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• No me arranca ubuntu 12.04

  - by MAgnum

  Buenos Dias, Tengo un Notebook Intel(R) Atom(TM) CPU N270 1.60GHz Version de la BIOS Intel V1585, tenia un sistema operativo de windows xp e intente instalar ubunto 12.04 por medio de live USB debido a que no tengo la adaptación de CD segui todos los pasos y le di instalar completamente formateando el sistema anterior, terminando la instalacion me salio un problema que no encontraba el sistema de arranque o algo asi el hecho es que me salia algo de SDA donde aparecia el modelo del HDD y como es Hitachi HTS543212L9A300 le di en esa y le di finalizar, pero al reiniciar cuando debe iniciar el sistema operativo se queda en negro y no carga nada =S he intentado volver a arrancar la usb pero no me deja hacer nada se me traba =S. soy principiante en este sistema operativo y quiera saber que solución me pueden decir para sacarme de este embrollo. tampoco me sale nada despues de usar ctrl+alt+F1 =S... Muchas gracias al alma caritativa que me quiera asesorar =D...

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• TCP connection stuck in SYN_RECV state despite ACK received, Linux 2.6.18, embedded, ARM

  - by waynix

  My client cannot connect to my protocol port (TCP) after some network glitches, even though all other protocols (telnet/HTTP/FTP) work fine. netstat shows that my server is listening and tcpdump on the server shows all 3 packets are exchanged: 18:29:16.578964 IP 10.9.59.10.3355 10.9.43.131.5084: S 2602965897:2602965897(0) win 65535 <mss 1460,nop,nop,sackOK> 18:29:16.579107 IP 10.9.43.131.5084 10.9.59.10.3355: S 3464857909:3464857909(0) ack 2602965898 win 5840 <mss 1460,nop,nop,sackOK> 18:29:16.579284 IP 10.9.59.10.3355 10.9.43.131.5084: . ack 1 win 65535 But somehow netstat -t shows the connection still in SYN_RECV, as if the ack is not seen by the TCP state machine. I have to restart my server to get it to work. syncookie is not enabled, and I know from client code behavior and tcpdump that there is no SYN flooding. Help much appreciated.

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• MySQL hangs if connection comes from outside the LAN

  - by Subito

  I have a MySQL Server operating just fine if I access him from his local LAN (192.168.100.0/24). If I try to access hin from another LAN (192.168.113.0/24 in this case) it hangs for a really long time before delivering the result. SHOW PROCESSLIST; shows this process in Sleep, State empty. If I strace -p this process I get the following Output (23512 is the PID of the corresponding mysqld process): Process 23512 attached - interrupt to quit restart_syscall(<... resuming interrupted call ...>) = 1 fcntl(10, F_GETFL) = 0x2 (flags O_RDWR) fcntl(10, F_SETFL, O_RDWR|O_NONBLOCK) = 0 accept(10, {sa_family=AF_INET, sin_port=htons(51696), sin_addr=inet_addr("192.168.113.4")}, [16]) = 33 fcntl(10, F_SETFL, O_RDWR) = 0 rt_sigaction(SIGCHLD, {SIG_DFL, [CHLD], SA_RESTORER|SA_RESTART, 0x7f9ce7ca34f0}, {SIG_DFL, [CHLD], SA_RESTORER|SA_RESTART, 0x7f9ce7ca34f0}, ) = 0 getpeername(33, {sa_family=AF_INET, sin_port=htons(51696), sin_addr=inet_addr("192.168.113.4")}, [16]) = 0 getsockname(33, {sa_family=AF_INET, sin_port=htons(3306), sin_addr=inet_addr("192.168.100.190")}, [16]) = 0 open("/etc/hosts.allow", O_RDONLY) = 64 fstat(64, {st_mode=S_IFREG|0644, st_size=580, ...}) = 0 mmap(NULL, 4096, PROT_READ|PROT_WRITE, MAP_PRIVATE|MAP_ANONYMOUS, -1, 0) = 0x7f9ce9839000 read(64, "# /etc/hosts.allow: list of host"..., 4096) = 580 read(64, "", 4096) = 0 close(64) = 0 munmap(0x7f9ce9839000, 4096) = 0 open("/etc/hosts.deny", O_RDONLY) = 64 fstat(64, {st_mode=S_IFREG|0644, st_size=880, ...}) = 0 mmap(NULL, 4096, PROT_READ|PROT_WRITE, MAP_PRIVATE|MAP_ANONYMOUS, -1, 0) = 0x7f9ce9839000 read(64, "# /etc/hosts.deny: list of hosts"..., 4096) = 880 read(64, "", 4096) = 0 close(64) = 0 munmap(0x7f9ce9839000, 4096) = 0 getsockname(33, {sa_family=AF_INET, sin_port=htons(3306), sin_addr=inet_addr("192.168.100.190")}, [16]) = 0 fcntl(33, F_SETFL, O_RDONLY) = 0 fcntl(33, F_GETFL) = 0x2 (flags O_RDWR) setsockopt(33, SOL_SOCKET, SO_RCVTIMEO, "\36\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0", 16) = 0 setsockopt(33, SOL_SOCKET, SO_SNDTIMEO, "<\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0", 16) = 0 fcntl(33, F_SETFL, O_RDWR|O_NONBLOCK) = 0 setsockopt(33, SOL_IP, IP_TOS, [8], 4) = 0 setsockopt(33, SOL_TCP, TCP_NODELAY, [1], 4) = 0 futex(0x7f9cea5c9564, FUTEX_WAKE_OP_PRIVATE, 1, 1, 0x7f9cea5c9560, {FUTEX_OP_SET, 0, FUTEX_OP_CMP_GT, 1}) = 1 futex(0x7f9cea5c6fe0, FUTEX_WAKE_PRIVATE, 1) = 1 poll([{fd=10, events=POLLIN}, {fd=12, events=POLLIN}], 2, -1) = 1 ([{fd=10, revents=POLLIN}]) fcntl(10, F_GETFL) = 0x2 (flags O_RDWR) fcntl(10, F_SETFL, O_RDWR|O_NONBLOCK) = 0 accept(10, {sa_family=AF_INET, sin_port=htons(51697), sin_addr=inet_addr("192.168.113.4")}, [16]) = 31 fcntl(10, F_SETFL, O_RDWR) = 0 rt_sigaction(SIGCHLD, {SIG_DFL, [CHLD], SA_RESTORER|SA_RESTART, 0x7f9ce7ca34f0}, {SIG_DFL, [CHLD], SA_RESTORER|SA_RESTART, 0x7f9ce7ca34f0}, ) = 0 getpeername(31, {sa_family=AF_INET, sin_port=htons(51697), sin_addr=inet_addr("192.168.113.4")}, [16]) = 0 getsockname(31, {sa_family=AF_INET, sin_port=htons(3306), sin_addr=inet_addr("192.168.100.190")}, [16]) = 0 open("/etc/hosts.allow", O_RDONLY) = 33 fstat(33, {st_mode=S_IFREG|0644, st_size=580, ...}) = 0 mmap(NULL, 4096, PROT_READ|PROT_WRITE, MAP_PRIVATE|MAP_ANONYMOUS, -1, 0) = 0x7f9ce9839000 read(33, "# /etc/hosts.allow: list of host"..., 4096) = 580 read(33, "", 4096) = 0 close(33) = 0 munmap(0x7f9ce9839000, 4096) = 0 open("/etc/hosts.deny", O_RDONLY) = 33 fstat(33, {st_mode=S_IFREG|0644, st_size=880, ...}) = 0 mmap(NULL, 4096, PROT_READ|PROT_WRITE, MAP_PRIVATE|MAP_ANONYMOUS, -1, 0) = 0x7f9ce9839000 read(33, "# /etc/hosts.deny: list of hosts"..., 4096) = 880 read(33, "", 4096) = 0 close(33) = 0 munmap(0x7f9ce9839000, 4096) = 0 getsockname(31, {sa_family=AF_INET, sin_port=htons(3306), sin_addr=inet_addr("192.168.100.190")}, [16]) = 0 fcntl(31, F_SETFL, O_RDONLY) = 0 fcntl(31, F_GETFL) = 0x2 (flags O_RDWR) setsockopt(31, SOL_SOCKET, SO_RCVTIMEO, "\36\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0", 16) = 0 setsockopt(31, SOL_SOCKET, SO_SNDTIMEO, "<\0\0\0\0\0\0\0\0\0\0\0\0\0\0\0", 16) = 0 fcntl(31, F_SETFL, O_RDWR|O_NONBLOCK) = 0 setsockopt(31, SOL_IP, IP_TOS, [8], 4) = 0 setsockopt(31, SOL_TCP, TCP_NODELAY, [1], 4) = 0 futex(0x7f9cea5c9564, FUTEX_WAKE_OP_PRIVATE, 1, 1, 0x7f9cea5c9560, {FUTEX_OP_SET, 0, FUTEX_OP_CMP_GT, 1}) = 1 futex(0x7f9cea5c6fe0, FUTEX_WAKE_PRIVATE, 1) = 1 poll([{fd=10, events=POLLIN}, {fd=12, events=POLLIN}], 2, -1^C <unfinished ...> Process 23512 detached This output repeats itself until the answer gets send. It could take up to 15 Minutes until the request gets served. In the local LAN its a matter of Milliseconds. Why is this and how can I debug this further? [Edit] tcpdump shows a ton of this: 14:49:44.103107 IP cassandra-test.mysql > 192.168.X.6.64626: Flags [S.], seq 1434117703, ack 1793610733, win 14600, options [mss 1460,nop,nop,sackOK,nop,wscale 7], length 0 14:49:44.135187 IP 192.168.X.6.64625 > cassandra-test.mysql: Flags [P.], seq 106:145, ack 182, win 4345, length 39 14:49:44.135293 IP cassandra-test.mysql > 192.168.X.6.64625: Flags [P.], seq 182:293, ack 145, win 115, length 111 14:49:44.167025 IP 192.168.X.6.64624 > cassandra-test.mysql: Flags [.], ack 444, win 4280, length 0 14:49:44.168933 IP 192.168.X.6.64626 > cassandra-test.mysql: Flags [.], ack 1, win 4390, length 0 14:49:44.169088 IP cassandra-test.mysql > 192.168.X.6.64626: Flags [P.], seq 1:89, ack 1, win 115, length 88 14:49:44.169672 IP 192.168.X.6.64625 > cassandra-test.mysql: Flags [P.], seq 145:171, ack 293, win 4317, length 26 14:49:44.169726 IP cassandra-test.mysql > 192.168.X.6.64625: Flags [P.], seq 293:419, ack 171, win 115, length 126 14:49:44.275111 IP 192.168.X.6.64626 > cassandra-test.mysql: Flags [P.], seq 1:74, ack 89, win 4368, length 73 14:49:44.275131 IP cassandra-test.mysql > 192.168.X.6.64626: Flags [.], ack 74, win 115, length 0 14:49:44.275149 IP 192.168.X.6.64625 > cassandra-test.mysql: Flags [P.], seq 171:180, ack 419, win 4286, length 9 14:49:44.275189 IP cassandra-test.mysql > 192.168.X.6.64626: Flags [P.], seq 89:100, ack 74, win 115, length 11 14:49:44.275264 IP 192.168.X.6.64625 > cassandra-test.mysql: Flags [P.], seq 180:185, ack 419, win 4286, length 5 14:49:44.275281 IP cassandra-test.mysql > 192.168.X.6.64625: Flags [.], ack 185, win 115, length 0 14:49:44.275295 IP cassandra-test.mysql > 192.168.X.6.64625: Flags [F.], seq 419, ack 185, win 115, length 0 14:49:44.275650 IP 192.168.X.6.64625 > cassandra-test.mysql: Flags [F.], seq 185, ack 419, win 4286, length 0 14:49:44.275660 IP cassandra-test.mysql > 192.168.X.6.64625: Flags [.], ack 186, win 115, length 0 14:49:44.275910 IP 192.168.X.6.64627 > cassandra-test.mysql: Flags [S], seq 2336421549, win 8192, options [mss 1351,nop,wscale 2,nop,nop,sackOK], length 0 14:49:44.275921 IP cassandra-test.mysql > 192.168.X.6.64627: Flags [S.], seq 3289359778, ack 2336421550, win 14600, options [mss 1460,nop,nop,sackOK,nop,wscale 7], length 0

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• Why is the code adding 7 if the number is not >= 0

  - by Hugo Dozois

  I've got this program in MIPS assembly which comes from a C code that does the simple average of the eigth arguments of the function. average8: addu $4,$4,$5 addu $4,$4,$6 addu $4,$4,$7 lw $2,16($sp) #nop addu $4,$4,$2 lw $2,20($sp) #nop addu $4,$4,$2 lw $2,24($sp) #nop addu $4,$4,$2 lw $2,28($sp) #nop addu $2,$4,$2 bgez $2,$L2 addu $2,$2,7 $L2: sra $2,$2,3 j $31 When the number is positve, we directly divided by 8 (shift by 3 bits), but when the number is negative, we first addu 7 then do the division. My question is why do we add 7 to $2 when $2 is not >= 0 ? EDIT : Here is the C code : int average8(int x1, int x2, int x3, int x4, int x5, int x6, int x7, int x8) { return (x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8) / 8; } note : the possible loss in the division since we are using ints instead of floats or doubles is not important in this case.

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• Sparc Assembly Call currupts data

  - by Sigge

  I am at the moment working with some assembler code for the Sparc processor family, and i am having some truble with a piece of code.. I think the code and output explains more, but in the short.. When i do a call to the function println my varaibels that i have written to the %fp - 8 memory location is destoryed.. here is my assembler code that i am trying to run !PROCEDURE main .section ".text" .global main .align 4 main: save %sp, -96, %sp L1: set 96, %l0 mov %l0, %o0 call initObject ; nop mov %o0, %l0 mov %l0, %o0 call Test$go ; nop mov %o0, %l0 mov %l0, %o0 call println ; nop L0: ret restore !END main !PROCEDURE Test$go .section ".text" .global Test$go .align 4 Test$go: save %sp, -96, %sp L3: mov %i0, %l0 set 0, %l0 set -8, %l1 add %fp,%l1, %l1 st %l0, [%l1] set 1, %l0 mov %l0, %o0 call println ; nop set -8, %l0 add %fp,%l0, %l0 ld [%l0], %l0 mov %l0, %o0 call println ; nop set 1, %l0 mov %l0, %i0 L2: ret restore !END Test$go Here is the assembler code for the println code .global println .type println,#function println: save %sp,-96,%sp ! block 1 .L193: ! File runtime.c: ! 42 } ! 43 ! 45 /** ! 46 Prints an integer to the standard output stream. ! 47 ! 48 @param i The integer to be printed. ! 49 */ ! 50 void println(int i) { ! 51 printf("%d\n", i); sethi %hi(.L195),%o0 or %o0,%lo(.L195),%o0 call printf mov %i0,%o1 jmp %i7+8 restore This is the out put i get when i run this piece of assembler code 1 67584 1 As u can see, the data that is located at %fp - 8 has been destroyed.. please all feedback is apritiated

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• Sparc Assembly Call corrupts data

  - by Sigge

  I am at the moment working with some assembler code for the Sparc processor family, and i am having some truble with a piece of code.. I think the code and output explains more, but in the short.. When i do a call to the function println my varaibels that i have written to the %fp - 8 memory location is destoryed.. here is my assembler code that i am trying to run !PROCEDURE main .section ".text" .global main .align 4 main: save %sp, -96, %sp L1: set 96, %l0 mov %l0, %o0 call initObject ; nop mov %o0, %l0 mov %l0, %o0 call Test$go ; nop mov %o0, %l0 mov %l0, %o0 call println ; nop L0: ret restore !END main !PROCEDURE Test$go .section ".text" .global Test$go .align 4 Test$go: save %sp, -96, %sp L3: mov %i0, %l0 set 0, %l0 set -8, %l1 add %fp,%l1, %l1 st %l0, [%l1] set 1, %l0 mov %l0, %o0 call println ; nop set -8, %l0 add %fp,%l0, %l0 ld [%l0], %l0 mov %l0, %o0 call println ; nop set 1, %l0 mov %l0, %i0 L2: ret restore !END Test$go Here is the assembler code for the println code .global println .type println,#function println: save %sp,-96,%sp ! block 1 .L193: ! File runtime.c: ! 42 } ! 43 ! 45 /** ! 46 Prints an integer to the standard output stream. ! 47 ! 48 @param i The integer to be printed. ! 49 */ ! 50 void println(int i) { ! 51 printf("%d\n", i); sethi %hi(.L195),%o0 or %o0,%lo(.L195),%o0 call printf mov %i0,%o1 jmp %i7+8 restore This is the out put i get when i run this piece of assembler code 1 67584 1 As u can see, the data that is located at %fp - 8 has been destroyed.. please all feedback is apritiated

