lambda<Func<string>>(propertyExpression).Compile().Invoke();                 expando.Add(propertyInfo.Name.ToLower(), currentValue);             }             return expando as ExpandoObject;         }     }

    Read the article

  • Documentation often ommits to specify which flavour of regular expression to use, so is there a default flavour that we should all be familiar with?

    - by JW01
    Often I come across documentation that says "use a regular expression here" I have to spend quite some time digging around trying to work out which regular expression format they are expecting. As far as I can tell, there are many types of regular expression. But, at my last place of work I was made to feel stupid when I suggested adding some text to our User Documentation to specify the type of regular expression to be used. When someone says "a regular expression" what is the regular expression syntax most people expect and where is it documented? Update: I was prompted to single-out some examples - but no disrespect to these great projects: eregi docs page is not particularly helpful in explaining expected syntax. Nor can I easily work out the syntax expected here if i just land on the page from a search. No explicit mention of the regular expression pattern expected by PatternExpectation() on the SimpleTest page. etc. etc. here is a highly voted SO answer that seems to assume there is only one flavour of regular expressions.

    Read the article

  • Illegal start of expression?

    - by Fraser
    I'm trying to build a simple Android app that increments a number displayed every time a button is pressed, but I can't work out how to fix the "illegal start of expression" error I keep getting. My code: package com.clicker; import android.app.Activity; import android.os.Bundle; import android.view.View; import android.widget.Button; import android.widget.TextView; public class Clicker extends Activity { private int clickerNumber = 0; private TextView clickerText; private Button clickerButton; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); clickerText = (TextView)findViewById(R.id.clickerText); final Button clickerButton = (Button)findViewById(R.id.clickerButton); clickerButton.setOnClickListener(new View.OnClickListener()); { public void onClick(); { clickerNumber = clickerNumber++; clickerText.setText(Integer.toString(clickerNumber)); } } } } And compiler output: compile: [javac] Compiling 2 source files to /home/fraser/Applications/Android/Code/Clicker/bin/classes [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:24: ')' expected [javac] clickerButton.setOnClickListener(new View.OnClickListener(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: illegal start of expression [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: illegal start of expression [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:26: ';' expected [javac] public void onClick(); [javac] ^ [javac] /home/fraser/Applications/Android/Code/Clicker/src/com/clicker/Clicker.java:29: ';' expected [javac] clickerText.setText(Integer.toString(clickerNumber))); [javac] ^ [javac] 5 errors

    Read the article

  • .NET Regular Expression to find actual words in text

    - by Mehdi Anis
    I am using VB .NET to write a program that will get the words from a suplied text file and count how many times each word appears. I am using this regular expression:- parser As New Regex("\w+") It gives me almost 100% correct words. Except when I have words like "Ms Word App file name is word.exe." or "is this a c# statment If(ab?1,0) ?" In such cases I get [word & exe] AND [If, a, b, 1 and 0] as seperate words. it would be nice (for my purpose) that I received word.exe and (If(ab?1,0) as words. I guess \w+ looks for white space, sentence terminating punctuation mark and other punctuation marks to determine a word. I want a similar regular Expression that will not break a word by a punctuation mark, if the punctuation mark is not the end of the word. I think end-of-word can be defined by a trailing WhiteSpace, Sentence terminating Punctuation (you may think of others). if you can suggest some regular expression 9for VB .NET) that will be great help. Thanks.

    Read the article

  • Moq.Mock<T> - how to setup a method that takes an expression

    - by Paul
    I am Mocking my repository interface and am not sure how to setup a method that takes an expression and returns an object? I am using Moq and NUnit Interface: public interface IReadOnlyRepository : IDisposable { IQueryable<T> All<T>() where T : class; T Single<T>(Expression<Func<T, bool>> expression) where T : class; } Test with IQueryable already setup, but don't know how to setup the T Single: private Moq.Mock<IReadOnlyRepository> _mockRepos; private AdminController _controller; [SetUp] public void SetUp() { var allPages = new List<Page>(); for (var i = 0; i < 10; i++) { allPages.Add(new Page { Id = i, Title = "Page Title " + i, Slug = "Page-Title-" + i, Content = "Page " + i + " on page content." }); } _mockRepos = new Moq.Mock<IReadOnlyRepository>(); _mockRepos.Setup(x => x.All<Page>()).Returns(allPages.AsQueryable()); //Not sure what to do here??? _mockRepos.Setup(x => x.Single<Page>() //---- _controller = new AdminController(_mockRepos.Object); }

    Read the article

  • Regular expression, excluding .. in suffix of email addy

    - by user1754700
    This is homework, I've been working on it for a while, I've done lots of reading and feel I have gotten pretty familiar with regex for a beginner. I am trying to find a regular expression for validating/invalidating a list of emails. There are two addresses which are giving me problems, I can't get them both to validate the correct way at the same time. I've gone through a dozen different expressions that work for all the other emails on the list but I can't get those two at the same time. First, the addresses. [email protected] - invalid [email protected] - valid The part of my expression which validates the suffix I originally started with @.+\\.[[a-z]0-9]+ And had a second pattern for checking some more invalid addresses and checked the email against both patterns, one checked for validity the other invalidity but my professor said he wanted it all in on expression. @[[\\w]+\\.[\\w]+]+ or @[\\w]+\\.[\\w]+ I've tried it written many, many different ways but I'm pretty sure I was just using different syntax to express these two expressions. I know what I want it to do, I want it to match a character class of "character+"."character+"+ The plus sign being at least one. It works for the invalid class when I only allow the character class to repeat one time(and obviously the ip doesn't get matched), but when I allow the character class to repeat itself it matches the second period even thought it isn't preceded by a character. I don't understand why.

    Read the article

  • Linq generic Expression in query on "element" or on IQueryable (multiple use)

    - by Bogdan Maxim
    Hi, I have the following expression public static Expression<Func<T, bool>> JoinByDateCheck<T>(T entity, DateTime dateToCheck) where T : IDateInterval { return (entityToJoin) => entityToJoin.FromDate.Date <= dateToCheck.Date && (entityToJoin.ToDate == null || entityToJoin.ToDate.Value.Date >= dateToCheck.Date); } IDateInterval interface is defined like this: interface IDateInterval { DateTime FromDate {get;} DateTime? ToDate {get;} } and i need to apply it in a few ways: (1) Query on Linq2Sql Table: var q1 = from e in intervalTable where FunctionThatCallsJoinByDateCheck(e, constantDateTime) select e; or something like this: intervalTable.Where(FunctionThatCallsJoinByDateCheck(e, constantDateTime)) (2) I need to use it in some table joins (as linq2sql doesn't provide comparative join): var q2 = from e1 in t1 join e2 in t2 on e1.FK == e2.PK where OtherFunctionThatCallsJoinByDateCheck(e2, e1.FromDate) or var q2 = from e1 in t1 from e2 in t2 where e1.FK == e2.PK && OtherFunctionThatCallsJoinByDateCheck(e2, e1.FromDate) (3) I need to use it in some queries like this: var q3 = from e in intervalTable.FilterFunctionThatCallsJoinByDateCheck(constantDate); Dynamic linq is not something that I can use, so I have to stick to plain linq. Thank you Clarification: Initially I had just the last method (FilterFunctionThatCallsJoinByDateCheck(this IQueryable<IDateInterval> entities, DateTime dateConstant) ) that contained the code from the expression. The problem is that I get a SQL Translate exception if I write the code in a method and call it like that. All I want is to extend the use of this function to the where clause (see the second query in point 2)

    Read the article

  • OrderBy Linq.Expression as parameter = (Of Func(Of T,IComparable)) to perform LinqToEntity is not working

    - by NicoJuicy
    I'd like to get this working: Call: (Count & Page are used for pagination, so Count = 20 and Page = 1 for example, for the first 20 values). Sorting should be by name LeverancierService.GetLeveranciers(Function(el) el.Name, Count, Page) Equivalent in c#: LeverancierService.GetLeveranciers(el= el.Name, Count, Page) Method that gives an error (parameters shown above): Public Overridable Function GetAllPaged(orderby As Expression(Of Func(Of T, IComparable)), ByVal Count As Integer, ByVal Page As Integer) As IEnumerable(Of T) Return dbset.OrderBy(orderby).Skip((Page - 1) * Count).Take(Count).ToList() End Function Already tried changing it to this, but it gives the same error: Public Overridable Function GetAllPaged(Of TOrderBy)(orderby As Expression(Of Func(Of T, TOrderBy)), ByVal Count As Integer, ByVal Page As Integer) As IEnumerable(Of T) Return dbset.OrderBy(orderby).Skip((Page - 1) * Count).Take(Count).ToList() End Function Error: Unable to cast the type 'System.String' to type 'System.IComparable'. LINQ to Entities only supports casting Entity Data Model primitive types. Any idea how to do this? Extra info: I'm in a DDD-layered application, so the parameter should stay the same as the called method is an overridden interface (eg. if i change this, i have to do this for 200 times or so, because it's in VB.Net and not in C# (= 1 change) ) I know there is a way to change the expression to a string and then use DLinq (= Dynamic Linq), but that's not how it should be.

