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  • Tile-wide extent tracing on a grid.

    - by Larolaro
    I'm currently working on A* pathfinding on a grid and I'm looking to smooth the generated path, while also considering the extent of the character moving along it. I'm using a grid for the pathfinding, however character movement is free roaming, not strict tile to tile movement. To achieve a smoother, more efficient path, I'm doing line traces on a grid to determine if there is unwalkable tiles between tiles to shave off unecessary corners. However, because a line trace is zero extent, it doesn't consider the extent of the character and gives bad results (not returning unwalkable tiles just missed by the line, causing unwanted collisions). So what I'm looking for is rather than a line algorithm that determines the tiles under it, I'm looking for one that determines the tiles under a tile-wide extent line. Here is an image to help visualise my problem! Does anyone have any ideas? I've been working with Bresenham's line and other alternatives but I haven't yet figured out how to nail this specific problem.

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  • Aberdeen 10/25 Webcast: Service Excellence and the Path to Business Transformation

    - by Charles Knapp
    The uncertain economy has had a sustained impact on service organizations and processes. The impact has contributed to new complexities - new customer engagement channels, enhanced user and customer expectations, rapidly evolving technologies, increased competition, and increased compliance and regulatory mandates. Yet many organizations have embraced these challenges by investing in and transforming customer service to evolve, differentiate, and thrive under current constraints. What is their secret? Transforming Support Centers into Profit Centers According to the recent Aberdeen research report, “Service Excellence and the Path to Business Transformation”, service is now viewed as a strategic profit center at nearly 70% of organizations. As customers demand improved service, in terms of speed, efficiency and reliability, an organization's success has become increasingly dependent on optimizing the customer ownership experience. Those service organizations focused on providing easy, consistent, and relevant interactions across the customer lifecycle, including service and support delivery, are experiencing higher levels of customer acquisition and retention and are achieving better revenue and margin growth rates.  Don't miss this opportunity to learn how to transform to provide the next generation of service offerings. Click here to register now for the webcast and download a complimentary copy of this informative new research paper.

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  • Commands don't have permission when using absplute path

    - by Markos
    I have folders set up this way: /srv/samba/video getfacl /srv/samba/video # file: srv/samba/video # owner: root # group: nogroup user::rwx group::--- group:sambaclients:rwx group:deluge:rwx mask::rwx other::--- default:user::rwx default:group::--- default:group:sambaclients:rwx default:group:deluge:rwx default:mask::rwx default:other::--- That means, user deluge has rwx to folder /srv/samba/video. However, when running command as user deluge, I am getting weird permission errors. When in folder /srv/samba/video: sudo -u deluge mkdir foo works flawlessly. But when using absolute path: sudo -u deluge mkdir /srv/samba/video/foo I am getting permission denied. When running sudo -u deluge id, I get output uid=113(deluge) gid=124(deluge) skupiny=124(deluge) which shows that user deluge is indeed in group deluge. Also, the behavior was the same when I gave the permissions also to user deluge not just group deluge. When executing as non-system user, it does work. The reason that I want to use absolute paths is that I am using automatically triggered post-download script which extracts some files into the folder. I have spent way too many hours to solve this problem myself. mkdir isn't the only command that fails, touch is doing the same thing, so I suspect that it's not mkdir's fault. If you need more info, I will try to put it in here, just ask. Thanx in advance.

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  • How to setup Java-Home and Path in Ubuntu 12.04

    - by ur truly friend
    we are new to Ubuntu.Recently we changed my server OS to ubuntu 12.04 from windows 7 . every one have their own login details. one of my college installed Open-Jdk7. I asked him, where you installed JAVA, then he suggested to switch the following directory su root cd /usr/lib/Jvm Totally 3 folders are there in JVM folder. names are. java-1.7.0-openjdk-amd64 java-7-openjdk-amd64 java-7-openjdk-common generally, If you install Java in Windows, we will get 2 folder. 1 folder is for JDKand another points to JRE. but, in Ubuntu we have 3 folders. is it right? for my conformation, whether he installed correctly or not. I open Terminal. I run the following 2 commands javac java -version both commands are working fine. now I want to set-up Java-Home and Path for all users at same place.because everyone is working on Application server. Can anyone explain step-by-step. Thanks.

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  • How to make natural-looking paths with A* on a grid?

