Search Results

Search found 3457 results on 139 pages for 'displaying'.

Page 18/139 | < Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >

  • Internet Explorer not displaying gif file

    - by INTPnerd
    My friend is making a website for a class. Some of the pages display gif image files as links. They display correctly in Firefox and Chrome but not in Internet Explorer. Anybody know why? Here is a line of html code that should display the gif links: <a href="kendo.htm"><img src="arrowprev.gif" alt="previous page arrow"/></a> | <a href="index.htm">HOME</a> | <a href="festivals.htm"><img src="arrownext.gif" alt="next page arrow"/></a> Thanks for the help!

    Read the article

  • SDL_BlitSurface() not displaying image?

    - by Christian Gonzalez
    So I'm trying to display a simply image with the SDL library, but when I use the function SDL_BlitSurface() nothing happens, and all I get is a black screen. I should also note that I have the .bmp file, the source, and the executable file all in the same directory. //SDL Header #include "SDL/SDL.h" int main(int argc, char* args[]) { //Starts SDL SDL_Init(SDL_INIT_EVERYTHING); //SDL Surfaces are images that are going to be displayed. SDL_Surface* Hello = NULL; SDL_Surface* Screen = NULL; //Sets the size of the window (Length, Height, Color(bits), Sets the Surface in Software Memory) Screen = SDL_SetVideoMode(640, 480, 32, SDL_SWSURFACE); //Loads a .bmp image Hello = SDL_LoadBMP("Hello.bmp"); //Applies the loaded image to the screen SDL_BlitSurface(Hello, NULL, Screen, NULL); //Update Screen SDL_Flip(Screen); //Pause SDL_Delay(2000); //Deletes the loaded image from memory SDL_FreeSurface(Hello); //Quits SDL SDL_Quit(); return 0; }

    Read the article

  • OpenGL Projection matrix won't allow displaying anything

    - by user272973
    I'm trying to get some basic OpenGL-ES with Shaders to run on the iPhone, based on some examples. For some reason my projection matrix refuses to result in something on the screen. It feels like a clipping plane is set very near but that contradicts with the values I supply. If I render the same scene with an Orthogonal projection matrix I see my object just no perspective obviously. Here's the code that generates the projection matrix: esPerspective(&proj, 45.f, 768.0/1024.0, 1.f, 10000.f); void esPerspective(ESMatrix *result, float fovy, float aspect, float nearZ, float farZ) { float frustumW, frustumH; frustumH = tanf( fovy / 360.0f * PI ) * nearZ; frustumW = frustumH * aspect; esFrustum( result, -frustumW, frustumW, -frustumH, frustumH, nearZ, farZ ); } void esFrustum(ESMatrix *result, float left, float right, float bottom, float top, float nearZ, float farZ) { float deltaX = right - left; float deltaY = top - bottom; float deltaZ = farZ - nearZ; ESMatrix frust; if ( (nearZ <= 0.0f) || (farZ <= 0.0f) || (deltaX <= 0.0f) || (deltaY <= 0.0f) || (deltaZ <= 0.0f) ) return; frust.m[0][0] = 2.0f * nearZ / deltaX; frust.m[0][1] = frust.m[0][2] = frust.m[0][3] = 0.0f; frust.m[1][1] = 2.0f * nearZ / deltaY; frust.m[1][0] = frust.m[1][2] = frust.m[1][3] = 0.0f; frust.m[2][0] = (right + left) / deltaX; frust.m[2][1] = (top + bottom) / deltaY; frust.m[2][2] = -(nearZ + farZ) / deltaZ; frust.m[2][3] = -1.0f; frust.m[3][2] = -2.0f * nearZ * farZ / deltaZ; frust.m[3][0] = frust.m[3][1] = frust.m[3][3] = 0.0f; esMatrixMultiply(result, &frust, result); } My projection matrix comes out as: [3.21, 0, 0, 0] [0, 2.41, 0, 0] [0, 0, -1, -1] [0, 0, -2, 0] Even if I manually set the [3][3] cell to 1 I still don't see anything. Any ideas?

    Read the article

  • displaying the values in textbox based on AJAX fetched entries

    - by Anurag
    hello, I've a table in which addition rows can be generatred as per the user need by clicking a javascript function. Each row has a drop down list, and based on the values of this an AJAX script fetchs some values which has to be displayed in corresponding textfields of the same row.. here is the code for HTML.. <td><div align="center"> <label> <select name="gcno1" id="gcno1" onchange="fetch_gc(this)"> <option value="0">NIL</option> <option value="2">1</option> <?php while($row=mysql_fetch_array($result)) { ?> <option value="<?php echo $row[0]; ?>"><?php echo $row[0]; ?></option> <?php }?> </select> </label> </div></td> <td><div align="center"><input name="date1" id="date1" type="text" size="10" /> </div></td> and here is the AJAX which I'm writing... xmlhttp = new XMLHttpRequest(); var value=encodeURIComponent(document.getElementById('gcno1').value); var parameters="param1="+value; xmlhttp.open("POST", 'fetch_gc.php', true); xmlhttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); xmlhttp.send(parameters); xmlhttp.onreadystatechange=function(){ if(xmlhttp.readyState == 4 && xmlhttp.status == 200) { var detail=xmlhttp.responseText.split('+'); alert(detail[0]); document.getElementsByName('date1').value=String(detail[0]); alert("life " + document.getElementById('gcno1').value); } } The alert inside the AJAX shows the correct response text, detail[0] but is unable to put the value in corresponding textbox i.e. with name 'gcno1'...... Please help me with this problem...

    Read the article

  • Having a problem displaying data from last inserted data

    - by Gideon
    I'm designing a staff rota planner....have three tables Staff (Staff details), Event (Event details), and Job (JobId, JobDate, EventId (fk), StaffId (fk)). I need to display the last inserted job detail with the staff name. I've been at it for couple of hours and getting nowhere. Thanks for the help in advance. My code is the following: $eventId = $_POST['eventid']; $selectBox = $_POST['selectbox']; $timePeriod = $_POST['time']; $selectedDate = $_POST['date']; $count = count($selectBox); //constructing the staff selection if (empty($selectBox)) { echo "<p>You didn't select any member of staff to be assigned."; echo "<p><input type='button' value='Go Back' onClick='history.go(-1)'>"; } else { echo "<p> You selected ".$count. " staff for this show."; for ($i=0;$i<$count;$i++) { $selectId = $selectBox[$i]; //insert the details into the Job table in the database $insertJob = "INSERT INTO Job (JobDate, TimePeriod, EventId, StaffId) VALUES ('".$selectedDate."', '".$timePeriod."', ".$eventId.", ".$selectId.")"; $exeinsertJob = mysql_query($insertJob) or die (mysql_error()); } } //display the inserted job details $insertedlist = "SELECT Job.JobId, Staff.LastName, Staff.FirstName, Job.JobDate, Job.TimePeriod FROM Staff, Job WHERE Job.StaffId = Staff.StaffId AND Job.EventId = $eventId AND Job.JobDate = ".$selectedDate; $exeinsertlist = mysql_query($insertedlist) or die (mysql_error()); if ($exeinsertlist) { echo "<p><table cellspacing='1' cellpadding='3'>"; echo "<tr><th colspan=5> ".$eventname."</th></tr>"; echo "<tr><th>Job Id</th><th>Last Name</th> <th>First Name </th><th>Date</th><th>Hours</th></tr>"; while ($joblistarray = mysql_fetch_array($exeinsertlist)) { echo "<tr><td align=center>".$joblistarray['JobId']." </td><td align=center>".$joblistarray['LastName']."</td><td align=center>".$joblistarray['FirstName']." </td><td align=center>".$joblistarray['JobDate']." </td><td align=center>".$joblistarray['TimePeriod']."</td></tr>"; } echo "</table>"; echo "<h3><a href=AssignStaff.php>Add More Staff?</a></h3>"; } else { echo "The Job list can not be displayed at this time. Try again."; echo "<p><input type='button' value='Go Back' onClick='history.go(-1)'>"; }

    Read the article

  • NavBar displaying back twice when app changed to landscape mode

    - by Graeme
    Hi, Not sure what's going on here, but my iPhone apps nav bar shows back and the title of my detail view controller even when I'm back to the original view. It wasn't happening earlier, it has changed recently (but not sure when exactly). E.g. I click on a row, view the didSelectRow XIB and then click back on the NavBar controller, but it still shows back even though the view does change back to the original table view. I then have to press back again and then it clears. Update: It's as if its trying to go back three times instead of two. Because, if you visit another row without removing the back button, it stores it as if you need to go back twice. It works fine in portrait mode. Any ideas?

    Read the article

  • Cocoa class not displaying data in NSWindow

    - by Matt S.
    I have one class that controls one window, and another class that controls a different window in the same xib, however, the second window never displays what it should. In the first class I alloc and init the second class, then pass some information to it. In the second class it displays that data in the table view. Yes, in the .xib I have all the connections set up correctly, I've quadruple checked. Also the code is correct, same with the connections, I've quadruple checked.

    Read the article

  • List view and list adapters for displaying json

    - by Rahul Varma
    Hi, I am trying to display the text from json in a list view. I got help for retrieving the json text from the following... http://www.josecgomez.com/2010/04/30/android-accessing-restfull-web-services-using-json/comment-page-1/#comment-498.... But my problem is that i cant figure out how to display them in list view. I also want to get only some of the text from url(for example, alerttext and date). Can anyone help me in declaring the list adapter and list view in order to display the data in the way i want... Plzzzz...

    Read the article

  • A good solution for displaying galleries with lytebox and php

    - by Johann
    Hello I have thought for a while over an issue with the loading of images on a website-solution that I have programmed (For fun and the experience) The programming language used is PHP with MYSQL as the database language It also uses javascript, but not extensively I have recently realized that the engine I programmed, while it has it's smart solutions also carry a lot of flaws and redundant code. I have therefore decided to make a new one, now incorporating what I know, but didn't when I started the previous project. For the new system, there will be an option to add galleries to a site, and upload images to it. I have used the javascript image viewer Lytebox before. The screen goes dark and an image appears with a "Previous" and "next" button to view the other images. The problem is that I used groups with lytebox and the images themselves, resized as thumbs. This causes lytebox to work only when all the images have loaded. If you click a link before that, the image is shown as if you right click and choose "Show image" Information about these images is parsed from a database using a while statement with a counter that goes from 0 to sizeof() I'm thinking it probably isn't a good idea to have the images as the thumbs, even if you restrict the upload size. Likewise, adding thumbs at upload also seems like a hassle. It would be practical if the thumbs didn't show up before they were fully loaded. Has anyone got any good tips. Any help would be appreciated. Johann

    Read the article

  • jquery-ui autocomplete with ASP MVC suggestions not displaying

    - by adamnickerson
    I have been trying to get a simple example of the jquery-ui autocomplete to work. I have a controller setup to handle the query, and it returns the json that looks to be in order, but I am getting no suggestions showing up. Here are the js libraries I am including: <script type="text/javascript" language="javascript" src="/Scripts/jquery-1.4.1.js"></script> <script type="text/javascript" language="javascript" src="/Scripts/jquery-ui-1.8.1.custom.min.js"></script> <link href="/Content/jquery-ui-1.8.1.custom.css" rel="stylesheet" type="text/css" /> and here is the javascript and the form tags: <script type="text/javascript"> $(function () { $("#organization").autocomplete({ source: function (request, response) { $.ajax({ url: '/Organization/OrganizationLookup', dataType: "json", data: { limit: 12, q: request.term } }) }, minLength: 2 }); }); </script> <div class="ui-widget"> <label for="organization">Organization: </label> <input id="organization" /> </div> I get back a json response that looks reasonable from my controller: [{"id":"Sector A","value":"Sector A"},{"id":"Sector B","value":"Sector B"},{"id":"Sector C","value":"Sector C"}] id and value seem to be the default naming that autocomplete is looking for. But I get no joy at all. Any thoughts?

    Read the article

  • Displaying build times in Visual Studio?

    - by Roger Lipscombe
    Our build server is taking too long to build one of our C++ projects. It uses Visual Studio 2008. Is there any way to get devenv.com to log the time taken to build each project in the solution, so that I know where to focus my efforts? Improved hardware is not an option in this case. I've tried setting the output verbosity (under Tools / Options / Projects and Solutions / Build and Run / MSBuild project build output verbosity). This doesn't seem to have any effect in the IDE. When running MSBuild from the command line (and, for Visual Studio 2008, it needs to be MSBuild v3.5), it displays the total time elapsed at the end, but not in the IDE. I really wanted a time-taken report for each project in the solution, so that I could figure out where the build process was taking its time. Alternatively, since we actually use NAnt to drive the build process (we use Jetbrains TeamCity), is there a way to get NAnt to tell me the time taken for each step?

    Read the article

  • Retrieving and displaying a contact name from a contact id while using a SimpleCursorAdapter

    - by Henrique
    I am storing information on the phone's contacts using a sqlite database. The fields I am storing are: _id, contact_id, body where _id is the row's id, contact_id is the phone contact's id and body is just a simple text which is the actual information I am storing. I'm using a SimpleCursorAdapter to map the data to the view, like so: Cursor cursor = database.fetchInformation(); // fetch info from DB String[] from = new String[] { CONTACT_ID, BODY }; int[] to = new int[] { R.id.contact, R.id.body }; SimpleCursorAdapter adapter = new SimpleCursorAdapter(this, R.layout.row, cursor, from, to); getListView().setAdapter(adapter); What I would actually want is to get the contact name that is associated with this CONTACT_ID, and have that be shown in the view. I can't seem to find a simple solution. I've tried implementing my own SimpleCursorAdapter and rewriting setViewText(TextView, String) but it didn't work. Also, it just seems overly complicated for such a simple task. Any help? Thanks.

    Read the article

  • Mobile web on nokia devices not displaying centain elements

    - by Jan de Jager
    So i have a site which is rendered with our in-house portal engine. It resizes images and adjusts style-sheets automatically in real-time. Issue is that some html elements are inexplicably disappearing due to what only can be described as HTML compatibility. But the problem is not consistent. And only seems to be an issue on some nokia devices. I have tried to install the Nokia Mobile Browser Emulator... but its the worst piece of software i have seen in my life... after 4 hours of installing and uninstalling different versions of JRE, i still can't get it to install. EDIT: Problem now residing at http://wiseguy.mobi/?PageID=657

    Read the article

  • FF extension: displaying an array of string elements in a sidebar

    - by sujay-jain
    I am developing a ff extension which displays a list of elements from an array (dynamic) in the sidebar. The array is dynamic and needs to be constructed in a function everytime the sidebar is opened (or any other event handler). Later, i will need to implement link functionality on parts of the string. What is the best way to go about this? I have created an empty sidebar and just know the label element as of now. menu, and menuitem dont work. What other elements can i use to display text in a good way which supports dynamic contruction. Is there some good tutorial/sample extension which i can see and learn?

    Read the article

  • displaying german characters in iphone

    - by Jaimin
    i have following string coming in the json response. "Gas-Heizung-Sanit\u00e4r" so how to display it. i want to display that \u00e4 as a german character.. NSString *str = "Gas-Heizung-Sanit\u00e4r"; NSLog(@"%c",str); it only prints the german character.

    Read the article

  • Displaying success/failure messages from hidden iframe submit

    - by Erik Nelson
    I'm using the hidden iframe method to submit a form with a file upload field. I want to display a message back on the page using javascript and I'm not sure how to do this. If this was just a form with text fields I'd do an AJAX post and respond with a message I'd display in my callback function. I'm just not sure how to accomplish this same task with the hidden iframe method since it is a standard form post.

    Read the article

  • Displaying current time above the thumb of a slider in Silverlight

    - by Scharrels
    I've made a time slider in Silverlight. To style it, I've made a control template and modified the style. I've added a text field above the thumb (always centered above the thumb), which should display the time. However, I can't find any way to access the slider information (e.g. current value) or find another way to pass any information to the style, which I can then data bind to the text field. So my question in short: how can I display time information above the thumb?

    Read the article

  • Displaying an image from the tmp directory

    - by Roland
    I have the following. A website that create temporarily images in the /tmp folder on the Linux server. The reason why I store it within this folder is since these images need to be cleared once in a while and it's so much easier just to clear the tmp directory using tmpwatch. Now my issue is to display the image within my browser? Code <img src="/tmp/3d34636.png" alt="image" /> I'm running Centos with PHP

    Read the article

  • Displaying a To-Many Relationship in a Table View

    - by DanF
    I've got an application I've been working on. There are projects and employees, projects can have several employees, employees can work on several projects. Right now I want selecting a project to display which employees are related to it, and allows me to add employees I select from another full-roster list. Somehow, this has proven more complicated, because (at least for now), selecting different projects still displays the same list of employees, as if all employees who'd been assigned to any project, belong to all of them. What part of Master-Detail am I missing?

    Read the article

  • Displaying very large images on the iPad

    - by Brodie4598
    I need to display some very large images on the iPad. The files are jpgs and are about 6700x2700 (maps). Is there any way around loading the entire image into memory? Currently I load it int a scroll view for zooming/panning. The images are stored locally on the device.

    Read the article

  • session management: problem displaying username in the header

    - by aeonsleo
    hi, I am working on a simple login and logout module for my website without any security. I am using wamp on a windows xp machine. I am creating session when a user submits the login informaton it redirects to a process.php file which creates the session variables and starts session. Now if the login is successful user is redirected to the welcome page which includes a header file(which displays the header involving signin logout help options) The problem is the header is not changing the signin link to logout as the user logs successfully. The below code is from process.php which initiates a login. $username = $_POST['username']; $password = $_POST['password']; //echo "{$username}:{$password}"; $connection = mysql_connect("localhost","root",""); if(!$connection) { die("Database Connection Failed".mysql_error()); } $db_select = mysql_select_db("tester",$connection); if(!$db_select) { die("Database Selection Failed".mysql_error()); } $result = mysql_query("SELECT * FROM user",$connection); if(!$result) { die("Database Selection Failed".mysql_error()); } $q = "SELECT * FROM user " ."WHERE Name='".$username."' AND Password='".$password. "' "; // Run query $r = mysql_query($q); if ( $obj = @mysql_fetch_object($r) ) { session_start(); // Login good, create session variables $_SESSION["valid_id"] = session_id(); $_SESSION["valid_user"] = $_POST["username"]; $_SESSION["valid_time"] = time(); Header('Location: welcome.php'); The following code is from header.php which is included in welcome.php </div> <div id = "userdetail"> <?php if(isset($_SESSION["valid_user"])) { echo($_SESSION["valid_user"]." " ); echo("<a href=logout.php>Logout</a>"); } else { echo("<a href = login.php>Sign In</a>"); } ?> | Help | Search <input type = "text" name = "searchbox" value = "" /> </div> </div>

    Read the article

< Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >