Search Results

Search found 2636 results on 106 pages for 'friend of kim'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 2/106 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • Earn $10 for each friend you refer to FREE Amazon Mom Account

    - by Gopinath
    If you are looking for options to earn some handful of referral bonuses then here is a great deal from Amazon. You can earn $10 for every friend/family member you refer to join free Amazon Mom trail account. What is Amazon Mom by the way? Amazon Mom is a free membership program created especially for parents and caretakers of small children. It gives free 2 days shipping of products purchased on Amazon.com, 20% discount on diapers, wipes and other baby stuff.  Though the name says Mom, it’s open to any one who has children. It does not matter whether you are father, grand parent, aunty or uncle. You can join the program and avail all the benefits of the program. It costs nothing to join FREE 3 months trail Amazon Mom costs $79/year, but anyone can join FREE 3 months trail and explore it with no cost. At the end of your 3 months trail you may either continue the program by paying the required amount or just opt out of it without any charges. You can learn more details about the Amazon Mom program benefits over here. To earn bonus you need to refer friends to join the free 3 months trail and as soon as they join Amazon will automatically credit $10 bonus to your Amazon.com account. Did you ever make money? Couple of weeks ago I saw this promotion and referred my friends. They loved the program as it gives a lot of discounts on baby diapers, wipes and they immediately joined. Within a 10 days they joined the program, Amazon sent emails to me confirming referral bonus. Here is a screen grab of one such referral email and my Amazon bonus are adding up every day as referrals pulling more people in to this program     How to refer friends and earn bonus? So you are ready to refer your friends and here are the steps to be followed Sign in to your Amazon.com account Go to Amazon Mom Referral page and copy the referral link displayed on screen Start sharing the link with your friends and request them to join the free trail If you own a blog or website, write about the program and let your readers know about it. You can also have a image banner on your website with referral link. Facebook and Twitter are the other two places where you can share the referral links and bring your friends on board. Know the rules and don’t gamble Amazon Mom referral program has few conditions that must be satisfied. Make sure that you read and understand all of them. Final and most important one is not to gamble Amazon! Yes, don’t play tricks like referring yourself or creating fake Amazon Mom accounts  in order to earn money. By gambling you may be able to cheat Amazon for a while, but as soon as Amazon detects the fraud  you will be booted out of their system.  Being on the good side always takes you in right direction and helps you earn money.

    Read the article

  • SQLAuthority News – A Conversation with an Old Friend – Sri Sridharan

    - by pinaldave
    Sri Sridharan is my old friend and we often talk on GTalk. The subject varies from Life in India/USA, movies, musics, and of course SQL. We have our differences when we talk about food or movie but we always agree when we talk about SQL. Yesterday while chatting with him we talked about SQLPASS and the conversation lasted for a long time. Here is the conversation between us on GTalk. I have removed a few of the personal talks and formatted into paragraphs as GTalk often shows stuff out of formatting. Pinal: Sri, Congrats on running for the PASS BoD again. You were so close last year. What made you decide to run again this year? Sri: Thank you Pinal for your leadership in the PASS India Community and all the things you do out there. After coming so close last year, there was no doubt in my mind that I will run again. I was truly humbled by the support I got from the community. Growing up in India for over 25 years, you are brought up in a very competitive part of the world. Right from the pressure of staying in the top of the class from kindergarten to your graduation, the relentless push from your parents about studying and getting good grades (and nothing else matters), you land up essentially living in a pressure cooker. To survive that relentless pressure, you need to have a thick skin, ability to stand up for who you really are , what you want to accomplish and in the process stay true those values. I am striving for a greater cause, to make PASS an organization that can help people with their SQL Server careers, to make PASS relevant to its chapter members, to make PASS an organization that every SQL professional in the world wants to be connected with. Just because I did not get elected or appointed last year does not mean that these causes are not worth fighting. Giving up upon failing the first time is simply not in me. If I did that, what message would I send to those who voted for me? What message would I send to my kids? Pinal: As someone who has such strong roots in India, what can the Indian PASS Community expect from you? Sri: First of all, I think fostering a regional leadership is something PASS must encourage as part of its global growth plan. For PASS global being able to understand all the issues in a region of the world and make sound decisions will be a tough thing to do on a continuous basis. I expect people like you, chapter leaders, regional mentors, MVPs of the region start playing a bigger role in shaping the next generation of PASS. That is something I said in my campaign and I still stand by it. I would like to see growth in the number of chapters in India. The current count does not truly represent the full potential of that region. I was pretty thrilled to see the Bangalore SQLSaturday happen early this year. I would like to see more of SQLSaturday events, at least in the major metro cities. I know the issues in India are very different from the rest of the world. So the formula needs to be tweaked a little for it to work better in India. Once the SQLSaturday model is vetted out, maybe there could be enough justification to have SQLRally India. PASS needs to have a premier SQL event in that region. Going to USA or Europe for that matter is incredibly hard due to VISA issues etc. So this could be a case of where PASS comes closer to where the community is. Pinal: What portfolio would take on if you are elected to the PASS Board? Sri: There are some very strong folks on the PASS Board today. The President discusses the portfolios with the group and makes the final call on the portfolios. I am also a fan of having a team associated with the portfolios. In that case, one person is the primary for a portfolio but secondary on a couple of other portfolios. This way people on the board have a direct vested interest in a few portfolios. Personally, I know I would these portfolios good justice – Chapters, Global Growth and Events (SQLSat, SQLRally). I would try to see if we can get a director to focus on Volunteers.  To me that is very critical for growth in the international regions. Pinal: This is an interesting conversation with you Sri. I know you so long time but this is indeed inspiring to many. India is a big country and we appreciate your thoughts. Sri: Thank you very much for taking time to chat with me today. Cheers. There are pretty strong candidates for SQLPASS Board of Elections this year. I know all of them in person and honestly it is going to be extremely difficult to not to vote for anybody. I am indeed in a crunch right now how to pick one over another. Though the choice is difficult, I encourage you to vote for them. I am extremely confident that the new board of directors will all have the same goal – Better SQL Server Community. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Database, DBA, PostADay, SQL, SQL Authority, SQL PASS, SQL Query, SQL Server, SQL Tips and Tricks, SQLAuthority News, T SQL, Technology

