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  • How to read spring-application-context.xml and AnnotationConfigWebApplicationContext both in spring mvc

    - by Suvasis
    In case I want to read bean definitions from spring-application-context.xml, I would do this in web.xml file. <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/applicationContext.xml </param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> In case I want to read bean definitions through Java Configuration Class (AnnotationConfigWebApplicationContext), I would do this in web.xml <servlet> <servlet-name>appServlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextClass</param-name> <param-value> org.springframework.web.context.support.AnnotationConfigWebApplicationContext </param-value> </init-param> <init-param> <param-name>contextConfigLocation</param-name> <param-value> org.package.MyConfigAnnotatedClass </param-value> </init-param> </servlet> How do I use both in my application. like reading beans from both configuration xml file and annotated class. Is there a way to load spring beans in xml file while we are using AppConfigAnnotatedClass to instantiate/use rest of the beans.

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  • Howcan I get started with Spring Batch?

    - by C. Ross
    I'm trying to learn Spring Batch, but the startup guide is very confusing. Comments like You can get a pretty good idea about how to set up a job by examining the unit tests in the org.springframework.batch.sample package (in src/main/java) and the configuration in src/main/resources/jobs. aren't exactly helpful. Also I find the Sample project very complicated (17 non-empty Namespaces with 109 classes)! Is there a simpler place to get started with Spring Batch?

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  • What are annotations and how do they actually work for frameworks like Spring?

    - by Rachel
    I am new to Spring and now a days I hear a lot about Spring Framework. I have two sets of very specific questions: Set No. 1: What are annotations in general ? How does annotations works specifically with Spring framework ? Can annotations be used outside Spring Framework or are they Framework specific ? Set No. 2: What module of Spring Framework is widely used in Industry ? I think it is Spring MVC but why it is the most used module, if am correct or correct me on this ? I am newbie to Spring and so feel free to edit this questions to make more sense.

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  • What is annotations and how do it actually works for frameworks like Spring ?

    - by Rachel
    I am new to Spring and now a days I hear a lot about Spring Framework. I have two sets of very specific questions: Set No. 1: What are annotations in general ? How does annotations works specifically with Spring framework ? Can annotations be used outside Spring Framework or are they Framework specific ? Set No. 2: What module of Spring Framework is widely used in Industry ? I think it is Spring MVC but why it is the most used module, if am correct or correct me on this ? I am newbie to Spring and so feel free to edit this questions to make more sense.

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  • Getting rejected value null spring validation

    - by Shabarinath
    Hi in my project when I am trying to validate my form its not showing any error messages even if validation fails (Event Form is not submitted and enters into validation fail block) Here is my code /****************** Post Method *************/ @RequestMapping(value="/property", method = RequestMethod.POST) public String saveOrUpdateProperty(@ModelAttribute("property") Property property, BindingResult result, Model model, HttpServletRequest request) throws Exception { try { if(validateFormData(property, result)) { model.addAttribute("property", new Property()); return "property/postProperty"; } } /********* Validate Block *************/ private boolean validateFormData(Property property, BindingResult result) throws DaoException { if (property.getPropertyType() == null || property.getPropertyType().equals("")) { result.rejectValue("propertyType", "Cannot Be Empty !", "Cannot Be Empty !"); } if (property.getTitle() == null || property.getTitle().equals("")) { result.rejectValue("title", "Cannot Be Empty !", "Cannot Be Empty !"); } return (result.hasFieldErrors() || result.hasErrors()); } But when i debug i can see below one org.springframework.validation.BeanPropertyBindingResult: 1 errors Field error in object 'property' on field 'title': rejected value [null]; codes [Cannot Be Empty !.property.title,Cannot Be Empty !.title,Cannot Be Empty !.java.lang.String,Cannot Be Empty !]; arguments []; default message [Cannot Be Empty !] and this is how i am displaying in jsp file <div class="control-group"> <div class="controls"> <label class="control-label"><span class="required">* </span>Property Type</label> <div class="controls"> <form:input path="title" placeholder="Pin Code" cssClass="form-control border-radius-4 textField"/> <form:errors path="title" style="color:red;"/> </div> </div> </div> Event though when i see the below one when i debug (1 Error its correct) org.springframework.validation.BeanPropertyBindingResult: 1 errors Why it is not displayed in jsp can any one hep me?

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  • Spring @PostConstruct function in a @Repository called multiple times

    - by Seth
    I have a DAO that I'm trying to inject into a couple different places: @Repository public class FooDAO { @Autowired private HibernateManager sessionFactory; @PostConstruct public void doSomeDatabaseStuff() throws DataAccessException { ... } } And my application-context.xml is a fairly simple context:component-scan: <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd" default-init-method="init" default-destroy-method="destroy"> <context:component-scan base-package="top.level"/> </beans> The DAO is accessed from a couple servlets in my application server through @Autowired properties. As far as I understand, anything annotated with @Repository should default to being a singleton and thus doSomeDatabaseStuff() should only be called once (as is my intention). The problem is that I'm seeing doSomeDatabaseStuff() called multiple times. What's going on here? Have I set something up incorrectly? I'm using spring 3.0.0. Thanks for the help.

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  • Spring security - Reach users ID without passing it through every controller

    - by nilsi
    I have a design issue that I don't know how to solve. I'm using Spring 3.2.4 and Spring security 3.1.4. I have a Account table in my database that looks like this: create table Account (id identity, username varchar unique, password varchar not null, firstName varchar not null, lastName varchar not null, university varchar not null, primary key (id)); Until recently my username was just only a username but I changed it to be the email address instead since many users want to login with that instead. I have a header that I include on all my pages which got a link to the users profile like this: <a href="/project/users/<%= request.getUserPrincipal().getName()%>" class="navbar-link"><strong><%= request.getUserPrincipal().getName()%></strong></a> The problem is that <%= request.getUserPrincipal().getName()%> returns the email now, I don't want to link the user's with thier emails. Instead I want to use the id every user have to link to the profile. How do I reach the users id's from every page? I have been thinking of two solutions but I'm not sure: Change the principal to contain the id as well, don't know how to do this and having problem finding good information on the topic. Add a model attribute to all my controllers that contain the whole user but this would be really ugly, like this. Account account = entityManager.find(Account.class, email); model.addAttribute("account", account); There are more way's as well and I have no clue which one is to prefer. I hope it's clear enough and thank you for any help on this. ====== Edit according to answer ======= I edited Account to implement UserDetails, it now looks like this (will fix the auto generated stuff later): @Entity @Table(name="Account") public class Account implements UserDetails { @Id private int id; private String username; private String password; private String firstName; private String lastName; @ManyToOne private University university; public Account() { } public Account(String username, String password, String firstName, String lastName, University university) { this.username = username; this.password = password; this.firstName = firstName; this.lastName = lastName; this.university = university; } public String getUsername() { return username; } public String getPassword() { return password; } public String getFirstName() { return firstName; } public String getLastName() { return lastName; } public void setUsername(String username) { this.username = username; } public void setPassword(String password) { this.password = password; } public void setFirstName(String firstName) { this.firstName = firstName; } public void setLastName(String lastName) { this.lastName = lastName; } public University getUniversity() { return university; } public void setUniversity(University university) { this.university = university; } public int getId() { return id; } public void setId(int id) { this.id = id; } @Override public Collection<? extends GrantedAuthority> getAuthorities() { // TODO Auto-generated method stub return null; } @Override public boolean isAccountNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isAccountNonLocked() { // TODO Auto-generated method stub return false; } @Override public boolean isCredentialsNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isEnabled() { // TODO Auto-generated method stub return true; } } I also added <%@ taglib prefix="sec" uri="http://www.springframework.org/security/tags" %> To my jsp files and trying to reach the id by <sec:authentication property="principal.id" /> This gives me the following org.springframework.beans.NotReadablePropertyException: Invalid property 'principal.id' of bean class [org.springframework.security.authentication.UsernamePasswordAuthenticationToken]: Bean property 'principal.id' is not readable or has an invalid getter method: Does the return type of the getter match the parameter type of the setter? ====== Edit 2 according to answer ======= I based my application on spring social samples and I never had to change anything until now. This are the files I think are relevant, please tell me if theres something you need to see besides this. AccountRepository.java public interface AccountRepository { void createAccount(Account account) throws UsernameAlreadyInUseException; Account findAccountByUsername(String username); } JdbcAccountRepository.java @Repository public class JdbcAccountRepository implements AccountRepository { private final JdbcTemplate jdbcTemplate; private final PasswordEncoder passwordEncoder; @Inject public JdbcAccountRepository(JdbcTemplate jdbcTemplate, PasswordEncoder passwordEncoder) { this.jdbcTemplate = jdbcTemplate; this.passwordEncoder = passwordEncoder; } @Transactional public void createAccount(Account user) throws UsernameAlreadyInUseException { try { jdbcTemplate.update( "insert into Account (firstName, lastName, username, university, password) values (?, ?, ?, ?, ?)", user.getFirstName(), user.getLastName(), user.getUsername(), user.getUniversity(), passwordEncoder.encode(user.getPassword())); } catch (DuplicateKeyException e) { throw new UsernameAlreadyInUseException(user.getUsername()); } } public Account findAccountByUsername(String username) { return jdbcTemplate.queryForObject("select username, firstName, lastName, university from Account where username = ?", new RowMapper<Account>() { public Account mapRow(ResultSet rs, int rowNum) throws SQLException { return new Account(rs.getString("username"), null, rs.getString("firstName"), rs.getString("lastName"), new University("test")); } }, username); } } security.xml <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd"> <http pattern="/resources/**" security="none" /> <http pattern="/project/" security="none" /> <http use-expressions="true"> <!-- Authentication policy --> <form-login login-page="/signin" login-processing-url="/signin/authenticate" authentication-failure-url="/signin?error=bad_credentials" /> <logout logout-url="/signout" delete-cookies="JSESSIONID" /> <intercept-url pattern="/addcourse" access="isAuthenticated()" /> <intercept-url pattern="/courses/**/**/edit" access="isAuthenticated()" /> <intercept-url pattern="/users/**/edit" access="isAuthenticated()" /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder ref="passwordEncoder" /> <jdbc-user-service data-source-ref="dataSource" users-by-username-query="select username, password, true from Account where username = ?" authorities-by-username-query="select username, 'ROLE_USER' from Account where username = ?"/> </authentication-provider> <authentication-provider> <user-service> <user name="admin" password="admin" authorities="ROLE_USER, ROLE_ADMIN" /> </user-service> </authentication-provider> </authentication-manager> </beans:beans> And this is my try of implementing a UserDetailsService public class RepositoryUserDetailsService implements UserDetailsService { private final AccountRepository accountRepository; @Autowired public RepositoryUserDetailsService(AccountRepository repository) { this.accountRepository = repository; } @Override public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException { Account user = accountRepository.findAccountByUsername(username); if (user == null) { throw new UsernameNotFoundException("No user found with username: " + username); } return user; } } Still gives me the same error, do I need to add the UserDetailsService somewhere? This is starting to be something else compared to my initial question, I should maybe start another question. Sorry for my lack of experience in this. I have to read up.

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  • Infinite loop using Spring Security - Login page is protected even though it should allow anonymous

    - by Tai Squared
    I have a Spring application (Spring version 2.5.6.SEC01, Spring Security version 2.0.5) with the following setup: web.xml <welcome-file-list> <welcome-file> index.jsp </welcome-file> </welcome-file-list> The index.jsp page is in the WebContent directory and simply contains a redirect: <c:redirect url="/login.htm"/> In the appname-servlet.xml, there is a view resolver to point to the jsp pages in WEB-INF/jsp <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> In the security-config.xml file, I have the following configuration: <http> <!-- Restrict URLs based on role --> <intercept-url pattern="/WEB-INF/jsp/login.jsp*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/WEB-INF/jsp/header.jsp*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/WEB-INF/jsp/footer.jsp*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/login*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/index.jsp" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/logoutSuccess*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/css/**" filters="none" /> <intercept-url pattern="/images/**" filters="none" /> <intercept-url pattern="/**" access="ROLE_ANONYMOUS" /> <form-login login-page="/login.jsp"/> </http> <authentication-provider> <jdbc-user-service data-source-ref="dataSource" /> </authentication-provider> However, I can't even navigate to the login page and get the following error in the log: WARNING: The login page is being protected by the filter chain, but you don't appear to have anonymous authentication enabled. This is almost certainly an error. I've tried changing the ROLE_ANONYMOUS to IS_AUTHENTICATED_ANONYMOUSLY, changing the login-page to index.jsp, login.htm, and adding different intercept-url values, but I can't get it so the login page is accesible and security applies to the other pages. What do I have to change to avoid this loop?

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  • How to expose an entity via alternate keys with spring data rest

    - by dan carter
    Spring-data-rest does a great job exposing entities via their primary key for GET, PUT and DELETE etc. operations. /myentityies/123 It also exposes search operations. /myentities/search/byMyOtherKey?myOtherKey=123 In my case the entities have a number of alternate keys. The systems calling us, will know the objects by these IDs, rather than our internal primary key. Is it possible to expose the objects via another URL and have the GET, PUT and DELETE handled by the built-in spring-data-rest controllers? /myentities/myotherkey/456 We'd like to avoid forcing the calling systems to have to make two requests for each update. I've tried playing with @RestResource path value, but there doesn't seem to be a way to add additional paths.

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  • Spring - Redirect after POST (even with validation errors)

    - by Taylor L
    I'm trying to figure out how to "preserve" the BindingResult so it can be used in a subsequent GET via the Spring <form:errors> tag. The reason I want to do this is because of Google App Engine's SSL limitations. I have a form which is displayed via HTTP and the post is to an HTTPS URL. If I only forward rather than redirect then the user would see the https://whatever.appspot.com/my/form URL. I'm trying to avoid this. Any ideas how to approach this? Below is what I'd like to do, but I only see validation errors when I use return "create". @RequestMapping(value = "/submit", method = RequestMethod.POST) public final String submit( @ModelAttribute("register") @Valid final Register register, final BindingResult binding) { if (binding.hasErrors()) { return "redirect:/register/create"; } return "redirect:/register/success"; }

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  • No flow definition found. Spring web flow

    - by user184794
    Hi, I am new to Spring webflow and now I am trying the example in Spring recipes book and I know this is a basic question. I am getting the error as follows, org.springframework.webflow.definition.registry.NoSuchFlowDefinitionException: No flow definition '${flowExecutionUrl}&_eventId=next' found at org.springframework.webflow.definition.registry.FlowDefinitionRegistryImpl.getFlowDefinitionHolder(FlowDefinitionRegistryImpl.java:126) at org.springframework.webflow.definition.registry.FlowDefinitionRegistryImpl.getFlowDefinition(FlowDefinitionRegistryImpl.java:61) at org.springframework.webflow.executor.FlowExecutorImpl.launchExecution(FlowExecutorImpl.java:138) at org.springframework.webflow.mvc.servlet.FlowHandlerAdapter.handle(FlowHandlerAdapter.java:193).... Shown below is my configurations, <bean name="flowController" class="org.springframework.webflow.mvc.servlet.FlowController"> <property name="flowExecutor" ref="flowExecutor"></property> </bean> <webflow:flow-executor id="flowExecutor" /> <webflow:flow-registry id="flowRegistry" > <webflow:flow-location path="/WEB-INF/flows/welcome/welcome.xml"></webflow:flow-location> </webflow:flow-registry> /WEB-INF/flows/welcome/welcome.xml, <view-state id="welcome"> <transition on="next" to="introduction" /> <transition on="skip" to="menu" /> </view-state> <view-state id="introduction"> <on-render> <evaluate expression="libraryService.getHolidays()" result="requestScope.holidays" /> </on-render> <transition on="next" to="menu" /> </view-state> <view-state id="menu"></view-state> In welcome.jsp, <a href="${flowExecutionUrl}&_eventId=next">Next</a> <a href="${flowExecutionUrl}&_eventId=skip">Skip</a> Please let me know what is going wrong. I am using 2.0.9 Release. Thanks in advance, SD

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  • Access and modify attributes/objects which are not part of the form backing bean

    - by spa
    I use Spring MVC (via Spring Roo) to build a small web application for administering persons. In the page for creating a person the bean Person is used as form backing object (key "person" in the model map). <form:form action="${form_url}" method="POST" modelAttribute="person"> I would like to add some attributes to the model map which can be altered by the user in the creation form. Basically, I try to add a Boolean, so that I can control which page is displayed next after the user presses the submit button. I try to modify the Boolean (key "myBoolean" in the model map) using a simple checkbox: <form:checkbox id="_myboolean_id" path="myBoolean"/> However, as I am new to Spring MVC I have some difficulties here. The Boolean object is not an attribute of the form backing object. So if I try to access it the following exception is thrown (of course): Invalid property 'myBoolean' of bean class [de.cm.model.Person]: Bean property 'myBoolean' is not readable or has an invalid getter method: Does the return type of the getter match the parameter type of the setter? Is there are way to access a value of the model map directly? The only solution I can imagine right now is a kind of wrapper object around the class Person and my additional attributes which is used as a new form backing object. However, this is more work for a IMHO simple task. Do you have a better solution?

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  • Spring security problem, Error creating bean with name 'org.springframework.web.servlet.mvc.annotati

    - by benaissa
    Hello; I'm developping a web application with spring mvc, i started by developping the web application after i'm trying to add spring security; but i have this message, and i don't find a solution, thanks 16-04-2010 12:10:22:296 6062 ERROR org.springframework.web.servlet.DispatcherServlet - Context initialization failed org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping': Initialization of bean failed; nested exception is java.lang.NoClassDefFoundError: org/springframework/beans/factory/generic/GenericBeanFactoryAccessor at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:527) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:456) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:286) at org.springframework.web.servlet.DispatcherServlet.createDefaultStrategy(DispatcherServlet.java:770) at org.springframework.web.servlet.DispatcherServlet.getDefaultStrategies(DispatcherServlet.java:737) at org.springframework.web.servlet.DispatcherServlet.initHandlerMappings(DispatcherServlet.java:518) at org.springframework.web.servlet.DispatcherServlet.initStrategies(DispatcherServlet.java:410) at org.springframework.web.servlet.DispatcherServlet.onRefresh(DispatcherServlet.java:398) at org.springframework.web.servlet.FrameworkServlet.onApplicationEvent(FrameworkServlet.java:474) at org.springframework.context.event.GenericApplicationListenerAdapter.onApplicationEvent(GenericApplicationListenerAdapter.java:51) at org.springframework.context.event.SourceFilteringListener.onApplicationEventInternal(SourceFilteringListener.java:97) at org.springframework.context.event.SourceFilteringListener.onApplicationEvent(SourceFilteringListener.java:68) at org.springframework.context.event.SimpleApplicationEventMulticaster.multicastEvent(SimpleApplicationEventMulticaster.java:97) at org.springframework.context.support.AbstractApplicationContext.publishEvent(AbstractApplicationContext.java:301) at org.springframework.context.support.AbstractApplicationContext.finishRefresh(AbstractApplicationContext.java:888) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:426) at org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:402) at org.springframework.web.servlet.FrameworkServlet.initWebApplicationContext(FrameworkServlet.java:316) at org.springframework.web.servlet.FrameworkServlet.initServletBean(FrameworkServlet.java:282) at org.springframework.web.servlet.HttpServletBean.init(HttpServletBean.java:126) at javax.servlet.GenericServlet.init(GenericServlet.java:212) at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1173) at org.apache.catalina.core.StandardWrapper.allocate(StandardWrapper.java:809) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:129) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Thread.java:619) Caused by: java.lang.NoClassDefFoundError: org/springframework/beans/factory/generic/GenericBeanFactoryAccessor at org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping.determineUrlsForHandler(DefaultAnnotationHandlerMapping.java:113) at org.springframework.web.servlet.handler.AbstractDetectingUrlHandlerMapping.detectHandlers(AbstractDetectingUrlHandlerMapping.java:79) at org.springframework.web.servlet.handler.AbstractDetectingUrlHandlerMapping.initApplicationContext(AbstractDetectingUrlHandlerMapping.java:57) at org.springframework.context.support.ApplicationObjectSupport.initApplicationContext(ApplicationObjectSupport.java:119) at org.springframework.web.context.support.WebApplicationObjectSupport.initApplicationContext(WebApplicationObjectSupport.java:69) at org.springframework.context.support.ApplicationObjectSupport.setApplicationContext(ApplicationObjectSupport.java:73) at org.springframework.context.support.ApplicationContextAwareProcessor.invokeAwareInterfaces(ApplicationContextAwareProcessor.java:99) at org.springframework.context.support.ApplicationContextAwareProcessor.postProcessBeforeInitialization(ApplicationContextAwareProcessor.java:82) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyBeanPostProcessorsBeforeInitialization(AbstractAutowireCapableBeanFactory.java:394) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1405) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:519) ... 32 more Caused by: java.lang.ClassNotFoundException: org.springframework.beans.factory.generic.GenericBeanFactoryAccessor at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1516) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1361) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) ... 43 more

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  • Spring redirecting back to referrer

    - by Eqbal
    I have some resources in my application that require redirection to another resource (form) if some context information is not set. After the context gets set (requires two user steps), I need to redirect back to the requested resource. How do I achieve that. I am using annotation based controllers in Spring 3. Is org.springframework.security.web.savedrequest.HttpSessionRequestCache of any use.

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  • Spring Web MVC: Use same request mapping for request parameter and path variable

    - by ngeek
    Good people: is there a way to express that my Spring Web MVC controller method should be matched either by a request handing in a ID as part of the URI path ... @RequestMapping(method=RequestMethod.GET, value="campaigns/{id}") public String getCampaignDetails(Model model, @PathVariable("id") Long id) { ... or if the client sends in the ID as a HTTP request parameter in the style ... @RequestMapping(method=RequestMethod.GET, value="campaigns") public String getCampaignDetails(Model model, @RequestParam("id") Long id) { This seems to me a quite common real-world URL scheme where I don't want to add duplicate code, but I wasn't able to find an answer yet. Any advice highly welcome.

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  • Spring Security 3.0 and Active Directory LDAP: DOMAIN\user login

    - by Bernd Haug
    I would like to have users authenticate against an ActiveDirectory LDAP server using the DOMAIN\user.name syntax. I think that should be possible with SpringSec 3.0 since the docs mention an "alternative syntax" which I guess refers to the DOM\user syntax instead of a bind DN, but the docs don't elaborate further. Is there some way to configure Spring Sec 3 LDAP to use "the MS way" or do I have to write my own Authenticator implementation (against e.g. the java.naming.directory package, which I've tested to be able to use the MS syntax as its SECURITY_PRINCIPAL)?

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  • Httpsession with Spring 3 MVC

    - by vipul12389
    I want to use httpsession in Spring 3 MVC..i have searched all the web and got this solution..at http://forum.springsource.org/showthread.php?98850-Adding-to-stuff-to-the-session-while-using-ResponseBody Basically, My application auto authenticates user by getting winId and authorizes through LDAP..(Its a intranet site) Here is the flow of the application, 1. User enters Aplication url (http://localhost:8082/eIA_Mock_5) it has a welcome page (index.jsp) Index.jsp gets winId through jQuery and hits login.html (through Ajax) and passes windowsId login.html (Controller) authenticates through LDAP and gives back 'Valid' String as a response javascript, upon getting the correct response, redirects/loads welcome page i.e. goes to localhost:8082/eIA_Mock_5/welcome.html Now, i have filter associated with it..which checks for is session valid for each incoming request..Now the problem is even though i set data on to httpsession, yet the filter or any other controller fails to get the data through session as a result it doesnt proceeds further.. here is the code..and could you suggest what is wrong actually ?? Home_Controller.java @Controller public class Home_Controller { public static Log logger = LogFactory.getLog(Home_Controller.class); @RequestMapping(value={"/welcome"}) public ModelAndView loadWelcomePage(HttpServletRequest request,HttpServletResponse response) { ModelAndView mdv = new ModelAndView(); try{ /*HttpSession session = request.getSession(); UserMasterBean userBean = (UserMasterBean)session.getAttribute("userBean"); String userName=userBean.getWindowsId(); if(userName==null || userName.equalsIgnoreCase("")) { mdv.setViewName("homePage"); System.out.println("Unable to authenticate user "); logger.debug("Unable to authenticate user "); } else { System.out.println("Welcome User "+userName); logger.debug("Welcome User "+userName); */ mdv.setViewName("homePage"); /*}*/ } catch(Exception e){ logger.debug("inside authenticateUser ",e); e.printStackTrace(); } return mdv; } @RequestMapping(value = "/login", method = RequestMethod.GET) public @ResponseBody String authenticateUser(@RequestParam String userName,HttpSession session) { logger.debug("inside authenticateUser"); String returnResponse=new String(); try{ logger.debug("userName for Authentication "+userName); System.out.println("userName for Authentication "+userName); //HttpSession session = request.getSession(); if(userName==null || userName.trim().equalsIgnoreCase("")) returnResponse="Invalid"; else { System.out.println("uname "+userName); String ldapResponse = LDAPConnectUtil.isValidActiveDirectoryUser(userName, ""); if(ldapResponse.equalsIgnoreCase("true")) { returnResponse="Valid"; System.out.println(userName+" Authenticated"); logger.debug(userName+" Authenticated"); UserMasterBean userBean = new UserMasterBean(); userBean.setWindowsId(userName); //if(session.getAttribute("userBean")==null) session.setAttribute("userBean", userBean); } else { returnResponse="Invalid"; //session.setAttribute("userBean", null); System.out.println("Unable to Authenticate the user through Ldap"); logger.debug("Unable to Authenticate the user through Ldap"); } System.out.println("ldapResponse "+ldapResponse); logger.debug("ldapResponse "+ldapResponse); System.out.println("returnResponse "+returnResponse); } UserMasterBean u = (UserMasterBean)session.getAttribute("userBean"); System.out.println("winId "+u.getWindowsId()); } catch(Exception e){ e.printStackTrace(); logger.debug("Exception in authenticateUser ",e); } return returnResponse; } Filter public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) { System.out.println("in PageFilter"); boolean flag = false; HttpServletRequest objHttpServletRequest = (HttpServletRequest)request; HttpServletResponse objHttpServletResponse = (HttpServletResponse)response; HttpSession session = objHttpServletRequest.getSession(); String contextPath = objHttpServletRequest.getContextPath(); String servletPath = objHttpServletRequest.getSession().getServletContext().getRealPath(objHttpServletRequest.getServletPath()); logger.debug("contextPath :" + contextPath); logger.debug("servletPath :" + servletPath); System.out.println("in PageFilter, contextPath :" + contextPath); System.out.println("in PageFilter, servletPath :" + servletPath); if (servletPath.endsWith("\\") || servletPath.endsWith("/") || servletPath.indexOf("css") > 0 || servletPath.indexOf("jsp") > 0 || servletPath.indexOf("images") > 0 || servletPath.indexOf("js") > 0 || servletPath.endsWith("index.jsp") || servletPath.indexOf("xls") > 0 || servletPath.indexOf("ini") > 0 || servletPath.indexOf("login.html") > 0 || /*servletPath.endsWith("welcome.html") ||*/ servletPath.endsWith("logout.do") ) { System.out.println("User is trying to access allowed pages like Login.jsp, errorPage.jsp, js, images, css"); logger.debug("User is trying to access allowed pages like Login.jsp, errorPage.jsp, js, images, css"); flag = true; } if (flag== false) { System.out.println("flag = false"); if(session.getAttribute("userBean") == null) System.out.println("yes session.userbean is null"); if ((session != null) && (session.getAttribute("userBean") != null)) { System.out.println("session!=null && session.getAttribute(userId)!=null"); logger.debug("IF Part"); UserMasterBean userBean = (UserMasterBean)session.getAttribute("userBean"); String windowsId = userBean.getWindowsId(); logger.debug("User Id " + windowsId + " allowed access"); System.out.println("User Id " + windowsId + " allowed access"); flag = true; } else { System.out.println("else .....session!=null && session.getAttribute(userId)!=null"); logger.debug("Else Part"); flag = false; } } if (flag == true) { try { System.out.println("before chain.doFilter(request, response)"); chain.doFilter(request, response); } catch (Exception e) { e.printStackTrace(); try { objHttpServletResponse.sendRedirect(contextPath + "/logout.do"); } catch (Exception ex) { ex.printStackTrace(); } } } else { try { System.out.println("before sendRedirect"); objHttpServletResponse.sendRedirect(contextPath + "/jsp/errorPage.jsp"); } catch (Exception ex) { ex.printStackTrace(); } } System.out.println("end of PageFilter"); } Index.jsp <script type="text/javascript"> //alert("inside s13"); var WinNetwork = new ActiveXObject("WScript.Network"); var userName=WinNetwork.UserName; alert(userName); $.ajax({ url : "login.html", data : "userName="+userName, success : function(result) { alert("result == "+result); if(result=="Valid") window.location = "http://10.160.118.200:8082/eIA_Mock_5/welcome.html"; } }); </script> web.xml has a filter entry with URL pattern as * I am using spring 3 mvc

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  • Error while splitting application context file in spring

    - by Krupal
    I am trying to split the ApplicationContext file in Spring. For ex. the file is testproject-servlet.xml having all the entries. Now I want to split this single file into multiple files according to logical groups like : group1-services.xml, group2-services.xml I have created following entries in web.xml : <servlet> <servlet-name>testproject</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/group1-services.xml, /WEB-INF/group2-services.xml </param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> I am using SimpleUrlHandlerMapping as: RegisterController PayrollServicesController I also have the controller defined as : .. .. The problem is that I have splitted the ApplicationContext file "testproject-servlet.xml" into two different files and I have kept the above entries in "group1-services.xml". Is it fine? I want to group things logically based on their use in seperate .xml files. But I am getting the following error when I try to access a page inside the application : org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping for [/TestProject/payroll_services.htm] in DispatcherServlet with name 'testproject' Please tell me how to resolve it. Thanks in Advance !

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  • How to send html form data from one form to multiple database tables

    - by user1701556
    I am able to send html form data to database using hibernate. I am using mySQL, Hibernate, Java 1.6, Spriong 3.0. But I would like to send that same data to multiple tables in the database. My issue is that I want to use only one html form not multiple html form. I have these tables: name, address, email, login, phone_num. From this one html form I want data to go to different tables depending on what the data is. I want to do it using Hibernate so that I am not manually taking form data and inserting it in the database. Please let me know if this is possible.

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  • Spring Security 3.1 xsd and jars mismatch issue

    - by kmansoor
    I'm Trying to migrate from spring framework 3.0.5 to 3.1 and spring-security 3.0.5 to 3.1 (not to mention hibernate 3.6 to 4.1). Using Apache IVY. I'm getting the following error trying to start Tomcat 7.23 within Eclipse Helios (among a host of others, however this is the last in the console): org.springframework.beans.factory.BeanDefinitionStoreException: Line 7 in XML document from ServletContext resource [/WEB-INF/focus-security.xml] is invalid; nested exception is org.xml.sax.SAXParseException: Document root element "beans:beans", must match DOCTYPE root "null". org.xml.sax.SAXParseException: Document root element "beans:beans", must match DOCTYPE root "null". my security config file looks like this: <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:jdbc="http://www.springframework.org/schema/jdbc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd http://www.springframework.org/schema/jdbc http://www.springframework.org/schema/jdbc/spring-jdbc-3.1.xsd"> Ivy.xml looks like this: <dependencies> <dependency org="org.hibernate" name="hibernate-core" rev="4.1.7.Final"/> <dependency org="org.hibernate" name="com.springsource.org.hibernate.validator" rev="4.2.0.Final" /> <dependency org="org.hibernate.javax.persistence" name="hibernate-jpa-2.0-api" rev="1.0.1.Final"/> <dependency org="org.hibernate" name="hibernate-entitymanager" rev="4.1.7.Final"/> <dependency org="org.hibernate" name="hibernate-validator" rev="4.3.0.Final"/> <dependency org="org.springframework" name="spring-context" rev="3.1.2.RELEASE"/> <dependency org="org.springframework" name="spring-web" rev="3.1.2.RELEASE"/> <dependency org="org.springframework" name="spring-tx" rev="3.1.2.RELEASE"/> <dependency org="org.springframework" name="spring-webmvc" rev="3.1.2.RELEASE"/> <dependency org="org.springframework" name="spring-test" rev="3.1.2.RELEASE"/> <dependency org="org.springframework.security" name="spring-security-core" rev="3.1.2.RELEASE"/> <dependency org="org.springframework.security" name="spring-security-web" rev="3.1.2.RELEASE"/> <dependency org="org.springframework.security" name="spring-security-config" rev="3.1.2.RELEASE"/> <dependency org="org.springframework.security" name="spring-security-taglibs" rev="3.1.2.RELEASE"/> <dependency org="net.sf.dozer" name="dozer" rev="5.3.2"/> <dependency org="org.apache.poi" name="poi" rev="3.8"/> <dependency org="commons-io" name="commons-io" rev="2.4"/> <dependency org="org.slf4j" name="slf4j-api" rev="1.6.6"/> <dependency org="org.slf4j" name="slf4j-log4j12" rev="1.6.6"/> <dependency org="org.slf4j" name="slf4j-ext" rev="1.6.6"/> <dependency org="log4j" name="log4j" rev="1.2.17"/> <dependency org="org.testng" name="testng" rev="6.8"/> <dependency org="org.dbunit" name="dbunit" rev="2.4.8"/> <dependency org="org.easymock" name="easymock" rev="3.1"/> </dependencies> I understand (hope) this error is due to a mismatch between the declared xsd and the jars on the classpath. Any pointers will be greatly appreciated.

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  • how to retrive pK using spring security

    - by aditya
    i implement this method of the UserDetailService interface, public UserDetails loadUserByUsername(final String username) throws UsernameNotFoundException, DataAccessException { final EmailCredential userDetails = persistentEmailCredential .getUniqueEmailCredential(username); if (userDetails == null) { throw new UsernameNotFoundException(username + "is not registered"); } final HashSet<GrantedAuthority> authorities = new HashSet<GrantedAuthority>(); authorities.add(new GrantedAuthorityImpl("ROLE_USER")); for (UserRole role:userDetails.getAccount().getRoles()) { authorities.add(new GrantedAuthorityImpl(role.getRole())); } return new User(userDetails.getEmailAddress(), userDetails .getPassword(), true, true, true, true, authorities); } in the security context i do some thing like this <!-- Login Info --> <form-login default-target-url='/dashboard.htm' login-page="/login.htm" authentication-failure-url="/login.htm?authfailed=true" always-use-default-target='false' /> <logout logout-success-url="/login.htm" invalidate-session="true" /> <remember-me user-service-ref="emailAccountService" key="fuellingsport" /> <session-management> <concurrency-control max-sessions="1" /> </session-management> </http> now i want to pop out the Pk of the logged in user, how can i show it in my jsp pages, any idea thanks in advance

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  • Zend Framework, Zend_Form_Element how to set custom name?

    - by ikso
    Hello, I have form, where some fields are looks like rows, so I can add/delete them using JS. For example: Field with ID=1 (existing row) <input id="id[1]" type="text" name="id[1]" value="1" /> <input id="name[1]" type="text" name="name[1]" value="100" /> Field with ID=2 (existing row) <input id="name[2]" type="text" name="name[2]" value="200" /> <input id="name[2]" type="text" name="name[2]" value="200" /> new row created by default (to allow add one more row to existing rows) <input id="id[n0]" type="text" name="id[n0]" value="" /> <input id="name[n0]" type="text" name="name[n0]" value="" /> new row created by JS <input id="id[n1]" type="text" name="id[n1]" value="" /> <input id="name[n1]" type="text" name="name[n1]" value="" /> So than we will proceed form, we will know what rows to update and what to add (if index starts with "n" - new, if index is number - existent element). I tried subforms... but do I have to create subform for each field? If I use following code: $subForm = new Zend_Form_SubForm(); $subForm->addElement('Text', 'n0'); $this->addSubForm($subForm, 'pid'); $subForm = new Zend_Form_SubForm(); $subForm->addElement('Text', 'n0'); $this->addSubForm($subForm, 'name'); What is the best way for this? 1) Use subforms? 2) Extend Zend/Form/Decorator/ViewHelper.php to use names like name[nX]? 3) Other solutions? Thanks.

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  • accessing HttpServletRequest object in Spring WebFlow

    - by user198530
    I am using WebFlow and would like to add the current Locale into the flow. I already have a resolveLocale method that does this with this signature: public Locale resolveLocale (HttpServletRequest request); I would like to add something like this in my WebFlow XML: <on-start> <evaluate expression="localeService.resolveLocale(???)" result="flowScope.locale"/> </on-start> Now, I don't know what to put in the ??? parameter part. Any ideas? Thanks for reading.

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