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• missing network usage through iptables

  - by Purres

  I inserted a rule to iptables to track the input usage to a certain ip address. The vps server's IP is 192.168.1.5 and the guest os's IP is 192.168.1.115. I ran 'yum update' inside the guest OS to get some network traffic. Then I ran iptables -vnL from the hypervisor. However it only showed network usage to the host, but not to the guest. Chain INPUT (policy ACCEPT 0 packets, 0 bytes) pkts bytes target source destination 0 0 0.0.0.0/0 0.0.0.0/0 destination IP range 192.168.1.115-192.168.1.115 1853 114K 0.0.0.0/0 0.0.0.0/0 destination IP range 192.168.1.5-192.168.1.5 I ran tcpdump and the log showed that there're data packets to the guest os. 16:17:43.932514 IP mirrordenver.fdcservers.net.http > 192.168.1.115.34471: Flags [.], seq 17694667:17696115, ack 1345, win 113, options [nop,nop,TS val 1060308643 ecr 1958781], length 1448 16:17:43.932559 IP 192.168.1.115.34471 > mirrordenver.fdcservers.net.http: Flags [.], ack 17696115, win 15287, options [nop,nop,TS val 1958869 ecr 1060308643], length 0 Why the guest OS network usage couldn't be tracked? iptables -L will return the INPUT chain as following: Chain INPUT (policy ACCEPT) target prot opt source destination all -- anywhere anywhere destination IP range 192.168.1.115-192.168.1.115 all -- anywhere anywhere destination IP range 192.168.1.5-192.168.1.5 all -- anywhere anywhere

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• Server resolve issues not consistent

  - by bobthemac

  I am having some weird issues with my web server. It has a public ip address and is set-up on an openVZ virtual machine. Accessing in to the site works fine every time but when trying to access out from the server I can't always connect out. Sometimes I can connect out and resolve addresses, sometimes I can't. The issue is visible in both ssh when trying to do a wget command on Google; sometimes it works and I get the index.html page and sometimes I get nothing. The issue is more visible in wordpress where you can't view themes but after a few presses of the try again button you can then view them. I have searched google and found nothing about this issue. Does anyone here have any ideas what could be causing this strange behaviour? Ports 80 and 2222 are open for web and ssh. Failed 17:26:33.398412 IP 86.148.184.124.38445 > 176.9.36.252.http: Flags [.], ack 98383, win 632, options [nop,nop,TS val 3070086 ecr 323106946], length 0 [email protected]..|. $..-.P..,.e......x....... .....B8. Passed 17:30:00.179630 IP 146.90.206.241.50091 > 176.9.36.252.http: Flags [F.], seq 1, ack 1, win 115, options [nop,nop,TS val 13740559 ecr 323308537], length 0 [email protected]... $....P.w...x.....s(K..... .....EK. Thanks in advance

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• Access Violation

  - by Justin

  I've been learning how to NOP functions in C++ or even C but there are very few tutorials online about it. I've been googling for the past few hours now and I'm just stuck. Here is my code. #include <iostream> #include <windows.h> #include <tlhelp32.h> using namespace std; //#define NOP 0x90 byte NOP[] = {0x90}; void enableDebugPrivileges() { HANDLE hcurrent=GetCurrentProcess(); HANDLE hToken; BOOL bret=OpenProcessToken(hcurrent,40,&hToken); LUID luid; bret=LookupPrivilegeValue(NULL,"SeDebugPrivilege",&luid); TOKEN_PRIVILEGES NewState,PreviousState; DWORD ReturnLength; NewState.PrivilegeCount =1; NewState.Privileges[0].Luid =luid; NewState.Privileges[0].Attributes=2; AdjustTokenPrivileges(hToken,FALSE,&NewState,28,&PreviousState,&ReturnLength); } DWORD GetProcId(char* ProcName) { PROCESSENTRY32 pe32; HANDLE hSnapshot = NULL; pe32.dwSize = sizeof( PROCESSENTRY32 ); hSnapshot = CreateToolhelp32Snapshot( TH32CS_SNAPPROCESS, 0 ); if( Process32First( hSnapshot, &pe32 ) ) { do{ if( strcmp( pe32.szExeFile, ProcName ) == 0 ) break; }while( Process32Next( hSnapshot, &pe32 ) ); } if( hSnapshot != INVALID_HANDLE_VALUE ) CloseHandle( hSnapshot ); return pe32.th32ProcessID; } void WriteMem(DWORD Address, void* Value, size_t Size) { DWORD Protect = NULL; VirtualProtect((LPVOID)Address, 3, PAGE_READWRITE, &Protect); memcpy((void*)Address, Value, 3); VirtualProtect((LPVOID)Address, 3, Protect, &Protect); } void nop_(PVOID address, int bytes){ DWORD d, ds; VirtualProtect(address, bytes, PAGE_EXECUTE_READWRITE, &d); memset(address, 144, bytes); VirtualProtect(address,bytes,d,&ds); } void MemCopy(HANDLE pHandle, void* Dest, const void* Src, int Len) { DWORD OldProtect; DWORD OldProtect2; VirtualProtect(Dest, Len, PAGE_EXECUTE_READWRITE, &OldProtect); memcpy(Dest, Src, Len); VirtualProtect(Dest, Len, OldProtect, &OldProtect2); FlushInstructionCache(pHandle, Dest, Len); } int main() { enableDebugPrivileges(); DWORD pid; HANDLE phandle; // Obtain the process ID pid = GetProcId("gr.exe"); if(GetLastError()) { cout << "Error_PID_: " << GetLastError() << endl; system("pause"); return -1; } // Obtain the process handle phandle = OpenProcess(PROCESS_ALL_ACCESS,0,pid); if(GetLastError()) { cout << "Error_HANDLE_: " << GetLastError() << endl; system("pause"); return -1; } // Debug info, 0 = bad cout <<"pid : " << pid << endl; cout <<"HANDLE: " << phandle << endl << endl; system("pause"); // Change value to short iValue = -1; int choice = 0; BYTE * bGodMode = (BYTE *) (0x409A7E); // Lives Address bool hack = true; while(hack) { system("cls"); cout << "What hack?\n0. Exit\n1. Lives\n\n!> "; cin >> choice; switch(choice) { case 0: { hack=false; break; } case 1: // Modify Time cout << "God Mode On\n!> "; // cin >> iValue; // nop_((PVOID)(0x409A7E), 3); // MemCopy(phandle, (PVOID)0x409A7E, &NOP, 1); WriteMem((DWORD)(0x00409A7E), (void*)NOP, sizeof NOP); if(GetLastError()) { cout << "Error: " << GetLastError() << endl; system("pause"); } break; default: cout << "ERROR!\n"; break; } Sleep(100); } system("pause"); return 0; } This is suppose to NOP the DEC function that is 3 bytes long preventing me from losing lives. However each time I try it, it crashes the hack and says I had a access violation. I tried to look up the reasons and most of them dealt with with the size of the location I'm writing to and what I'm copying from. Otherwise, I have absolutely no idea. Any help would be nice. The game is GunRoar and the base address "0x409A7E" is where the DEC function is.

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• tcpdump selective acknowledgements question

  - by wlaus

  Hi All, I eventually sometimes watch most initial tcp connection attempts like this: tcpdump -nn -Z somepcapuser not src host (12x.x5.109.xxx or 62.75.160.xxx ) and not (port 9001 or 443 or 8080 ) and tcp[tcpflags]&(tcp-syn) !=0 and not tcp[tcpflags]& (tcp-ack) !=0 or icmp this works pretty well to quickly identify oddness so far. However, I now have a question on the following output: 03:53:52.227884 IP 203.81.166.20.53786 62.75.160.xxx.80: S 846930886:846930886(0) win 61690 "<"mss 1460,nop,nop,sackOK,opt-178:f04700000000,nop,wscale 4"" I wonder what the marked portion means, haven't seen that before. Thanks for help wlaus

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• Ubuntu 12.04 Very slow especially with Android Studio

  - by Nada

  I have an old laptop with the following specification: Memory: 485 MiB, Processor: Genuine intel CPU T2300 @ 1.66 GHz ×2, OS Type: 32 bit, Disk: 78.1 GB, I installed on it Ubuntu 12.04 LTS and I noticed that the overall system is very slow in responding. I tried to search about that in the internet and I found some articles talking about how to make Ubuntu 12.04 LTS run fast I applied all what they said including download LXDE desktop environment and then nothing different in the system response time. Then I need to develop some android applications so, I download Android Studio (Beta) 0.8.6. The problem became worse than before whenever I tried to open the Android Studio the screen is frozen for some minutes then it took time to download the projects and initialize the work space also, when I tried to move the cursor he is move very slowly. When I tried to run my first application on the AVD it took three hours and still not run yet. I delete the Android Studio and install it again several times, I was trying to solve the problem but still nothing change. Please if you have any suggestions that may help me make my laptop and Android Studio work faster I will appreciate it for you. Thank you in advance.

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• Extracting information from active directory

  - by Nop at NaDa

  I work in the IT support department of a branch of a huge company. I have to take care of a database with all the users, computers, etc. I'm trying to find a way to automatically update the database as much as possible, but the IT infrastructure guys doesn't give me enough privileges to use Active Directory in order to dump the users, nor they have the time to give me the information that I need. Some days ago I found Active Directory explorer from Sysinternals that allows me to browse through Active Directory, and I found all the information that I need there (username, real name, date when it was created, privileges, company, etc.). Unfortunately I'm unable to export the data to a human readable format. I'm just able to take a snapshot of the whole database in a machine-readable format. Doing the snapshot takes hours and I'm afraid that the infrastructure guys won't like me doing entire snapshots on a regular basis. Do you know of any tool (command-line is preferable) that would allow me to retrieve the values of the keys or export it to XML, CSV, etc?

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• Dumping active directory

  - by Nop at NaDa

  I work in the IT support department of a branch of a huge company. I have to take care of a database with all the users, computers, etc. I'm trying to find a way to automatically update the database as much as possible, but the IT infrastructure guys doesn't give me enough privileges to use Active Directory in order to dump the users, nor they have the time to give me the information that I need. Some days ago I found Active Directory explorer from Sysinternals that allows me to browse through Active Directory, and I found all the information that I need there (username, real name, date when it was created, privileges, company, etc.). Unfortunately I'm unable to export the data to a human readable format. I'm just able to take a snapshot of the whole database in a machine-readable format. Doing the snapshot takes hours and I'm afraid that the infrastructure guys won't like me doing entire snapshots on a regular basis. Do you know of any tool (command-line is preferable) that would allow me to retrieve the values of the keys or export it to XML, CSV, etc?

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• How to keep unreachable code?

  - by Gabriel

  I'd like to write a function that would have some optional code to execute or not depending on user settings. The function is cpu-intensive and having ifs in it would be slow since the branch predictor is not that good. My idea is making a copy in memory of the function and replace NOPs with jumps when I don't want to execute some code. My working example goes like this: int Test() { int x = 2; for (int i=0 ; i<10 ; i++) { x *= 2; __asm {NOP}; // to skip it replace this __asm {NOP}; // by JMP 2 (after the goto) x *= 2; // Op to skip or not x *= 2; } return x; } In my test's main, I copy this function into a newly allocated executable memory and replace the NOPs by a JMP 2 so that the following x *= 2 is not executed. The problem is that I would have to change the JMP operand every time I change the code to be skipped. An alternative that would fix this problem would be: __asm {NOP}; // to skip it replace this __asm {NOP}; // by JMP 2 (after the goto) goto dont_do_it; x *= 2; // Op to skip or not dont_do_it: x *= 2; This way, as a goto uses 2 bytes of binary, I would be able to replace the NOPs by a fixed JMP of alway 2 in order to skip the goto. Unfortunately, in full optimization mode, the goto and the x*=2 are removed because they are unreachable at compilation time. Hence the need to keep that dead code.

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• Error Ubuntu 11.10 despues de instalar [Error after installing Ubuntu 11.10]

  - by manue

  instale ubuntu 11.10, termino de instalar y no tiene nada, ni aplicaciones, ni esa barrita lateral de unity, no tiene nada, ni si quiera la barra donde aparece la hora; porque? y me aparece un cuadro diciendo que hay un error en el disco y que el fallo es inminente , que es? SMART no entiendo, ayuda Y en otro disco duro con windows xp sp3 se bloquea cuando lo instalo desde el live cd, y desde wubi aparece esto enter link description here que hacer? English translation (via Google Translate, edited) I have installed ubuntu 11.10, after finishing the installing there is nothing, no applications, no the sidebar called unity, there is nothing, not even the bar where time appears, why?. I get a box saying there is an error on the disk and that failure is imminent. What is SMART, I do not understand, help In my other hard drive, with windows xp sp3, it crashes when I try install from the live cd using wubi, this appears, what to do?

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• While loop in IL - why stloc.0 and ldloc.0?

  - by Michael Stum

  I'm trying to understand how a while loop looks in IL. I have written this C# function: static void Brackets() { while (memory[pointer] > 0) { // Snipped body of the while loop, as it's not important } } The IL looks like this: .method private hidebysig static void Brackets() cil managed { // Code size 37 (0x25) .maxstack 2 .locals init ([0] bool CS$4$0000) IL_0000: nop IL_0001: br.s IL_0012 IL_0003: nop // Snipped body of the while loop, as it's not important IL_0011: nop IL_0012: ldsfld uint8[] BFHelloWorldCSharp.Program::memory IL_0017: ldsfld int16 BFHelloWorldCSharp.Program::pointer IL_001c: ldelem.u1 IL_001d: ldc.i4.0 IL_001e: cgt IL_0020: stloc.0 IL_0021: ldloc.0 IL_0022: brtrue.s IL_0003 IL_0024: ret } // end of method Program::Brackets For the most part this is really simple, except for the part after cgt. What I don't understand is the local [0] and the stloc.0/ldloc.0. As far as I see it, cgt pushes the result to the stack, stloc.0 gets the result from the stack into the local variable, ldloc.0 pushes the result to the stack again and brtrue.s reads from the stack. What is the purpose of doing this? Couldn't this be shortened to just cgt followed by brtrue.s?

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• WIX: How to register an Application to a URL Protocol?

  - by NOP slider

  In WIX 3.5 you can register file types easily: <ProgId Id="MyApp.File" Description="MyApp File" Icon="MyAppEXE" IconIndex="0"> <Extension Id="ext" ContentType="application/x-myapp-file"> <Verb Id="open" Command="&amp;Open" TargetFile="MyAppEXE" Argument="&quot;%1&quot;"/> </Extension> </ProgId> What if I want to register an URL protocol, as specified here? Obviously, it has no extension so where would I put the Verb tag? Or should I use another approach? Thanks.

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• Reverse all words in current line

  - by KasiyA

  I have a file and I want to reverse all word in it. Read line as long as (.) not seen, or seen (\n), if found first (.) in line then It is a word , so reverse this word and continue reading for next word in current line until end of file. ex input file: DCBA. HGFE.GI MLK,PON.RQ UTS. ZYXWV. 321 ex output file: (What I Want) ABCD. EFGH.IG KLM,NOP.QR STU. VWXYZ. 123 With this sed script: sed '/\n/!G;s/\(.\)\(.*\n\)/&\2\1/;//D;s/.//' in the entire line is reversed. The wrong output produced by the command above: IG.EFGH .ABCD QR.NOP,KLM 123 .VWXYZ .STU How can I get my desired output? Thanks for your help

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• Remote access to phpmyadmin from computer belongs to same LAN

  - by Charles

  OK... I solved it. It is because I have not configured the httpd.conf to allow the centos listen port 80 and 8080. Listen 80 Listen 8080 I have setup the myphpadmin on my CentOS 6.4 recently. I can access and login to the myphpadmin on my localhost. However, when I type http://[hostipaddr]/phpmyadmin on my other computer in the same LAN with the CentOS, the browser simply cannot access the page. Below are some of the current configuration. Anyone can help please......? config.inc.php $i++; /* Authentication type */ $cfg['Servers'][$i]['auth_type'] = 'http'; /* Server parameters */ $cfg['Servers'][$i]['host'] = 'localhost'; $cfg['Servers'][$i]['connect_type'] = 'tcp'; $cfg['Servers'][$i]['compress'] = false; /* Select mysql if your server does not have mysqli */ $cfg['Servers'][$i]['extension'] = 'mysql'; $cfg['Servers'][$i]['AllowNoPassword'] = false; phpmyadmin.conf <Directory /var/www/html/phpmyadmin/> order allow,deny allow from all </Directory> Furthermore, I can access the webpage that stored in the CentOS from my other computer without problems. After using wireshark and tcpdump, I found that the server (the Cent OS) keep resetting the connection. (192.168.1.106 is my other computer, 192.168.1.101 is my CentOS) 23:29:42.281473 IP 192.168.1.106.55999 > 192.168.1.101.webcache: Flags [S], seq 2559409090, win 65535, options [mss 1460,nop,wscale 8,nop,nop,sackOK], length 0 23:29:42.281504 IP 192.168.1.101.webcache > 192.168.1.106.55999: Flags [R.], seq 0, ack 2559409091, win 0, length 0 I have disabled the iptables service on the CentOS already.

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• How is printf() implemented in c?

  - by Mask

  Disassembling printf doesn't give much info: (gdb) disas printf Dump of assembler code for function printf: 0x00401b38 <printf+0>: jmp *0x405130 0x00401b3e <printf+6>: nop 0x00401b3f <printf+7>: nop End of assembler dump. How is it implemented under the hood? Why disassembling doesn't help? What does * mean before 0x405130?

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• [MSIL] Variable comparison

  - by alexn

  Hi, The following C#-snippet: var x = 1; var y = 1; if (x == y) Console.Write("True"); Generates this MSIL: .locals init ( [0] int32 x, [1] int32 y, [2] bool CS$4$0000) L_0000: nop L_0001: ldc.i4.1 L_0002: stloc.0 L_0003: ldc.i4.1 L_0004: stloc.1 L_0005: ldloc.0 L_0006: ldloc.1 L_0007: ceq L_0009: ldc.i4.0 L_000a: ceq L_000c: stloc.2 L_000d: ldloc.2 L_000e: brtrue.s L_001b L_0010: ldstr "True" L_0015: call void [mscorlib]System.Console::Write(string) L_001a: nop L_001b: ret Why is there two ceq calls? Thanks

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• What does * address(found in printf) mean in assembly?

  - by Mask

  Disassembling printf doesn't give much info: (gdb) disas printf Dump of assembler code for function printf: 0x00401b38 <printf+0>: jmp *0x405130 0x00401b3e <printf+6>: nop 0x00401b3f <printf+7>: nop End of assembler dump. (gdb) disas 0x405130 Dump of assembler code for function _imp__printf: 0x00405130 <_imp__printf+0>: je 0x405184 <_imp__vfprintf+76> 0x00405132 <_imp__printf+2>: add %al,(%eax) How is it implemented under the hood? Why disassembling doesn't help? What does * mean before 0x405130?

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• How is prinf() implemented in c?

  - by Mask

  Disassembling printf doesn't give much info: (gdb) disas printf Dump of assembler code for function printf: 0x00401b38 <printf+0>: jmp *0x405130 0x00401b3e <printf+6>: nop 0x00401b3f <printf+7>: nop End of assembler dump. How is it implemented under the hood?

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• Jumping into argv?

  - by jth

  Hi, I`am experimenting with shellcode and stumbled upon the nop-slide technique. I wrote a little tool that takes buffer-size as a parameter and constructs a buffer like this: [ NOP | SC | RET ], with NOP taking half of the buffer, followed by the shellcode and the rest filled with the (guessed) return address. Its very similar to the tool aleph1 described in his famous paper. My vulnerable test-app is the same as in his paper: int main(int argc, char **argv) { char little_array[512]; if(argc>1) strcpy(little_array,argv[1]); return 0; } I tested it and well, it works: jth@insecure:~/no_nx_no_aslr$ ./victim $(./exploit 604 0) $ exit But honestly, I have no idea why. Okay, the saved eip was overwritten as intended, but instead of jumping somewhere into the buffer, it jumped into argv, I think. gdb showed up the following addresses before strcpy() was called: (gdb) i f Stack level 0, frame at 0xbffff1f0: eip = 0x80483ed in main (victim.c:7); saved eip 0x154b56 source language c. Arglist at 0xbffff1e8, args: argc=2, argv=0xbffff294 Locals at 0xbffff1e8, Previous frame's sp is 0xbffff1f0 Saved registers: ebp at 0xbffff1e8, eip at 0xbffff1ec Address of little_array: (gdb) print &little_array[0] $1 = 0xbfffefe8 "\020" After strcpy(): (gdb) i f Stack level 0, frame at 0xbffff1f0: eip = 0x804840d in main (victim.c:10); saved eip 0xbffff458 source language c. Arglist at 0xbffff1e8, args: argc=-1073744808, argv=0xbffff458 Locals at 0xbffff1e8, Previous frame's sp is 0xbffff1f0 Saved registers: ebp at 0xbffff1e8, eip at 0xbffff1ec So, what happened here? I used a 604 byte buffer to overflow little_array, so he certainly overwrote saved ebp, saved eip and argc and also argv with the guessed address 0xbffff458. Then, after returning, EIP pointed at 0xbffff458. But little_buffer resides at 0xbfffefe8, that`s a difference of 1136 byte, so he certainly isn't executing little_array. I followed execution with the stepi command and well, at 0xbffff458 and onwards, he executes NOPs and reaches the shellcode. I'am not quite sure why this is happening. First of all, am I correct that he executes my shellcode in argv, not little_array? And where does the loader(?) place argv onto the stack? I thought it follows immediately after argc, but between argc and 0xbffff458, there is a gap of 620 bytes. How is it possible that he successfully "lands" in the NOP-Pad at Address 0xbffff458, which is way above the saved eip at 0xbffff1ec? Can someone clarify this? I have actually no idea why this is working. My test-machine is an Ubuntu 9.10 32-Bit Machine without ASLR. victim has an executable stack, set with execstack -s. Thanks in advance.

