Search Results

Search found 6723 results on 269 pages for 'django models'.

Page 23/269 | < Previous Page | 19 20 21 22 23 24 25 26 27 28 29 30  | Next Page >

  • Social Game Mechanics in Django

    - by oliland
    I want users to receive 'points' for completing various tasks in my application - ranging from tasks such as tagging objects to making friends. I havn't yet found a Django application that simplifies this. At the moment I'm thinking that the best way to accumulate points is that each user action creates the equivalent of a "stream item", and the points are calculated through counting the value of each action published to their stream. Obviously social game mechanics is a huge area with a lot of research going on at the moment. But from a development perspective what's the easiest way to get started? Am I on the wrong track or are there better / simpler ways?

    Read the article

  • South migration error: NoMigrations exception for django.contrib.auth

    - by danpalmer
    I have been using South on my project for a while, but I recently did a huge amount of development and changed development machine and I think something messed up in the process. The project works fine, but I can't apply migrations. Whenever I try to apply a migration I get the following traceback: danpalmer:pest Dan$ python manage.py migrate frontend Traceback (most recent call last): File "manage.py", line 11, in <module> execute_manager(settings) File "/Library/Python/2.6/site-packages/django/core/management/__init__.py", line 362, in execute_manager utility.execute() File "/Library/Python/2.6/site-packages/django/core/management/__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 222, in execute output = self.handle(*args, **options) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/management/commands/migrate.py", line 102, in handle delete_ghosts = delete_ghosts, File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/__init__.py", line 182, in migrate_app applied = check_migration_histories(applied, delete_ghosts) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/__init__.py", line 85, in check_migration_histories m = h.get_migration() File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/models.py", line 34, in get_migration return self.get_migrations().migration(self.migration) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/models.py", line 31, in get_migrations return Migrations(self.app_name) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/base.py", line 60, in __call__ self.instances[app_label] = super(MigrationsMetaclass, self).__call__(app_label_to_app_module(app_label), **kwds) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/base.py", line 88, in __init__ self.set_application(application, force_creation, verbose_creation) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/base.py", line 159, in set_application raise exceptions.NoMigrations(application) south.exceptions.NoMigrations: Application '<module 'django.contrib.auth' from '/Library/Python/2.6/site-packages/django/contrib/auth/__init__.pyc'>' has no migrations. I am not that experienced with South and I haven't met this error before. The only helpful mention I can find online about this error is for pre-0.7 I think and I am on South 0.7. I ran 'easy_install -U South' just to make sure. Thanks for any help that you can provide. I really appreciate it.

    Read the article

  • Django CMS error when running project

    - by 47
    I'd set up a site a while back using Django-CMS and it was working fine. However, after upgrading to the latest version of both Django and Django-CMS, it doesn't work anymore...when I try to run the development server, I get this message: "Signal recerivers must accept keyword arguments (**kwargs)." AssertionError: Signal receivers must accept keyword arguments (**kwargs). What could be the problem here? I've tried running the sample app that comes with the CMS and it works just fine.

    Read the article

  • Django comparing model instances for equality

    - by orokusaki
    I understand that, with a singleton situation, you can perform such an operation as: spam == eggs and if spam and eggs are instances of the same class with all the same attribute values, it will return True. In a Django model, this is natural because two separate instances of a model won't ever be the same unless they have the same .pk value. The problem with this is that if a reference to an instance has attributes that have been updated by middleware somewhere along the way and it hasn't been saved, and you're trying to it to another variable holding a reference to an instance of the same model, it will return False of course because they have different values for some of the attributes. Obviously I don't need something like a singleton , but I'm wondering if there some official Djangonic (ha, a new word) method for checking this, or if I should simply check that the .pk value is the same with: spam.pk == eggs.pk I'm sorry if this was a huge waste of time, but it just seems like there might be a method for doing this, and something I'm missing that I'll regret down the road if I don't find it.

