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  • Sorting in Hash Maps in Java

    - by Crystal
    I'm trying to get familiar with Collections. I have a String which is my key, email address, and a Person object (firstName, lastName, telephone, email). I read in the Java collections chapter on Sun's webpages that if you had a HashMap and wanted it sorted, you could use a TreeMap. How does this sort work? Is it based on the compareTo() method you have in your Person class? I overrode the compareTo() method in my Person class to sort by lastName. But it isn't working properly and was wondering if I have the right idea or not. getSortedListByLastName at the bottom of this code is where I try to convert to a TreeMap. Also, if this is the correct way to do it, or one of the correct ways to do it, how do I then sort by firstName since my compareTo() is comparing by lastName. import java.util.*; public class OrganizeThis { /** Add a person to the organizer @param p A person object */ public void add(Person p) { staff.put(p.getEmail(), p); //System.out.println("Person " + p + "added"); } /** * Remove a Person from the organizer. * * @param email The email of the person to be removed. */ public void remove(String email) { staff.remove(email); } /** * Remove all contacts from the organizer. * */ public void empty() { staff.clear(); } /** * Find the person stored in the organizer with the email address. * Note, each person will have a unique email address. * * @param email The person email address you are looking for. * */ public Person findByEmail(String email) { Person aPerson = staff.get(email); return aPerson; } /** * Find all persons stored in the organizer with the same last name. * Note, there can be multiple persons with the same last name. * * @param lastName The last name of the persons your are looking for. * */ public Person[] find(String lastName) { ArrayList<Person> names = new ArrayList<Person>(); for (Person s : staff.values()) { if (s.getLastName() == lastName) { names.add(s); } } // Convert ArrayList back to Array Person nameArray[] = new Person[names.size()]; names.toArray(nameArray); return nameArray; } /** * Return all the contact from the orgnizer in * an array sorted by last name. * * @return An array of Person objects. * */ public Person[] getSortedListByLastName() { Map<String, Person> sorted = new TreeMap<String, Person>(staff); ArrayList<Person> sortedArrayList = new ArrayList<Person>(); for (Person s: sorted.values()) { sortedArrayList.add(s); } Person sortedArray[] = new Person[sortedArrayList.size()]; sortedArrayList.toArray(sortedArray); return sortedArray; } private Map<String, Person> staff = new HashMap<String, Person>(); public static void main(String[] args) { OrganizeThis testObj = new OrganizeThis(); Person person1 = new Person("J", "W", "111-222-3333", "[email protected]"); Person person2 = new Person("K", "W", "345-678-9999", "[email protected]"); Person person3 = new Person("Phoebe", "Wang", "322-111-3333", "[email protected]"); Person person4 = new Person("Nermal", "Johnson", "322-342-5555", "[email protected]"); Person person5 = new Person("Apple", "Banana", "123-456-1111", "[email protected]"); testObj.add(person1); testObj.add(person2); testObj.add(person3); testObj.add(person4); testObj.add(person5); System.out.println(testObj.findByEmail("[email protected]")); System.out.println("------------" + '\n'); Person a[] = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("------------" + '\n'); a = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("SORTED" + '\n'); a = testObj.getSortedListByLastName(); for (Person b : a) { System.out.println(b); } } } Person class: public class Person implements Comparable { String firstName; String lastName; String telephone; String email; public Person() { firstName = ""; lastName = ""; telephone = ""; email = ""; } public Person(String firstName) { this.firstName = firstName; } public Person(String firstName, String lastName, String telephone, String email) { this.firstName = firstName; this.lastName = lastName; this.telephone = telephone; this.email = email; } public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } public String getTelephone() { return telephone; } public void setTelephone(String telephone) { this.telephone = telephone; } public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } public int compareTo(Object o) { String s1 = this.lastName + this.firstName; String s2 = ((Person) o).lastName + ((Person) o).firstName; return s1.compareTo(s2); } public boolean equals(Object otherObject) { // a quick test to see if the objects are identical if (this == otherObject) { return true; } // must return false if the explicit parameter is null if (otherObject == null) { return false; } if (!(otherObject instanceof Person)) { return false; } Person other = (Person) otherObject; return firstName.equals(other.firstName) && lastName.equals(other.lastName) && telephone.equals(other.telephone) && email.equals(other.email); } public int hashCode() { return this.email.toLowerCase().hashCode(); } public String toString() { return getClass().getName() + "[firstName = " + firstName + '\n' + "lastName = " + lastName + '\n' + "telephone = " + telephone + '\n' + "email = " + email + "]"; } }

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  • Where to Get Expert SEO Help and Best SEO Information to Help Boost Your Online Business

    Traffic is the lifeblood of any online business. Without it, your online business is considered not existing; and without it, it will not earn a dime. Whatever products or services you sell, you definitely need to gain or maintain a good amount of traffic to your site through a robust Search Engine Optimization or SEO campaign. But how can SEO help you boost your business exactly? If you are reading this article, chances are, you are looking for helpful SEO information to improve your website's rank in search engines. SEO, as the name suggests, helps you optimize your website to give it excellent visibility in search engines.

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  • Given a project and working with 1 other person - never worked with someone before

    - by Celeritas
    I'm taking a class where I work with a partner to implement the link layer of the OSI model. I've worked programmed with a partner once before and it went bad. Is the goal to divide the work up and decides who does what or should one person code and the other person reviews and switch roles after a while? Any tips are much appreciated. Literally I know nothing about working with a partner to program so even if it's basic please tell me.

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  • How to set the default page for a .CHM file in HTML Help Workshop?

    - by mengchew0113
    When I open the help (.chm) application, I could see table of contents. By default, the first entry in the file is selected, however I couldn't see the corresponding page data. Instead, I see "This program cannot display the web page" (the default error message that comes in IE7).The page is displayed only when I click on any of the contents on the left side. Is there a way of showing the page by default without clicking on the entry? The following code is the .hhp file. [OPTIONS] Compatibility = 1.1 or later Compiled file=Config.chm Contents file=Config.hhc Default topic=D:\apps\bin\Debug\html\Databases.htm Language=0x409 English (United States) Display compile progress=No Title=ETL_Config Documentation [FILES] D:\apps\bin\Debug\html\Databases.htm D:\apps\bin\Debug\html\InstanceInformation.htm

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  • Frustum culling with third person camera

    - by Christian Frantz
    I have a third person camera that contains two matrices: view and projection, and two Vector3's: camPosition and camTarget. I've read up on frustum culling and it makes it seem easy enough for a first person camera, but how would I implement this for a third person camera? I need to take into effect the objects I can see behind me too. How would I implement this into my camera class so it runs at the same time as my update method? public void CameraUpdate(Matrix objectToFollow) { camPosition = objectToFollow.Translation + (objectToFollow.Backward *backward) + (objectToFollow.Up * up); camTarget = objectToFollow.Translation; view = Matrix.CreateLookAt(camPosition, camTarget, Vector3.Up); } Can I just create another method within the class which creates a bounding sphere with a value from my camera and then uses the culling based on that? And if so, which value am I using to create the bounding sphere from? After this is implemented, I'm planning on using occlusion culling for the faces of my objects adjacent to other objects. Will using just one or the other make a difference? Or will both of them be better? I'm trying to keep my framerate as high as possible

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  • Circular dependency and object creation when attempting DDD

    - by Matthew
    I have a domain where an Organization has People. Organization Entity public class Organization { private readonly List<Person> _people = new List<Person>(); public Person CreatePerson(string name) { var person = new Person(organization, name); _people.Add(person); return person; } public IEnumerable<Person> People { get { return _people; } } } Person Entity public class Person { public Person(Organization organization, string name) { if (organization == null) { throw new ArgumentNullException("organization"); } Organization = organization; Name = name; } public Organization { get; private set; } public Name { get; private set; } } The rule for this relationship is that a Person must belong to exactly one Organization. The invariants I want to guarantee are: A person must have an organization this is enforced via the Person's constuctor An organization must know of its people this is why the Organization has a CreatePerson method A person must belong to only one organization this is why the organization's people list is not publicly mutable (ignoring the casting to List, maybe ToEnumerable can enforce that, not too concerned about it though) What I want out of this is that if a person is created, that the organization knows about its creation. However, the problem with the model currently is that you are able to create a person without ever adding it to the organizations collection. Here's a failing unit-test to describe my problem [Test] public void AnOrganizationMustKnowOfItsPeople() { var organization = new Organization(); var person = new Person(organization, "Steve McQueen"); CollectionAssert.Contains(organization.People, person); } What is the most idiomatic way to enforce the invariants and the circular relationship?

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  • Java Dynamic Binding

    - by Chris Okyen
    I am having trouble understanding the OOP Polymorphic principl of Dynamic Binding ( Late Binding ) in Java. I looked for question pertaining to java, and wasn't sure if a overall answer to how dynamic binding works would pertain to Java Dynamic Binding, I wrote this question. Given: class Person { private String name; Person(intitialName) { name = initialName; } // irrelevant methods is here. // Overides Objects method public void writeOutput() { println(name); } } class Student extends Person { private int studentNumber; Student(String intitialName, int initialStudentNumber) { super(intitialName); studentNumber = initialStudentNumber; } // irrellevant methods here... // overides Person, Student and Objects method public void writeOutput() { super.writeOutput(); println(studentNumber); } } class Undergaraduate extends Student { private int level; Undergraduate(String intitialName, int initialStudentNumber,int initialLevel) { super(intitialName,initialStudentNumber); level = initialLevel; } // irrelevant methods is here. // overides Person, Student and Objects method public void writeOutput() { super.writeOutput(); println(level); } } I am wondering. if I had an array called person declared to contain objects of type Person: Person[] people = new Person[2]; person[0] = new Undergraduate("Cotty, Manny",4910,1); person[1] = new Student("DeBanque, Robin", 8812); Given that person[] is declared to be of type Person, you would expect, for example, in the third line where person[0] is initialized to a new Undergraduate object,to only gain the instance variable from Person and Persons Methods since doesn't the assignment to a new Undergraduate to it's ancestor denote the Undergraduate object to access Person - it's Ancestors, methods and isntance variables... Thus ...with the following code I would expect person[0].writeOutput(); // calls Undergraduate::writeOutput() person[1].writeOutput(); // calls Student::writeOutput() person[0] to not have Undergraduate's writeOutput() overidden method, nor have person[1] to have Student's overidden method - writeOutput(). If I had Person mikeJones = new Student("Who?,MikeJones",44,4); mikeJones.writeOutput(); The Person::writeOutput() method would be called. Why is this not so? Does it have to do with something I don't understand about relating to arrays? Does the declaration Person[] people = new Person[2] not bind the method like the previous code would?

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  • Finding a person in the forest

    - by PointsToShare
    © 2011 By: Dov Trietsch. All rights reserved finding a person in the forest or Limiting the AD result in SharePoint People Picker There are times when we need to limit the SharePoint audience of certain farms or servers or site collections to a particular audience. One of my experiences involved limiting access to US citizens, another to a particular location. Now, most of us – your humble servant included – are not Active Directory experts – but we must be able to handle the “audience restrictions” as required. So here is how it’s done in a nutshell. Important note. Not all could be done in PowerShell (at least not yet)! There are no Windows PowerShell commands to configure People Picker. The stsadm command is: stsadm -o setproperty -pn peoplepicker-searchadcustomquery -pv ADQuery –url http://somethingOrOther Note the long-hyphenated property name. Now to filling the ADQuery.   LDAP Query in a nutshell Syntax LDAP is no older than SQL and an LDAP query is actually a query against the LDAP Database. LDAP attributes are the equivalent of Database columns, so why do we have to learn a new query language? Beats me! But we must, so here it is. The syntax of an LDAP query string is made of individual statements with relational operators including: = Equal <= Lower than or equal >= Greater than or equal… and memberOf – a group membership. ! Not * Wildcard Equal and memberOf are the most commonly used. Checking for absence uses the ! – not and the * - wildcard Example: (SN=Grant) All whose last name – SurName – is Grant Example: (!(SN=Grant)) All except Grant Example: (!(SN=*)) all where there is no SurName i.e SurName is absent (probably Rappers). Example: (CN=MyGroup) Common Name is MyGroup.  Example: (GN=J*) all the Given Names that start with J (JJ, Jane, Jon, John, etc.) The cryptic SN, CN, GN, etc. are attributes and more about them later All the queries are enclosed in parentheses (Query). Complex queries are comprised of sets that are in AND or OR conditions. AND is denoted by the ampersand (&) and the OR is denoted by the vertical pipe (|). The general syntax is that of the Prefix polish notation where the operand precedes the variables. E.g +ab is the sum of a and b. In an LDAP query (&(A)(B)) will garner the objects for which both A and B are true. In an LDAP query (&(A)(B)(C)) will garner the objects for which A, B and C are true. There’s no limit to the number of conditions. In an LDAP query (|(A)(B)) will garner the objects for which either A or B are true. In an LDAP query (|(A)(B)(C)) will garner the objects for which at least one of A, B and C is true. There’s no limit to the number of conditions. More complex queries have both types of conditions and the parentheses determine the order of operations. Attributes Now let’s get into the SN, CN, GN, and other attributes of the query SN – is the SurName (last name) GN – is the Given Name (first name) CN – is the Common Name, usually GN followed by SN OU – is an Organization Unit such as division, department etc. DC – is a Domain Content in the AD forest l – lower case ‘L’ stands for location. Jerusalem anybody? Or Katmandu. UPN – User Principal Name, is usually the first part of an email address. By nature it is unique in the forest. Most systems set the UPN to be the first initial followed by the SN of the person involved. Some limit the total to 8 characters. If we have many ‘jsmith’ we have to somehow distinguish them from each other. DN – is the distinguished name – a name unique to AD forest in which it lives. Usually it’s a CN with some domain or group distinguishers. DN is important in conjunction with the memberOf relation. Groups have stricter requirement. Each group has to have a unique name - its CN and it has to be unique regardless of its place. See more below. All of the attributes are case insensitive. CN, cn, Cn, and cN are identical. objectCategory is an element that requires special consideration. AD contains many different object like computers, printers, and of course people and groups. In the queries below, we’re limiting our search to people (person). Putting it altogether Let’s get a list of all the Johns in the SPAdmin group of the Jerusalem that local domain. (&(objectCategory=person)(memberOf=cn=SPAdmin,ou=Jerusalem,dc=local)) The memberOf=cn=SPAdmin uses the cn (Common Name) of the SPAdmin group. This is how the memberOf relation is used. ‘SPAdmin’ is actually the DN of the group. Also the memberOf relation does not allow wild cards (*) in the group name. Also, you are limited to at most one ‘OU’ entry. Let’s add Marvin Minsky to the search above. |(&(objectCategory=person)(memberOf=cn=SPAdmin,ou=Jerusalem,dc=local))(CN=Marvin Minsky) Here I added the or pipeline at the beginning of the query and put the CN requirement for Minsky at the end. Note that if Marvin was already in the prior result, he’s not going to be listed twice. One last note: You may see a dryer but more complete list of attributes rules and examples in: http://www.tek-tips.com/faqs.cfm?fid=5667 And finally (thus negating the claim that my previous note was last), to the best of my knowledge there are 3 more ways to limit the audience. One is to use the peoplepicker-searchadcustomfilter property using the same ADQuery. This works only in SP1 and above. The second is to limit the search to users within this particular site collection – the property name is peoplepicker-onlysearchwithinsitecollection and the value is yes (-pv yes) And the third is –pn peoplepicker-serviceaccountdirectorypaths –pv “OU=ou1,DC=dc1…..” Again you are limited to at most one ‘OU’ phrase – no OU=ou1,OU=ou2… And now the real end. The main property discussed in this sprawling and seemingly endless monogram – peoplepicker-searchadcustomquery - is the most general way of getting the job done. Here are a few examples of command lines that worked and some that didn’t. Can you see why? C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\12\BIN>stsa dm -o setproperty -url http://somethingOrOther -pn peoplepicker-searchadcustomfi lter -pv (Title=David) Operation completed successfully. C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\12\BIN>stsa dm -o setproperty -url http://somethingOrOther -pn peoplepicker-searchadcustomfi lter -pv (!Title=David) Operation completed successfully. C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\12\BIN>stsa dm -o setproperty -url http://somethingOrOther -pn peoplepicker-searchadcustomfi lter -pv (OU=OURealName,OU=OUMid,OU=OUTop,DC=TopDC,DC=MidDC,DC=BottomDC) Command line error. Too many OUs C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\12\BIN>stsa dm -o setproperty -url http://somethingOrOther -pn peoplepicker-searchadcustomfi lter -pv (OU=OURealName) Operation completed successfully. C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\12\BIN>stsa dm -o setproperty -url http://somethingOrOther -pn peoplepicker-searchadcustomfi lter -pv (DC=TopDC,DC=MidDC,DC=BottomDC) Operation completed successfully. C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\12\BIN>stsa dm -o setproperty -url http://somethingOrOther -pn peoplepicker-searchadcustomfi lter -pv (OU=OURealName,DC=TopDC,DC=MidDC,DC=BottomDC) Operation completed successfully.   That’s all folks!

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  • “I could use a little help here” or “I can do it myself, thank you” for Cloud Projects

    - by BuckWoody
    Windows Azure allows you to write code in languages within the .NET stack, you can use Java, C++, PHP, NodeJS and others. Code is code - other than keeping things stateless, using a Web or Worker Role in Azure is not all that different from working with an on-premises system. However…. Working in a scalable, component-based stateless architecture that can use federated security is not all that common for many developers. Some are used to owning the server, scaling up, and state-full paradigms that have a single security domain. Making the transition whilst trying to create a new software application or even port a previous one can be daunting. Sure, we have absolutely tons of free training, kits, videos, online books and more to learn on your own, but some things like architecture can be pivotal as you move along. So the question is, should you just strike out on your own for a Cloud project, or get Microsoft Consulting Services or another partner to work with you on your first one? I use a few decision points to help guide the projects I assist in. Note: I’m a huge fan of having help that ends up giving you training and leaves you in charge. If you do engage with someone to help you, make sure you keep this clear and take more and more ownership yourself as the project progresses. How much time do you have? Usually the first thing I ask is about the timeline for the project. It doesn’t matter how skilled you are, if you have a short window to get things done it’s better to get help - especially if this is your first cloud project. Having someone that knows the platform well can save you amazing amounts of time. If you have longer, then start with the training in the link above and once you feel confident, jump in. How complex is the project? If there are a lot of moving parts, it’s best to engage a partner. The reason is that certain interactions - particularly things like Service Bus or Data Integration  - can be quite different than what you may have encountered before. How many people do you have? I have a “pizza rule” about projects I’ve used in my career - if it takes over two pizzas to feed everyone on the project, it’s too big and will fail. That being said, one developer and a one-week deadline does not a good project make, usually. It’s best to have at least one architect (or someone in that role) guiding the project along, and at least two developers to work on a cloud project. That’s a generalization of course, since I’ve seen great software on Azure with one developer writing code all by herself, but for more complex projects, more (to a point) is better. The nice thing about bringing on a partner is that you don’t have to hire them full time - they help you and then they go away. How critical is the project? There’s no shame in using some help. If the platform is new, if the project is large and complex, and if it is critical to the business, you should engage a partner. That’s regardless of Cloud or anything else - get some help. You don’t want to hit your company’s bottom line in a negative way, but you have to innovate and get them a competitive advantage. Do your research, make sure the partner is qualified to help you, and get it done. Don’t let these questions scare you off. There are lots of projects you can implement on Windows and SQL Azure with nothing other than the Software Development Kit (SDK) that you get for free with Windows Azure. And assistance comes in many forms - sometimes just phone support, a friend you can ask. Microsoft Consulting Services or any of our great partners. You can get help on just the architecture piece or have them show you how to write the code. They’ll get involved as little or as much as you like.

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  • Introducing UPK 3.6 Simulation Help (You Say It and We Do It!)

    - by kathryn.lustenberger(at)oracle.com
    We would like to thank everyone that participated in the recent documentation survey that was conducted over the last several months. Your feedback is valuable and we appreciate the time you took to provide it. Many of you commented that you would like to have "UPKs for UPK" in the documentation. In response, we are pleased to announce the availability of Simulation Help. This unique help system is a blending of the text-based Developer help and a collection of approximately 200 simulations that show authors how to create, record, refine, localize, and publish content using the Developer. You can access Simulation Help at any time using the following link: http://download.oracle.com/technology/products/upk/index.html Save this link as a favorite or bookmark in your browser for easy access anytime. We have also provided a link to a short one-question survey so you can tell us what you think of the new Simulation Help. http://www.surveymonkey.com/s/BJT7LV6 Thanks again for your valuable feedback on the product documentation!

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  • How do I sort an array of Person Objects by using compareto()?

    - by Adam
    Here is my code: > import java.util.Scanner; import java.util.Arrays; /** This class tests the Person class. */ public class PersonDemo { public static void main(String[] args) { int count = 0; Scanner in = new Scanner(System.in); boolean more = false; Person first = null; Person last = null; while (more) { System.out.println( "Please enter the person's name or a blank line to quit"); String name = in.nextLine(); if (name.equals("")) more = false; else { Person p = new Person(name); //new person object created with inputted name Person[] people = new Person[10]; //new array of 10 person objects people[count] = p; //declare person object with index of variable count as the new person object first = people[count]; // I have no idea what to do here. This is where I'm stuck. last = people[count]; // I can't figure out what to do with this either. first.compareTo(p); //call compareTo method on first and new person object last.compareTo(p); //call compareTo method on last and new person object count++; // increase count variable } } System.out.println("First: " + first.toString()); System.out.println("Last: " + last.toString()); } } And the Person class: /** A person with a name. */ public class Person implements Comparable { /** * Constructs a Person with a name. * @param aName the person's name */ public Person(String aName) { name = aName; } public String getName() { return name; } @Override public int compareTo(Object otherObject) { Person other = (Person)otherObject; if (name.compareTo(other.name) < 0) return -1; if (name.compareTo(other.name) > 0) return 1; return 0; } /** Returns a string representation of the object. @return name of Person */ public String toString() { return "[name=" + name + "]"; } private String name; }

