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  • How to get max of composite data in SQL?

    - by Siddharth Sinha
    SELECT "Name""Month","Year","Value" from Table WHERE "Name" LIKE '%JERRY%' AND "Year" = (SELECT MAX("Year") FROM Table where "Name" LIKE '%JERRY%') AND "Month"= (SELECT MAX("Month") FROM Table where "Name" LIKE '%JERRY%' AND "Year"= (SELECT MAX("Year") FROM Table where "Name" LIKE '%JERRY%')) Table -- Name | Year | Month | Value ----------------------------- JERRY 2012 9 100 JERRY 2012 9 120 JERRY 2012 9 130 JERRY 2012 8 20 JERRY 2011 12 50 So i want the first three rows as output. As for the latest month for the latest year i need all the values. Can someone suggest a better cleaner query?

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  • What's the best way to select max over multiple fields in SQL?

    - by allyourcode
    The I kind of want to do is select max(f1, f2, f3). I know this doesn't work, but I think what I want should be pretty clear (see update 1). I was thinking of doing select max(concat(f1, '--', f2 ...)), but this has various disadvantages. In particular, doing concat will probably slow things down. What's the best way to get what I want? update 1: The answers I've gotten so far aren't what I'm after. max works over a set of records, but it compares them using only one value; I want max to consider several values, just like the way order by can consider several values. update 2: Suppose I have the following table: id class_name order_by1 order_by_2 1 a 0 0 2 a 0 1 3 b 1 0 4 b 0 9 I want a query that will group the records by class_name. Then, within each "class", select the record that would come first if you ordered by order_by1 ascending then order_by2 ascending. The result set would consist of records 2 and 3. In my magical query language, it would look something like this: select max(* order by order_by1 ASC, order_by2 ASC) from table group by class_name

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  • How do i generate a random integer between min and max in java?

    - by David
    What method returns a random int between a min and max? Or does no such method exist? what i'm looking for is something like this: NAMEOFMETHOD (min, max) (where min and max are ints) that returns soemthing like this: 8 (randomly) if such a method does exist could you please link to the relevant documentation with your answer. thanks.

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  • Why does RIGHT(@foostr, 0) return NULL when @foostr is varchar(max)?

    - by bob-montgomery
    In SQL Server 2005 If I want to find the right-most one character of a varchar(max) variable, no problem: declare @foostr varchar(max) set @foostr = 'abcd' select right (@foostr, 1) ---- d If I want to find the right-most zero characters of a string literal, no problem: select right ('abcd', 0) ------------------ It returns an empty string. If I want to find the right-most zero characters of a varchar(10), no problem: declare @foostr varchar(10) set @foostr = 'abcd' select right (@foostr, 0) ---- It returns an empty string. If I want to find the right-most zero characters of a varchar(max), well: declare @foostr varchar(max) set @foostr = 'abcd' select right (@foostr, 0) ---- NULL It returns NULL. Why?

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  • 3DS Max MassFX -- Animation to XNA without bones/skins?

    - by AnKoe
    I made a model in which a number of cobble stones fall into a hole using the rigid bodies in 3DS Max 2012 MassFX. They are just editable polys, no skin, no bone. I want this to play (Take 001, 0-100 frames) when the game loads the mesh. I haven't found a way to get to the animation though. Does anyone have suggestions? All the tutorials for animated skinned models don't seem to work with a model set up like this? Do I really need to give each of 145 rocks a bone? If so, does anyone have a suggestion how to streamline that, or if there is an alternate solution to achieving this effect? The animation only needs to play once when the game starts, and that's it. Thanks.

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  • Is there an equivalent to the Max OS X software Hazel that runs on Ubuntu?

    - by Stuart Woodward
    Is there an equivalent to the Max OS X software Hazel that runs on Ubuntu? "Hazel watches whatever folders you tell it to, automatically organizing your files according to the rules you create. It features a rule interface [..]. Have Hazel move files around based on name, date, type, what site/email address it came from [..] and much more. Automatically put your music in your Music folder, movies in Movies. Keep your downloads off the desktop and put them where they are supposed to be." This question probably won't make sense unless you have used Hazel, but basically you can define rules via the GUI to move and rename files automatically to make an automated workflow.

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  • Optimizing this "Boundarize" method for Numerics in Ruby

    - by mstksg
    I'm extending Numerics with a method I call "Boundarize" for lack of better name; I'm sure there are actually real names for this. But its basic purpose is to reset a given point to be within a boundary. That is, "wrapping" a point around the boundary; if the area is betweeon 0 and 100, if the point goes to -1, -1.boundarize(0,100) = 99 (going one too far to the negative "wraps" the point around to one from the max). 102.boundarize(0,100) = 2 It's a very simple function to implement; when the number is below the minimum, simply add (max-min) until it's in the boundary. If the number is above the maximum, simply subtract (max-min) until it's in the boundary. One thing I also need to account for is that, there are cases where I don't want to include the minimum in the range, and cases where I don't want to include the maximum in the range. This is specified as an argument. However, I fear that my current implementation is horribly, terribly, grossly inefficient. And because every time something moves on the screen, it has to re-run this, this is one of the bottlenecks of my application. Anyone have any ideas? module Boundarizer def boundarize min=0,max=1,allow_min=true,allow_max=false raise "Improper boundaries #{min}/#{max}" if min >= max new_num = self if allow_min while new_num < min new_num += (max-min) end else while new_num <= min new_num += (max-min) end end if allow_max while new_num > max new_num -= (max-min) end else while new_num >= max new_num -= (max-min) end end return new_num end end class Numeric include Boundarizer end

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  • Project Euler 11: (Iron)Python

