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  • xVal and Regular Expression Match

    - by gmcalab
    I am using xVal to validate my forms in asp.net MVC 1.0 Not sure why my regular expression isn't validating correctly. It validates with the value of "12345" It validates with the value of "12345 " It validates with the value of "12345 -" It validates with the value of "12345 -1" It validates with the value of "12345 -12" ... etc For a zip code I expect one of the two patterns: 12345 or 12345 -1234 Here are the two regex I tried: (\d{5})((( -)(\d{4}))?) (\d{5})|(\d{5} -\d{4}) Here is my MetaData class for xVal [MetadataType(typeof(TIDServiceMetadata))] public class TIDServiceStep : TIDDetail { public class TIDServiceMetadata { [Required(ErrorMessage = " [Required] ")] [RegularExpression(@"(\d{5})|(\d{5} -\d{4})", ErrorMessage = " Invalid Zip ")] public string Zip { get; set; } } } Here is my aspx page: <% Html.BeginForm("Edit", "Profile", FormMethod.Post); %> <table border="0" cellpadding="0" cellspacing="0"> <tr> <td> <h6>Zip:</h6> </td> <td> <%= Html.TextBox("Profile.Zip")%> </td> </tr> <tr> <td> <input type="submit"/> </td> </tr> </table> <% Html.EndForm(); %> <% Html.Telerik().ScriptRegistrar() .OnDocumentReady(() => { %> <%= Html.ClientSideValidation<TIDProfileStep>("Profile").SuppressScriptTags() %> <% }); %>

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  • SoundManager / Jquery / Regular expression : Parse class name before certain character To Get SoundI

    - by j-man86
    So I am trying to access a jquery soundmanager variable from one script (wpaudio.js – from the wp-audio plugin) inside of another (init.js – my own javascript). I am creating an alternate pause/play button higher up on the page and need to resume the current soundID, which is contained as part of a class name in the DOM. Here is the code that creates that class name in wpaudio.js: function wpaButtonCheck() { if (!this.playState || this.paused) jQuery('#' + this.sID + '_play').attr('src', wpa_url + '/wpa_play.png'); else jQuery('#' + this.sID + '_play').attr('src', wpa_url + '/wpa_pause.png'); } Here is the output: where wpa0 would be the sID of the sound I need. My current script in init.js is: $('.mixesSidebar #currentSong .playBtn').toggle(function() { soundManager.pauseAll(); $(this).addClass('paused'); }, function() { soundManager.resumeAll(); $(this).removeClass('paused'); }); I need to change resumeAll to "resume(this.sID)", but I need to somehow store the sID onclick and call it in the above function. Alternately, I think a regular expression that could get the class name of the current play button and either parse the string up to the "_play" or use a trim function to get rid of "_play"– but I'm not sure how to do this. Thanks for your help!

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  • Some regular expression help?

    - by Rohan
    Hey there. I'm trying to create a Regex javascript split, but I'm totally stuck. Here's my input: 9:30 pm The user did action A. 10:30 pm Welcome, user John Doe. ***This is a comment 11:30 am This is some more input. I want the output array after the split() to be (I've removed the \n for readability): ["9:30 pm The user did action A.", "10:30 pm Welcome, user John Doe.", "***This is a comment", "11:30 am This is some more input." ]; My current regular expression is: var split = text.split(/\s*(?=(\b\d+:\d+|\*\*\*))/); This works, but there is one problem: the timestamps get repeated in extra elements. So I get: ["9:30", "9:30 pm The user did action A.", "10:30", "10:30 pm Welcome, user John Doe.", "***This is a comment", "11:30", "11:30 am This is some more input." ]; I cant split on the newlines \n because they aren't consistent, and sometimes there may be no newlines at all. Could you help me out with a Regex for this? Thanks so much!!

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  • Regular Expression doesn't match

    - by dododedodonl
    Hi All, I've got a string with very unclean HTML. Before I parse it, I want to convert this: <TABLE><TR><TD width="33%" nowrap=1><font size="1" face="Arial"> NE </font> </TD> <TD width="33%" nowrap=1><font size="1" face="Arial"> DEK </font> </TD> <TD width="33%" nowrap=1><font size="1" face="Arial"> 143 </font> </TD> </TR></TABLE> in NE DEK 143 so it is a bit easier to parse. I've got this regular expression (RegexKitLite): NSString *str = [dataString stringByReplacingOccurrencesOfRegex:@"<TABLE><TR><TD width=\"33%\" nowrap=1><font size=\"1\" face=\"Arial\">(.+?)<\\/font> <\\/TD>(.+?)<TD width=\"33%\" nowrap=1><font size=\"1\" face=\"Arial\">(.+?)<\\/font> <\\/TD>(.+?)<TD width=\"33%\" nowrap=1><font size=\"1\" face=\"Arial\">(.+?)<\\/font> <\\/TD>(.+?)<\\/TR><\\/TABLE>" withString:@"$1 $3 $5"]; I'm no an expert in Regex. Can someone help me out here? Regards, dodo

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  • Treetop basic parsing and regular expression usage

    - by ucint
    I'm developing a script using the ruby Treetop library and having issues working with its syntax for regex's. First off, many regular expressions that work in other settings dont work the same in treetop. This is my grammar: (myline.treetop) grammar MyLine rule line string whitespace condition end rule string [\S]* end rule whitespace [\s]* end rule condition "new" / "old" / "used" end end This is my usage: (usage.rb) require 'rubygems' require 'treetop' require 'polyglot' require 'myline' parser = MyLineParser.new p parser.parse("randomstring new") This should find the word new for sure and it does! Now I wont to extend it so that it can find new if the input string becomes "randomstring anotherstring new yetanother andanother" and possibly have any number of strings followed by whitespace (tab included) before and after the regex for rule condition. In other words, if I pass it any sentence with the word "new" etc in it, it should be able to match it. So let's say I change my grammar to: rule line string whitespace condition whitespace string end Then, it should be able to find a match for: p parser.parse("randomstring new anotherstring") So, what do I have to do to allow the string whitespace to be repeated before and after condition? If I try to write this: rule line (string whitespace)* condition (whitespace string)* end , it goes in an infinite loop. If i replace the above () with [], it returns nil In general, regex's return a match when i use the above, but treetop regex's dont. Does anyone have any tips/points on how to go about this? Plus, since there isn't much documentation for treetop and the examples are either too trivial or too complex, is there anyone who knows a more thorough documentation/guide for treetop?

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  • SQL with Regular Expressions vs Indexes with Logical Merging Functions

    - by geeko
    Hello Lads, I am trying to develop a complex textual search engine. I have thousands of textual pages from many books. I need to search pages that contain specified complex logical criterias. These criterias can contain virtually any compination of the following: A: Full words. B: Word roots (semilar to stems; i.e. all words with certain key letters). C: Word templates (in some languages are filled in certain templates to form various part of speech such as adjactives, past/present verbs...). D: Logical connectives: AND/OR/XOR/NOT/IF/IFF and parentheses to state priorities. Now, would it be faster to have the pages' full text in database (not indexed) and search though them all using SQL and Regular Expressions ? Or would it be better to construct indexes of word/root/template-page-location tuples. Hence, we can boost searching for individual words/roots/templates. However, it gets tricky as we interdouce logical connectives into our query. I thought of doing the following steps in such cases: 1: Seperately search for each individual words/roots/templates in the specified query. 2: On priority bases, we merge two result lists (from step 1) at a time depedning on the logical connective For example, if we are searching for "he AND (is OR was)": 1: We shall search for "he", "is" and "was" seperately and get result lists for each word. 2: Merge the result lists of "is" and "was" using the merging function OR-MERGE 3: Merge the merged result list from the OR-MERGE function with the one of "he" using the merging function AND-MERGE The result of step 3 is then returned as the result of the specified query. What do you think gurues ? Which is faster ? Any better ideas ? Thank you all in advance.

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  • Extracting one word based on special character using Regular Expression in C#

    - by Jankhana
    I am not very good at regular expression but want to do some thing like this : string="c test123 d split" I want to split the word based on "c" and "d". this can be any word which i already have. The string will be given by the user. i want "test123" and "split" as my output. and there can be any number of words i.e "c test123 d split e new" etc. c d e i have already with me. I want just the next word after that word i.e after c i have test123 and after d i have split and after e i have new so i need test123 and split and new. how can I do this??? And one more thing I will pass just c first than d and than e. not together all of them. I tried string strSearchWord="c "; Regex testRegex1 = new Regex(strSearchWord); List lstValues = testRegex1.Split("c test123 d split").ToList(); But it's working only for last character i.e for d it's giving the last word but for c it includes test123 d split. How shall I do this???

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  • Regular expression either/or not matching everything

    - by dwatransit
    I'm trying to parse an HTTP GET request to determine if the url contains any of a number of file types. If it does, I want to capture the entire request. There is something I don't understand about ORing. The following regular expression only captures part of it, and only if .flv is the first int the list of ORd values. (I've obscured the urls with spaces because Stackoverflow limits hyperlinks) regex: GET.?(.flv)|(.mp4)|(.avi).? test text: GET http: // foo.server.com/download/0/37/3000016511/.flv?mt=video/xy match output: GET http: // foo.server.com/download/0/37/3000016511/.flv I don't understand why the .*? at the end of the regex isnt callowing it to capture the entire text. If I get rid of the ORing of file types, then it works. Here is the test code in case my explanation doesn't make sense: public static void main(String[] args) { // TODO Auto-generated method stub String sourcestring = "GET http: // foo.server.com/download/0/37/3000016511/.flv?mt=video/xy"; Pattern re = Pattern.compile("GET .?\.flv."); // this works //output: // [0][0] = GET http :// foo.server.com/download/0/37/3000016511/.flv?mt=video/xy // the match from the following ends with the ".flv", not the entire url. // also it only works if .flv is the first of the 3 ORd options //Pattern re = Pattern.compile("GET .?(\.flv)|(\.mp4)|(\.avi).?"); // output: //[0][0] = GET http: // foo.server.com/download/0/37/3000016511/.flv // [0][1] = .flv // [0][2] = null // [0][3] = null Matcher m = re.matcher(sourcestring); int mIdx = 0; while (m.find()){ for( int groupIdx = 0; groupIdx < m.groupCount()+1; groupIdx++ ){ System.out.println( "[" + mIdx + "][" + groupIdx + "] = " + m.group(groupIdx)); } mIdx++; } } }

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  • I need to remove Java Script tags using regular expressions and JRegex

    - by piotr
    I need to remove all the Java Script tags and the content in between and style tags from the HTML code of web pages.So far I've come up with this expression : "(<[ \r\n\t]script([ \r\n\t]|){1,}([ \r\n\t]|.)?)|(<[ \r\n\t]noscript([ \r\n\t]|){1,}([ \r\n\t]|.)?)|(<[ \r\n\t]style([ \r\n\t]|){1,}([ \r\n\t]|.)?)" I use JRegex library to work with regular expressions. When I test it in any regex tester it works just fine, but once I run my program - it all crashes down with this error report: Exception in thread "Thread-0" java.lang.StackOverflowError at java.util.regex.Pattern$BranchConn.match(Unknown Source) at java.util.regex.Pattern$BmpCharProperty.match(Unknown Source) at java.util.regex.Pattern$Branch.match(Unknown Source) at java.util.regex.Pattern$GroupHead.match(Unknown Source) at java.util.regex.Pattern$LazyLoop.match(Unknown Source) at java.util.regex.Pattern$GroupTail.match(Unknown Source) at java.util.regex.Pattern$BranchConn.match(Unknown Source) at java.util.regex.Pattern$CharProperty.match(Unknown Source) at java.util.regex.Pattern$Branch.match(Unknown Source) at java.util.regex.Pattern$GroupHead.match(Unknown Source) at java.util.regex.Pattern$LazyLoop.match(Unknown Source) .................................. And it keeps on going forever. If anyone can give me an advice on this one - I'll be very grateful.

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  • Python Regular Expressions: Capture lookahead value (capturing text without consuming it)

    - by Lattyware
    I wish to use regular expressions to split words into groups of (vowels, not_vowels, more_vowels), using a marker to ensure every word begins and ends with a vowel. import re MARKER = "~" VOWELS = {"a", "e", "i", "o", "u", MARKER} word = "dog" if word[0] not in VOWELS: word = MARKER+word if word[-1] not in VOWELS: word += MARKER re.findall("([%]+)([^%]+)([%]+)".replace("%", "".join(VOWELS)), word) In this example we get: [('~', 'd', 'o')] The issue is that I wish the matches to overlap - the last set of vowels should become the first set of the next match. This appears possible with lookaheads, if we replace the regex as follows: re.findall("([%]+)([^%]+)(?=[%]+)".replace("%", "".join(VOWELS)), word) We get: [('~', 'd'), ('o', 'g')] Which means we are matching what I want. However, it now doesn't return the last set of vowels. The output I want is: [('~', 'd', 'o'), ('o', 'g', '~')] I feel this should be possible (if the regex can check for the second set of vowels, I see no reason it can't return them), but I can't find any way of doing it beyond the brute force method, looping through the results after I have them and appending the first character of the next match to the last match, and the last character of the string to the last match. Is there a better way in which I can do this? The two things that would work would be capturing the lookahead value, or not consuming the text on a match, while capturing the value - I can't find any way of doing either.

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  • Regular expression of unicode characters on string

    - by Marcus King
    I'm working in c# doing some OCR work and have extracted the text I need to work with. Now I need to parse a line using Regular Expressions. string checkNum; string routingNum; string accountNum; Regex regEx = new Regex(@"\u9288\d+\u9288"); Match match = regEx.Match(numbers); if (match.Success) checkNum = match.Value.Remove(0, 1).Remove(match.Value.Length - 1, 1); regEx = new Regex(@"\u9286\d{9}\u9286"); match = regEx.Match(numbers); if(match.Success) routingNum = match.Value.Remove(0, 1).Remove(match.Value.Length - 1, 1); regEx = new Regex(@"\d{10}\u9288"); match = regEx.Match(numbers); if (match.Success) accountNum = match.Value.Remove(match.Value.Length - 1, 1); The problem is that the string contains the necessary unicode characters when I do a .ToCharArray() and inspect the contents of the string, but it never seems to recognize the unicode characters when I parse the string looking for them. I thought strings in C# were unicode by default.

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  • Regular Expression Newbie

    - by Registered User
    I need to parse strings inputs where the columns are separated by columns and any field that contains a comma in the data is wrapped in quotes (commas separated, quoted text identifiers). For this project I need to remove the quotes and any commas that occur between pairs of quotes. Basically, I need to remove commas and quotes that are contained in fields while preserving the commas that are used to separate the fields. Here's a little code I put together that handles the simple scenario: // Sample input 1: This works and covers 99% of the records that I need to parse. string str1 = "[email protected],2010/03/27 12:2:02,,some_first_name,some_last_name,,\"This Address Works, Suite 200\",Some City,TN,09876-5432,9795551212x123,XYZ"; str1 = Regex.Replace(str1, "\"([^\"^,]*),([^\"^,]*)\"", "$1$2"); Console.WriteLine(str1); // Outputs: [email protected],2010/03/27 12:2:02,,some_first_name,some_last_name,,This Address Works Suite 200,Some City,TN,09876-5432,9795551212x123,XYZ Although this code works for most of my records, it doesn't work when a field contains more than one commas. What I would like to do is modify the code so that it remove each instance of a comma contained within the column no matter how many commas there are in the field. I don't want to hard code only handling 2 commas, or 3 commas, or 25 commas. The code should just remove all the commas in the field. Below is an example of what my code doesn't handle properly. // Sample input 2: This doesn't work since there is more than 1 comma between the quotes. string str2 = "[email protected],2010/03/27 12:2:02,,some_first_name,some_last_name,,\"i,l,k,e, c,o,m,m,a,s, i,n ,m,y, f,i,e,l,d\",Some City,TN,09876-5432,9795551212x123,XYZ"; str2 = Regex.Replace(str2, "\"([^\"^,]*),([^\"^,]*)\"", "$1$2"); Console.WriteLine(str2); // Desired output: [email protected],2010/03/27 12:2:02,,some_first_name,some_last_name,,i like commas in my field,Some City,TN,09876-5432,9795551212x123,XYZ Any help would be appreciated for this Regular Expression newbie.

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  • how to make Regular expression into non-greedy ?

    - by Rueta
    Hi everyone! I have made a Work with JQ. My Work is a string width a special character block begin and end of string. I want take the text in that special characters, i used regular expression for find in string, but how to make JQ find multi result when have two special character or more. My html here; <div id="container"> <div id="textcontainer"> Cu?c chi?n pháp lý gi?a [|co th?|nghi?m|] th? tru?ng [|test2|dây là test l?n 2|] ch?ng khoán [|M?|day la nuoc my|] và ngân hàng d?u tu quy?n l?c nh?t Ph? Wall m?i ch? b?t d?u. </div> </div> and my JQ $(document).ready(function() { var takedata = $("#textcontainer").text(); var test = 'abcd adddb'; var filterdata = takedata.match(/(\[.+\])/); alert(filterdata); //end write js }); my result is: [|co th?|nghi?m|] th? tru?ng [|test2|dây là test l?n 2|] ch?ng khoán [|M?|day la nuoc my|] . but this is'nt the result i want :(. How to get [text] for times 1 and [demo] for times 2 ?. pls help me !. thankyou :)

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  • regular expression for indian vehicle number in javascript and php

    - by I Like PHP
    i need regular expression in java script as well as in PHP for Indian vehicle NUMBER here are conditions list let expression is (x)(y)(z)(m)(a)(b)(c) 1. (x) contains only alphabets of length 2. 2. (y) may be - or single space ' ' 3. (z) contains only numbers of length 2 4. (m) may be or , or single space ' ' 5. length of (a) can be 2 or 3. contains alphanumeric value with minimum one alphabetic character. 6. (b) may be - or single space ' ' ( similar to (y) ) 7. (c) contains only numbers of length 4 i show you the various examples of vehicle number valid number RJ-14,NL-1234 RJ-01,4M-5874 RJ-07,14M-2345 RJ 07,3M 2345 RJ-07,3M-8888 RJ 07 4M 2345 RJ 07,4M 2933 invalid number RJ-07 3M 1234 ( both (y) and (b) should be same). RJ-07 M3-1234 ((a) must ends with alphabat). rj-07 M3-123 ( length of (c) must be 4).

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  • Regular expression for dividing country calling codes

    - by RickiG
    Hi I have a list of calling codes for all countries(the phone number prefixes), I would like to split them up in the country name and the actual code so I can put then into an xml. I have tried back and forth but can not get a regexp going that takes all cases into account. I think it is fairly simple for someone with a bit of experience. The codes have these formats: Afghanistan 93 Anguilla 1 264 Antarctica 6721 Antigua and Barbuda 1 268 Bosnia and Herzegovina 387 Canada 1 Congo, Republic of the 242 Cote d'Ivoire 225 Ireland (Eire) 353 United States of America 1 There are around 235 of them in total, but these are the regulars and the exceptions. ^[a-zA-Z]\s,'()] for between 1 and X words and then it is [0-9\s]{1,5}$ for the numbers: X XX XXX XXXX X XXX So if I should express it as a sentence it would be: "from beginning of a line, take all characters (1) including space,'() until you encounter digits, then take all of these including space(2) until you encounter a line break." I am using TextMate, and the docs says: TextMate uses the Oniguruma regular expression library by K. Kosako. I would appreciate any help given:) Thank you.

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  • Regular Expression to replace a pattern at runtime(C#3.0)

    - by deepak.kumar.goyal
    I have a requirement. I have some files in a folder among which some file names looks like say **EUDataFiles20100503.txt, MigrateFiles20101006.txt.** Basically these are the files that I need to work upon. Now I have a config file where it is mentioned as the file pattern type as EUDataFilesYYYYMMDD, MigrateFilesYYYYMMDD. Basically the idea is that, the user can configure the file pattern and based on the pattern mentioned, I need to search for those files that are present in the folder. i.e. at runtime the YYYYMMDD will get replaced by the Year Month and Date Values. It does not matter what dates will be there(but not with time stamp ; only dates)). And the EUDataFiles or MigrateFiles names will be there.(they are fixed) i.e. If the folder has a file name as EUDataFile20100504.txt(i.e. Year 2010, Month 05, Day 04) , I should ignore this file as it is not EUDataFiles20100504.txt (kindly note that the name is plural - File(s) and not file for which the system will ignore the file). Similarly, if the Pattern given as EUDataFilesYYYYMMDD and if the file present is of type EUDataFilesYYYYDDMM then also the system should ignore. How can I solve this problem? Is it doable using regular expression(Replacing the pattern at runtime)? If so can anyone be good enough in helping me out? I am using C#3.0 and dotnet framework 3.5. Thanks

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  • How to use PHP preg_replace regular expression to find and replace text

    - by Roger
    I wrote this PHP code to make some substitutions: function cambio($txt){ $from=array( '/\+\>([^\+\>]+)\<\+/', //finds +>text<+ '/\%([^\%]+)\%/', //finds %text% ); $to=array( '<span class="P">\1</span>', '<span>\1</span>', ); return preg_replace($from,$to,$txt); } echo cambio('The fruit I most like is: +> %apple% %banna% %orange% <+.'); Resulting into this: The fruit I most like is: <span class="P"> <span>apple</span> <span>banna</span> <span>orange</span> </span>. however I needed to identify the fruit's span tags, like this: The fruit I most like is: <span class="P"> <span class="a">apple</span> <span class="b">banna</span> <span class="c">coco</span> </span>. I'd buy a fruit to whom discover a regular expression to accomplish this :-)

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  • Regular expression, excluding .. in suffix of email addy

    - by user1754700
    This is homework, I've been working on it for a while, I've done lots of reading and feel I have gotten pretty familiar with regex for a beginner. I am trying to find a regular expression for validating/invalidating a list of emails. There are two addresses which are giving me problems, I can't get them both to validate the correct way at the same time. I've gone through a dozen different expressions that work for all the other emails on the list but I can't get those two at the same time. First, the addresses. [email protected] - invalid [email protected] - valid The part of my expression which validates the suffix I originally started with @.+\\.[[a-z]0-9]+ And had a second pattern for checking some more invalid addresses and checked the email against both patterns, one checked for validity the other invalidity but my professor said he wanted it all in on expression. @[[\\w]+\\.[\\w]+]+ or @[\\w]+\\.[\\w]+ I've tried it written many, many different ways but I'm pretty sure I was just using different syntax to express these two expressions. I know what I want it to do, I want it to match a character class of "character+"."character+"+ The plus sign being at least one. It works for the invalid class when I only allow the character class to repeat one time(and obviously the ip doesn't get matched), but when I allow the character class to repeat itself it matches the second period even thought it isn't preceded by a character. I don't understand why.

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  • Invalid quantifer error using Regular Expression (UK Telephone numbers)

    - by Matt
    HI all, as per the title I am getting the error "Invalid Quantifier" Trying to match this reg ex:- ^(((+44\s?\d{4}|(?0\d{4})?)\s?\d{3}\s?\d{3})|((+44\s?\d{3}|(?0\d{3})?)\s?\d{3}\s?\d{4})|((+44\s?\d{2}|(?0\d{2})?)\s?\d{4}\s?\d{4}))(\s?#(\d{4}|\d{3}))?$ Infact ive tried a few UK telephone number regex's from the regex librairy but im getting the same error all the time. If anyone can help id be much appreciative! Just for info, im using the jQuery form validation librairy, and here is my code: - $(document).ready(function(){ //Set Fields to be validated $("#EventForm").validate(); $( "#StartDate" ).datepicker(); $( "#EndDate" ).datepicker(); //Add Postcode Regex Method to Validator Function $.validator.addMethod( "postcode", function(value, element, regexp) { var check = false; var re = new RegExp(regexp); return this.optional(element) || re.test(value); }, "Please enter a valid postcode." ); //Add UK Telephone number Regex Method to Validator Function $.validator.addMethod( "telephone", function(value, element, regexp) { var check = false; var re = new RegExp(regexp); return this.optional(element) || re.test(value); }, "Please enter a valid UK telephone number in the format - 01856 666666." ); //Add Postcode Regular Expression Rule to Postcode Field $("#EventPostcode").rules("add", { postcode: "^([a-zA-Z]){1}([0-9][0-9]|[0-9]|[a-zA-Z][0-9][a-zA-Z]|[a-zA-Z][0-9][0-9]|[a-zA-Z][0-9]){1}([ ])([0-9][a-zA-z][a-zA-z]){1}$"}); $("#EventTelephoneNo").rules("add", { telephone: "^(((\+44\s?\d{4}|\(?0\d{4}\)?)\s?\d{3}\s?\d{3})|((\+44\s?\d{3}|\(?0\d{3}\)?)\s?\d{3}\s?\d{4})|((\+44\s?\d{2}|\(?0\d{2}\)?)\s?\d{4}\s?\d{4}))(\s?\#(\d{4}|\d{3}))?$"}); }); Many thanks

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  • AWK: compare apache dates without using regular expression

    - by smallmeans
    I'm writing a loganalysis application and wanted to grab apache log records between two certain dates. Assume that a date is formated as such: 22/Dec/2009:00:19 (day/month/year:hour:minute) Currently, I'm using a regular expression to replace the month name with its numeric value, remove the separators, so the above date is converted to: 221220090019 making a date comparison trivial.. but.. Running a regex on each record for large files, say, one containing a quarter million records, is extremely costly.. is there any other method not involving regex substitution? Thanks in advance Edit: here's the function doing the convertion/comparison function dateInRange(t, from, to) { sub(/[[]/, "", t); split(t, a, "[/:]"); match("JanFebMarAprMayJunJulAugSepOctNovDec", a[2]); a[2] = sprintf("%02d", (RSTART + 2) / 3); s = a[3] a[2] a[1] a[4] a[5]; return s >= from && s <= to; } "from" and "to" are the intervals in the aforementioned format, and "t" is the raw apache log date/time field (e.g [22/Dec/2009:00:19:36)

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  • Regular Expression with Names and Emails

    - by Nina
    I am having a problem with regular expressions at the moment. What I'm trying to do is that for each line through the iteration, it checks for this type of pattern: Lastname, Firstname If it finds the name, then it will take the first letter of the first name, and the first six letters of the lastname and form it as an email. I have the following: $checklast = "[A-z],"; $checkfirst = "[A-z]"; if (ereg($checklast, $parts[1])||ereg($checkfirst, $parts[2])){ $first = preg_replace($checkfirst, $checkfirst{1,1}, $parts[2]); print "<a href='mailto:[email protected];'> $parts[$i] </a>"; } This one obviously broke the code. But I was initially attempting to find only the first letter of the firstname and then after that the first six letters of the lastname followed by the @email.com This didn't work out too well. I'm not sure what to do at this point. Any help is much appreciated.

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  • Regular Expression doesn't match

    - by dododedodonl
    Hi All, I've got a regular expression in my cocoa-touch app (using RegexKitLite). NSString *week = [[NSString alloc] initWithFormat:@"%@", [pageContent stringByReplacingOccurrencesOfRegex:@"<select name=\"week\" class=\"selectbox\" style='width:134' onChange=\"doDisplayTimetable(NavBar, topDir);\">(.+?)<option value=\"(.+?)\">(.+?)</option>" withString:@"$2"]]; I expect it to match with the section of this (what is in NSString pageContent): <span class="selection"> <nobr> Periode<br> <span class="absatz"> &nbsp;<br> </span> <select name="week" class="selectbox" style='width:134' onChange="doDisplayTimetable(NavBar, topDir);"> <option value="14">17-5 - 16-7</option> </select> </nobr> </span> But it doesn't... I need the value of the option, it is possible that there is more than one (in that case I need them both separated by a ,. Can someone help me out? Regards, Dodo

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  • Javascipt Regular Expression

    - by Ghoul Fool
    Having problems with regular expressions in JavaScript. I've got a number of strings that need delimiting by commas. Unfortunately the sub strings don't have quotes around them which would make life easier. var str1 = "Three Blind Mice 13 Agents of Cheese Super 18" var str2 = "An Old Woman Who Lived in a Shoe 7 Pixies None 12" var str3 = "The Cow Jumped Over The Moon 21 Crazy Cow Tales Wonderful 9" They are in the form of PHRASE1 (Mixed type with spaces") INTEGER1 (1 or two digit) PHRASE2 (Mixed type with spaces") WORD1 (single word mixed type, no spaces) INTEGER2 (1 or two digit) so I should get: result1 = "Three Blind Mice, 13, Agents of Cheese, Super, 18" result2 = "An Old Woman Who Lived in a Shoe, 7, Pixies, None, 12" result3 = "A Cow Jumped Over The Moon, 21, Crazy Cow Tales, Wonderful, 9" I've looked at txt2re.com, but can't quite get what I need and ended up delimiting by hand. But I'm sure it can be done, albeit someone with a bigger brain. There are lots of examples of regEx but I couldn't find any to deal with phrases; so I was wondering if anyone could help me out. Thank you.

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  • Regular Expressions .NET

    - by Fosa
    I need a regular expression for some arguments that must match on a string. here it is... The string exists out of minimum 8 en maximum 20 characters. These characters of this string may be characters of the alfabet or special chars --With other words..all charachters except from the whitespaces In the complete string there must be atleast 1 number. The string cannot start with a number or an underscore The last 2 characters of the string must be identical, But it doenst matter if those last --identical characters are capital or non-capital (case insensitive) Must match all : +234567899 a_1de*Gg xy1Me*__ !41deF_hij2lMnopq3ss C234567890123$^67800 *5555555 sDF564zer"" !!!!!!!!!4!!!!!!!!!! abcdefghijklmnopq9ss May not match : Cannot be less then 8 or more then 20 chars: a_1+Eff B41def_hIJ2lmnopq3stt Cannot contain a whitespace: A_4 e*gg b41def_Hij2l nopq3ss Cannot start with a number or an underscore: __1+Eff 841DEf_hij2lmnopq3stt cannot end on 2 diffrent characters: a_1+eFg b41DEf_hij2lmnopq3st Cannot be without a number in the string: abCDefghijklmnopqrss abcdef+++dF !!!!!!!!!!!!!!!!!!!! ------------------------------------------------------ This is what I have so far...But I'm really breaking my head on this... If you Don't know the answer completely it's not a problem... I just want to get in the right direction ([^0-9_])(?=.*\d)(\S{8,20})(?i:[\S])\1

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  • Getting dialogue snippets from text using regular expressions

    - by sheldon
    I'm trying to extract snippets of dialogue from a book text. For example, if I have the string "What's the matter with the flag?" inquired Captain MacWhirr. "Seems all right to me." Then I want to extract "What's the matter with the flag?" and "Seem's all right to me.". I found a regular expression to use here, which is "[^"\\]*(\\.[^"\\]*)*". This works great in Eclipse when I'm doing a Ctrl+F find regex on my book .txt file, but when I run the following code: String regex = "\"[^\"\\\\]*(\\\\.[^\"\\\\]*)*\""; String bookText = "\"What's the matter with the flag?\" inquired Captain MacWhirr. \"Seems all right to me.\""; Pattern p = Pattern.compile(regex); Matcher m = p.matcher(bookText); if(m.find()) System.out.println(m.group(1)); The only thing that prints is null. So am I not converting the regex into a Java string properly? Do I need to take into account the fact that Java Strings have a \" for the double quotes?

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