    - by user11177
    I've been reading this: http://theory.stanford.edu/~amitp/GameProgramming/Heuristics.html But there are some things I don't understand, for example the article says to use something like this for pathfinding with diagonal movement: function heuristic(node) = dx = abs(node.x - goal.x) dy = abs(node.y - goal.y) return D * max(dx, dy) I don't know how do set D to get a natural looking path like in the article, I set D to the lowest cost between adjacent squares like it said, and I don't know what they meant by the stuff about the heuristic should be 4*D, that does not seem to change any thing. This is my heuristic function and move function: def heuristic(self, node, goal): D = 10 dx = abs(node.x - goal.x) dy = abs(node.y - goal.y) return D * max(dx, dy) def move_cost(self, current, node): cross = abs(current.x - node.x) == 1 and abs(current.y - node.y) == 1 return 19 if cross else 10 Result: The smooth sailing path we want to happen: The rest of my code: http://pastebin.com/TL2cEkeX

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  • Getting the relative path to the rdlc report in my winform app.

    - by Mike Wills
    I am automatically creating a PDF from some of our reports in a month-end process. I am running into a problem where ReportViewer.LocalReport can't find my report. Within the project, the report files are in "(project root folder)/Reports/report.rdlc". How do I set ReportViewer.LocalReport.ReportPath so I can reference my report file? I would rather not set the full path because I don't know where it would be installed when installed on the client machines.

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  • How to retrieve video thumbnail from an absolute path?

    - by steff
    Hi everyone, I know this has to be trivial but I just don't find the right resource, I guess. So all I want to do is retrieving a thumbnail for a video. All I have is the absolute path to the file on the sdcard as a String. So please point me into the right direction. And believe me, this is embarrassing enough to ask... Regards, Steff

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  • What path for wkhtmltoimage for Windows and local server?

    - by user1697061
    I am running rails on a local server on windows. I installed wkhtmltoimage to C:/Sites/wkhtmltoimage Now I have to tell IMGKit where to find it, so I added a file initializers/imgkit.rb: IMGKit.configure do |config| config.wkhtmltoimage = 'C:/Sites/wkhtmltoimage' end But When I try to use IMGKit, rails tells me: No wkhtmltoimage executable found at /usr/local/bin/wkhtmltoimage But I set up a new path for it ? What do I have to do now ? Please help.

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  • Visual Studio Question: How to go to a specific file path and line number programmatically?

    - by Jack
    In the Visual Studio output window, you can double click a line that contains a file path and line number and it automatically takes you to that location. In my program, I need to mimic this behavior and be able to click something (a button for example) and do go to a specific file and line number that I tell it to go to. Any help/suggestions would be appreciated. I am working in C#.

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  • Directory.GetFiles returning entire path, I only want the filename?

    - by blerh
    This is the code I have set up to scan a directory of files: Dim fileArray() As String fileArray = Directory.GetFiles(System.AppDomain.CurrentDomain.BaseDirectory & "help\") And it successfully gets all files in the directory, but it gets their absolute paths aswell. For example, one of the entries in fileArray() is: F:\Project\Project\bin\x86\Debug\help\book_troubleshoot.html And I want it to just be: book_troubleshoot.html Is there a way to do this without parsing through all the array entries to trim off the path? Thanks.

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  • How to find out or where to specify path of the JavaEE project?

    - by Milan
    I develop Java EEapplication and I have to create some files in the src folder in the my application. But I dont where or how to specify the path. I want my application to be portable. It means just to say TestProject/src/.... and not C:/bla/bla/TestProject/src/... do we specify this in some app file like web.inf, meta-inf or its just some trick. Thanks!

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  • Problem registering a COM server written for Excel registered on client machine (can't set full path

    - by toytrains
    In this previous question <How to get COM Server for Excel written in VB.NET installed and registered in Automation Servers list? there is an example of how to create the full path to a registry key using VS 2008. Everything in the previous answer works correctly except the full path that I am setting (using the registry editor in VS) for mscoree.dll is not working (meaning it seems to do nothing). The full registry path is: HKEY_CLASSES_ROOT\CLSID{my_GUID}\InprocServer32(default) and the value I am setting is: [SystemFolder]mscoree.dll I can put anything (including hardcoding the full path) but the setting does not seem to matter and the registry always contains mscoree.dll without any path. I have tried adding another value to the registry path via VS and that works correctly including having the full path as specified by [SystemFolder]. The reason I need the full path (as explained in the previous question) is that without the path, Excel generates an error when the automation server is selected as it cannot find mscoree.dll (interestingly even though I receive an error the registration works OK). I am doing the install via a setup project which otherwise works fine. I am installing on a VISTA*64 system but have gotten the same error on other OS's. Does anyone know what I am doing wrong?

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  • boost::filesystem - how to create a boost path from a windows path string on posix plattforms?

    - by VolkA
    I'm reading path names from a database which are stored as relative paths in Windows format, and try to create a boost::filesystem::path from them on a Unix system. What happens is that the constructor call interprets the whole string as the filename. I need the path to be converted to a correct Posix path as it will be used locally. I didn't find any conversion functions in the boost::filesystem reference, nor through google. Am I just blind, is there an obvious solution? If not, how would you do this? Example: std::string win_path("foo\\bar\\asdf.xml"); std::string posix_path("foo/bar/asdf.xml"); // loops just once, as part is the whole win_path interpreted as a filename boost::filesystem::path boost_path(win_path); BOOST_FOREACH(boost::filesystem::path part, boost_path) { std::cout << part << std::endl; } // prints each path component separately boost::filesystem::path boost_path_posix(posix_path); BOOST_FOREACH(boost::filesystem::path part, boost_path_posix) { std::cout << part << std::endl; }

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  • Get filename from path

    - by Eric
    I am trying to parse the filename from paths. I have this: my $filepath = "/Users/Eric/Documents/foldername/filename.pdf"; $filepath =~ m/^.*\\(.*[.].*)$/; print "Linux path:"; print $1 . "\n\n"; print "-------\n"; my $filepath = "c:\\Windows\eric\filename.pdf"; $filepath =~ m/^.*\\(.*[.].*)$/; print "Windows path:"; print $1 . "\n\n"; print "-------\n"; my $filepath = "filename.pdf"; $filepath =~ m/^.*\\(.*[.].*)$/; print "Without path:"; print $1 . "\n\n"; print "-------\n"; But that returns: Linux path: ------- Windows path:Windowsic ilename.pdf ------- Without path:Windowsic ilename.pdf ------- I am expecting this: Linux path: filename.pdf ------- Windows path: filename.pdf ------- Without path: filename.pdf ------- Can somebody please point out what I am doing wrong? Thanks! :)

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  • How To Disconnect Non-Mapped UNC Path “Drives” in Windows

    - by The Geek
    Have you ever browsed over to another PC on your network using “network neighborhood”, and then connected to one of the file shares? Without a drive letter, how do you disconnect yourself once you’ve done so? Really confused as to what I’m talking about? Let’s walk through the process. First, imagine that you browse through and connect to a share, entering your username and password to gain access. The problem is that you stay connected, and there’s no visible way to disconnect yourself. If you try and shut down the other PC, you’ll receive a message that users are still connected. So let’s disconnect! Open up a command prompt, and then type in the following: net use This will give you a list of the connected drives, including the ones that aren’t actually mapped to a drive letter. To disconnect one of the connections, you can use the following command: net use /delete \\server\sharename For example, in this instance we’d disconnect like so: net use /delete \\192.168.1.205\root$ Now when you run the “net use” command again, you’ll see that you’ve been properly disconnected. If you wanted to actually connect to a share without mapping a drive letter, you can do the following: net use /user:Username \\server\sharename Password You could then just pop \\server\sharename into a Windows Explorer window and browse the files that way. Note that this technique should work exactly the same in any version of windows. Similar Articles Productive Geek Tips Remove "Map Network Drive" Menu Item from Windows Vista or XPDisable the Annoying "This page has an unspecified potential security risk" When Using Files on a Network ShareCopy Path of a File to the Clipboard in Windows 7 or VistaMap a Network Drive from XP to Windows 7Defrag Multiple Hard Drives At Once In Windows TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Enable DreamScene in Windows 7 Microsoft’s “How Do I ?” Videos Home Networks – How do they look like & the problems they cause Check Your IMAP Mail Offline In Thunderbird Follow Finder Finds You Twitter Users To Follow Combine MP3 Files Easily

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  • Spotlight on a career path: Paul, Business Development Consultant

    - by Maria Sandu
    I came to work for Oracle in November 2012 as a Customer Intelligence Representative and since then I was promoted to a Business Development Consultant, for Commercial Industries in the UK, based in Dublin. My background was primarily in Logistics, working for such companies as Indaver Ireland, Wincanton and P&O. I spent 10 years working in this industry and gained experience in negotiating with customers and suppliers in order to meet the needs of both, monitoring the quality and quantity of goods as well as the efficiency and organisation of the movement and storage of products. I decided to move from my logistics career in 2009 to study Information Technology in D.I.T. This was a challenge for me to move my career path; however the lectures at the college helped me significantly with the ability to understand how IT can have an effect on how businesses operate. Following on from college I came to work for Oracle. This also presented challenges but the training I received and the encouragement from management helped me understand that the same business rules apply no matter what background you come from. I have also learnt that using my past experience in working with customers and suppliers in Logistics has helped me understand how to meet customer’s needs. Oracle has offered me excellent training such as Sandler Sales Techniques and John Costigan. I continue to get all the training that I need to develop my career. If you’re interested in joining the Business Development Group visit http://bit.ly/oracledirectcareers or follow our CareersatOracle Facebook Community! /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin-top:0in; mso-para-margin-right:0in; mso-para-margin-bottom:10.0pt; mso-para-margin-left:0in; line-height:115%; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;}

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  • Inkscape: what are "line" objects?

    - by Peter Mortensen
    What is a "line" object in Inkscape? Drawing lines in Inkscape is by using the tool "Draw Bezier curves and straight lines (Shift+F6)". This creates objects of another type, "path". Using Inkscape: is there a way to convert an object of type "line" into an object of the more general type "path"? I have imported a drawing (mostly lines, rectangles and text) that has been through Adobe Illustrator: originally made in Inkscape, imported into Illustrator, edited, saved from Illustrator as SVG, imported into Inkscape. Sample from the imported SVG file: <path id="path5855" stroke="#000000" d=" M320.198,275.935" /> <line fill="none" stroke="#000000" x1="348.553" y1="45.097" x2="348.553" y2="185.346" id="line3368" /> Update 1: I have inspected the original XML (SVG) file from 2006 and it does not contain any "line" XML tags. Thus it must be a crime of Adobe Illustrator. When a line is selected in this imported SVG file the bottom panel displays: "Line in root. Click selection to toggle scale/rotation handles.". When a line is selected that was drawn in Inkscape the bottom panel displays: "Path (2 nodes) in Layer 1. Click selection to toggle scale/rotation handles." What is the difference between "line" and "path"? Is "line" some kind of read-only/non-editable object? A generic term like "line" is not easy to use in search, but I have now found the definitions for "line" and "path": SVG line: http://www.w3schools.com/svg/svg_line.asp SVG path: http://www.w3schools.com/svg/svg_path.asp Platform: Inkscape v0.46 (2008-03-10), Windows XP 64 bit, 8 GB RAM.

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  • Finding the shortest path between two points on a grid, using Haskell.

    - by esperantist
    This is a problem that I can easily enough solve in a non-functional manner. But solving it in Haskell is giving me big problems. Me being inexperienced when it comes to functional programming is surely a reason. The problem: I have a 2D field divided into rectangles of equal size. A simple grid. Some rectangles are empty space (and can be passed through) while others are impassable. Given a starting rectangle A and a destination rectangle B, how would I calculate the shortest path between the two? Movement is possible only vertically and horizontally, in steps a single rectangle large. How would I go about accomplishing this in Haskell? Code snippets certainly welcome, but also certainly not neccessary. And links to further resources also very welcome! Thanks!

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  • how to merge multiple url/path into multidimensional array ?

    - by KelNoReem
    I have array like this: $path = array ( [0] => site\projects\terrace_and_balcony\mexico.jpg [1] => site\projects\terrace_and_balcony\new_york.jpg [2] => site\projects\terrace_and_balcony\berlin.jpg [3] => site\projects\terrace_and_balcony\Kentucky.jpg [4] => site\projects\terrace_and_balcony\Utah.jpg [5] => site\projects\terrace_and_balcony\Hawaii.jpg [6] => site\projects\private_gardens\mexico.jpg [7] => site\projects\private_gardens\new_york.jpg [8] => site\projects\private_gardens\berlin.jpg [9] => site\projects\private_gardens\Kentucky.jpg [10] => site\projects\private_gardens\Utah.jpg [11] => site\projects\private_gardens\Hawaii.jpg ) How to convert it to that: $path11 = array ( "site"=>array ( "projects"=>array ( "terrace_and_balcony"=>array ( "mexico.jpg", "new_york.jpg", "berlin.jpg", "Kentucky.jpg", "Utah.jpg", "Hawaii.jpg" ), "private_gardens"=>array ( "mexico.jpg", "new_york.jpg", "berlin.jpg", "Kentucky.jpg", "Utah.jpg", "Hawaii.jpg" ) ) ) );

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