    - by Ben Griswold
    In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 11.  As always, any feedback is welcome. # Euler 11 # http://projecteuler.net/index.php?section=problems&id=11 # What is the greatest product # of four adjacent numbers in any direction (up, down, left, # right, or diagonally) in the 20 x 20 grid? import time start = time.time() grid = [\ [8,02,22,97,38,15,00,40,00,75,04,05,07,78,52,12,50,77,91,8],\ [49,49,99,40,17,81,18,57,60,87,17,40,98,43,69,48,04,56,62,00],\ [81,49,31,73,55,79,14,29,93,71,40,67,53,88,30,03,49,13,36,65],\ [52,70,95,23,04,60,11,42,69,24,68,56,01,32,56,71,37,02,36,91],\ [22,31,16,71,51,67,63,89,41,92,36,54,22,40,40,28,66,33,13,80],\ [24,47,32,60,99,03,45,02,44,75,33,53,78,36,84,20,35,17,12,50],\ [32,98,81,28,64,23,67,10,26,38,40,67,59,54,70,66,18,38,64,70],\ [67,26,20,68,02,62,12,20,95,63,94,39,63,8,40,91,66,49,94,21],\ [24,55,58,05,66,73,99,26,97,17,78,78,96,83,14,88,34,89,63,72],\ [21,36,23,9,75,00,76,44,20,45,35,14,00,61,33,97,34,31,33,95],\ [78,17,53,28,22,75,31,67,15,94,03,80,04,62,16,14,9,53,56,92],\ [16,39,05,42,96,35,31,47,55,58,88,24,00,17,54,24,36,29,85,57],\ [86,56,00,48,35,71,89,07,05,44,44,37,44,60,21,58,51,54,17,58],\ [19,80,81,68,05,94,47,69,28,73,92,13,86,52,17,77,04,89,55,40],\ [04,52,8,83,97,35,99,16,07,97,57,32,16,26,26,79,33,27,98,66],\ [88,36,68,87,57,62,20,72,03,46,33,67,46,55,12,32,63,93,53,69],\ [04,42,16,73,38,25,39,11,24,94,72,18,8,46,29,32,40,62,76,36],\ [20,69,36,41,72,30,23,88,34,62,99,69,82,67,59,85,74,04,36,16],\ [20,73,35,29,78,31,90,01,74,31,49,71,48,86,81,16,23,57,05,54],\ [01,70,54,71,83,51,54,69,16,92,33,48,61,43,52,01,89,19,67,48]] # left and right max, product = 0, 0 for x in range(0,17): for y in xrange(0,20): product = grid[y][x] * grid[y][x+1] * \ grid[y][x+2] * grid[y][x+3] if product > max : max = product # up and down for x in range(0,20): for y in xrange(0,17): product = grid[y][x] * grid[y+1][x] * \ grid[y+2][x] * grid[y+3][x] if product > max : max = product # diagonal right for x in range(0,17): for y in xrange(0,17): product = grid[y][x] * grid[y+1][x+1] * \ grid[y+2][x+2] * grid[y+3][x+3] if product > max: max = product # diagonal left for x in range(0,17): for y in xrange(0,17): product = grid[y][x+3] * grid[y+1][x+2] * \ grid[y+2][x+1] * grid[y+3][x] if product > max : max = product print max print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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  • Code Contracts: How they look after compiling?

    - by DigiMortal
    When you are using new tools that make also something at code level then it is good idea to check out what additions are made to code during compilation. Code contracts have simple syntax when we are writing code at Visual Studio but what happens after compilation? Are our methods same as they look in code or are they different after compilation? In this posting I will show you how code contracts look after compiling. In my previous examples about code contracts I used randomizer class with method called GetRandomFromRangeContracted. public int GetRandomFromRangeContracted(int min, int max) {     Contract.Requires<ArgumentOutOfRangeException>(         min < max,         "Min must be less than max"     );       Contract.Ensures(         Contract.Result<int>() >= min &&         Contract.Result<int>() <= max,         "Return value is out of range"     );       return _generator.Next(min, max); } Okay, it is nice to dream about similar code when we open our assembly with Reflector and disassemble it. But… this time we have something interesting. While reading this code don’t feel uncomfortable about the names of variables. This is disassembled code. .NET Framework internally allows these names. It is our compilators that doesn’t accept them when we are building our code. public int GetRandomFromRangeContracted(int min, int max) {     int Contract.Old(min);     int Contract.Old(max);     if (__ContractsRuntime.insideContractEvaluation <= 4)     {         try         {             __ContractsRuntime.insideContractEvaluation++;             __ContractsRuntime.Requires<ArgumentOutOfRangeException>(                min < max,                "Min must be less than max", "min < max");         }         finally         {             __ContractsRuntime.insideContractEvaluation--;         }     }     try     {         Contract.Old(min) = min;     }     catch (Exception exception1)     {         if (exception1 == null)         {             throw;         }     }     try     {         Contract.Old(max) = max;         catch (Exception exception2)     {         if (exception2 == null)         {             throw;         }     }     int CS$1$0000 = this._generator.Next(min, max);     int Contract.Result<int>() = CS$1$0000;     if (__ContractsRuntime.insideContractEvaluation <= 4)     {         try         {             __ContractsRuntime.insideContractEvaluation++;             __ContractsRuntime.Ensures(                (Contract.Result<int>() >= Contract.Old(min)) &&                (Contract.Result<int>() <= Contract.Old(max)),                "Return value is out of range",                "Contract.Result<int>() >= min && Contract.Result<int>() <= max");         }         finally         {             __ContractsRuntime.insideContractEvaluation--;         }     }     return Contract.Result<int>(); } As we can see then contracts are not simply if-then-else checks and exceptions throwing. We can see that there is counter that is incremented before checks and decremented after these whatever the result of check was. One thing that is annoying for me are null checks for exception1 and exception2. Is there really some situation possible when null is thrown instead of some instance that is Exception or that inherits from exception? Conclusion Code contracts are more complex mechanism that it seems when we look at it on our code level. Internally there are done more things than we know. I don’t say it is wrong, it is just good to know how our code looks after compiling. Looking at this example it is sure we need also performance tests for contracted code to see how heavy is their impact to system performance when we run code that makes heavy use of code contracts.

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  • What's wrong with this answer? [migrated]

    - by MikeLJ
    I wrote an answer to this question, but I can't post it even though it's not opinion based. which tile size to choice for 16-bits What's wrong with my answer? The Answer: I'll use these classic 16-bit consoles as reference: http://en.wikipedia.org/wiki/History_of_video_game_consoles_(fourth_generation) Super Nintendo: Max Resolution: 512x478 Sprites On Screen: 128 Max Sprite Size: 8×8. TurboGrafx-16: Max Resolution: 565x242 "Normal" resolution: 256×239 Sprites On Screen: 64 Max Sprite Sizes: 32×64 Neo Geo: Display resolution: 320×224 "Normal" Resolution: 304x224 Sprites on screen: 380 Max Sprite Size: 16x512

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  • Why won't 2GB of ram across 3 of 4 slots work on my motherboard (max 2GB)?

    - by Andrew
    My desktop is an old home-built machine circa 200[5-6] running Ubuntu 11.10 (but this is not relevant because I'm reading available ram from BIOS loading screen), with an ASUS P5GPL motherboard, not X or X-SE - it has four slots. I'm mainly a laptop person, but keep this around for running a server from if needed, backing up to, seeding Ubuntu to people from, etc… It has four (DDR) ram slots, two black and two blue, in the order black-blue-black-blue (I will call them D, C, B, and A, respectively) with some space in the middle. The blue ones are the closest to the processor. I used to have two 512MB chips in the two blue slots. I just got a 1GB chip and plugged it into one of the black slots; my system didn't recognize it. I messed around and discovered that it will not recognize chips in many positions, and I couldn't get it to recognize all three of these chips at the same time. In particular, if I put the 512MB chips in A and B it would only use 1, but AC, AD, BD, and CD worked. I didn't try BC, I believe. Only some of these continue to work when I switch the 1GB chip into one of these positions. Can I have some advice as to how to position these chips to get all 2GB used? How about if I get another 1GB chip - where should I put the two? And what about the RAM maximum Crucial says? Can I go above 2GB, if I get another 1GB chip? Right now, I have a 512MB chip in A and the 1GB chip in C. EDIT: I read some other posts and tried dmidecode in Ubuntu to clarify the max memory question, that wasn't a major part anyways. It says my max memory module size is 1024M (OK) and my max memory size is 4096M (doesn't agree with Crucial OR the Asus web site, maybe it will only work while in Linux and BIOS won't OK it?).

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  • My VARCHAR(MAX) field is capping itself at 4000; what gives?

    - by eidylon
    Hello all... I have a table in one of my databases which is a queue of emails. Emails to certain addresses get accumulated into one email, which is done by a sproc. In the sproc, I have a table variable which I use to build the accumulated bodies of the emails, and then loop through to send each email. In my table var I have my body column defined as VARCHAR(MAX), seeing as there could be any number of emails currently accumulated for a given email address. It seems though that even though my column is defined as VARCHAR(MAX) it is behaving as if it were VARCHAR(4000) and is truncating the data going into it, although it does NOT throw any exceptions, it just silently stops concatenating any more data after 4000 characters. The MERGE statement is where it is building the accumulated email body into @EMAILS.BODY, which is the field that is truncating itself at 4000 characters. Below is the code of my sproc... ALTER PROCEDURE [system].[SendAccumulatedEmails] AS BEGIN SET NOCOUNT ON; DECLARE @SENTS BIGINT = 0; DECLARE @ROWS TABLE ( ROWID ROWID, DATED DATETIME, ADDRESS NAME, SUBJECT VARCHAR(1000), BODY VARCHAR(MAX) ) INSERT INTO @ROWS SELECT ROWID, DATED, ADDRESS, SUBJECT, BODY FROM system.EMAILQUEUE WHERE ACCUMULATE = 1 AND SENT IS NULL ORDER BY ADDRESS, DATED DECLARE @EMAILS TABLE ( ADDRESS NAME, ALLIDS VARCHAR(1000), BODY VARCHAR(MAX) ) DECLARE @PRVRID ROWID = NULL, @CURRID ROWID = NULL SELECT @CURRID = MIN(ROWID) FROM @ROWS WHILE @CURRID IS NOT NULL BEGIN MERGE @EMAILS AS DST USING (SELECT * FROM @ROWS WHERE ROWID = @CURRID) AS SRC ON SRC.ADDRESS = DST.ADDRESS WHEN MATCHED THEN UPDATE SET DST.ALLIDS = DST.ALLIDS + ', ' + CONVERT(VARCHAR,ROWID), DST.BODY = DST.BODY + '<i>'+CONVERT(VARCHAR,SRC.DATED,101)+' ' +CONVERT(VARCHAR,SRC.DATED,8) +':</i> <b>'+SRC.SUBJECT+'</b>'+CHAR(13)+SRC.BODY +' (Message ID '+CONVERT(VARCHAR,SRC.ROWID)+')' +CHAR(13)+CHAR(13) WHEN NOT MATCHED BY TARGET THEN INSERT (ADDRESS, ALLIDS, BODY) VALUES ( SRC.ADDRESS, CONVERT(VARCHAR,ROWID), '<i>'+CONVERT(VARCHAR,SRC.DATED,101)+' ' +CONVERT(VARCHAR,SRC.DATED,8)+':</i> <b>' +SRC.SUBJECT+'</b>'+CHAR(13)+SRC.BODY +' (Message ID '+CONVERT(VARCHAR,SRC.ROWID)+')' +CHAR(13)+CHAR(13)); SELECT @PRVRID = @CURRID, @CURRID = NULL SELECT @CURRID = MIN(ROWID) FROM @ROWS WHERE ROWID > @PRVRID END DECLARE @MAILFROM VARCHAR(100) = system.getOption('MAILFROM'), DECLARE @SMTPHST VARCHAR(100) = system.getOption('SMTPSERVER'), DECLARE @SMTPUSR VARCHAR(100) = system.getOption('SMTPUSER'), DECLARE @SMTPPWD VARCHAR(100) = system.getOption('SMTPPASS') DECLARE @ADDRESS NAME, @BODY VARCHAR(MAX), @ADDL VARCHAR(MAX) DECLARE @SUBJECT VARCHAR(1000) = 'Accumulated Emails from LIJSL' DECLARE @PRVID NAME = NULL, @CURID NAME = NULL SELECT @CURID = MIN(ADDRESS) FROM @EMAILS WHILE @CURID IS NOT NULL BEGIN SELECT @ADDRESS = ADDRESS, @BODY = BODY FROM @EMAILS WHERE ADDRESS = @CURID SELECT @BODY = @BODY + 'This is an automated message sent from an unmonitored mailbox.'+CHAR(13)+'Do not reply to this message; your message will not be read.' SELECT @BODY = '<style type="text/css"> * {font-family: Tahoma, Arial, Verdana;} p {margin-top: 10px; padding-top: 10px; border-top: single 1px dimgray;} p:first-child {margin-top: 10px; padding-top: 0px; border-top: none 0px transparent;} </style>' + @BODY exec system.LogIt @SUBJECT, @BODY BEGIN TRY exec system.SendMail @SMTPHST, @SMTPUSR, @SMTPPWD, @MAILFROM, @ADDRESS, NULL, NULL, @SUBJECT, @BODY, 1 END TRY BEGIN CATCH DECLARE @EMSG NVARCHAR(2048) = 'system.EMAILQUEUE.AI:'+ERROR_MESSAGE() SELECT @ADDL = 'TO:'+@ADDRESS+CHAR(13)+'SUBJECT:'+@SUBJECT+CHAR(13)+'BODY:'+@BODY exec system.LogIt @EMSG,@ADDL END CATCH SELECT @PRVID = @CURID, @CURID = NULL SELECT @CURID = MIN(ADDRESS) FROM @EMAILS WHERE ADDRESS > @PRVID END UPDATE system.EMAILQUEUE SET SENT = getdate() FROM system.EMAILQUEUE E, @ROWS R WHERE E.ROWID = R.ROWID END

