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  • I am trying to use user-defined functions to print out an A out of stars, but i need help defining m

    - by lm
    def horizline(col): for col in range (col): print("*", end='') print() def vertline(rows, col): for rows in range (rows-2): print ("*", end='') for col in range (col-2): print(' ', end='') print("*") def functionA(width): horizline(width) vertline(width) horizline(width) vertline(width) print() def main(): width=int(input("Please enter a width for the letter: ")) length=int(input("Please enter a lenght for the letter: ")) letter=input("Enter one of the capital letters: A ") if(width>=5 and width<=20): functionA(width) else: print("You have entered an incorrect value") main()

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  • ASP.NET TextBox verses input type="text" behavior

    - by harrije
    I notice with ASP.NET if the server side control TextBox is used with out autopostback it will not submit (or postback) the form when typed text ends with enter, which is different from the behavior for plain old HTML pages. Fine, I can set autopostback to get the behavior I want after the enter key. However, autopostback will also cause submit (or postback) when the typed text does not end with enter but focus has changed (i.e. with tab or mouse click), which again is different from plain old HTML pages. How can I get an ASP.NET page to behave the same as a plain old HTML page with respect to text input regardless of whether enter key or change of focus occurs?

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  • I am trying to use user-defined functions to print out an T out of stars, but i need help shifting t

    - by lm
    I know main() and other parts of the prog are missing, but please help def horizLine(col): for cols in range(col): print("*", end='') print() def line(col): #C,E,F,G,I,L,P,T for col in range(col//2): print("*", end='') print() def functionT(width): horizLine(width) line(width) enter width for the box width = int(input("Enter a width between 5 and 20: ")) letter=input("Enter one of the capital letters: T ") if ((width >= 5 and width <=20)): if letter=="T": functionT(width) else: print() print("Invalid letter!") else: print("You have entered a wrong range for the width!") main()

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  • table cell background color change problem

    - by Mellon
    I work on another guy's code, and I try to change the table cell background color when mouse over the cell, and change back to the original background color when mouse leave. I use the following code: var bgcolor=$(".cell-el").css("background-color") $(".cell-el").hover( function(){ $(this).css("background-color", "#3c3c36")}, //mouse enter, bg-color change function(){ $(this).css("background-color", bgcolor) // mouse leave, bg-color change back }) Things are working fine, EXCEPT that when mouse first time enter the cell, the cell background color is not changed to "#3c3c36", but when mouse leave the cell after first entering and enter in the cell again, the cell's background color changed to "#3c3c36". That's the cell color never change for mouse first enter, after that, everything is working great. What's could be the cause of this problem?

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  • Other test cases for this openFile function?

    - by igor
    I am trying to figure out why my function to open a file is failing this autograder I submit my homework into. What type of input would fail here, I can't think of anything else? Code: bool openFile(ifstream& ins) { char fileName[256]; cout << "Enter board filename: "; cin.getline(fileName,256); cout << endl << fileName << endl; ins.open(fileName); if(!ins) { ins.clear(); cout<<"Error opening file"<<endl; return false; } return true; } Here is output from the 'Autograder' of what my program's output is, and what the correct output is supposed to be (and I do not know what is in the file they use for the input) Autograder output: ******************************************* ***** ***** ***** Your output is: ***** ***** ***** ******************************************* Testing function openFile Enter board filename: test.txt 1 Enter board filename: not a fileName Error opening file 0 ******************************************* ***** ***** ***** Correct Output ***** ***** ***** ******************************************* Testing function openFile Enter board filename: 1 Enter board filename: Error opening file 0

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  • how to get inline javascript to fire with jQuery

    - by lloydphillips
    I have a javascript action on a div (asp.net panel) as an onkeypress attribute. This is the default action button on an asp.net Panel control. It contains the following: onkeypress="javascript:return WebForm_FireDefaultButton(event, 'ctl00_cp1_ucInvoiceSearch_btnSearch')" For some reason when I change my textbox to a jQuery textbox clicking enter no longer fires this div. Why and how can I hook it back up so when I enter text in the textbox and click enter it fires? Lloyd

