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  • Processing file uploads before object is saved

    - by Dominic Rodger
    I've got a model like this: class Talk(BaseModel): title = models.CharField(max_length=200) mp3 = models.FileField(upload_to = u'talks/', max_length=200) seconds = models.IntegerField(blank = True, null = True) I want to validate before saving that the uploaded file is an MP3, like this: def is_mp3(path_to_file): from mutagen.mp3 import MP3 audio = MP3(path_to_file) return not audio.info.sketchy Once I'm sure I've got an MP3, I want to save the length of the talk in the seconds attribute, like this: audio = MP3(path_to_file) self.seconds = audio.info.length The problem is, before saving, the uploaded file doesn't have a path (see this ticket, closed as wontfix), so I can't process the MP3. I'd like to raise a nice validation error so that ModelForms can display a helpful error ("You idiot, you didn't upload an MP3" or something). Any idea how I can go about accessing the file before it's saved? p.s. If anyone knows a better way of validating files are MP3s I'm all ears - I also want to be able to mess around with ID3 data (set the artist, album, title and probably album art, so I need it to be processable by mutagen).

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  • Django show manytomanyfield on form when definition is on other model

    - by John
    Hi I have the definition for my manytomany relationship on one model but want to display the field on a form for the other model. How do I do this? for example: # classes class modelA(models.Model): name = models.CharField(max_length=300) manytomany = models.ManyToManyField(modelA) class modelB(models.Model): name = models.CharField(max_length=300) # forms class modelBForm(forms.ModelForm): class Meta: model = modelB I want to use the form modelBForm but show a select box with a list from modelA (just how it would work if the model was set to modelA in the form class). How can I do this? Thanks

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  • verbose_name for a model's method

    - by mawimawi
    How can I set a verbose_name for a model's method, so that it might be displayed in the admin's change_view form? example: class Article(models.Model): title = models.CharField(max_length=64) created_date = models.DateTimeField(....) def created_weekday(self): return self.created_date.strftime("%A") in admin.py: class ArticleAdmin(admin.ModelAdmin): readonly_fields = ('created_weekday',) fields = ('title', 'created_weekday') Now the label for created_weekday is "Created Weekday", but I'd like it to have a different label which should be i18nable using ugettext_lazy as well. I've tried created_weekday.verbose_name=... after the method, but that did not show any result. Is there a decorator or something I can use, so I could make my own "verbose_name" / "label" / whateverthename is?

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  • Django - Threading in views without hanging the server

    - by bobthabuilda
    One of my applications in my Django project require each request/visitor to that instance to have their own thread. This might sound confusing, so I'll describe what I'm looking to accomplish in a case based scenario, with steps: User visits application Thread starts Until the thread finishes, that user's server instance hangs Once the thread completes, a response is delivered to the user Other visitors to the site should not be affected by any other users using the application How can I accomplish something like this? If possible, I'd like to find a lightweight solution.

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  • Correct way to model recursive relationship in Django

    - by Yuval A
    My application has two node types: a parent node which can hold recursive child nodes. Think of it like the post-comment system in SO, but comments can be recursive: parent_1 child_11 child_12 child_121 child_3 parent_2 child_21 child_211 child_2111 Important to note that the parent nodes have different attributes and behavior than the child nodes. What is the correct (and presumably most efficient) way of modeling this relationship in Django?

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  • XML file as model for django project

    - by Ankur Chauhan
    Hi, I have a XML file that is managed by other programs, I am writing a web service such that users are able to query this file. In essence i am using a xml based database instead of using sql as the model database in Django. how do i do this? all the tutorials that i find use a sql database in the backend. is there a way to use the xml file as a database.

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  • Django model fields getter / setter

    - by pistacchio
    Hi, is there something like getters and setters for django model's fields? For example, I have a text field in which i need to make a string replace before it get saved (in the admin panel, for both insert and update operations) and make another, different replace each time it is read. Those string replace are dynamic and need to be done at the moment of saving and reading. As I'm using python 2.5, I cannot use python 2.6 getters / setters. Any help?

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  • Duplicate django query set?

    - by Piotr Czapla
    I have a simple django's query set like: qs = AModel.objects.exclude(state="F").order_by("order") I'd like to use it as follows: qs[0:3].update(state='F') expected = qs[3] # throws error here But last statement throws: "Cannot update a query once a slice has been taken." How can I duplicate the query set?

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  • Extending the User model with custom fields in Django

    - by Gaurav
    I am trying to extend the User model so that I can add my own custom fields but I keep getting an error stating: 'NoneType' object has no attribute '_default_manager' whenever I try to use user.get_profile() to add values to the custom field i.e. whenever I use it like so: user = User.objects.create_user(username, email, password) user.first_name = fname user.last_name = lname user.save() uinfo = user.get_profile() uinfo.timezone = "Asia/Pune" uinfo.save() I have already followed the steps given at http://stackoverflow.com/questions/44109/extending-the-user-model-with-custom-fields-in-django/965883#965883 with no luck.

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  • Django - 2 fields unique together

    - by webvulture
    Suppose, I want to record say poll choices by users everyday. In this case, i have a table named vote which has columns poll , choice and user-id . So how can i out the constraint (maybe in the django models or wherever possible) that poll and user-id both should not be the same for any entry but like the same user can vote for various different polls once and obviously various users can vote for the same poll. I hope I am clear.

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  • SQL commands generated in Django by running sqlall

    - by k-g-f
    In my Django app, I just ran $ python manage.py sqlall and I see a lot of SQL statements that look like this, when describing FK relationships: ALTER TABLE `app1_model1` ADD CONSTRAINT model2_id_refs_id_728de91f FOREIGN KEY (`model2_id`) REFERENCES `app1_model2` (`id`); Where does "7218de91f" come from? I would like to know because I'd like to manually write SQL statements to accompany models changes in the app so that my db's can be kept up to date.

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  • Can Django be used for non web apps?

    - by Leeks and Leaks
    I noticed in the main Django introductin they show a feature that maps python objects to the database. This doesn't strike me as being mutually exclusive with with development, is there any reason why this can't be used for non web apps? Is it easy to separate out?

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  • Django Admin: OneToOne Relation as an Inline?

    - by Jim Robert
    I am putting together the admin for a satchmo application. Satchmo uses OneToOne relations to extend the base Product model, and I'd like to edit it all on one page. It is possible to have a OneToOne relation as an Inline? If not, what is the best way to add a few fields to a given page of my admin that will eventually be saved into the OneToOne relation? for example: class Product(models.Model): name = models.CharField(max_length=100) ... class MyProduct(models.Model): product = models.OneToOne(Product) ... I tried this for my admin but it does not work, and seems to expect a Foreign Key: class ProductInline(admin.StackedInline): model = Product fields = ('name',) class MyProductAdmin(admin.ModelAdmin): inlines = (AlbumProductInline,) admin.site.register(MyProduct, MyProductAdmin) Which throws this error: <class 'satchmo.product.models.Product'> has no ForeignKey to <class 'my_app.models.MyProduct'> Is the only way to do this a Custom Form? edit: Just tried the following code to add the fields directly... also does not work: class AlbumAdmin(admin.ModelAdmin): fields = ('product__name',)

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  • Writing good tests for Django applications

    - by Ludwik Trammer
    I've never written any tests in my life, but I'd like to start writing tests for my Django projects. I've read some articles about tests and decided to try to write some tests for an extremely simple Django app or a start. The app has two views (a list view, and a detail view) and a model with four fields: class News(models.Model): title = models.CharField(max_length=250) content = models.TextField() pub_date = models.DateTimeField(default=datetime.datetime.now) slug = models.SlugField(unique=True) I would like to show you my tests.py file and ask: Does it make sense? Am I even testing for the right things? Are there best practices I'm not following, and you could point me to? my tests.py (it contains 11 tests): # -*- coding: utf-8 -*- from django.test import TestCase from django.test.client import Client from django.core.urlresolvers import reverse import datetime from someproject.myapp.models import News class viewTest(TestCase): def setUp(self): self.test_title = u'Test title: bareksc' self.test_content = u'This is a content 156' self.test_slug = u'test-title-bareksc' self.test_pub_date = datetime.datetime.today() self.test_item = News.objects.create( title=self.test_title, content=self.test_content, slug=self.test_slug, pub_date=self.test_pub_date, ) client = Client() self.response_detail = client.get(self.test_item.get_absolute_url()) self.response_index = client.get(reverse('the-list-view')) def test_detail_status_code(self): """ HTTP status code for the detail view """ self.failUnlessEqual(self.response_detail.status_code, 200) def test_list_status_code(self): """ HTTP status code for the list view """ self.failUnlessEqual(self.response_index.status_code, 200) def test_list_numer_of_items(self): self.failUnlessEqual(len(self.response_index.context['object_list']), 1) def test_detail_title(self): self.failUnlessEqual(self.response_detail.context['object'].title, self.test_title) def test_list_title(self): self.failUnlessEqual(self.response_index.context['object_list'][0].title, self.test_title) def test_detail_content(self): self.failUnlessEqual(self.response_detail.context['object'].content, self.test_content) def test_list_content(self): self.failUnlessEqual(self.response_index.context['object_list'][0].content, self.test_content) def test_detail_slug(self): self.failUnlessEqual(self.response_detail.context['object'].slug, self.test_slug) def test_list_slug(self): self.failUnlessEqual(self.response_index.context['object_list'][0].slug, self.test_slug) def test_detail_template(self): self.assertContains(self.response_detail, self.test_title) self.assertContains(self.response_detail, self.test_content) def test_list_template(self): self.assertContains(self.response_index, self.test_title)

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  • How do I relate two models/tables in Django based on non primary non unique keys?

    - by wizard
    I've got two tables that I need to relate on a single field po_num. The data is imported from another source so while I have a little bit of control over what the tables look like but I can't change them too much. What I want to do is relate these two models so I can look up one from the other based on the po_num fields. What I really need to do is join the two tables so I can do a where on a count of the related table. I would like to do filter for all Order objects that have 0 related EDI856 objects. I tried adding a foreign key to the Order model and specified the db_column and to_fields as po_num but django didn't like that the fact that Edi856.po_num wasn't unique. Here are the important fields of my current models that let me display but not filter for the data that I want. class Edi856(models.Model): po_num = models.CharField(max_length=90, db_index=True ) class Order(models.Model): po_num = models.CharField(max_length=90, db_index=True) def in_edi(self): '''Has the edi been processed?''' return Edi856.objects.filter(po_num = self.po_num).count() Thanks for taking the time to read about my problem. I'm not sure what to do from here.

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  • django join-like expansion of queryset

    - by jimbob
    I have a list of Persons each which have multiple fields that I usually filter what's upon, using the object_list generic view. Each person can have multiple Comments attached to them, each with a datetime and a text string. What I ultimately want to do is have the option to filter comments based on dates. class Person(models.Model): name = models.CharField("Name", max_length=30) ## has ~30 other fields, usually filtered on as well class Comment(models.Model): date = models.DateTimeField() person = models.ForeignKey(Person) comment = models.TextField("Comment Text", max_length=1023) What I want to do is get a queryset like Person.objects.filter(comment__date__gt=date(2011,1,1)).order_by('comment__date') send that queryset to object_list and be able to only see the comments ordered by date with only so many objects on a page. E.g., if "Person A" has comments 12/3/11, 1/2/11, 1/5/11, "Person B" has no comments, and person C has a comment on 1/3, I would see: "Person A", 1/2 - comment "Person C", 1/3 - comment "Person A", 1/5 - comment I would strongly prefer not to have to switch to filtering based on Comments.objects.filter(), as that would make me have to largely repeat large sections of code in the both the view and template. Right now if I tried executing the following command, I will get a queryset returning (PersonA, PersonC, PersonA), but if I try rendering that in a template each persons comment_set will contain all their comments even if they aren't in the date range. Ideally they're would be some sort of functionality where I could expand out a Person queryset's comment_set into a larger queryset that can be sorted and ordered based on the comment and put into a object_list generic view. This normally is fairly simple to do in SQL with a JOIN, but I don't want to abandon the ORM, which I use everywhere else.

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  • Keeping track of changes - Django

    - by RadiantHex
    Hi folks!! I have various models of which I would like to keep track and collect statistical data. The problem is how to store the changes throughout time. I thought of various alternative: Storing a log in a TextField, open it and update it every time the model is saved. Alternatively pickle a list and store it in a TextField. Save logs on hard drive. What are your suggestions?

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  • django url from another template than the one associated with the view-function

    - by dana
    Heyy there, i have an application, and in my urls.py i have something like that: urlpatterns = patterns('', url(r'^profile_view/(?P<id>\d+)/$', profile_view, name='profile_view'),) meaning that the profile_view function has id as a parameter. Now, i want to call that function from another template than the one associated with the def-view that has this url. How should i do that? i have to put two render_to_response to one same function, in order to render the objects from both models? thank you!

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  • How much knowledge do I need to begin a project in Django

    - by Smock
    I started learning django about a month ago. I have an intermediate C, Java programming experience. I read the first 8 chapters of the django book . Afterwards, I picked up Practical Django Projects by James Bennett and did the first two projects: CMS & Web Blog. Although, I started getting lost when he got to the generic views part. I know that's important but I'm not sure how important that is when trying to implement a project. Anyway, I have a project in mind that I'd like to start; however, I'm nervous as to where to begin. I'm overwhelmed with the number of things that I'd like my project to do but no knowledge or minimal knowledge as to how e.g. how do i implement css and javascript in my project. Moreover, I am aware that some django packages exists to ease development but I don't know if I should use them or not. Anyway, I apologize for my length message. I just want some advice/encouragement. I have a project in mind but do you think I need to read more materials/tutorials or is it smart to just start working on my project based on the minimal knowledge i've gained from those books? Any information that can be provided is much appreciated. I really want to get good at this but I just need some direction.

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  • Single django instance with subdomains for each app in the django project

    - by jwesonga
    I have a django project (django+apache+mod_wsgi+nginx) with multiple apps, I'd like to map each app as a subdomain: project/ app1 (domain.com) app2 (sub1.domain.com) app3 (sub3.domain.com) I have a single .wsgi script serving the project, which is stored in a folder /apache. Below is my vhost file. I'm using a single vhost file instead of separate ones for each sub-domain: <VirtualHost *:8080> ServerAdmin [email protected] ServerName www.domain.com ServerAlias domain.com DocumentRoot /home/path/to/app/ Alias /admin_media/ /usr/local/lib/python2.6/dist-packages/django/contrib/admin/media <Directory /home/path/to/wsgi/apache/> Order deny,allow Allow from all </Directory> LogLevel warn ErrorLog /home/path/to/logs/apache_error.log CustomLog /home/path/to/logs/apache_access.log combined WSGIDaemonProcess domain.com user=www-data group=www-data threads=25 WSGIProcessGroup domain.com WSGIScriptAlias / /home/path/to/apache/kcdf.wsgi </VirtualHost> <VirtualHost *:8081> ServerAdmin [email protected] ServerName sub1.domain.com ServerAlias sub1.domain.com DocumentRoot /home/path/to/app Alias /admin_media/ /usr/local/lib/python2.6/dist-packages/django/contrib/admin/media <Directory /home/path/to/wsgi/apache/> Order deny,allow Allow from all </Directory> LogLevel warn ErrorLog /home/path/to/logs/apache_error.log CustomLog /home/path/to/logs/apache_access.log combined WSGIDaemonProcess sub1.domain.com user=www-data group=www-data threads=25 WSGIProcessGroup sub1.domain.com WSGIScriptAlias / /home/path/to/apache/kcdf.wsgi </VirtualHost> My Nginx configuration for the domain.com: server { listen 80; server_name domain.com; access_log off; error_log off; # proxy to Apache 2 and mod_wsgi location / { proxy_pass http://127.0.0.1:8080/; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_max_temp_file_size 0; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffer_size 4k; proxy_buffers 4 32k; proxy_busy_buffers_size 64k; proxy_temp_file_write_size 64k; } } Configuration for the sub.domain.com: server { listen 80; server_name sub.domain.com; access_log off; error_log off; # proxy to Apache 2 and mod_wsgi location / { proxy_pass http://127.0.0.1:8081/; proxy_redirect off; proxy_set_header Host $host; proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_max_temp_file_size 0; client_max_body_size 10m; client_body_buffer_size 128k; proxy_connect_timeout 90; proxy_send_timeout 90; proxy_read_timeout 90; proxy_buffer_size 4k; proxy_buffers 4 32k; proxy_busy_buffers_size 64k; proxy_temp_file_write_size 64k; } } This set up doesn't seem to work, everything seems to point to the main domain. I've tried http://effbot.org/zone/django-multihost.htm which kind of worked but seems to have issues with loading my css,images,js files.

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