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  • RHEL 6.x on Rackspace Cloud and Dedicated hardware experiencing Redis Timeouts

    - by zhallett
    I just recently set up a mixture of RHEL 6.1 Rackspace cloud hosts and RHEL 6.2 dedicated hosts using Rackconnect. I am experiencing intermittent Redis timeouts from within our Rails 3.2.8 app with Redis 2.4.16 running on the RHEL 6.2 dedicated hosts. There is no network latency or packet loss. Also there are no errors on any interfaces on our cloud or dedicated servers or on the managed firewall from Rackspace. When Redis timesout, there is nothing logged within redis even though it is set up to do debug logging. The only error we receive is from Airbrake saying there was a Redis timeout. Network topology: RHEL 6.1 cloud hosts <--> Alert logic IDS <--> Cisco ASA 5510 <--> RHEL 6.2 dedicated hosts (web nodes) (two way NAT) (db hosts running redis) Ping from db host to web host: 64 bytes from 10.181.230.180: icmp_seq=998 ttl=64 time=0.520 ms 64 bytes from 10.181.230.180: icmp_seq=999 ttl=64 time=0.579 ms 64 bytes from 10.181.230.180: icmp_seq=1000 ttl=64 time=0.482 ms --- web1.xxxxxx.com ping statistics --- 1000 packets transmitted, 1000 received, 0% packet loss, time 999007ms rtt min/avg/max/mdev = 0.359/0.535/5.684/0.200 ms Ping from web host to db host: 64 bytes from 192.168.100.26: icmp_seq=998 ttl=64 time=0.544 ms 64 bytes from 192.168.100.26: icmp_seq=999 ttl=64 time=0.452 ms 64 bytes from 192.168.100.26: icmp_seq=1000 ttl=64 time=0.529 ms --- data1.xxxxxx.com ping statistics --- 1000 packets transmitted, 1000 received, 0% packet loss, time 999017ms rtt min/avg/max/mdev = 0.358/0.499/6.120/0.201 ms Redis config: daemonize yes pidfile /var/run/redis/6379/redis_6379.pid port 6379 timeout 0 loglevel debug logfile /var/lib/redis/log syslog-enabled yes syslog-ident redis-6379 syslog-facility local0 databases 16 save 900 1 save 300 10 save 60 10000 rdbcompression yes dbfilename dump-6379.rdb dir /var/lib/redis maxclients 10000 maxmemory-policy volatile-lru maxmemory-samples 3 appendfilename appendonly-6379.aof appendfsync everysec no-appendfsync-on-rewrite no auto-aof-rewrite-percentage 100 auto-aof-rewrite-min-size 64mb slowlog-log-slower-than 10000 slowlog-max-len 1024 vm-enabled no vm-swap-file /tmp/redis.swap vm-max-memory 0 vm-page-size 32 vm-pages 134217728 vm-max-threads 4 hash-max-zipmap-entries 512 hash-max-zipmap-value 64 list-max-ziplist-entries 512 list-max-ziplist-value 64 set-max-intset-entries 512 zset-max-ziplist-entries 128 zset-max-ziplist-value 64 activerehashing yes Redis-cli info: redis-cli info redis_version:2.4.16 redis_git_sha1:00000000 redis_git_dirty:0 arch_bits:64 multiplexing_api:epoll gcc_version:4.4.6 process_id:4174 uptime_in_seconds:79346 uptime_in_days:0 lru_clock:1064644 used_cpu_sys:13.08 used_cpu_user:19.81 used_cpu_sys_children:1.56 used_cpu_user_children:7.69 connected_clients:167 connected_slaves:0 client_longest_output_list:0 client_biggest_input_buf:0 blocked_clients:6 used_memory:15060312 used_memory_human:14.36M used_memory_rss:22061056 used_memory_peak:15265928 used_memory_peak_human:14.56M mem_fragmentation_ratio:1.46 mem_allocator:jemalloc-3.0.0 loading:0 aof_enabled:0 changes_since_last_save:166 bgsave_in_progress:0 last_save_time:1352823542 bgrewriteaof_in_progress:0 total_connections_received:286 total_commands_processed:507254 expired_keys:0 evicted_keys:0 keyspace_hits:1509 keyspace_misses:65167 pubsub_channels:0 pubsub_patterns:0 latest_fork_usec:690 vm_enabled:0 role:master db0:keys=6,expires=0 edit 1: add redis-cli info output

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  • Perl: Negative look behind regex question [migrated]

    - by James
    The Perlre in Perldoc didn't go into much detail on negative look around but I tried testing it, and didn't work as expected. I want to see if I can differentiate a C preprocessor macro definition (e.g. #define MAX(X) ....) from actual usage (y = MAX(x);), but it didn't work as expected. my $macroName = 'MAX'; my $macroCall = "y = MAX(X);"; my $macroDef = "# define MAX(X)"; my $boundary = qr{\b$macroName\b}; my $bstr = " MAX(X)"; if($bstr =~ /$boundary/) { print "boundary: $bstr matches: $boundary\n"; } else { print "Error: no match: boundary: $bstr, $boundary\n"; } my $negLookBehind = qr{(?<!define)\b$macroName\b}; if($macroCall =~ /$negLookBehind/) # "y = MAX(X)" matches "(?<!define)\bMAX\b" { print "negative look behind: $macroCall matches: $negLookBehind\n"; } else { print "no match: negative look behind: $macroCall, $negLookBehind\n"; } if($macroDef =~ /$negLookBehind/) # "#define MAX(X)" should not match "(?<!define)\bMAX\b" { print "Error: negative look behind: $macroDef matches: $negLookBehind\n"; } else { print "no match: negative look behind: $macroDef, $negLookBehind\n"; } It seems that both $macroDef and $macroCall seem to match regex /(?<!define)\b$macroName\b/. I backed off from the original /(?<\#)\s*(?<!define)\b$macroName\b/ since that didn't work either. So what did I screw up? Also does Perl allow chaining of multiple look around expressions?

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  • Why aren't min-width and max-width working as I expect?

    - by Nathan Long
    I'm trying to adjust a CSS page layout using min-width and max-width. To simplify the problem, I made this test page. I'm trying it out in the latest versions of Firefox and Chrome with the same results. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Testing min-width and max-width</title> <style type="text/css"> div{float: left; max-width: 400px; min-width: 200px;} div.a{background: orange;} div.b{background: gray;} </style> </head> <body> <div class="a"> (Giant block of filler text here) </div> <div class="b"> (Giant block of filler text here) </div> </body> </html> Here's what I expect to happen: With the browser maximized, the divs sit side by side, each 400px wide: their maximum width Shrink the browser window, and they both shrink to 200px: their minimum width Further shrinking the browser has no effect on them Here's what actually happens, starting at step 2: Shrink the browser window, and as soon as they can't sit side-by-side at their max width, the second div drops below the first Further shrinking the browser makes them get narrower and narrower, as small as I can make the window So here's are my questions: What does max-width mean if the element will sooner hop down in the layout than go lower than its maximum width? What does min-width mean if the element will happily get narrower than that if the browser window keeps shrinking? Is there any way to achieve what I want: have these elements sit side-by-side, happily shrinking until they reach 200px each, and only then adjust the layout so that the second one drops down? And of course... What am I doing wrong?

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  • Liquid Layout: 100% max-width img not applied - why?

    - by MEM
    I'm totally new to this liquid layout stuff. I've notice, as most of us, that while most of my layout components "liquify", images, unfortunately, don't. So I'm trying to use the max-width: 100% on images as suggested on several places. However, and despite the definition of max-width and min-height of the img container, the img don't scale. Sample code: CSS img { max-width: 100%; } article { float: left; margin: 30px 1%; max-width: 31%; min-height: 350px; } HTML <article> <header> <h2>some header</h2> </header> <img src="/images/thumb1.jpg" alt="thumb"> <p>Vestibulum ante ipsum primis in faucibus orci luctus et ultrices posuere cubilia Curae; Proin vel ante a orci tempus eleifend.</p> </article> Please have a look on the following link: http://tinyurl.com/d849f8x If you see it on a wide resolution, you will notice that the "kid image", for example, don't scale. Any clue about what could the issue be, why does that image not scale? Test case: Browsers: Firefox 15.0 / Chrome 21.0 IOS: MAC OS X Lion - 10.7.3 Resolution: 1920x1200 What I get: I get an image that doesn't scale until the end of it's container. The img width won't fit the article element that contains it. What I do expect: I expect the image to enlarge, until it reaches the end it's container. Visually, I'm expecting the image to be as wide as the paragraph immediately below, in a way that, the right side of the image stays vertically aligned with the right side of the paragraph below.

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  • Interface contracts – forcing code contracts through interfaces

    - by DigiMortal
    Sometimes we need a way to make different implementations of same interface follow same rules. One option is to duplicate contracts to all implementation but this is not good option because we have duplicated code then. The other option is to force contracts to all implementations at interface level. In this posting I will show you how to do it using interface contracts and contracts class. Using code from previous example about unit testing code with code contracts I will go further and force contracts at interface level. Here is the code from previous example. Take a careful look at it because I will talk about some modifications to this code soon. public interface IRandomGenerator {     int Next(int min, int max); }   public class RandomGenerator : IRandomGenerator {     private Random _random = new Random();       public int Next(int min, int max)     {         return _random.Next(min, max);     } }    public class Randomizer {     private IRandomGenerator _generator;       private Randomizer()     {         _generator = new RandomGenerator();     }       public Randomizer(IRandomGenerator generator)     {         _generator = generator;     }       public int GetRandomFromRangeContracted(int min, int max)     {         Contract.Requires<ArgumentOutOfRangeException>(             min < max,             "Min must be less than max"         );           Contract.Ensures(             Contract.Result<int>() >= min &&             Contract.Result<int>() <= max,             "Return value is out of range"         );           return _generator.Next(min, max);     } } If we look at the GetRandomFromRangeContracted() method we can see that contracts set in this method are applicable to all implementations of IRandomGenerator interface. Although we can write new implementations as we want these implementations need exactly the same contracts. If we are using generators somewhere else then code contracts are not with them anymore. To solve the problem we will force code contracts at interface level. NB! To make the following code work you must enable Contract Reference Assembly building from project settings. Interface contracts and contracts class Interface contains no code – only definitions of members that implementing type must have. But code contracts must be defined in body of member they are part of. To get over this limitation, code contracts are defined in separate contracts class. Interface is bound to this class by special attribute and contracts class refers to interface through special attribute. Here is the IRandomGenerator with contracts and contracts class. Also I write simple fake so we can test contracts easily based only on interface mock. [ContractClass(typeof(RandomGeneratorContracts))] public interface IRandomGenerator {     int Next(int min, int max); }   [ContractClassFor(typeof(IRandomGenerator))] internal sealed class RandomGeneratorContracts : IRandomGenerator {     int IRandomGenerator.Next(int min, int max)     {         Contract.Requires<ArgumentOutOfRangeException>(                 min < max,                 "Min must be less than max"             );           Contract.Ensures(             Contract.Result<int>() >= min &&             Contract.Result<int>() <= max,             "Return value is out of range"         );           return default(int);     } }   public class RandomFake : IRandomGenerator {     private int _testValue;       public RandomGen(int testValue)     {         _testValue = testValue;     }       public int Next(int min, int max)     {         return _testValue;     } } To try out these changes use the following code. var gen = new RandomFake(3);   try {     gen.Next(10, 1); } catch(Exception ex) {     Debug.WriteLine(ex.Message); }   try {     gen.Next(5, 10); } catch(Exception ex) {     Debug.WriteLine(ex.Message); } Now we can force code contracts to all types that implement our IRandomGenerator interface and we must test only the interface to make sure that contracts are defined correctly.

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  • eeePC 1001HA/1101HA max resolution when connected to external display?

    - by Marco Demaio
    Hello, I would like to buy a new Eee PC 1001HA or 1101HA. I know the max display resolution is: 1024x600 for eeePC 1001 and 1366x768 for eeePC 1101 But what's the max resolution of the graphic board when connecting these two types of eeePC to an external LCD monitor??? Let's say the external LCD monitor supports a full HD resolution of 1920x1080, are these eeePC graphic boards able to go up to such resolution??? It's really incredible to me, how such a useful information is missing everywhere on every ASUS website. Eee PC are very well suited to be connected to external monitor, so I can't believe how difficult is to find out this information. I downloaded aldo the manual, but it's not in there too. So I was hoping somone has got one and knows the answer. Thanks!

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  • What does the "Max Memory Size" on the new Intel Core i3 / i5 / i7 CPU's mean?

    - by Josh
    I just noticed in the specs of the new Intel Core i-series processors that there is a "Max Memory Size" that is usually pretty small -- anywhere from 8GB to 24GB. See here: http://ark.intel.com/Product.aspx?id=41316 Core 2-based motherboards were just starting to roll out support for 32GB and greater memory sizes. Anyone have any idea what the Max Memory Size indicates? Is this the total limitation of the on-chip memory controller? Limitation per channel? Limitation per stick (e.g. density??)? Thinking of building a decent machine that needs lots of RAM, so I'm looking at the i7 860.

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  • Can the JVM(Oracle) run into an OutOfMemory error if the heap size is below the max?

    - by user439407
    I am running a Tomcat site(with an NGinx front end) that seems to be randomly running out of memory even though the max heap size is pretty large. My question is is it possible for the JVM to get an OutOfMemory error even if the heap size is significantly less than -Xmx? For instance, here is a snapshot I took just 15 seconds before an OutOfMemory error: Tue Dec 18 23:13:28 JST 2012 Free memory: 162.31 MB Total memory: 727.75 MB Max memory: 3808.00 MB I guess theoretically it's possible that my code generated 3 gigs worth of objects in 15 seconds, but I highly doubt it. It seems like the JVM was unable to grow the heap even though it theoretically had room....Is it possible that other processes started using memory to the point that the JVM could not grow? I am running 64-bit Oracle Hotspot on a 64 bit vm running CentOS 5 with 6 gigs of ram.

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  • Using BPEL Performance Statistics to Diagnose Performance Bottlenecks

    - by fip
    Tuning performance of Oracle SOA 11G applications could be challenging. Because SOA is a platform for you to build composite applications that connect many applications and "services", when the overall performance is slow, the bottlenecks could be anywhere in the system: the applications/services that SOA connects to, the infrastructure database, or the SOA server itself.How to quickly identify the bottleneck becomes crucial in tuning the overall performance. Fortunately, the BPEL engine in Oracle SOA 11G (and 10G, for that matter) collects BPEL Engine Performance Statistics, which show the latencies of low level BPEL engine activities. The BPEL engine performance statistics can make it a bit easier for you to identify the performance bottleneck. Although the BPEL engine performance statistics are always available, the access to and interpretation of them are somewhat obscure in the early and current (PS5) 11G versions. This blog attempts to offer instructions that help you to enable, retrieve and interpret the performance statistics, before the future versions provides a more pleasant user experience. Overview of BPEL Engine Performance Statistics  SOA BPEL has a feature of collecting some performance statistics and store them in memory. One MBean attribute, StatLastN, configures the size of the memory buffer to store the statistics. This memory buffer is a "moving window", in a way that old statistics will be flushed out by the new if the amount of data exceeds the buffer size. Since the buffer size is limited by StatLastN, impacts of statistics collection on performance is minimal. By default StatLastN=-1, which means no collection of performance data. Once the statistics are collected in the memory buffer, they can be retrieved via another MBean oracle.as.soainfra.bpel:Location=[Server Name],name=BPELEngine,type=BPELEngine.> My friend in Oracle SOA development wrote this simple 'bpelstat' web app that looks up and retrieves the performance data from the MBean and displays it in a human readable form. It does not have beautiful UI but it is fairly useful. Although in Oracle SOA 11.1.1.5 onwards the same statistics can be viewed via a more elegant UI under "request break down" at EM -> SOA Infrastructure -> Service Engines -> BPEL -> Statistics, some unsophisticated minds like mine may still prefer the simplicity of the 'bpelstat' JSP. One thing that simple JSP does do well is that you can save the page and send it to someone to further analyze Follows are the instructions of how to install and invoke the BPEL statistic JSP. My friend in SOA Development will soon blog about interpreting the statistics. Stay tuned. Step1: Enable BPEL Engine Statistics for Each SOA Servers via Enterprise Manager First st you need to set the StatLastN to some number as a way to enable the collection of BPEL Engine Performance Statistics EM Console -> soa-infra(Server Name) -> SOA Infrastructure -> SOA Administration -> BPEL Properties Click on "More BPEL Configuration Properties" Click on attribute "StatLastN", set its value to some integer number. Typically you want to set it 1000 or more. Step 2: Download and Deploy bpelstat.war File to Admin Server, Note: the WAR file contains a JSP that does NOT have any security restriction. You do NOT want to keep in your production server for a long time as it is a security hazard. Deactivate the war once you are done. Download the bpelstat.war to your local PC At WebLogic Console, Go to Deployments -> Install Click on the "upload your file(s)" Click the "Browse" button to upload the deployment to Admin Server Accept the uploaded file as the path, click next Check the default option "Install this deployment as an application" Check "AdminServer" as the target server Finish the rest of the deployment with default settings Console -> Deployments Check the box next to "bpelstat" application Click on the "Start" button. It will change the state of the app from "prepared" to "active" Step 3: Invoke the BPEL Statistic Tool The BPELStat tool merely call the MBean of BPEL server and collects and display the in-memory performance statics. You usually want to do that after some peak loads. Go to http://<admin-server-host>:<admin-server-port>/bpelstat Enter the correct admin hostname, port, username and password Enter the SOA Server Name from which you want to collect the performance statistics. For example, SOA_MS1, etc. Click Submit Keep doing the same for all SOA servers. Step 3: Interpret the BPEL Engine Statistics You will see a few categories of BPEL Statistics from the JSP Page. First it starts with the overall latency of BPEL processes, grouped by synchronous and asynchronous processes. Then it provides the further break down of the measurements through the life time of a BPEL request, which is called the "request break down". 1. Overall latency of BPEL processes The top of the page shows that the elapse time of executing the synchronous process TestSyncBPELProcess from the composite TestComposite averages at about 1543.21ms, while the elapse time of executing the asynchronous process TestAsyncBPELProcess from the composite TestComposite2 averages at about 1765.43ms. The maximum and minimum latency were also shown. Synchronous process statistics <statistics>     <stats key="default/TestComposite!2.0.2-ScopedJMSOSB*soa_bfba2527-a9ba-41a7-95c5-87e49c32f4ff/TestSyncBPELProcess" min="1234" max="4567" average="1543.21" count="1000">     </stats> </statistics> Asynchronous process statistics <statistics>     <stats key="default/TestComposite2!2.0.2-ScopedJMSOSB*soa_bfba2527-a9ba-41a7-95c5-87e49c32f4ff/TestAsyncBPELProcess" min="2234" max="3234" average="1765.43" count="1000">     </stats> </statistics> 2. Request break down Under the overall latency categorized by synchronous and asynchronous processes is the "Request breakdown". Organized by statistic keys, the Request breakdown gives finer grain performance statistics through the life time of the BPEL requests.It uses indention to show the hierarchy of the statistics. Request breakdown <statistics>     <stats key="eng-composite-request" min="0" max="0" average="0.0" count="0">         <stats key="eng-single-request" min="22" max="606" average="258.43" count="277">             <stats key="populate-context" min="0" max="0" average="0.0" count="248"> Please note that in SOA 11.1.1.6, the statistics under Request breakdown is aggregated together cross all the BPEL processes based on statistic keys. It does not differentiate between BPEL processes. If two BPEL processes happen to have the statistic that share same statistic key, the statistics from two BPEL processes will be aggregated together. Keep this in mind when we go through more details below. 2.1 BPEL process activity latencies A very useful measurement in the Request Breakdown is the performance statistics of the BPEL activities you put in your BPEL processes: Assign, Invoke, Receive, etc. The names of the measurement in the JSP page directly come from the names to assign to each BPEL activity. These measurements are under the statistic key "actual-perform" Example 1:  Follows is the measurement for BPEL activity "AssignInvokeCreditProvider_Input", which looks like the Assign activity in a BPEL process that assign an input variable before passing it to the invocation:                                <stats key="AssignInvokeCreditProvider_Input" min="1" max="8" average="1.9" count="153">                                     <stats key="sensor-send-activity-data" min="0" max="1" average="0.0" count="306">                                     </stats>                                     <stats key="sensor-send-variable-data" min="0" max="0" average="0.0" count="153">                                     </stats>                                     <stats key="monitor-send-activity-data" min="0" max="0" average="0.0" count="306">                                     </stats>                                 </stats> Note: because as previously mentioned that the statistics cross all BPEL processes are aggregated together based on statistic keys, if two BPEL processes happen to name their Invoke activity the same name, they will show up at one measurement (i.e. statistic key). Example 2: Follows is the measurement of BPEL activity called "InvokeCreditProvider". You can not only see that by average it takes 3.31ms to finish this call (pretty fast) but also you can see from the further break down that most of this 3.31 ms was spent on the "invoke-service".                                  <stats key="InvokeCreditProvider" min="1" max="13" average="3.31" count="153">                                     <stats key="initiate-correlation-set-again" min="0" max="0" average="0.0" count="153">                                     </stats>                                     <stats key="invoke-service" min="1" max="13" average="3.08" count="153">                                         <stats key="prep-call" min="0" max="1" average="0.04" count="153">                                         </stats>                                     </stats>                                     <stats key="initiate-correlation-set" min="0" max="0" average="0.0" count="153">                                     </stats>                                     <stats key="sensor-send-activity-data" min="0" max="0" average="0.0" count="306">                                     </stats>                                     <stats key="sensor-send-variable-data" min="0" max="0" average="0.0" count="153">                                     </stats>                                     <stats key="monitor-send-activity-data" min="0" max="0" average="0.0" count="306">                                     </stats>                                     <stats key="update-audit-trail" min="0" max="2" average="0.03" count="153">                                     </stats>                                 </stats> 2.2 BPEL engine activity latency Another type of measurements under Request breakdown are the latencies of underlying system level engine activities. These activities are not directly tied to a particular BPEL process or process activity, but they are critical factors in the overall engine performance. These activities include the latency of saving asynchronous requests to database, and latency of process dehydration. My friend Malkit Bhasin is working on providing more information on interpreting the statistics on engine activities on his blog (https://blogs.oracle.com/malkit/). I will update this blog once the information becomes available. Update on 2012-10-02: My friend Malkit Bhasin has published the detail interpretation of the BPEL service engine statistics at his blog http://malkit.blogspot.com/2012/09/oracle-bpel-engine-soa-suite.html.

