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  • SQLBeat Podcast – Episode 6 – And the Winner is…Meredith Ryan from Albakerkee.

    - by SQLBeat
    In this episode I speak with the winner of the Exceptional DBA Award for 2012, Meredith Ryan.  We talk about a lot of things, but mainly attending the PASS Summit, first timers (this is PASS related too) and SQL Saturdays. Meredith has been with her present company for 14 years, an achievement of a bygone era in IT, but we are kindred in this area having worked at my present position for nearly 7. We also agree that every DBA should have to spend at least 2 years on Help Desk. I feel really, really dumb for not having recognized her tattoo, which I shamelessly ask about.  Congratulations, Meredith on your award and I look forward to meeting you this year in a few short weeks. Download the MP3

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  • Tellago 2011: Dwight, Chris and Don are MVPs

    - by gsusx
    It’s been a great start of 2011. Tellago’s Dwight Goins has been awarded as a Microsoft BizTalk Server MVP for 2011. I’ve always said that Dwight should have been an MVP a long time ago. His contributions to the BizTalk Server community are nothing but remarkable. In addition to Dwight, my colleagues Don Demsak and Chris Love also renewed their respective MVP award. A few other of us are up for renewal later in the year. As a recognition to Dwight’s award, we have made him the designated doorman...(read more)

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  • Microsoft MVP for the Third Time

    - by shiju
    I just received an email from Microsoft which stating that I have been awarded as Microsoft MVP again for 2012!! Now I became a Microsoft MVP for the third time in a row. Here's the email below: Dear Shiju Varghese, Congratulations! We are pleased to present you with the 2012 Microsoft® MVP Award! This award is given to exceptional technical community leaders who actively share their high quality, real world expertise with others. We appreciate your outstanding contributions in ASP.NET/IIS technical communities during the past year. On this occasion, I would like to thank Microsoft, community leaders, fellow MVPs, my blog readers, my employer Marlabs and finally big thanks to my lovely wife Rosmi and to my daughter Irene Rose.

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  • AJI Report 14 &ndash; Brian Lagunas on XAML and Windows 8

    - by Jeff Julian
    We sat down with Brian at the Iowa Code Camp to talk about his sessions, WPF, Application Design, and what Infragistics has to offer developers. Infragistics is a huge supporter of regional events like Iowa Code Camp and we want to thank them for their support of the Midwest region. Brian is a sharp guy and it was great to meet him and learn more about what makes him tick. Brian Lagunas is an INETA Community Speaker, co-leader of the Boise .Net Developers User Group (NETDUG), and original author of the Extended WPF Toolkit. He is a multi-recipient of the Microsoft Community Contributor Award and can be found speaking at a variety of user groups and code camps around the nation. Brian currently works at Infragistics as a Product Manager for the award winning NetAdvantage for WPF and Silverlight components. Before geeking out, Brian served his country in the United States Army as an infantryman and later served his local community as a deputy sheriff.   Listen to the Show   Site: http://brianlagunas.com Twitter: @BrianLagunas

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  • The Oracle Retail Week Awards - Store Manager of the year

    - by user801960
    Below is a video featuring interviews with the nominees for the Oracle Retail Week Awards 2012 Store Manager of the Year Award, in which the nominees talk about the value of being nominated for an Oracle Retail Week Award and what it means to them to be recognised. The video includes interviews with ASDA CEO Andy Clarke, who talks about how important the store managers are to the functioning of a retail business. The nominees interviewed were: Ian Allcock from Homebase in Aylesford David Bickell from Argos in Milton Keynes Karl Lynsdale from Co-operative Food in Heathfield, Sussex Paul Norcross from B&Q in Bristol Darren Parfitt from Boots in Melton Mowbray Helen Smith from H Samuel in Manchester Oracle Retail would like to congratulate the winner, Ian Allcock from Homebase in Aylesford. Well done Ian!

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  • Awarded Visual Studio ALM MVP for 2012!

    - by Jakob Ehn
    Today I received an email from Microsoft stating that: Dear Jakob Ehn, Congratulations! We are pleased to present you with the 2012 Microsoft® MVP Award! This award is given to exceptional technical community leaders who actively share their high quality, real world expertise with others. We appreciate your outstanding contributions in Visual Studio ALM technical communities during the past year.   This is incredibles news and I really want to thank both the people at Microsoft who nominated me and some of the (now) fellow MVP’s that I have worked with over the last year, both as part of the Visual Studio ALM Rangers program and as part of the TFS Build Extensions community project, in particular Mike Fourie and of course my colleague and main source of inspiration Terje Sandström    I’m really looking forward to this year, it’s going to be a blast!

