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  • Dot Matrix printing in C# ?

    - by Dale
    I'm trying to print to Dot Matrix printers (various models) out of C#, currently I'm using Win32 API (you can find alot of examples online) calls to send escape codes directly to the printer out of my C# application. This works great, but... My problem is because I'm generating the escape codes and not relying on the windows print system the printouts can't be sent to any "normal" printers or to things like PDF print drivers. (This is now causing a problem as we're trying to use the application on a 2008 Terminal Server using Easy Print [Which is XPS based]) The question is: How can I print formatted documents (invoices on pre-printed stationary) to Dot Matrix printers (Epson, Oki and Panasonic... various models) out of C# not using direct printing, escape codes etc. **Just to clarify, I'm trying things like GDI+ (System.Drawing.Printing) but the problem is that its very hard, to get things to line up like the old code did. (The old code sent the characters direct to the printer bypassing the windows driver.) Any suggestions how things could be improved so that they could use GDI+ but still line up like the old code did?

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  • strange chi-square result using scikit_learn with feature matrix

    - by user963386
    I am using scikit learn to calculate the basic chi-square statistics(sklearn.feature_selection.chi2(X, y)): def chi_square(feat,target): """ """ from sklearn.feature_selection import chi2 ch,pval = chi2(feat,target) return ch,pval chisq,p = chi_square(feat_mat,target_sc) print(chisq) print("**********************") print(p) I have 1500 samples,45 features,4 classes. The input is a feature matrix with 1500x45 and a target array with 1500 components. The feature matrix is not sparse. When I run the program and I print the arrray "chisq" with 45 components, I can see that the component 13 has a negative value and p = 1. How is it possible? Or what does it mean or what is the big mistake that I am doing? I am attaching the printouts of chisq and p: [ 9.17099260e-01 3.77439701e+00 5.35004211e+01 2.17843312e+03 4.27047184e+04 2.23204883e+01 6.49985540e-01 2.02132664e-01 1.57324454e-03 2.16322638e-01 1.85592258e+00 5.70455805e+00 1.34911126e-02 -1.71834753e+01 1.05112366e+00 3.07383691e-01 5.55694752e-02 7.52801686e-01 9.74807972e-01 9.30619466e-02 4.52669897e-02 1.08348058e-01 9.88146259e-03 2.26292358e-01 5.08579194e-02 4.46232554e-02 1.22740419e-02 6.84545170e-02 6.71339545e-03 1.33252061e-02 1.69296016e-02 3.81318236e-02 4.74945604e-02 1.59313146e-01 9.73037448e-03 9.95771327e-03 6.93777954e-02 3.87738690e-02 1.53693158e-01 9.24603716e-04 1.22473138e-01 2.73347277e-01 1.69060817e-02 1.10868365e-02 8.62029628e+00] ********************** [ 8.21299526e-01 2.86878266e-01 1.43400668e-11 0.00000000e+00 0.00000000e+00 5.59436980e-05 8.84899894e-01 9.77244281e-01 9.99983411e-01 9.74912223e-01 6.02841813e-01 1.26903019e-01 9.99584918e-01 1.00000000e+00 7.88884155e-01 9.58633878e-01 9.96573548e-01 8.60719653e-01 8.07347364e-01 9.92656816e-01 9.97473024e-01 9.90817144e-01 9.99739526e-01 9.73237195e-01 9.96995722e-01 9.97526259e-01 9.99639669e-01 9.95333185e-01 9.99853998e-01 9.99592531e-01 9.99417113e-01 9.98042114e-01 9.97286030e-01 9.83873717e-01 9.99745466e-01 9.99736512e-01 9.95239765e-01 9.97992843e-01 9.84693908e-01 9.99992525e-01 9.89010468e-01 9.64960636e-01 9.99418323e-01 9.99690553e-01 3.47893682e-02]

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  • minimum L sum in a mxn matrix - 2

    - by hilal
    Here is my first question about maximum L sum and here is different and hard version of it. Problem : Given a mxn *positive* integer matrix find the minimum L sum from 0th row to the m'th row . L(4 item) likes chess horse move Example : M = 3x3 0 1 2 1 3 2 4 2 1 Possible L moves are : (0 1 2 2), (0 1 3 2) (0 1 4 2) We should go from 0th row to the 3th row with minimum sum I solved this with dynamic-programming and here is my algorithm : 1. Take a mxn another Minimum L Moves Sum array and copy the first row of main matrix. I call it (MLMS) 2. start from first cell and look the up L moves and calculate it 3. insert it in MLMS if it is less than exists value 4. Do step 2. until m'th row 5. Choose the minimum sum in the m'th row Let me explain on my example step by step: M[ 0 ][ 0 ] sum(L1 = (0, 1, 2, 2)) = 5 ; sum(L2 = (0,1,3,2)) = 6; so MLMS[ 0 ][ 1 ] = 6 sum(L3 = (0, 1, 3, 2)) = 6 ; sum(L4 = (0,1,4,2)) = 7; so MLMS[ 2 ][ 1 ] = 6 M[ 0 ][ 1 ] sum(L5 = (1, 0, 1, 4)) = 6; sum(L6 = (1,3,2,4)) = 10; so MLMS[ 2 ][ 2 ] = 6 ... the last MSLS is : 0 1 2 4 3 6 6 6 6 Which means 6 is the minimum L sum that can be reach from 0 to the m. I think it is O(8*(m-1)*n) = O(m*n). Is there any optimal solution or dynamic-programming algorithms fit this problem? Thanks, sorry for long question

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  • Why does Farseer 2.x store temporaries as members and not on the stack? (.NET)

    - by Andrew Russell
    UPDATE: This question refers to Farseer 2.x. The newer 3.x doesn't seem to do this. I'm using Farseer Physics Engine quite extensively at the moment, and I've noticed that it seems to store a lot of temporary value types as members of the class, and not on the stack as one might expect. Here is an example from the Body class: private Vector2 _worldPositionTemp = Vector2.Zero; private Matrix _bodyMatrixTemp = Matrix.Identity; private Matrix _rotationMatrixTemp = Matrix.Identity; private Matrix _translationMatrixTemp = Matrix.Identity; public void GetBodyMatrix(out Matrix bodyMatrix) { Matrix.CreateTranslation(position.X, position.Y, 0, out _translationMatrixTemp); Matrix.CreateRotationZ(rotation, out _rotationMatrixTemp); Matrix.Multiply(ref _rotationMatrixTemp, ref _translationMatrixTemp, out bodyMatrix); } public Vector2 GetWorldPosition(Vector2 localPosition) { GetBodyMatrix(out _bodyMatrixTemp); Vector2.Transform(ref localPosition, ref _bodyMatrixTemp, out _worldPositionTemp); return _worldPositionTemp; } It looks like its a by-hand performance optimisation. But I don't see how this could possibly help performance? (If anything I think it would hurt by making objects much larger).

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  • What algorithm can I use to detect simple shapes in a 4x4 matrix?

    - by ion
    I'm working on a simple multiplayer game that receives a random 4x4 matrix from a server and extracts a shape from it. For example: XXOO OXOO XXOX XXOO XOOX and XOOO XXXX OXXX So in the first matrix the shape I want to parse is: oo o oo and the 2nd: oo oo ooo I know there must be an algorithm for this because I saw this kind of behavior on some puzzle games but I have no idea how to go about to detecting them or even where to start. So my question is: How do I detect what shape is in the matrix and how do I differentiate between multiple colors? (it doesn't come only in X and O, it comes in a maximum of 4). Additionally, the shape must be a minimum of 4 blocks.

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  • 3D Model not translating correctly (visually)

    - by ChocoMan
    In my first image, my model displays correctly: But when I move the model's position along the Z-axis (forward) I get this, yet the Y-axis doesnt change. An if I keep going, the model disappears into the ground: Any suggestions as to how I can get the model to translate properly visually? Here is how Im calling the model and the terrain in draw(): cameraPosition = new Vector3(camX, camY, camZ); // Copy any parent transforms. Matrix[] transforms = new Matrix[mShockwave.Bones.Count]; mShockwave.CopyAbsoluteBoneTransformsTo(transforms); Matrix[] ttransforms = new Matrix[terrain.Bones.Count]; terrain.CopyAbsoluteBoneTransformsTo(ttransforms); // Draw the model. A model can have multiple meshes, so loop. foreach (ModelMesh mesh in mShockwave.Meshes) { // This is where the mesh orientation is set, as well // as our camera and projection. foreach (BasicEffect effect in mesh.Effects) { effect.EnableDefaultLighting(); effect.PreferPerPixelLighting = true; effect.World = transforms[mesh.ParentBone.Index] * Matrix.CreateRotationY(modelRotation) * Matrix.CreateTranslation(modelPosition); // Looking at the model (picture shouldnt change other than rotation) effect.View = Matrix.CreateLookAt(cameraPosition, modelPosition, Vector3.Up); effect.Projection = Matrix.CreatePerspectiveFieldOfView( MathHelper.ToRadians(45.0f), aspectRatio, 1.0f, 10000.0f); effect.TextureEnabled = true; } // Draw the mesh, using the effects set above. prepare3d(); mesh.Draw(); } //Terrain test foreach (ModelMesh meshT in terrain.Meshes) { foreach (BasicEffect effect in meshT.Effects) { effect.EnableDefaultLighting(); effect.PreferPerPixelLighting = true; effect.World = ttransforms[meshT.ParentBone.Index] * Matrix.CreateRotationY(0) * Matrix.CreateTranslation(terrainPosition); // Looking at the model (picture shouldnt change other than rotation) effect.View = Matrix.CreateLookAt(cameraPosition, terrainPosition, Vector3.Up); effect.Projection = Matrix.CreatePerspectiveFieldOfView( MathHelper.ToRadians(45.0f), aspectRatio, 1.0f, 10000.0f); effect.TextureEnabled = true; } // Draw the mesh, using the effects set above. prepare3d(); meshT.Draw(); DrawText(); } base.Draw(gameTime); } Im suspecting that there may be something wrong with how I'm handling my camera. The model rotates fine on its Y-axis.

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  • Why does my 3D model not translate the way I expect? [closed]

    - by ChocoMan
    In my first image, my model displays correctly: But when I move the model's position along the Z-axis (forward) I get this, yet the Y-axis doesnt change. An if I keep going, the model disappears into the ground: Any suggestions as to how I can get the model to translate properly visually? Here is how Im calling the model and the terrain in draw(): cameraPosition = new Vector3(camX, camY, camZ); // Copy any parent transforms. Matrix[] transforms = new Matrix[mShockwave.Bones.Count]; mShockwave.CopyAbsoluteBoneTransformsTo(transforms); Matrix[] ttransforms = new Matrix[terrain.Bones.Count]; terrain.CopyAbsoluteBoneTransformsTo(ttransforms); // Draw the model. A model can have multiple meshes, so loop. foreach (ModelMesh mesh in mShockwave.Meshes) { // This is where the mesh orientation is set, as well // as our camera and projection. foreach (BasicEffect effect in mesh.Effects) { effect.EnableDefaultLighting(); effect.PreferPerPixelLighting = true; effect.World = transforms[mesh.ParentBone.Index] * Matrix.CreateRotationY(modelRotation) * Matrix.CreateTranslation(modelPosition); // Looking at the model (picture shouldnt change other than rotation) effect.View = Matrix.CreateLookAt(cameraPosition, modelPosition, Vector3.Up); effect.Projection = Matrix.CreatePerspectiveFieldOfView( MathHelper.ToRadians(45.0f), aspectRatio, 1.0f, 10000.0f); effect.TextureEnabled = true; } // Draw the mesh, using the effects set above. prepare3d(); mesh.Draw(); } //Terrain test foreach (ModelMesh meshT in terrain.Meshes) { foreach (BasicEffect effect in meshT.Effects) { effect.EnableDefaultLighting(); effect.PreferPerPixelLighting = true; effect.World = ttransforms[meshT.ParentBone.Index] * Matrix.CreateRotationY(0) * Matrix.CreateTranslation(terrainPosition); // Looking at the model (picture shouldnt change other than rotation) effect.View = Matrix.CreateLookAt(cameraPosition, terrainPosition, Vector3.Up); effect.Projection = Matrix.CreatePerspectiveFieldOfView( MathHelper.ToRadians(45.0f), aspectRatio, 1.0f, 10000.0f); effect.TextureEnabled = true; } // Draw the mesh, using the effects set above. prepare3d(); meshT.Draw(); DrawText(); } base.Draw(gameTime); } I'm suspecting that there may be something wrong with how I'm handling my camera. The model rotates fine on its Y-axis.

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  • parallel to usb driver windows 7 dot matrix printer

    - by user975234
    I recently built a new Core i5 system with Windows 7 Professional. I had planned to hook up my TVS MSP 250 XL printer using a USB to parallel cable Once I plug the cable in, Windows 7 recognizes it as an IEEE-1284 controller and automatically installs the appropriate driver. However, in the status window it reports the following: "USB Printing Support -- Ready to use" "No Printer Attached -- Ready to use" When I then go ahead and manually add the printer using the "virtual printer port for USB" I can add the printer seemingly without problem. Once finished, it appears in the Devices and Printers panel. Yet, all attempts to print on this printer fail. It appears that simply no data is sent to the printer (either by programs like word or adobe or by attempting to print a test page. Does anybody know how to fix this?

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  • Speed boost to adjacency matrix

    - by samoz
    I currently have an algorithm that operates on an adjacency matrix of size n by m. In my algorithm, I need to zero out entire rows or columns at a time. My implementation is currently O(m) or O(n) depending on if it's a column or row. Is there any way to zero out a column or row in O(1) time?

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  • Creating an adjacency Matrix from a JUNG Graph.

    - by prince
    Graph < Integer, Integer> g = new SparseMultigraph<Integer, Integer>(); g.addVertex(1);g.addVertex(2);g.addVertex(3); g.addEdge(0,1,2 ,EdgeType.DIRECTED);g.addEdge(1,2,3 ,EdgeType.DIRECTED);g.addEdge(2,3,1 ,EdgeType.DIRECTED);g.addEdge(3,1,3 ,EdgeType.DIRECTED); How can I convert this graph into an adjacency matrix taking into consideration that it is a directed graph.

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  • Matrix Transpose TSQL

    - by rmdussa
    Can we do matrix transpose (rows become columns and columns become rows) in standard SQL? 1 2 3 4 5 4 5 6 6 7 7 8 9 8 9 1 3 4 5 6 2 4 5 6 7 changes to 1 4 7 1 2 2 5 8 3 4 3 6 9 5 6 4 6 8 5 6 5 7 9 6 7 how about no of rows < no of column ? let's consider the no of rows it's fixed.

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  • Read data matrix barcodes on iPhone?

    - by Saurabh
    Hi All, Is there any Open Source project I can use to read data matrix codes (not QR codes, I know I can use ZXing project to read QR Codes) on iPhone? Any JAVA Open Source would also be helpful (I'll convert that into a web service and use on iPhone). Any help would be much appreciated! Thanks Saurabh

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  • Performance Optimization for Matrix Rotation

    - by Summer_More_More_Tea
    Hello everyone: I'm now trapped by a performance optimization lab in the book "Computer System from a Programmer's Perspective" described as following: In a N*N matrix M, where N is multiple of 32, the rotate operation can be represented as: Transpose: interchange elements M(i,j) and M(j,i) Exchange rows: Row i is exchanged with row N-1-i A example for matrix rotation(N is 3 instead of 32 for simplicity): ------- ------- |1|2|3| |3|6|9| ------- ------- |4|5|6| after rotate is |2|5|8| ------- ------- |7|8|9| |1|4|7| ------- ------- A naive implementation is: #define RIDX(i,j,n) ((i)*(n)+(j)) void naive_rotate(int dim, pixel *src, pixel *dst) { int i, j; for (i = 0; i < dim; i++) for (j = 0; j < dim; j++) dst[RIDX(dim-1-j, i, dim)] = src[RIDX(i, j, dim)]; } I come up with an idea by inner-loop-unroll. The result is: Code Version Speed Up original 1x unrolled by 2 1.33x unrolled by 4 1.33x unrolled by 8 1.55x unrolled by 16 1.67x unrolled by 32 1.61x I also get a code snippet from pastebin.com that seems can solve this problem: void rotate(int dim, pixel *src, pixel *dst) { int stride = 32; int count = dim >> 5; src += dim - 1; int a1 = count; do { int a2 = dim; do { int a3 = stride; do { *dst++ = *src; src += dim; } while(--a3); src -= dim * stride + 1; dst += dim - stride; } while(--a2); src += dim * (stride + 1); dst -= dim * dim - stride; } while(--a1); } After carefully read the code, I think main idea of this solution is treat 32 rows as a data zone, and perform the rotating operation respectively. Speed up of this version is 1.85x, overwhelming all the loop-unroll version. Here are the questions: In the inner-loop-unroll version, why does increment slow down if the unrolling factor increase, especially change the unrolling factor from 8 to 16, which does not effect the same when switch from 4 to 8? Does the result have some relationship with depth of the CPU pipeline? If the answer is yes, could the degrade of increment reflect pipeline length? What is the probable reason for the optimization of data-zone version? It seems that there is no too much essential difference from the original naive version. EDIT: My test environment is Intel Centrino Duo processor and the verion of gcc is 4.4 Any advice will be highly appreciated! Kind regards!

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  • MATrix LABoratory interview questions?

    - by Shane
    I programmed in MATrix LABoratory for many years, but switched to using R exclusively in the past few years so I'm a little out of practice. I'm interviewing a candidate today who describes himself as an expert? What interview questions that I should be asking?

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  • Understanding this matrix transposition function in Haskell

    - by dmindreader
    This matrix transposition function works, but I'm trying to understand its step by step execurtion and I don't get it. transpose:: [[a]]->[[a]] transpose ([]:_) = [] transpose x = (map head x) : transpose (map tail x) with transpose [[1,2,3],[4,5,6],[7,8,9]] it returns: [[1,4,7],[2,5,8],[3,6,9]] I don't get how the concatenation operator is working with map. It is concatenating each head of x in the same function call? How?

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  • Is there an Open Source licence matrix?

    - by tobsen
    I am trying to find a simple matrix overview of the various licenses around open source software but can't find anything useful. I would like to know whether software under a certain licence can be used in commercial closed source software, if there has to be the original source code included, if the licence has to be redistirbuted, etc. I know this is a difficult topic because I guess only the minority of programmers are also moonlighting lawyers - neither am I.

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  • OpenGL: Implementing transformation matrix stack

    - by Jakub M.
    In a newer OpenGL there is no matrix stack. I am working on a simple display engine, and I am going to implement the transformation stack. What is a common strategy here? Should I build a push/pop stack, and use it with a tree representing my model? I suppose this is the "old" approach, that was deprecated in the newer OpenGL versions. Maybe then it is not the best solution (it was removed for some reason)

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  • To find a determinate of Matrix using Boost library in c++

    - by user314097
    Hi, I' am required to convert a MATLAB function into C++, and this requires me to find determinate of a matrix. I was told that use of BOOST library would make my job easier. I went through the documentation of BOOST Library, but couldn't find much info about the same. If anyone could give a template for the above operation, It would be of lot of help and would be greatly appreciated. Thanks Regards

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