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  • Python script to delete old SVN files lacks permission

    - by Rosarch
    I'm trying to delete old SVN files from directory tree. shutil.rmtree and os.unlink raise WindowsErrors, because the script doesn't have permissions to delete them. How can I get around that? Here is the script: # Delete all files of a certain type from a direcotry import os import shutil dir = "c:\\" verbosity = 0; def printCleanMsg(dir_path): if verbosity: print "Cleaning %s\n" % dir_path def cleandir(dir_path): printCleanMsg(dir_path) toDelete = [] dirwalk = os.walk(dir_path) for root, dirs, files in dirwalk: printCleanMsg(root) toDelete.extend([root + os.sep + dir for dir in dirs if '.svn' == dir]) toDelete.extend([root + os.sep + file for file in files if 'svn' in file]) print "Items to be deleted:" for candidate in toDelete: print candidate print "Delete all %d items? [y|n]" % len(toDelete) choice = raw_input() if choice == 'y': deleted = 0 for filedir in toDelete: if os.path.exists(filedir): # could have been deleted already by rmtree try: if os.path.isdir(filedir): shutil.rmtree(filedir) else: os.unlink(filedir) deleted += 1 except WindowsError: print "WindowsError: Couldn't delete '%s'" % filedir print "\nDeleted %d/%d files." % (deleted, len(toDelete)) exit() if __name__ == "__main__": cleandir(dir) Not a single file is able to be deleted. What am I doing wrong?

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  • Python Terminated Thread Cannot Restart

    - by Mel Kaye
    Hello, I have a thread that gets executed when some action occurs. Given the logic of the program, the thread cannot possibly be started while another instance of it is still running. Yet when I call it a second time, I get a "RuntimeError: thread already started" error. I added a check to see if it is actually alive using the Thread.is_alive() function, and it is actually dead. What am I doing wrong? I can provide more details as are needed.

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  • Python regular expression

    - by user3692739
    I have this HTTP Request and I want to display only the Authorization section (base64 Value) : any help ? This Request is stored on a variable called hreq I have tried this : reg = re.search(r"Authorization:\sBasic\s(.*)\r", hreq) print reg.group() but doesn't work Here is the request : HTTP Request: Path: /dynaform/custom.js Http-Version: HTTP/1.1 Host: 192.168.1.254 Accept-Language: en-US,en;q=0.5 Accept-Encoding: gzip, deflate Referer: http://domain.com/userRpm/StatusRpm.htm Authorization: Basic YWhtEWa6MDfGcmVlc3R6bGH I want to display the value YWhtEWa6MDfGcmVlc3R6bGH Please I need your help thanks in advance experts

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  • Number of elements in Python Set

    - by Tim
    I have a list of phone numbers that have been dialed (nums_dialed). I also have a set of phone numbers which are the number in a client's office (client_nums) How do I efficiently figure out how many times I've called a particular client (total) For example: >>>nums_dialed=[1,2,2,3,3] >>>client_nums=set([2,3]) >>>??? total=4 Problem is that I have a large-ish dataset: len(client_nums) ~ 10^5; and len(nums_dialed) ~10^3.

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  • Accessing items from a dictionary using pickle efficiently in Python

    - by user248237
    I have a large dictionary mapping keys (which are strings) to objects. I pickled this large dictionary and at certain times I want to pull out only a handful of entries from it. The dictionary has usually thousands of entries total. When I load the dictionary using pickle, as follows: from cPickle import * # my dictionary from pickle, containing thousands of entries mydict = open(load('mypickle.pickle')) # accessing only handful of entries here for entry in relevant_entries: # find relevant entry value = mydict[entry] I notice that it can take up to 3-4 seconds to load the entire pickle, which I don't need, since I access only a tiny subset of the dictionary entries later on (shown above.) How can I make it so pickle only loads those entries that I have from the dictionary, to make this faster? Thanks.

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  • Python: NameError: 'self' is not defined

    - by Rosarch
    I must be doing something stupid. I'm running this in Google App Engine: def render(self, template_name, template_data): path = os.path.join(os.path.dirname(__file__), 'static/templates/%s.html' % template_name) self.response.out.write(template.render(path, template_data)) This gives an error: Traceback (most recent call last): File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 3192, in _HandleRequest self._Dispatch(dispatcher, self.rfile, outfile, env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 3135, in _Dispatch base_env_dict=env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 516, in Dispatch base_env_dict=base_env_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2394, in Dispatch self._module_dict) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2304, in ExecuteCGI reset_modules = exec_script(handler_path, cgi_path, hook) File "C:\Program Files\Google\google_appengine\google\appengine\tools\dev_appserver.py", line 2200, in ExecuteOrImportScript exec module_code in script_module.__dict__ File "main.py", line 22, in <module> class MainHandler(webapp.RequestHandler): File "main.py", line 38, in MainHandler self.writeOut(template.render(path, template_data)) NameError: name 'self' is not defined What am I doing wrong?

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  • Python List length as a string

    - by mvid
    Is there a preferred (not ugly) way of outputting a list length as a string? Currently I am nesting function calls like so: print "Length: %s" % str(len(self.listOfThings)) This seems like a hack solution, is there a more graceful way of achieving the same result?

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  • Python - Removing duplicates from a string

    - by Daniel
    def remove_duplicates(strng): """ Returns a string which is the same as the argument except only the first occurrence of each letter is present. Upper and lower case letters are treated as different. Only duplicate letters are removed, other characters such as spaces or numbers are not changed. >>> remove_duplicates('apple') 'aple' >>> remove_duplicates('Mississippi') 'Misp' >>> remove_duplicates('The quick brown fox jumps over the lazy dog') 'The quick brown fx jmps v t lazy dg' >>> remove_duplicates('121 balloons 2 u') '121 balons 2 u' """ s = strng.split() return strng.replace(s[0],"") Writing a function to get rid of duplicate letters but so far have been playing around for an hour and can't get anything. Help would be appreciated, thanks.

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  • Python: combine two neighbor list components

    - by kame
    When i use this code I get elements wich containing one number or letter. How to combine two neighbors? data = '4D41544C414220352E30204D41542D66696C652C20506C6174666F726D3A20504357494E2C2043726561746564206F6E3A20576564204D61792030352031363A31393A3337203230313020202020202020202020202020202020202020202020202020202020202020202020202020202020202020202020202020200001494D0F00000026000000789CE36360607000623620E680D220C00AE53343312310BA00692620E604F351010025BE00C8' data2 = list(data) print data2

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  • Python Pandas operate on row

    - by wuha
    Hi my dataframe look like: Store,Dept,Date,Sales 1,1,2010-02-05,245 1,1,2010-02-12,449 1,1,2010-02-19,455 1,1,2010-02-26,154 1,1,2010-03-05,29 1,1,2010-03-12,239 1,1,2010-03-19,264 Simply, I need to add another column called '_id' as concatenation of Store, Dept, Date like "1_1_2010-02-05", I assume I can do it through df['id'] = df['Store'] +'' +df['Dept'] +'_'+df['Date'], but it turned out to be not. Similarly, i also need to add a new column as log of sales, I tried df['logSales'] = math.log(df['Sales']), again, it did not work.

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  • Python sort 2-D list by time string

    - by Mark Kennedy
    How do I sort a multi dimensional list like this based on a time string? The sublists can be of different sizes (i.e. 4 and 5, here) I want to sort by comparing the first time string in each sublist (sublist[-4]) x = (['1513', '08:19PM', '10:21PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['0690', '07:25AM', '09:19AM', 1, 4], ['0201', '08:50AM', '10:50AM', 1, 4], ['1166', '04:35PM', '06:36PM', 1, 4], ['0845', '05:40PM', '07:44PM', 1, 4], ['1267', '07:05PM', '09:07PM', 1, 4], ['1513', '08:19PM', '10:21PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['8772', '0159', '12:33PM', '02:43PM', 1, 5], ['0888', '0570', '09:42PM', '12:20AM', 1, 5], ['2086', '2231', '04:10PM', '06:20PM', 1, 5]) The sorted result would be sortedX = (['0690', '07:25AM', '09:19AM', 1, 4], ['0201', '08:50AM', '10:50AM', 1, 4], ['1166', '04:35PM', '06:36PM', 1, 4], ['0845', '05:40PM', '07:44PM', 1, 4], ['1267', '07:05PM', '09:07PM', 1, 4], ['1513', '08:19PM', '10:21PM', 1, 4], ['1513', '08:19PM', '10:21PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['1290', '09:45PM', '11:43PM', 1, 4], ['8772', '0159', '12:33PM', '02:43PM', 1, 5], ['2086', '2231', '04:10PM', '06:20PM', 1, 5], ['0888', '0570', '09:42PM', '12:20AM', 1, 5]) I tried the following: sortedX = sorted(x, key=lambda k : k[-4]) #k[-4] is the first time string and it works but it doesn't respect the sublist size ordering

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  • python regular expressions, how to extract longest of overlapping groups

    - by xulochavez
    Hi How can I extract the longest of groups which start the same way For example, from a given string, I want to extract the longest match to either CS or CSI. I tried this "(CS|CSI).*" and it it will return CS rather than CSI even if CSI is available. If I do "(CSI|CS).*" then I do get CSI if it's a match, so I gues the solution is to always place the shorter of the overlaping groups after the longer one. Is there a clearer way to express this with re's? somehow it feels confusing that the result depends on the order you link the groups.

