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  • OutOfMemoryException when I read FileStream 500 MB

    - by Alhambra Eidos
    Hi all, I'm using Filestream for read big file ( 500 MB) and I get the OutOfMemoryException. Any solutions about it. My Code is: using (var fs3 = new FileStream(filePath2, FileMode.Open, FileAccess.Read)) { byte[] b2 = ReadFully(fs3, 1024); } public static byte[] ReadFully(Stream stream, int initialLength) { // If we've been passed an unhelpful initial length, just // use 32K. if (initialLength < 1) { initialLength = 32768; } byte[] buffer = new byte[initialLength]; int read = 0; int chunk; while ((chunk = stream.Read(buffer, read, buffer.Length - read)) > 0) { read += chunk; // If we've reached the end of our buffer, check to see if there's // any more information if (read == buffer.Length) { int nextByte = stream.ReadByte(); // End of stream? If so, we're done if (nextByte == -1) { return buffer; } // Nope. Resize the buffer, put in the byte we've just // read, and continue byte[] newBuffer = new byte[buffer.Length * 2]; Array.Copy(buffer, newBuffer, buffer.Length); newBuffer[read] = (byte)nextByte; buffer = newBuffer; read++; } } // Buffer is now too big. Shrink it. byte[] ret = new byte[read]; Array.Copy(buffer, ret, read); return ret; } thanks in advanced,

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  • Java - is it possible to read a file line by line, stop, and then immediately start reading bytes wh

    - by hatorade
    I'm having an issue trying to parse the ascii part of a file, and once I hit the end tag, IMMEDIATELY start reading in the bytes from that point on. Everything I know in Java to read off a line or a whole word creates a buffer, which ruins any chance of getting the bytes immediately following my stop point. Is the only way to do this read in byte-by-byte, find new-lines, reconstruct everything prior to the new-line, see if it's my end tag, and go from there?

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  • Printf in assembler doesn't print

    - by Gaim
    Hi there, I have got a homework to hack program using buffer overflow ( with disassambling, program was written in C++, I haven't got the source code ). I have already managed it but I have a problem. I have to print some message on the screen, so I found out address of printf function, pushed address of "HACKED" and address of "%s" on the stack ( in this order ) and called that function. Called code passed well but nothing had been printed. I have tried to simulate the environment like in other place in the program but there has to be something wrong. Do you have any idea what I am doing wrong that I have no output, please? Thanks a lot EDIT: This program is running on Windows XP SP3 32b, written in C++, Intel asm there is the "hack" code CPU Disasm Address Hex dump Command Comments 0012F9A3 90 NOP ;hack begins 0012F9A4 90 NOP 0012F9A5 90 NOP 0012F9A6 89E5 MOV EBP,ESP 0012F9A8 83EC 7F SUB ESP,7F ;creating a place for working data 0012F9AB 83EC 7F SUB ESP,7F 0012F9AE 31C0 XOR EAX,EAX 0012F9B0 50 PUSH EAX 0012F9B1 50 PUSH EAX 0012F9B2 50 PUSH EAX 0012F9B3 89E8 MOV EAX,EBP 0012F9B5 83E8 09 SUB EAX,9 0012F9B8 BA 1406EDFF MOV EDX,FFED0614 ;address to jump, it is negative because there mustn't be 00 bytes 0012F9BD F7DA NOT EDX 0012F9BF FFE2 JMP EDX ;I have to jump because there are some values overwritten by the program 0012F9C1 90 NOP 0012F9C2 0090 00000000 ADD BYTE PTR DS:[EAX],DL 0012F9C8 90 NOP 0012F9C9 90 NOP 0012F9CA 90 NOP 0012F9CB 90 NOP 0012F9CC 6C INS BYTE PTR ES:[EDI],DX ; I/O command 0012F9CD 65:6E OUTS DX,BYTE PTR GS:[ESI] ; I/O command 0012F9CF 67:74 68 JE SHORT 0012FA3A ; Superfluous address size prefix 0012F9D2 2069 73 AND BYTE PTR DS:[ECX+73],CH 0012F9D5 203439 AND BYTE PTR DS:[EDI+ECX],DH 0012F9D8 34 2C XOR AL,2C 0012F9DA 2066 69 AND BYTE PTR DS:[ESI+69],AH 0012F9DD 72 73 JB SHORT 0012FA52 0012F9DF 74 20 JE SHORT 0012FA01 0012F9E1 3120 XOR DWORD PTR DS:[EAX],ESP 0012F9E3 6C INS BYTE PTR ES:[EDI],DX ; I/O command 0012F9E4 696E 65 7300909 IMUL EBP,DWORD PTR DS:[ESI+65],-6F6FFF8D 0012F9EB 90 NOP 0012F9EC 90 NOP 0012F9ED 90 NOP 0012F9EE 31DB XOR EBX,EBX ; hack continues 0012F9F0 8818 MOV BYTE PTR DS:[EAX],BL ; writing 00 behind word "HACKED" 0012F9F2 83E8 06 SUB EAX,6 0012F9F5 50 PUSH EAX ; address of "HACKED" 0012F9F6 B8 3B8CBEFF MOV EAX,FFBE8C3B 0012F9FB F7D0 NOT EAX 0012F9FD 50 PUSH EAX ; address of "%s" 0012F9FE B8 FFE4BFFF MOV EAX,FFBFE4FF 0012FA03 F7D0 NOT EAX 0012FA05 FFD0 CALL EAX ;address of printf This code is really ugly because I am new in assembler and there mustn't be null bytes because of buffer-overflow bug

