Search Results

Search found 6908 results on 277 pages for 'username 4567'.

Page 17/277 | < Previous Page | 13 14 15 16 17 18 19 20 21 22 23 24  | Next Page >

  • how can I exit from a php script and continue right after the script?

    - by Samir Ghobril
    Hey guys, I have this piece of code, and when I add return after echo(if there is an error and I need to continue right after the script) I can't see the footer, do you know what the problem is? <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html lang="en" > <head> <title>Login | JM Today </title> <link href="Mainstyles.css" type="text/css" rel="stylesheet" /> </head> <body> <div class="container"> <?php include("header.php"); ?> <?php include("navbar.php"); ?> <?php include("cleanquery.php") ?> <div id="wrap"> <?php ini_set('display_errors', 'On'); error_reporting(E_ALL | E_STRICT); $conn=mysql_connect("localhost", "***", "***") or die(mysql_error()); mysql_select_db('jmtdy', $conn) or die(mysql_error()); if(isset($_POST['sublogin'])){ if(( strlen($_POST['user']) >0) && (strlen($_POST['pass']) >0)) { checklogin($_POST['user'], $_POST['pass']); } elseif((isset($_POST['user']) && empty($_POST['user'])) || (isset($_POST['pass']) && empty($_POST['pass']))){ echo '<p class="statusmsg">You didn\'t fill in the required fields.</p><br/><input type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } } else{ echo '<p class="statusmsg">You came here by mistake, didn\'t you?</p><br/><input type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } function checklogin($username, $password){ $username=mysql_real_escape_string($username); $password=mysql_real_escape_string($password); $result=mysql_query("select * from users where username = '$username'"); if($result != false){ $dbArray=mysql_fetch_array($result); $dbArray['password']=mysql_real_escape_string($dbArray['password']); $dbArray['username']=mysql_real_escape_string($dbArray['username']); if(($dbArray['password'] != $password ) || ($dbArray['username'] != $username)){ echo '<p class="statusmsg">The username or password you entered is incorrect. Please try again.</p><br/><input type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } $_SESSION['username']=$username; $_SESSION['password']=$password; if(isset($_POST['remember'])){ setcookie("jmuser",$_SESSION['username'],time()+60*60*24*356); setcookie("jmpass",$_SESSION['username'],time()+60*60*24*356); } } else{ echo'<p class="statusmsg"> The username or password you entered is incorrect. Please try again.</p><br/>input type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } } ?> </div> <br/> <br/> <?php include("footer.php") ?> </div> </body> </html>

    Read the article

  • Nginx proxy upstream cached?

    - by Julian H. Lam
    Attempting to resolve an issue that's been annoying me for a bit. I've distilled the symptoms into a set of reproducible steps: I have two sites, siteA, and siteB. They are both Node.js applications running on different ports (for the sake of example, 4567 and 4568) Both applications have their own file in sites_available (plus a symlink from sites_enabled), which contain the directives proxy_pass http://node_siteA/ and proxy_pass http://node_siteB/ respectively, inside of a location block. They also each have an upstream block (defined globally?): upstream node_siteA { upstream node_siteB { server 127.0.0.1:4567; server 127.0.0.1:4568; } } Site A and Site B have nothing to do with each other. Yes, I am restarting (reloading, actually) nginx every time I make a change. If I take down site B and attempt to access it via the web, I am served site A. Why is this? Thoughts Other times, when I create a new Site C, for example, nginx refuses to show me anything except "Welcome to nginx!" for ~5 minutes. This suggests a resolver timeout, perhaps? When I access Site B after its config has been deleted, and it sends me to Site A, this sounds like nginx sending me to servers in a round-robin fashion...

    Read the article

  • Excel: How to treat multiple lines as one while sorting?

    - by crono
    I get a XLS-File as a database report. The File is in the following format: | Customer | Name | ... | Orders 1 | 6 | ... | ... | 1234 2 | | | | 4567 3 | | | | 8910 4 | 3 | ... | ... | 3210 5 | | | | 8765 6 | 1 | ... | ... | 1000 7 | | | | 1001 I need to sort this thing on a column which is only "filled" in the first line of a "record" (here: Line 1-3, 4+5, 6+7) like "Customer" in this example. Is there a way (without falling back to VBA) to keep the lines together which form a "record" while sorting on them. I know, this is abusing Excel but I have no other choise here. The expected output after sorting on "Customer" would be: | Customer | Name | ... | Orders 1 | 1 | ... | ... | 1000 2 | | | | 1001 3 | 3 | ... | ... | 3210 4 | | | | 8765 5 | 6 | ... | ... | 1234 6 | | | | 4567 7 | | | | 8910

