Search Results

Search found 9638 results on 386 pages for 'matlab engine'.

Page 18/386 | < Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >

  • Sorting in Matlab

    - by smichak
    Hi, I would like to sort elements in a comma-separated list. The elements in the list are structs and I would like the list to be sorted according to one of the fields in the struct. For example, given the following code: L = {struct('obs', [1 2 3 4], 'n', 4), struct('obs', [6 7 5 3], 'n', 2)}; I would want to have a way to sort L by the field 'n'. Matlab's sort function only works on matrices or arrays and on lists of strings (not even lists of numbers). Any ideas on how that may be achieved? Thanks, Micha

    Read the article

  • Get dimensions for dataset matlab, Size Function

    - by Tim
    Hello I have been trying to display the dimensions of a dataset, below is the following matlab code that i used...but it gives me the wrong output....i'e number of rows and columns values are wrong....any help regarding this issue would be highly appreciated [file_input,pathname] = uigetfile( ... {'*.txt', 'Text (*.txt)'; ... '*.xls', 'Excel (*.xls)'; ... '*.*', 'All Files (*.*)'}, ... 'Select files'); [pathstr, name, ext, versn] = fileparts(file_input) r = size(name,1); c = size(name,2); disp(r) disp(c)

    Read the article

  • troubles with integration on matlab

    - by user648666
    I'd like some help please I really need to solve this problem. Well before anything thank you for your time... My problem: I have a matrix (826x826 double) and I want to integrate this matrix with respect to a vector of (826x1 double) I don't have the functions of any of this. Is there a command or an algorithm to take the integral of a matrix with respect to a vector? Please I really need help, I'm such a newbie at matlab. Sincerely. George

    Read the article

  • FFT in MATLAB: wrong 0Hz frequency

    - by roujhan
    Hello I want to use fft in MATLAB to analize some exprimental data saved as an excell file. my code: A=xlsread('Book.xls'); G=A'; x=G(2, : ); N=length(x); F=[-N/2:N/2-1]/N; X = abs(fft(x-mean(x),N)) X = fftshift(X); plot(F,X) But it plots a graph with a large 0Hz wrong component, my true frequency is about 395Hz and it is not shown in the plotted graph. Please tell me what is wrong. Any help would be appreciated.

    Read the article

  • Reading Matrices in MATLAB and assigning coordinates to the entries

    - by Michael Schofield
    Hi, I'm a bit new to MATLAB. Basically, I have a 25x25 Matrix, complete with various random entries ranging from 0 to 3. I need to write a program that reads this matrix, and assigns x-y coordinates to the entries, so that when I ask for an input of a particular x-y coordinate which has, say an entry of 3, then it will result in an error. I'm a bit overwhelmed - but I understand the general concept of what I'm supposed to be finding. I'm wondering if I should use a plot instead to help me.

    Read the article

  • Background subtracting in MATLAB

    - by eiphyomin
    I'm looking to do background subtracting on an image. I'm new to MATLAB and new to image processing/analysis, so sorry if any of this sounds stupid. 1) Other than imsubtract() are there other ways to do background subtracting (besides comparing one image to another)? 2) In the Math Works explanation for imsubtract() why do they make their structuring element a disk? This seems rather difficult so far because every time I try something, I end up not only subtracting the noisy background but also losing the parts of the image I want to look at!

    Read the article

  • read text files containing binary data as a single matrix in matlab

    - by user1716595
    I have a text file which contains binary data in the following manner: 00000000000000000000000000000000001011111111111111111111111111111111111111111111111111111111110000000000000000000000000000000 00000000000000000000000000000000000000011111111111111111111111111111111111111111111111000111100000000000000000000000000000000 00000000000000000000000000000000000011111111111111111111111111111111111111111111111111111111100000000000000000000000000000000 00000000000000000000000000000000000111111111111111111111111111111111111111111111111111111111100000000000000000000000000000000 00000000000000000000000000000000000011111111111111111111111111111111111111111111111111111111100000000000000000000000000000000 00000000000000000000000000000000000000011111111111111111111111111111111111111111111111111111100000000000000000000000000000000 00000000000000000000000000000000000000011111111111111111111111111111111111111111111111000111110000000000000000000000000000000 00000000000000000000000000000000000000111111111111111111111111111111111111111111111111111111110000000000000000000000000000000 00000000000000000000000000000000000000000000111111111111111111111111111111111111110000000011100000000000000000000000000000000 00000000000000000000000000000000000000011111111111111111111111111111111111111111111111100111110000000000000000000000000000000 00000000000000000000000000000000000111111111111111111111111111111111111111111111111111110111110000000000000000000000000000000 00000000000000000000000000000000001111111111111111111111111111111111111111111111111111111111100000000000000000000000000000000 00000000000000000000000000000000000000001111111111111111111111111111111111111111111111000011100000000000000000000000000000000 00000000000000000000000000000000000000001111111111111111111111111111111111111111111111000011100000000000000000000000000000000 00000000000000000000000000000000000001111111111111111111111111111111111111111111111111111111000000000000000000000000000000000 00000000000000000000000000000000000000011111111111111111111111111111111111111111111110000011100000000000000000000000000000000 00000000000000000000000000000000000000000000011111111111111111111111111111111111100000000011100000000000000000000000000000000 00000000000000000000000000000000000000111111111111111111111111111111111111111111111111110111100000000000000000000000000000000 Plz note that each 1 or 0 is independent i.e the values are not decimal.I need to find the column wise sum of the file.There are 125 columns in all (here it is jumping onto the next line) and there are 840946 rows. I have tried textread,fscanf and a few other matlab commands but the result is that they all read each row in decimal format and create a 840946*1 array.I want to create a 840946*125 array to compute a column wise sum. Kindly help, Thanks!

    Read the article

  • MATLAB: Designing a "Warm Start"

    - by squall14414
    I'm currently coding a function in MATLAB that has two steps: It processes some data It does some calculations on the processed data I'm using the function to run a series of experiments, where I tweak the way calculations occur in step 2). Seeing how I'm working with a large dataset and the data processing step takes a while each time, however, I'm wondering whether there is anyway to code in a "warm start" in the function. That is to say, is there anyway to save all the progress that I've done after step 1) so that if I run the function a second or third time, it can skip step 1) and go right to step 2)?

    Read the article

  • MatLab plot part of surface

    - by Kristian
    Say I have the following script: u = -5:.2:5; [X,Y] = meshgrid(u, u); Z = cos(X).*cos(Y).*exp(-sqrt(X.^2 + Y.^2)/4); surf(X,Y,Z); Is there anyway that I can make MatLab plot only parts of the surface? Say, for instance, I just want to plot a single point, or a single grid, what can I do? I thought perhaps to plot a single point I could use: surf(X(1,1), Y(1,1), Z(1,1)) But then I get the error message: ??? Error using ==> surf at 78 Data dimensions must agree. I would really appreciate some input/help here. Thanks in advance :)

    Read the article

  • Finding whether a value is equal to the value of any array element in MATLAB

    - by James
    Hi, Can anyone tell me if there is a way (in MATLAB) to check whether a certain value is equal to any of the values stored within another array? The way I intend to use it is to check whether an element index in one matrix is equal to the values stored in another array (where the stored values are the indexes of the elements which meet a certain criteria). So, if the indices of the elements which meet the criteria are stored in the matrix below: criteriacheck = [3 5 6 8 20]; Going through the main array (called array) & checking if the index matches: for i = 1:numel(array) if i == 'Any value stored in criteriacheck' ... "Do this" end Does anyone have an idea of how I might go about this? Thanks in advance

    Read the article

  • DAQ Triggers in Matlab

    - by RidePlanet
    I'm writing a program that detects the speed of a object by hall effect sensors that are run into MATLAB through a DAQ (MCC USB-1408FS) The problem that has arisen is that I'm using a non-stop scan technique to detect the state of one of 3 sensors. Unfortunately this means that unless the object is rotating past each sensor at the exact rate the program runs, I will see an instantaneous speed (done by comparing the time between two sensors) of zero. I need the sensors to signal the program to count when they are hit, instead of constantly scanning for the signal. How can this be done?

    Read the article

  • summing up excel files in matlab

    - by AP
    Is there a easy good way to sum up various excel files in matlab? what i really want is similar to dos command type file*.xls sumfile.xls I have from 10-100 excel files with similar file name formats excet the date XXXXX_2010_03_03.xls, XXXXX_2010_03_03.xls and so on..... Is there a command to copy the files one after other. All files are of diff length so i cannot know the position of the rows after each file. I would like to have them copied in same sheet of excel. Thanks

    Read the article

  • Skip reading strings in matlab

    - by Paul
    Is there is easy command in matlab which prevents program from crashing when it reads characters? I use xlsread to read a (20 400) matrix data , the first row and column get disregarded as they have headers, so that: data = xlsread ( ' C:\file.xls') results in data with a size of (19 399). I have a problem, some cells have missing data and it's written ' missing' and on some data sets i have headers reappear in middle. Is there a way to skip these characters without the program crashing and me having to open the file in excel and deleting those fields? Thanks

    Read the article

  • How does one escape the GPL?

    - by tehtros
    DISCLAIMER I don't pretend to know anything about licensing. In fact, everything I say below may be completely false! Backstory: Recently, I've been looking for a decent game engine, and I think I've found one that I really like, Cafu Engine. However, they have a dual licensing plan, where everything you make with the engine is forced under GPL, unless you pay for a commercial license. I'm not saying that it's a bad engine, they even say that they are very relaxed about the licensing fees. However, the fact that it even involves the GPL scares me. So my question is basicly, how does one escape the GPL. Here's an example: The id Tech engine, also known as the Quake engine, or the Doom engine, was the base for the popular Source engine. However, the id Tech engine has been released under the GPL, and the Source engine is proprietary. Did Valve get a different license? Or did they do something to escape the GPL? Is there a way to escape the GPL? Or, if you use GPL'd source code as a base for another project, are you forced to use the GPL, and make your source code available to the world. Could some random person take the id Tech engine, modify it past the point of recognition, then use it as a proprietary engine for commercial products? Or are they required to make it open source. One last thing, I generally have no problem what-so-ever with open source. However I feel that open source has it's place, but that is not in the bushiness world.

    Read the article

  • Pros & Cons of Google App Engine

    - by Rishi
    Pros & Cons of Google App Engine [An Updated List 21st Aug 09] Help me Compile a List of all the Advantages & Disadvantages of Building an Application on the Google App Engine Pros: 1) No Need to buy Servers or Server Space (no maintenance). 2) Makes solving the problem of scaling much easier. Cons: 1) Locked into Google App Engine ?? 2)Developers have read-only access to the filesystem on App Engine. 3)App Engine can only execute code called from an HTTP request (except for scheduled background tasks). 4)Users may upload arbitrary Python modules, but only if they are pure-Python; C and Pyrex modules are not supported. 5)App Engine limits the maximum rows returned from an entity get to 1000 rows per Datastore call. 6)Java applications may only use a subset (The JRE Class White List) of the classes from the JRE standard edition. 7)Java applications cannot create new threads. Known Issues!! http://code.google.com/p/googleappengine/issues/list Hard limits Apps per developer - 10 Time per request - 30 sec Files per app - 3,000 HTTP response size - 10 MB Datastore item size - 1 MB Application code size - 150 MB Pro or Con? App Engine's infrastructure removes many of the system administration and development challenges of building applications to scale to millions of hits. Google handles deploying code to a cluster, monitoring, failover, and launching application instances as necessary. While other services let users install and configure nearly any *NIX compatible software, App Engine requires developers to use Python or Java as the programming language and a limited set of APIs. Current APIs allow storing and retrieving data from a BigTable non-relational database; making HTTP requests; sending e-mail; manipulating images; and caching. Most existing Web applications can't run on App Engine without modification, because they require a relational database.

    Read the article

  • pluto or jetspeed on google app engine?

    - by Patrick Cornelissen
    I am trying to build something "portlet server"-ish on the google app engine. (as open source) I'd like to use the JSR168/286 standards, but I think that the restrictions of the app engine will make it somewhere between tricky and impossible. Has anyone tried to run jetspeed or an application that uses pluto internally on the google app engine? Based on my current knowledge of portlets and the google app engine I'm anticipating these problems: A war file with portlets is from the deployment standpoint more or less a complete webapp (yes, I know that it doesn't really work without a portal server). The war file may contain it's own web.xml etc. This makes deployment on the app engine rather difficult, because the apps are not visible to each other, so all portlet containing archives need to be included in the war file of the deployed "app engine based portal server". The "portlets" are (at least in liferay) started as permanent servlet processes, based on their portlet.xmls and web.xmls which is located in the same spot for every portlet archive that is loaded. I think this may be problematic in the app engine, because everything is in one big "web app", so it may be tricky to access the portlet.xmls from each archive. This prevents a 100% compatibility in my opinion. Is here anyone who has any experience with the combination of portlets and the app engine? Do you think it's feasible to modify jetspeed, pluto or any other portlet container to be able to run it on the app engine?

    Read the article

  • MATLAB intersection of 2 surfaces

    - by caglarozdag
    Hi everyone, I consider myself a beginner in MATLAB so bear with me if the answer to my question is an obvious one. Phi=0:pi/100:2*pi; Theta=0:pi/100:2*pi; [PHI,THETA]=meshgrid(Phi,Theta); R=(1 + cos(PHI).*cos(PHI)).*(1 + cos(THETA).*cos(THETA)); [X,Y,Z]=sph2cart(THETA,PHI,R); surf(X,Y,Z); %display hold on; x1=-4:.1:4; [X1,Y1] = meshgrid(x1); a=1.8; b=0; c=3; d=0; Z1=(d- a * X1 - b * Y1)/c; shading flat; surf(X1,Y1,Z1); I have written this code which plots a 3d cartesian plot of a plane intersecting a peanut shaped object at an angle. I need to get the intersection of these on 2D (going to be the outline of a peanut, but a bit skewed since the intersection happens at an angle), but don't know how. Thanks

    Read the article

  • Problem in matlab with too many outputs

    - by Ben Fossen
    I am writing a Matlab program for simpson's rule I keep getting an error about to many outputs when the program gets to left_simpson = Simpson(a,c,(e1)/2,level, level_max); What is wrong with settinf left_simpson to Simpson(a,c,(e1)/2,level, level_max);? function Simpson(a,b,e1,level, level_max) level = level + 1; h = b - a; c = (a+b)/2; one_simpson = h*(f(a) + 4*f(c) + f(b))/6; d = (a+c)/2; e = (c+b)/2; two_simpson = h*(f(a) + 4*f(d) + 2*f(c) + 4*f(e))/2; if level >= level_max disp('h') simpson_result = two_simpson; disp('maximum levels reached') disp(simpson_result); if abs(two_simpson - one_simpson) < 15*e1 simpson_result = two_simpson + (two_simpson - one_simpson)/15; else left_simpson = Simpson(a,c,(e1)/2,level, level_max); right_simpson = Simpson(c,b,(e1)/2,level, level_max); simpson_result = left_simpson + right_simpson; end end

    Read the article

  • matlab precision determint problem

    - by ldigas
    I have the following program format compact; format short g; clear; clc; L = 140; J = 77; Jm = 10540; G = 0.8*10^8; d = L/3; for i=1:500000 omegan=1.+0.0001*i; a(1,1) = ((omegan^2)*(Jm/(G*J))*d^2)-2; a(1,2) = 2; a(1,3) = 0; a(1,4) = 0; a(2,1) = 1; a(2,2) = ((omegan^2)*(Jm/(G*J))*d^2)-2; a(2,3) = 1; a(2,4) = 0; a(3,1) = 0; a(3,2) = 1; a(3,3) = ((omegan^2)*(Jm/(G*J))*d^2)-2; a(3,4) = 1; a(4,1) = 0; a(4,2) = 0; a(4,3) = 2; a(4,4) = ((omegan^2)*(Jm/(G*J))*d^2)-2; if(abs(det(a))<1E-10) sprintf('omegan= %8.3f det= %8.3f',omegan,det(a)) end end Analytical solution of the above system, and the same program written in fortran gives out values of omegan equal to 16.3818 and 32.7636 (fortran values; analytical differ a little, but they're there somewhere). So, now I'm wondering ... where am I going wrong with this ? Why is matlab not giving the expected results ? (this is probably something terribly simple, but it's giving me headaches)

    Read the article

  • Matlab-Bisection-Newton-Secant , finding roots?

    - by i z
    Hello and thanks in advance for your possible help ! Here's my problem: I have 2 functions f1(x)=14.*x*exp(x-2)-12.*exp(x-2)-7.*x.^3+20.*x.^2-26.*x+12 f2(x)=54.*x.^6+45.*x.^5-102.*x.^4-69.*x.^3+35.*x.^2+16.*x-4 Make the graph for those 2, the first one in [0,3] and the 2nd one in [-2,2]. Find the 3 roots with accuracy of 6 decimal digits using a) bisection ,b) newton,c)secant.For each root find the number of iterations that have been made. For Newton-Raphson, find which roots have quadratic congruence and which don't. What is the main common thing that roots with no quadratic congruence (Newton's method)? Why ? Excuse me if i ask silly things, but i'm asked to do this with no Matlab courses and I'm trying to learn it myself. There are many issues i have with this exercise . Questions : 1.I only see 2 roots in the graph for the f1 function and 4-5 (?) roots for the function f2 and not 3 roots as the exercise says. Here's the 2 graphs : http://postimage.org/image/cltihi9kh/ http://postimage.org/image/gsn4sg97f/ Am i wrong ? Do both have only 3 roots in [0,3] and [-2,2] ? Concerning the Newton's method , how am i supposed to check out which roots have quadratic congruence and which not??? Accuracy means tolerance e=10^(-6), right ?

    Read the article

  • matlab precision determinant problem

    - by ldigas
    I have the following program format compact; format short g; clear; clc; L = 140; J = 77; Jm = 10540; G = 0.8*10^8; d = L/3; for i=1:500000 omegan=1.+0.0001*i; a(1,1) = ((omegan^2)*(Jm/(G*J))*d^2)-2; a(1,2) = 2; a(1,3) = 0; a(1,4) = 0; a(2,1) = 1; a(2,2) = ((omegan^2)*(Jm/(G*J))*d^2)-2; a(2,3) = 1; a(2,4) = 0; a(3,1) = 0; a(3,2) = 1; a(3,3) = ((omegan^2)*(Jm/(G*J))*d^2)-2; a(3,4) = 1; a(4,1) = 0; a(4,2) = 0; a(4,3) = 2; a(4,4) = ((omegan^2)*(Jm/(G*J))*d^2)-2; if(abs(det(a))<1E-10) sprintf('omegan= %8.3f det= %8.3f',omegan,det(a)) end end Analytical solution of the above system, and the same program written in fortran gives out values of omegan equal to 16.3818 and 32.7636 (fortran values; analytical differ a little, but they're there somewhere). So, now I'm wondering ... where am I going wrong with this ? Why is matlab not giving the expected results ? (this is probably something terribly simple, but it's giving me headaches)

    Read the article

  • MATLAB Easter Egg Spy vs Spy

    - by Aqui1aZ3r0
    I heard that MATLAB 2009b or earlier had a fun function. When you typed spy in the console, you would get something like this: http://t2.gstatic.com/images?q=tbn:ANd9GcSHAgKz-y1HyPHcfKvBpYmZ02PWpe3ONMDat8psEr89K0VsP_ft However, now you have an image like this:http://undocumentedmatlab.com/images/spy2.png I'd like it if I could get the code of the original spy vs spy image FYI, there's a code, but has certain errors in it: c = [';@3EA4:aei7]ced.CFHE;4\T*Y,dL0,HOQQMJLJE9PX[[Q.ZF.\JTCA1dd' '-IorRPNMPIE-Y\R8[I8]SUDW2e+' '=4BGC;7imiag2IFOQLID8''XI.]K0"PD@l32UZhP//P988_WC,U+Z^Y\<2' '&lt;82BF>?8jnjbhLJGPRMJE9/YJ/L1#QMC$;;V[iv09QE99,XD.YB,[_]=3a' '9;CG?@9kokc2MKHQSOKF:0ZL0aM2$RNG%AAW\jw9E.FEE-_G8aG.d]_W5+' '?:CDH@A:lpld3NLIRTPLG=1[M1bN3%SOH4BBX]kx:J9LLL8H9bJ/+d_dX6,' '@;DEIAB;mqmePOMJSUQMJ2\N2cO4&TPP@HCY^lyDKEMMN9+I@+S8,+deY7^' '8@EFJBC<4rnfQPNPTVRNKB3]O3dP5''UQQCIDZ_mzEPFNNOE,RA,T9/,++\8_' '9A2G3CD=544gRQPQUWUOLE4^P4"Q6(VRRIJE[n{KQKOOPK-SE.W:F/,,]Z+' ':BDH4DE>655hSRQRVXVPMF5_Q5#R>)eSSJKF\ao0L.L-WUL.VF8XCH001_[,' ';3EI<eo ?766iTSRSWYWQNG6$R6''S?*fTTlLQ]bp1M/P.XVP8[H9]DIDA=]' '?4D3=FP@877jUTSTXZXROK7%S7(TF+gUUmMR^cq:N9Q8YZQ9_IcIJEBd_^' '@5E@GQA98b3VUTUY*YSPL8&T)UI,hVhnNS_dr;PE.9Z[RCaR?+JTFC?e+' '79FA?HRB:9c4WVUVZ+ZWQM=,WG*VJ-"gi4OTes-XH+bK.#hj@PUvftDRMEF,]UH,UB.TYVWX,e\' '9;ECAKTY< ;eWYXWX\:)YSOE.YI,cL/$ikCqV1guE/PFL-^XI-YG/WZWXY1+]' ':AFDBLUZ=jgY[ZYZ-<7[XQG0[K.eN1&"$K2u:iyO9.PN9-_K8aJ9_]]82[' '?CEFDNW\?khZ[Z[==8\YRH1\M/!O2''#%m31Bw0PE/QXE8+R9bS;da^]93\' '@2FGEOX]ali[][9(ZSL2]N0"P3($&n;2Cx1QN9--L9,SA+T< +d_:4,' 'A3GHFPY^bmj\^]\]??:)[TM3^O1%Q4)%''oA:D0:0OE.8ME-TE,XB,+da;5[' '643IGQZ_cnk]_^]^@@;5\UN4_P2&R6*&(3B;E1<1PN99NL8WF.^C/,a+bY6,' '7:F3HR[dol^_^AA<6]VO5Q3''S>+'');CBF:=:QOEEOO9_G8aH6/d,cZ[Y' '8;G4IS\aep4_a-BD=7''XP6aR4(T?,(5@DCHCC;RPFLPPDH9bJ70+0d\\Z' '9BH>JT^bf45ba.CE@8(YQ7#S5)UD-)?AEDIDDD/QKMVQJ+S?cSDF,1e]a,' ':C3?K4_cg5[acbaADFA92ZR8$T6*VE.*@JFEJEEE0.NNWTK,U@+TEG0?+_bX' ';2D@L9dh6\bdcbBEGD:3[S=)U7+cK/+CKGFLIKI9/OWZUL-VA,WIHB@,`cY']; i = double(c(:)-32); j = cumsum(diff([0; i])< =0) + 1; S = sparse(i,j,1)'; spy(S)

    Read the article

  • How to hide zero values in bar3 plot in MATLAB

    - by Doresoom
    I've got a 2-D histogram (the plot is 3D - several histograms graphed side by side) that I've generated with the bar3 plot command. However, all the zero values show up as flat squares in the x-y plane. Is there a way I can prevent MATLAB from displaying the values? I already tried replacing all zeros with NaNs, but it didn't change anything about the plot. Here's the code I've been experimenting with: x1=normrnd(50,15,100,1); %generate random data to test code x2=normrnd(40,13,100,1); x3=normrnd(65,12,100,1); low=min([x1;x2;x3]); high=max([x1;x2;x3]); y=linspace(low,high,(high-low)/4); %establish consistent bins for histogram z1=hist(x1,y); z2=hist(x2,y); z3=hist(x3,y); z=[z1;z2;z3]'; bar3(z) As you can see, there are quite a few zero values on the plot. Closing the figure and re-plotting after replacing zeros with NaNs seems to change nothing: close z(z==0)=NaN; bar3(z)

    Read the article

  • Assigning figure size to a figure with a given handle (MATLAB)

    - by James
    Hi, is there a way to assign the outerposition property of a figure to a figure with a given handle? For example, if I wanted to define a figure as say figure 1, I would use: figure(1) imagesc(Arrayname) % I.e. any array I can also change the properties of a figure using the code: figure('Name', 'Name of figure','NumberTitle','off','OuterPosition',[scrsz(1) scrsz(2) 700 700]); Is there a propertyname I can use to assign the outerposition property to the figure assigned as figure 1? The reason I am asking this is because I am using a command called save2word (from the MATLAB file exchange) to save some plots from a function I have made to a word file, and I want to limit the number of figures I have open as it does this. The rest of the code I have is: plottedloops = [1, 5:5:100]; % Specifies which loops I want to save GetGeometry = getappdata(0, 'GeometryAtEachLoop') % Obtains a 4D array containing geometry information at each loop NumSections = size(GetGeometry,4); %Defined by the fourth dimension of the 4D array for j = 1:NumSections for i = 1:plottedloops P = GetGeometry(:,:,i,j); TitleSize = 14; Fsize = 8; % Save Geometry scrsz = get(0,'ScreenSize'); %left, bottom, width height figure('Name', 'Geometry at each loop','NumberTitle','off','OuterPosition',[scrsz(1) scrsz(2) 700 700]); This specifies the figure name, dims etc., but also means multiple figures are opened as the command runs. % I have tried this, but it doesn't work: % figure(0, 'OuterPosition',[scrsz(1) scrsz(2) 700 700]); imagesc(P), title('Geometry','FontSize', TitleSize), axis([0 100 0 100]); text(20,110,['Loop:',num2str(i)], 'FontSize', TitleSize); % Show loop in figure text(70,110,['Section:',num2str(j)], 'FontSize', TitleSize);% Show Section number in figure save2word('Geometry at each loop'); % Saves figure to a word file end end Thanks

    Read the article

  • Matlab Simulation: Point (symbol) Moving from start point to end point and back

    - by niko
    Hi, I would like to create an animation to demonstrate LDPC coding which is based on Sum-Product Algorithm So far I have created a graph which shows the connections between symbol nodes (left) and parity nodes (right) and would like to animate points travelling from symbol to parity nodes and back. The figure is drawn by executing the following method: function drawVertices(H) hold on; nodesCount = size(H); parityNodesCount = nodesCount(1); symbolNodesCount = nodesCount(2); symbolPoints = zeros(symbolNodesCount, 2); symbolPoints(:, 1) = 0; for i = 0 : symbolNodesCount - 1 ji = symbolNodesCount - i; scatter(0, ji) symbolPoints(i + 1, 2) = ji; end; parityPoints = zeros(parityNodesCount, 2); parityPoints(:, 1) = 10; for i = 0 : parityNodesCount - 1 ji = parityNodesCount - i; y0 = symbolNodesCount/2 - parityNodesCount/2; scatter(10, y0 + ji) parityPoints(i + 1, 2) = y0 + ji; end; axis([-1 11 -1 symbolNodesCount + 2]); axis off %connect vertices d = size(H); for i = 1 : d(1) for j = 1 : d(2) if(H(i, j) == 1) plot([parityPoints(i, 1) symbolPoints(j, 1)], [parityPoints(i, 2) symbolPoints(j, 2)]); end; end; end; So what I would like to do here is to add another method which takes start point (x and y) and end point as arguments and animates a travelling circle (dot) from start to end and back along the displayed lines. I would appreciate if anyone of you could show the solution or suggest any useful tutorial about matlab simulations. Thank you!

    Read the article

< Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >