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  • select multiple double side

    - by Mercer
    hello, i want to do a select multiple double side like this : http://www.senamion.com/blog/jmultiselect2side.html (Demo2) but i don't know how i can retrieve my data when i click submit button..?

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  • MYSQL Select statment Order By with Group By

    - by mouthpiec
    I have the following simple SQL statment SELECT id, name, value_name, value_id FROM table GROUP BY id ORDER BY value_id DESC when grouping I would like to get the value_name and value_id of the tuple where the value_id is the biggest. The way it is i am getting the smallest value. For example 1, name1, valuename, 3 (where i know that there is a value_id of 5) Can you please help?

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  • SQL Complex Select - Trouble forming query

    - by JoshSpacher
    I have three tables, Customers, Sales and Products. Sales links a CustomerID with a ProductID and has a SalesPrice. select Products.Category, AVG(SalePrice) from Sales inner join Products on Products.ProductID = Sales.ProductID group by Products.Category This lets me see the average price for all sales by category. However, I only want to include customers that have more than 3 sales records or more in the DB. I am not sure the best way, or any way, to go about this. Ideas?

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  • CSS Doozie: Replacing BG Image on SELECT dropdown

    - by ToiletOverflow
    I need to be able to change the background-image property of a SELECT drop-down using JavaScript/CSS. We have been able to accomplish this in Firefox, but it doesn't appear to be supported at all in IE. From what I've read, IE won't support this. But I'm wondering if there's anything else I could try. Does anyone here have any recommendations?

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  • MySQL get variable from SELECT

    - by rlb.usa
    MySQL keeps saying my syntax is incorrect. I want to do this: DELIMITER $$ DROP PROCEDURE IF EXISTS `myprocedure` $$ CREATE DEFINER=`db`@`%` PROCEDURE `myprocedure`( var_name varchar(10) ) BEGIN /* syntax errors below */ DECLARE countTemp integer; SET countTemp=(SELECT COUNT(Name) FROM mytable WHERE Name= var_name); /* more stuff */ END $$ DELIMITER ; What's the correct syntax?

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  • MySQL select one field from table WHERE condition is in multiple rows

    - by Alex
    Tried to find the answer, but still couldn't.. The table is as follows: id, keyword, value 1 display 15.6 1 harddrive 320 1 ram 3 So what i need is something like this.. Select an id from this table where (keyword="display" and value="15.6") AND (keyword="harddrive" and value="320") There's also a possibility that there will be 3 or 4 such keyword conditions which should result into returning one id (one row) It seems there's something to deal with UNION but i didn't use it before so i can't figure it out Thanks in advance

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  • IE font size decrease does not cause select box height to decrease

    - by leaf dev
    I have a font resize function on my page which increases the font size via javascript for the entire page. This works fine in most browsers except IE. When decreasing the font size after increasing it, the select boxes new height does not decrease, even though the font size is decreasing on it. Instead the smaller font appears to be padded with white space. Any ideas as to what IE is doing here, and a work around?

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  • SQL select from last inserted

    - by arik-so
    Hello, in MySQL, I have table. One column has auto-increment. When I insert something mysql_query('INSERT INTO `table` SET `column` = "data";'); Now, what I want is, without further queries, to get the value of the auto-incrementing column, maybe like this: mysql_query('insertion = (INSERT INTO `table` SET `column` = "data"); SELECT `auto_incrementing_column` FROM `table`.insertion'); Please tell me how something like that is done. Thanks in advance!

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  • jquery autocomplete: works for first value, how to enable it for next?

    - by Toni Michel Caubet
    hello there! I'm using autocomplete so user can easly enter data on inputs, like this: <? $a = new etiqueta(0, ''); $b = $a->autocomplete_etiquetas(); ?> <script type="text/javascript"> function cargar_autocomplete_etiquetas(){ $("#tags").autocomplete({ source: [<? echo $b; ?>] }); } </script> $a = $b its an array with a result like: 'help','please',i','need','to,'be able to', 'select next item',' with autocomplete'; and i checked the ui documentation, but it doesn't fith with my source method.. any idea? I'm trying like this (edited with Bugai13 aportation): <? $a = new etiqueta(0, ''); $b = $a->autocomplete_etiquetas(); ?> <script type="text/javascript"> function cargar_autocomplete_etiquetas(){ $("#tags").autocomplete({ source: [<? echo $b; ?>], multiple: true, multipleSeparator: ", ", matchContains: true }); } </script> but i don't know how to do it.. any idea? are .push and .pop functions from the autocomplete? or shall i define, them? thanks again! PS: i'm getting adicted to this site! PS: come on dudes, i think the answer will be very usefull for many people PS: is it allowed to offer paypal reward?

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  • how to disable a jqgrid select list (dropdown) on the edit form

    - by MikeD
    This is strange and any alternative method to what I want to accomplish is welcome. My app uses the jqgrid 3.5.3 and I need to disable a select list on my edit form. When I do so using the code displayed below it breaks the edit form - meaning I can not cancel or submit it. Thanks. This code is in the edit options array of the navGrid method. The the dropdown is the 'serv_descr' field. The others are text boxes and don't pose a problem. The form does come up and the field is disabled - its just broken. beforeShowForm: function(eparams) { document.getElementById('equip_id').disabled = true; document.getElementById('service_dt').disabled = true; document.getElementById('serv_descr').disabled = true; document.getElementById('calc_next_svc').checked = 'true'; }

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  • I can't get onChange to fire for dijit.form.Select

    - by user306462
    I seem unable to correctly attach the onchange event to a dijit.form.Select widget. However, I am new to web development, so I could be doing something completely idiotic (although, as best I can tell (and I've read all the docs I could find) I'm not). I made sure the body class matches the dojo theme, that I dojo.require() for all the widgets I use (and dojo.parser), and still, nada. The code I'm using is: dojo.addOnLoad (function () { var _query = dojo.query('.toggle'); for (var i=0; i < _query.length; i++) { dojo.connect(_query[i], 'onchange', function (ev) { console.log(ev + ' fired onchange'); }); } }); Any help at all would be appreciated.

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  • How to correctly filter a datatable (datatable.select)

    - by Phil
    Dim dt As New DataTable Dim da As New SqlDataAdapter(s, c) c.Open() If Not IsNothing(da) Then da.Fill(dt) dt.Select("GroupingID = 0") End If GridView1.DataSource = dt GridView1.DataBind() c.Close() When I call da.fill I am inserting all records from my query. I was then hoping to filter them to display only those where the GroupingID is equal to 0. When I run the above code. I am presented with all the data, the filter did not work. Please can you tell me how to get this working correctly. Thanks.

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  • MySQL SELECT MAX multiple tables : foreach parent return eldest son's picture

    - by Guillermo
    **Table parent** parentId | name **Table children** childId | parentId | pictureId | age **Table childrenPictures** pictureId | imgUrl no i would like to return all parent names with their eldest son's picture (only return parents that have children, and only consider children that have pictures) so i thought of something like : SELECT c.childId AS childId, p.name AS parentName, cp.imgUrl AS imgUrl, MAX(c.age) AS age FROM parent AS p RIGHT JOIN children AS c ON (p.parentId = c.parentId) RIGHT JOIN childrenPictures AS cp ON (c.pictureId = cp.pictureId)) GROUP BY p.name This query will return each parent's eldest son's age, but the childId will not correspond to the eldest sons id, so the output does not show the right sons picture. Well if anyone has a hint i'd appreciate very much Thank you very much, G

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  • MySQL select using datetime, group by date only

    - by Matt
    Is is possible to select a datetime field from a MySQL table and group by the date only? I'm trying to output a list of events that happen at multiple times, grouped by the date it happened on. My table/data looks like this: (the timestamp is a datetime field) 1. 2010-03-21 18:00:00 Event1 2. 2010-03-21 18:30:00 Event2 3. 2010-03-30 13:00:00 Event3 4. 2010-03-30 14:00:00 Event4 I want to output something like this: March 21st 1800 - Event 1 1830 - Event 2 March 30th 1300 - Event 3 1400 - Event 4 Thanks!

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  • Mysql : Request to select the last 10 send/received messages to/by different users

    - by Yako malin
    Hello, I want to select the 10 last messages you received OR you sent TO different users. For example the results must be shown like that : 1. John1 - last message received 04/17/10 3:12 2. Thomy - last message sent 04/16/10 1:26 3. Pamela - last message received 04/12/10 3:51 4. Freddy - last message received 03/28/10 9:00 5. Jack - last message sent 03/20/10 4:53 6. Tom - last message received 02/01/10 7:41 ..... Table looks like : CREATE TABLE `messages` ( `id` int(11) NOT NULL AUTO_INCREMENT, `time` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, `sender` int(11) DEFAULT NULL, `receiver` int(11) DEFAULT NULL, `content` text ) Have someone any solution ? Thanks in advance for your help.

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  • performance issue in a select query from a single table

    - by daedlus
    Hi , I have a table as below dbo.UserLogs ------------------------------------- Id | UserId |Date | Name| P1 | Dirty ------------------------------------- There can be several records per userId[even in millions] I have clustered index on Date column and query this table very frequently in time ranges. The column 'Dirty' is non-nullable and can take either 0 or 1 only so I have no indexes on 'Dirty' I have several millions of records in this table and in one particular case in my application i need to query this table to get all UserId that have at least one record that is marked dirty. I tried this query - select distinct(UserId) from UserLogs where Dirty=1 I have 10 million records in total and this takes like 10min to run and i want this to run much faster than this. [i am able to query this table on date column in less than a minute.] Any comments/suggestion are welcome. my env 64bit,sybase15.0.3,Linux

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  • Select from mysql by day with different timezones (php)

    - by Adam
    I'm storing leads in a database, and each lead has a datetime field with a PST timezone based date & time. I want my user to be able to display all leads from a certain date (e.g. today, yseterday), and choose the timezone. E.g. if I want to see all leads that were generated yesterday in EST timezone, I need to first convert (or read) all the datetime values to EST, and then only select those who are in the right range (yesterday). What would be the best way to do that?

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  • MYSQL select query where multiple conditions in same column must exist

    - by David
    I'm putting together a dating site and I'm having a mysql query issue. This works: SELECT * FROM `user` , `desired_partner` , `user_personality` WHERE dob BETWEEN '1957-05-18' AND '1988-05-18' AND country_id = '190' AND user.gender_id = '1' AND user.user_id = desired_partner.user_id AND desired_partner.gender_id = '2' AND user.user_id = user_personality.user_id AND user_personality.personality_id = '2' The sql finds any male (gender_id=1) with ATLEAST personality trait 2 (and possibly other personality traits) between certain age range in the USA (country_id=190) looking for a female (gender_id=2). Question 1) How do I make it so it returns those with personality type 2 ONLY and no other personality traits? Find any man in the USA that is between 22 and 53 that is of personality type 2 (only) that is looking for a woman. Question 2) Supposing I want to find someone that matches personality type 1, personality type 2, and personality type 5 ONLY. There are 14 personality traits in the database and a user can be associated with any of them. Find any man in the USA that is between 22 and 53 that is of personality type 1, 2, and 5 (ONLY) that is looking for a woman.

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