    Read the article

  • Hibernate Query Language Problem

    - by Sarang
    Well, I have implemented a distinct query in hibernate. It returns me result. But, while casting the fields are getting interchanged. So, it generates casting error. What should be the solution? As an example, I do have database, "ProjectAssignment" that has three fields, aid, pid & userName. I want all distinct userName data from this table. I have applied query : select distinct userName, aid, pid from ProjectAssignment Whereas the ProjectAssignment.java file has the fields in sequence aid, pid & userName. Now, here the userName is first field in output. So, Casting is not getting possible. Also, query : select aid, pid, distinct userName from ProjectAssignment is not working. What is the proper query for the same ? Or what else the solution ? The code is as below : System Utilization Service Bean Method where I have to retrieve data : public List<ProjectAssignment> getProjectAssignments() { projectAssignments = ProjectAssignmentHelper.getAllResources(); //Here comes the error return projectAssignments; } ProjectAssignmentHelper from where I fetch Data : package com.hibernate; import java.util.List; import org.hibernate.Query; import org.hibernate.Session; public class ProjectAssignmentHelper { public static List<ProjectAssignment> getAllResources() { List<ProjectAssignment> projectMasters; Session session = HibernateUtil.getSessionFactory().openSession(); Query query = session.createQuery("select distinct aid, pid, userName from ProjectAssignment"); projectMasters = (List<ProjectAssignment>) query.list(); session.close(); return projectMasters; } } Hibernate Data Bean : package com.hibernate; public class ProjectAssignment implements java.io.Serializable { private short aid; private String pid; private String userName; public ProjectAssignment() { } public ProjectAssignment(short aid) { this.aid = aid; } public ProjectAssignment(short aid, String pid, String userName) { this.aid = aid; this.pid = pid; this.userName = userName; } public short getAid() { return this.aid; } public void setAid(short aid) { this.aid = aid; } public String getPid() { return this.pid; } public void setPid(String pid) { this.pid = pid; } public String getUserName() { return this.userName; } public void setUserName(String userName) { this.userName = userName; } } Error : For input string: "userName" java.lang.NumberFormatException: For input string: "userName" at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48) at java.lang.Integer.parseInt(Integer.java:447) at java.lang.Integer.parseInt(Integer.java:497) at javax.el.ArrayELResolver.toInteger(ArrayELResolver.java:375) at javax.el.ArrayELResolver.getValue(ArrayELResolver.java:195) at javax.el.CompositeELResolver.getValue(CompositeELResolver.java:175) at com.sun.faces.el.FacesCompositeELResolver.getValue(FacesCompositeELResolver.java:72) at com.sun.el.parser.AstValue.getValue(AstValue.java:116) at com.sun.el.parser.AstValue.getValue(AstValue.java:163) at com.sun.el.ValueExpressionImpl.getValue(ValueExpressionImpl.java:219) at com.sun.faces.facelets.el.TagValueExpression.getValue(TagValueExpression.java:102) at javax.faces.component.ComponentStateHelper.eval(ComponentStateHelper.java:190) at javax.faces.component.ComponentStateHelper.eval(ComponentStateHelper.java:178) at javax.faces.component.UICommand.getValue(UICommand.java:218) at org.primefaces.component.commandlink.CommandLinkRenderer.encodeMarkup(CommandLinkRenderer.java:113) at org.primefaces.component.commandlink.CommandLinkRenderer.encodeEnd(CommandLinkRenderer.java:54) at javax.faces.component.UIComponentBase.encodeEnd(UIComponentBase.java:878) at org.primefaces.renderkit.CoreRenderer.renderChild(CoreRenderer.java:70) at org.primefaces.renderkit.CoreRenderer.renderChildren(CoreRenderer.java:54) at org.primefaces.component.datatable.DataTableRenderer.encodeTable(DataTableRenderer.java:525) at org.primefaces.component.datatable.DataTableRenderer.encodeMarkup(DataTableRenderer.java:407) at org.primefaces.component.datatable.DataTableRenderer.encodeEnd(DataTableRenderer.java:193) at javax.faces.component.UIComponentBase.encodeEnd(UIComponentBase.java:878) at