    Read the article

  • How to write an R function that evaluates an expression within a data-frame

    - by Prasad Chalasani
    Puzzle for the R cognoscenti: Say we have a data-frame: df <- data.frame( a = 1:5, b = 1:5 ) I know we can do things like with(df, a) to get a vector of results. But how do I write a function that takes an expression (such as a or a > 3) and does the same thing inside. I.e. I want to write a function fn that takes a data-frame and an expression as arguments and returns the result of evaluating the expression "within" the data-frame as an environment. Never mind that this sounds contrived (I could just use with as above), but this is just a simplified version of a more complex function I am writing. I tried several variants ( using eval, with, envir, substitute, local, etc) but none of them work. For example if I define fn like so: fn <- function(dat, expr) { eval(expr, envir = dat) } I get this error: > fn( df, a ) Error in eval(expr, envir = dat) : object 'a' not found Clearly I am missing something subtle about environments and evaluation. Is there a way to define such a function?

    Read the article

  • Linq - reuse expression on child property

    - by user175528
    Not sure if what I am trying is possible or not, but I'd like to reuse a linq expression on an objects parent property. With the given classes: class Parent { int Id { get; set; } IList<Child> Children { get; set; } string Name { get; set; } } class Child{ int Id { get; set; } Parent Dad { get; set; } string Name { get; set; } } If i then have a helper Expression<Func<Parent,bool> ParentQuery() { Expression<Func<Parent,bool> q = p => p.Name=="foo"; } I then want to use this when querying data out for a child, along the lines of: using(var context=new Entities.Context) { var data=context.Child.Where(c => c.Name=="bar" && c.Dad.Where(ParentQuery)); } I know I can do that on child collections: using(var context=new Entities.Context) { var data=context.Parent.Where(p => p.Name=="foo" && p.Childen.Where(childQuery)); } but cant see any way to do this on a property that isnt a collection. This is just a simplified example, actually the ParentQuery will be more complex and I want to avoid having this repeated in multiple places as rather than just having 2 layers I'll have closer to 5 or 6, but all of them will need to reference the parent query to ensure security.

    Read the article

  • java phone number validation....

    - by user69514
    Here is my problem: Create a constructor for a telephone number given a string in the form xxx-xxx-xxxx or xxx-xxxx for a local number. Throw an exception if the format is not valid. So I was thinking to validate it using a regular expression, but I don't know if I'm doing it correctly. Also what kind of exception would I have to throw? Do I need to create my own exception? public TelephoneNumber(String aString){ if(isPhoneNumberValid(aString)==true){ StringTokenizer tokens = new StringTokenizer("-"); if(tokens.countTokens()==3){ areaCode = Integer.parseInt(tokens.nextToken()); exchangeCode = Integer.parseInt(tokens.nextToken()); number = Integer.parseInt(tokens.nextToken()); } else if(tokens.countTokens()==2){ exchangeCode = Integer.parseInt(tokens.nextToken()); number = Integer.parseInt(tokens.nextToken()); } else{ //throw an excemption here } } } public static boolean isPhoneNumberValid(String phoneNumber){ boolean isValid = false; //Initialize reg ex for phone number. String expression = "(\\d{3})(\\[-])(\\d{4})$"; CharSequence inputStr = phoneNumber; Pattern pattern = Pattern.compile(expression); Matcher matcher = pattern.matcher(inputStr); if(matcher.matches()){ isValid = true; } return isValid; } Hi sorry, yes this is homework. For this assignments the only valid format are xxx-xxx-xxxx and xxx-xxxx, all other formats (xxx)xxx-xxxx or xxxxxxxxxx are invalid in this case. I would like to know if my regular expression is correct

    Read the article

  • NHibernate Criteria - How to filter on combination of properties

    - by DavGarcia
    I needed to filter a list of results using the combination of two properties. A plain SQL statement would look like this: SELECT TOP 10 * FROM Person WHERE FirstName + ' ' + LastName LIKE '%' + @Term + '%' The ICriteria in NHibernate that I ended up using was: ICriteria criteria = Session.CreateCriteria(typeof(Person)); criteria.Add(Expression.Sql( "FirstName + ' ' + LastName LIKE ?", "%" + term + "%", NHibernateUtil.String)); criteria.SetMaxResults(10); It works perfectly, but I'm not sure if it is the ideal solution since I'm still learning about NHibernate's Criteria API. What are the recommended alternatives? Is there something besides Expression.Sql that would perform the same operation? I tried Expression.Like but couldn't figure out how to combine the first and last names. Should I map a FullName property to the formula "FirstName + ' ' + LastName" in the mapping class? Should I create a read only FullName property on the domain object then map it to a column?