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  • Watch 53rd Grammy Awards 2011 Live Stream & Follow The Event On Facebook & Twitter

    - by Gopinath
    Grammy Awards is the biggest music awards ceremony that honours music genres. The 53rd Grammy Awards function will be held on February 13, 2011 at Staples Center in Los Angeles. The star studded musical event will be telecasted live on CBS TV between 8pm ET until 11:30pm ET. Behind The Scenes Live Stream On YouTube and Grammy.com Grammy, YouTube and TurboTax has teamed up to provide live stream of behind the scene coverage of key events starting at 5pm Feb 11th and runs through February 13th. Note that this stream will not broadcast the 3 hour long award presentation. Kind of bad, except the award presentation rest of the ceremony is streamed here.  The video stream is embedded below Catch live behind-the-scenes coverage of key events during GRAMMY week. Before the show, you can watch the Nominees Reception, Clive Davis Pre-GRAMMY Gala, the red carpet and the pre-telecast ceremony. During the show, go backstage to see the winners after they accept their award! You can catch the same stream on Grammys’s YouTube channel as well as on Grammy.com website Follow Grammy Awards On Facebook & Twitter The Grammy Awards has an official Facebook and Twitter account and you can follow them for all the latest information The Grammy’s Facebook Page The Grammy’s Twitter Page Grammy Live Streaming on UStream & Justin.tv Even though there is no official source that stream live of The Grammy Awards presentation ceremony, there will be plenty of unofficial sources on UStream and Justin.tv. So search UStream and Justin.tv for live streaming of The Grammy’s. TV Channels Telecasting The Grammy Awards 2011 Here is the list of TV channels in various countries offering live telecast of The Grammy Awards 2011. We keep updating this section as and when we get more information USA – CBS Television Network  – February 13, 2011 India – VH1 TV – February 14  2011 , 6:30 AM United Kingdom – ITV2  – 16 February 2011, 10:00PM – 12:00AM This article titled,Watch 53rd Grammy Awards 2011 Live Stream & Follow The Event On Facebook & Twitter, was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

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  • 2011 The Year of Awesomesauce

    - by MOSSLover
    So I was talking to one of my friends, Cathy Dew, and I’m wondering how to start out this post.  What kind of title should I put?  Somehow we’re just randomly throwing things out and this title pops into my head the one you see above. I woke up today to the buzz of a text message.  I spent New Years laying around until 3 am watching Warehouse 13 Episodes and drinking champagne.  It was one of the best New Year’s I spent with my boyfriend and my cat.  I figured I would sleep in until Noon, but ended up waking up around 11:15 to that text message buzz.  I guess my DE, Rachel Appel, had texted me “Happy New Years”, because Rachel is that kind of person.  I immediately proceeded to check my email.  I noticed my live account had a hit.  The account I rarely ever use had an email.  I sort of had that sinking suspicion I was going to get Silverlight MVP right?  So I open the email and something out of the blue happens it says “blah blah blah SharePoint Server MVP blah blah…”.  I’m sitting here a little confused what?  Really?  Just about when you give up on something the unexplained happens.  I am grateful for what I have every day. So let me tell you a story.  I was a senior in high school and it was December 31st, 1999.  A couple days prior my grandmother was complaining she had a cold and her assisted living facility was not going to let her see a doctor.  She claimed to be very sick.  New Year’s Eve Day 1999 my grandmother was rushed to the hospital sometime very early in the morning.  My uncle, my little brother, and myself were sitting in the waiting room eagerly awaiting news.  The Sydney Opera House was playing in the background as New Years 2000 for Australia was ringing in.  They come out and they tell us my grandmother has pneumonia.  She is in the ICU in critical condition.  Eventually time passes in the day and my parents take my brother and I home.  So in the car we had a huge fight that ended in the worst new years of my life.  The next 30 days were the worst 30 days of my life.  I went to the hospital every single day to do my homework and watch my grandmother.  Each day was a challenge mentally and physically as my grandmother berated me in her demented state.  On the 30th day my grandmother ended up in critical condition in the ICU maxed out on painkillers.  At approximately 3 am I hear my parents telling me they don’t want to wake me up and that my grandmother had passed away.  I must have cried more collectively that day than any other day in my life.  Every New Years Even since I have cried thinking about who she was and what she represented.  She was human looking back she wasn’t anything great, but she was one of the positive lights in my life.  Her and my dad and my other grandmother constantly tried to make me feel great when my mother was telling me the opposite.  I’d like to think since 2000 the past 11 years have been the best 11 years of my life.  I got out of a bad situation by using the tools that I had in front of me.  Good grades and getting into a college so I could aspire to be the person that I wanted to be.  I had some great people along the way to help me out. So getting to the point I like to help people further there lives somehow in the best way I can possibly help out.  This New Years was one of the great years that helped me forget the past and focus on the present.  It makes me realize how far I’ve come since high school and even since college.  The one thing I’ve been grappling with over the years is how do you feel good about making money while helping others out.  I’d to think I try really hard to give back to my community.  I could not have done what I did without other people’s help.  I sent out an email prior to even announcing I got the award today.  I can’t say I did everything on my own.  It’s not possible.  I had the help of others every step of the way.  I’m not sure if this makes sense but the award can’t just be mine.  This award is really owned by each and everyone who helped me get here.  From my dad to my grandmother to Rachel Appel to Bob Hunt to Jason Gallicchio to Cathy Dew to Mark Rackley to Johnny Ennion to Lee Brandt to Jeff Julian to John Alexander to Lori Gowin and to many others.  Thank you guys for all the help and support. Technorati Tags: SharePoint Community,MVP Award,Microsoft Community