org.primefaces.renderkit.CoreRenderer.renderChild(CoreRenderer.java:70) at org.primefaces.renderkit.CoreRenderer.renderChildren(CoreRenderer.java:54) at org.primefaces.component.tabview.TabViewRenderer.encodeContents(TabViewRenderer.java:198) at org.primefaces.component.tabview.TabViewRenderer.encodeMarkup(TabViewRenderer.java:130) at org.primefaces.component.tabview.TabViewRenderer.encodeEnd(TabViewRenderer.java:48) at javax.faces.component.UIComponentBase.encodeEnd(UIComponentBase.java:878) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1620) at javax.faces.render.Renderer.encodeChildren(Renderer.java:168) at javax.faces.component.UIComponentBase.encodeChildren(UIComponentBase.java:848) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1613) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1616) at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1616) at com.sun.faces.application.view.FaceletViewHandlingStrategy.renderView(FaceletViewHandlingStrategy.java:380) at com.sun.faces.application.view.MultiViewHandler.renderView(MultiViewHandler.java:126) at com.sun.faces.lifecycle.RenderResponsePhase.execute(RenderResponsePhase.java:127) at com.sun.faces.lifecycle.Phase.doPhase(Phase.java:101) at com.sun.faces.lifecycle.LifecycleImpl.render(LifecycleImpl.java:139) at javax.faces.webapp.FacesServlet.service(FacesServlet.java:313) at org.apache.catalina.core.StandardWrapper.service(StandardWrapper.java:1523) at org.apache.catalina.core.ApplicationDispatcher.doInvoke(ApplicationDispatcher.java:802) at org.apache.catalina.core.ApplicationDispatcher.invoke(ApplicationDispatcher.java:664) at org.apache.catalina.core.ApplicationDispatcher.processRequest(ApplicationDispatcher.java:497) at org.apache.catalina.core.ApplicationDispatcher.doDispatch(ApplicationDispatcher.java:468) at org.apache.catalina.core.ApplicationDispatcher.dispatch(ApplicationDispatcher.java:364) at org.apache.catalina.core.ApplicationDispatcher.forward(ApplicationDispatcher.java:314) at org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:783) at org.apache.jsp.welcome_jsp._jspService(welcome_jsp.java from :59) at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:109) at javax.servlet.http.HttpServlet.service(HttpServlet.java:847) at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:406) at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:483) at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:373) at javax.servlet.http.HttpServlet.service(HttpServlet.java:847) at org.apache.catalina.core.StandardWrapper.service(StandardWrapper.java:1523) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:279) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:188) at org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:641) at com.sun.enterprise.web.WebPipeline.invoke(WebPipeline.java:97) at com.sun.enterprise.web.PESessionLockingStandardPipeline.invoke(PESessionLockingStandardPipeline.java:85) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:185) at org.apache.catalina.connector.CoyoteAdapter.doService(CoyoteAdapter.java:332) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:233) at com.sun.enterprise.v3.services.impl.ContainerMapper.service(ContainerMapper.java:165) at com.sun.grizzly.http.ProcessorTask.invokeAdapter(ProcessorTask.java:791) at com.sun.grizzly.http.ProcessorTask.doProcess(ProcessorTask.java:693) at com.sun.grizzly.http.ProcessorTask.process(ProcessorTask.java:954) at com.sun.grizzly.http.DefaultProtocolFilter.execute(DefaultProtocolFilter.java:170) at com.sun.grizzly.DefaultProtocolChain.executeProtocolFilter(DefaultProtocolChain.java:135) at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:102) at com.sun.grizzly.DefaultProtocolChain.execute(DefaultProtocolChain.java:88) at com.sun.grizzly.http.HttpProtocolChain.execute(HttpProtocolChain.java:76) at com.sun.grizzly.ProtocolChainContextTask.doCall(ProtocolChainContextTask.java:53) at com.sun.grizzly.SelectionKeyContextTask.call(SelectionKeyContextTask.java:57) at com.sun.grizzly.ContextTask.run(ContextTask.java:69) at com.sun.grizzly.util.AbstractThreadPool$Worker.doWork(AbstractThreadPool.java:330) at com.sun.grizzly.util.AbstractThreadPool$Worker.run(AbstractThreadPool.java:309) at java.lang.Thread.run(Thread.java:619)

