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  • how to append a string to next line in perl

    - by tprayush
    hi all , i have a requirement like this.. this just a sample script... $ cat test.sh #!/bin/bash perl -e ' open(IN,"addrss"); open(out,">>addrss"); @newval; while (<IN>) { @col_val=split(/:/); if ($.==1) { for($i=0;$i<=$#col_val;$i++) { print("Enter value for $col_val[$i] : "); chop($newval[$i]=<STDIN>); } $str=join(":"); $_="$str" print OUT; } else { exit 0; } } close(IN); close(OUT); ' when i run this scipt... $ ./test.sh Enter value for NAME : abc Enter value for ADDRESS : asff35 Enter value for STATE : XYZ Enter value for CITY : EIDHFF Enter value for CONTACT : 234656758 $ cat addrss NAME:ADDRESS:STATE:CITY:CONTACT abc:asff35:XYZ:EIDHFF:234656758 when ran it second time $ cat addrss NAME:ADDRESS:STATE:CITY:CONTACT abc:asff35:XYZ:EIDHFF:234656758ioret:56fgdh:ghdgh:afdfg:987643221 ## it is appended in the same line... i want it to be added to the next line..... NOTE: i want to do this by explitly using the filehandles in perl....and not with redirection operators in shell. please help me!!!

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  • Controlling the alpha of a UIImageView with Slider ..Can' t get it

    - by user1824839
    first i' d like to say this Forum was really helpfull for me that just started coding some weeks ago .. I succeed to do a quite nice app for the moment , than, but i m stuck on this : HOW COULD I CONTROL THE ALPHA OF A UIIMAGEVIEW , WITH A SLIDER EMBEDED IN ANOTHER VIEW ??? ; Basically i' like to do like the alpha slider of this : http://www.edumobile.org/iphone/how-to-make-an-app-2/controlling-a-uiviews-properties-for-ipad/ , but for a UIImageView. I promised i searched for hours , and didnt find how to do it ... Could someone have some minutes to give me ideas ?? Sorry for my poor english too. Thanks if you can. L. The resume of the link i posted, only focussing on the alpha property would be : ( considering a UIView ( View ) embeded in a ViewController ( ViewController ): enter code here ----View.h----- @interface View : UIView @property ( nonatomic, assign ) CGFloat alpha; @end enter code here ----View.m---- @implementation View @synthesize alpha; ?} @end enter code here ------ViewController.h----- import "View.h" @interface ViewController : UIViewController @property (nonatomic, strong) IBOutlet View *view; ?- (IBAction)alphaChanged:(UISlider *)sender; @end enter code here -------ViewController.m------ @interface ViewController () @end @implementation ViewController @synthesize view; (View *)view {?     if (!view) {?        view = [[View alloc] init];?    }?    return view;?} enter code here (IBAction)redChanged:(UISlider *)sender? {?    self.circle.alpha = sender.value;?    [self.circle setNeedsDisplay];?} (void)viewDidLoad ?{?    [super viewDidLoad];?         ?    self.circle.alpha = (CGFloat)1;?} (void)didReceiveMemoryWarning? {?  [super didReceiveMemoryWarning];?    @end enter code here

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  • Works for Short Input, Fails for Long Input. How to Solve?

    - by r0ach
    I've this program which finds substring in a string. It works for small inputs. But fails for long inputs. Here's the program: //Find Substring in given String #include <stdio.h> #include <string.h> main() { //Variable Initialization int i=0,j=0,k=0; char sentence[50],temp[50],search[50]; //Gets Strings printf("Enter Sentence: "); fgets(sentence,50,stdin); printf("Enter Search: "); fgets(search,50,stdin); //Actual Work Loop while(sentence[i]!='\0') { k=i;j=0; while(sentence[k]==search[j]) { temp[j]=sentence[k]; j++; k++; } if(strcmp(temp,search)==0) break; i++; } //Output Printing printf("Found string at: %d \n",k-strlen(search)); } Works for: Enter Sentence: good evening Enter Search: evening Found string at 6 Fails for: Enter Sentence: dear god please make this work Enter Search: make Found string at 25 Which is totally wrong. Can any expert find me a solution? P.S: This is kinda like reinventing the wheel since strstr() has this functionality. But I'm trying for a non-library way of doing it.

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  • SCCM 2007 Collections per OU

    - by VirtualizeIT
    Recently I wanted to create our SCCM collections setup as our Active Directory structure. I finally figured out how to create collections per OU of the domain. I decided to create a simple tutorial that may help other IT professionals the steps to complete this task.   1. Open the ConfigMgr and navigation to the collections. To navigate to the collections go to Site Database>Computer Management>Collections. 2. In the ‘Collections’ right-click and select New Collections. Then it will pop up a Wizards so you can enter the name of the collection and any notes that you may want to add that is associated with the collection.                       3. Next, select the database icon. In the ‘Name’ textbox enter the name of the query. I named mine ‘Query’ just for simplicity sake. After you enter the name select ‘Edit Query Statement…’ 4. Select the ‘Criteria’ tab 5. Select the icon that looks like a sun. 6. At this point you should see a dialog box like this…                     7. Next, click the ‘select’ button. 8. Under the ‘Attribute class’ scroll through until you see ’System Resource’ and for the ‘Attribute"’ scroll through you see ‘System OU Name’. It should look something like this…                 9. After that select OK. 10. In the ‘Value’ textbox enter the string that is associated with the OU in your domain. NOTE: If you don’t know your string name for your OU you can simply go to “Active Directory Users and Computers” and right-click on the OU and select properties. In the ‘object’ tab you should see the string under the ‘Canonical name of object”. That is the string that you put in the ‘Value’ text box. 11. After you enter the OU string name press OK>OK>OK>NEXT>NEXT>FINISH.   That’s it!   I hope this tutorial has help you understand how to create a collection through your OU structure.

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  • Preventing Users From Copying Text From and Pasting It Into TextBoxes

    Many websites that support user accounts require users to enter an email address as part of the registration process. This email address is then used as the primary communication channel with the user. For instance, if the user forgets her password a new one can be generated and emailed to the address on file. But what if, when registering, a user enters an incorrect email address? Perhaps the user meant to enter [email protected], but accidentally transposed the first two letters, entering [email protected]. How can such typos be prevented? The only foolproof way to ensure that the user's entered email address is valid is to send them a validation email upon registering that includes a link that, when visited, activates their account. (This technique is discussed in detail in Examining ASP.NET's Membership, Roles, and Profile - Part 11.) The downside to using a validation email is that it adds one more step to the registration process, which will cause some people to bail out on the registration process. A simpler approach to lessening email entry errors is to have the user enter their email address twice, just like how most registration forms prompt users to enter their password twice. In fact, you may have seen registration pages that do just this. However, when I encounter such a registration page I usually avoid entering the email address twice, but instead enter it once and then copy and paste it from the first textbox into the second. This behavior circumvents the purpose of the two textboxes - any typo entered into the first textbox will be copied into the second. Using a bit of JavaScript it is possible to prevent most users from copying text from one textbox and pasting it into another, thereby requiring the user to type their email address into both textboxes. This article shows how to disable cut and paste between textboxes on a web page using the free jQuery library. Read on to learn more! Read More >Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Indefinite loops where the first time is different

    - by George T
    This isn't a serious problem or anything someone has asked me to do, just a seemingly simple thing that I came up with as a mental exercise but has stumped me and which I feel that I should know the answer to already. There may be a duplicate but I didn't manage to find one. Suppose that someone asked you to write a piece of code that asks the user to enter a number and, every time the number they entered is not zero, says "Error" and asks again. When they enter zero it stops. In other words, the code keeps asking for a number and repeats until zero is entered. In each iteration except the first one it also prints "Error". The simplest way I can think of to do that would be something like the folloing pseudocode: int number = 0; do { if(number != 0) { print("Error"); } print("Enter number"); number = getInput(); }while(number != 0); While that does what it's supposed to, I personally don't like that there's repeating code (you test number != 0 twice) -something that should generally be avoided. One way to avoid this would be something like this: int number = 0; while(true) { print("Enter number"); number = getInput(); if(number == 0) { break; } else { print("Error"); } } But what I don't like in this one is "while(true)", another thing to avoid. The only other way I can think of includes one more thing to avoid: labels and gotos: int number = 0; goto question; error: print("Error"); question: print("Enter number"); number = getInput(); if(number != 0) { goto error; } Another solution would be to have an extra variable to test whether you should say "Error" or not but this is wasted memory. Is there a way to do this without doing something that's generally thought of as a bad practice (repeating code, a theoretically endless loop or the use of goto)? I understand that something like this would never be complex enough that the first way would be a problem (you'd generally call a function to validate input) but I'm curious to know if there's a way I haven't thought of.

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  • Writing to a xml file in java

    - by user243680
    import java.io.*; import javax.xml.parsers.*; import javax.xml.transform.*; import javax.xml.transform.dom.*; import javax.xml.transform.stream.*; import org.w3c.dom.*; public class CreatXMLFile { public static void main(String[] args) throws Exception { BufferedReader bf = new BufferedReader(new InputStreamReader(System.in)); // System.out.print("Enter number to add elements in your XML file: "); // String str = bf.readLine(); int no=2; // System.out.print("Enter root: "); String root = "SMS"; DocumentBuilderFactory documentBuilderFactory =DocumentBuilderFactory.newInstance(); DocumentBuilder documentBuilder =documentBuilderFactory.newDocumentBuilder(); Document document = documentBuilder.newDocument(); Element rootElement = document.createElement(root); document.appendChild(rootElement); // for (int i = 1; i <= no; i++) // System.out.print("Enter the element: "); // String element = bf.readLine(); String element ="Number"; System.out.print("Enter the Number: "); String data = bf.readLine(); Element em = document.createElement(element); em.appendChild(document.createTextNode(data)); rootElement.appendChild(em); String element1 ="message"; System.out.print("Enter the SMS: "); String data1 = bf.readLine(); Element em1 = document.createElement(element1); em1.appendChild(document.createTextNode(data1)); rootElement.appendChild(em1); TransformerFactory transformerFactory = TransformerFactory.newInstance(); Transformer transformer = transformerFactory.newTransformer(); DOMSource source = new DOMSource(document); StreamResult result = new StreamResult(System.out); transformer.transform(source, result); } } i am working on the above code and it gives the following output run: Enter the Number: 768678 Enter the SMS: ytu <?xml version="1.0" encoding="UTF-8" standalone="no"?><SMS><Number>768678</Number><message>ytu</message></SMS>BUILD SUCCESSFUL (total time: 8 seconds) Now i want to write the output generated(<?xml version="1.0" encoding="UTF-8" standalone="no"?><SMS><Number>768678</Number><message>ytu</message></SMS>) to a XML file on the hard disk.How do i do it?

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  • Multiple choice test GUI with serialization of Q&A

    - by Bobby
    I'm working on a project for school in Java programming. I need to design a GUI that will take in questions and answers and store them in a file. It should be able to contain an unlimited number of questions. We have covered binary I/O. How do I write the input they give to a file? How would I go about having them add multiple questions from this GUI? package multiplechoice; import java.awt.*; import javax.swing.*; public class MultipleChoice extends JFrame { public MultipleChoice() { /* * Setting Layout */ setLayout(new GridLayout(10,10)); /* * First Question */ add(new JLabel("What is the category of the question?: ")); JTextField category = new JTextField(); add(category); add(new JLabel("Please enter the question you wish to ask: ")); JTextField question = new JTextField(); add(question); add(new JLabel("Please enter the correct answer: ")); JTextField correctAnswer = new JTextField(); add(correctAnswer); add(new JLabel("Please enter a reccomended answer to display: ")); JTextField reccomendedAnswer = new JTextField(); add(reccomendedAnswer); add(new JLabel("Please enter a choice for multiple choice option " + "A")); JTextField A = new JTextField(); add(A); add(new JLabel("Please enter a choice for multiple choice option " + "B")); JTextField B = new JTextField(); add(B); add(new JLabel("Please enter a choice for multiple choice option " + "C")); JTextField C = new JTextField(); add(C); add(new JLabel("Please enter a choice for multiple choice option " + "D")); JTextField D = new JTextField(); add(D); add(new JButton("Compile Questions")); add(new JButton("Next Question")); } public static void main(String[] args) { /* * Creating JFrame to contain questions */ FinalProject frame = new FinalProject(); // FileOutputStream output = new FileOutputStream("Questions.dat"); JPanel panel = new JPanel(); // button.setLayout(); // frame.add(panel); panel.setSize(100,100); // button.setPreferredSize(new Dimension(100,100)); frame.setTitle("FinalProject"); frame.setSize(600, 400); frame.setLocationRelativeTo(null); // Center the frame frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setVisible(true); } }

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  • Alias/shortcut in windows explorer address bar

    - by Stan
    The question comes from when opening 'Run' in start menu (windows key+R) and enter system32 will open up an explorer and directly go to C:\WINDOWS\system32. Q1: how to make my own alias, so when I enter photos, it brings me to c:\photos Q2: Is there any way to use alias in windows explorer address bar similar to that? Say enter photos in address bar and go to c:\photos Thanks

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  • DNS add www.domain.dyndns.org record

    - by Darxis
    My config is a DNS Server on Windows Server 2008 R2. My domain is on dyndns.org dynamic IP service. This server is a DNS server and a WebServer with IIS. When someone from outside network enter the site "http://domain.dyndns.org" within a webbrowser it is ok, but when someone try to enter "http://www.domain.dyndns.org" it doesn't find any website. So I would like to add a "www." record to my DNS. I did this: Added a A-Type record pointing to my server's local IP. Added a CNAME-Type record named "www" pointing to "domain.dyndns.org." Now I can enter the "www.domain.dyndns.org" from internal network, and it works, but when I enter this address from outside it doesn't work.

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  • Making a cracked or activated windows uncracked

    - by ugurcode
    I have a pc which has windows 7 license but I installed windows from an image i downloaded and it is already activated. for validating genuine microsoft, i need to entet my own product key but the necessary activation tools do not exist in my windows folder. What do? I googled stuff but because the keywords are too broad I couldn't find a useful tool DAZ doesn't work, activation button doesn't show up. When I enter my original key to Windows Anytime Upgrade, I get this error When I attempt using slmgr, I get this error I used sfc /scannow Now slmgr is existing, I entered slmgr.vbs -ipk XXXXX-XXXXX-XXXXX-XXXXX-XXXXX (replacing X es with the cd key) the operation successful. Now I have installed Microsoft Security essentials, which means the problem is solved. Main steps are here open cmd enter Enter "sfc /scannow" enter slmgr.vbs -ipk XXXXX-XXXXX-XXXXX-XXXXX-XXXXX Success

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  • Apache server in raspberry PI not visible from outside( public IP)

    - by Kronos
    I have made a fresh install of Arch Linux ARM into a Raspberry PI and I mounted there a LAMP, all fresh. I have another Arch(x86) in my laptop with Apache also there, and as far as I know, two web servers cannot run in the same network segment so, the problem is as follows. I my laptop, having Apache running, if I enter via the public ip of my network everything turns ok and I can see my website but, (obviously turning this server down) if I enter from the public IP with the Apache running in the raspberry pi( yes, only that Apache running) i cannot see my website in there. Also, if I access via local network it is a normal success, I can see my website. So, I can enter my raspberry website only via local but in my other web server i can enter it via local and public. I have the same conf files in both of them so what is the difference? I was planning in making the rpi as a development server. Thanks in advance

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  • Powershell Version

    - by NItin
    Everytime I try to run a Enter-PSSession -ComputerName name, I am logged on to version 1.0 even tought 2.0 is installed. Being the powershell newbie, I looked into the registry in HKLM\SOftWare\Microsoft\PowerShell\1\PowerShellEngine I see these registries http://yfrog.com/gzo5s8j Unfortunately I am unable to change it to syswow64 directory. Nor remove the 1.0 in compatability Am I doing something wrong? http://yfrog.com/kgyavsj I just want is PSH v2 when I enter remotely (Enter-PSSession) Any and all help is appreciated

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  • Bit of python help

    - by user42780
    I've tried to get this to work, but it just freezes. It should display a pyramid, but all it does is.. halts. from graphics import * valid_colours = ['red', 'blue', 'yellow', 'green'] colour = ['', '', ''] while True: colour[0] = raw_input("Enter your first colour: ") colour[1] = raw_input("Enter your second colour: ") colour[2] = raw_input("Enter your third colour: ") if ((colour[0] and colour[1] and colour[2]) in valid_colours): break while True: width = raw_input("Enter a width between 2-7: ") if width.isdigit(): if (int(width) <= 7 and int(width) >= 2): break width = int(width) win = GraphWin("My Mini Project ", 1000, 1000) # 1000 \ 20 = 50 win.setCoords(0 , 0 , 20, 20) p1 = [0, 2] while width > 0: p = [1, 3] loopWidth = 0 while loopWidth < width: loopWidth = loopWidth + 1 c = 0 while c <= 10: c = c + 1 if c % 2: colour = "white" else: colour = "red" rectangle = Rectangle(Point(p[0],p1[0]), Point(p[1], p1[1])) rectangle.setFill(colour) rectangle.setOutline("black") rectangle.draw(win) p[0] = p[0] + 0.2 p1[0] = p1[0] + 0.2 p[0] = p[0] - 2 p1[0] = p1[0] - 2 p[0] = p[0] + 2 p[1] = p[1] + 2 width = width - 1 p1[0] = p1[0] + 2 p1[1] = p1[1] + 2

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  • SSH sometimes screws up connection when terminal overflows?

    - by SeveQ
    I've got a problem with SSH on a Debian Lenny based server (it's a vHost within a Xen environment, booted on a Xen kernel). I hope someone can help me with this. The SSH connection seems somehow getting screwed up frequently when the terminal overflows (new lines beyond the bottom of the terminal, usually forcing it to scroll). The connection gets lost but not regularly disconnected. It nearly always happens when I do the following: an existing SSH connection gets disconnected (regularly) I order putty to reestablish the connection login-prompt appears at the very bottom of the putty terminal window I enter my login-name, press the enter key I'm asked for the password, I enter it, press the enter key and BOOM! Nothing more happens. I have to reconnect again. So it is reproducable. I'm not totally sure if the connection crashes before or after I enter the password. Furthermore it also happens when there is much text to be displayed (for example when I compile something or do an ls -l on a directory with many entries). Using 'screen', however, helps to reduces the frequency of occurence but doesn't solve the problem completely. It's occurence is independent from which terminal software I use. I mostly use putty but it also happens with other clients. I certainly hope somebody can help me solving this problem. Thanks in advance! //edit: I've just made a Wireshark trace of the ssh connection and there is nothing, I repeat, nothing different between the working and the failing connection (at least aside from frame numbers, ports and times that obviously can't be equal). This leads me to the assumption that the error has to happen on the server's side.

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  • Where are Credentials stored for Network Drives on WinXP?

    - by Tom Tresansky
    I have a drive mapped to a folder on a remote machine that I connect to using the Cisco VPN client. The password to the Windows account I use on that remote machine has changed. I had stored the username/password locally, using Window's remember my password feature, so I wouldn't have to enter it every time (the enter user/password login dialog used to appear each time I attempted to open the remote folder, and I would have to look up and enter my credentials). The password to that remote Windows account has changed. Now, I am no longer prompted to enter a user name / password, but instead, upon trying to open the remote folder, receive a message: unknown user name or bad password. How do I view and change these stored credentials?

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  • Ubuntu Server login not recognizing the keyboard after entering username.

    - by Jeff Malewski
    I'm having similar issues with logging into ubuntu server. chief problem is that once I enter my user name & hit enter, I can't enter anything ffor my password - it won't accept any keystrokes until I press Ctrl+any key. Once I've pressed Ctrl+ any key, I'm able to type again, but have never been able to enter any more than 3 characters before the 60 sec time limit. This problem is present on fresh installs of both 10.04 & 9.10. Part of the problem is lkely to be my antique pc which is an old Emachines Trigems I850 based mbd and an equally ancient Nvidia 4x AGP video card. Initially I was going to install Ubuntu 10.10, but with ORCA running with both screen reader and full screen magnification crashed the system & smoked a stick of Rambus memory. Is there any fix to this problem? Jeff

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  • Citrix XenApp application does not have keyboard focus when launched

    - by Jason Pearce
    On new or existing Citrix XenApp 4.5 servers, I am having problems streaming the Allscripts Pro EHR application via the XenApp web interface. When users launch the application via the Citrix XenApp web interface, the application does not have focus, preventing users from typing in their username and password. If they use their mouse to select either the username or password fields, they still cannot enter any text. However, if they do any of the following actions, they can then enter in their username and password and the application runs without problems: Click on the Login button with empty fields. Logon fails but they can then enter their credentials. Minimize the login window and then maximize it. They can then gain keyboard focus to enter their credentials. What might be preventing this particular application from having focus when it launches?

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  • How do you open a folder in OSX using the keyboard?

    - by Daniel T.
    On Windows, pressing enter when you highlight on a folder in Windows Explorer will open that folder. On OSX, pressing enter when you highlight a folder edits the folder's name (like F2 in Windows). Is there a keyboard shortcut to do the same thing on Windows, so that you'll open the folder? It doesn't have to be enter, but I'd like to know if there's another hotkey that does it. The reason why I ask is because I like to navigate through deep folder structures by using the arrow keys for navigation and enter to drill down into them.

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  • How do I print filenames residing on the server? [on hold]

    - by Suhail Gupta
    How do I list files on a server after I make a HTTP connection via telnet with that server ? I tried establishing connection like : As I push enter, I enter the following screen : but as I type ls (which is not visible when I write) and press enter, I see this screen : I want to establish connection with the server and try to print the file names residing on the server directory. Note : The server OS is Windows Server 2003 and web-server is Microsoft-IIS/6.0

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  • powershell Read-host does not stop for input

    - by llirik42
    I thought this would be fairly basic, but i'm stuck. I have 3 lines of powershell script in which I want to collect a mailbox name from user input, then create names based on that mailbox name. (later the script proceeds to create the groups in AD, etc) my problem is that when I run all 3 of these lines by pasting them into powershell window, I don't get a change to enter the response to read-host. Instead the script just scrolls through to the next line and uses it as the response for the Read-Host here's the powershell: $name = read-host "enter group name" $groupfull = ($name+'.Full'a) $groupsendas = ($name+'.SendAs') Here's the output: PS C:\Users\kg> $name = read-host "enter group name" enter group name: $groupfull = ($name+'.Full') PS C:\Users\kg> $groupsendas = ($name+'.SendAs') PS C:\Users\kg> Thanks in advance

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  • my HP desktop with Windows Vista wont boot

    - by John
    It continues to loop to a BSOD and I cant get a dos prompt or repair screen, I dont have recovery disks but I have brought up a window, black, with gray title bar that is labeled Edit Boot Options, below that it has Edit Windows boot options for: Windows Vista (TM) Home Premium Path: \WINDOWS\system32\winload.exe Partition:1 Hard Disk: 1549f232 and then it has a place to enter something starting with one of these [ and one or two lines down it has ] what do i enter in this space and is there something i can enter that would help solve my boot up issues

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  • wireless printer - entering WPA - is there a quicker way?

    - by camcam
    I have a wireless printer (Brother DCP-585CW). The wireless setup instruction says I should enter the WPA key to the printer. The key is entered using up and down buttons on the printer. So, I am supposed to enter 64 characters using up and down buttons. To enter 1 character, it takes on average (24+10)/2 = 17 times pressing the button (digits start after 24 letters). So 17*64 = 1088 times. Is there a quicker way to setup a wireless printer? Maybe there is a Windows program that discovers printers connected to computer through USB or Ethernet (my printer has both sockets) and allows to pre-configure it for wireless usage (enter the long WPA key)? Update There is BRAdmin program and it allows to set up almost all wireless settings... almost - all except WPA :(

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  • Vim: auto-comment in new line

    - by padde
    Vim automatically inserts a comment when I start a new line from a commented out line, because I have set formatoptions=tcroql. For example (cursor is *): // this is a comment* and after hitting <Enter> (insert mode) or o (normal mode) i am left with: // this is a comment // * This feature is very handy when writing long multi-line comments, but often I just want a single line comment. Now if I want to end the comment series I have several options: hit <Esc>S hit <BS> three times Both of these afford three keystrokes, taken together with the <Enter> this means four keystrokes for a new line, which I think is too much. Ideally, I would like to just hit <Enter> a second time to be left with: // this is a comment * It is important that the solution will also work with different indentation levels, i.e. int main(void) { // this is a comment* } hit <Enter> int main(void) { // this is a comment // * } hit <Enter> int main(void) { // this is a comment * } I think I have seen this feature in some text editor a few years ago but I do not recall which one it was. Is anyone aware of a solution that will do this for me in Vim? Pointers in the right direction on how to roll my own solution are also very welcome.

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  • Citrix XenApp application does not have keyboard focus when launched

    - by Jason Pearce
    On new or existing Citrix XenApp 4.5 servers, I am having problems streaming the Allscripts Pro EHR application via the XenApp web interface. When users launch the application via the Citrix XenApp web interface, the application does not have focus, preventing users from typing in their username and password. If they use their mouse to select either the username or password fields, they still cannot enter any text. However, if they do any of the following actions, they can then enter in their username and password and the application runs without problems: Click on the Login button with empty fields. Logon fails but they can then enter their credentials. Minimize the login window and then maximize it. They can then gain keyboard focus to enter their credentials. What might be preventing this particular application from having focus when it launches?

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