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  • Oracle Excellence Awards 2012

    - by A&C Redaktion
    Spezialisierte Partner können sich ab sofort bis 29. Juni als „Specialized Partner of the Year“ bewerben. Damit honoriert Oracle diejenigen OPN Partner in EMEA, die sich mithilfe der Spezialisierung besonders ausgezeichnet haben, sei es durch einen hohen Mehrwert für deren Endkunden oder innovativen Lösungen und Services. Voraussetzung für eine Bewerbung ist mindestens eine abgeschlossene Spezialisierung in diesen sieben Kategorien: Specialized Partner of the Year: Database Specialized Partner of the Year: Applications Specialized Partner of the Year: Middleware Specialized Partner of the Year: Industry Specialized Partner of the Year: Oracle Accelerate Specialized Partner of the Year: Servers and Storage Systems Specialized Partner of the Year: Oracle on Oracle Der Gewinner eines “Specialized Partner of the Year” EMEA Awards erhält 5.000 US-Dollar MDF und vielfältige Möglichkeiten, sich in Szene zu setzen. Wie auch im letzten Jahr wird der Award wieder auf der Oracle OpenWorld in San Francisco überreicht. Interviews, Videos, Werbung, Berichte im Oracle Magazine und ein kostenloser Konferenzpass sind natürlich inklusive. Wie immer, gilt die Bewerbung für den EMEA-Award gleichzeitig als Bewerbung für den deutschen Partner-Award 2012, der auf dem Oracle Partner Day (im Herbst nach der OpenWorld) verliehen wird. Normal 0 21 false false false DE X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Die Nominierung Ihres erfolgreichen Projektes muss diesmal hier auf Englisch eingereicht werden, da eine internationale Jury entscheidet. Beschreiben Sie Ihr Projekt so ausführlich wie möglich, damit sich die Juroren ein gutes Bild Ihrer Leistungen und Services machen können. Wenn Sie hierbei Unterstützung benötigen, fragen Sie einfach Ihren Channel Manager. Denn: Je aussagekräftiger Ihre Unterlagen sind, desto höher ist Ihre Chance zu gewinnen! Alle Informationen zu den diesjährigen Awards finden Sie auf der Oracle Excellence Awards Website. Wir drücken Ihnen die Daumen!

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  • Oracle Excellence Awards 2012

    - by A&C Redaktion
    Spezialisierte Partner können sich ab sofort bis 29. Juni als „Specialized Partner of the Year“ bewerben. Damit honoriert Oracle diejenigen OPN Partner in EMEA, die sich mithilfe der Spezialisierung besonders ausgezeichnet haben, sei es durch einen hohen Mehrwert für deren Endkunden oder innovativen Lösungen und Services. Voraussetzung für eine Bewerbung ist mindestens eine abgeschlossene Spezialisierung in diesen sieben Kategorien: Specialized Partner of the Year: Database Specialized Partner of the Year: Applications Specialized Partner of the Year: Middleware Specialized Partner of the Year: Industry Specialized Partner of the Year: Oracle Accelerate Specialized Partner of the Year: Servers and Storage Systems Specialized Partner of the Year: Oracle on Oracle Der Gewinner eines “Specialized Partner of the Year” EMEA Awards erhält 5.000 US-Dollar MDF und vielfältige Möglichkeiten, sich in Szene zu setzen. Wie auch im letzten Jahr wird der Award wieder auf der Oracle OpenWorld in San Francisco überreicht. Interviews, Videos, Werbung, Berichte im Oracle Magazine und ein kostenloser Konferenzpass sind natürlich inklusive. Wie immer, gilt die Bewerbung für den EMEA-Award gleichzeitig als Bewerbung für den deutschen Partner-Award 2012, der auf dem Oracle Partner Day (im Herbst nach der OpenWorld) verliehen wird. Normal 0 21 false false false DE X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Die Nominierung Ihres erfolgreichen Projektes muss diesmal hier auf Englisch eingereicht werden, da eine internationale Jury entscheidet. Beschreiben Sie Ihr Projekt so ausführlich wie möglich, damit sich die Juroren ein gutes Bild Ihrer Leistungen und Services machen können. Wenn Sie hierbei Unterstützung benötigen, fragen Sie einfach Ihren Channel Manager. Denn: Je aussagekräftiger Ihre Unterlagen sind, desto höher ist Ihre Chance zu gewinnen! Alle Informationen zu den diesjährigen Awards finden Sie auf der Oracle Excellence Awards Website. Wir drücken Ihnen die Daumen!

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  • Sometimes you have to brag on your employer

    - by Mickey Gousset
    A lot of you know me as an Application Lifecycle Management MVP, and a huge proponent of ALM, TFS, and Visual Studio.  For my day job, however, I work for Infront Consulting Group, a System Center consulting and training organization.  I love what I do there, and work closely with Operations Manager, Service Manager, and Orchestrator.  And believe it or not, use a lot of ALM best practices around all of those. Infront was just recognized as a 2012 Microsoft Corporate Account Virtualization Data Center Services Partner of the Year.  This award recognizes a solution partner that has demonstrated leadership and commitment in driving Microsoft virtualization solutions in the Microsoft Corporate Account segment.  I’m very proud of Infront, and all the hard work that everyone here has put into the incredible services we provide, which lead to us winning this award.

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  • Eco-Enterprise Innovation Awards: Bewerben Sie sich bis 17. Juli!

    - by A&C Redaktion
    Sie haben einen Kunden, der mihilfe eines Oracle Produkts die Umweltbelastung reduzieren und gleichzeitig die betriebliche Effizienz steigern konnte? Zum Beispiel durch Senkung des Energie- oder Benzinverbrauchs oder durch ein papierloses Büro? Damit können Sie beide profitieren und sich beim Eco-Enterprise Innovation Award bewerben. Der Eco-Award ist Teil des Oracle Excellence Awards Programms. Hier finden Sie weitere Informationen und können sich noch bis 17. Juli 2012 anmelden. Die Verleihung der Awards findet während der Oracle OpenWorld in einer speziellen Session statt und wird von Jeff Henley, Oracle Chairman of the Board, überreicht. Die Gewinner erhalten einen kostenlosen Konferenzpass für die Oracle OpenWorld.

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  • SSMS Tools Pack 2.1.0 is out. Added support for SQL Server 2012 RC0.

    - by Mladen Prajdic
    This version adds support for SQL Server 2012 RC0 and fixes a few bugs with SQL History. Because of the support for regions in SSMS 2012 the regions and debug sections feature has been removed from SSMS Tools Pack for SQL Server 2012. The feature is still available for previous SSMS versions. In other news SSMS Tools Pack has won the SQL Magazine bronze award for best free tool of 2011. You can view all the details at the SQL Server Magazine Award page. Thanx to all the people who voted for it. I'm glad you all like it and use it with great success. Also I've added a possibility for you to subscribe to email notifications in case the auto-updater doesn't work for you for some reason like being behind a proxy. Enjoy it!

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  • c# Regex trouble

    - by Shannow
    Hi there, I'm having a bit of trouble with my regex. String a = @"{target=}jump"; String b = "continue"; String c = "jump"; String d = @"{target=intro}jump"; String e = "prev"; String f = @"{target=}choice"; String g = @"{target=intro}choice"; String h = "choice"; String i = "previous"; String j = @"{target=intro}continue"; String k = "cont"; String l = @"{target=}continue"; Regex regex = new Regex(@"(^{target=(\w.*)}(choice|jump))|(^[^.]*(continue|previous))"); var a_res = regex.IsMatch(a); var b_res = regex.IsMatch(b); var c_res = regex.IsMatch(c); var d_res = regex.IsMatch(d); var e_res = regex.IsMatch(e); var f_res = regex.IsMatch(f); var g_res = regex.IsMatch(g); var h_res = regex.IsMatch(h); var i_res = regex.IsMatch(i); var j_res = regex.IsMatch(j); var k_res = regex.IsMatch(k); var l_res = regex.IsMatch(l); Basically what i need is to get a match when choice or jump is present that it is proceeded by {target= } with any number of characters after the =. And also to match if continue or previous are present but only if they are proceeded by nothing. so A = false, b = true, c = false, d = true, e = false, f = false, g = true, h = false, i = true, j = false, k = false and l = false, with my regex above I get correct reading for everything bar j and l. Can anyone please help?

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  • Link List Problem,

    - by david
    OK i have a problem with a Link List program i'm trying to Do, the link List is working fine. Here is my code #include <iostream> using namespace std; struct record { string word; struct record * link; }; typedef struct record node; node * insert_Node( node * head, node * previous, string key ); node * search( node *head, string key, int *found); void displayList(node *head); node * delete_node( node *head, node * previous, string key); int main() { node * previous, * head = NULL; int found = 0; string node1Data,newNodeData, nextData,lastData; //set up first node cout <<"Depature"<<endl; cin >>node1Data; previous = search( head, node1Data, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, node1Data); cout <<"Depature inserted"<<endl; //insert node between first node and head cout <<"Destination"<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Destinationinserted"<<endl; //insert node between second node and head cout <<"Cost"<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Cost inserted"<<endl; cout <<"Number of Seats Required"<<endl; //place node between new node and first node cin >>nextData; previous = search( head, nextData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, nextData); cout <<"Number of Seats Required inserted"<<endl; //insert node between first node and head cout <<"Name"<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Name inserted"<<endl; //insert node between node and head cout <<"Address "<<endl; cin >>newNodeData; previous = search( head, newNodeData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, newNodeData); cout <<"Address inserted"<<endl; //place node as very last node cin >>lastData; previous = search( head, lastData, &found); cout <<"Previous" <<previous<<endl; head = insert_Node(head, previous, lastData); cout <<"C"<<endl; displayList(head); char Ans = 'y'; //Delete nodes do { cout <<"Enter Keyword to be delete"<<endl; cin >>nextData; previous = search( head, nextData, &found); if (found == 1) head = delete_node( head, previous,nextData); displayList(head); cout <<"Do you want to Delete more y /n "<<endl; cin >> Ans; } while( Ans =='y'); int choice, i=0, counter=0; int fclass[10]; int coach[10]; printf("Welcome to the booking program"); printf("\n-----------------"); do{ printf("\n Please pick one of the following option:"); printf("\n 1) Reserve a first class seat on Flight 101."); printf("\n 2) Reserve a coach seat on Flight 101."); printf("\n 3) Quit "); printf("\n ---------------------------------------------------------------------"); printf("\nYour choice?"); scanf("%d",&choice); switch(choice) { case 1: i++; if (i <10){ printf("Here is your seat: %d " , fclass[i]); } else if (i = 10) { printf("Sorry there is no more seats on First Class. Please wait for the next flight"); } break; case 2: if (i <10){ printf("Here is your Seat Coach: %d " , coach[i]); } else if ( i = 10) { printf("Sorry their is no more Seats on Coach. Please wait for the next flight"); } break; case 3: printf("Thank you and goodbye\n"); //exit(0); } } while (choice != 3); } /******************************************************* search function to return previous position of node ******************************************************/ node * search( node *head, string key, int *found) { node * previous, * current; current = head; previous = current; *found = 0;//not found //if (current->word < key) move through links until the next link //matches or current_word > key while( current !=NULL) { //compare exactly if (key ==current->word ) { *found = 1; break; } //if key is less than word else if ( key < current->word ) break; else { //previous stays one link behind current previous = current; current = previous -> link; } } return previous; } /******************************************************** display function as used with createList ******************************************************/ void displayList(node *head) { node * current; //current now contains the address held of the 1st node similar //to head current = head; cout << "\n\n"; if( current ==NULL) cout << "Empty List\n\n"; else { /*Keep going displaying the contents of the list and set current to the address of the next node. When set to null, there are no more nodes */ while(current !=NULL) { cout << current->word<<endl; current = current ->link; } } } /************************************************************ insert node used to position node (i) empty list head = NULL (ii) to position node before the first node key < head->word (iii) every other position including the end of the list This is done using the following steps (a) Pass in all the details to create the node either details or a whole record (b) Pass the details over to fill the node (C) Use the if statement to add the node to the list **********************************************************/ node * insert_Node( node * head, node * previous, string key ) { node * new_node, * temp; new_node = new node; //create the node new_node ->word = key; new_node -> link = NULL; if (head == NULL || key < head->word ) //empty list { //give address of head to temp temp = head; //head now points to the new_node head = new_node; //new_node now points to what head was pointing at new_node -> link = temp; } else { //pass address held in link to temp temp = previous-> link; //put address of new node to link of previous previous -> link = new_node; //pass address of temp to link of new node new_node -> link = temp; } return head; } node * delete_node( node *head, node * previous, string key) { /* this function will delete a node but will not return its contents */ node * temp; if(key == head->word) //delete node at head of list { temp = head; //point head at the next node head = head -> link; } else { //holds the address of the node after the one // to be deleted temp = previous-> link; /*assign the previous to the address of the present node to be deleted which holds the address of the next node */ previous-> link = previous-> link-> link; } delete temp; return head; }//end delete The problem i have is when i Enter in the Number 2 in the Node(Seats) i like to get a Counter Taken 2 off of 50, some thing like what i have here enter code here int choice, i=0, counter=0; int fclass[10]; int coach[10]; printf("Welcome to the booking program"); printf("\n-----------------"); do{ printf("\n Please pick one of the following option:"); printf("\n 1) Reserve a first class seat on Flight 101."); printf("\n 2) Reserve a coach seat on Flight 101."); printf("\n 3) Quit "); printf("\n ---------------------------------------------------------------------"); printf("\nYour choice?"); scanf("%d",&choice); switch(choice) { case 1: i++; if (i <10){ printf("Here is your seat: %d " , fclass[i]); } else if (i = 10) { printf("Sorry there is no more seats on First Class. Please wait for the next flight"); } break; case 2: if (i <10){ printf("Here is your Seat Coach: %d " , coach[i]); } else if ( i = 10) { printf("Sorry their is no more Seats on Coach. Please wait for the next flight"); } break; case 3: printf("Thank you and goodbye\n"); //exit(0); } } while (choice != 3); How can i get what the User enters into number of Seats into this function

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  • How to set arrayList size as null?

    - by Jessy
    String a []= {null,null,null,null,null}; //add array to arraylist ArrayList<Object> choice = new ArrayList<Object>(Arrays.asList(a)); System.out.println(choice.size()); Why the size of the arrayList choice is 5 when all the elements have been set to null

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  • Multiple autocompletes on same form in socialengine

    - by Mirza Awais
    I am quite new to socialegine module development. I want to use multiple autocomplets on my one form. I have no problem of showing multiple auto completes but problem comes when one selects options from auto complete. I have seen that autocompet.js uses id toValues to show selected option from autocomlte. So if there is only one autocomplete on one form then we can have one element as toValues to show the selected value. But if we have multiple auto completes then how to show the selected item of each auto complete as separately? Using the following code for autocomplete en4.core.runonce.add(function() { new Autocompleter.Request.JSON('to', '<?php echo $this->url(array('module' => 'localspots', 'controller' => 'lookup', 'action' => 'city'), 'default', true) ?>', { 'minLength': 2, 'delay' : 1, 'selectMode': 'pick', 'autocompleteType': 'message', 'multiple': false, 'className': 'message-autosuggest', 'filterSubset' : true, 'tokenFormat' : 'object', 'tokenValueKey' : 'label', 'injectChoice': function(token){ console.log(token.type); var choice = new Element('li', {'class': 'autocompleter-choices', 'html': token.photo, 'id':token.label}); new Element('div', {'html': this.markQueryValue(token.label),'class': 'autocompleter-choice'}).inject(choice); this.addChoiceEvents(choice).inject(this.choices); choice.store('autocompleteChoice', token); }, onPush : function(){ if( $('toValues').value.split(',').length >= maxRecipients ){ $('to').disabled = true; $('to').setAttribute("class", "disabled"); } }, }); });

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  • calling calloc - memory leak valgrind

    - by Mike
    The following code is an example from the NCURSES menu library. I'm not sure what could be wrong with the code, but valgrind reports some problems. Any ideas... ==4803== 1,049 (72 direct, 977 indirect) bytes in 1 blocks are definitely lost in loss record 25 of 36 ==4803== at 0x4C24477: calloc (vg_replace_malloc.c:418) ==4803== by 0x400E93: main (in /home/gerardoj/a.out) ==4803== ==4803== LEAK SUMMARY: ==4803== definitely lost: 72 bytes in 1 blocks ==4803== indirectly lost: 977 bytes in 10 blocks ==4803== possibly lost: 0 bytes in 0 blocks ==4803== still reachable: 64,942 bytes in 262 blocks Source code: #include <curses.h> #include <menu.h> #define ARRAY_SIZE(a) (sizeof(a) / sizeof(a[0])) #define CTRLD 4 char *choices[] = { "Choice 1", "Choice 2", "Choice 3", "Choice 4", "Choice 5", "Choice 6", "Choice 7", "Exit", } ; int main() { ITEM **my_items; int c; MENU *my_menu; int n_choices, i; ITEM *cur_item; /* Initialize curses */ initscr(); cbreak(); noecho(); keypad(stdscr, TRUE); /* Initialize items */ n_choices = ARRAY_SIZE(choices); my_items = (ITEM **)calloc(n_choices + 1, sizeof(ITEM *)); for (i = 0; i < n_choices; ++i) { my_items[i] = new_item(choices[i], choices[i]); } my_items[n_choices] = (ITEM *)NULL; my_menu = new_menu((ITEM **)my_items); /* Make the menu multi valued */ menu_opts_off(my_menu, O_ONEVALUE); mvprintw(LINES - 3, 0, "Use <SPACE> to select or unselect an item."); mvprintw(LINES - 2, 0, "<ENTER> to see presently selected items(F1 to Exit)"); post_menu(my_menu); refresh(); while ((c = getch()) != KEY_F(1)) { switch (c) { case KEY_DOWN: menu_driver(my_menu, REQ_DOWN_ITEM); break; case KEY_UP: menu_driver(my_menu, REQ_UP_ITEM); break; case ' ': menu_driver(my_menu, REQ_TOGGLE_ITEM); break; case 10: { char temp[200]; ITEM **items; items = menu_items(my_menu); temp[0] = '\0'; for (i = 0; i < item_count(my_menu); ++i) if(item_value(items[i]) == TRUE) { strcat(temp, item_name(items[i])); strcat(temp, " "); } move(20, 0); clrtoeol(); mvprintw(20, 0, temp); refresh(); } break; } } free_item(my_items[0]); free_item(my_items[1]); free_menu(my_menu); endwin(); }

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  • C++: Calling class functions within a switch

    - by user1446002
    i've been trying to study for my finals by practicing classes and inheritance, this is what I've come up with so far for inheritance and such however I'm unsure how to fix the error occuring below. #include<iostream> #include<iomanip> #include<cmath> #include<string.h> using namespace std; //BASE CLASS DEFINITION class hero { protected: string name; string mainAttr; int xp; double hp; double mana; double armour; int range; double attkDmg; bool attkType; public: void dumpData(); void getName(); void getMainAttr(); void getAttkData(); void setAttkData(string); void setBasics(string, string, double, double, double); void levelUp(); }; //CLASS FUNCTIONS void hero::dumpData() { cout << "Name: " << name << endl; cout << "Main Attribute: " << mainAttr << endl; cout << "XP: " << xp << endl; cout << "HP: " << hp << endl; cout << "Mana: " << mana << endl; cout << "Armour: " << armour << endl; cout << "Attack Range: " << range << endl; cout << "Attack Damage: " << attkDmg << endl; cout << "Attack Type: " << attkType << endl << endl; } void hero::getName() { cout << "Name: " << name << endl; } void hero::getMainAttr() { cout << "Main Attribute: " << mainAttr << endl; } void hero::getAttkData() { cout << "Attack Range: " << range << endl; cout << "Attack Damage: " << attkDmg << endl; cout << "Attack Type: " << attkType << endl; } void hero::setAttkData(string attr) { int choice = 0; if (attr == "Strength") { choice = 1; } if (attr == "Agility") { choice = 2; } if (attr == "Intelligence") { choice = 3; } switch (choice) { case 1: range = 128; attkDmg = 80.0; attkType = 0; break; case 2: range = 350; attkDmg = 60.0; attkType = 0; break; case 3: range = 600; attkDmg = 35.0; attkType = 1; break; default: break; } } void hero::setBasics(string heroName, string attribute, double health, double mp, double armourVal) { name = heroName; mainAttr = attribute; hp = health; mana = mp; armour = armourVal; } void hero::levelUp() { xp = 0; hp = hp + (hp * 0.1); mana = mana + (mana * 0.1); armour = armour + ((armour*0.1) + 1); attkDmg = attkDmg + (attkDmg * 0.05); } //INHERITED CLASS DEFINITION class neutHero : protected hero { protected: string drops; int xpGain; public: int giveXP(int); void dropItems(); }; //INHERITED CLASS FUNCTIONS int neutHero::giveXP(int exp) { xp += exp; } void neutHero::dropItems() { cout << name << " has dropped the following items: " << endl; cout << drops << endl; } /* END OF OO! */ //FUNCTION PROTOTYPES void dispMenu(); int main() { int exit=0, choice=0, mainAttrChoice=0, heroCreated=0; double health, mp, armourVal; string heroName, attribute; do { dispMenu(); cin >> choice; switch (choice) { case 1: system("cls"); cout << "Please enter your hero name: "; cin >> heroName; cout << "\nPlease enter your primary attribute\n"; cout << "1. Strength\n" << "2. Agility\n" << "3. Intelligence\n"; cin >> mainAttrChoice; switch (mainAttrChoice) { case 1: attribute = "Strength"; health = 750; mp = 150; armourVal = 2; break; case 2: attribute = "Agility"; health = 550; mp = 200; armourVal = 6; break; case 3: attribute = "Intelligence"; health = 450; mp = 450; armourVal = 1; break; default: cout << "Choice invalid, please try again."; exit = 1; break; hero player; player.setBasics(heroName, attribute, health, mp, armourVal); player.setAttkData(attribute); heroCreated=1; system("cls"); cout << "Your hero has been created!\n\n"; player.dumpData(); system("pause"); break; } case 2: system("cls"); if (heroCreated == 1) { cout << "Your hero has been detailed below.\n\n"; **player.dumpData(); //ERROR OCCURS HERE !** system("pause"); } else { cout << "You have not created a hero please exit this prompt " "and press 1 on the menu to create a hero."; } break; case 3: system("cls"); cout << "Still Under Development"; system("pause"); break; case 4: system("cls"); exit = 1; break; default: cout << "Your command has not been recognised, please try again.\n"; system("pause"); break; } } while (exit != 1); system("pause"); return 0; } void dispMenu() { system("cls"); cout << "1. Create New Hero\n" "2. View Current Hero\n" "3. Fight Stuff\n" "4. Exit\n\n" "Enter your choice: "; } However upon compilation I get the following errors: 220 `player' undeclared (first use this function) Unsure exactly how to fix it as I've only recently started using OO approach. The error has a comment next to it above and is in case 2 in the main. Cheers guys.

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  • Django models & Python class attributes

    - by Geo
    The tutorial on the django website shows this code for the models: from django.db import models class Poll(models.Model): question = models.CharField(max_length=200) pub_date = models.DateTimeField('date published') class Choice(models.Model): poll = models.ForeignKey(Poll) choice = models.CharField(max_length=200) votes = models.IntegerField() Now, each of those attribute, is a class attribute, right? So, the same attribute should be shared by all instances of the class. A bit later, they present this code: class Poll(models.Model): # ... def __unicode__(self): return self.question class Choice(models.Model): # ... def __unicode__(self): return self.choice How did they turn from class attributes into instance attributes? Did I get class attributes wrong?

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  • Possible to set two values for two different nodes from user input in XForms?

    - by iHeartGreek
    Hi! I would like to set two values for two different nodes from user input in XForms. I am curious about how this is done, if at all possible. For example, if I have the following data model: <xf:instance id="criteria_data" xmlns=""> <criteria> <set> <root></root> <criterion></criterion> </set> </criteria> </xf:instance> <xf:instance id="choices" xmlns=""> <choices> <root label="The Choices">/AAA</root> <choice label="BBB">/@BBB</choice> </choices> </xf:instance> <xf:instance id="choices" xmlns=""> <choices> <root>/AAA</root> <choice label="BBB">/@BBB</choice> <choice label="CCC">/@CCC</choice> <choices> </xf:instance> <xf:bind id="data_criterion" nodeset="instance('criteria_data')/criteria/set/criterion"/> <xf:bind id="data_root" nodeset="instance('criteria_data')/criteria/set/root"/> <xf:bind id="choices_root" nodeset="instance('choices')/root"/> <xf:bind id="choices" nodeset="instance('choices')/choice"/> and my ui code looks like: <xf:select bind="data_criterion" appearance="full"> <xf:label>Your choices:</xf:label> <xf:itemset bind="choices"> <xf:label ref="@label"></xf:label> <xf:value ref="."></xf:value> </xf:itemset> </xf:select> But I essentially want it to be like this (though this is invalid and does not produce any xml at all): <xf:select appearance="full"> <xf:label>Your choices:</xf:label> <xf:itemset bind="choices"> <xf:label ref="@label"></xf:label> <xf:value bind="data_criterion" ref="."></xf:value> <xf:value bind="data_root" ref="instance('choices')/root"></xf:value> </xf:itemset> </xf:select> The XML output I want to achieve (if user checks "BBB"): <criteria> <set> <root>/AAA</root> <criterion>/@BBB</criterion> </set> </criteria> How can I achieve setting these two nodes for the one checkbox seletion? Hope that all made sense... Thanks! :)

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  • Inorder tree traversal in binary tree in C

    - by srk
    In the below code, I'am creating a binary tree using insert function and trying to display the inserted elements using inorder function which follows the logic of In-order traversal.When I run it, numbers are getting inserted but when I try the inorder function( input 3), the program continues for next input without displaying anything. I guess there might be a logical error.Please help me clear it. Thanks in advance... #include<stdio.h> #include<stdlib.h> int i; typedef struct ll { int data; struct ll *left; struct ll *right; } node; node *root1=NULL; // the root node void insert(node *root,int n) { if(root==NULL) //for the first(root) node { root=(node *)malloc(sizeof(node)); root->data=n; root->right=NULL; root->left=NULL; } else { if(n<(root->data)) { root->left=(node *)malloc(sizeof(node)); insert(root->left,n); } else if(n>(root->data)) { root->right=(node *)malloc(sizeof(node)); insert(root->right,n); } else { root->data=n; } } } void inorder(node *root) { if(root!=NULL) { inorder(root->left); printf("%d ",root->data); inorder(root->right); } } main() { int n,choice=1; while(choice!=0) { printf("Enter choice--- 1 for insert, 3 for inorder and 0 for exit\n"); scanf("%d",&choice); switch(choice) { case 1: printf("Enter number to be inserted\n"); scanf("%d",&n); insert(root1,n); break; case 3: inorder(root1); break; default: break; } } }

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  • An error saying unidentifed function "push", "pop", and"display" occurs, what should i add to fix i

    - by Alesha Aris
    #include<stdio.h> #include<iostream.h> #include<conio.h> #include<stdlib.h>(TOP) #include<fstream.h> #define MAX 5 int top = -1; int stack_arr[MAX]; main() { int choice; while(1) { printf("1.Push\n"); printf("2.Pop\n"); printf("3.Display\n"); printf("4.Quit\n"); printf("Enter your choice : "); scanf("%d",&choice); switch(choice) { case 1 : push(); break; case 2: pop(); break; case 3: display(); break; case 4: exit(1); default: printf("Wrong choice\n"); }/*End of switch*/ }/*End of while*/ }/*End of main()*/ push() { int pushed_item; if(top == (MAX-1)) printf("Stack Overflow\n"); else { printf("Enter the item to be pushed in stack : "); scanf("%d",&pushed_item); top=top+1; stack_arr[top] = pushed_item; } }/*End of push()*/ pop() { if(top == -1) printf("Stack Underflow\n"); else { printf("Popped element is : %d\n",stack_arr[top]); top=top-1; } }/*End of pop()*/ display() { int i; if(top == -1) printf("Stack is empty\n"); else { printf("Stack elements :\n"); for(i = top; i >=0; i--) printf("%d\n", stack_arr[i] ); } }/*End of display()*/

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