    Read the article

  • how to escape “@” in the username when logging in through FTPES with curl?

    - by user62367
    $ curl -T "index.html" -k --ftp-ssl -u "[email protected]" MYDOMAIN.COM Enter host password for user '[email protected]': % Total % Received % Xferd Average Speed Time Time Time Current Dload Upload Total Spent Left Speed 0 57173 0 0 0 0 0 0 --:--:-- 0:00:01 --:--:-- 0 <!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN"> <html><head> <title>405 Method Not Allowed</title> </head><body> <h1>Method Not Allowed</h1> <p>The requested method PUT is not allowed for the URL /index.html.</p> <hr> <address>Apache/2.2.16 Server at MYDOMAIN.COM Port 80</address> </body></html> 100 57480 100 307 100 57173 284 52902 0:00:01 0:00:01 --:--:-- 53633 can someone help me? Also posted on Stack Overflow

    Read the article

  • hosting people asking for my account username and password to enable curl and socket function only for me

    - by Jayapal Chandran
    I have hosted my site in a shared environment. My hosting people disabled socket function all together. and they said that we can enable only for you if i given a written statement. I did but they asked for my control panel login details so they will run some kind of script to enable it. Is it right for the hosting company to ask for credentials. They have the total control so why cant they do it? Edit: Before six months many websites in their server got hacked. So they think it would be because of socket functions and had disabled it. They say they can enable it for specific users who do programming using that and that is by email request.

    Read the article

  • Git clone/push/pull - where's that username comes from?

    - by Kuroki Kaze
    I've set up gitosis and able to pull/push through ssh. Gitosis is installed on Debian Lenny server, I'm using git from windows machine (msysgit). The strange thing, if I enable loglevel = DEBUG in gitosis.conf, I see something like this when doing any actions with gitosis server: D:\Kaze\source\test-project>git pull origin master DEBUG:gitosis.serve.main:Got command "git-upload-pack 'test_project.git'" DEBUG:gitosis.access.haveAccess:Access check for '[email protected]' as 'writable' on 'test_project.git'... DEBUG:gitosis.access.haveAccess:Stripping .git suffix from 'test_project.git', new value 'test_project' DEBUG:gitosis.group.getMembership:found '[email protected]' in 'test' DEBUG:gitosis.access.haveAccess:Access ok for '[email protected]' as 'writable' on 'test_project' DEBUG:gitosis.access.haveAccess:Using prefix 'repositories' for 'test_project' DEBUG:gitosis.serve.main:Serving git-upload-pack 'repositories/test_project.git' From 192.168.175.128:test_project * branch master -> FETCH_HEAD Already up-to-date. Question is: why am I *[email protected]? This email is in global user.email config variable, too. Yesterday, when the gitosis was installed, it seen me as kaze@KAZE, this is the name under which I was added to gitosis-admin group (and it worked). But today git (or gitosis) started to see me as [email protected]. This is true for all repositories I push or clone. I had to add this address to gitosis.conf directly on server to be able to edit configs again (it worked). There is 2 public keys in keydir: [email protected] and [email protected], their content is identical and they have kaze@KAZE at end. Origin URL looks like git@lennyserver:test_project. Now, the question is - why Git (or gitosis) suddenly decided to call me by email instead of name@machinename? I've changed a couple things trying to set up Gitosis (updated git on server to 1.6.0 for example), but maybe I broke something in my local git installation?

    Read the article

  • Cisco login on-failure using syslog doesn't show username on failure?

    - by Jim
    interesting issue I am running into. I am trying to get syslog rmeote logging working with a Cisco switch. i have it working and logging for both on-success and on-failure. However when it is a failed login attempt it does not show the user name that tried to log in in the logs? Here is what the log looks like after a failed login: %SEC_LOGIN-4-LOGIN_FAILED: Login failed [user: ] [Source: 10.0. 0.6] [localport: 23] [Reason: Login Authentication Failed] Here is what I ahve in the sh run: login block-for 60 attempts 3 within 60 login delay 1 login on-failure log login on-success log archive log config logging enable notify syslog contenttype plaintext logging trap notifications logging facility local4 logging 10.0.0.8 aaa new-model aaa authentication login default local group tacacs+ aaa authorization config-commands aaa authorization exec default local group tacacs+

    Read the article

  • Ubuntu Server login not recognizing the keyboard after entering username.

    - by Jeff Malewski
    I'm having similar issues with logging into ubuntu server. chief problem is that once I enter my user name & hit enter, I can't enter anything ffor my password - it won't accept any keystrokes until I press Ctrl+any key. Once I've pressed Ctrl+ any key, I'm able to type again, but have never been able to enter any more than 3 characters before the 60 sec time limit. This problem is present on fresh installs of both 10.04 & 9.10. Part of the problem is lkely to be my antique pc which is an old Emachines Trigems I850 based mbd and an equally ancient Nvidia 4x AGP video card. Initially I was going to install Ubuntu 10.10, but with ORCA running with both screen reader and full screen magnification crashed the system & smoked a stick of Rambus memory. Is there any fix to this problem? Jeff

    Read the article

  • GNU-Screen still has only old groups for my username.

    - by Dan
    I was recently added to a group on the unix server. My active screen session has not been update to the new groups: $groups A B C D $screen -r $groups A B C Without closing my screen session is there a way for me to use my new privileges in the screen session? Or if not, is there at least a way I can save all of the different directories each of the tabs are on? Thanks, Dan

    Read the article

  • How to convert tag-and-username-like text into proper links in a twitter message?

    - by Satoru.Logic
    Hi, all. I'm writing a twitter-like note-taking web app. In a page the latest 20 notes of the user will be listed, and when the user scroll to the bottom of the browser window more items will be loaded and rendered. The initial 20 notes are part of the generated html of my django template, but the other dynamically loaded items are in json format. I want to know how do I do the tag-and-username converting consistently. Thanks in advance.

    Read the article

  • Rails: Accessing the username/password used for HTTP Basic Auth?

    - by Shpigford
    I'm building a basic API where user information can be retrieved after that user's login and password are correctly sent. Right now I'm using something like this: http://foo:[email protected]/api/user.xml So, what I need to do is access the user/password sent in the request (the foo and bar) but am not sure how to access that info in a Rails controller. Then I'd check those variables via a quick User.find and then set those as the username and password variables for authenticate_or_request_with_http_basic. It's possible I'm looking at this at the completely wrong way, but that's where I'm at right now. :)

    Read the article

  • Why Shouldn't I Programmatically Submit Username/Password to Facebook/Twitter/Amazon/etc?

    - by viatropos
    I wish there was a central, fully customizable, open source, universal login system that allowed you to login and manage all of your online accounts (maybe there is?)... I just found RPXNow today after starting to build a Sinatra app to login to Google, Facebook, Twitter, Amazon, OpenID, and EventBrite, and it looks like it might save some time. But I keep wondering, not being an authentication guru, why couldn't I just have a sleek login page saying "Enter username and password, and check your login service", and then in the background either scrape the login page from say EventBrite and programmatically submit the form with Mechanize, or use an API if there was one? It would be so much cleaner and such a better user experience if they didn't have to go through popups and redirects and they could use any previously existing accounts. My question is: What are the reasons why I shouldn't do something like that? I don't know much about the serious details of cookies/sessions/security, so if you could be descriptive or point me to some helpful links that would be awesome. Thanks!

    Read the article

  • how is this jquery app validating the username? (3rd party script)

    - by SarmenHB
    The tutorial that I'm trying to figure out is this: http://www.position-absolute.com/articles/jquery-form-validator-because-form-validation-is-a-mess/ The username field looks like this: <input value="" class="validate[required,custom[noSpecialCaracters],length[0,20],ajax[ajaxUser]]" type="text" name="user" id="user" /> That <input> field has a class item named ajax[ajaxUser] which has its rules contained in this script (jquery.validationEngine-en.js). The snippet for that item looks like this: "ajaxUser":{ "file":"validateUser.php", "extraData":"name=eric", "alertTextOk":"* This user is available", "alertTextLoad":"* Loading, please wait", "alertText":"* This user is already taken"}, What I can't figure out at all is how its PHP page is working which is validateUser.php. Where are all those post fields coming from? I looked around and can't find a field with those names. Thanks

    Read the article

  • How do I program a hyperlink to include a username and password to the target site?

    - by Fred Griffith
    We have a website with a section restricted to members only. They log in and can view the website. Some of the information is stored on another server. We want that information to ONLY be accessible to those who have logged into the main website. What would be the best way to link the two sites, without making members log in again? Seems like there must be some way to send an encrypted username and password along with the URL in the hyperlink. Any ideas? Thank you in advance. Fred G.

    Read the article

  • Getting Oracle Exception: ORA-1017: invalid username/password; logon denied

    - by Paks
    I have tried so many thing but i can't resolve that Error. I can connect with my username and password to: Database in SQLDeveloper, in SQL-Plus, in Server-Explorer (Visual Studio 2008) and all works fine. But if i Compile my Project i get that Error. Why is that? I tried to set case_sensitive to false, but the same error appears. I dont know what else to do. My Oracle version: Oracle Database 11g Express Edtiton Release 11.2.0.2.0 - Production PL/SQL Release 11.2.0.2.0 - Production CORE 11.2.0.2.0 Production TNS for 32-bit Windows: Version 11.2.0.2.0 - Production NLSRTL Version 11.2.0.2.0 - Production

    Read the article

  • Things to take care while sending the username and password using Ajax request ?

