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  • Deploy CakePHP to a subfolder

    - by mgroves
    I have created a CakePHP 2 app, and now I'm trying to deploy it to a production web server. My app uses the default folder structure (app/lib/plugins/vendors), default htaccess, default routing, nothing special. I've been developing locally as if the app were in the root folder of the site (e.g. http://mycakeapp.localhost/ takes me to the site). But I'm deploying to a site (shared hosting) where that will not be the case (e.g. http://www.somedomain.com/mycakeapp). It doesn't work (I didn't really expect it to), so I assumed I had to tweak one or more htaccess files. I tried modifying the root .htaccess as suggested in this post, but that only partially worked (the link to the CSS didn't work, for instance): <IfModule mod_rewrite.c> RewriteEngine on RewriteRule ^mycakeapp$ mycakeapp/app/webroot/ [L] RewriteRule ^mycakeapp/(.*)$ mycakeapp/app/webroot/$1 [L] </IfModule> So what should I do to all the htaccess files to make this CakePHP site work in a subfolder?

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  • pysvn client.log() returning empty dictionary

    - by nashr rafeeg
    i have the following script that i am using to get the log messages from svn import pysvn class svncheck(): def __init__(self, svn_root="http://10.11.25.3/svn/Moodle/modules", svn_user=None, svn_password=None): self.user = svn_user self.password = svn_password self.root = svn_root def diffrence(self): client = pysvn.Client() client.commit_info_style = 1 client.callback_notify = self.notify client.callback_get_login = self.credentials log = client.log( self.root, revision_start=pysvn.Revision( pysvn.opt_revision_kind.number, 0), revision_end=pysvn.Revision( pysvn.opt_revision_kind.number, 5829), discover_changed_paths=True, strict_node_history=True, limit=0, include_merged_revisions=False, ) print log def notify( event_dict ): print event_dict return def credentials(realm, username, may_save): return True, self.user, self.password, True s = svncheck() s.diffrence() when i run this script its returning a empty dictionary object [<PysvnLog ''>, <PysvnLog ''>, <PysvnLog ''>,.. any idea what i am doing wrong here ? i am using pysvn version 1.7.2 built again svn version 1.6.5 cheers Nash

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  • fb:comments does not showing Log out link

    - by mahfuz05
    fb.comments does not showing Log out link here is my code < fb:comments xid="mahfuz" canpost="true" candelete="false" > < /fb:comments> here is JS SDK code <div id="fb-root"></div> <script type="text/javascript"> window.fbAsyncInit = function() { FB.init({appId: 'my app id', status: true, cookie: true, xfbml: true}); }; (function() { var e = document.createElement('script'); e.async = true; e.src = document.location.protocol + '//connect.facebook.net/en_US/all.js'; document.getElementById('fb-root').appendChild(e); }()); </script>

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  • Drupal: installing it in a subfolder...

    - by Patrick
    hi, this is a question about drupal installation on server. I usually upload my drupal into a subfolder "drupal" and I ask my customers to check the website in such subfolders until when it is ready. Then I asl to change the default folder in Apache to the "drupal" one. Sometimes my customer cannot change Apache configuration, so I was wondering if I can use a php script to forward users from root folder to the drupal one, or I should move the website to the root folder (which I would prefer to avoid, because is time consuming). thanks

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  • DotNetNuke + XPath = Custom navigation menu DNNMenu HTML render

    - by Rui Santos
    I'm developing a skin for DotNetNuke 5 using the Component DNN Done Right menu by Mark Alan which uses XSL-T to convert the XML sitemap into an HTML navigation. The XML sitemap outputs the following structure: <Root > <root > <node id="40" text="Home" url="http://localhost/dnn/Home.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="0" > <node id="58" text="Child1" url="http://localhost/dnn/Home/Child1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="1" > <keywords >Child1</keywords> <description >Child1</description> <node id="59" text="Child1 SubItem1" url="http://localhost/dnn/Home/Child1/Child1SubItem1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="2" > <keywords >Child1 SubItem1</keywords> <description >Child1 SubItem1</description> </node> <node id="60" text="Child1 SubItem2" url="http://localhost/dnn/Home/Child1/Child1SubItem2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="0" only="0" depth="2" > <keywords >Child1 SubItem2</keywords> <description >Child1 SubItem2</description> </node> <node id="61" text="Child1 SubItem3" url="http://localhost/dnn/Home/Child1/Child1SubItem3.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="2" > <keywords >Child1 SubItem3</keywords> <description >Child1 SubItem3</description> </node> </node> <node id="65" text="Child2" url="http://localhost/dnn/Home/Child2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="1" > <keywords >Child2</keywords> <description >Child2</description> <node id="66" text="Child2 SubItem1" url="http://localhost/dnn/Home/Child2/Child2SubItem1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="2" > <keywords >Child2 SubItem1</keywords> <description >Child2 SubItem1</description> </node> <node id="67" text="Child2 SubItem2" url="http://localhost/dnn/Home/Child2/Child2SubItem2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="2" > <keywords >Child2 SubItem2</keywords> <description >Child2 SubItem2</description> </node> </node> </node> </root> </Root> My Goal is to render this XML block into this HTML Navigation structure only using UL's LI's, etc.. <ul id="topnav"> <li> <a href="#" class="home">Home</a> <!-- Parent Node - Depth0 --> <div class="sub"> <ul> <li><h2><a href="#">Child1</a></h2></li> <!-- Parent Node 1 - Depth1 --> <li><a href="#">Child1 SubItem1</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child1 SubItem2</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child1 SubItem3</a></li ><!-- ChildNode - Depth2 --> </ul> <ul> <li><h2><a href="#">Child2</a></h2></li> <!-- Parent Node 2 - Depth1 --> <li><a href="#">Child2 SubItem1</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child2 SubItem2</a></li> <!-- ChildNode - Depth2 --> </ul> </div> </li> </ul> Can anyone help with the XSL coding? I'm just starting now with XSL..

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  • Need help with this Regex + UrlRewriter.NET please :)

    - by Pure.Krome
    Previously, on StackOverflow ... (Summarized) I need to capture all requests, for a particluar subdomain .. and rewrite their destination. Now, the trick to determining the host via regex was solved. Now, i need to make sure all requests to the root index page is rewritten, but i can't figure out the correct regex to find the 'homepage' / website root. this is what i have.... <if header="HTTP_HOST" match="^foo\.mydomain\.com\.au(?::\d+)?/?$"> <!-- snip some other rewrites, eg./buying/product -> ~/Pages/Foo/Bar.aspx --> <rewrite url="^/$" to="~/Pages/SomeWeirdFolder/Home.aspx" processing="stop"/> </if> Now if one of the rewrites were not found, then it falls through and continues. So .. can anyone please help?

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  • Powerpoint file can be deleted without consequence

    - by John Maloney
    I am working on a license management type application that copies a password protected zip file to the applications root. The user clicks a button "Open Presentation" and the zipped file is extracted into the root folder and then I use the Office interop to open the file in Powerpoint. At this point to my surprise I am able to delete the extracted file that is currently open in the Powerpoint application. I had assumed that trying to delete the file would fail as the file is still open in Powerpoint. Why is it allowing me to delete the file? Is the file somehow copied to a temp folder and then opened in PowerPoint? Can I move forward with the application relying on this ability to delete the file as soon as it is opened in Powerpoint? This would be optimal because it helps insure that the file cannot be copied(I am also using the xml to stop "Save As" and "Save" from appearing int Powerpoint). Thanks for the insight, John

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  • Parsing log files in a folder in ColdFusion

    - by Simon Guo
    The problem is there is a folder ./log/ containing the files like: jan2010.xml, feb2010.xml, mar2010.xml, jan2009.xml, feb2009.xml, mar2009.xml ... each xml file would like: <root><record name="bob" spend="20"></record>...(more records)</root> I want to write a piece of ColdFusion code (log.cfm) that simply parsing those xml files. For the front end I would let user to choose a year, then the click submit button. All the content in that year will be show up in separate table by month. Each table shows the total money spent for each person. like: person cost bob 200 mike 300 Total 500 Thanks.

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  • Getting Bad file descriptor when running Tornado AsyncHTTPTestCase

    - by Will
    When running a test using the Tornado AsyncHTTPTestCase I'm getting a stack trace that isn't related to the test. The test is passing so this is probably happening on the test clean up? I'm using Python 2.7.2, Tornado 2.2. The test code is: class AllServersHandlerTest(AsyncHTTPTestCase): endpoint = AllServersHandler.endpoint # '/rest/test/' def test_server_status_with_advertiser(self): on_new_host(None, '127.0.0.1') response = self.fetch(self.endpoint, method='GET') result = json.loads(response.body, 'utf8').get('data') self.assertEquals(['127.0.0.1'], result) The test passes ok, but I get the following stack trace from the Tornado server. OSError: [Errno 9] Bad file descriptor INFO:root:200 POST /rest/serverStatuses (127.0.0.1) 0.00ms DEBUG:root:error closing fd 688 Traceback (most recent call last): File "C:\Python27\Lib\site-packages\tornado-2.2-py2.7.egg\tornado\ioloop.py", line 173, in close os.close(fd) OSError: [Errno 9] Bad file descriptor Any ideas how to cleanly shutdown the test case?

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  • Wicket app in embedded Jetty causes UnsupportedClassVersionError

    - by Ondra Žižka
    I've tried to run a Wicket app in an embedded Jetty, using this code: public static void main( String[] args ){ Server server = new Server(8080); Context root = new Context( server, "/", Context.SESSIONS ); FilterHolder filterHolder = new FilterHolder( new WicketFilter() ); filterHolder.getInitParameters().put("applicationClassName", cz.dw.test.WicketApplication.class.getName() ); root.addFilter( filterHolder, "/*" , Handler.ALL ); try { server.start(); } catch (Exception ex) { ex.printStackTrace(); } } But I got java.lang.UnsupportedClassVersionError: Bad version number in .class file. Switching the target class version for my app (1.6 - 1.5) did not help. I use Sun JDK 1.6.0_17, Wicket 1.4.8, Jetty 6.1.24. I tried to debug, but the JRE classes have no debug data. The stacktrace is of no use as it happens when loading the classes into JVM. Any ideas what could be wrong? How can I find which class is causing this? Thanks, Ondra

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  • how to embed flash that is trying to access xml in it's original folder.

    - by mkprogramming
    I've got various flash files stored on my server. For this exmaple - here is the directory structure: Files Example - example.swf - example.xml So then on a separate webpage stored in the root of my server.. i'm embeding the flash. ... <param name="movie" value="http://www.example.com/Files/Example/example.swf"> ... Now the issue comes. Because the .swf is trying to access example.xml ... which is NOT stored in the root directory. How can I fix this problem? (I'd rather not use an iframe)

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  • XPath: How to check multiple attributes across similar nodes

    - by Justin
    Hi, If I have some xml like: <root> <customers> <customer firstname="Joe" lastname="Bloggs" description="Member of the Bloggs family"/> <customer firstname="Joe" lastname="Soap" description="Member of the Soap family"/> <customer firstname="Fred" lastname="Bloggs" description="Member of the Bloggs family"/> <customer firstname="Jane" lastname="Bloggs" description="Is a member of the Bloggs family"/> </customers> </root> How do I get, in pure XPath - not XSLT - an xpath expression that detects rows where lastname is the same, but has a different description? So it would pull the last node above? Thanks a mill if you can help, been scratching at it for ages, and I can't find it by searching (apologies if it is) Cheers, J

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  • using php to check if xml is atom or rss

    - by guest86
    i'm writing a php code which has to determine if given xml is in "atom" or "rss" format. After observing atom and rss xml files, i decided classify xml based on a root element. If root element is "<feed" it's an atom xml. If it's "<rss" it's not an atom. How can i perform that check using DOM? So far i have: $dom->loadXML($resp); $feed = $dom->getElementsByTagName("feed"); but it's not working quite right....

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  • Starting synergy automatically on RHEL/CentOS

    - by Matt
    I have a Red Had Enterprise Linux 5 and a CentOS 5 box, both of which I am trying to configure to automatically connect to a synergy server on startup. I have followed the guide at http://synergy2.sourceforge.net/autostart.html and configured them the same way I configured previous Ubuntu 7.10 boxes, and this only seems to get me half way there. Currently, synergy connects at the login screen, but once I login, it doesn't come back up. I added the following lines to /etc/gdm/{Init,PostLogin,PreSession}/Default : /usr/bin/killall synergyc sleep 1 /usr/bin/synergyc fried-chicken # Init,PreSession only All files are owned by root:root with 755 permissions, I'm just not sure what I'm missing here.

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  • Java xsd validation of xml without namespace

    - by Darkflare
    Hi, I want to validate an xml file against an xsd schema. The xml files root element does not have any namespace or xsi details. It has no attributes so just . I have tried the following code from http://www.ibm.com/developerworks/xml/library/x-javaxmlvalidapi.html with no luck as I receive cvc-elt.1: Cannot find the declaration of element 'root' SchemaFactory factory = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema"); File schemaFile = new File("schema.xsd"); Schema xsdScheme = factory.newSchema(schemaFile); Validator validator = xsdScheme.newValidator(); Source source = new StreamSource(xmlfile); validator.validate(source); The xml validates fine with the namespace headers included etc (added via xmlspy), but I would have thought the xml namespace could be declared without having to manually edit the source file?

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  • How can I create the XML::Simple data structure using a Perl XML SAX parser?

    - by DVK
    Summary: I am looking a fast XML parser (most likely a wrapper around some standard SAX parser) which will produce per-record data structure 100% identical to those produced by XML::Simple. Details: We have a large code infrastructure which depends on processing records one-by-one and expects the record to be a data structure in a format produced by XML::Simple since it always used XML::Simple since early Jurassic era. An example simple XML is: <root> <rec><f1>v1</f1><f2>v2</f2></rec> <rec><f1>v1b</f1><f2>v2b</f2></rec> <rec><f1>v1c</f1><f2>v2c</f2></rec> </root> And example rough code is: sub process_record { my ($obj, $record_hash) = @_; # do_stuff } my $records = XML::Simple->XMLin(@args)->{root}; foreach my $record (@$records) { $obj->process_record($record) }; As everyone knows XML::Simple is, well, simple. And more importantly, it is very slow and a memory hog—due to being a DOM parser and needing to build/store 100% of data in memory. So, it's not the best tool for parsing an XML file consisting of large amount of small records record-by-record. However, re-writing the entire code (which consist of large amount of "process_record"-like methods) to work with standard SAX parser seems like an big task not worth the resources, even at the cost of living with XML::Simple. I'm looking for an existing module which will probably be based on a SAX parser (or anything fast with small memory footprint) which can be used to produce $record hashrefs one by one based on the XML pictured above that can be passed to $obj->process_record($record) and be 100% identical to what XML::Simple's hashrefs would have been. I don't care much what the interface of the new module is; e.g whether I need to call next_record() or give it a callback coderef accepting a record.

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  • Firefox why window.opener is defined even for a new tab

    - by jonny
    Hi! I am porting quite old corp application from IE to Firefox. Here is my situation. User goes away from computer for a while and his session becomes expired. When user tries to access something in popup, he is being redirected to login page (in popup window). In login page onload event popup window chain is being closed and root page refreshed (in root page tab user is redirected to login page). The guy before me wrote this like this: if window.top.opener is undefined, we're not in popup. That's why I am getting non-stoppable refresh in Firefox. Why in Firefox window.opener is still defined and points to same window, even if this is a new tab, not popup? How should I correctly determine that current window is popup?

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  • Python, how to tell if screen is running.

    - by Joe Spoon
    Hello, I am very new to programming and am trying to run a python code to see if the screen program is running and if it is then to not run the rest of the code. This is what I have and it's not working. !/usr/bin/python import os var1 = os.system ('screen -r /root/screenlog/screen.log') fd = open("/root/screenlog/screen.log") content = fd.readline() while content: if content == "There is no screen to be resumed.": os.system ('/etc/init.d/tunnel.sh') print "The tunnel is now active." else: print "The tunnel is running." fd.close() I know there are probably several things here that don't need to be and quite a few that I'm missing. I will be running this program in cron. Thanks for any help.

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  • Thin & Sinatra not taking port

    - by NekoNova
    I'm having problems settig up my application using Thin and Sinatra. I have created a development-config.ru file that contains the following settings: # This is a rack configuration file to fire up the Sinatra application. # This allows better control and configuration as we are using the modular # approach here for controlling our application. # # Extend the Ruby load path with the root of the API and the lib folder # so that we can automatically include all our own custom classes. This makes # the requiring of files a bit cleaner and easier to maintain. # This is basically what rails does as well. # We also store the root of the API in the ENV settings to ensure we have # always access to the root of the API when building paths. ENV['API_ROOT'] = File.dirname(__FILE__) $:.unshift ENV['API_ROOT'] $:.unshift File.expand_path(File.join(ENV['API_ROOT'], 'lib')) $:.unshift File.expand_path(File.join(ENV['API_ROOT'], 'db')) # Now we can require all the gems used for the entire API by simpling requiring # them here. We can also include the classes that we have defined inside the lib # folder. require 'rubygems' require 'bundler' # Run Bundler to setup our gems properly. This will install all the missing gems on # the system and ensure that the deployment environment is ready to run. Bundler.require # To make the loading easier for the application, we will now automatically load all # models that have been defined inside the lib folder. This ensures that we do not need # to load them anymore anywhere else in our application, as the models will be known to # ruby everywhere. Dir.glob(File.join(ENV['API_ROOT'], 'lib', '**', '*.rb')).each{|file| require file} # Now we will configure the Sinatra application so that we can fire up the entire API. # This requires some detailed settings like whether logging is allowed, the port to be # used and some folder locations. require 'sinatra' require 'app' set :logging, true set :dump_errors, true set :port, 3001 set :views, "#{ENV['API_ROOT']}/views" set :public_folder, "#{ENV['API_ROOT']}/public" set :environment, :test # Start up the Sinatra application with all the settings that we have defined. run App.new This is based upon the information I found on the Sinatra website. However, the problem is that I cannot get the application running on port 3001. If I use thin start -R development-config.ru it runs on port 3000. If I use rackup config-development.ru it runs on port 9696. However I never see Sinatra kick in or run over port 3000. My application looks like this: # Author : Arne De Herdt # Email : # This is the actuall application that will be running under Sinatra # to serve the requests for the billing middleware API. # We use the modular approach here to allow control when deploying # the application using Capistrano. require 'sinatra/base' require 'logger' require 'savon' require 'billcrux' class App < Sinatra::Base # This action responds to POST requests on the URI '/billcrux/register' # and is responsible for handeling registration requests with the # BillCrux payment system. # The post "/billcrux/register" do # do stuff end end Can someone tell me what I am doing wrong?

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  • Copy NSArray and replace text items with bool values

    - by Frank Martin
    I utilize a (nested) plist to populate UITableViews where users can select entries at the deepest levels and set a checkmark (or not). I want to save these selections in a same structured list where at the deepest level the NSArray contains bool values instead the text strings that are displayed in the UITableView. So how can i build from a hierarchy like the following: Root - Item 0 (Dictionary) - Group (Dictionary) - Items (NSArray) - Item 0: @"Please check me" (String) a hierarchy like this? Root - Item 0 (Dictionary) - Group (Dictionary) - Items (NSArray) - Item 0: 0 (NSNumber) // NSNumber for bool values I'm trying to create a deep mutable copy and replace the items at the deepest levels but have somehow the feeling that this can be done easier. Thanks for any help with this in advance. Frank

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  • File paths with XSLT includes

    - by Andrew Parisi
    Hi again everyone. I'm working on a website with a large number of pages, and each one has this in it: <xsl:include href="team-menu.xsl" /> This xsl file is stored in the root directory. Essentially including my "team menu" on each page. My problem is when I include this on nested pages, e.g. "/teammembers/smith.xsl", the links in the menu are broken because they refer to pages that aren't in the same directory as the page i'm viewing. This is probably really easy, but I just don't know how to fix it. Is there a way to tell the XSL the root directory and/or set some sort of global directory? Thanks for your help!

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  • Show UIView for app presentation only once in iOS

    - by André Muniz
    I need to show an UIScrollView with some pages for present the app to user when launched for the first time. My slides are working correctly, lefting the logic to present it. Is a good practice to set the UIScrollViewController as root controller and set a NSUserDefault variable to control the presentation and redirect to main controller or set the main ViewController as root normally and call the presentation view if needed is a better approach? If there is a better way to do this can someone help? Thanks.

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  • Writing to a xml file in java

    - by user243680
    import java.io.*; import javax.xml.parsers.*; import javax.xml.transform.*; import javax.xml.transform.dom.*; import javax.xml.transform.stream.*; import org.w3c.dom.*; public class CreatXMLFile { public static void main(String[] args) throws Exception { BufferedReader bf = new BufferedReader(new InputStreamReader(System.in)); // System.out.print("Enter number to add elements in your XML file: "); // String str = bf.readLine(); int no=2; // System.out.print("Enter root: "); String root = "SMS"; DocumentBuilderFactory documentBuilderFactory =DocumentBuilderFactory.newInstance(); DocumentBuilder documentBuilder =documentBuilderFactory.newDocumentBuilder(); Document document = documentBuilder.newDocument(); Element rootElement = document.createElement(root); document.appendChild(rootElement); // for (int i = 1; i <= no; i++) // System.out.print("Enter the element: "); // String element = bf.readLine(); String element ="Number"; System.out.print("Enter the Number: "); String data = bf.readLine(); Element em = document.createElement(element); em.appendChild(document.createTextNode(data)); rootElement.appendChild(em); String element1 ="message"; System.out.print("Enter the SMS: "); String data1 = bf.readLine(); Element em1 = document.createElement(element1); em1.appendChild(document.createTextNode(data1)); rootElement.appendChild(em1); TransformerFactory transformerFactory = TransformerFactory.newInstance(); Transformer transformer = transformerFactory.newTransformer(); DOMSource source = new DOMSource(document); StreamResult result = new StreamResult(System.out); transformer.transform(source, result); } } i am working on the above code and it gives the following output run: Enter the Number: 768678 Enter the SMS: ytu <?xml version="1.0" encoding="UTF-8" standalone="no"?><SMS><Number>768678</Number><message>ytu</message></SMS>BUILD SUCCESSFUL (total time: 8 seconds) Now i want to write the output generated(<?xml version="1.0" encoding="UTF-8" standalone="no"?><SMS><Number>768678</Number><message>ytu</message></SMS>) to a XML file on the hard disk.How do i do it?

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  • XSLT Transforming sequential XML to hierarchical XML

    - by Jean-Paul Smit
    I have a requirement to transform a sequential XML node list into a hierarchical, but I run into some XSLT specific knowledge gap. The input XML contains articles, colors and sizes. In the sample below 'Record1' is an article, 'Record2' represents a color and 'Record3' are the sizes. The number of colors and sizes (record2 and record3) elements can vary. <root> <Record1>...</Record1> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record1>...</Record1> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> </root> All fields are on the same hierarchical level, but still I have to create this structure as output: <root> <article> -> Record1 <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> </article> <article> -> Record1 <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> </article> </root> I've tried to iterate the nodes sequentially but for example the 'article' (=record1) node tag needs to remain unclosed while 'color' (=record2) nodes are processed. The same counts for processing 'size' (=record3) having 'color' unclosed, but that is not allowed by XSLT. My next idea was to call a template for every article, color and size level, but I don't know how to select for example all 'record3' nodes between the current 'record2' and the next article represented by 'record1'. I've also got a limitation on the XSLT version because I need this transformation in BizTalk Server which only supports XSLT 1.0 Can someone push me in the right direction?

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  • XDocument change all attribute names

    - by Dested
    I have an XDocument that looks similar to <root> <a> <b foo="1" bar="2" /> <b foo="3" bar="4" /> <b foo="5" bar="6" /> <b foo="7" bar="8" /> <b foo="9" bar="10" /> </a> </root> I wish to change the attribute foo to something else, and the attribute bar to something else. How can I easily do this? My current version (below) stack overflows with large documents, and has an awful smell to it. string dd=LoadedXDocument.ToString(); foreach (var s in AttributeReplacements) dd = dd.Replace(s.Old+"=", s.New+"=");

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