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  • Newb Question: scanf() in C

    - by riemannliness
    So I started learning C today, and as an exercise i was told to write a program that asks the user for numbers until they type a 0, then adds the even ones and the odd ones together. Here is is (don't laugh at my bad style): #include <stdio.h>; int main() { int esum = 0, osum = 0; int n, mod; puts("Please enter some numbers, 0 to terminate:"); scanf("%d", &n); while (n != 0) { mod = n % 2; switch(mod) { case 0: esum += n; break; case 1: osum += n; } scanf("%d", &n); } printf("The sum of evens:%d,\t The sum of odds:%d", esum, osum); return 0; } My question concerns the mechanics of the scanf() function. It seems that when you enter several numbers at once separated by spaces (eg. 1 22 34 2 8), the scanf() function somehow remembers each distinct numbers in the line, and steps through the while loop for each one respectively. Why/how does this happen? Example interaction within command prompt: - Please enter some numbers, 0 to terminate: 42 8 77 23 11 (enter) 0 (enter) - The sum of evens:50, The sum of odds:111 I'm running the program through the command prompt, it's compiled for win32 platforms with visual studio.

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  • Passing a parameter in a Report's Open Event to a parameter query (Access 2007)

    - by JPM
    Hi there, I would like to know if there is a way to set the parameters in an Access 2007 query using VBA. I am new to using VBA in Access, and I have been tasked with adding a little piece of functionality to an existing app. The issue I am having is that the same report can be called in two different places in the application. The first being on a command button on a data entry form, the other from a switchboard button. The report itself is based on a parameter query that has requires the user to enter a Supplier ID. The user would like to not have to enter the Supplier ID on the data entry form (since the form displays the Supplier ID already), but from the switchboard, they would like to be prompted to enter a Supplier ID. Where I am stuck is how to call the report's query (in the report's open event) and pass the SupplierID from the form as the parameter. I have been trying for a while, and I can't get anything to work correctly. Here is my code so far, but I am obviously stumped. Private Sub Report_Open(Cancel As Integer) Dim intSupplierCode As Integer 'Check to see if the data entry form is open If CurrentProject.AllForms("frmExample").IsLoaded = True Then 'Retrieve the SupplierID from the data entry form intSupplierCode = Forms![frmExample]![SupplierID] 'Call the parameter query passing the SupplierID???? DoCmd.OpenQuery "qryParams" Else 'Execute the parameter query as normal DoCmd.OpenQuery "qryParams"????? End If End Sub I've tried Me.SupplierID = intSupplierCode, and although it compiles, it bombs when I run it. And here is my SQL code for the parameter query: PARAMETERS [Enter Supplier] Long; SELECT Suppliers.SupplierID, Suppliers.CompanyName, Suppliers.ContactName, Suppliers.ContactTitle FROM Suppliers WHERE (((Suppliers.SupplierID)=[Enter Supplier])); I know there are ways around this problem (and probably an easy way as well) but like I said, my lack of experience using Access and VBA makes things difficult. If any of you could help, that would be great!

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  • Consing lists with user-defined type in Haskell

    - by user1319603
    I have this type I defined myself: data Item = Book String String String Int -- Title, Author, Year, Qty | Movie String String String Int -- Title, Director, Year, Qty | CD String String String Int deriving Show -- Title, Artist, Year, Qty I've created an empty list all_Items = [] With the following function I am trying to insert a new book of type Item (Book) into the all_Items addBook all_Items = do putStrLn "Enter the title of the book" tit <- getLine putStrLn "Enter the author of the book" aut <- getLine putStrLn "Enter the year this book was published" yr <- getLine putStrLn "Enter quantity of copies for this item in the inventory" qty <- getLine Book tit aut yr (read qty::Int):all_Items return(all_Items) I however am receiving this error: Couldn't match expected type `IO a0' with actual type `[a1]' The error points to the line where I am using the consing operator to add the new book to the list. I can gather that it is a type error but I can't figure out what it is that I am doing wrong and how to fix it. Thanks in Advance!

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  • how to design two inputs in or/And logic for email form with validation

    - by Raj Nimbalkar
    my purpose is user enter only email or mobile number.i have the partial success in that.code notify user in OR logic but....IF user entered the incorrect mobile & email @same time then user must be notified for dat. var emailReg = /^([\w-\.]+@([\w-]+\.)+[\w-]{2,4})?$/; var emailaddressVal = $("#UserEmail").val(); ////email & mobile input cheak if(emailaddressVal == '' && $("#mobile").val() == '') { $("#UserEmail").after('<p><span class="error">Please enter your email address.</span></p>') $("#mobile").after('<p><span class="error">Please enter your Mobile number.</span></p>') hasError = true; } //////validating currect email else if(!emailReg.test(emailaddressVal)) { $("#UserEmail").after('<p><span class="error">Enter a valid email address.</span></p>') hasError = true; } //////Mobile number else if( $("#mobile").val()) { $("#mobile").after('<p><span class="error">Enter currect Mobile number.</span></p>') hasError = true; }

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  • python gui generate math equation

    - by Nero Dietrich
    I have a homework question for one specific item with python GUIs. My goal is to create a GUI that asks a random mathematical equation and if the equation is evaluated correctly, then I will receive a message stating that it is correct. My main problem is finding out where to place my statements so that they show up in the labels; I have 1 textbox which generates the random equation, the next textbox is blank for me to enter the solution, and then an "Enter" button at the end to evaluate my solution. It looks like this: [randomly generated equation][Empty space to enter solution] [ENTER] I've managed to get the layout and the evaluate parameters, but I don't know where to go from here. This is my code so far: class Equation(Frame): def __init__(self,parent=None): Frame.__init__(self, parent) self.pack() Equation.make_widgets(self) Equation.new_problem(self) def make_widgets(self): Label(self).grid(row=0, column=1) ent = Entry(self) ent.grid(row=0, column=1) Label(self).grid(row=0, column=2) ent = Entry(self) ent.grid(row=0, column=2) Button(self, text='Enter', command=self.evaluate).grid(row=0, column=3) def new_problem(self): pass def evaluate(self): result = eval(self.get()) self.delete(0, END) self.insert(END, result) print('Correct')

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  • displaying multiple forms in asp.net

    - by Indranil Mutsuddy
    Hello friends, I have a page where i enter the number of members i need to add now suppose i chose 3 so on next page i have get a display like member1 enter details(name, address, phone etc) just below that again member2 enter details(name, address, phone etc) and member3 enter details(name, address, phone etc)in short the no of forms displayed in a page depends on the no of member an user want to add and on submitting the data's of 3(no. provided by the user)member has to be inserted. As i am a rookie to asp.net its hard for me to imagine the logic and implementing them, what to do about tose textfied id's? how to generate the id's and how to separate the codes in .cs and .aspx etc

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  • some logical error in taking up character in java

    - by Himanshu Aggarwal
    This is my code... class info{ public static void main (String[]args) throws IOException{ char gen; while(true) { //problem occurs with this while System.out.print("\nENTER YOUR GENDER (M/F) : "); gen=(char)System.in.read(); if(gen=='M' || gen=='F' || gen=='m' || gen=='f'){ break; } } System.out.println("\nGENDER = "+gen); } } This is my output... ENTER YOUR GENDER (M/F) : h ENTER YOUR GENDER (M/F) : ENTER YOUR GENDER (M/F) : ENTER YOUR GENDER (M/F) : m GENDER = m Could someone please help me understand why it is asking for the gender so many times.

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  • switching default keyevents actions after key combinations

    - by liysd
    I need to change default actions of two events. When I press "enter" one action occurs, when I press "shift-enter" another. I need to switch it. I means if I press "enter" than "shift-enter" action occurs. I tried something like this but if doesn't work. f(evt.keyCode == 13) { if(!evt.shiftKey){ evt.preventDefault(); evt.shiftKey = true; var e = jQuery.Event("keydown"); e.which = 13; e.shiftKey = true; $(wym._doc).trigger(e); Is there any way to do it?

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  • Java/Swing: Problem with key listener

    - by Mike
    I have a search dialog with a JTextField that's being used as a search box. When the user types something, it searches the DB, shows the result in a JTable and selects the first item in it. If the first result is what they were looking for, I want to let them quickly accept the dialog, by pressing Enter (while the JTextField is focused). So I added a KeyListener to the JTextField and it's working OK. Now the problem: The user opens can open the dialog by pressing Enter when a "Search" button on the dialog's parent frame is focused. The dialog is displayed and the JTextField gets the keyReleased event (from the Enter key that displayed it), so it shows up and closes. If the user holds Enter down, then the JTextField receives the keyPressed, keyTyped and keyReleased events. How can I fix without resorting to ugly workarounds? Platform is Windows 7 x64, btw. Test NetBeans project here: http://dl.dropbox.com/u/6354360/KeyListenerTest.zip Thanks.

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  • How to Detect an Event Coming from the Firefox History Dropdown Box

    - by banterCZ
    How to detect an event coming from the Firefox history dropdown box? I need to distinguish between the enter key simply pressed on input field or on item from his native history dropdown box. The reason is that I would like to call custom submit button (not first one, which is default) on the enter key pressed on any input field. But right now, the enter key pressed on history dropdown box unfortunately call submit as well.

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  • Segmentation fault on certain inputs and not others

    - by Brandon Schwandt
    Heres a function I wrote that has some debugging elements in it already. When i enter either a "y" or a "Y" as the input I get a segmentation fault during runtime. When I enter any other value the code runs. The seg fault kicks out after it scans and gives me the response but before the "scan worked" line is output. DOn't know why it would act like this only on these values. If anyone needs the function call I have that as well. query_user(char *response [10]) { printf("response after query call before clear=%s\n",response); strcpy(response,""); printf("response after clearing before scan=%s\n",response); printf("Enter another person into the line? y or n\n"); scanf("%s", response); printf("response after scan=%s\n",response); printf("scan worked"); } main() { char response [10]; strcpy(response,"y"); printf("response=%s\n",response); printf("When finished with program type \"done\" to exit\n"); while (strcmp(response,"done") != 0) { printf("response after while loop and before query call=%s\n",response); query_user(&response); } } output on error: response after query call before clear=y response after clearing before scan= Enter another person into the line? y or n y response after scan=y Segmentation Fault (core dumped) output on non-error: response after query call before clear=y response after clearing before scan= Enter another person into the line? y or n n response after scan=n scan worked Cycle number 0 (program continues to run outside this function)

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  • Codesample with bufferoverflow (gets method). Why does it not behave as expected?

    - by citronas
    This an extract from an c program that should demonstrate a bufferoverflow. void foo() { char arr[8]; printf(" enter bla bla bla"); gets(arr); printf(" you entered %s\n", arr); } The question was "How many input chars can a user maximal enter without a creating a buffer overflow" My initial answer was 8, because the char-array is 8 bytes long. Although I was pretty certain my answer was correct, I tried a higher amount of chars, and found that the limit of chars that I can enter, before I get a segmentation fault is 11. (Im running this on A VirtualBox Ubuntu) So my question is: Why is it possible to enter 11 chars into that 8 byte array?

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  • Simple addition calculator in python

    - by Krysten
    I built a very simple addition calculator in python: #This program will add two numbers entered in by the user print "Welcome!" num1 = input("Please enter in the first number to be added.") num2 = input("Please enter in the second number to be added.") sum = num1 + num2 print "The sum of the two numbers entered is: ", sum I haven't setup python yet, so I'm using codepad.org (an online compiler). I get the following error: Welcome! Please enter in the first number to be addeded.Traceback (most recent call last): Line 5, in num1 = input("Please enter in the first number to be addeded.") EOFError

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  • Ruby - Passing Blocks To Methods

    - by Chris Bunch
    I'm trying to do Ruby password input with the Highline gem and since I have the user input the password twice, I'd like to eliminate the duplication on the blocks I'm passing in. For example, a simple version of what I'm doing right now is: new_pass = ask("Enter your new password: ") { |prompt| prompt.echo = false } verify_pass = ask("Enter again to verify: ") { |prompt| prompt.echo = false } And what I'd like to change it to is something like this: foo = Proc.new { |prompt| prompt.echo = false } new_pass = ask("Enter your new password: ") foo verify_pass = ask("Enter again to verify: ") foo Which unfortunately doesn't work. What's the correct way to do this?

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  • Hot to log in to a website using installed twill?

    - by brilliant
    Hello, everybody!!!! I have just successfully installed TWILL on my computer with the help of one very supportive member of "StackOverflow" (you can check it out HERE) and have tried to run one of the simple examples on the twill documentation page (you can see that page HERE). Here is that example: Let's say my username on www.slash.org is lynxye and my password is mammal. When I try to enter that exanple code into my Python prompt, I can only enter the first line of the code bexcause when I click on "Enter" to start a new line, I get some error messages right away: The same happens when I try to enter this code into my terminal: I think I miss out on some basics here. Perhaps, I need to create a file that would contain that code and then run that file somehow, but I really don't know where I need to create that file and with what extensdion. Can anyone, please, help me with this?

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  • How to read input until the user enters ^X

    - by Koning Baard
    I am creating an interpreter for my esolang, and I need the user to enter some text which then will be interpreted as an INTERCAL program. I want the user to enter text, which may contain any character including newlines, until the user presses ^X (Ctrl-X), like this: Enter your code followed by ^X: Bla Blablabla Bla^X Thank you for entering your code (line 2, 3 and 4 were entered by the user) can anyone explain me how I can read input including newlines till the user enters ^X? Thanks

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  • How to get JOptionPane with three text fields

    - by Dr.Mostafa
    I want to know how i can do a messageBox from three input dialog .. Like this: JOptionPane.showInputMessageDialog("Enter your FirstName"); JOptionPane.showInputMessageDialog("Enter your MiddleName"); JOptionPane.showInputMessageDialog("Enter your LastName"); But I want one message has a three input boxes.

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  • Rails group validation with just one error message

    - by Victor
    The following validation code in the model: validates :formatted_address, :zip, :city, :state, :country, :presence => true, :message => "is incomplete. Please enter full address." is displayed when either of the fields are empty. Let's say now :address and country are empty, 2 errors are displayed: Formatted Address is incomplete. Please enter full address. Country is incomplete. Please enter full address. How can I group the error message in the validation to just show one error message if either of the fields validated does not exist? Address is incomplete. Please enter full address. Thanks.

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  • replacing elements horizontally and vertically in a 2D array

    - by wello horld
    the code below ask for the user's input for the 2D array size and prints out something like this: (say an 18x6 grid) .................. .................. .................. .................. .................. .................. code starts here: #include <stdio.h> #define MAX 10 int main() { char grid[MAX][MAX]; int i,j,row,col; printf("Please enter your grid size: "); scanf("%d %d", &row, &col); for (i = 0; i < row; i++) { for (j = 0; j < col; j++) { grid[i][j] = '.'; printf("%c ", grid[i][j]); } printf("\n"); } return 0; } I now ask the user for a string, then ask them where to put it for example: Please enter grid size: 18 6 Please enter word: Hello Please enter location: 0 0 Output: Hello............. .................. .................. .................. .................. .................. Please enter location: 3 4 Output: .................. .................. .................. ..Hello........... .................. .................. program just keeps going. Any thoughts on how to modify the code for this? PS: Vertical seems way hard, but I want to start on horizontal first to have something to work on.

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