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  • problem with pasting image over lines in wx DC

    - by Moayyad Yaghi
    hello .. i have the same code as wx Doodle pad in the wx demos i added a tool to paste images from the clipboard to the pad. using wx.DrawBitmap() function , but whenever i refresh the buffer .and call funtions ( drawSavedLines and drawSavedBitmap) it keeps putting bitmap above line no matter what i did even if i called draw bitmap first and then draw lines . is there anyway to put a line above the bitmap ? please inform me if i miss anything thanx in advance

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  • How to tell GDB to flush the stdio of the program being debugged

    - by Yorkwar
    The stdio is usually buffered. When I hit a breakpoint and there's a printf before the breakpoint, the printed string may still be in the buffer and I can not see it. I know I can flush the stdio by adding some flush code in the program. Without doing this, is there any way to tell GDB to flush the stdio of the program being debugged after GDB stops? This way is more friendly when debugging a program.

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  • opengl es render but dont show on display

    - by Sponge
    i have written a object selection algorithm which picks the objects by there color. i give every object an unique color and then i just have to use the glReadPixels method to check which object was selected this works fine and is really fast but the problem is that the frame is displayed on the screen with all the picking-colors so the screen flashes every time you select something. so my question is: how do i write everything in the correct display buffer but dont display it on the screen to avoid these flashes?

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  • rTorrent, too low memory usage !?

    - by Claudiu
    I want to know from more experienced rTorrent users how to tweak the .rtorrent.rc so that rTorrent will cache disk reading and writing (same as uTorrent does). I have set the max_memory_usage = 1GB but this amount is not used. I run 6 rTorrent instances on a Quad Core, 8 GB Ram machine and total used memory reported by htop is only ~500MB. I need to use memory buffers cause disk IO activity is very high.

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  • How to read the statistics in Media Player Classic?

    - by netvope
    I understand that the two numbers under bitrate are the average bitrate and the current bitrate of the stream. But what are the two numbers under buffers? I suppose the second one is the amount of data loaded in memory, but what is the first number? The amount of data decoded? Also, why are there a jitter and a sync offset? (For your reference, here stream 0-6 are video, audio track 1, audio track 2, subtitle track 1 and subtitle track 2.)

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  • OpenGL - Rendering from part of an index and vertex array depending on an element count

    - by user1423893
    I'm currently drawing my shapes as lines by using a VAO and then assigning the dynamic vertices and indices each frame. // Bind VAO glBindVertexArray(m_vao); // Update the vertex buffer with the new data (Copy data into the vertex buffer object) glBufferData(GL_ARRAY_BUFFER, numVertices * sizeof(VertexPosition), m_vertices.data(), GL_DYNAMIC_DRAW); // Update the index buffer with the new data (Copy data into the index buffer object) glBufferData(GL_ELEMENT_ARRAY_BUFFER, numIndices * sizeof(unsigned short), indices.data(), GL_DYNAMIC_DRAW); glDrawElements(GL_LINES, numIndices, GL_UNSIGNED_SHORT, BUFFER_OFFSET(0)); // Unbind VAO glBindVertexArray(0); What I would like to do is draw the lines using only part of the data stored in the index and vertex buffer objects. The vertex buffer has its vertices set from an array of defined maximum size: std::array<VertexPosition, maxVertices> m_vertices; The index buffer has its elements set from an array of defined maximum size: std::array<unsigned short, maxIndices> indices = { 0 }; A running total is kept of the number of vertices and indices needed for each draw call numVertices numIndices Can I not specify that the buffer data contain the entire array and only read from part of it when drawing? For example using the vertex buffer object glBufferData(GL_ARRAY_BUFFER, numVertices * sizeof(VertexPosition), m_vertices.data(), GL_DYNAMIC_DRAW); m_vertices.data() = Entire array is stored numVertices * sizeof(VertexPosition) = Amount of data to read from the entire array Is this not the correct way to approach this? I do not wish to use std::vector if possible.

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  • Can't use the hardware scissor any more, should I use the stencil buffer or manually clip sprites?

    - by Alex Ames
    I wrote a simple UI system for my game. There is a clip flag on my widgets that you can use to tell a widget to clip any children that try to draw outside their parent's box (for scrollboxes for example). The clip flag uses glScissor, which is fed an axis aligned rectangle. I just added arbitrary rotation and transformations to my widgets, so I can rotate or scale them however I want. Unfortunately, this breaks the scissor that I was using as now my clip rectangle might not be axis aligned. There are two ways I can think of to fix this: either by using the stencil buffer to define the drawable area, or by having a wrapper function around my sprite drawing function that will adjust the vertices and texture coords of the sprites being drawn based on the clipper on the top of a clipper stack. Of course, there may also be other options I can't think of (something fancy with shaders possibly?). I'm not sure which way to go at the moment. Changing the implementation of my scissor functions to use the stencil buffer probably requires the smallest change, but I'm not sure how much overhead that has compared to the coordinate adjusting or if the performance difference is even worth considering.

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  • Problem when trying to use simple Shaders + VBOs

    - by Mr.Gando
    Hello I'm trying to convert the following functions to a VBO based function for learning purposes, it displays a static texture on screen. I'm using OpenGL ES 2.0 with shaders on the iPhone (should be almost the same than regular OpenGL in this case), this is what I got working: //Works! - (void) drawAtPoint:(CGPoint)point depth:(CGFloat)depth { GLfloat coordinates[] = { 0, 1, 1, 1, 0, 0, 1, 0 }; GLfloat width = (GLfloat)_width * _maxS, height = (GLfloat)_height * _maxT; GLfloat vertices[] = { -width / 2 + point.x, -height / 2 + point.y, width / 2 + point.x, -height / 2 + point.y, -width / 2 + point.x, height / 2 + point.y, width / 2 + point.x, height / 2 + point.y, }; glBindTexture(GL_TEXTURE_2D, _name); //Attrib position and attrib_tex coord are handles for the shader attributes glVertexAttribPointer(ATTRIB_POSITION, 2, GL_FLOAT, GL_FALSE, 0, vertices); glEnableVertexAttribArray(ATTRIB_POSITION); glVertexAttribPointer(ATTRIB_TEXCOORD, 2, GL_FLOAT, GL_FALSE, 0, coordinates); glEnableVertexAttribArray(ATTRIB_TEXCOORD); glDrawArrays(GL_TRIANGLE_STRIP, 0, 4); } I tried to do this to convert to a VBO however I don't see anything displaying on-screen with this version: //Doesn't display anything - (void) drawAtPoint:(CGPoint)point depth:(CGFloat)depth { GLfloat width = (GLfloat)_width * _maxS, height = (GLfloat)_height * _maxT; GLfloat position[] = { -width / 2 + point.x, -height / 2 + point.y, width / 2 + point.x, -height / 2 + point.y, -width / 2 + point.x, height / 2 + point.y, width / 2 + point.x, height / 2 + point.y, }; //Texture on-screen position ( each vertex is x,y in on-screen coords ) GLfloat coordinates[] = { 0, 1, 1, 1, 0, 0, 1, 0 }; // Texture coords from 0 to 1 glBindVertexArrayOES(vao); glGenVertexArraysOES(1, &vao); glGenBuffers(2, vbo); //Buffer 1 glBindBuffer(GL_ARRAY_BUFFER, vbo[0]); glBufferData(GL_ARRAY_BUFFER, 8 * sizeof(GLfloat), position, GL_STATIC_DRAW); glEnableVertexAttribArray(ATTRIB_POSITION); glVertexAttribPointer(ATTRIB_POSITION, 2, GL_FLOAT, GL_FALSE, 0, position); //Buffer 2 glBindBuffer(GL_ARRAY_BUFFER, vbo[1]); glBufferData(GL_ARRAY_BUFFER, 8 * sizeof(GLfloat), coordinates, GL_DYNAMIC_DRAW); glEnableVertexAttribArray(ATTRIB_TEXCOORD); glVertexAttribPointer(ATTRIB_TEXCOORD, 2, GL_FLOAT, GL_FALSE, 0, coordinates); //Draw glBindVertexArrayOES(vao); glBindTexture(GL_TEXTURE_2D, _name); glDrawArrays(GL_TRIANGLE_STRIP, 0, 4); } In both cases I'm using this simple Vertex Shader //Vertex Shader attribute vec2 position;//Bound to ATTRIB_POSITION attribute vec4 color; attribute vec2 texcoord;//Bound to ATTRIB_TEXCOORD varying vec2 texcoordVarying; uniform mat4 mvp; void main() { //You CAN'T use transpose before in glUniformMatrix4fv so... here it goes. gl_Position = mvp * vec4(position.x, position.y, 0.0, 1.0); texcoordVarying = texcoord; } The gl_Position is equal to product of mvp * vec4 because I'm simulating glOrthof in 2D with that mvp And this Fragment Shader //Fragment Shader uniform sampler2D sampler; varying mediump vec2 texcoordVarying; void main() { gl_FragColor = texture2D(sampler, texcoordVarying); } I really need help with this, maybe my shaders are wrong for the second case ? thanks in advance.

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  • how to exploit vulnerability in php

    - by Dr Deo
    i have never seen a buffer overflow exploit in live action. supporse I have found a server that seems to have vulnerabilities. Where can i get proof of the concept code preferably in c/c++ to exploit the vulnerability? eg i found this vulnerability Multiple directory traversal vulnerabilities in functions such as 'posix_access()', 'chdir()', 'ftok()' may allow a remote attacker to bypass 'safe_mode' restrictions. (CVE-2008-2665 and CVE-2008-2666). How can i get proof of concept code for educational purposes PS I am a student and my only desire is to learn

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  • recv returns old data

    - by anon
    This loop is supposed to take data from a socket line by line and put it in a buffer. For some reason, when there is no new data to return, recv returns the last couple lines it got. I was able to stop the bug by commenting out the first recv, but then I cant tell how long the next line will be. I know it's not a while(this->connected){ memset(buf, '\0', sizeof(buf)); recv(this->sock, buf, sizeof(buf), MSG_PEEK); //get length of next message ptr = strstr(buf, "\r\n"); if (ptr == NULL) continue; err = recv(this->sock, buf, (ptr-buf), NULL); //get next message printf("--%db\n%s\n", err, buf); tok[0] = strtok(buf, " "); for(i=1;tok[i-1]!=NULL;i++) tok[i] = strtok(NULL, " "); //do more stuff }

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  • Storing Shell Output

    - by Emil Radoncik
    Hello everybody, I am trying to read the output of a shell command into a string buffer, the reading and adding the values is ok except for the fact that the added values are every second line in the shell output. for example, I have 10 rows od shell output and this code only stores the 1, 3, 5, 7, 9, row . Can anyone point out why i am not able to catch every row with this code ??? any suggestion or idea is welcomed :) import java.io.*; public class Linux { public static void main(String args[]) { try { StringBuffer s = new StringBuffer(); Process p = Runtime.getRuntime().exec("cat /proc/cpuinfo"); BufferedReader input = new BufferedReader(new InputStreamReader(p.getInputStream())); while (input.readLine() != null) { //System.out.println(line); s.append(input.readLine() + "\n"); } System.out.println(s.toString()); } catch (Exception err) { err.printStackTrace(); } } }

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  • Right multi object dependance design

    - by kenny
    I need some help with a correct design. I have a class called BufferManager. The push() method of this class reads data from a source and pushes it to a buffer repeatedly until there is no more data left in the source. There are also consumer threads that read data from this buffer, as soon as new data arrives. There is an option to sort the data before it comes to buffer. What I do right now is that BufferManager, instead of pushing data to the buffer, pushes it to another "sorting" buffer and starts a sorting thread. SorterManager class reads the data, sorts it in files and push()es the sorted data into the buffer. There will be a bottleneck (I use merge sort with files) but this is something I can't avoid. This is a bad design, because both BufferManager and SorterManager push data to a buffer (that consumers read from). I think only BufferManager should do it. How can I design it?

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  • how to exploit vulnerability of php?

    - by Dr Deo
    i have never seen a buffer overflow exploit in live action. supporse I have found a server that seems to have vulnerabilities. Where can i get proof of the concept code preferably in c/c++ to exploit the vulnerability? eg i found this vulnerability Multiple directory traversal vulnerabilities in functions such as 'posix_access()', 'chdir()', 'ftok()' may allow a remote attacker to bypass 'safe_mode' restrictions. (CVE-2008-2665 and CVE-2008-2666). How can i get proof of concept code for educational purposes PS I am a student and my only desire is to learn

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  • How should I handle incomplete packet buffers?

    - by Benjamin Manns
    I am writing a client for a server that typically sends data as strings in 500 or less bytes. However, the data will occasionally exceed that, and a single set of data could contain 200,000 bytes, for all the client knows (on initialization or significant events). However, I would like to not have to have each client running with a 50 MB socket buffer (if it's even possible). Each set of data is delimited by a null \0 character. What kind of structure should I look at for storing partially sent data sets? For example, the server may send ABCDEFGHIJKLMNOPQRSTUV\0WXYZ\0123!\0. I would want to process ABCDEFGHIJKLMNOPQRSTUV, WXYZ, and 123! independently. Also, the server could send ABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890LOL123HAHATHISISREALLYLONG without the terminating character. I would want that data set stored somewhere for later appending and processing. Also, I'm using asynchronous socket methods (BeginSend, EndSend, BeginReceive, EndReceive) if that matters.

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  • Java threads, wait time always 00:00:00-Producer/Consumer

    - by user3742254
    I am currently doing a producer consumer problem with a number of threads and have had to set priorities and waits to them to ensure that one thread, the security thread, runs last. I have managed to do this and I have managed to get the buffer working. The last thing that I am required to do is to show the wait time of threads that are too large for the buffer and to calculate the average wait time. I have included code to do so, but everything I run the program, the wait time is always returned as 00:00:00, and by extension, the average is returned as the same. I was speaking to one of my colleagues who said that it is not a matter of the code but rather a matter of the computer needing to work off of one processor, which can be adjusted in the task manager settings. He has an HP like myself but his program prints the wait time 180 times, whereas mine prints usually about 3-7 times and is only 00:00:01 on one instance before finishing when I have made the processor adjustments. My other colleague has an iMac and hers puts out an average of 42:00:34(42 minutes??) I am very confused about this because I can see no difference between our codes and like my colleague said, I was wondering is it a computer issue. I am obviously concerned as I wanted to make sure that my code correctly calculated an average wait time, but that is impossible to tell when the wait times always show as 00:00:00. To calculate the thread duration, including the time it entered and exited the buffer was done by using a timestamp import, and then subtracting start time from end time. Is my code correct for this issue or is there something which is missing? I would be very grateful for any solutions. Below is my code: My buffer class package com.Com813cw; import java.text.DateFormat; import java.text.SimpleDateFormat; /** * Created by Rory on 10/08/2014. */ class Buffer { private int contents, count = 0, process = 200; private int totalRam = 1000; private boolean available = false; private long start, end, wait, request = 0; private DateFormat time = new SimpleDateFormat("ss:SSS"); public int avWaitTime =0; public void average(){ System.out.println("Average Application Request wait time: "+ time.format(request/count)); } public synchronized int get() { while (process <= 500) { try { wait(); } catch (InterruptedException e) { } } process -= 200; System.out.println("CPU After Process " + process); notifyAll(); return contents; } public synchronized void put(int value) { if (process <= 500) { process += value; } else { start = System.currentTimeMillis(); try { wait(); } catch (InterruptedException e) { } end = System.currentTimeMillis(); wait = end - start; count++; request += wait; System.out.println("Application Request Wait Time: " + time.format(wait)); process += value; contents = value; calcWait(wait, count); } notifyAll(); } public void calcWait(long wait, int count){ this.avWaitTime = (int) (wait/count); } public void printWait(){ System.out.println("Wait time is " + time.format(this.avWaitTime)); } } My spotify class package com.Com813cw; import java.sql.Timestamp; /** * Created by Rory on 11/08/2014. */ class Spotify extends Thread { private Buffer buffer; private int number; private int bytes = 250; public Spotify(Buffer c, int number) { buffer = c; this.number = number; } long startTime = System.currentTimeMillis(); public void run() { for (int i = 0; i < 20; i++) { buffer.put(bytes); System.out.println(getName() + this.number + " put: " + bytes + " bytes "); try { sleep(1000); } catch (InterruptedException e) { } } long endTime = System.currentTimeMillis(); long timeTaken = endTime - startTime; java.util.Date date = new java.util.Date(); System.out.println("-----------------------------"); System.out.println("Spotify has finished executing."); System.out.println("Time taken to execute was " + timeTaken + " milliseconds"); System.out.println("Time that Spotify thread exited Buffer was " + new Timestamp(date.getTime())); System.out.println("-----------------------------"); } } My BubbleWitch class package com.Com813cw; import java.lang.*; import java.lang.System; import java.sql.Timestamp; /** * Created by Rory on 10/08/2014. */ class BubbleWitch2 extends Thread { private Buffer buffer; private int number; private int bytes = 100; public BubbleWitch2(Buffer c, int number) { buffer = c; this.number=number ; } long startTime = System.currentTimeMillis(); public void run() { for (int i = 0; i < 10; i++) { buffer.put(bytes); System.out.println(getName() + this.number + " put: " + bytes + " bytes "); try { sleep(1000); } catch (InterruptedException e) { } } long endTime = System.currentTimeMillis(); long timeTaken = endTime - startTime; java.util.Date date = new java.util.Date(); System.out.println("-----------------------------"); System.out.println("BubbleWitch2 has finished executing."); System.out.println("Time taken to execute was " +timeTaken+ " milliseconds"); System.out.println("Time Bubblewitch2 thread exited Buffer was " + new Timestamp(date.getTime())); System.out.println("-----------------------------"); } } My Test class package com.Com813cw; /** * Created by Rory on 10/08/2014. */ public class ProducerConsumerTest { public static void main(String[] args) throws InterruptedException { Buffer c = new Buffer(); BubbleWitch2 p1 = new BubbleWitch2(c,1); Processor c1 = new Processor(c, 1); Spotify p2 = new Spotify(c, 2); SystemManagement p3 = new SystemManagement(c, 3); SecurityUpdate p4 = new SecurityUpdate(c, 4, p1, p2, p3); p1.setName("BubbleWitch2 "); p2.setName("Spotify "); p3.setName("System Management "); p4.setName("Security Update "); p1.setPriority(10); p2.setPriority(10); p3.setPriority(10); p4.setPriority(5); c1.start(); p1.start(); p2.start(); p3.start(); p4.start(); p2.join(); p3.join(); p4.join(); c.average(); System.exit(0); } } My security update package com.Com813cw; import java.lang.*; import java.lang.System; import java.sql.Timestamp; /** * Created by Rory on 11/08/2014. */ class SecurityUpdate extends Thread { private Buffer buffer; private int number; private int bytes = 150; private int process = 0; public SecurityUpdate(Buffer c, int number, BubbleWitch2 bubbleWitch2, Spotify spotify, SystemManagement systemManagement) throws InterruptedException { buffer = c; this.number = number; bubbleWitch2.join(); spotify.join(); systemManagement.join(); } long startTime = System.currentTimeMillis(); public void run() { for (int i = 0; i < 15; i++) { buffer.put(bytes); System.out.println(getName() + this.number + " put: " + bytes + " bytes"); try { sleep(1500); } catch (InterruptedException e) { } } long endTime = System.currentTimeMillis(); long timeTaken = endTime - startTime; java.util.Date date = new java.util.Date(); System.out.println("-----------------------------"); System.out.println("Security Update has finished executing."); System.out.println("Time taken to execute was " + timeTaken + " milliseconds"); System.out.println("Time that SecurityUpdate thread exited Buffer was " + new Timestamp(date.getTime())); System.out.println("------------------------------"); } } I'd be grateful as I said for any help as this is the last and most frustrating obstacle.

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  • Codesample with bufferoverflow (gets method). Why does it not behave as expected?

    - by citronas
    This an extract from an c program that should demonstrate a bufferoverflow. void foo() { char arr[8]; printf(" enter bla bla bla"); gets(arr); printf(" you entered %s\n", arr); } The question was "How many input chars can a user maximal enter without a creating a buffer overflow" My initial answer was 8, because the char-array is 8 bytes long. Although I was pretty certain my answer was correct, I tried a higher amount of chars, and found that the limit of chars that I can enter, before I get a segmentation fault is 11. (Im running this on A VirtualBox Ubuntu) So my question is: Why is it possible to enter 11 chars into that 8 byte array?

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  • The frame buffer layout of the current display cannot be made to match...

    - by adambox
    I get this error when I have VM running in VMWare Workstation on my work PC and try Remote Desktop-ing in from my iMac at home. I just upgraded VMWare Workstation to 7.0 from 6.0 and now I'm getting it when I try to resume my VM at work. It then asks me the scary question of whether I want to preserve or discard the suspended state. I don't want to lose stuff! ack! Update I backed up my VM and tried hitting that "discard" button and the result was a reboot of the VM. I then tried restoring to a snapshot, and none of my snapshots work! Is there anyway to fix this so I can run 7 but still have my old snapshots? The frame buffer layout of the current display cannot be made to match the frame buffer layout stored in the snapshot. The dimensions of the frame buffer in the snapshot are: Max width 3200, Max height 1770, Max size 22659072. The dimensions of the frame buffer on the current display are: Max width 3200, Max height 1600, Max size 20512768. Error encountered while trying to restore the virtual machine state from file "C:\Documents and Settings\adam\My Documents\My Virtual Machines\dev\Windows XP Professional.vmss". What do I do so I don't break things horribly?

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  • AudioRecord problems with non-HTC devices

    - by Marc
    I'm having troubles using AudioRecord. An example using some of the code derived from the splmeter project: private static final int FREQUENCY = 8000; private static final int CHANNEL = AudioFormat.CHANNEL_CONFIGURATION_MONO; private static final int ENCODING = AudioFormat.ENCODING_PCM_16BIT; private int BUFFSIZE = 50; private AudioRecord recordInstance = null; ... android.os.Process.setThreadPriority(android.os.Process.THREAD_PRIORITY_URGENT_AUDIO); recordInstance = new AudioRecord(MediaRecorder.AudioSource.MIC, FREQUENCY, CHANNEL, ENCODING, 8000); recordInstance.startRecording(); short[] tempBuffer = new short[BUFFSIZE]; int retval = 0; while (this.isRunning) { for (int i = 0; i < BUFFSIZE - 1; i++) { tempBuffer[i] = 0; } retval = recordInstance.read(tempBuffer, 0, BUFFSIZE); ... // process the data } This works on the HTC Dream and the HTC Magic perfectly without any log warnings/errors, but causes problems on the emulators and Nexus One device. On the Nexus one, it simply never returns useful data. I cannot provide any other useful information as I'm having a remote friend do the testing. On the emulators (Android 1.5, 2.1 and 2.2), I get weird errors from the AudioFlinger and Buffer overflows with the AudioRecordThread. I also get a major slowdown in UI responsiveness (even though the recording takes place in a separate thread than the UI). Is there something apparent that I'm doing incorrectly? Do I have to do anything special for the Nexus One hardware?

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  • Using OpenGL vertex buffers in C++.

    - by Ren
    I've loaded a Wavefront .obj file and drawn it in immediate mode, and it works fine. I'm now trying to draw the same model with a vertex buffer, but I have a question. My model data is organized in the following structures: struct Vert { double x; double y; double z; }; struct Norm { double x; double y; double z; }; struct Texcoord { double u; double v; double w; }; struct Face { unsigned int v[3]; unsigned int n[3]; unsigned int t[3]; }; struct Model { unsigned int vertNumber; unsigned int normNumber; unsigned int texcoordNumber; unsigned int faceNumber; Vert * vertArray; Norm * normArray; Texcoord * texcoordArray; Face * faceArray; }; As it is now, I don't think there is any redundant data, since multiple face structures can point to the same vertex, normal, or texture coordinate. When I make vbo's for the vertex positions, normals, and texture coordinates, and assign data to them with glBufferData, do I have to have make arrays with redundant data so that they will all have the same number of elements in the same order? I'd like to know if there is a simpler way to fill the buffers with the way I already have the model's data organized.

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  • Differences between Assembly Code output of the same program

    - by ultrajohn
    I have been trying to replicate the buffer overflow example3 from this article aleph one I'm doing this as a practice for a project in a computer security course i'm taking so please, I badly need your help. I've been the following the example, performing the tasks as I go along. My problem is the assembly code dumped by gdb in my computer (i'm doing this on a debian linux image running on VM Ware) is different from that of the example in the article. There are some constructs which I find confusing. Here is the one from my computer: here is the one from the article... Dump of assembler code for function main: 0x8000490 <main>: pushl %ebp 0x8000491 <main+1>: movl %esp,%ebp 0x8000493 <main+3>: subl $0x4,%esp 0x8000496 <main+6>: movl $0x0,0xfffffffc(%ebp) 0x800049d <main+13>: pushl $0x3 0x800049f <main+15>: pushl $0x2 0x80004a1 <main+17>: pushl $0x1 0x80004a3 <main+19>: call 0x8000470 <function> 0x80004a8 <main+24>: addl $0xc,%esp 0x80004ab <main+27>: movl $0x1,0xfffffffc(%ebp) 0x80004b2 <main+34>: movl 0xfffffffc(%ebp),%eax 0x80004b5 <main+37>: pushl %eax 0x80004b6 <main+38>: pushl $0x80004f8 0x80004bb <main+43>: call 0x8000378 <printf> 0x80004c0 <main+48>: addl $0x8,%esp 0x80004c3 <main+51>: movl %ebp,%esp 0x80004c5 <main+53>: popl %ebp 0x80004c6 <main+54>: ret 0x80004c7 <main+55>: nop As you can see, there are differences between the two. I'm confuse and I can't understand totally the assembly code from my computer. I would like to know the differences between the two. How is pushl different from push, mov vs movl , and so on... what does the expression 0xhexavalue(%register) means? I am sorry If I'm asking a lot, But I badly need your help. Thanks for the help really...

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