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  • Facebook PHP SDK - can't pass parameters to getLoginUrl()

    - by Elliott
    I'm using the Facebook PHP SDK for simple login with extended permissions. I'm using the example code from the SDK docs, but I found that I need to manually clear out the FB session data otherwise if($user) comes back as true even though the user is logged out. I have the app going to logout.php upon logout; this page clears out the session vars and redirects to the app home page. Once I clear out the FB session data, log in/log out works fine. However, it stops working if I pass $params to the getLoginUrl function. Once I pass any params (I've tried several), the login breaks, either by not bringing up the second extended permissions screen or by refreshing the app page w/out login success. index page and logout page code follow. index.php <?php require 'services/facebook-php-sdk/src/facebook.php'; $facebook = new Facebook(array( 'appId' => '[APP_ID]', 'secret' => '[SECRET]', )); // Get User ID $user = $facebook->getUser(); if($user) { try { // Proceed knowing you have a logged in user who's authenticated. $user_profile = $facebook->api('/me'); $params = array('next' => 'http://'.$_SERVER["SERVER_NAME"].'/logout.php'); $logout_url = $facebook->getLogoutUrl($params); } catch (FacebookApiException $e) { error_log($e); $user = null; } } else { $login_url = $facebook->getLoginUrl($params = array('redirect_uri' => 'http://'.$_SERVER["SERVER_NAME"].'/', 'scope' => 'read_stream')); } ?> <!DOCTYPE html> <html lang="en"> <head> </head> <body> <?php if($user) { ?> <p><a href="<?php echo($logout_url); ?>">Log out</a></p> <?php } else { ?> <p><a href="<?php echo($login_url); ?>">Log in</a></p> <?php } ?> </body> </html> logout.php <?php session_start(); $fb_app_id = '[APP_ID]'; unset($_SESSION['fb_'.$fb_app_id.'_code']); unset($_SESSION['fb_'.$fb_app_id.'_access_token']); unset($_SESSION['fb_'.$fb_app_id.'_user_id']); unset($_SESSION['fb_'.$fb_app_id.'_state']); header('Location: http://'.$_SERVER["SERVER_NAME"].'/'); ?>

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  • Inotifywait doesn't run command

    - by Marius Miliunas
    I have a basic inotifywait script called watch.sh and a few files ending in .styl in the same directory. Here's the script, that catches the changes, but doesn't execute the code within the do/done I init it like sh watch.sh and here's the script #!/bin/sh while inotifywait -m -o ./log.txt -e modify ./*.styl; do stylus -c %f done I tried having echo "hi" within the exec portion but nothing executes

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  • Hyperlink for each record

    - by shantanuo
    I need a link for each depotname that will bring up a child window with the details of the last 10 backup status. while($data=mysql_fetch_array($res)) { if(is_null($depot_array) || !in_array($data['depotname'],$depot_array )) { $depot_array[$r]=$data['depotname']; if($data['SCP_status'] <> 'success') { echo "<tr id='fail'>"; The results of the following query should be displayed in a child window. select * from backup_log where depotname = $data['depotname']

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  • Multi-line code in PHP interactive shell

    - by Andrei
    I'm learning to use the PHP interactive shell, but I'm having trouble with multi-line code. Using backslashes like in the UNIX shells doesn't seem to work. What am I doing wrong ? php > function test(){\ php { echo "test";\ php { }\ php > test(); PHP Parse error: syntax error, unexpected T_ECHO, expecting T_STRING in php shell code on line 2

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  • pagination - 10 pages per page

    - by arthur
    I have a pagination script that displays a list of all pages like so: prev [1][2][3][4][5][6][7][8][9][10][11][12][13][14] next But I would like to only show ten of the numbers at a time: prev [3][4][5][6][7][8][9][10][11][12] next How can I accomplish this? Here is my code so far: <?php /* Set current, prev and next page */ $page = (!isset($_GET['page']))? 1 : $_GET['page']; $prev = ($page - 1); $next = ($page + 1); /* Max results per page */ $max_results = 2; /* Calculate the offset */ $from = (($page * $max_results) - $max_results); /* Query the db for total results. You need to edit the sql to fit your needs */ $result = mysql_query("select title from topics"); $total_results = mysql_num_rows($result); $total_pages = ceil($total_results / $max_results); $pagination = ''; /* Create a PREV link if there is one */ if($page > 1) { $pagination .= '< a hr_ef="?page='.$prev.'">Previous</a> '; } /* Loop through the total pages */ for($i = 1; $i <= $total_pages; $i++) { if(($page) == $i) { $pagination .= $i; } else { $pagination .= '< a hr_ef="index.php?page='.$i.'">'.$i.'</a>'; } } /* Print NEXT link if there is one */ if($page < $total_pages) { $pagination .= '< a hr_ef="?page='.$next.'"> Next</a>'; } /* Now we have our pagination links in a variable($pagination) ready to print to the page. I pu it in a variable because you may want to show them at the top and bottom of the page */ /* Below is how you query the db for ONLY the results for the current page */ $result=mysql_query("select * from topics LIMIT $from, $max_results "); while ($i = mysql_fetch_array($result)) { echo $i['title'].'<br />'; } echo $pagination; ?>

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  • how to use alert in php and js combined

    - by user295189
    have a need to alert through php, I have the code below. Problem is that it works as long as I dont use header redirect. But as soon as I use it..I loose alert. echo "I will do some functions here in php"; if($value == 1){ alert('ok working'); } header(location: 'someOtherpagethanthis.php');

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  • mysql_fetch_array() expects parameter 1 to be resource problem

    - by user225269
    I don't get it, I see no mistakes in this code but there is this error, please help: mysql_fetch_array() expects parameter 1 to be resource problem <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO=".$_GET['id']); ?> <?php while ($row = mysql_fetch_array($result)) { ?> <table class="a" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#D3D3D3"> <tr> <form name="formcheck" method="get" action="updateact.php" onsubmit="return formCheck(this);"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Update Students</td> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" onkeypress="return isNumberKey(event)" type="text" maxlength="5" id='numbers'/ value="<?php echo $_GET['id']; ?>"></td> </tr> <tr> <td width="30" height="35"><font size="2">*Year:</td> <td width="30"><input name="yr" onkeypress="return isNumberKey(event)" type="text" maxlength="5" id='numbers'/ value="<?php echo $row["YEAR"]; ?>"></td> <?php } ?> I'm just trying to load the data in the forms but I don't know why that error appears. What could possibly be the mistake in here?

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  • tomcat startup.sh trouble finding JAVA_HOME

    - by peter
    I am a bit puzzled by this strange behavior on CentOs 5.4 when starting Tomcat 6.0 as a service I've added a script at /etc/init.d/tomcat that can start/stop/restart Apache Tomcat 6.0 with user 'tomcat', and registered it as service. The problem with the service is that I am getting a 'Neither the JAVA_HOME nor the JRE_HOME environment variable is defined'. But when type 'sudo -u tomcat echo $JAVA_HOME' I get '/usr/java/jdk1.5.0_22' which is correct since I am using that JDK. What can I do about this?

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  • PHP something faster than explode to get filename from URL

    - by FFish
    My URL's can be absolute or relative: $rel = "date/album/001.jpg"; $abs = "http://www.site.com/date/album/image.jpg"; function getFilename($url) { $imgName = explode("/", $url); $imgName = $imgName[count($imgName) - 1]; echo $imgName; } There must be a faster way to do this right? Maybe a reg expression? But that's Chinese to me..

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  • PHP using Declare ? What is a tick?

    - by ArneRie
    Iam a little bit confused by php function declare. What exactly is an single tick, i thought 1 tick = one line of code? But if i use: function myfunc() { print "Tick"; } register_tick_function("myfunc"); declare(ticks=1) { echo 'foo!bar'; } The script prints : "Tick" 2 Times??

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  • PHP syntax question: global $argv, $argc;

    - by Andrew
    So I have a PHPUnit test, and found this code within a function. global $argv, $argc; echo $argc; print_r($argv); I understand what these variables represent (arguments passed from the command line), but I've never seen this syntax before:global $argv, $argc; What specifically is going on here?

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  • I am having trouble using jquery to submit a form. It was working before

    - by noah
    When a user clicks a link it uses jquery ajax to submit a form to go to paypal. Not working for some reason. Really appreciate any help... LINK TO CLICK I put this in an href for onClick: javascript:go_paypal(); CODE TO EXECUTE ON CLICK function go_paypal() { data = 'req_paypal=1'; $.blockUI({ message: '<h1> Going to Paypal...</h1>',css:{background:'#000'} }); $.ajax({ type: "POST", url: "index.php", data: data, success: function(data) { $("#paypal_form").html(data); $("#payPalForm").submit(); } , error: function() {$.unblockUI(); alert('Unable to communicate to server.'); } }); return false; } CODE TO GO ON SUBMIT if(isset($_POST['req_paypal']) && $_POST['req_paypal'] == 1 ) { $sql = 'INSERT INTO `transactions` (id,type,ip,time,ammount,status) VALUES (NULL,1,\''.$_SERVER['REMOTE_ADDR'].'\',\''.time().'\',\''.$global['paypal_prod_amount'].'\',0) '; echo $sql; mysql_query($sql); $id = mysql_insert_id(); $html = ' <form action="https://www.sandbox.paypal.com/cgi-bin/webscr" method="post" id="payPalForm"> <input type="hidden" name="item_number" value="One Year of Imgur Pro"> <input type="hidden" name="cmd" value="_xclick"> <input type="hidden" name="no_note" value="1"> <input type="hidden" name="business" value="'.$global['paypal_email'].'"> <input type="hidden" name="custom" value="'.base64_encode($id).'"> <input type="hidden" name="currency_code" value="USD"> <input type="hidden" name="return" value="'.$global['paypal_return'].'"> <input name="item_name" type="hidden" id="item_name" value="One Year of Imgur Pro" > <input name="amount" type="hidden" id="amount" value="'.$global['paypal_prod_amount'].'" > </form> '; echo $html;exit; }

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  • Ant variable does not exists in Ubuntu 10.10

    - by Nishat Baig
    I am trying to set up ANT build. However when I invoke build command helloworld_15/${NAME} does not exist. BUILD FAILED (total time: 0 seconds) Also the configure variables does not seems to be assigned. However i have set them into /etc/envitonment I tried echo $<varaiable_name> and value get displayed. Tried to google but not solutions seems am the first one having this issue. PS: OS Ubuntu 10.10

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  • php function output ina table row... how?

    - by user352868
    I want to run this function but show the result in a table row strlen($cat_row['sms'] This is what i came up with but it is not working: echo "<tr><td bgcolor=#626E7A>".**strlen($cat_row['cars']**."</td></tr>"; How do you show result of a php function in a table row? i am trying to format the output some how. please help

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  • Zend Framework: View variable in layout script is always null

    - by understack
    I set a view variable in someAction function like this: $this->view->type = "some type"; When I access this variable inside layout script like this: <?php echo $this->type ?> it prints nothing. What's wrong? My application.ini settings related to layout resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts/" resources.layout.layout = "layout" ; changed 'default' to 'layout'

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  • Make my Billing and Shipping Fields Match

    - by user1899209
    I want to make my Billing fields automatically match my Shipping fields. I can make it work with text values, but I can't automatically populate a RADIO BUTTON. I'm using this code: http://jsfiddle.net/aDNH7/ I would like to keep this in Javascript. <script> function FillBilling(f) { if(f.billingtoo.checked == true) { f.billingname.value = f.shippingname.value; f.billingcity.value = f.shippingcity.value; } if(f.billingtoo.checked == false) { f.billingname.value = ''; f.billingcity.value = ''; } } </script> <td bgcolor="eeeeee"> <b>Mailing Address</b> <br><br> <form> Name: <input type="text" name="shippingname"> <br> City: <input type="text" name="shippingcity"> / Checking / Savings <br> <input type="checkbox" onclick="FillBilling(this.form)" name="billingtoo"> <em>Check this box if Billing Address and Mailing Address are the same.</em> <p> <b>Billing Address</b> <br><br> Name: <input type="text" name="billingname"> <br> City: <input type="text" name="billingcity"> / Checking / Savings ? BUT, I want to add this to the form: <!-- <td colspan="2"><p> <label> <input type="radio" name="acct" value="checking" id="acct_0" <?php if ($user_info['acct'] == "checking"){ echo "checked='checked'"; }?>/> Checking</label> <br /> <label> <input type="radio" name="acct" value="savings" id="acct_1" <?php if ($user_info['acct'] == "savings"){ echo "checked='checked'"; }?>/> Savings</label> <br /> </p> </td>-->

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