    - by Anil Namde
    Normally we have login page with username, password filed and signin button. Using the normal form based approach we send the data on and page gets post back. Now i would like to change this using the Ajax. As Ajax too using the normal HTTP so i guess nothing in different from the existing workflow barring postback right ? Now my question is is what all securities issues can be there? and what care should be taken for doing so ? Should we encode data using say base64 or so before sending using Ajax?

    Read the article

  • Save user names on .txt file witch username is listed in /etc/passwd file. Bash

    - by user1448637
    well my goal is to make bash script to check if the username exist in /etc/passwd, if true i want to add it to the users.txt file. i am not really good at UNIX programming so i hope somebody help me. while(get to the end of /etc/passwd){ name=$(cat /etc/passwd | cut -d: -f1); num1=$(cat /etc/passwd | cut -d: -f3); num2=$(cat /etc/passwd | cut -d: -f4); if(num1==num2) /*i compare argv[0] with $name */ /* if true i=1 */ } if(i==1) save folowing string "argv[0]=agrv[1]" else "error message"

    Read the article

  • How do I create email addresses for all my users using my domain ([email protected])?

    - by rwain
    My client wants to create email addresses for all their dotnetnuke users using their domain. The point is to keep the user's email addresses 'private' while still allowing communication through a public email address that they can control. It's not necessary to have a full webmail interface (although that would be nice). I'm thinking it would be enough just to forward any mail on and just act as a gateway. So if an email was sent to [email protected], it would be forwarded on to the email address associated with the dotnetnuke account with username 'rwain'. Is this possible to do in a shared hosting environment? Or do I need to create some custom mail server that does a conversion of the email address and forwards it?

    Read the article

  • How to prompt for username and password entry in C# / SQL ASP.NET web app?

    - by salvationishere
    How do I prompt for username and password in my C#/SQL web application? This was developed in VS 2008 on a 32-bit XP. The current connection string I'm using in my web.config file is: <add name="AdventureWorksConnectionString2" connectionString="Data Source=SIDEKICK;Initial Catalog=AdventureWorks;Persist Security Info=false; " providerName="System.Data.SqlClient" /> When I select Basic Authentication it pops up the warning: "The authentication option you have chosen results in passwords being sent over the network without data encryption..." How do I choose this authentication method and still send passwords over securely? So essentially I am looking for the most secure authentication method but that still requires users to input password?

    Read the article

  • Getting the username entered by the user after he hits submit on the login form, irrespective of whe

    - by simonr
    Duplicate of http://stackoverflow.com/questions/2803425 Hello, When a user enters his login information and hits submit, irrespective of whether the login credentials entered by the user were correct or not, i want my function to be called. In this function, i need the username entered by the user. I think i cannot use the login op of hook_user because its called only when the user has successfully logged in. So, how can i achieve the above functionality ? Some sample code would be really appreciated. Please help. Thank You.

    Read the article

  • Sending Messages to SignalR Hubs from the Outside

    - by Ricardo Peres
    Introduction You are by now probably familiarized with SignalR, Microsoft’s API for real-time web functionality. This is, in my opinion, one of the greatest products Microsoft has released in recent time. Usually, people login to a site and enter some page which is connected to a SignalR hub. Then they can send and receive messages – not just text messages, mind you – to other users in the same hub. Also, the server can also take the initiative to send messages to all or a specified subset of users on its own, this is known as server push. The normal flow is pretty straightforward, Microsoft has done a great job with the API, it’s clean and quite simple to use. And for the latter – the server taking the initiative – it’s also quite simple, just involves a little more work. The Problem The API for sending messages can be achieved from inside a hub – an instance of the Hub class – which is something that we don’t have if we are the server and we want to send a message to some user or group of users: the Hub instance is only instantiated in response to a client message. The Solution It is possible to acquire a hub’s context from outside of an actual Hub instance, by calling GlobalHost.ConnectionManager.GetHubContext<T>(). This API allows us to: Broadcast messages to all connected clients (possibly excluding some); Send messages to a specific client; Send messages to a group of clients. So, we have groups and clients, each is identified by a string. Client strings are called connection ids and group names are free-form, given by us. The problem with client strings is, we do not know how these map to actual users. One way to achieve this mapping is by overriding the Hub’s OnConnected and OnDisconnected methods and managing the association there. Here’s an example: 1: public class MyHub : Hub 2: { 3: private static readonly IDictionary<String, ISet<String>> users = new ConcurrentDictionary<String, ISet<String>>(); 4:  5: public static IEnumerable<String> GetUserConnections(String username) 6: { 7: ISet<String> connections; 8:  9: users.TryGetValue(username, out connections); 10:  11: return (connections ?? Enumerable.Empty<String>()); 12: } 13:  14: private static void AddUser(String username, String connectionId) 15: { 16: ISet<String> connections; 17:  18: if (users.TryGetValue(username, out connections) == false) 19: { 20: connections = users[username] = new HashSet<String>(); 21: } 22:  23: connections.Add(connectionId); 24: } 25:  26: private static void RemoveUser(String username, String connectionId) 27: { 28: users[username].Remove(connectionId); 29: } 30:  31: public override Task OnConnected() 32: { 33: AddUser(this.Context.Request.User.Identity.Name, this.Context.ConnectionId); 34: return (base.OnConnected()); 35: } 36:  37: public override Task OnDisconnected() 38: { 39: RemoveUser(this.Context.Request.User.Identity.Name, this.Context.ConnectionId); 40: return (base.OnDisconnected()); 41: } 42: } As you can see, I am using a static field to store the mapping between a user and its possibly many connections – for example, multiple open browser tabs or even multiple browsers accessing the same page with the same login credentials. The user identity, as is normal in .NET, is obtained from the IPrincipal which in SignalR hubs case is stored in Context.Request.User. Of course, this property will only have a meaningful value if we enforce authentication. Another way to go is by creating a group for each user that connects: 1: public class MyHub : Hub 2: { 3: public override Task OnConnected() 4: { 5: this.Groups.Add(this.Context.ConnectionId, this.Context.Request.User.Identity.Name); 6: return (base.OnConnected()); 7: } 8:  9: public override Task OnDisconnected() 10: { 11: this.Groups.Remove(this.Context.ConnectionId, this.Context.Request.User.Identity.Name); 12: return (base.OnDisconnected()); 13: } 14: } In this case, we will have a one-to-one equivalence between users and groups. All connections belonging to the same user will fall in the same group. So, if we want to send messages to a user from outside an instance of the Hub class, we can do something like this, for the first option – user mappings stored in a static field: 1: public void SendUserMessage(String username, String message) 2: { 3: var context = GlobalHost.ConnectionManager.GetHubContext<MyHub>(); 4: 5: foreach (String connectionId in HelloHub.GetUserConnections(username)) 6: { 7: context.Clients.Client(connectionId).sendUserMessage(message); 8: } 9: } And for using groups, its even simpler: 1: public void SendUserMessage(String username, String message) 2: { 3: var context = GlobalHost.ConnectionManager.GetHubContext<MyHub>(); 4:  5: context.Clients.Group(username).sendUserMessage(message); 6: } Using groups has the advantage that the IHubContext interface returned from GetHubContext has direct support for groups, no need to send messages to individual connections. Of course, you can wrap both mapping options in a common API, perhaps exposed through IoC. One example of its interface might be: 1: public interface IUserToConnectionMappingService 2: { 3: //associate and dissociate connections to users 4:  5: void AddUserConnection(String username, String connectionId); 6:  7: void RemoveUserConnection(String username, String connectionId); 8: } SignalR has built-in dependency resolution, by means of the static GlobalHost.DependencyResolver property: 1: //for using groups (in the Global class) 2: GlobalHost.DependencyResolver.Register(typeof(IUserToConnectionMappingService), () => new GroupsMappingService()); 3:  4: //for using a static field (in the Global class) 5: GlobalHost.DependencyResolver.Register(typeof(IUserToConnectionMappingService), () => new StaticMappingService()); 6:  7: //retrieving the current service (in the Hub class) 8: var mapping = GlobalHost.DependencyResolver.Resolve<IUserToConnectionMappingService>(); Now all you have to do is implement GroupsMappingService and StaticMappingService with the code I shown here and change SendUserMessage method to rely in the dependency resolver for the actual implementation. Stay tuned for more SignalR posts!