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  • Python code, extracting extensions

    - by user1434001
    import os path = '/Users/Marjan/Documents/Nothing/Costco' print path names = os.listdir(path) print len(names) for name in names: print name Here is the code I've been using, it lists all the names in this category in terminal. There are a few filenames in this file (Costco) that don't have .html and _files. I need to pick them out, the only issue is that it has over 2,500 filenames. Need help on a code that will search through this path and pick out all the filenames that don't end with .html or _files. Thanks guys

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  • Python: Regex outputs 12_34 - I need 1234

    - by Guy F-W
    So I have input coming in like: 12_34 5_6_8_2 4___3 1234 and the output I need from it is: 1234, 5682, 43, 1234 I'm currently working with r'[0-9]+[0-9_]*'.replace('_','') which (as far as I can tell) successfully rejects any input which is not a combination of numeric digits and under-scores, where the underscore cannot be the first character. However, replacing the _ with the empty string causes 12_34 to come out as 12 and 34. Is there a better method than 'replace' for this? Or could I adapt my regex to deal with this problem?

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  • is there a better way of replacing duplicates in a list (python)

    - by myeu2
    Given a list: l1: ['a', 'b', 'c', 'a', 'a', 'b'] output: ['a', 'b', 'c', 'a'_1, 'a'_2, 'b'_1 ] I created the following code to get the output. Its messyyy.. for index in range(len(l1)): counter = 1 list_of_duplicates_for_item = [dup_index for dup_index, item in enumerate(l1) if item == l1[index] and l1.count(l1[index]) > 1] for dup_index in list_of_duplicates_for_item[1:]: l1[dup_index] = l1[dup_index] + '_' + str(counter) counter = counter + 1 Is there a more pythonic way of doing this? I couldnt find anything on the web.

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  • Python - open text file, but specify name when executing command

    - by Dunnolol
    I have a directory of text files that all end in the extension .txt My goal is to print the contents of the text file. I wish to be able use the wildcard *.txt to be able to specific the text file name I wish to open (I'm thinking along the lines of something like "F:\text*.txt" ?), split the lines of the text file, then print the output. Here is an example of what I want to do, but I want to be able to change "somefile" when executing my command. f = open('F:\text\somefile.txt', 'r') for line in f: print line,

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  • Http.Request and cookies Python

    - by Kyle
    I am trying to retrieve source code from a webpage with an already issued cookie and write the source code to a txt file. If I remove the cookies=cookie portion I can retrieve the source code but I need to somehow send the cookie with the http.request. output = open('Filler.txt', 'w+') http = urllib3.PoolManager() cookie =('users' , '1597413515') r = http.request('http://google.com' , 'GET' , cookies=cookie) output.write(r.data) output.close() I get a KeyError: None

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  • python send/receive hex data via TCP socket

    - by Mike
    I have a ethenet access control device that is said to be able to communicate via TCP. How can i send a pachet by entering the HEX data, since this is what i have from their manual (a standard format for the communication packets sent and received after each command)

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  • convert the key in MIME encoded form in python

    - by jaysh
    this is the code : f = urllib.urlopen('http://pool.sks-keyservers.net:11371/pks/lookup?op=get&search= 0x58e9390daf8c5bf3') #Retrieve the public key from PKS data = f.read() decoded_bytes = base64.b64decode(data) print decoded_bytes i need to convert the key in MIME encoded form which is presently comes in (ascii armored) radix 64 format.for that i have to get this radix64 format in its binary form and also need to remove its header and checksum than coversion in MIME format but i didnt find any method which can do this conversion. i used the base64.b64decode method and its give me error: Traceback (most recent call last): File "RetEnc.py", line 12, in ? decoded_bytes = base64.b64decode(data) File "/usr/lib/python2.4/base64.py", line 76, in b64decode raise TypeError(msg) TypeError: Incorrect padding what to do i'didnt getting .can anybody suggest me something related to this...... thanks!!!!

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