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  • Why are there 3 conflicting OpenCV camera calibration formulas?

    - by John
    I'm having a problem with OpenCV's various parameterization of coordinates used for camera calibration purposes. The problem is that three different sources of information on image distortion formulae apparently give three non-equivalent description of the parameters and equations involved: (1) In their book "Learning OpenCV…" Bradski and Kaehler write regarding lens distortion (page 376): xcorrected = x * ( 1 + k1 * r^2 + k2 * r^4 + k3 * r^6 ) + [ 2 * p1 * x * y + p2 * ( r^2 + 2 * x^2 ) ], ycorrected = y * ( 1 + k1 * r^2 + k2 * r^4 + k3 * r^6 ) + [ p1 * ( r^2 + 2 * y^2 ) + 2 * p2 * x * y ], where r = sqrt( x^2 + y^2 ). Assumably, (x, y) are the coordinates of pixels in the uncorrected captured image corresponding to world-point objects with coordinates (X, Y, Z), camera-frame referenced, for which xcorrected = fx * ( X / Z ) + cx and ycorrected = fy * ( Y / Z ) + cy, where fx, fy, cx, and cy, are the camera's intrinsic parameters. So, having (x, y) from a captured image, we can obtain the desired coordinates ( xcorrected, ycorrected ) to produced an undistorted image of the captured world scene by applying the above first two correction expressions. However... (2) The complication arises as we look at OpenCV 2.0 C Reference entry under the Camera Calibration and 3D Reconstruction section. For ease of comparison we start with all world-point (X, Y, Z) coordinates being expressed with respect to the camera's reference frame, just as in #1. Consequently, the transformation matrix [ R | t ] is of no concern. In the C reference, it is expressed that: x' = X / Z, y' = Y / Z, x'' = x' * ( 1 + k1 * r'^2 + k2 * r'^4 + k3 * r'^6 ) + [ 2 * p1 * x' * y' + p2 * ( r'^2 + 2 * x'^2 ) ], y'' = y' * ( 1 + k1 * r'^2 + k2 * r'^4 + k3 * r'^6 ) + [ p1 * ( r'^2 + 2 * y'^2 ) + 2 * p2 * x' * y' ], where r' = sqrt( x'^2 + y'^2 ), and finally that u = fx * x'' + cx, v = fy * y'' + cy. As one can see these expressions are not equivalent to those presented in #1, with the result that the two sets of corrected coordinates ( xcorrected, ycorrected ) and ( u, v ) are not the same. Why the contradiction? It seems to me the first set makes more sense as I can attach physical meaning to each and every x and y in there, while I find no physical meaning in x' = X / Z and y' = Y / Z when the camera focal length is not exactly 1. Furthermore, one cannot compute x' and y' for we don't know (X, Y, Z). (3) Unfortunately, things get even murkier when we refer to the writings in Intel's Open Source Computer Vision Library Reference Manual's section Lens Distortion (page 6-4), which states in part: "Let ( u, v ) be true pixel image coordinates, that is, coordinates with ideal projection, and ( u ~, v ~ ) be corresponding real observed (distorted) image coordinates. Similarly, ( x, y ) are ideal (distortion-free) and ( x ~, y ~ ) are real (distorted) image physical coordinates. Taking into account two expansion terms gives the following: x ~ = x * ( 1 + k1 * r^2 + k2 * r^4 ) + [ 2 p1 * x * y + p2 * ( r^2 + 2 * x^2 ) ] y ~ = y * ( 1 + k1 * r^2 + k2 * r^4 ] + [ 2 p2 * x * y + p2 * ( r^2 + 2 * y^2 ) ], where r = sqrt( x^2 + y^2 ). ... "Because u ~ = cx + fx * u and v ~ = cy + fy * v , … the resultant system can be rewritten as follows: u ~ = u + ( u – cx ) * [ k1 * r^2 + k2 * r^4 + 2 * p1 * y + p2 * ( r^2 / x + 2 * x ) ] v ~ = v + ( v – cy ) * [ k1 * r^2 + k2 * r^4 + 2 * p2 * x + p1 * ( r^2 / y + 2 * y ) ] The latter relations are used to undistort images from the camera." Well, it would appear that the expressions involving x ~ and y ~ coincided with the two expressions given at the top of this writing involving xcorrected and ycorrected. However, x ~ and y ~ do not refer to corrected coordinates, according to the given description. I don't understand the distinction between the meaning of the coordinates ( x ~, y ~ ) and ( u ~, v ~ ), or for that matter, between the pairs ( x, y ) and ( u, v ). From their descriptions it appears their only distinction is that ( x ~, y ~ ) and ( x, y ) refer to 'physical' coordinates while ( u ~, v ~ ) and ( u, v ) do not. What is this distinction all about? Aren't they all physical coordinates? I'm lost! Thanks for any input!

