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  • Bootstrap: show/hide column divs with checkbox and change column span

    - by Berto Alvaro
    I'm using Bootstrap 3.2. I'm trying to figure out if there's a way to show/hide a "col-sz-#" div AND change the "col-sz-#" class in visible divs to resize them to fit the container using checkbox style buttons for each column. For example, if I start with <div class="row"> <div class="col-md-2">...</div> <div class="col-md-2">...</div> <div class="col-md-2">...</div> <div class="col-md-2">...</div> <div class="col-md-2">...</div> <div class="col-md-2">...</div> </div> Then if hide 2 of them and the others resize: <div class="row"> <div class="col-md-2 hidden">...</div> <div class="col-md-2 hidden">...</div> <div class="col-md-3">...</div> <div class="col-md-3">...</div> <div class="col-md-3">...</div> <div class="col-md-3">...</div> </div> if the total columns can't divide 12 evenly like 5, then it wouldn't change.

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  • Problem bounding name to a class in Django

    - by martinthenext
    Hello! I've got a view function that has to decide which form to use depending on some conditions. The two forms look like that: class OpenExtraForm(forms.ModelForm): class Meta: model = Extra def __init__(self, *args, **kwargs): super(OpenExtraForm, self).__init__(*args, **kwargs) self.fields['opening_challenge'].label = "lame translation" def clean_opening_challenge(self): challenge = self.cleaned_data['opening_challenge'] if challenge is None: raise forms.ValidationError('??????? ???, ??????????? ?????? ???. ???????????') return challenge class HiddenExtraForm(forms.ModelForm): class Meta: model = Extra exclude = ('opening_challenge') def __init__(self, *args, **kwargs): super(HiddenExtraForm, self).__init__(*args, **kwargs) The view code goes like that: @login_required def manage_extra(request, extra_id=None, hidden=False): if not_admin(request.user): raise Http404 if extra_id is None: # Adding a new extra extra = Extra() if hidden: FormClass = HiddenExtraForm else: FormClass = OpenExtraForm else: # Editing an extra extra = get_object_or_404(Extra, pk=extra_id) if extra.is_hidden(): FromClass = HiddenExtraForm else: FormClass = OpenExtraForm if request.POST: form = FormClass(request.POST, instance=extra) if form.is_valid(): form.save() return HttpResponseRedirect(reverse(view_extra, args=[extra.id])) else: form = FormClass(instance=extra) return render_to_response('form.html', { 'form' : form, }, context_instance=RequestContext(request) ) The problem is somehow if extra.is_hidden() returns True, the statement FromClass = HiddenExtraForm doesn't work. I mean, in all other conditions that are used in the code it works fine: the correct Form classes are intantiated and it all works. But if extra.is_hidden(), the debugger shows that the condition is passed and it goes to the next line and does nothing! As a result I get a UnboundLocalVar error which says FormClass hasn't been asssigned at all. Any ideas on what's happening?

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  • MVC: Submit one form from a page with multiple forms

    - by Rob
    I'm working in an ASP.NET 3.5 MVC application where i've got a view with multiple forms in it. Form 1 contains information about products and will form a shoppingcart with a remove button. Form 2 is as below and is to be used to get the information from the shoppingcart and create an order of it. <% using (Html.BeginForm()) { %> <%=Html.Hidden(Order.ProductId", "E63EF586-F625-4C8D-B82E-E63A6FA4A63C")%> <%=Html.Hidden(Order.Amount", 1)%> <input type="submit" value="Pay" /> <%} % The first form contains a similar beginform with a foreach loop to get the information about the products from the model. When i use the submit button on the second form everything seems to be submitted and the action in the controller for the first form is trying to handle the request. That is where the error occurce because the information in the viewmodel isn't corresponding to what is being expected. The controller which is trying to handle the request: [AcceptVerbs(HttpVerbs.Post)] public ActionResult ShowShoppingcartForm([Bind(Prefix = "Order")] MyViewmodel viewModel) { //.. } The controller which is expected to handle the request: [AcceptVerbs(HttpVerbs.Post)] public ActionResult SaveOrder([Bind(Prefix = "Order")] MyViewmodel viewModel) { throw new NotImplementedException(); }

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  • How can I change the VisualState in a View from the ViewModel?

    - by Decker
    I'm new to WPF and MVVM. I think this is a simple question. My ViewModel is performing an asynch call to obtain data for a DataGrid which is bound to an ObservableCollection in the ViewModel. When the data is loaded, I set the proper ViewModel property and the DataGrid displays the data with no problem. However, I want to introduce a visual cue for the user that the data is loading. So, using Blend, I added this to my markup: <VisualStateManager.VisualStateGroups> <VisualStateGroup x:Name="LoadingStateGroup"> <VisualState x:Name="HistoryLoading"> <Storyboard> <ObjectAnimationUsingKeyFrames Storyboard.TargetProperty="(UIElement.Visibility)" Storyboard.TargetName="HistoryGrid"> <DiscreteObjectKeyFrame KeyTime="0" Value="{x:Static Visibility.Hidden}"/> </ObjectAnimationUsingKeyFrames> </Storyboard> </VisualState> <VisualState x:Name="HistoryLoaded"> <Storyboard> <ObjectAnimationUsingKeyFrames Storyboard.TargetProperty="(UIElement.Visibility)" Storyboard.TargetName="WorkingStackPanel"> <DiscreteObjectKeyFrame KeyTime="0" Value="{x:Static Visibility.Hidden}"/> </ObjectAnimationUsingKeyFrames> </Storyboard> </VisualState> </VisualStateGroup> </VisualStateManager.VisualStateGroups> I think I know how to change the state in my code-behind (something similar to this): VisualStateManager.GoToElementState(LayoutRoot, "HistoryLoaded", true); However, the place where I want to do this is in the I/O completion method of my ViewModel which does not have a reference to it's corresponding View. How would I accomplish this using the MVVM pattern?

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  • django: How to make one form from multiple models containing foreignkeys

    - by Tim
    I am trying to make a form on one page that uses multiple models. The models reference each other. I am having trouble getting the form to validate because I cant figure out how to get the id of two of the models used in the form into the form to validate it. I used a hidden key in the template but I cant figure out how to make it work in the views My code is below: views: def the_view(request, a_id,): if request.method == 'POST': b_form= BForm(request.POST) c_form =CForm(request.POST) print "post" if b_form.is_valid() and c_form.is_valid(): print "valid" b_form.save() c_form.save() return HttpResponseRedirect(reverse('myproj.pro.views.this_page')) else: b_form= BForm() c_form = CForm() b_ide = B.objects.get(pk=request.b_id) id_of_a = A.objects.get(pk=a_id) return render_to_response('myproj/a/c.html', {'b_form':b_form, 'c_form':c_form, 'id_of_a':id_of_a, 'b_id':b_ide }) models class A(models.Model): name = models.CharField(max_length=256, null=True, blank=True) classe = models.CharField(max_length=256, null=True, blank=True) def __str__(self): return self.name class B(models.Model): aid = models.ForeignKey(A, null=True, blank=True) number = models.IntegerField(max_length=1000) other_number = models.IntegerField(max_length=1000) class C(models.Model): bid = models.ForeignKey(B, null=False, blank=False) field_name = models.CharField(max_length=15) field_value = models.CharField(max_length=256, null=True, blank=True) forms from mappamundi.mappa.models import A, B, C class BForm(forms.ModelForm): class Meta: model = B exclude = ('aid',) class CForm(forms.ModelForm): class Meta: model = C exclude = ('bid',) B has a foreign key reference to A, C has a foreign key reference to B. Since the models are related, I want to have the forms for them on one page, 1 submit button. Since I need to fill out fields for the forms for B and C & I dont want to select the id of B from a drop down list, I need to somehow get the id of the B form into the form so it will validate. I have a hidden field in the template, I just need to figure how to do it in the views

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  • Did anyone have this issue with a simple Facebook app or know how to solve it?

    - by Jian Lin
    I have a really simple few lines of Facebook app, using the new Facebook API: <pre> <?php require 'facebook.php'; // Create our Application instance. $facebook = new Facebook(array( 'appId' => '117676584930569', 'secret' => '**********', // hidden here on the post... 'cookie' => true, )); var_dump($facebook); ?> but it is giving me the following output: http://apps.facebook.com/woolaladev/i2.php would give out object(Facebook)#1 (6) { ["appId:protected"]=> string(15) "117676584930569" ["apiSecret:protected"]=> string(32) "**********" <--- just hidden on this post ["session:protected"]=> NULL ["sessionLoaded:protected"]=> bool(false) ["cookieSupport:protected"]=> bool(true) ["baseDomain:protected"]=> string(0) "" } Session is NULL for some reason, but I am logged in and can access my home and profile and run other apps on Facebook (to see that I am logged on). I am following the sample on: http://github.com/facebook/php-sdk/blob/master/examples/example.php http://github.com/facebook/php-sdk/blob/master/src/facebook.php (download using raw URL: wget http://github.com/facebook/php-sdk/raw/master/src/facebook.php ) Trying on both hosting companies at dreamhost.com and netfirms.com, and the results are the same.

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  • DD_belatedPNG.js - how to access the vml object? this is for a PNG image-swap.

    - by akc
    I am trying to use Drew Dillard's awesome DD_belatedPNG fix + jQuery to achieve a run-of-the-mill image-swap on hover -- but with PNGs, and to work on IE6. Example: <a id="thelink" href="blah.html"><img src="f-u-ie6.png" /></a> Since DD's script sets the visibility of the original image to "hidden", you can't effectively hover over it. A lot of people, I have noticed, are thwarted by this limitation. Enough so that Drew mentioned he would try to get a work-around into the next version of his PNG fix. Well, in the meantime, I thought I could get around this by handling the hover event on the image's parent instead. So onmouseover, I would hide the VML object created by DD_belatedPNG while setting a background image on "thelink", and onmouseout, show the VML object again and set the background image to nothing. The following code was just to see if I could access the VML object, but it does not work on the VML. It hides all manner of other children, but not the VML. Any ideas? $(document).ready(function(){ $("thelink").hover(function() { $(this).children().attr({ style: "visibility:hidden" }); }, function() { $(this).children().attr({ style: "visibility:visible" }); }); }); Alternatively, can anyone suggest a great PNG image-swap method? I know that you can swap a background image of a link. But you still need to have something inside the A tag. That's not my case. Also, you could put a transparent GIF in the A tag and have the background image swapped to achieve the effect, but I really don't want to do that. Thanks for your insights!

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  • Hide table rows if Cookie is there

    - by kuswantin
    Based on my previous question here and here, I found that I can set a cookie with javascript. I want to combine it with jquery to have a cookie state set for toggled table rows. I want to keep the hidden rows hidden upon reload. Here is what I have achieved so far: // Load cookies if any if(readCookie('togState')) { $('table#toggle tr.' + readCookie('togState')).hide(); } $(function() { $('table#toggle tr.container').click(function() { var idTog = $(this).attr('id'); $(this).toggleClass('off').nextAll('.' + idTog).toggle(); setCookie('togState', idTog, 30); alert('Cookies: ' + readCookie('togState')); }); }); As you can see the cookie is read, but is not set upon browser refresh. What am I doing wrong? What I want is hide any toggled rows (having their classes equal to their parent's container ID), if the parent container is clicked, and so the cookie is set. Any help would be very much appreciated. Thanks.

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  • In CSS, how to not float a 300px wide Div to the next line?

    - by Jian Lin
    Say, there is a bar that is styled at the bottom of the viewport, using position: fixed; bottom: 0; left: 0; width: 100%; height 50px; overflow: hidden and then there are 4 Divs inside it, each one floated to the left. Each Div is about 300px wide or can be more (depending on the content) Now, when the window is 1200 pixel wide, and we see all 4 Divs, but when the window is resize to be 1180 pixel wide (just 20 pixels less), then the whole 300px wide Div will disappear, because it is "floated" to the next line. So how can this be made so that, the Div will stay there and showing 280px of itself, rather than totally disappear? By the way, white-space: nowrap won't work as that probably has to do with not wrapping inline content. I was thinking of putting another Div inside this Div, having a fixed width of 1200px or 2000px, so that all Divs will float on the same level in this inner Div, and the outer Div will cut it off with the overflow: hidden. But this seems more like a hack... since the wide of all those Divs can be dynamic, and setting a fixed width of 1200px or 2000px seems like too much of a hack.

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  • Expanding DIV slides behind DIV beneath it...

    - by Paddy
    I'm not sure that I'm going to get an answer here, as I'd need to post a lot of CSS and html to get a working recreation, however... I have structure something like this: <fieldset> <legend>Test A</legend> <h3>Test A</h3> <p> Something here. </p> <div style="display:hidden;">I'm dynamically displayed</div> </fieldset> <fieldset> <legend>Test B</legend> <h3>Test B</h3> <p> Something B here. </p> </fieldset> I have code that toggles the display of my hidden div using jQuery and .show(). This works fine in IE8, firefox and Safari, but when I stick IE8 into compatibility mode, then the first fieldset (Test A) will expand, but the expansion happens behind the second fieldset, which doesn't move (i.e. it slides down behind it). I have quite a bit of CSS in use here, and I'm going to have to go back and unpick the whold lot, which isn't a fun idea. If anybody has any idea of one of the IE7 rendering issues that might be affecting this, then I'd very much appreciate it. (note that there is more to the content in these fieldsets than shown, including floated divs). Quick note - if I stick IE7 into quirks mode, it works (but wrecks the rest of my layout) - in standards mode, I get the above behaviour.

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  • pass other form elements to ajax suggestion box script

    - by Alex Calder
    I paid somebody to build me a jQuery AJAX suggestion box script a while back. It works great. Now I'm trying to learn about it enough to modify it to do something different. Right now, the script that generates the suggestions just takes the query text and does the same check every time. Now, I want to be able to pass along additional info so different things are looked for with each instance of a search box. The HTML... simple, obvious. input class="suggest" name="q" type="text" autocomplete="off" / The jQuery looks like this: jQuery(document).ready(function() { $('.suggest').autocomplete( { source:'output.php', minLength:3, focus: function (event, ui) { $(event.target).val(ui.item.label); return false; } } ); [snip] } Instead of: source:'output.php', minLength:3, I'd like: source:'output.php?arg1=blah1&arg2=blah2', minLength:3, where arg1 and arg2 are passed along in the form... input class="suggest" name="q" type="text" autocomplete="off" / input type="hidden" name="arg1" value="blah1" input type="hidden" name="arg2" value="blah2" Does this make sense? Thanks guys. I know just about "this much" about OOL's and javascript, so I'm learning... Alex

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  • Same jQuery code returns two different results – Submit Button Text

    - by Lijo
    I have two jQuery codes - http://jsfiddle.net/Lijo/CXGX7/7/ and http://jsfiddle.net/Lijo/CXGX7/8/ . The first code returns undefined whereas the second code returns text of button. QUESTIONS What is the reason for this difference in result? Why is the first code not returning expected text of button? Note: I verified that both are using same version of jQuery (by an alert of jQuery) alert($.fn.jquery); CODE <html xmlns="http://www.w3.org/1999/xhtml"> <head><title> </title> <script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jquery/jquery-1.8.1.js"></script> <script type="text/javascript"> alert($('.myButton').attr("value")); </script> </head> <body> <form method="post" action="Test.aspx" id="form1"> <div class="aspNetHidden"> <input type="hidden" name="__VIEWSTATE" id="__VIEWSTATE" value="/wEPDwULLTE0MDM4MzYxMjNkZMycQvsYQ+GPFsQHoQ8j/8vEo2vQbqkhfgPc60kxXaQO" /> </div> <div class="aspNetHidden"> <input type="hidden" name="__EVENTVALIDATION" id="__EVENTVALIDATION" value="/wEWAwKqxqqrCgLi/JazDQKM54rGBqgaroRQTXJkD1LyUlVxAmLRCNfTGVe73swQBMemBtvN" /> </div> <div> <input name="txtEmpName" type="text" id="txtEmpName" /> <input type="submit" name="Button1" value="Submit" id="Button1" class="myButton" /> </div> </form> </body> </html> REFERENCES Retrieve Button value with jQuery How to determine and print jQuery version?

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  • PHP self form validation

    - by Jordan Pagaduan
    <?php function VerifyForm(&$values, &$errors) { if (strlen($values['fname']) == 0) $errors['fname'] = 'Enter First Name'; if (strlen($values['lname']) == 0) $errors['lname'] = 'Enter Last Name'; if (strlen($values['mname']) == 0) $errors['mname'] = 'Enter Middle Name'; if (strlen($values['address']) == 0) $errors['address'] = 'Enter Address'; if (strlen($values['terms']) == 0) $errors['terms'] = 'Please Read Terms and Agreement and Check the box.'; if (!ereg('.*@.*\..{2,4}', $values['email'])) $errors['email'] = 'Email address invalid'; else if (strlen($values['email']) < 0) $errors['email'] = 'Enter Email Address'; return (count($errors) == 0); } function DisplayForm($values, $errors) { ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>GIA Soap » Products » Customer Informations</title> <link href="stylesheet/style.css" rel="stylesheet" type="text/css" /> <script type="text/javascript" src="js_files/jquery.js"></script> <script type="text/javascript" src="js_files/sliding_effect.js"></script> <script type="text/javascript" src="js_files/slideshow.js"></script> </head> <body> <div class="bg_top"> <div class="bg_bottom"> <div class="wrapper"> <div class="header"> <div class="logo"> </div> <div class="logo_text"> <div class="logo_head_text">Gia Soap Making</div> <div class="logo_sub_text">Sub text here</div> </div> </div> <div class="h_nav"> <div class="h_nav_dash"> </div> </div> <div class="container"> <div class="content_term"> <div class="content_terms"> <br /> <h1><p>Customer Information</p></h1><br /> <p>Please the following correctly.</p> <div class="customer_info"> <?php if (count($errors) > 0) echo "<p>There were some errors in your submitted form, please correct them and try again.</p>"; ?> <form method="post" action="<?= $_SERVER['PHP_SELF'] ?>"> <!-- hidden values --> <input type="hidden" value="<?php echo $papaya; ?>" name="papaya" /> <input type="hidden" value="<?php echo $carrot; ?>" name="carrot" /> <input type="hidden" value="<?php echo $guava; ?>" name="guava" /> <label for="customer_fname">First Name (<i>Required</i>)</label> <input type="text" class="textbox" id="customer_fname" name="customer_fname" value="<?= htmlentities($values['fname']) ?>" /> <span class="error_msg"><?= $errors['fname'] ?></span> <label for="customer_lname">Last Name (<i>Required</i>)</label> <input type="text" class="textbox" id="customer_fname" name="customer_fname" value="<?= htmlentities($values['lname']) ?>" /> <span class="error_msg"><?= $errors['lname'] ?></span> <label for="customer_mname">Middle Name (<i>Required</i>)</label> <input type="text" class="textbox" id="customer_fname" name="customer_fname" value="<?= htmlentities($values['mname']) ?>" /> <span class="error_msg"><?= $errors['mname'] ?></span> <label for="customer_add">Address (<i>Required : Complete Address Please</i>)</label> <input type="text" class="textbox" id="customer_add" name="customer_add1" value="<?= htmlentities($values['address']) ?>" /><br /> <input type="text" class="textbox" id="customer_add" name="customer_add2" /><br /> <input type="text" class="textbox" id="customer_add" name="customer_add3" /> <span class="error_msg"><?= $errors['address'] ?></span> <label for="customer_email">Email Address (<i>Required</i>)</label> <input type="text" class="textbox" id="customer_email" name="customer_email" value="<?= htmlentities($values['email']) ?>" /> <span class="error_msg"><?= $errors['email'] ?></span> <label for="customer_phone">Phone Number </label> <input type="text" class="textbox" id="customer_phone" name="customer_phone" /> <label for="customer_mobile">Mobile Number </label> <input type="text" class="textbox" id="customer_mobile" name="customer_mobile" /> <br /><br /> <div class="terms"> <center> <h1>Terms and Agreement</h1><br /> <p>Please read the following.</p><br /> </div> <br /> <input type="checkbox" name="terms" value="<?= htmlentities($values['terms']) ?>" /> I Read the Terms and Agreement<br /><br /> <span class="error_msg"><?= $errors['terms'] ?></span> <input type="submit" value="Send Order" class="prod_subbtn" /> </center> </form> </div> </div> </div> <div class="clear"></div> </div> <?php include ('includes/footer.php'); ?> </div> </div> </div> </body> </html> <?php } function ProcessForm($values) { $papaya = $_POST['papaya']; $carrot = $_POST['carrot']; $guava = $_POST['guava']; $fname = $_POST['fname']; $lname = $_POST['lname']; $mname = $_POST['mname']; $address = $_POST['address']; } if ($_SERVER['REQUEST_METHOD'] == 'POST') { $formValues = $_POST; $formErrors = array(); if (!VerifyForm($formValues, $formErrors)) DisplayForm($formValues, $formErrors); else ProcessForm($formValues); } else DisplayForm(null, null); ?> The output is: [link text]1 Problem the value that I put is can be seen by users.

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  • Can this code cause a "500" internal server error ?

    - by Scott B
    A few of my customers are reporting that they are getting "500" Internal Server errors lately. I believe it might be caused by various plugins they are using but each time, the hosting company (multiple hosts) are saying that the htaccess file had to be replaced to fix the issue. I'm submitting the code below from my custom theme because its the only place where I trigger an htaccess write. And I want to be sure that there are no problems here that could cause an issue that might contribute to the 500 errors... if (file_exists(ABSPATH.'/wp-admin/includes/taxonomy.php')) { require_once(ABSPATH.'/wp-admin/includes/taxonomy.php'); if(get_option('permalink_structure') !== "/%postname%/" || get_option('mycustomtheme_permalinks') !=="/%postname%/") { $mycustomtheme_permalinks = get_option('mycustomtheme_permalinks'); require_once(ABSPATH . '/wp-admin/includes/misc.php'); require_once(ABSPATH . '/wp-admin/includes/file.php'); global $wp_rewrite; $wp_rewrite->set_permalink_structure($mycustomtheme_permalinks); $wp_rewrite->flush_rules(); } if(!get_cat_ID('topMenu')){wp_create_category('topMenu');} if(!get_cat_ID('hidden')){wp_create_category('hidden');} if(!get_cat_ID('noads')){wp_create_category('noads');} } if (!is_dir(ABSPATH.'wp-content/uploads')) { mkdir(ABSPATH.'wp-content/uploads'); }

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  • Should I Use Anchor, Button Or Form Submit For "Follow" Feature In Rails

    - by James
    I am developing an application in Rails 3 using a nosql database. I am trying to add a "Follow" feature similar to twitter or github. In terms of markup, I have determined that there are three ways to do this. 1) Use a regular anchor. (Github Uses This Method) <a href="/users/follow?target=Joe">Follow</a> 2) Use a button. (Twitter Uses This Method) <button href="/friendships/create/">Follow</button> 3) Use a form with a submit button. (Has some advantages for me, but I haven't see anyone do it yet.) <form method="post" id="connection_new" class="connection_new" action="/users/follow"> <input type="hidden" value="60d7b563355243796dd8496e17d36329" name="target" id="target"> <input type="submit" value="Follow" name="commit" id="connection_submit"> </form> Since I want to store the user_id in the database and not the username, options 1 and 2 will force me to do a database query to get the actual user_id, whereas option 3 will allow me to store the user_id in a hidden form field so that I don't have to do any database lookups. I can just get the id from the params hash on form submission. I have successfully got each of these methods working, but I would like to know what is the best way to do this. Which way is more semantic, secure, better for spiders, etc...? Is there a reason both twitter and github don't use forms to do this? Any guidance would be appreciated. I am leaning towards using the form method since then I don't have to query the db to get the id of the user, but I am worried that there must be a reason the big guys are just using anchors or buttons for this. I am a newb so go easy on me if I am totally missing something. Thanks!

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  • What are some methods to prevent double posting in a form? (PHP)

    - by jpjp
    I want to prevent users from accidentally posting a comment twice. I use the PRG (post redirect get) method, so that I insert the data on another page then redirect the user back to the page which shows the comment. This allows users to refresh as many times as they want. However this doesn't work when the user goes back and clicks submit again or when they click submit 100 times really fast. I don't want 100 of the same comments. I looked at related questions on SO and found that a token is best. But I am having trouble using it. //makerandomtoken(20) returns a random 20 length char. <form method="post" ... > <input type="text" id="comments" name="comments" class="commentbox" /><br/> <input type="hidden" name="_token" value="<?php echo $token=makerandomtoken(20); ?>" /> <input type="submit" value="submit" name="submit" /> </form> if (isset($_POST['submit']) && !empty($comments)) { $comments= mysqli_real_escape_string($dbc,trim($_POST['comments'])); //how do I make the if-statment to check if the token has been already set once? if ( ____________){ //don't insert comment because already clicked submit } else{ //insert the comment into the database } } So I have the token as a hidden value, but how do I use that to prevent multiple clicking of submit. METHODS: someone suggested using sessions. I would set the random token to $_SESSION['_token'] and check if that session token is equal to the $_POST['_token'], but how do I do that? When I tried, it still doesn't check

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  • pagination and url encoding help

    - by Sufyan
    <?php $name=$_POST['name']; ?> <form method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input type="text" name="name"> <input type="submit" value="GO" name="submit"> </form> <?php include ('db.php'); if(isset($_POST['submit'])) { mysql_query ("INSERT INTO example (name) VALUES('$name')") or die(mysql_error()); } if (!isset($_GET['startrow']) or !is_numeric($_GET['startrow'])) { $startrow = 0; } else { $startrow = (int)$_GET['startrow']; } $query = "SELECT * FROM example ORDER BY id DESC LIMIT $startrow, 20"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ echo "<li>"; echo $row['name'] ." "." <a href= 'like.php?quote=" . urlencode( $row['name'] ) . "'>Click Here</a>"; echo "</li>"; } echo '<a href="'.$_SERVER['PHP_SELF'].'?startrow='.($startrow+10).'">Next</a>'; ?> I want to make my page links hidden , how can i make then hidden so that a user cant edit it. 2nd question, currently i am showing total 10 records on each page and then a next page button , but the next button is keep showing even when there is no more records...! how to remove a next page button when records ended. ?? line number 28 is the link to pages which can be easyily editable by any user, i wnat to make them secure (using ID) and line 35 is n'next' page link , this link should not be appear when number of records ended

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  • Creating a method for wrapping a loaded image in a UIImageView

    - by eco_bach
    I have the following un my applicationDidFinishLaunching method UIImage *image2 = [UIImage imageWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"image2.jpg" ofType:nil]]; view2 = [[UIImageView alloc] initWithImage:image2]; view2.hidden = YES; [containerView addSubview:view2]; I'm simply adding an image to a view. But because I need to add 30-40 images I need to wrap the above in a function (which returns a UIImageView) and then call it from a loop. This is my first attempt at creating the function -(UIImageView)wrapImageInView:(NSString *)imagePath { UIImage *image = [UIImage imageWithContentsOfFile:[[NSBundle mainBundle] pathForResource:imagePath ofType:nil]]; UIImageView *view = [[UIImageView alloc] initWithImage:image]; view.hidden = YES; } And then to invoke it I have the following so far, for simplicity I am only wrapping 3 images //Create an array and add elements to it NSMutableArray *anArray = [[NSMutableArray alloc] init]; [anArray addObject:@"image1.jpg"]; [anArray addObject:@"image2.jpg"]; [anArray addObject:@"image3.jpg"]; //Use a for each loop to iterate through the array for (NSString *s in anArray) { UIImageView *wrappedImgInView=[self wrapImage:s]; [containerView addSubview:wrappedImgInView]; NSLog(s); } //Release the array [anArray release]; I have 2 general questions 1-Is my approach correct?, ie following best practices, for what I am trying to do (load a multiple number of images(jpgs, pngs, etc.) and adding them to a container view) 2-For this to work properly with a large number of images, do I need to keep my array creation separate from my method invocation? Any other suggestions welcome!

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  • MySQL PHP SELECT throwing up an error?

    - by user1909695
    I am trying to make a comment section on my hand made site, using PHP and MySQL. I have got the comments stored in my database, but when I try to SELECT them my site throws up this error, mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 9 in /home/a9210109/public_html/comments.php on line 16 My code so far is below <?php $comment = $_POST['comment']; $mysql_host = ""; $mysql_database = ""; $mysql_user = ""; $mysql_password = ""; mysql_connect($mysql_host,$mysql_user,$mysql_password); @mysql_select_db($mysql_database) or die( "Unable to select database"); $CreateTable = "CREATE TABLE comments (comment VARCHAR(255), time VARCHAR(255));"; mysql_query($CreateTable); $UseComment = "INSERT INTO comments VALUES ('$comment')"; mysql_query($UseComment); $SelectComments = "SELECT * FROM comments"; $comments = mysql_query($SelectComments); $num=mysql_numrows($comments); $variable=mysql_result($comments,$i,"comment"); mysql_close(); ?> <a href="#" onclick="toggle_visibility('hidden');">Show/Hide Comments</a> <?php $i=0; while ($i < $num) { $comment=mysql_result($comments,$i,"comment"); echo "<div id='hidden' style='display:none'><h3>$comment</h3></div>"; $i++; } ?>

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  • Cross-domain data access in JavaScript

    - by vit
    We have an ASP.Net application hosted on our network and exposed to a specific client. This client wants to be able to import data from their own server into our application. The data is retrieved with an HTTP request and is CSV formatted. The problem is that they do not want to expose their server to our network and are requesting the import to be done on the client side (all clients are from the same network as their server). So, what needs to be done is: They request an import page from our server The client script on the page issues a request to their server to get CSV formatted data The data is sent back to our application This is not a challenge when both servers are on the same domain: a simple hidden iframe or something similar will do the trick, but here what I'm getting is a cross-domain "access denied" error. They also refuse to change the data format to return JSON or XML formatted data. What I tried and learned so far is: Hidden iframe -- "access denied" XMLHttpRequest -- behaviour depends on the browser security settings: may work, may work while nagging a user with security warnings, or may not work at all Dynamic script tags -- would have worked if they could have returned data in JSON format IE client data binding -- the same "access denied" error Is there anything else I can try before giving up and saying that it will not be possible without exposing their server to our application, changing their data format or changing their browser security settings? (DNS trick is not an option, by the way).

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  • ASP.NET MVC URL Routing problem

    - by Sadegh
    hi, i have defined a route as below: context.MapRoute("SearchEngineWebSearch", "search/web/{query}/{index}/{size}", new { controller = "search", action = "web", query = "", index = 0, size = 5 }); and action method to handle request match with that: public System.Web.Mvc.ActionResult Web(string query = "", int index = 0, int size = 5) { if (string.IsNullOrEmpty(query)) return RedirectToRoute("SearchEngineBasicSearch"); var search = new Search(); var results = search.PerformSearch(query, index, size); ViewData["Query"] = query; if (results != null && results.Count() > 0) { ViewData["Results"]= results; return View("Web"); } else return View("Not-Found"); } and form to sent parameter to action method: <% using (Html.BeginForm("Web", "Search", FormMethod.Post)) { %> <input name="query" type="text" value="<%: ViewData["Query"]%>" class="search-field" /> <input type="submit" value="Search" class="search-button" /> <input type="hidden" name="index" value="2" /> <input type="hidden" name="size" value="2" /> <%} %> now after click on submit and sending value to action method all route values updated but url values still is equals to first time of sending parameter. for example if i sent for first time request such as http://localhost/search/web/google and for next time http://localhost/search/web/yahoo, query parameter which passed to action method is yahoo but url after postback is http://localhost/search/web/google still! can anybody help me plz? ;)

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  • Conditional execution of EventTriggers in Silverlight 3

    - by Jason
    I'm currently working on the UI of a Silverlight application and need to be able to change the visual state of a control to one of two possible states based on it's current state when handling the same event trigger. For example: I have a control that sits partially in a clipping path, when I click the visible part of the control I want to change the state to "visible" and if I click it again when it is in its "visible" state I want to change to the "hidden" state. Example XAML: <i:Interaction.Triggers> <i:EventTrigger EventName="MouseLeftButtonUp"> <ic:GoToStateAction StateName="Visible"/> <ic:GoToStateAction StateName="Hidden"/> </i:EventTrigger> </i:Interaction.Triggers> Where "i" is "System.Windows.Interactivity;assembly=System.Windows.Interactivity" and "ic" is "Microsoft.Expression.Interactivity.Core;assembly=Microsoft.Expression.Interactions". I'm currently working in Expression Blend 3 and would prefer to have a XAML only solution but am not opposed to coding this if it is completely necessary. I have tried recording a change in the target state name in Blend but this did not work. Any thoughts on this?

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  • Jquery drag /drop and clone

    - by Sajeev
    Hi I need to achive this .. I have a set of droppable items ( basically I am droping designs on a apparel ) and I am dropping a clone.. If I don't like the dropped object (designs) - I want to delete that by doing something like hidden . But I am unable to do that. Please help me.. here is the code var clone; $(document).ready(function(){ $(".items").draggable({helper: 'clone',cursor: 'hand'}); $(".droparea").droppable({ accept: ".items", hoverClass: 'dropareahover', tolerance: 'pointer', drop: function(ev, ui) { var dropElemId = ui.draggable.attr("id"); var dropElem = ui.draggable.html(); clone = $(dropElem).clone(); // clone it and hold onto the jquery object clone.id="newId"; clone.css("position", "absolute"); clone.css("top", ui.absolutePosition.top); clone.css("left", ui.absolutePosition.left); clone.draggable({ containment: 'parent' ,cursor: 'crosshair'}); $(this).append(clone); alert("done dragging "); /lets assume I have a delete button when I click that clone should dissapear so that I can drop another design - but the following code has no effect //and the item is still visible , how to make it dissapear ? $('#newId').css("visibility","hidden"); } }); });

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  • JAVASCRIPT - What am I doing incorrectly?

    - by DarkLightA
    LIVE CODE: http://jsfiddle.net/vy4nY/ I'm following this challenge, but I'm having some issues. I'm trying to make the Email Address box only appear when the checkbox is clicked on. What have I done incorrectly? <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html lang="en"> <head> <title>JavaScript Challenges</title> <style type="text/css"> #emailpara {visibility:hidden;} </style> </head> <body> <form action=""> <fieldset> <legend>Email subscriptions</legend> <p id="subscribepara"> <label> <input type="checkbox" name="subscribe" id="subscribe"> Yes! I would like to receive the occasional newsletter via email. </label> </p> <p id="emailpara"> <label> Email Address: <input type="text" name="email" id="email"> </label> </p> </fieldset> </form> <script type="text/javascript"> document.getElementById('subscribe').onclick = (document.getElementById('subscribe').checked ? (document.getElementById('emailpara').style.visibility = 'visible') : (document.getElementById('emailpara').style.visibility = 'hidden')); </script> </body> </html>

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  • iPhone shooter game bullet physics!

    - by user298261
    Hello, Making a new shooter game here in the vein of "Galaga" (my fav shooter game growing up). Here's the code I have for bullet physics: -(IBAction)shootBullet:(id)sender{ imgBullet.hidden = NO; timer = [NSTimer scheduledTimerWithTimeInterval:0.05 target:self selector:@selector(fireBullet) userInfo:Nil repeats:YES]; } -(void)fireBullet{ imgBullet.center = CGPointMake(imgBullet.center.x + bulletVelocity.x , imgBullet.center.y + bulletVelocity.y); if(imgBullet.center.y <= 0){ imgBullet.hidden = YES; imgBullet.center = self.view.center; [timer invalidate]; } } Anyway, the obvious issue is that once the bullet leaves the screen, its center is being reset, so I'm reusing the same bullet for each press of the "fire" button. Ideally, I would like the user to be able to spam the "fire" button without causing the program to crash. How would I tinker this existing code so that a bullet object would spawn on the button press each time, and then despawn after it exits the screen, or collides with an enemy? Thank you for any assistance you can offer!

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