    Read the article

  • How to split the definition of template friend funtion within template class?

    - by ~joke
    The following example compiles fine but I can't figure out how to separate declaration and definition of operator<<() is this particular case. Every time I try to split the definition friend is causing trouble and gcc complains the operator<<() definition must take exactly one argument. #include <iostream> template <typename T> class Test { public: Test(const T& value) : value_(value) {} template <typename STREAM> friend STREAM& operator<<(STREAM& os, const Test<T>& rhs) { os << rhs.value_; return os; } private: T value_; }; int main() { std::cout << Test<int>(5) << std::endl; }

    Read the article

  • Sql Query - Selecting rows where user can be both friend and user

    - by Gublooo
    Hey Sorry the title is not very clear. This is a follow up to my earlier question where one of the members helped me with a query. I have a following friends Table Friend friend_id - primary key user_id user_id_friend status The way the table is populated is - when I send a friend request to John - my userID appears in user_id and Johns userID appears in user_id_friend. Now another scenario is say Mike sends me a friend request - in this case mike's userID will appear in user_id and my userID will appear in user_id_friend So to find all my friends - I need to run a query to find where my userID appears in both user_id column as well as user_id_friend column What I am trying to do now is - when I search for user say John - I want all users Johns listed on my site to show up along with the status of whether they are my friend or not and if they are not - then show a "Add Friend" button. Based on the previous post - I got this query which does part of the job - My example user_id is 1: SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id = u.user_id and f.user_id_friend = 1 where u.name like '%' So this only shows users with whom I am friends where they have sent me request ie my userID appears in user_id_friend. Although I am friends with others (where my userID appears in user_id column) - this query will return that as null To get those I need another query like this SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id_friend = u.user_id and f.user_id = 1 where u.name like '%' So how do I combine these queries to return 1 set of users and what my friendship status with them is. I hope my question is clear Thanks

    Read the article

  • C# internal VS VBNET Friend

    - by Will Marcouiller
    To this SO question: What is the C# equivalent of friend?, I would personally have answered "internal", just like Ja did among the answers! However, Jon Skeet says that there is no direct equivalence of VB Friend in C#. If Jon Skeet says so, I won't be the one telling otherwise! ;P I'm wondering how can the keyword internal (C#) not be the equivalent of Friend (VBNET) when their respective definitions are: Friend VBNET The Friend (Visual Basic) keyword in the declaration statement specifies that the elements can be accessed from within the same assembly, but not from outside the assembly. [...] internal C# Internal: Access is limited to the current assembly. To my understanding, these definitions mean quite the same to me. Then, respectively, when I'm coding in VB.NET, I use the Friend keyword to specify that a class or a property shall be accessible only within the assembly where it is declared. The same in C#, I use the internal keyword to specify the same. Am I doing something or anything wrong from this perspective? What are the refinements I don't get? Might someone please explain how or in what Friend and internal are not direct equivalences? Thanks in advance for any of your answers!

    Read the article

  • Platform Builder: Cloning – the Linker is your Friend

    - by Bruce Eitman
    I was tasked this week with making a minor change to NetMsgBox() behavior. NetMsgBox() is a little function in NETUI that handles MessageBox() for the Network User Interface.  The obvious solution is to clone the entire NETUI directory from Public\Common\Oak\Drivers (see Platform Builder: Clone Public Code for more on cloning). If you haven’t already, take a minute to look in that folder. There are a lot of files in the folder, but I only needed to modify one function in one of those files. There must be a better way. Enter the linker. Instead of cloning the entire folder, here is what I did: Create a new folder in my Platform named NETUI (but the name isn’t important) Copy the C file that I needed to modify to the new folder, in this case netui.c Copy a makefile from one of the other folder (really they are all the same) Run Sysgen_capture Open a build window (see Platform Builder: Build Tools, Opening a Build Window) Change directories to the new folder Run “Sysgen_capture netui” Rename sources.netui to sources Add the C file to sources as SOURCES=netui.c Modify the code Build the code Done That is it, the functions from my new folder now replace the functions from the Public code and link with the rest to create NETUI.dll. There is a catches. If you remove any of the functions from the C file, linking will fail because the remaining functions will be found twice.   Copyright © 2010 – Bruce Eitman All Rights Reserved

    Read the article

  • Solaris 11 pkg fix is my new friend

    - by user12611829
    While putting together some examples of the Solaris 11 Automated Installer (AI), I managed to really mess up my system, to the point where AI was completely unusable. This was my fault as a combination of unfortunate incidents left some remnants that were causing problems, so I tried to clean things up. Unsuccessfully. Perhaps that was a bad idea (OK, it was a terrible idea), but this is Solaris 11 and there are a few more tricks in the sysadmin toolbox. Here's what I did. # rm -rf /install/* # rm -rf /var/ai # installadm create-service -n solaris11-x86 --imagepath /install/solaris11-x86 \ -s [email protected] Warning: Service svc:/network/dns/multicast:default is not online. Installation services will not be advertised via multicast DNS. Creating service from: [email protected] DOWNLOAD PKGS FILES XFER (MB) SPEED Completed 1/1 130/130 264.4/264.4 0B/s PHASE ITEMS Installing new actions 284/284 Updating package state database Done Updating image state Done Creating fast lookup database Done Reading search index Done Updating search index 1/1 Creating i386 service: solaris11-x86 Image path: /install/solaris11-x86 So far so good. Then comes an oops..... setup-service[168]: cd: /var/ai//service/.conf-templ: [No such file or directory] ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ This is where you generally say a few things to yourself, and then promise to quit deleting configuration files and directories when you don't know what you are doing. Then you recall that the new Solaris 11 packaging system has some ability to correct common mistakes (like the one I just made). Let's give it a try. # pkg fix installadm Verifying: pkg://solaris/install/installadm ERROR dir: var/ai Group: 'root (0)' should be 'sys (3)' dir: var/ai/ai-webserver Missing: directory does not exist dir: var/ai/ai-webserver/compatibility-configuration Missing: directory does not exist dir: var/ai/ai-webserver/conf.d Missing: directory does not exist dir: var/ai/image-server Group: 'root (0)' should be 'sys (3)' dir: var/ai/image-server/cgi-bin Missing: directory does not exist dir: var/ai/image-server/images Group: 'root (0)' should be 'sys (3)' dir: var/ai/image-server/logs Missing: directory does not exist dir: var/ai/profile Missing: directory does not exist dir: var/ai/service Group: 'root (0)' should be 'sys (3)' dir: var/ai/service/.conf-templ Missing: directory does not exist dir: var/ai/service/.conf-templ/AI_data Missing: directory does not exist dir: var/ai/service/.conf-templ/AI_files Missing: directory does not exist file: var/ai/ai-webserver/ai-httpd-templ.conf Missing: regular file does not exist file: var/ai/service/.conf-templ/AI.db Missing: regular file does not exist file: var/ai/image-server/cgi-bin/cgi_get_manifest.py Missing: regular file does not exist Created ZFS snapshot: 2012-12-11-21:09:53 Repairing: pkg://solaris/install/installadm Creating Plan (Evaluating mediators): | DOWNLOAD PKGS FILES XFER (MB) SPEED Completed 1/1 3/3 0.0/0.0 0B/s PHASE ITEMS Updating modified actions 16/16 Updating image state Done Creating fast lookup database Done In just a few moments, IPS found the missing files and incorrect ownerships/permissions. Instead of reinstalling the system, or falling back to an earlier Live Upgrade boot environment, I was able to create my AI services and now all is well. # installadm create-service -n solaris11-x86 --imagepath /install/solaris11-x86 \ -s [email protected] Warning: Service svc:/network/dns/multicast:default is not online. Installation services will not be advertised via multicast DNS. Creating service from: [email protected] DOWNLOAD PKGS FILES XFER (MB) SPEED Completed 1/1 130/130 264.4/264.4 0B/s PHASE ITEMS Installing new actions 284/284 Updating package state database Done Updating image state Done Creating fast lookup database Done Reading search index Done Updating search index 1/1 Creating i386 service: solaris11-x86 Image path: /install/solaris11-x86 Refreshing install services Warning: mDNS registry of service solaris11-x86 could not be verified. Creating default-i386 alias Setting the default PXE bootfile(s) in the local DHCP configuration to: bios clients (arch 00:00): default-i386/boot/grub/pxegrub Refreshing install services Warning: mDNS registry of service default-i386 could not be verified. # installadm create-service -n solaris11u1-x86 --imagepath /install/solaris11u1-x86 \ -s [email protected] Warning: Service svc:/network/dns/multicast:default is not online. Installation services will not be advertised via multicast DNS. Creating service from: [email protected] DOWNLOAD PKGS FILES XFER (MB) SPEED Completed 1/1 514/514 292.3/292.3 0B/s PHASE ITEMS Installing new actions 661/661 Updating package state database Done Updating image state Done Creating fast lookup database Done Reading search index Done Updating search index 1/1 Creating i386 service: solaris11u1-x86 Image path: /install/solaris11u1-x86 Refreshing install services Warning: mDNS registry of service solaris11u1-x86 could not be verified. # installadm list Service Name Alias Of Status Arch Image Path ------------ -------- ------ ---- ---------- default-i386 solaris11-x86 on i386 /install/solaris11-x86 solaris11-x86 - on i386 /install/solaris11-x86 solaris11u1-x86 - on i386 /install/solaris11u1-x86 This is way way better than pkgchk -f in Solaris 10. I'm really beginning to like this new IPS packaging system.

    Read the article

  • Is perfectionism a newbie's friend or enemy? [closed]

    - by Akromyk
    Possible Duplicate: Where do you draw the line for your perfectionism? I see that the development community is very focused on doing things the right way and personally I would like to do the same too, however, is it a good or bad idea for a newbie to focus on design principles, design patterns, and commenting code when getting started, or is it better to let creativity run wild and potentially write sloppy code. Where should a newbie draw the line?

    Read the article

  • Why friend overloaded operator is preferred to conversion operator in this case

    - by skydoor
    Hi I have a code like this, I think both the friend overloaded operator and conversion operator have the similar function. However, why does the friend overloaded operator is called in this case? What's the rules? Thanks so much! class A{ double i; public: A(int i):i(i) {} operator double () const { cout<<"conversion operator"<<endl;return i;} // a conversion operator friend bool operator>(int i, A a); // a friend funcion of operator > }; bool operator>(int i, A a ){ cout<<"Friend"<<endl; return i>a.i; } int main() { A aa(1); if (0 > aa){ return 1; } }

    Read the article

  • How to define and use a friend function to a temlate class with the same template?

    - by Narek
    I have written the following code: #include <iostream> using namespace std; template <class T> class AA { T a; public: AA() { a = 7; } friend void print(const AA<T> & z); }; template <class T> void print(const AA<T> & z) { cout<<"Print: "<<z.a<<endl; } void main() { AA<int> a; print<int>(a); } And getting the following error: error C2248: 'AA<T>::a' : cannot access private member declared in class 'AA<T>' 1> with 1> [ 1> T=int 1> ] 1> c:\users\narek\documents\visual studio 2008\projects\aaa\aaa\a.cpp(7) : see declaration of 'AA<T>::a' 1> with 1> [ 1> T=int 1> ] 1> c:\users\narek\documents\visual studio 2008\projects\aaa\aaa\a.cpp(30) : see reference to function template instantiation 'void print<int>(const AA<T> &)' being compiled 1> with 1> [ 1> T=int 1> ] What's wrong?

    Read the article

  • List of social networks which allow developers to find out friend of friends info

    - by Jack
    I have been working on social application development for some time now. I now need to build an application which makes use of friend of friends data. Any info like friend count, interest, location etc. would be helpful. Here's the list I have till now 1) Networks where you can find info about your friend of friends Twitter,Digg 2) Complement Facebook, MySpace, Orkut I am more interested in the latter category. Any help will be appreciated.

    Read the article

  • Friend WithEvents in VB vs private in C#

    - by serhio
    Hello, friends Who knows, why in vb.net WinForm projects the designer by default use the Friend WithEvents attributes and in C# - private ones. By ex, in a form.designer. .cs private Label Label1; .vb Friend WithEvents Label1 as Label; For WithEvents is more or less clear(for using Handles, apparently). But why Friend in VB and private in C#... Thanks.

    Read the article

  • C++ adding friend to a template class in order to typecast

    - by user1835359
    I'm currently reading "Effective C++" and there is a chapter that contains code similiar to this: template <typename T> class Num { public: Num(int n) { ... } }; template <typename T> Num<T> operator*(const Num<T>& lhs, const Num<T>& rhs) { ... } Num<int> n = 5 * Num<int>(10); The book says that this won't work (and indeed it doesn't) because you can't expect the compiler to use implicit typecasting to specialize a template. As a soluting it is suggested to use the "friend" syntax to define the function inside the class. //It works template <typename T> class Num { public: Num(int n) { ... } friend Num operator*(const Num& lhs, const Num& rhs) { ... } }; Num<int> n = 5 * Num<int>(10); And the book suggests to use this friend-declaration thing whenever I need implicit conversion to a template class type. And it all seems to make sense. But why can't I get the same example working with a common function, not an operator? template <typename T> class Num { public: Num(int n) { ... } friend void doFoo(const Num& lhs) { ... } }; doFoo(5); This time the compiler complaints that he can't find any 'doFoo' at all. And if i declare the doFoo outside the class, i get the reasonable mismatched types error. Seems like the "friend ..." part is just being ignored. So is there a problem with my understanding? What is the difference between a function and an operator in this case?

    Read the article

  • Facebook multi-friend-selector + new javascript API = BROKEN ?

    - by Simon_Weaver
    I am using the fb:serverfbml tag to render a multi-friend-selector inside an IFrame. I am using the new javascript API. I have been trying ALL DAY to get it working. When I click on the underlines 'selected' link (to filter by the selected friends) the whole page refreshes and the selected friends disappear. Does the multi-friend-selector just not work with the javascript API? <fb:serverfbml> <script type="text/fbml"> <fb:request-form action="http://apps.facebook.com/rollingrazor/" target="_top" method="POST" invite="true" type="Blah blah blah" content="Blah blah! &lt;fb:req-choice url=&quot;http://apps.facebook.com/rollingrazor/&quot; label=&quot;Let me check my friends&quot; /&gt;"> <fb:multi-friend-selector showborder="false" actiontext="Invite your friends" rows="5" cols="5" bypass="cancel" target="_top" /> </fb:request-form> </script> </fb:serverfbml> <div id="fb-root"></div> <script> window.fbAsyncInit = function () { FB.init({ appId: 'xxxxxxx', status: true, cookie: true, xfbml: true }); }; (function () { var e = document.createElement('script'); e.async = true; e.src = document.location.protocol + '//connect.facebook.net/en_US/all.js'; document.getElementById('fb-root').appendChild(e); } ()); </script> Can someone give me a working example using new javascript API with a multi-friend-selector?

    Read the article

  • software to allow a friend to look on your screen

    - by acidzombie24
    I want a friend of mine to review my code. I have a mic built into my laptop but i can use another software for voice chat. So i would like to have him to either view my screen (taking control might be fine) or show me his screen so he can talk about a specific piece of code. What software is good for this? We both think about security so an MS product (netmeeting? if that still exist on normal msn live installs) or an open source would be preferred. Should be free.

    Read the article

  • Facebook iOS SDK Share Dialog - Sharing on a Friend's Wall

    - by JPK
    Is it possible to use the Facebook iOS SDK Share Dialog to share on a Friend's Wall? I know that it is possible to do this using the Feed Dialog, but that provides the user with a less than optimal experience, and seems to be discouraged by Facebook. It would be fantastic if we could configure the Share Dialog to share with one particular friend. Additionally, is there a way to share with a friend privately (such that it would be sent to Messages)? I have researched pretty extensively and it seems like there is not a way to do either of these things using the iOS SDK - I would just like to confirm that I am not missing something.

    Read the article

  • Why friend function is preferred to member function for operator<<

    - by skydoor
    When you are going to print an object, a friend operator<< is used. Can we use member function for operator<< ? class A { public: void operator<<(ostream& i) { i<<"Member function";} friend ostream& operator<<(ostream& i, A& a) { i<<"operator<<"; return i;} }; int main () { A a; A b; A c; cout<<a<<b<<c<<endl; a<<cout; return 0; } One point is that friend function enable us to use it like this cout<<a<<b<<c What other reasons?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >