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  • Google Chrome Omnibox truncating searches after "#" - I.E. "c# foo" becomes "c"

    - by tony722
    I have recently been finding myself stymied trying to perform searches for c#-related things in Chrome. The problem is that the omnibox truncates the # and everything after it. This means typing c# foo" in the omnibox in Chrome and hitting enter returns highly unhelpful search results for "c" Google. Any tricks or extensions that would allow me to type "c# foo" into the omnibox and return results that are related to c# and foo? Am I the only person with this problem?

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  • foo and _foo - about variables inside a class

    - by kame
    class ClassName(object): """ """ def __init__(self, foo, bar): """ """ self.foo = foo # read-write property self.bar = bar # simple attribute def _set_foo(self, value): self._foo = value def _get_foo(self): return self._foo foo = property(_get_foo, _set_foo) a = ClassName(1,2) #a._set_foo(3) print a._get_foo() When I print a._get_foo() the function _get_foo prints the variable self._foo . But where does it come from? self._foo and self.foo are different, aren't they?

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  • bash dirtrim produces strange results with ~/foo/bar/var directory

    - by queueoverflow
    In some of my projects, I keep a var or a lib folder for runtime output and external libraries. To keep my prompt rather short, I have the export PROMPT_DIRTRIM=3 option in my .bashrc. This works very well for most paths, but as soon as I have a /var in there, it goes nuts like this (for ~/Projects/someproject/var/gfx): ~/.../gfxr/gfxr/gfxr/gfxr/gfxr/gfx Interestingly, it works with /opt/lampp/lib Is there some way to get around this? Update my .bashrc my .bash_functions

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  • Do you Kung Foo? [closed]

    - by Darknight
    As a programmer who also trains in martial arts (Wing Tsun + Escrima + Judo). I am really interested to know if there are other fellow programmers who also practice martial arts. Do you practice martial arts? or do you know of programmers who practice martial arts. Further question: Do you see any analogy between your art and programming. [Apologies for the terrible pun in the title :) but I do like it cheesy...]

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  • Is it okay to define a [] method in ruby's NilClass?

    - by Silasj
    Ruby by default does not include the method [] for NilClass For example, to check if foo["bar"] exists when foo may be nil, I have to do: foo = something_that_may_or_may_not_return_nil if foo && foo["bar"] # do something with foo["bar"] here end If I define this method: class NilClass def [](arg) nil end end Something like that would make this possible, even if foo is nil: if foo["bar"] # do something with foo["bar"] end Or even: if foo["bar"]["baz"] # do something with foo["bar"]["baz"] here end Question: Is this a good idea or is there some reason ruby doesn't include this functionality by default?

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  • What's with "foo" and "bar" [closed]

    - by Matt S.
    Possible Duplicates: When foo and bar is not enough Code examples Foo Bar I've always wondered, why is there always "foo" and "bar" named as variables in most tutorials I've seen. Where did it come from? Why do we call them "foo" and "bar" why not something else?

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  • Partial overriding in Java (or dynamic overriding while overloading)

    - by Lie Ryan
    If I have a parent-child that defines some method .foo() like this: class Parent { public void foo(Parent arg) { System.out.println("foo in Function"); } } class Child extends Parent { public void foo(Child arg) { System.out.println("foo in ChildFunction"); } } When I called them like this: Child f = new Child(); Parent g = f; f.foo(new Parent()); f.foo(new Child()); g.foo(new Parent()); g.foo(new Child()); the output is: foo in Parent foo in Child foo in Parent foo in Parent But, I want this output: foo in Parent foo in Child foo in Parent foo in Child I have a Child class that extends Parent class. In the Child class, I want to "partially override" the Parent's foo(), that is, if the argument arg's type is Child then Child's foo() is called instead of Parent's foo(). That works Ok when I called f.foo(...) as a Child; but if I refer to it from its Parent alias like in g.foo(...) then the Parent's foo(..) get called irrespective of the type of arg. As I understand it, what I'm expecting doesn't happen because method overloading in Java is early binding (i.e. resolved statically at compile time) while method overriding is late binding (i.e. resolved dynamically at compile time) and since I defined a function with a technically different argument type, I'm technically overloading the Parent's class definition with a distinct definition, not overriding it. But what I want to do is conceptually "partially overriding" when .foo()'s argument is a subclass of the parent's foo()'s argument. I know I can define a bucket override foo(Parent arg) in Child that checks whether arg's actual type is Parent or Child and pass it properly, but if I have twenty Child, that would be lots of duplication of type-unsafe code. In my actual code, Parent is an abstract class named "Function" that simply throws NotImplementedException(). The children includes "Polynomial", "Logarithmic", etc and .foo() includes things like Child.add(Child), Child.intersectionsWith(Child), etc. Not all combination of Child.foo(OtherChild) are solvable and in fact not even all Child.foo(Child) is solvable. So I'm best left with defining everything undefined (i.e. throwing NotImplementedException) then defines only those that can be defined. So the question is: Is there any way to override only part the parent's foo()? Or is there a better way to do what I want to do?

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  • Container of Generic Types in java

    - by Cyker
    I have a generic class Foo<T> and parameterized types Foo<String> and Foo<Integer>. Now I want to put different parameterized types into a single ArrayList. What is the correct way of doing this? Candidate 1: public class MMM { public static void main(String[] args) { Foo<String> fooString = new Foo<String>(); Foo<Integer> fooInteger = new Foo<Integer>(); ArrayList<Foo<?> > list = new ArrayList<Foo<?> >(); list.add(fooString); list.add(fooInteger); for (Foo<?> foo : list) { // Do something on foo. } } } class Foo<T> {} Candidate 2: public class MMM { public static void main(String[] args) { Foo<String> fooString = new Foo<String>(); Foo<Integer> fooInteger = new Foo<Integer>(); ArrayList<Foo> list = new ArrayList<Foo>(); list.add(fooString); list.add(fooInteger); for (Foo foo : list) { // Do something on foo. } } } class Foo<T> {} In a word, it is related to the difference between Foo<?> and the raw type Foo. Update: Grep What is the difference between the unbounded wildcard parameterized type and the raw type? on this link may be helpful.

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  • mod_rewrite to find missing /img/foo.jpg in /img/f/

    - by Ambrose
    I've got a folder of images which is reaching a critical mass after a few years. I want to move images into alphabetical folders, so that /img/foo.jpg goes into /img/f/foo.jpg and /img/bar.jpg goes into /img/b/bar.jpg and so on. In order to make the transition smooth, and to allow the manual uploaders to put stuff into the top level, I'd like to use mod_rewrite to do this: if /img/foo.jpg exists, serve it up, if not look for it in /img/f/foo.jpg thanks for any suggestions. For the record, no, I don't think we need to go /img/f/fo/foo.jpg just yet.

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  • Why, in Ruby, does Array("foo\nbar") == ["foo\n", "bar"]?

    - by Tyson
    In Ruby 1.8.7, Array("hello\nhello") gives you ["hello\n", "hello"]. This does two things that I don't expect: It splits the string on newlines. I'd expect it simply to give me an array with the string I pass in as its single element without modifying the data I pass in. Even if you accept that it's reasonable to split a string when passing it to Array, why does it retain the newline character when "foo\nbar".split does not? Additionally: >> Array.[] "foo\nbar" => ["foo\nbar"] >> Array.[] *"foo\nbar" => ["foo\n", "bar"]

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  • zsh: Do NOT expand wildcard on tab completion

    - by BMorgenthaler
    I'm wondering how I can configure ZSH to NOT expand the wildcard in a filename. So for example I have a directory of a couple hundred files named like so: a.foo-bar a.foo b.foo-bar b.foo c.foo-bar c.foo I would like to be able to perform a tab completion matching AFTER a wildcard, so cat *.foo-< tab = cat *.foo-bar instead what I get is cat *.foo-< tab = cat a.foo-bar file a.foo-bar b.foo-bar c.foo-bar

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  • Regular expression to remove one parameter from query string

    - by Kip
    I'm looking for a regular expression to remove a single parameter from a query string, and I want to do it in a single regular expression if possible. Say I want to remove the foo parameter. Right now I use this: /&?foo\=[^&]+/ That works as long as foo is not the first parameter in the query string. If it is, then my new query string starts with an ampersand. (For example, "foo=123&bar=456" gives a result of "&bar=456".) Right now, I'm just checking after the regex if the query string starts with ampersand, and chopping it off if it does. Example edge cases: Input | Output -------------------------+----------------- foo=123 | (empty string) foo=123&bar=456 | bar=456 bar=456&foo=123 | bar=456 abc=789&foo=123&bar=456 | abc=789&bar=456 Edit OK as pointed out in comments there are there are way more edge cases than I originally considered. I got the following regex to work with all of them: /&foo(\=[^&]*)?(?=&|$)|^foo(\=[^&]*)?(&|$)/ This is modified from Mark Byers's answer, which is why I'm accepting that one, but Roger Pate's input helped a lot too. Here is the full suite of test cases I'm using, and a Perl script which tests them. Input | Output -------------------------+------------------- foo | foo&bar=456 | bar=456 bar=456&foo | bar=456 abc=789&foo&bar=456 | abc=789&bar=456 foo= | foo=&bar=456 | bar=456 bar=456&foo= | bar=456 abc=789&foo=&bar=456 | abc=789&bar=456 foo=123 | foo=123&bar=456 | bar=456 bar=456&foo=123 | bar=456 abc=789&foo=123&bar=456 | abc=789&bar=456 xfoo | xfoo xfoo&bar=456 | xfoo&bar=456 bar=456&xfoo | bar=456&xfoo abc=789&xfoo&bar=456 | abc=789&xfoo&bar=456 xfoo= | xfoo= xfoo=&bar=456 | xfoo=&bar=456 bar=456&xfoo= | bar=456&xfoo= abc=789&xfoo=&bar=456 | abc=789&xfoo=&bar=456 xfoo=123 | xfoo=123 xfoo=123&bar=456 | xfoo=123&bar=456 bar=456&xfoo=123 | bar=456&xfoo=123 abc=789&xfoo=123&bar=456 | abc=789&xfoo=123&bar=456 foox | foox foox&bar=456 | foox&bar=456 bar=456&foox | bar=456&foox abc=789&foox&bar=456 | abc=789&foox&bar=456 foox= | foox= foox=&bar=456 | foox=&bar=456 bar=456&foox= | bar=456&foox= abc=789&foox=&bar=456 | abc=789&foox=&bar=456 foox=123 | foox=123 foox=123&bar=456 | foox=123&bar=456 bar=456&foox=123 | bar=456&foox=123 abc=789&foox=123&bar=456 | abc=789&foox=123&bar=456 Test script (Perl) @in = ('foo' , 'foo&bar=456' , 'bar=456&foo' , 'abc=789&foo&bar=456' ,'foo=' , 'foo=&bar=456' , 'bar=456&foo=' , 'abc=789&foo=&bar=456' ,'foo=123' , 'foo=123&bar=456' , 'bar=456&foo=123' , 'abc=789&foo=123&bar=456' ,'xfoo' , 'xfoo&bar=456' , 'bar=456&xfoo' , 'abc=789&xfoo&bar=456' ,'xfoo=' , 'xfoo=&bar=456' , 'bar=456&xfoo=' , 'abc=789&xfoo=&bar=456' ,'xfoo=123', 'xfoo=123&bar=456', 'bar=456&xfoo=123', 'abc=789&xfoo=123&bar=456' ,'foox' , 'foox&bar=456' , 'bar=456&foox' , 'abc=789&foox&bar=456' ,'foox=' , 'foox=&bar=456' , 'bar=456&foox=' , 'abc=789&foox=&bar=456' ,'foox=123', 'foox=123&bar=456', 'bar=456&foox=123', 'abc=789&foox=123&bar=456' ); @exp = ('' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'xfoo' , 'xfoo&bar=456' , 'bar=456&xfoo' , 'abc=789&xfoo&bar=456' ,'xfoo=' , 'xfoo=&bar=456' , 'bar=456&xfoo=' , 'abc=789&xfoo=&bar=456' ,'xfoo=123', 'xfoo=123&bar=456', 'bar=456&xfoo=123', 'abc=789&xfoo=123&bar=456' ,'foox' , 'foox&bar=456' , 'bar=456&foox' , 'abc=789&foox&bar=456' ,'foox=' , 'foox=&bar=456' , 'bar=456&foox=' , 'abc=789&foox=&bar=456' ,'foox=123', 'foox=123&bar=456', 'bar=456&foox=123', 'abc=789&foox=123&bar=456' ); print "Succ | Input | Output | Expected \n"; print "-----+--------------------------+--------------------------+-------------------------\n"; for($i=0; $i <= $#in; $i++) { $out = $in[$i]; $out =~ s/_PUT_REGEX_HERE_//; $succ = ($out eq $exp[$i] ? 'PASS' : 'FAIL'); #if($succ eq 'FAIL') #{ printf("%s | %- 24s | %- 24s | %- 24s\n", $succ, $in[$i], $out, $exp[$i]); #} }

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  • Why use "foo" in coding examples? [closed]

    - by ThePower
    Possible Duplicates: To foo bar, or not to foo bar: that is the question. Bit of a general question here, but it's something I would like to know! Whenever I am looking for resolutions to my C# problems online, I always come across "foo" being used as an example. Does this represent anything or is it just one of those unexplained catchy object names, used by many people in examples?

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  • How can I have a Foo* iterator to a vector of Foo?

    - by mghie
    If I have a class that contains a std::list<Foo>, how can I implement iterators to a Foo* collection, preferably without using boost? I'd rather not maintain a parallel collection of pointers. For now I have std::list<Foo>, mostly so that removing or inserting an element does not invalidate all other iterators, but would it be possible to implement other iterators too, so that the collection type used in the implementation is opaque to the user of the class?

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  • .htaccess to redirect any URL from a domain to a fixed URL on another domain

    - by AlexV
    Anyone can help me out with an .htaccess I'm trying to create? I want to redirect foo.com to foo.ca. Any URL from foo.com (with or without www and under http or https) will all be redirected to www.foo.ca. Some examples: http://www.foo.com/ -- http://www.foo.ca/ (http + www) https://www.foo.com/ -- http://www.foo.ca/ (https + www) http://foo.com/bar/ -- http://www.foo.ca/ (http + some url) https://foo.com/bar/ -- http://www.foo.ca/ (https + some url) http://www.foo.com/bar/ -- http://www.foo.ca/ (http + www + some url) https://www.foo.com/bar -- http://www.foo.ca/ (https + www + some url) Many thanks!

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  • RPM Spec How to specify in package so that previous RPM is removed

    - by user123819
    Question: What do I put in the foo.spec file so that the rpm's will remove the previous rpm before installing? Description: I have created a spec file that creates rpm's for a few packages that use the same source and provide the same service, each with a slightly different configuration. E.g. they each provide the same "capability" Here's an example of the essentials that my .spec file looks like: %define version 1234 %define name foo %define release 1 %define pkgname %{name}-%{version}-%{release} Name: %{name} Version: %{version} Release: %{release} Provides: %{name} %package one Summary: Summary for foo-one Group: %{group} Obsoletes: %{name} <= %{version} Provides: %{name} = %{version} %description one Blah blah blah %package two Summary: Summary for foo-two Group: %{group} Obsoletes: %{name} <= %{version} Provides: %{name} = %{version} %description two Blah blah blah # %prep, %install, %build and %clean are pretty simple # and omitted here for brevity sake %files one %defattr(-,root,root,-) %{_prefix}/%{pkgname} %files two %defattr(-,root,root,-) %{_prefix}/%{pkgname} When I install the first one, it installs ok. I then remove the first one, and then install the second one, that works fine too. I then install the first one, followed immediately by installing the second one, and they both install, one over the other, but, I was expecting that the second one would be removed before installing the second. Example session: # rpmbuild foo and copy rpms to yum repo $ yum install foo-one ... $ yum list installed|grep foo foo-one.noarch 1234-1 @myrepo $ yum install foo-two ...[Should say that it is removing foo-one, but does not]... $ yum list installed|grep foo foo-one.noarch 1234-1 @myrepo foo-two.noarch 1234-1 @myrepo $ rpm -q --provides foo-one foo = 1234 foo-one = 1234-1 $ rpm -q --provides foo-two foo = 1234 foo-two = 1234-1 What do I put in the foo.spec file so that the rpm's will remove the previous rpm before installing? Thank you, .dave.

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  • Unable to load DLL 'foo.dll', but only when running through vhost

    - by biozinc
    This is a variation on the old System.DllNotFoundException: Unable to load DLL 'foo.dll': The specified module could not be found. (Exception from HRESULT: 0x8007007E). problem (where, of course, foo.dll is the name of an actual DLL). The strange part is that I only get this error when I "Run" in VS (2008 if that's relevant). That sits in the MyApp.vhost.exe processes. If I run the actual app in a command line (MyApp.exe) I encounter no errors. The problem extends to unit tests with MSTest. A check on the DLL with DependencyWalker on Foo.dll doesn't show any issues. Any ideas?

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  • How to generate a specific CPPDEFINE such as -DOEM="FOO BAR" using Scons

    - by Vineet
    My intention is to end up with a compiler command line including -DOEM="FOO BAR" I have the following in my SConstruct file: opts = Options( 'overrides.py', ARGUMENTS ) opts.Add( 'OEM_NAME', 'Any string can be used here', 'UNDEFINED' ) . . . if (env.Dictionary('OEM_NAME') != 'UNDEFINED'): OEM_DEFINE = 'OEM=' + str(env.Dictionary('OEM_NAME')) env.Append( CPPDEFINES=[ OEM_DEFINE ] ) Then I put the following in the "overrides.py" file: OEM_NAME = "FOO BAR" I seem to end up with "-DOEM=FOO BAR" in the command line that gets generated. Can someone point me in the right direction? Thanks.

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  • (solved) `ssh foo "<command/>"` not loading remote aliases?

    - by TomRoche
    summary: Why does this fail $ ssh foo 'R --version | head -n 1' bash: R: command not found but this succeeds $ ssh foo 'grep -nHe 'bashrc' ~/.bash_profile' /home/me/.bash_profile:3:# source the users .bashrc if it exists /home/me/.bash_profile:4:if [ -f "${HOME}/.bashrc" ] ; then /home/me/.bash_profile:5: source "${HOME}/.bashrc" $ ssh foo 'grep -nHe "\WR\W" ~/.bashrc' /home/me/.bashrc:118:alias R='/share/linux86_64/bin/R' $ ssh foo '/share/linux86_64/bin/R --version | head -n 1' R version 2.14.1 (2011-12-22) ? details: I am a (rootless) user on 2 clusters. One uses environment modules, so any given server on that cluster can provide (via module add) pretty much the same resources. The other cluster, on which I must also unfortunately work, has servers managed individually, so I get in the habit of doing, e.g., EXEC_NAME='whatever' for S in 'foo' 'bar' 'baz' ; do ssh ${SERVER} "${EXEC_NAME} --version" done This works fine for packages installed normally/consistently, but often (for reasons unknown to me) packages are not: e.g. (compare alias below to alias above), $ ssh bar 'R --version | head -n 1' bash: R: command not found $ ssh bar 'grep -nHe 'bashrc' ~/.bash_profile' /home/me/.bash_profile:3:# source the users .bashrc if it exists /home/me/.bash_profile:4:if [ -f "${HOME}/.bashrc" ] ; then /home/me/.bash_profile:5: source "${HOME}/.bashrc" $ ssh bar 'grep -nHe "\WR\W" ~/.bashrc' /home/me/.bashrc:118:alias R='/share/linux/bin/R' $ ssh bar '/share/linux86_64/bin/R --version | head -n 1' R version 2.14.1 (2011-12-22) Using aliases copes well with these install differences when I interactively shell into the server, but fails when I try to script ssh commands (as above); i.e., # interactively $ ssh foo ... foo> R --version calls my alias for R on remote host=foo, but # scripting $ ssh foo 'R --version' doesn't. What do I need to do to make ssh foo "<command/>" load my aliases on the remote host?

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  • [Ruby] Object assignment and pointers

    - by Jergason
    I am a little confused about object assignment and pointers in Ruby, and coded up this snippet to test my assumptions. class Foo attr_accessor :one, :two def initialize(one, two) @one = one @two = two end end bar = Foo.new(1, 2) beans = bar puts bar puts beans beans.one = 2 puts bar puts beans puts beans.one puts bar.one I had assumed that when I assigned bar to beans, it would create a copy of the object, and modifying one would not affect the other. Alas, the output shows otherwise. ^_^[jergason:~]$ ruby test.rb #<Foo:0x100155c60> #<Foo:0x100155c60> #<Foo:0x100155c60> #<Foo:0x100155c60> 2 2 I believe that the numbers have something to do with the address of the object, and they are the same for both beans and bar, and when I modify beans, bar gets changed as well, which is not what I had expected. It appears that I am only creating a pointer to the object, not a copy of it. What do I need to do to copy the object on assignment, instead of creating a pointer? Tests with the Array class shows some strange behavior as well. foo = [0, 1, 2, 3, 4, 5] baz = foo puts "foo is #{foo}" puts "baz is #{baz}" foo.pop puts "foo is #{foo}" puts "baz is #{baz}" foo += ["a hill of beans is a wonderful thing"] puts "foo is #{foo}" puts "baz is #{baz}" This produces the following wonky output: foo is 012345 baz is 012345 foo is 01234 baz is 01234 foo is 01234a hill of beans is a wonderful thing baz is 01234 This blows my mind. Calling pop on foo affects baz as well, so it isn't a copy, but concatenating something onto foo only affects foo, and not baz. So when am I dealing with the original object, and when am I dealing with a copy? In my own classes, how can I make sure that assignment copies, and doesn't make pointers? Help this confused guy out.

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  • XPath Query - Select relative top level nodes

    - by John
    I'm trying to iterate over some elements in an XML document that may be nested, but as I iterate over them I may be removing some from the tree. I'm thinking the best way is to do this recursively, so I'm trying to come up with an XPath Query that will select all the top-level nodes relative to the current node. //foo[not(ancestor::foo)] works great at the document level, but I'm trying to figure out how to do this from a relative query. <foo id="1"> <foo id="2" /> <foo id="3"> <foo id="4"> <bar> <foo id="5"> <foo id="6" /> </foo> <foo id="7" /> </bar> </foo> </foo> </foo> If the current node is foo#3, I only want to select foo#4. When the current node is foo#4, I only want to select foo#5 and foo#7. I think I'm trying to select any descendant foo nodes of the current node, but without any ancestor foo nodes between the current node and the node I'm selecting. My conundrum is if we're already inside a foo node, not(ancestor::foo) doesn't help.

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