    Read the article

  • Syncing data between devel/live databases in Django

    - by T. Stone
    With Django's new multi-db functionality in the development version, I've been trying to work on creating a management command that let's me synchronize the data from the live site down to a developer machine for extended testing. (Having actual data, particularly user-entered data, allows me to test a broader range of inputs.) Right now I've got a "mostly" working command. It can sync "simple" model data but the problem I'm having is that it ignores ManyToMany fields which I don't see any reason for it do so. Anyone have any ideas of either how to fix that or a better want to handle this? Should I be exporting that first query to a fixture first and then re-importing it? from django.core.management.base import LabelCommand from django.db.utils import IntegrityError from django.db import models from django.conf import settings LIVE_DATABASE_KEY = 'live' class Command(LabelCommand): help = ("Synchronizes the data between the local machine and the live server") args = "APP_NAME" label = 'application name' requires_model_validation = False can_import_settings = True def handle_label(self, label, **options): # Make sure we're running the command on a developer machine and that we've got the right settings db_settings = getattr(settings, 'DATABASES', {}) if not LIVE_DATABASE_KEY in db_settings: print 'Could not find "%s" in database settings.' % LIVE_DATABASE_KEY return if db_settings.get('default') == db_settings.get(LIVE_DATABASE_KEY): print 'Data cannot synchronize with self. This command must be run on a non-production server.' return # Fetch all models for the given app try: app = models.get_app(label) app_models = models.get_models(app) except: print "The app '%s' could not be found or models could not be loaded for it." % label for model in app_models: print 'Syncing %s.%s ...' % (model._meta.app_label, model._meta.object_name) # Query each model from the live site qs = model.objects.all().using(LIVE_DATABASE_KEY) # ...and save it to the local database for record in qs: try: record.save(using='default') except IntegrityError: # Skip as the record probably already exists pass

    Read the article

  • Django: How to create a model dynamically just for testing

    - by muhuk
    I have a Django app that requires a settings attribute in the form of: RELATED_MODELS = ('appname1.modelname1.attribute1', 'appname1.modelname2.attribute2', 'appname2.modelname3.attribute3', ...) Then hooks their post_save signal to update some other fixed model depending on the attributeN defined. I would like to test this behaviour and tests should work even if this app is the only one in the project (except for its own dependencies, no other wrapper app need to be installed). How can I create and attach/register/activate mock models just for the test database? (or is it possible at all?) Solutions that allow me to use test fixtures would be great.

    Read the article

  • Django internationalization for admin pages - translate model name and attributes

    - by geekQ
    Django's internationalization is very nice (gettext based, LocaleMiddleware), but what is the proper way to translate the model name and the attributes for admin pages? I did not find anything about this in the documentation: http://docs.djangoproject.com/en/dev/topics/i18n/internationalization/ http://www.djangobook.com/en/2.0/chapter19/ I would like to have "???????? ????? ??? ?????????" instead of "???????? order ??? ?????????". Note, the 'order' is not translated. First, I defined a model, activated USE_I18N = True in settings.py, run django-admin makemessages -l ru. No entries are created by default for model names and attributes. Grepping in the Django source code I found: $ ack "Select %s to change" contrib/admin/views/main.py 70: self.title = (self.is_popup and ugettext('Select %s') % force_unicode(self.opts.verbose_name) or ugettext('Select %s to change') % force_unicode(self.opts.verbose_name)) So the verbose_name meta property seems to play some role here. Tried to use it: class Order(models.Model): subject = models.CharField(max_length=150) description = models.TextField() class Meta: verbose_name = _('order') Now the updated po file contains msgid 'order' that can be translated. So I put the translation in. Unfortunately running the admin pages show the same mix of "???????? order ??? ?????????". I'm currently using Django 1.1.1. Could somebody point me to the relevant documentation? Because google can not. ;-) In the mean time I'll dig deeper into the django source code...

    Read the article

  • django forms- register user script

    - by itsandy
    Hi all, I want to make something like http://www.djangosnippets.org/accounts/register/ using django..the register form. I am new to django. i have made a simple view form using django forms but unable o understand how to connect my form to a database. Im using postgresql. is there an easy way to use some snippet or script to achieve this. Please Help

    Read the article

  • user model password field default password field in django

    - by imran-glt
    Hi, I've created a custom user model in my application. This user model is working fine, but there are a couple of problems I have with it. 1) The change password link in the my register.html page doesn't work? 2) The default password box on the add/edit page for a user is a little unfriendly. Ideally, what I'd like is the two password fields from the change password form on the add/edit user form in the admin, which will automatically turn convert the entered password into a valid encrypted password in Django. This would make the admin system MUCH friendlier and much more suited to my needs, as a fair number of user accounts will be created and maintained manually in this app, and the person responsible for doing so will likely be scared off at the sight of that admin field, or just type a clear text password and wonder why it doesn't work. Is this possible / How do I do this?

    Read the article

  • Django admin interface upload failing on request data read error

    - by Jake
    Hi All, This is an updated version of an old question I asked. I've now done a lot more testing, plus the old question got hijacked. I'm getting a request data read error when trying to upload files to the Django admin interface. Files under about 150k work, but bigger files always fail and almost always at around 192k (that's 3 chunks) completed, sometimes at around 160k. The Exception I get is below. File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 405, in read return self._file.read(num_bytes) IOError: request data read error I've tried Chrome and Firefox on Windows and Firefox on Mac - Same results. I can upload to other sites so I don't think it's my connection. I'm running python 2.4, django 1.1, mod_wsgi, on CentOS (a media temple DV server) Locally it's fine (Django development server) Everything I've found on this issue says it's a mod_python issue and that changing to mod_wsgi will fix it, but I am running mod_wsgi. Can anyone help?

    Read the article

  • How do I find the "concrete class" of a django model baseclass

    - by Mr Shark
    I'm trying to find the actual class of a django-model object, when using model-inheritance. Some code to describe the problem: class Base(models.model): def basemethod(self): ... class Child_1(Base): pass class Child_2(Base): pass If I create various objects of the two Child classes and the create a queryset containing them all: Child_1().save() Child_2().save() (o1, o2) = Base.objects.all() I want to determine if the object is of type Child_1 or Child_2 in basemethod, I can get to the child object via o1.child_1 and o2.child_2 but that reconquers knowledge about the childclasses in the baseclass. I have come up with the following code: def concrete_instance(self): instance = None for subclass in self._meta.get_all_related_objects(): acc_name = subclass.get_accessor_name() try: instance = self.__getattribute__(acc_name) return instance except Exception, e: pass But it feels brittle and I'm not sure of what happens when if I inherit in more levels.

    Read the article

  • Django database caching

    - by hekevintran
    I have a Django form that uses an integer field to lookup a model object by its primary key. The form has a save() method that uses the model object referred to by the integer field. The model's manager's get() method is called twice, once in the clean method and once in the save() method: class MyForm(forms.Form): id_a = fields.IntegerField() def clean_id_a(user_id): id_a = self.cleaned_data['id_a'] try: # here is the first call to get MyModel.objects.get(id=id_a) except User.DoesNotExist: raise ValidationError('Object does not exist') def save(self): id_a = self.cleaned_data['id_a'] # here is the second call to get my_model_object = MyModel.objects.get(id=id_a) # do other stuff I wasn't sure whether this hits the database two times or one time so I returned the object itself in the clean method so that I could avoid a second get() call. Does calling get() hit the database two times? Or is the object cached in the thread? class MyForm(forms.Form): id_a = fields.IntegerField() def clean_id_a(user_id): id_a = self.cleaned_data['id_a'] try: # here is my workaround return MyModel.objects.get(id=id_a) except User.DoesNotExist: raise ValidationError('Object does not exist') def save(self): # looking up the cleaned value returns the model object my_model_object = self.cleaned_data['id_a'] # do other stuff

