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• which regular expression will capture this sequence?

  - by John Smith

  The text follows this pattern <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) <tr class="text" (any sequence of characters here, except ABC)ABC(any sequence of characters here, except ABC) so basically the above line might repeat itself multiple times, and the idea is to retrieve the first 3 characters immediately after ABC. I have tried regular expressions along the lines of \<tr class="text" [.]+ABC(?<capture>[.]{3}) but they all fail. Can someone give me a hint?

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• Need a regular expression for an Irish phone number

  - by Eoghan O'Brien

  I need to validate an Irish phone number but I don't want to make it too user unfriendly, many people are used to writing there phone number with brackets wrapping their area code followed by 5 to 7 digits for their number, some add spaces between the area code or mobile operator. The format of Irish landline numbers is an area code of between 1 and 4 digits and a number of between 5 to 8 digits. e.g. (021) 9876543 (01)9876543 01 9876543 (0402)39385 I'm looking for a regular expression for Javascript/PHP. Thanks.

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• MySQL cross table regular expression match

  - by Josef Sábl

  I have a web application and I am working on engine that analyzes referals. Now I have table with pageviews along with referes that looks something like this: pv_id referer ------------------------------------------------------------ 5531854534 http://www.google.com/search?ie=UTF-8... 8161876343 http://google.cn/search?search=human+rights 8468434831 http://search.yahoo.com/search;_... The second table contains sources definitions like: source regex ------------------------------------------------------------ Google ^https?:\/\/[^\/]*google\.([a-z]{2,4})(\/.*|)$ Yahoo ^https?:\/\/[^\/]*yahoo\.com(\/.*|)$ What I want is third table created by joinin these two: pv_id source ------------------------------------------------------------ 5531854534 Google 8161876343 Google 8468434831 Yahoo How to join these tables with regular expression?

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• Regular expressions and matching URLs with metacharacters

  - by James P.

  I'm having trouble finding a regular expression that matches the following String. Korben;http://feeds.feedburner.com/KorbensBlog-UpgradeYourMind?format=xml;1 One problem is escaping the question mark. Java's pattern matcher doesn't seem to accept \? as a valid escape sequence but it also fails to work with the tester at myregexp.com. Here's what I have so far: ([a-zA-Z0-9])+;http://([a-zA-Z0-9./-]+);[0-9]+ Any suggestions? Edit: The original intent was to match all URLs that could be found after the first semi colon.

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• Regular expression problem (PHP)

  - by Marcos

  Hello all. I have a little problem with my regular expression, that I use in PHP. My code identify all tags of my content and add a link in this image. My code is working when I use dinamycally, without any defined image. When I try with a imapge path, the code does not work. How can I solve this problem? Working code: $content = preg_replace('/(<img .*?src="(.+?)".*?>)/','<a class="nyromodal foto" href="'.$imagem_wordpress.'">\1</a>', $content); Problem code: $content = preg_replace('/(<img .*?src="ttp://mysite.com/files/2010/04/bac-gallery-site-matters-saline-project1.jpg".*?>)/','<a class="nyromodal foto" href="'.$imagem_wordpress.'">\1</a>', $content);

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• Buggy Perl regular expression

  - by Tichomir Mitkov

  Hi, there I'm writing a program that has to get values from a file. In the file each line indicates an entity. Each entity has three values. For example: Value1 Value2 value3 I have a regular expresion to match them m/(.*?) (.*?) (.*?)/m; But it seems that the third value in never matched! The only way to match the third value is to add another value in the file and another "matching brackets" in the expresion. But this does not satisfy me. Thanks in Advance!