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  • Camera rotation - First Person Camera using GLM

    - by tempvar
    I've just switched from deprecated opengl functions to using shaders and GLM math library and i'm having a few problems setting up my camera rotations (first person camera). I'll show what i've got setup so far. I'm setting up my ViewMatrix using the glm::lookAt function which takes an eye position, target and up vector // arbitrary pos and target values pos = glm::vec3(0.0f, 0.0f, 10.0f); target = glm::vec3(0.0f, 0.0f, 0.0f); up = glm::vec3(0.0f, 1.0f, 0.0f); m_view = glm::lookAt(pos, target, up); i'm using glm::perspective for my projection and the model matrix is just identity m_projection = glm::perspective(m_fov, m_aspectRatio, m_near, m_far); model = glm::mat4(1.0); I send the MVP matrix to my shader to multiply the vertex position glm::mat4 MVP = camera->getProjection() * camera->getView() * model; // in shader gl_Position = MVP * vec4(vertexPos, 1.0); My camera class has standard rotate and translate functions which call glm::rotate and glm::translate respectively void camera::rotate(float amount, glm::vec3 axis) { m_view = glm::rotate(m_view, amount, axis); } void camera::translate(glm::vec3 dir) { m_view = glm::translate(m_view, dir); } and i usually just use the mouse delta position as the amount for rotation Now normally in my previous opengl applications i'd just setup the yaw and pitch angles and have a sin and cos to change the direction vector using (gluLookAt) but i'd like to be able to do this using GLM and matrices. So at the moment i have my camera set 10 units away from the origin facing that direction. I can see my geometry fine, it renders perfectly. When i use my rotation function... camera->rotate(mouseDeltaX, glm::vec3(0, 1, 0)); What i want is for me to look to the right and left (like i would with manipulating the lookAt vector with gluLookAt) but what's happening is It just rotates the model i'm looking at around the origin, like im just doing a full circle around it. Because i've translated my view matrix, shouldn't i need to translate it to the centre, do the rotation then translate back away for it to be rotating around the origin? Also, i've tried using the rotate function around the x axis to get pitch working, but as soon as i rotate the model about 90 degrees, it starts to roll instead of pitch (gimbal lock?). Thanks for your help guys, and if i've not explained it well, basically i'm trying to get a first person camera working with matrix multiplication and rotating my view matrix is just rotating the model around the origin.

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  • Title of person reporting to CEO responsible for strategy and projects [closed]

    - by user64134
    Case in point: What is the title of the person reporting directly to the CEO and/or CTO, responsible for the overall technical strategy and the overall responsibility for all projects and programs among multiple teams (being led by team leads) in a tech company I'm thinking that it is a mix of a staff and line position - making chief architect being too advisory and not matching the project/program part and VP of engineering a bit too high level?

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  • Chrome not selecting correct language for Help tab

    - by Andy
    When I click Help in Chrome, a new tab appears with the Google help links etc as expected, but I have a message saying: "This Help Centre is not currently available in your language...", etc. The drop down box at the bottom is not selected correctly for en-GB (my location). Instead it is set at the first language on the list. This happens if I am signed in to my Google account or not. Selecting English from the drop-down works ok, so no great drama. Just wondering if anybody else sees this behaviour? EDIT: Using current stable build 8.0.552.224

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  • Adding help button for each window

    - by Miraaj
    Hi all, I have found that user can associate help with his application using Help Viewer. Users typically launch Help Viewer by choosing the application help item from the Help menu, or by typing a query in the Spotlight For Help text field in the Help menu. I have some different requirement: I want to associate component specific help to my application, means that there will be a small '?' marked icon at bottom left corner of a window and when user clicks it, appropriate help page will open. This case is similar to 'print' panels where there is a small '?' icon. Can anyone suggest me some way to accomplish it, if it is possible? Thanks, Miraaj

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  • need major webcam help for project!!

    - by adam
    hey guys i have a porject where i have to be able to view my webcam on my mobile phone, which happens to be a blackberry bold 9700 but can also get a hold of an i pod touch so either phone is ok to use. the problem that i have is that everytime i do a search for help on this i end up with a program which enevitably asks for money and this is not allowd in the project, ive been trying to stream using vlc player and viewing it on the opera mini for blackberry but no such luck so far, any help would be great thanks a lot

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  • Need Tech Support? Call the Star Wars Help Desk! [Video Classic]

    - by Asian Angel
    Having problems with the Tractor Beam? Did a weapons malfunction bring your computer system down? Is the Replicator making your Earl Grey Tea taste odd? Wait…what??!! Just call the Star Wars Help Desk to get the personalized help you need. Star Wars Help Desk [YouTube] Latest Features How-To Geek ETC How to Enable User-Specific Wireless Networks in Windows 7 How to Use Google Chrome as Your Default PDF Reader (the Easy Way) How To Remove People and Objects From Photographs In Photoshop Ask How-To Geek: How Can I Monitor My Bandwidth Usage? Internet Explorer 9 RC Now Available: Here’s the Most Interesting New Stuff Here’s a Super Simple Trick to Defeating Fake Anti-Virus Malware Comix is an Awesome Comics Archive Viewer for Linux Get the MakeUseOf eBook Guide to Speeding Up Windows for Free Need Tech Support? Call the Star Wars Help Desk! [Video Classic] Reclaim Vertical UI Space by Adding a Toolbar to the Left or Right Side of Firefox Androidify Turns You into an Android-style Avatar Reader for Android Updates; Now with Feed Widgets and More

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  • Rendering skybox in first person shooter

    - by brainydexter
    I am trying to get a skybox rendered correctly in my first person shooter game. I have the skybox cube rendering using GL_TEXTURE_CUBE_MAP. I author the cube with extents of -1 and 1 along X,Y and Z. However, I can't wrap my head around the camera transformations that I need to apply to get it right. My render loop looks something like this: mp_Camera-ApplyTransform() :: Takes the current player transformation and inverts it and pushes that on the modelview stack. Draw GameObjects Draw Skybox DrawSkybox does the following: glEnable(GL_TEXTURE_CUBE_MAP); glDepthMask(GL_FALSE); // draw the cube here with extents glDisable(GL_TEXTURE_CUBE_MAP); glDepthMask(GL_TRUE); Do I need to translate the skybox by the translation of the camera ? (btw, that didn't help either) EDIT: I forgot to mention: It looks like a small cube with unit extents. Also, I can strafe in/out of the cube. Screenshot:

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  • First Person Shooter game agent development

    - by LangerHansIslands
    I would like to apply (program) the Artificial intelligence methods to create a intelligent game bots for a first person shooter game. Do you have any knowledge from where can I start to develop as a Linux user? Do you have a suggestion for an easy-to-start game for which I can develop bots easily, caring more about the result of my algorithms rather than spending a lot of time dealing with the game code? I've read some publications about the applied methods to Quake 3 (c) and Open Arena. But I couldn't find the source codes and manuals describing how to start coding( for compiling, developing ai and etc.). I appreciate your help.

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  • Referring to hardware/software in first-person? [closed]

    - by JYelton
    At my company, there is a habit for the engineers to refer to their respective hardware/firmware/software in the first-person as if the device they are responsible for is a manifestation of themselves. I'll give you an example: Hardware Engineer: "I don't receive the first byte, so I stay off." Software Engineer: "I'm sending you the first byte after the ack flag, so I thought you were getting it." Hardware Engineer: "No, you're not turning me on." It was this very example I overheard today that nearly had me giggling in fits. "You're not turning me on." Well, I should hope not! So, is it common practice for engineers to do this, or simply unprofessional? Any suggestions for changing this apparently bad habit?

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  • 2010 SQLPeople Person of the Year

    - by andyleonard
    Introduction Back in 2010, I started recognizing the SQLPeople Person of the Year. It's been a tradition ever since. "But Andy, you're writing this in 2010." Yep. Good eye, Pep. The Award Goes To: Steve Jones ( Blog | @way0utwest ). I am not a DBA - I'm a database developer. I joke and say I look like the world's greatest DBA when there's no contention, the jobs are finishing successfully, queries return data quickly and accurately, and the backups succeed. But anyone looks like the world's greatest...(read more)

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  • Tableview not updating correctly after adding person

    - by tazboy
    I have to be missing something simple here but it escapes me. After the user enters a new person to a mutable array I want to update the table. The mutable array is the datasource. I believe my issue lies within cellForRowAtIndexPath. - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { TextFieldCell *customCell = (TextFieldCell *)[tableView dequeueReusableCellWithIdentifier:@"TextCellID"]; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"cell"]; if (indexPath.row == 0) { if (customCell == nil) { NSArray *nibObjects = [[NSBundle mainBundle] loadNibNamed:@"TextFieldCell" owner:nil options:nil]; for (id currentObject in nibObjects) { if ([currentObject isKindOfClass:[TextFieldCell class]]) customCell = (TextFieldCell *)currentObject; } } customCell.nameTextField.delegate = self; cell = customCell; } else { if (cell == nil) { cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:@"cell"]; cell.textLabel.text = [[self.peopleArray objectAtIndex:indexPath.row-1] name]; NSLog(@"PERSON AT ROW %d = %@", indexPath.row-1, [[self.peopleArray objectAtIndex:indexPath.row-1] name]); NSLog(@"peopleArray's Size = %d", [self.peopleArray count]); } } return cell; } When I first load the view everything is great. This is what prints: PERSON AT ROW 0 = Melissa peopleArray's Size = 2 PERSON AT ROW 1 = Dave peopleArray's Size = 2 After I add someone to that array I get this: PERSON AT ROW 1 = Dave peopleArray's Size = 3 PERSON AT ROW 2 = Tom peopleArray's Size = 3 When I add a second person I get: PERSON AT ROW 2 = Tom peopleArray's Size = 4 PERSON AT ROW 3 = Ralph peopleArray's Size = 4 Why is not printing everyone in the array? This pattern continues and it only ever prints two people, and it's always the last two people. What the heck am I missing?

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  • Adding string items to a list of type Person C#

    - by user1862808
    Im makeing a simple registration application and I have an assignment to learn more about lists. I have an assignment that says that i am to create a class called Persons and in that class set the values from the text fields in variables and add this to a list of type Person. So far: in the Person class: string strSocialSecurityNumber = string.Empty;//---( This will not be used now.) string strFirstName = string.Empty; string strLastName = string.Empty; string strFullName = string.Empty; string strAge = string.Empty; string strAll = string.Empty; int intAge = 0; List<Person> lstPerson = new List<Person>(); public void SetValues(string FirstName, string LastName, int Age) { strFirstName = FirstName; strLastName = LastName; strFullName = strFirstName + " " + strLastName; intAge = Age; strAge = Convert.ToString(intAge); strAll = strAge + " " + strFullName; } public List<Person> Person() { lstPerson.Add(strAll); return lstPerson; } Error message: "can not convert from string to Person" The assignment says that the list is to be of the type Person so i am suppose to add strings to it and ive looked how to do this but I dont know how. I have seen that there are options like "ConvertAll" But im not sure if I am allowed to use it since the list should be of type Person. Thank you!

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  • Scientists Demonstrate First-Person Shooter Games Improve Vision

    - by Jason Fitzpatrick
    Need an excuse to log a few more hours playing Call of Duty or Medal of Honor? Scientists demonstrated improved vision in test subjects after daily doses of first-person shooter games. Scientists at McMaster University took subjects who, as the result of surgery correcting congenital cataracts, had less than 20/20 vision. Subjects played Medal of Honor for a total of 40 hours over the course of 4 weeks before having their vision retested. The results? The CBC reports: The participants found improvements in detail, perception of motion and in low contrast settings. In essence, players could now read about one to one-and-a-half more lines on an optometrist’s eye chart. “We were thrilled,” Lewis said. “It’s very exciting to open up a new world of hope for these people.” How to Get Pro Features in Windows Home Versions with Third Party Tools HTG Explains: Is ReadyBoost Worth Using? HTG Explains: What The Windows Event Viewer Is and How You Can Use It

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  • Stuff every programmer needs while working

    - by Desai Shukla
    I've been tasked with creating a fun and relaxing environment, one thing I know that I want is ergonomic mice and keyboards, others have suggested exercise balls and bands. What is it that every programmer needs while working? What might not be necessary but would be nice to have anyway? Note: this question was asked previously, but has been recommended to be posted here. See this link for the previous responses: http://stackoverflow.com/questions/3911911/stuff-every-programmer-needs-while-working-closed

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