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  • Excel MAXIF function or emulation?

    - by Andre Boos
    I have a moderately sized dataset in Excel from which I wish to extract the maximum value of the values in Column B, but those that correspond only to cells in Column A that satisfy certain criteria. The desired functionality is similar to that of SUMIF or COUNTIF, but neither of those return data that is necessary. There isn't a MAXIF function, so I ask the SO community: how do I emulate one?

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  • SQL bottleneck, how to fix

    - by masfenix
    This is related to my previous thread: http://stackoverflow.com/questions/3069806/sql-query-takes-about-10-20-minutes However, I kinda figured out the problem. The problem (as described in the previous thread) is not the insert (while its still slow), the problem is looping through the data itself Consider the following code: Dim rs As DAO.Recordset Dim sngStart As Single, sngEnd As Single Dim sngElapsed As Single Set rs = CurrentDb().QueryDefs("select-all").OpenRecordset MsgBox "All records retreived" sngStart = Timer Do While Not rs.EOF rs.MoveNext Loop sngEnd = Timer sngElapsed = Format(sngEnd - sngStart, "Fixed") ' Elapsed time. MsgBox ("The query took " & sngElapsed _ & " seconds to run.") As you can see, this loop does NOTHING. You'd expect it to finish in seconds, however it takes about 857 seconds to run (or 15 minutes). I dont know why it is so slow. Maybe the lotusnotes sql driver? any other ideas? (java based solution, any other solution) What my goal is: To get all the data from remote server and insert into local access table

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  • How to allow users to define financial formulas in a C# app

    - by Peter Morris
    I need to allow my users to be able to define formulas which will calculate values based on data. For example //Example 1 return GetMonetaryAmountFromDatabase("Amount due") * 1.2; //Example 2 return GetMonetaryAmountFromDatabase("Amount due") * GetFactorFromDatabase("Discount"); I will need to allow / * + - operations, also to assign local variables and execute IF statements, like so var amountDue = GetMonetaryAmountFromDatabase("Amount due"); if (amountDue > 100000) return amountDue * 0.75; if (amountDue > 50000) return amountDue * 0.9; return amountDue; The scenario is complicated because I have the following structure.. Customer (a few hundred) Configuration (about 10 per customer) Item (about 10,000 per customer configuration) So I will perform a 3 level loop. At each "Configuration" level I will start a DB transaction and compile the forumlas, each "Item" will use the same transaction + compiled formulas (there are about 20 formulas per configuration, each item will use all of them). This further complicates things because I can't just use the compiler services as it would result in continued memory usage growth. I can't use a new AppDomain per each "Configuration" loop level because some of the references I need to pass cannot be marshalled. Any suggestions?

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  • Image Data via Ajax - how can I display the image on the Page

    - by Mike B
    I am creating a Domino Document via AJAX that contains a photo. I am able to get the base64 image data back to the server in a Notes Domino Document. Data is stored in a Richtext (textarea) field as "data:image/jpeg;base64,/9j/4AAQSkZJRgABAQAAAQABAAD/2wBDAFA..........." - (this goes on for several lines) I am trying to display on the Domino Webpage using passthru tag <<image id= "pic1" >> in the onLoad event of the Form i try to shove the data into the image element using this code: //Photo Stuff alert(document.forms[0].photo1.value); document.getElementById("pic1").src = document.forms[0].photo1.value; The alert is showing the data. Picture is not appearing. Please help. Thanks Mike

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  • Managing attachmnet files with same name and different content.

    - by Pari
    Hi, I am extracting attachment from Inbox,Send,Drafts e.t.c. mails. And saving them in a folder. Using below logic: http://stackoverflow.com/questions/1361695/how-to-access-attachments-from-notes-mail But problem i am facing here is. Attachment having same type and name but different content. In current situation it is replacing old file with new one. How i can uniquely manage this attachment for different mails.

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  • save managed bean to notes document

    - by Ove Stoerholt
    In a managed bean you have fields, and the fields have getters and setters. But I also need to save values back to, in this case, a Notes profile document. So I have a loadProfileDocument and a saveProfileDocument method. I was thinking of using the bean in the application scope. How do I make sure the profile document is saved? Do I have to call the saveProfileDocument from the setter? Do I call the saveProfileDocument() explisitly? Could I use a destructor (finalize)? Or what...???...

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  • Is there a macro or a way to conditionally copy rows from one or more worksheet to another in Excel 2007

    - by marison
    I'm pulling a list of data from two or more excel file into one with some specific condition. For Eg: File1 Date Project ID Engineer 8/2/2008 XYZ T0908-5555 JS 9/4/2008 ABC T0908-6666 DF 9/5/2008 ZZZ T0908-7777 TS 9/4/2008 ABC T0908-1111 DF 9/5/2008 POR T0908-7777 MS 9/4/2008 ABC T0908-2222 DD File 2 Date Project ID Engineer 8/2/2008 ABC T1908-5555 JS 9/4/2008 XYZ T1908-6666 DF 9/5/2008 ABC T1908-7777 TS 9/4/2008 ZZZ T1908-1111 DF 9/5/2008 POR T1908-7777 MS 9/4/2008 ABC T1908-2222 DD I want Data from both file1 and file2 in a new excel with only those rows whose Project ID= "ABC". And the path of file1 and file2 will be changed on daily basis. Kindly help.....

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  • Filtering and then counting distinct values

    - by Deon
    This is for Excel: I've been tasked with counting distinct records after I have filtered the data. I have 330 rows with column A containing the 'name' and in Column B I have the name of a test that was done for each 'name', which each 'name' could have taken several iterations of the same test. The test results are in Column C. Col A -Student Col B -Exam Col C - Grade Student 1 Exam 1 .80 Student 2 Exam 1 .50 Student 3 Exam 1 .90 Student 2 Exam 1 .75 Student 4 Exam 1 .90 Student 5 Exam 1 .55 Student 2 Exam 2 .90 Student 1 Exam 2 .90 .... .... ... If I filter col B for Exam 1, I want to count the unique number of students that have taken Exam 1.

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  • How to build a control programatically?

    - by W_K
    I have custom control written in Java. For the sake of simplicity lets assume that it looks like this: public class HelloworldControl extends UIComponentBase { @Override public void decode(FacesContext context) { String cid = this.getClientId(context); ... super.decode(context); } @Override public void encodeBegin(FacesContext context) throws IOException { ResponseWriter writer = context.getResponseWriter(); writer.writeText("Hello world!", this); // I want a view!! } @Override public void encodeEnd(FacesContext context) throws IOException { ResponseWriter writer = context.getResponseWriter(); ... } public void restoreState(FacesContext context, Object state) { Object values[] = (Object[]) state; ... super.restoreState(context, values[0]); } public Object saveState(FacesContext context) { Object values[] = ... } } I would like to add programatically child control to it. For example I would like a child view control to render a view just under the Hellow world text. How can i do this? What is the standard procedure to build dynamically a control? To put it simply - I want programatically build a hierarchy of standard components and I want to attach it to my control.

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  • How do I gather data from the same collumn in multiple worksheets in a single workbook?

    - by infiniteloop91
    Okay so here is what I want to accomplish. For this example I have a single workbook composed of 4 data sheets plus a totals sheet. Each of the 4 data sheets has a similar name following the same pattern where the only difference is the date. (Ex. 9854978_1009_US.txt, where 1009 is the date that changes while the rest of the file name is the same). In each of those documents column F contains a series of number that I would like to find the sum of but I will have no idea how many cells in F actually contain numbers. (However there will never be additional information below it the numbers so I could in theory just add the entire F column together). I will also add new files to the workbook over time and do not want to have to rewrite the code of which I gather my data from column F. Essentially what I would like to accomplish is for the 'totals' document to take every column F from documents in the workbook with the name of '9854978_????_US.txt', where the question marks change based on the file name. How would I go about doing this in pure Excel code?

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  • Why would 1.000 subforms in a db be a bad idea?

    - by KlaymenDK
    Warm-up I'm trying to come up with a good way to implement customized document forms. It's for a tool to request access to applications; each application will want to ask its own specific questions. The thing is, we have one kind of (common) user who needs to fill in and submit documents based on templates, and another kind of (super) user who needs to be able to define what each template needs to contain. One implementation option would be to use a form (with the basic mandatory stuff), and have that form dynamically include a subform appropriate to the specific task at hand. The gist of the matter is that we could (=will!) quite easily end up having many hundreds of different subforms! (NB. These subforms will be maintained in an automated manner, but that is another topic that may be considered outside the scope of this Question.) Question It's common knowledge that having a lot of views in a Notes database is Bad Thing. But has anyone tried pushing the number of forms or subforms and made any experiences regarding performance?

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  • Which CSS identifier is used for the selected tab in tabbed tables in browsers other than IE?

    - by David Navarre
    When you have a table on a form in Notes, you can choose to display only one row at a time (via the Special Table Row Display parameter on the Table Rows tab of the Table properties). In a Notes document displayed using Internet Explorer that contains such a table, a row is displayed with a cell for each "tab". The TD that serves as the tab for the selected "Notes table row" is assigned <td class="dominoSelTopTab">, while the other tabs get <td class="dominoTopTab">. However, when using other browsers, it's not nearly as simple. In Firefox, each "tab" ends up as a single-celled-single-row-table within the table with very little to identify it. <td><table border="1" cellpadding="2"> <tr><td><div align="center"><b>Tab 2</b></div></td></tr> </table></td> A non-selected tab would show as follows: <td><table border="1" cellpadding="2"> <tr><td><div align="center"><a name="1." href="/Projects/MyCSS.nsf/0c3b9489476440c085257a62006d97d6/d482a1767a4af77f85257a62006db064?OpenDocument&amp;TableRow=1.0#1." target="_self">Tab 1</a></div></td></tr> </table></td> So, the question is, how do I identify the selected tabs and the non-selected tabs when not using IE? Note: For those who are not Notes developers, the HTML is auto-generated from the visual design as laid out in the Notes designer client. I would replace it all with manual HTML, except there is so much of it that doing so would consume far too much time.

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  • optimization math computation (multiplication and summing)

    - by wiso
    Suppose you want to compute the sum of the square of the differences of items: $\sum_{i=1}^{N-1} (x_i - x_{i+1})^2$, the simplest code (the input is std::vector<double> xs, the ouput sum2) is: double sum2 = 0.; double prev = xs[0]; for (vector::const_iterator i = xs.begin() + 1; i != xs.end(); ++i) { sum2 += (prev - (*i)) * (prev - (*i)); // only 1 - with compiler optimization prev = (*i); } I hope that the compiler do the optimization in the comment above. If N is the length of xs you have N-1 multiplications and 2N-3 sums (sums means + or -). Now suppose you know this variable: sum = $x_1^2 + x_N^2 + 2 sum_{i=2}^{N-1} x_i^2$ Expanding the binomial square: $sum_i^{N-1} (x_i-x_{i+1})^2 = sum - 2\sum_{i=1}^{N-1} x_i x_{i+1}$ so the code becomes: double sum2 = 0.; double prev = xs[0]; for (vector::const_iterator i = xs.begin() + 1; i != xs.end(); ++i) { sum2 += (*i) * prev; prev = (*i); } sum2 = -sum2 * 2. + sum; Here I have N multiplications and N-1 additions. In my case N is about 100. Well, compiling with g++ -O2 I got no speed up (I try calling the inlined function 2M times), why?

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  • Formula to format a cell to subtract one decimal place from another cell and have the calculated results displayed

    - by user242618
    I have a value in one cell that has four decimal places, in the cell below, I have the metric conversion formula. I want the cell below, with the metric conversion formula to display one less decimal place than the cell above. For example, if the English measurement is .#### (4 decimal places), I need the conversion cell to display .### (3 decimal places) and if the English measurement is .### (3 decimal places), I need the conversion cell to display .### ( decimal places), and so on. How can I do this?

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  • Calculated Fields - Idiosyncracies

    - by PointsToShare
    © 2011 By: Dov Trietsch. All rights reserved Calculated Fields and some of their Idiosyncrasies Did you try to write a calculate field formula directly into the screen? Good Luck – You’ll need it! Calculated Fields are a sophisticated OOB feature of SharePoint, so you could think that they are best left to the end users – at least to the power users. But they reach their limits before the “Professionals “do, and the tough ones come back to us anyway. Back to business; the simpler the formula, the easier it is. Still, use your favorite editor to write it, then cut it and paste it to the ridiculously small window. What about complex formulae? Write them in steps! Here is a case in point and an idiosyncrasy or two. Our welders need to be certified and recertified every two years. Some of them are certifiable…., but I digress. To be certified you need to pass an eye exam, and two more tests – test A and test B. for each of those you have an expiry date. When renewed, each expiry date is advanced by two years from the date of renewal. My users wanted a visual clue so that when the supervisor looks at the list, she’ll have a KPI symbol telling her if anything expired (Red), is going to expire within the next 90 days (Yellow) or is not to be worried about (green). Not all the dates are filled and any blank date implies a complete lack of certification in the particular requirement. Obviously, I needed to figure the minimal of these 3 dates – a simple enough formula: =MIN([Date_EyeExam], {Date_TestA], [Date_TestB]). Aha! Here is idiosyncrasy #1. When one of the dates is a null, MIN(Date1, Date2) returns the non null date. Null is construed as “Far, far away”. The funny thing is that when you compare it to Today, the null is the lesser one. So a null it is less than today, but not when MIN is calculated. Now, to me the fact that the welder does not have an exam date, is synonymous with his exam being prehistoric, or at least past due. So here is what I did: Solution: Let’s set a blank date to 1/1/1800. How will we do that? Use the IF. IF([Field] rel relValue, TrueValue, FalseValue). rel is any relationship operator <, >, <=, >=, =, <>. If the field is related to the relValue as prescribed, the “IF” returns the TrueValue, otherwise it returns the FalseValue. Thus: =IF([SomeDate]="",1/1/1800,[SomeDate]) will return 1/1/1800 if the date is blank and the date itself if not. So, using this formula, if the welder missed an exam, the returned exam date will be far in the past. It would be nice if we could take such a formula and make it into a reusable function. Alas, here is a calculated field serious shortcoming: You cannot write subs and functions!! Aha, but we can use interim calculated fields! So let’s create 3 calculated fields as follows: 1: c_DateTestA as a calculated field of the date type, with the formula:  IF([Date_TestA]="",1/1/1800,[Date_TestA]) 2: c_DateTestB as a calculated field of the date type, with the formula:  IF([Date_TestB]="",1/1/1800,[Date_TestB]) 3: c_DateEyeExam as a calculated field of the date type, with the formula:  IF([Date_EyeExam]="",1/1/1800,[Date_EyeExam]) And now use these to get c_MinDate. This is again a calculated field of type date with the formula: MIN(c_DateTestA, cDateTestB, c_DateEyeExam) Note that I missed the square parentheses. In “properly named fields – where there are no embedded spaces, we don’t need the square parentheses. I actually strongly recommend using underscores in place of spaces in all the field names in your lists. Among other things, it makes using CAML much simpler. Now, we still need to apply the KPI to this minimal date. I am going to use the available KPI graphics that come with SharePoint and are always available in your 12 hive. "/_layouts/images/kpidefault-2.gif" is the Red KPI "/_layouts/images/kpidefault-1.gif" is the Yellow KPI "/_layouts/images/kpidefault-0.gif" is the Green KPI And here is the nested IF formula that will do the trick: =IF(c_MinDate<=Today,"/_layouts/images/kpidefault-2.gif", IF(cMinDate<Today+90,"/_layouts/images/kpidefault-1.gif","/_layouts/images/kpidefault-0.gif")) Nice! BUT when I tested, it did not work! This is Idiosyncrasy #2: A calculated field based on a calculated field based on a calculated field does not work. You have to stop at two levels! Back to the drawing board: We have to reduce by one level. How? We’ll eliminate the c_DateX items in the formula and replace them with the proper IF formulae. Notice that this needs to be done with precision. You are much better off in doing it in your favorite line editor, than inside the cramped space that SharePoint gives you. So here is the result: MIN(IF([Date_TestA]="",1/1/1800,[ Date_TestA]), IF([Date_TestB]="",1/1/1800,[ Date_TestB]), 1/1/1800), IF([Date_EyeExam]="",1/1/1800,[Date_EyeExam])) Note that I bolded the parentheses and painted them red. They have to match for this formula to work. Now we can leave the KPI formula as is and test again. This time with SUCCESS! Conclusion: build the inner functions first, and then embed them inside the outer formulae. Do this as long as necessary. Use your favorite line editor. Limit yourself to 2 levels. That’s all folks! Almost! As soon as I finished doing all of the above, my users added yet another level of complexity. They added another test, a test that must be passed, but never expires and asked for yet another KPI, this time in Black to denote that any test is not just past due, but altogether missing. I just finished this. Let’s hope it ends here! And OH, the formula  =IF(c_MinDate<=Today,"/_layouts/images/kpidefault-2.gif",IF(cMinDate<Today+90,"/_layouts/images/kpidefault-1.gif","/_layouts/images/kpidefault-0.gif")) Deals with “Today” and this is a subject deserving a discussion of its own!  That’s all folks?! (and this time I mean it)

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  • How to deal with lots of brackets in a formula?

    - by wenlibin02
    Say, I have a formula like this (in LaTeX or Maple or other text system): Result: ((6*(k2+k3))*A123*k2*k3*(A12*A13*k2^2-2*A12*A13*k2*k3+A12*A13*k3^2-A123*k2^2-2*A123*k2*k3-A123*k3^2)*(exp(-k3*(k3^2*t-x)))^2+6*A12*(-k3+k2)*k2*k3*(A12*A13*k2^2-2*A12*A13*k2*k3+A12*A13*k3^2-A123*k2^2-2*A123*k2*k3-A123*k3^2)*exp(-k3*(k3^2*t-x)))*(exp(-k2*(k2^2*t-x)))^2+(-(6*(-k3+k2))*A13*k2*k3*(A12*A13*k2^2-2*A12*A13*k2*k3+A12*A13*k3^2-A123*k2^2-2*A123*k2*k3-A123*k3^2)*(exp(-k3*(k3^2*t-x)))^2-(6*(k2+k3))*k2*k3*(A12*A13*k2^2-2*A12*A13*k2*k3+A12*A13*k3^2-A123*k2^2-2*A123*k2*k3-A123*k3^2)*exp(-k3*(k3^2*t-x)))*exp(-k2*(k2^2*t-x)) Note: the above formula is only one part of the result of a maple calculation, I just can't break them up because there are so many many terms. Apparently, It's very hard to read. What I want to do is to fold the matched brackets level by level. If all the brackets are folded, I can find out clearly how many terms there are. Then I can analyze from the top level to the details of every term. But I just don't know how to realize that. Maybe there are some existed software which can visualize this kind of complex formula. Any idea? P.S. I use Linux system. The open source alternatives are better.

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  • How to copy a cell's formatting using a formula?

    - by Alvin Lim
    For example, cell A1 contains the text "Hello World" which is in bold. In cell A2, I use the formula =A1. Therefore cell A2 now also contains "Hello World", but it is not in bold. How can I modify the formula to also copy the formatting (in this case, bold) of A1? A more complex example is strikethrough properties, i.e. A1 contains "Orange/Red". How do I show the same content in cell A2 dynamically, so that any changes made in A1 will update A2 as well?

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