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• question on regular servlets within GWT (working in dev mode ,not working in deployment in tomcat)

  - by molleman

  Hello guys, i am having trouble with my web application developed in GWT. the application allows users to upload and download using an upload servlet and a download servlet, the upload servlet was created using the gwtUpload library. the download servlet is using regular HTTPServlet. when i run the application within eclipse the download servlet works fine, when i deploy it to tomcat, when a user selects to upload a file, the file does not download, when a user selects a link to download a file, this error is returned type Status report message /testhibernategilead/downloadServlet description The requested resource (/testhibernategilead/downloadServlet) is not available. can anyone explain why this is

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• Dreamweaver regular expression substitution followed by number

  - by mark

  Hi. I'm using Dreamweaver to update copyright dates across my site. I want to preserve the existing spacing (or lack thereof) between years. Examples: © 2002-2008 should update to © 2002-2009 © 2003 - 2008 should update to © 2003 - 2009 This is the regular expression I'm using to accomplish this in Dreamweaver's find & replace function Find: ©\s*(\d{4}\s*-\s*)\d{3}[^9] Replace: © $1 2009 Here's the PROBLEM: This expression works, but has that that extra space between the hyphen and 2009. If I write the replace expression without the space, as © $12009 then dreamweaver looks for the 12,009th substitution in the find expression, and, not finding one, prints $12009. Any ideas?

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• ASP.NET MVC submitting json array to controller as regular post request (nonajax)

  - by j3ko

  All the examples of json I can find online only show how to submit json arrays w/ the jquery command $.ajax(). I'm submitting some data from a custom user control as a json array. I was wondering if it's possible to submit a json array as a regular post request to the server (like a normal form) so the browser renders the page returned. Controller: [JsonFilter(Param = "record", JsonDataType = typeof(TitleViewModel))] public ActionResult SaveTitle(TitleViewModel record) { // save the title. return RedirectToAction("Index", new { titleId = tid }); } Javascript: function SaveTitle() { var titledata = GetData(); $.ajax({ url: "/Listing/SaveTitle", type: "POST", data: titledata, contentType: "application/json; charset=utf-8", }); } Which is called from a save button. Everything works fine but the browser stays on the page after submitting. I was thinking of returning some kind of custom xml from the server and do javascript redirect but it seems like a very hacky way of doing things. Any help would be greatly appreciated.

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• Regular expression to match any table tag

  - by keeg

  I'm trying to write a regular expression to see if a string contains any of the typical table tags: <table></table> <td></td> <th></th> <tr></tr> <thead></thead> <tfoot></tfoot> <tbody></tbody> Along with tags that may contain other attributes e.g: <table border="1"> I've come up with this so far, however, it matches <br /> tag and I'm not sure why: /<\/?[table|td|th|tr|tfoot|thead|tbody]{1,}>?/ http://www.rexfiddle.net/20Xtqka

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• Which is more efficient regular expression?

  - by Vagnerr

  I'm parsing some big log files and have some very simple string matches for example if(m/Some String Pattern/o){ #Do something } It seems simple enough but in fact most of the matches I have could be against the start of the line, but the match would be "longer" for example if(m/^Initial static string that matches Some String Pattern/o){ #Do something } Obviously this is a longer regular expression and so more work to match. However I can use the start of line anchor which would allow an expression to be discarded as a failed match sooner. It is my hunch that the latter would be more efficient. Can any one back me up/shoot me down :-)

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• Regular expression in Ruby

  - by Sainath Mallidi

  Hi, Could anybody help me make a proper regular expression from a bunch of text in Ruby. I tried a lot but I don't know how to handle variable length titles. The string will be of format <sometext>title:"<actual_title>"<sometext>. I want to extract actual_title from this string. I tried /title:"."/ but it doesnt find any matches as it expects a closing quotation after one variable from opening quotation. I couldn't figure how to make it check for variable length of string. Any help is appreciated. Thanks.

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• PHP & Regular expression: keyword just occurs once

  - by lauthiamkok

  Hi, how can I make sure a certain keyword just occurs once in the input with regular expression? I think there is some mistakes in the expression below as I can repeat the same keywords, if (!preg_match('/\b(.php?){1}\b/', $cfg_path)) { $error = true; echo '<error elementid="cfg_path" message="PATH - make sure you have a \'.php?\' in the path."/>'; } I just want this to be true, form.php?category=something or form.php? but not this, form.php?.php?category=something or form.php?.php? please let me know how to fix it. thanks.

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• Dealing with regular expressions, Python

  - by Gusto

  I want to remove some symbols from a string using a regular expression, for example: == (that occur both at the beginning and at the end of a line), * (at the beginning of a line ONLY). def some_func(): clean = re.sub(r'= {2,}', '', clean) #Removes 2 or more occurrences of = at the beg and at the end of a line. clean = re.sub(r'^\* {1,}', '', clean) #Removes 1 or more occurrences of * at the beginning of a line. What's wrong with my code? It seems like expressions are wrong. How do I remove a character/symbol if it's at the beginning or at the end of the line (with one or more occurrences)?

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• Regular expressions in python unicode

  - by Remy

  I need to remove all the html tags from a given webpage data. I tried this using regular expressions: import urllib2 import re page = urllib2.urlopen("http://www.frugalrules.com") from bs4 import BeautifulSoup, NavigableString, Comment soup = BeautifulSoup(page) link = soup.find('link', type='application/rss+xml') print link['href'] rss = urllib2.urlopen(link['href']).read() souprss = BeautifulSoup(rss) description_tag = souprss.find_all('description') content_tag = souprss.find_all('content:encoded') print re.sub('<[^>]*>', '', content_tag) But the syntax of the re.sub is: re.sub(pattern, repl, string, count=0) So, I modified the code as (instead of the print statement above): for row in content_tag: print re.sub(ur"<[^>]*>",'',row,re.UNICODE But it gives the following error: Traceback (most recent call last): File "C:\beautifulsoup4-4.3.2\collocation.py", line 20, in <module> print re.sub(ur"<[^>]*>",'',row,re.UNICODE) File "C:\Python27\lib\re.py", line 151, in sub return _compile(pattern, flags).sub(repl, string, count) TypeError: expected string or buffer What am I doing wrong?

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• Jointure in linq with a regular expression

  - by Graveen

  I'm actually using a join in linqtosql (via dblinq). I'm trying to include a regular expression in the join part of the linq query. from i in collectiona join j in collectionb on Regex.IsMatch(i.name, j.jokered_name) equals true (...) I agree i can push the RegExp check in the where part of the linq query, but i was wondering if it is possible in the join part ? The above code wants an "i equals j" code structure. One thing i think to perform is overriding Equals() which 'll contains the RegEx.IsMatch() stuff and put a simple i equals j in the join part. Any suggestions about my problem ?

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• Regular Expression - Password Validation is not working

  - by Kesavan

  Hi, I have to validate the password using regex. The password rule is like at least 1 uppercase and at least 2 numeric. It works fine except if the character comes at the end of the string. The regular expression which i am using is "^(?=.*\d.{2})(?=.*[A-Z].{1})(?=.*[@#$%^&+=].{2}).{8,12}$" Rules: minimum length = 8 minimum uppercase = 1 minimum numeric = 2 minimum special character = 1 It works for Test123$$, Test$123, TEST123$s, Test123$1, Test12$3 but it fails if the character specified comes at the end of the string like Test123$, Test$a12, Test12aa@, 123aa@@T. Please let me know if there is any fix for this.

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• Regular Expression: Changes HTML Attributes Value to some pattern

  - by brain90

  Dear Engineers, I'm a newbie in RegEx I have thousands html tags, have wrote like this: <input type="text" name="CustomerName" /> <input type="text" name="SalesOrder"/> I need to match every name attribute values and convert them all to be like this: CustomerName -> cust[customer_name] SalesOrder -> cust[sales_order] So the results will be : <input type="text" name="cust[customer_name]" /> <input type="text" name="cust[sales_order]" /> My best try have stuck in this pattern: name=\"[a-zA-Z0-9]*\" - just found name="CustomerName" Please guide me wrote some Regular Expression magics to done this, I'm using Netbeans PDT. Thanks in advance for any pointers!.

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• Regular Expression to match unlimited number of options

  - by Pekka

  I want to be able to parse file paths like this one: /var/www/index.(htm|html|php|shtml) into an ordered array: array("htm", "html", "php", "shtml") and then produce a list of alternatives: /var/www/index.htm /var/www/index.html /var/www/index.php /var/www/index.shtml Right now, I have a preg_match statement that can split two alternatives: preg_match_all ("/\(([^)]*)\|([^)]*)\)/", $path_resource, $matches); Could somebody give me a pointer how to extend this to accept an unlimited number of alternatives (at least two)? Just regarding the regular expression, the rest I can deal with. The rule is: The list needs to start with a ( and close with a ) There must be one | in the list (i.e. at least two alternatives) Any other occurrence(s) of ( or ) are to remain untouched.

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• Mutually exclusive regular expressions

  - by CaptnCraig

  If I have a list of regular expressions, is there an easy way to determine that no two of them will both return a match for the same string? That is, the list is valid if and only if for all strings a maximum of one item in the list will match the entire string. It seems like this will be very hard (maybe impossible?) to prove definitively, but I can't seem to find any work on the subject. The reason I ask is that I am working on a tokenizer that accepts regexes, and I would like to ensure only one token at a time can match the head of the input.

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• Constructing a regular expression to wrap images with <a>

  - by bobo

  A web page contains lots of image elements: <img src="myImage.gif" width="180" height="18" /> But they may not be very well-formed, for example, the width or height attribute may be missing. And it also may not be properly closed with /. The src attribute is always there. I need a regular expression that wraps these with a hyperlink having href set to the src of the img. <a href="myImage.gif" target="_blank"><img src="myImage.gif" width="180" height="18" /></a> I can successfully locate the images using this regexp in this editor: http://gskinner.com/RegExr/: <img src="([^<]*)"[^<]*> But what is the next step?

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• Regular non-low energy bluetooth for IOS

  - by user3712524

  Ok, so I can't get my app to connect with a peripheral using bluetooth low-energy(my app is installed on an iPhone 5s and I have LightBlue installed on an iPhone 4S, simulating a peripheral. I also have light blue installed on the 5s, simulating a central, to verify that the two can connect and they do.) I have verified that the centralManager is instantiating and the State is powered on. So, my question is, is regular bluetooth still a viable option? Can I just use the GameKit API and go that route? Thanks in advance!

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• Complex regular expression

  - by Jose3d

  Hello, i will like to capture a substring part of a text choosing the number of characters but if any word is cut then get until de last blank. As example if this is the text: "This is an example of text lorem ipsum, etc..." and i would like to get for instance 12 characters that are: "This is an e". In this case example is cutted, then i would like to get "This is an". Its possible do this with Regular Expressions? Thanks in advance. Jose

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• Regular expressions in java

  - by rookie

  String s= "(See <a href=\"/wiki/Grass_fed_beef\" title=\"Grass fed beef\" " + "class=\"mw-redirect\">grass fed beef.) They have been used for " + "<a href=\"/wiki/Paper\" title=\"Paper\">paper-making since " + "2400 BC or before."; In the string above I have inter-mixed html with text. Well the requirement is that the output looks like:- They have been used for paper-making since 2400 BC or before. Could some one help me with a generic regular expression that would produce the desired output from the given input? Thanks in advance!

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• how to write regular expression to validate a string using regex in C#

  - by Charu

  I need to validate a user input based on condition. i wrote a regular expression to do so, but it's failing not sure why. Can somebody point where i am making mistake? Regex AccuracyCodeHexRegex = new Regex(@"^[PTQA]((0|8)[01234567]){2}$"); This is what i am trying to validate(If the string is a subset of these strings then it is valid): Phh, Thh, Qhh, Ahh where 'h' is a hex digit in the set {00, 80, 01, 81, 02, 82, 03, 83, 04, 84, 05, 85, 06, 86, 07, 87} Ex: P00 is valid P20 is not valid

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