    Read the article

  • Unable to set password in IIS 8 for Domain User as ApplicationPool Identity

    - by Niels R.
    I'm trying to set a Domain User account as ApplicationPool Identity in IIS 8 (Windows 2012). When trying this using the IIS Management Console I always get an error: Value does not fall within the expected range. When trying to set the identity using appcmd.exe it fails on both the command setting the username and password or the command only setting the password. Setting the username is no problem. Trying to set both the username and password [FAIL]: >appcmd set config /section:applicationPools /[name='AppPoolName'].processModel.identityType:SpecificUser /[name='AppPoolName'].processModel.userName:DOMAIN\Username /[name='AppPoolName'].processModel.password:P4ssW0rd Applied configuration changes to section "system.applicationHost/applicationPools" for "MACHINE/WEBROOT/APPHOST" at configuration commit path "MACHINE/WEBROOT/APPHOST" ERROR ( hresult:80070057, message:Failed to commit configuration changes. The parameter is incorrect. ) Trying to set only the username [SUCCESS]: >appcmd set config /section:applicationPools /[name='AppPoolName'].processModel.identityType:SpecificUser /[name='AppPoolName'].processModel.userName:DOMAIN\Username Applied configuration changes to section "system.applicationHost/applicationPools" for "MACHINE/WEBROOT/APPHOST" at configuration commit path "MACHINE/WEBROOT/APPHOST" Trying to set the password after successfully setting the username [FAIL]: >appcmd set config /section:applicationPools /[name='AppPoolName'].processModel.identityType:SpecificUser /[name='AppPoolName'].processModel.password:P4ssW0rd Applied configuration changes to section "system.applicationHost/applicationPools" for "MACHINE/WEBROOT/APPHOST" at configuration commit path "MACHINE/WEBROOT/APPHOST" ERROR ( hresult:80070057, message:Failed to commit configuration changes. The parameter is incorrect. ) I added the Domain User to the IIS_IUSRS group and allowed it to "Log on as a service". Any suggestions what I might be doing wrong?

    Read the article

  • How to give a user NTFS rights to a folder, via Powershell

    - by Don
    I'm trying to build a script that will create a folder for a new user on our file server. Then take the inherited rights away from that folder and add specific rights back in. I have it successfully adding the folder (if i give it a static entry in the script), giving domain admin rights, removing inheritance, etc...but i'm having trouble getting it to use a variable I set as the user. I don't want there to be a static user each time, I want to be able to run this script, have it ask me for a username, it then goes out and creates the folder, then gives that same user full rights to that folder based on the username i've supplied it. I can use Smithd as a user, like this: New-Item \\fileserver\home$\Smithd –Type Directory But can't get it to reference the user like this: New-Item \\fileserver\home$\$username –Type Directory Here's what i have: Creating a new folder and setting NTFS permissions. $username = read-host -prompt "Enter User Name" New-Item \\\fileserver\home$\$username –Type Directory Get-Acl \\\fileserver\home$\$username $acl = Get-Acl \\\fileserver\home$\$username $acl.SetAccessRuleProtection($True, $False) $rule = New-Object System.Security.AccessControl.FileSystemAccessRule("Administrators","FullControl", "ContainerInherit, ObjectInherit", "None", "Allow") $acl.AddAccessRule($rule) $rule = New-Object System.Security.AccessControl.FileSystemAccessRule("Domain\Domain Admins","FullControl", "ContainerInherit, ObjectInherit", "None", "Allow") $acl.AddAccessRule($rule) $rule = New-Object System.Security.AccessControl.FileSystemAccessRule("Domain\"+$username,"FullControl", "ContainerInherit, ObjectInherit", "None", "Allow") $acl.AddAccessRule($rule) Set-Acl \\\fileserver\home$\$username $acl I've tried several ways to get it to work, but no luck. Any ideas or suggestions would be welcome, thanks.

    Read the article

  • Can not access SQLServer database

    - by btrey
    I'm trying to convert an Access database to use a SQLServer backend. I've upsized the database and everything works on the server, but I'm unable to access it remotely. I'm running SQLServer Express 2005 on Windows Server 2003. The server is not configured as a domain controller, nor connected to a domain. The computers I'm trying to access the server from are part of a domain, but there are no local domain controllers. I'm at a remote location and the computers are configured and connected to the domain at the home office, then shipped to us. We normally log in with cached credentials and VPN into the home office when we need to access the domain. I can use Remote Desktop Connection to access the 2k3 server which is running SQLServer. If I log into the server with my username, I can bring up the database, access it via the Trusted Connection, and the database works. If I try to run the database locally, however, I get the Server Login dialog box. I can not use a Trusted Connection because my local login is to the home office domain and is not recognized by the SQLServer machine. If I try to use the username/password that is local to the SQLServer, I get a login failed error. I've tried entering the username as "username", "workgroup/username" (where "workgroup" is the name of the workgroup on the SQLServer), "sqlservername/username" and "[email protected]" where "1.2.3.4" is the IP of the SQLServer. In all cases, I get a login failed error. As I said, I can login to the server via Remote Desktop Connection with the same username and password and use the database, so permissions for the username appear to be correct for both a remote connection and for database access. Not sure where to go from here and any assistance would be appreciated.

    Read the article

< Previous Page | 13 14 15 16 17 18 19 20 21 22 23 24  | Next Page >