    Read the article

  • Varnish VCL - Regular Expression Evaluation

    - by Hugues ALARY
    I have been struggling for the past few days with this problem: Basically, I want to send to a client browser a cookie of the form foo[sha1oftheurl]=[randomvalue] if and only if the cookie has not already been set. e.g. If a client browser requests "/page.html", the HTTP response will be like: resp.http.Set-Cookie = "foo4c9ae249e9e061dd6e30893e03dc10a58cc40ee6=ABCD;" then, if the same client request "/index.html", the HTTP response will contain a header: resp.http.Set-Cookie = "foo14fe4559026d4c5b5eb530ee70300c52d99e70d7=QWERTY;" In the end, the client browser will have 2 cookies: foo4c9ae249e9e061dd6e30893e03dc10a58cc40ee6=ABCD foo14fe4559026d4c5b5eb530ee70300c52d99e70d7=QWERTY Now, that, is not complicated in itself. The following code does it: import digest; import random; ##This vmod does not exist, it's just for the example. sub vcl_recv() { ## We compute the sha1 of the requested URL and store it in req.http.Url-Sha1 set req.http.Url-Sha1 = digest.hash_sha1(req.url); set req.http.random-value = random.get_rand(); } sub vcl_deliver() { ## We create a cookie on the client browser by creating a "Set-Cookie" header ## In our case the cookie we create is of the form foo[sha1]=[randomvalue] ## e.g for a URL "/page.html" the cookie will be foo4c9ae249e9e061dd6e30893e03dc10a58cc40ee6=[randomvalue] set resp.http.Set-Cookie = {""} + resp.http.Set-Cookie + "foo"+req.http.Url-Sha1+"="+req.http.random-value; } However, this code does not take into account the case where the Cookie already exists. I need to check that the Cookie does not exists before generating a random value. So I thought about this code: import digest; import random; sub vcl_recv() { ## We compute the sha1 of the requested URL and store it in req.http.Url-Sha1 set req.http.Url-Sha1 = digest.hash_sha1(req.url); set req.http.random-value = random.get_rand(); set req.http.regex = "abtest"+req.http.Url-Sha1; if(!req.http.Cookie ~ req.http.regex) { set req.http.random-value = random.get_rand(); } } The problem is that Varnish does not compute Regular expression at run time. Which leads to this error when I try to compile: Message from VCC-compiler: Expected CSTR got 'req.http.regex' (program line 940), at ('input' Line 42 Pos 31) if(req.http.Cookie !~ req.http.regex) { ------------------------------##############--- Running VCC-compiler failed, exit 1 VCL compilation failed One could propose to solve my problem by matching on the "abtest" part of the cookie or even "abtest[a-fA-F0-9]{40}": if(!req.http.Cookie ~ "abtest[a-fA-F0-9]{40}") { set req.http.random-value = random.get_rand(); } But this code matches any cookie starting by 'abtest' and containing an hexadecimal string of 40 characters. Which means that if a client requests "/page.html" first, then "/index.html", the condition will evaluate to true even if the cookie for the "/index.html" has not been set. I found in bug report phk or someone else stating that computing regular expressions was extremely expensive which is why they are evaluated during compilation. Considering this, I believe that there is no way of achieving what I want the way I've been trying to. Is there any way of solving this problem, other than writting a vmod? Thanks for your help! -Hugues

    Read the article

  • Pass variable to regular expression pattern string in jquery

    - by phil
    Is that possible to pass variable into regular expression pattern string in jquery ( or javascript)? For example, I want to validate a zip code input field every time while user type in a character by passing variable i to the regular expression pattern. How to do it right? $('#zip').keyup( function(){ var i=$('#zip').val().length for ( i; i<=5; i++){ var pattern=/^[0-9]{i}$/; if ( !pattern.test( $('#zip').val() ) ) {$('#zip_error').css('display','inline');} else {$('#zip_error').css('display','none');} } })

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 13 14 15 16 17 18 19 20 21 22 23 24  | Next Page >