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• http request via iptables --to-destination ip redirect results in no response

  - by Wouter Vegter

  I have two Ubuntu servers with each having their own ip addresses. Let's call them server1 and server2, having respectively ip 1.1.1.1 and 2.2.2.2 I have a nginx running on server2. The sole purpose I want server1 to have is to redirect all incoming http (so port 80) requests to server2 without clients noticing that their request is being redirected. I tried the following command on server1: iptables -t nat -A PREROUTING -p tcp --dport 80 -j DNAT --to-destination 2.2.2.2 But when I enter 1.1.1.1 in my browser I get no respond: the page keeps trying to load without giving any message or error message (I get a time-out after 2-3 mins). But when I do remove the above iptables rule I immediately do get a "page not found error" when I enter 1.1.1.1 in my browser; so something is working but not as it should: when I enter 1.1.1.1 I want the html page to load that is hosted on 2.2.2.2 Because when i enter 2.2.2.2 in my browser I do see the webpage loaded. Could anyone please help me with this? I am searching quite some time (on severfault & Google) on this now so that's why I ask. Many thanks for reading my question! Update: Thank you all for you information. Unfortunately I still get no response I have the following iptables configuration: root@ip-10-48-238-216:/home/ubuntu# sudo iptables -L Chain INPUT (policy ACCEPT) target prot opt source destination Chain FORWARD (policy ACCEPT) target prot opt source destination Chain OUTPUT (policy ACCEPT) target prot opt source destination root@ip-10-48-238-216:/home/ubuntu# sudo iptables -t nat -L Chain PREROUTING (policy ACCEPT) target prot opt source destination DNAT tcp -- anywhere anywhere tcp dpt:www to:2.2.2.2 Chain OUTPUT (policy ACCEPT) target prot opt source destination Chain POSTROUTING (policy ACCEPT) target prot opt source destination When i run tcpdump and do request via chrome to 1.1.1.1 i get the following root@ip-10-48-238-216:/home/ubuntu# sudo tcpdump -i eth0 port 80 -vv tcpdump: listening on eth0, link-type EN10MB (Ethernet), capture size 65535 bytes 13:56:18.346625 IP (tos 0x0, ttl 52, id 12055, offset 0, flags [DF], proto TCP (6), length 60) 212-123-161-112.ip.telfort.nl.16386 ip-10-48-238-216.eu-west-1.compute.internal.www: Flags [S], cksum 0xb398 (correct), seq 2639758575, win 5840, options [mss 1460,sackOK,TS val 1223672 ecr 0,nop,wscale 6], length 0 13:56:18.346662 IP (tos 0x0, ttl 51, id 12055, offset 0, flags [DF], proto TCP (6), length 60) 212-123-161-112.ip.telfort.nl.16386 ww1dc1.shopreme.com.www: Flags [S], cksum 0x9ee0 (correct), seq 2639758575, win 5840, options [mss 1460,sackOK,TS val 1223672 ecr 0,nop,wscale 6], length 0 13:56:18.598747 IP (tos 0x0, ttl 52, id 10138, offset 0, flags [DF], proto TCP (6), length 60) 212-123-161-112.ip.telfort.nl.16387 ip-10-48-238-216.eu-west-1.compute.internal.www: Flags [S], cksum 0xac40 (correct), seq 2645658541, win 5840, options [mss 1460,sackOK,TS val 1223735 ecr 0,nop,wscale 6], length 0 13:56:18.598777 IP (tos 0x0, ttl 51, id 10138, offset 0, flags [DF], proto TCP (6), length 60) 212-123-161-112.ip.telfort.nl.16387 ww1dc1.shopreme.com.www: Flags [S], cksum 0x9788 (correct), seq 2645658541, win 5840, options [mss 1460,sackOK,TS val 1223735 ecr 0,nop,wscale 6], length 0 ^C 4 packets captured 4 packets received by filter 0 packets dropped by kernel the mentioned address relate to the following 212-123-161-112.ip.telfort.nl.16386 : my personal computer ww1dc1.shopreme.com.www : dns of server2 (2.2.2.2) ip-10-48-238-216.eu-west-1.compute.internal.www : amazon web services ec2 internal address of server1 (1.1.1.1) However, the tcpdump log on server2 (2.2.2.2) stays empty and I get no response back in my browser. I am able to ping from server1 to server2. And net.ipv4.ip_forward is set to 1 and so is /proc/sys/net/ipv4/ip_forward Could there be anything else that is missing?

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