    Read the article

  • AddThis Social SignIn and Django

    - by piokuc
    I am developing a Django website. I've been using django-registration for user registration so far but I would really like to allow users to login to my site using their Facebook, Twitter, Google, etc accounts. I am using addthis sharing buttons. I just noticed they introduced a social sign in solution. The idea seems great, you integrate your authentication system with their service once, and your users can login via all of the popular social networking sites. Has anybody integrated addthis social signin plugin with a django website? How can you use it along side django-registration? Are there any similar, alternative solutions?

    Read the article

  • Django admin output extra HTML in ModelSite

    - by VoteyDisciple
    Ultimately, I want to add an <iframe> to the display of a particular model on Django's admin page. Django is already rendering the form for this model correctly, but I want to add this <iframe> in addition to Django's form. The src attribute needs to involve the primary key for the currently-displayed record. I've learned how to properly override the change_form.html template through Django's documentation, and I can add markup to the right block, but I can't figure out how to access the primary key value. (No amount of determined Googling has helped at all.) Alternatively, is there a direct way to specify that I want to produce extra output in my ModelSite definition?

    Read the article

  • Problem with anchor tags in Django after using lighttpd + fastcgi

    - by Drew A
    I just started using lighttpd and fastcgi for my django site, but I've noticed my anchor links are no longer working. I used the anchor links for sorting links on the page, for example I use an anchor to sort links by the number of points (or votes) they have received. For example: the code in the html template: ... {% load sorting_tags %} ... {% ifequal sort_order "points" %} {% trans "total points" %} {% trans "or" %} {% anchor "date" "date posted" %} {% order_by_votes links request.direction %} {% else %} {% anchor "points" "total points" %} {% trans "or" %} {% trans "date posted" %} ... The anchor link on "www.mysite.com/my_app/" for total points will be directed to "my_app/?sort=points" But the correct URL should be "www.mysite.com/my_app/?sort=points" All my other links work, the problem is specific to anchor links. The {% anchor %} tag is taken from django-sorting, the code can be found at http://github.com/directeur/django-sorting Specifically in django-sorting/templatetags/sorting_tags.py Thanks in advance.

    Read the article

  • Incremement Page Hit Count in Django

    - by Andrew C
    I have a table with an IntegerField (hit_count), and when a page is visited (ie. http://site/page/3) I want record id 3 'hit_count' column in the database to increment by 1. The query should be like: update table set hit_count = hit_count + 1 where id=3 Can I do this with the standard Django Model conventions? Or should I just write the query by hand? I'm starting a new project, so I am trying to avoid hacks. We'll see how long this lasts! Thanks!

    Read the article

  • Django gives "I/O operation on closed file" error when reading from a saved ImageField

    - by Rob Osborne
    I have a model with two image fields, a source image and a thumbnail. When I update the new source image, save it and then try to read the source image to crop/scale it to a thumbnail I get an "I/O operation on closed file" error from PIL. If I update the source image, don't save the source image, and then try to read the source image to crop/scale, I get an "attempting to read from closed file" error from PIL. In both cases the source image is actually saved and available in later request/response loops. If I don't crop/scale in a single request/response loop but instead upload on one page and then crop/scale in another page this all works fine. This seems to be a cached buffer being reused some how, either by PIL or by the Django file storage. Any ideas on how to make an ImageField readable after saving?

    Read the article

  • csrf error in django

    - by niklasfi
    Hello, I want to realize a login for my site. I basically copied and pasted the following bits from the Django Book together. However I still get an error (CSRF verification failed. Request aborted.), when submitting my registration form. Can somebody tell my what raised this error and how to fix it? Here is my code: views.py: # Create your views here. from django import forms from django.contrib.auth.forms import UserCreationForm from django.http import HttpResponseRedirect from django.shortcuts import render_to_response def register(request): if request.method == 'POST': form = UserCreationForm(request.POST) if form.is_valid(): new_user = form.save() return HttpResponseRedirect("/books/") else: form = UserCreationForm() return render_to_response("registration/register.html", { 'form': form, }) register.html: <html> <body> {% block title %}Create an account{% endblock %} {% block content %} <h1>Create an account</h1> <form action="" method="post">{% csrf_token %} {{ form.as_p }} <input type="submit" value="Create the account"> </form> {% endblock %} </body> </html>

    Read the article

  • Will Django user permissions work for models with inline tabular forms of other models?

    - by stinkypyper
    I am setting up DJango admin to make a model editable. On the same page I have tabular inline of a child model. Everything works as expected. Now I want to restrict permission on the tabular inline child form. Specifically remove update and delete permissions on it. I have tried removing the permissions for the admin user using the 'user permissions' of that user. However, it does not work. Does DJango respect the user permissions in regards to inline model forms?

    Read the article

  • Django URL Conf Returns Incorrect "Current URL"

    - by natnit
    I have a django app that is mostly done, and the URLs work perfectly when I run it with the manage.py runserver command. However, I've recently tried to get it running via lighttpd, and many links have stopped working. For example: http://mysite.com/races/32 should work, but instead throws this error message. Page not found (404) Request Method: GET Request URL: http://mysite.com/races/32 Using the URLconf defined in racetrack.urls, Django tried these URL patterns, in this order: ^admin/ ^create/$ ^races/$ ^races/(?P<race_id>\d+)/$ ^races/(?P<race_id>\d+)/manage/$ ^races/(?P<text>\w+)/$ ^user/(?P<kol_id>\d+)/$ ^$ ^login/$ ^logout/$ The current URL, 32, didn't match any of these. The request URL is accurate, but the last line (which displays the current URL) is giving 32 instead of races/32 as expected. Here is my urlconf: from django.conf.urls.defaults import * from django.contrib import admin admin.autodiscover() urlpatterns = patterns('racetrack.races.views', (r'^admin/', include(admin.site.urls)), (r'^create/$', 'create'), (r'^races/$', 'index'), (r'^races/(?P<race_id>\d+)/$', 'detail'), (r'^races/(?P<race_id>\d+)/manage/$', 'manage'), (r'^races/(?P<text>\w+)/$', 'index'), (r'^user/(?P<kol_id>\d+)/$', 'user'), # temporary for index page replace with welcome page (r'^$', 'index'), ) urlpatterns += patterns('django.contrib.auth.views', (r'^login/$', 'login', {'template_name': 'races/login.html'}), (r'^logout/$', 'logout', {'next_page': '/'}), ) Thank you.

    Read the article

  • customizing Django look and feel in Python

    - by user248237
    I am learning Django and got it to work with wsgi. I'm following the tutorial here: http://docs.djangoproject.com/en/1.1/intro/tutorial01/ My question is: how can I customize the look and feel of Django? Is there a repository of templates that "look good", kind of like there are for Wordpress, that I can start from? I find the tutorial counterintuitive in that it goes immediately toward customizing the admin page of Django, rather than the main pages visible to users of the site. Is there an example of a "typical" Django site, with a decent template, that I can look at and built on/modify? The polls application is again not very representative since it's so specialized. any references on this would be greatly appreciated. thanks.

    Read the article

  • In django, how can I include some default records in my models.py?

    - by kdt
    If I have a models.py like class WidgetType(models.Model): name = models.CharField(max_length=200) class Widget(models.Model): typeid = models.ForeignKey(WidgetType) data = models.CharField(max_length=200) How can I build in a set of built in constant values for WidgetType when I know I'm only going to have a certain few types of widget? Clearly I could fire up my admin interface and add them by hand, but I'd like to simplify configuration by having it built into the python.

    Read the article

< Previous Page | 19 20 21 22 23 24 25 26 27 28 29 30  | Next Page >