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  • How can I make a universal construction more efficient?

    - by VF1
    A "universal construction" is a wrapper class for a sequential object that enables it to be linearized (a strong consistency condition for concurrent objects). For instance, here's an adapted wait-free construction, in Java, from [1], which presumes the existence of a wait-free queue that satisfies the interface WFQ (which only requires one-time consensus between threads) and assumes a Sequential interface: public interface WFQ<T> // "FIFO" iteration { int enqueue(T t); // returns the sequence number of t Iterable<T> iterateUntil(int max); // iterates until sequence max } public interface Sequential { // Apply an invocation (method + arguments) // and get a response (return value + state) Response apply(Invocation i); } public interface Factory<T> { T generate(); } // generate new default object public interface Universal extends Sequential {} public class SlowUniversal implements Universal { Factory<? extends Sequential> generator; WFQ<Invocation> wfq = new WFQ<Invocation>(); Universal(Factory<? extends Sequential> g) { generator = g; } public Response apply(Invocation i) { int max = wfq.enqueue(i); Sequential s = generator.generate(); for(Invocation invoc : wfq.iterateUntil(max)) s.apply(invoc); return s.apply(i); } } This implementation isn't very satisfying, however, since it presumes determinism of a Sequential and is really slow. I attempted to add memory recycling: public interface WFQD<T> extends WFQ<T> { T dequeue(int n); } // dequeues only when n is the tail, else assists other threads public interface CopyableSequential extends Sequential { CopyableSequential copy(); } public class RecyclingUniversal implements Universal { WFQD<CopyableSequential> wfqd = new WFQD<CopyableSequential>(); Universal(CopyableSequential init) { wfqd.enqueue(init); } public Response apply(Invocation i) { int max = wfqd.enqueue(i); CopyableSequential cs = null; int ctr = max; for(CopyableSequential csq : wfq.iterateUntil(max)) if(--max == 0) cs = csq.copy(); wfqd.dequeue(max); return cs.apply(i); } } Here are my specific questions regarding the extension: Does my implementation create a linearizable multi-threaded version of a CopyableSequential? Is it possible extend memory recycling without extending the interface (perhaps my new methods trivialize the problem)? My implementation only reduces memory when a thread returns, so can this be strengthened? [1] provided an implementation for WFQ<T>, not WFQD<T> - one does exist, though, correct? [1] Herlihy and Shavit, The Art of Multiprocessor Programming.

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  • Write a program using 3 threads, one prints 10 'A's and the second prints 'B's and the third prints 10 'C's with synchrornization

    - by user132967
    Iam try to implement this questions using threads and mutex this is my code : include include include include include define Num_thread 3 pthread_mutex_t lett[Num_thread]; void Sleep_rand(double max) { struct timespec delai; delai.tv_sec=max; delai.tv_nsec=0; nanosleep(&delai,NULL); } void *Print_Sequence(); int main() { int i; pthread_t tid[Num_thread];// this is threads identifier for(i=0;i<Num_thread;i++) pthread_mutex_init(&lett[i],0); for(i=0;i<Num_thread;i++) { printf("i=%d\n",i); /* create the threads / pthread_create(&tid[i], / This variable will have the thread is after successful creation / NULL, / send the thread attributes / Print_Sequence, / the function the thread will run / &i/ send the parameter's address to the function */); } /* Wait till threads are complete and join before main continues */ for (i = 0; i pthread_join(tid[i], NULL); } return 0; } /* The thread will begin control in this function */ void Print_Sequence(void param) { int i,j=(int)param; printf("j=%d\n",(*j)); int max; pthread_mutex_lock(&lett[0]); pthread_mutex_lock(&lett[1]); for (i = 1; i <= 10; i++) { max=(int) (8*rand()/(RAND_MAX+1.0)); Sleep_rand( max); printf("A"); } pthread_mutex_unlock(&lett[0]); pthread_mutex_lock(&lett[2]); for (i = 1; i <= 10; i++) { max=(int) (2*rand()/(RAND_MAX+1.0)); Sleep_rand( max); printf("B"); } for (i = 1; i <= 10; i++) { max=(int) (15*rand()/(RAND_MAX+1.0)); Sleep_rand( max); printf("C"); } pthread_mutex_unlock(&lett[1]); pthread_mutex_unlock(&lett[2]); pthread_exit(0); } and the o/p is like : AAAAAAAAAABBBBBBBBBBCCCCCCCCCCAAAAAAAAAABBBBBBBBBBCCCCCCCCCCAAAAAAAAAABBBBBBBBBBCCCCCCCCCC COULD ANYONE PLEASE EXPLAIN WHAT IS THE WRONG WITH CODE ??

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