bash: function + source + declare = boom
- by Chen Levy
Here is a problem:
In my bash scripts I want to source several file with some checks, so I have:
if [ -r foo ] ; then
source foo
else
logger -t $0 -p crit "unable to source foo"
exit 1
fi
if [ -r bar ] ; then
source bar
else
logger -t $0 -p crit "unable to source bar"
exit 1
fi
# ... etc ...
Naively I tried to create a function…
