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• Nameserver not resolving or domain not pingable [closed]

  - by Ricky

  Sorry, if anyone can think of a better title please change it! I want to host my own websites from home. For testing purposes, I have a virtual machine running a trial version of Windows Server 2008 Enterprise. Note I currently run a VPS and host my own websites but due to a nice speed upgrade on our line I now want to host from home. I have several domains but I wanted to test with one, that is rickyoleary.com. Our ISP does not provide static IP addresses unless we have a business account so I've been looking at no-ip.com. I admit my networking isn't the best, hence this question but I've been bashing my head all day on this one. I created a host name, muffinbubble.no-ip.org which runs on IP: 86.148.124.15. I've setup IIS on the server with a simple test page. I've then forwarded port 80 traffic from the router and from what I can see, it's working. If I access my website (I was unable to link to this for some reason so please copy and paste this) - http://86.148.124.15/ - I see my test page. So the next step was to create my nameservers. This domain is with namecheap.com so I created my nameservers, ns1.rickyoleary.com and ns2.rickyoleary.com. Both these point to the same IP (and yes, that will be changed after testing), the same IP as above: 86.148.124.15. On the server itself I have set up DNS entries as below which I believe to be correct and added rickyoleary.com and www.rickyoleary.com in the host headers (or bindings) in IIS 7.0. If I try and look up my domain, rickyoleary.com it shows ns1.rickyoleary.com and ns2.rickyoleary.com as the nameservers. I then tried to use just-ping.com on my nameserver ns1.rickyoleary.com. I get 100% packets lost, but the correct IP address is returned (I'm guessing the router does not allow pings, but is still accessible...). I get no response when pinging rickyoleary.com. Here's the problems: I cannot ping ns1.rickyoleary.com or ns2.rickyoleary.com from a command prompt. I'm not sure if this is an issue. When I added the nameservers in Windows Server 2008 and clicked 'resolve' a message box displays stating "No such host is known". I cannot ping rickyoleary.com. rickyoleary.com is not showing my test page on my server. Now - please note, I've waited around 6 hours for propagation. From my experience, although you're told to wait 24 - 48 hours, the changes are normally pretty quick so perhaps I'm being impatient or naive to think it should all be working fine until then. I would really appreciate some help here. Thanks.

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• Ubuntu not booting, recovery mode not loading

  - by TNC

  I have a dual-boot Ubuntu 11.10 and Windows 7 machine setup and last night I had to force shutdown Ubuntu during updates because it wasn't responding. Since then, Ubuntu will not boot up, only flashing a blank lit screen for a split second every couple of seconds. Booting in recovery mode does not help either, as it doesn't load at all. If anyone can help me diagnose what's wrong and figure out what to do, that would be greatly appreciated!

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• In CPanel, cron job is not being executing and not sending any mail

  - by Abhishek

  though many of us has asked many question related to cron jobs, let me ask my one... I want to execute a PHP script periodically. As a cron command I'm using: php -q http://www.example.com/cron.php?action=getA I also tried this one: php -q /home/myuser/www.example.com/cron.php?action=getA It is not getting executed and not sending any mail. I set the mail ID to my gMail ID. What am I doing wrong?

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• Win7 - Chrome: Accelerated rasterization not enabled/not supported

  - by Wozzie

  Win 7 Pro SP1 x64 EVGA Geforce GTX 670 FTW 2gb Geforce Driver: 320.49, it did happen with the previous version of the driver as well Chrome Version 28.0.1500.52 beta-m DirectX: 11 I was looking in chrome://gpu which told me that "Rasterization: Software only. Hardware acceleration disabled." and further down "Accelerated rasterization has not been enabled or is not supported by the current system." Is there a way to enable hardware acceleration?

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• Show Notes: Architects in the Cloud

  - by Bob Rhubart

  Stephen G. Bennett and Archie Reed, the authors of Silver Clouds, Dark Linings: A Concise Guide to Cloud Computing,  discuss what’s new and what’s not so new about cloud computing, talk about how marketing hype has muddied understanding of what cloud is and what it can do, and explore other issues in the latest ArchBeat interview series. Listen to Part 1 Listen to Part 2 (December 22) Listen to Part 3 (December 29) Listen to Part 4 (January 5) Connect If you have questions, comments, or would otherwise like to interact directly with Steve or Archie, you can so through the following channels: Stephen G. Bennett Blog | Twitter | LinkedIn Archie Reed Blog | Twitter | LinkedIn Steve and Archie have also set up a Twitter account and blog specifically for their book: Twitter: @concisecloud Blog: concisecloud.com Of course, the book is available on Amazon: http://amzn.to/silverclouddarklinings Stay tuned: RSS Technorati Tags: oracle,otn,archbeat,cloud computing,podcast,. stephen bennett,archie reed del.icio.us Tags: oracle,otn,archbeat,cloud computing,podcast,. stephen bennett,archie reed

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• Intell SSD + Win 7 after crash can not repair, can not re install

  - by Ori

  I have Lenovo w520, after i bought it i took away old hhd (no longer with me) and replaced it with intel ssd, it worked perfectly for 1 year or so, today my system fr0ze and after waiting for some time i didi hard reset - it wasn't able to boot anymore at all, i do not see any messages from windows ever, it only loads Intel boot utility that suggests to pick one of 3 devices to boot, it has my hdd there but nothing happens. /I dont have recovery tools from lenovo since i moved to another country, i got win 7 cd from a friend (came with his laptop) abd if in bios i have AHCI - it doesnt see my ssd, if compatible mode - it sees it but format not available, partition creation gives b\me 8007045 error. I tried diskpart, in compatible mode it sees my disk but doesnt do recover or clean all, also win 7 disk tools dont do anything if i try to do boot fix... I am ok with erasing it but i seem not to be able too, i jus tneed the machine to wpork asap, all my files are on external drives so i dont care about formatting. please help! I am given a very old machine by a friend so i am able to browse internet... it is under XP...

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• Random "not accessible" "you might not have permission to use this network resource"

  - by Jim Fred

  A couple of computers, both Win7-64 can connect to shares on a NAS server, at least most of the time. At random intervals, these Win7-64 computers cannot access some shares but can access others on the same NAS. When access is denied, a dialog box appears saying "\\myServer\MyShare02 not accessible...you might not have permission to use this network resource..." Other shares, say \\myServer\MyShare01, ARE accessible from the affected computers and yet other computers CAN access the affected shares. Reboots of the affected computers seem to allow the affected computer to connect to the affected shares - but then, getting a cup of coffee seems to help too. When the problem appears, the network seems to be ok e.g. the affected computers can access other shares on the affected server and can ping etc. Also Other computers can access the affected shares. The NAS server is a NetGear ReadyNas Pro. The problem might be on the NAS side such as a resource limitation but since only 2 Win7-64 PCs seem to be affected the most, the problem could be on the PC side - I'm not sure yet. I of course searched for solutions and found several tips addressing initial connection problems (use correct workgroup name, use IP address instead of server name, remove security restrictions etc) but none of those remedies address the random nature of this problem.

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• What does the caret operator in Python do?

  - by Fry

  I ran across the caret operator in python today and trying it out, I got the following output: >>> 8^3 11 >>> 8^4 12 >>> 8^1 9 >>> 8^0 8 >>> 7^1 6 >>> 7^2 5 >>> 7^7 0 >>> 7^8 15 >>> 9^1 8 >>> 16^1 17 >>> 15^1 14 >>> It seems to be based on 8, so I'm guessing some sort of byte operation? I can't seem to find much about this searching sites other than it behaves oddly for floats, does anybody have a link to what this operator does or can you explain it here?

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• Ethernet interface number changed, and old one does not exist, but does not leave IP address

  - by Sagar

  I have a virtual machine with Mandriva 2007.0 (yes, old - unfortunately we do not have a choice here). Anyway, the problem: Before reboot: active network interface = eth0. No other interfaces present, and network manager confirms this. Static IP address set to 172.31.2.22. No issues, everything working properly, routing et al. -------Reboot--------- After reboot: active network interface = eth1, with a DHCP address. Network manager shows eth0 as disconnected, and not connectable. When I try to set eth1 up with the static IP address (same one), it says "In Use". I then tried ifconfig eth0 172.31.2.29 just to free it up from the eth0 interface so I could use it with eth1 (since this is connected). Result: ifconfig eth0 172.31.2.29 SIOCSIFADDR: No such device eth0: unknown interface: No such device Nothing else changed. Any ideas what could be happening, or at least how I can get my IP address back?

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• Conditional Operator in SQL Where Clause

  - by Marc

  I'm wishing I could do something like the following in SQl Server 2005 (which I know isnt valid) for my where clause. Sometimes @teamID (passed into a stored procedure) will be the value of an existing teamID, otherwise it will always be zero and I want all rows from the Team table. I researched using Case and the operator needs to come before or after the entire statement which prevents me from having a different operator based on the value of @teamid. Any suggestions other than duplicating my select statements. declare @teamid int set @teamid = 0 Select Team.teamID From Team case @teamid when 0 then WHERE Team.teamID > 0 else WHERE Team.teamID = @teamid end

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• Can operator= may be not a member?

  - by atch

  Having construction in a form: struct Node { Node():left_(nullptr), right_(nullptr) { } int id_; Node* left_; Node* right_; }; I would like to enable syntax: Node parent; Node child; parent.right_ = child; So in order to do so I need: Node& operator=(Node* left, Node right); but I'm getting msg that operator= has to be a member fnc; Is there any way to circumvent this restriction?

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• Is a switch statement the fastest way to implement operator interpretation in Java

  - by Mordan

  Is a switch statement the fastest way to implement operator interpretation in Java public boolean accept(final int op, int x, int val) { switch (op) { case OP_EQUAL: return x == val; case OP_BIGGER: return x > val; case OP_SMALLER: return x < val; default: return true; } } In this simple example, obviously yes. Now imagine you have 1000 operators. would it still be faster than a class hierarchy? Is there a threshold when a class hierarchy becomes more efficient in speed than a switch statement? (in memory obviously not) abstract class Op { abstract public boolean accept(int x, int val); } And then one class per operator.

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• Apache 2 Symbolic link not allowed or link target not accessible

  - by djechelon

  While the title of this question matches an already asked question, in my case I already set Options +FollowSymLinks. The setup is the following: my hosting setup includes htdocs/ directory that is the default document root for HTTP websites and htdocs-secure that is for HTTPS. They are meant for sites that need a different HTTPS version. In case both share the same files I create a link from htdocs-secure to htdocs by ln -s htdocs htdocs-secure but here comes the problem! Log still says Symbolic link not allowed or link target not accessible: /path/to/htdocs-secure Vhost fragment Header always set Strict-Transport-Security "max-age=500" DocumentRoot /path/to/htdocs-secure <Directory "/path/to/htdocs-secure"> allow from all Options +FollowSymLinks </Directory> I think it's a correct setup. The HTTP version of the site is accessible, so it doesn't look like a permission problem. How to fix this? [Add] other info: I use MPM-itk and I set AssignUserId to the owner/group of both the directories

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• RTL8168B/8111B Lan card is not detected in RHEL5.1..Not finding Linux software that

  - by Deepak Narwal

  Hello friends... In My computer Lan card model is Realtek RTL8168B/8111B PCI-E GIGABIT ETHERNET NIC (NDIS 6.20) My system is dual boot windows 7 and redhat 5.1 Now windows 7 automatically detected this lan card but in redhat lan card is not detected.I have tried to through evrywhere like network or through neat-tui but it is not showing lan card.. I tried google also but all of them providing windows software for this lan card . So please anyone can tell me the link so that i can download drivers for this and can use internet there.. Thanks a lot in advance Deepak Narwal

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• php mail not arrives at gmail, not at local server

  - by thomas

  The php mail function I am using does not work completely. It will sent mails to gmail easy enough. However, emails routed directly to my internally hosted exchange server are not getting through. The servers/domains are setup is as follows. URLs are registered with Network solutions (www.independentsservice.com & www.isco.net) NS directs all traffic to our ISP (Socket.net). Socket directs as follows: Mail to our local server FTP to our local server HTTP to our website hosted on Chihost.com Traffic to our local server goes through a Watchguard firewall which routes mail traffic to our locally hosted Exchange server. Is there some reason why exchange won't accept these emails? Thanks!

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• ^= operator in vb.net (Xor Equals)?

  - by Shimmy

  Is there an equivalent in VB.NET to the C# ^= operator?

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• PHP's Dot Equals `.=` operator in Javascript?

  - by tarnfeld

  How can you use PHP's Dot Equals .= operator in Javascript?

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• subclassing QList and operator+ overloading

  - by Milen

  I would like to be able to add two QList objects. For example: QList<int> b; b.append(10); b.append(20); b.append(30); QList<int> c; c.append(1); c.append(2); c.append(3); QList<int> d; d = b + c; For this reason, I decided to subclass the QList and to overload the operator+. Here is my code: class List : public QList<int> { public: List() : QList<int>() {} // Add QList + QList friend List operator+(const List& a1, const List& a2); }; List operator+(const List& a1, const List& a2) { List myList; myList.append(a1[0] + a2[0]); myList.append(a1[1] + a2[1]); myList.append(a1[2] + a2[2]); return myList; } int main(int argc, char *argv[]) { QCoreApplication a(argc, argv); List b; b.append(10); b.append(20); b.append(30); List c; c.append(1); c.append(2); c.append(3); List d; d = b + c; List::iterator i; for(i = d.begin(); i != d.end(); ++i) qDebug() << *i; return a.exec(); } , the result is correct but I am not sure whether this is a good approach. I would like to ask whether there is better solution?

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• Arrow operator (->) usage in C

  - by Mohit Deshpande

  I am currently learning C by reading a good beginner's book called "Teach Yourself C in 21 Days" (I have already learned Java and C# so I am moving at a much faster pace). I was reading the chapter on pointers and the - (arrow) operator came up without explanation. I think that it is used to call members and functions (like the equivalent of the . (dot) operator, but for pointers instead of members). But I am not entirely sure. Could I please get an explanation and a code sample?

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• friendship and operator overloading help

  - by sil3nt

  hello there, I have the following class #ifndef Container_H #define Container_H #include <iostream> using namespace std; class Container{ friend bool operator==(const Container &rhs,const Container &lhs); public: void display(ostream & out) const; private: int sizeC; // size of Container int capacityC; // capacity of dynamic array int * elements; // pntr to dynamic array }; ostream & operator<< (ostream & out, const Container & aCont); #endif and this source file #include "container.h" /*----------------------------********************************************* note: to test whether capacityC and sizeC are equal, must i add 1 to sizeC? seeing as sizeC starts off with 0?? */ Container::Container(int maxCapacity){ capacityC = maxCapacity; elements = new int [capacityC]; sizeC = 0; } Container::~Container(){ delete [] elements; } Container::Container(const Container & origCont){ //copy constructor? int i = 0; for (i = 0; i<capacityC; i++){ //capacity to be used here? (*this).elements[i] = origCont.elements[i]; } } bool Container::empty() const{ if (sizeC == 0){ return true; }else{ return false; } } void Container::insert(int item, int index){ if ( sizeC == capacityC ){ cout << "\n*** Next: Bye!\n"; return; // ? have return here? } if ( (index >= 0) && (index <= capacityC) ){ elements[index] = item; sizeC++; } if ( (index < 0) && (index > capacityC) ){ cout<<"*** Illegal location to insert--"<< index << ". Container unchanged. ***\n"; }//error here not valid? according to original a3? have i implemented wrong? } void Container::erase(int index){ if ( (index >= 0) && (index <= capacityC) ){ //correct here? legal location? int i = 0; while (i<capacityC){ //correct? elements[index] = elements[index+1]; //check if index increases here. i++; } sizeC=sizeC-1; //correct? updated sizeC? }else{ cout<<"*** Illegal location to be removed--"<< index << ". Container unchanged. ***\n"; } } int Container::size()const{ return sizeC; //correct? } /* bool Container::operator==(const Container &rhs,const Container &lhs){ int equal = 0, i = 0; for (i = 0; i < capacityC ; i++){ if ( rhs.elements[i] == lhs.elements[i] ){ equal++; } } if (equal == sizeC){ return true; }else{ return false; } } ostream & operator<< (ostream & out, const Container & aCont){ int i = 0; for (i = 0; i<sizeC; i++){ out<< aCont.elements[i] << " " << endl; } } */ I dont have the other functions in the header file (just a quikie). Anyways, the last two functions in "/* */" I cant get to work, what am I doing wrong here? the first function is to see whether the two arrays are equal to one another

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• What logic operator to use, as3?

  - by VideoDnd

  What operator or expression can I use that will fire on every number, including zero? I want a logic operator that will fire with ever number it receives. My animations pause at zero. This skips on zero if (numberThing> 0); This skips on 9 if (numberThing>> 0); This jitters 'fires quickly and goes back on count' if (numberThing== 0); EXPLANATION I'm catching split string values in a logic function, and feeding them to a series of IF, ELSE IF statements. I'm using this with a timer, so I can measure the discrepency. CODE • I GET VALUES FROM TIMER • STRING GOES TO TEXTFIELD 'substr' • NUMBER TRIGGERS TWEENS 'parseInt' • Goes to series of IF and ELSE IF statements

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• Perl Hash Slice, Replication x Operator, and sub params

  - by user210757

  Ok, I understand perl hash slices, and the "x" operator in Perl, but can someone explain the following code example from here (slightly simplified)? sub test{ my %hash; @hash{@_} = (undef) x @_; } Example Call to sub: test('one', 'two', 'three'); This line is what throws me: @hash{@_} = (undef) x @_; It is creating a hash where the keys are the parameters to the sub and initializing to undef, so: %hash: 'one' = undef, 'two' = undef, 'three' = undef The rvalue of the x operator should be a number; how is it that @_ is interpreted as the length of the sub's parameter array? I would expect you'd at least have to do this: @hash{@_} = (undef) x length(@_);

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• Adding two different Objects by overloading operator+ C++

  - by lampshade

  Hello, I've been trying to figure out how to add a private member from Object A, to a private member from Object B. Both Cat and Dog Class's inheriate from the base class Animal. I have a thrid class 'MyClass', that I want to inheriate the private members of the Cat and Dog class. So in MyClass, I have a friend function to overload the + operator. THe friend function is defined as follows: MyClass operator+(const Dog &dObj, const Cat &cObj); I want to access dObj.age and cObj.age within the above function, invoke by this statement in main: mObj = dObj + cObj; Here is the entire source for a complete reference into the class objects: #include <iostream> #include <vld.h> using namespace std; class Animal { public : Animal() {}; virtual void eat() = 0 {}; virtual void walk() = 0 {}; }; class Dog : public Animal { public : Dog(const char * name, const char * gender, int age); Dog() : name(NULL), gender(NULL), age(0) {}; virtual ~Dog(); void eat(); void bark(); void walk(); private : char * name; char * gender; int age; }; class Cat : public Animal { public : Cat(const char * name, const char * gender, int age); Cat() : name(NULL), gender(NULL), age(0) {}; virtual ~Cat(); void eat(); void meow(); void walk(); private : char * name; char * gender; int age; }; class MyClass : private Cat, private Dog { public : MyClass() : action(NULL) {}; void setInstance(Animal &newInstance); void doSomething(); friend MyClass operator+(const Dog &dObj, const Cat &cObj); private : Animal * action; }; Cat::Cat(const char * name, const char * gender, int age) : name(new char[strlen(name)+1]), gender(new char[strlen(gender)+1]), age(age) { if (name) { size_t length = strlen(name) +1; strcpy_s(this->name, length, name); } else name = NULL; if (gender) { size_t length = strlen(gender) +1; strcpy_s(this->gender, length, gender); } else gender = NULL; if (age) { this->age = age; } } Cat::~Cat() { delete name; delete gender; age = 0; } void Cat::walk() { cout << name << " is walking now.. " << endl; } void Cat::eat() { cout << name << " is eating now.. " << endl; } void Cat::meow() { cout << name << " says meow.. " << endl; } Dog::Dog(const char * name, const char * gender, int age) : name(new char[strlen(name)+1]), gender(new char[strlen(gender)+1]), age(age) { if (name) { size_t length = strlen(name) +1; strcpy_s(this->name, length, name); } else name = NULL; if (gender) { size_t length = strlen(gender) +1; strcpy_s(this->gender, length, gender); } else gender = NULL; if (age) { this->age = age; } } Dog::~Dog() { delete name; delete gender; age = 0; } void Dog::eat() { cout << name << " is eating now.. " << endl; } void Dog::bark() { cout << name << " says woof.. " << endl; } void Dog::walk() { cout << name << " is walking now.." << endl; } void MyClass::setInstance(Animal &newInstance) { action = &newInstance; } void MyClass::doSomething() { action->walk(); action->eat(); } MyClass operator+(const Dog &dObj, const Cat &cObj) { MyClass A; //dObj.age; //cObj.age; return A; } int main() { MyClass mObj; Dog dObj("B", "Male", 4); Cat cObj("C", "Female", 5); mObj.setInstance(dObj); // set the instance specific to the object. mObj.doSomething(); // something happens based on which object is passed in dObj.bark(); mObj.setInstance(cObj); mObj.doSomething(); cObj.meow(); mObj = dObj + cObj; return 0; }

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• Disallow using comma operator

  - by RiaD

  I never use the comma operator. But sometimes, when I write some recursions, I make a stupid mistake: I forget the function name. That's why the last operand is returned, not the result of a recursion call. Simplified example: int binpow(int a,int b){ if(!b) return 1; if(b&1) return a*binpow(a,b-1); return (a*a,b/2); // comma operator } Is it possible get a compilation error instead of incorrect, hard to debug code?

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• Binary Tree operator overloading and recursion

  - by furious.snail

  I was wondering how to overload the == operator for a binary tree to compare if two trees have identical data at same nodes. So far this is what I have: bool TreeType::operator==(const TreeType& otherTree) const { if((root == NULL) && (otherTree.root == NULL)) return true; //two null trees are equal else if((root != NULL) && (otherTree.root != NULL)) { return((root-info == otherTree.root-info) && //this part doesn't actually do anything recursively... //(root-left == otherTree.root-left) && //(root-right == otherTree.root-right)) } else return false; //one tree is null the other is not } I have a similar function that takes two TreeNode pointers as parameters but I've been stuck on how to convert it to this function.

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