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  • Numpy: Sorting a multidimensional array by a multidimensional array

    - by JD Long
    Forgive me if this is redundant or super basic. I'm coming to Python/Numpy from R and having a hard time flipping things around in my head. I have a n dimensional array which I want to sort using another n dimensional array of index values. I know I could wrap this in a loop but it seems like there should be a really concise Numpyonic way of beating this into submission. Here's my example code to set up the problem where n=2: a1 = random.standard_normal(size=[2,5]) index = array([[0,1,2,4,3] , [0,1,2,3,4] ]) so now I have a 2 x 5 array of random numbers and a 2 x 5 index. I've read the help for take() about 10 times now but my brain is not groking it, obviously. I thought this might get me there: take(a1, index) array([[ 0.29589188, -0.71279375, -0.18154864, -1.12184984, 0.25698875], [ 0.29589188, -0.71279375, -0.18154864, 0.25698875, -1.12184984]]) but that's clearly reordering only the first element (I presume because of flattening). Any tips on how I get from where I am to a solution that sorts element 0 of a1 by element 0 of the index ... element n?

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  • NSMutableDictionary of NSMutableSets... sorting this out

    - by Mike
    I have a NSMutableDictionary of NSMutableSets. Each set entry is a string, something like this: NSMutableSet *mySet = [NSMutableSet setWithObjects: [NSString stringWithFormat:@"%d", time1], [NSString stringWithFormat:@"%d", time2], [NSString stringWithFormat:@"%d", time3], nil]; // time 1,2,3, are NSTimeInterval variables then I store each set on the dictionary using this: NSString *rightNowString = [NSString stringWithFormat:@"%d", rightNow]; [myDict setValue:mySet forKey:rightNow]; // rightNow is NSTimeInterval as rightNow key can occur out of order, I end with a NSDictionary that is not ordered by rightNow. How can I sort this NSDictionary by its keys considering that they are numbers stored as strings on the dictionary...? I don't care for ordering the sets, just the dictionary. thanks for any help.

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  • sorting two tables (full join)

    - by Ruslan
    i'm joining tables like: select * from tableA a full join tableB b on a.id = b.id But the output should be: row without null fields row with null fields in tableB row with null fields in tableA Like: a.id a.name b.id b.name 5 Peter 5 Jones 2 Steven 2 Pareker 6 Paul null null 4 Ivan null null null null 1 Smith null null 3 Parker

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  • sorting a php array

    - by cute
    how do i sort this array by the nums... Array( [nums] => Array ( [0] => 34 [1] => 12 [2] => 13 ) [players] => Array ( [0] => Mike [1] => Bob [2] => Mary ) ) ... so that i get this one? Array( [nums] => Array ( [0] => 12 [1] => 13 [2] => 34 ) [players] => Array ( [0] => Bob [1] => Mary [2] => Mike ) )

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  • Sorting in Hash Maps in Java

    - by Crystal
    I'm trying to get familiar with Collections. I have a String which is my key, email address, and a Person object (firstName, lastName, telephone, email). I read in the Java collections chapter on Sun's webpages that if you had a HashMap and wanted it sorted, you could use a TreeMap. How does this sort work? Is it based on the compareTo() method you have in your Person class? I overrode the compareTo() method in my Person class to sort by lastName. But it isn't working properly and was wondering if I have the right idea or not. getSortedListByLastName at the bottom of this code is where I try to convert to a TreeMap. Also, if this is the correct way to do it, or one of the correct ways to do it, how do I then sort by firstName since my compareTo() is comparing by lastName. import java.util.*; public class OrganizeThis { /** Add a person to the organizer @param p A person object */ public void add(Person p) { staff.put(p.getEmail(), p); //System.out.println("Person " + p + "added"); } /** * Remove a Person from the organizer. * * @param email The email of the person to be removed. */ public void remove(String email) { staff.remove(email); } /** * Remove all contacts from the organizer. * */ public void empty() { staff.clear(); } /** * Find the person stored in the organizer with the email address. * Note, each person will have a unique email address. * * @param email The person email address you are looking for. * */ public Person findByEmail(String email) { Person aPerson = staff.get(email); return aPerson; } /** * Find all persons stored in the organizer with the same last name. * Note, there can be multiple persons with the same last name. * * @param lastName The last name of the persons your are looking for. * */ public Person[] find(String lastName) { ArrayList<Person> names = new ArrayList<Person>(); for (Person s : staff.values()) { if (s.getLastName() == lastName) { names.add(s); } } // Convert ArrayList back to Array Person nameArray[] = new Person[names.size()]; names.toArray(nameArray); return nameArray; } /** * Return all the contact from the orgnizer in * an array sorted by last name. * * @return An array of Person objects. * */ public Person[] getSortedListByLastName() { Map<String, Person> sorted = new TreeMap<String, Person>(staff); ArrayList<Person> sortedArrayList = new ArrayList<Person>(); for (Person s: sorted.values()) { sortedArrayList.add(s); } Person sortedArray[] = new Person[sortedArrayList.size()]; sortedArrayList.toArray(sortedArray); return sortedArray; } private Map<String, Person> staff = new HashMap<String, Person>(); public static void main(String[] args) { OrganizeThis testObj = new OrganizeThis(); Person person1 = new Person("J", "W", "111-222-3333", "[email protected]"); Person person2 = new Person("K", "W", "345-678-9999", "[email protected]"); Person person3 = new Person("Phoebe", "Wang", "322-111-3333", "[email protected]"); Person person4 = new Person("Nermal", "Johnson", "322-342-5555", "[email protected]"); Person person5 = new Person("Apple", "Banana", "123-456-1111", "[email protected]"); testObj.add(person1); testObj.add(person2); testObj.add(person3); testObj.add(person4); testObj.add(person5); System.out.println(testObj.findByEmail("[email protected]")); System.out.println("------------" + '\n'); Person a[] = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("------------" + '\n'); a = testObj.find("W"); for (Person p : a) System.out.println(p); System.out.println("SORTED" + '\n'); a = testObj.getSortedListByLastName(); for (Person b : a) { System.out.println(b); } } } Person class: public class Person implements Comparable { String firstName; String lastName; String telephone; String email; public Person() { firstName = ""; lastName = ""; telephone = ""; email = ""; } public Person(String firstName) { this.firstName = firstName; } public Person(String firstName, String lastName, String telephone, String email) { this.firstName = firstName; this.lastName = lastName; this.telephone = telephone; this.email = email; } public String getFirstName() { return firstName; } public void setFirstName(String firstName) { this.firstName = firstName; } public String getLastName() { return lastName; } public void setLastName(String lastName) { this.lastName = lastName; } public String getTelephone() { return telephone; } public void setTelephone(String telephone) { this.telephone = telephone; } public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } public int compareTo(Object o) { String s1 = this.lastName + this.firstName; String s2 = ((Person) o).lastName + ((Person) o).firstName; return s1.compareTo(s2); } public boolean equals(Object otherObject) { // a quick test to see if the objects are identical if (this == otherObject) { return true; } // must return false if the explicit parameter is null if (otherObject == null) { return false; } if (!(otherObject instanceof Person)) { return false; } Person other = (Person) otherObject; return firstName.equals(other.firstName) && lastName.equals(other.lastName) && telephone.equals(other.telephone) && email.equals(other.email); } public int hashCode() { return this.email.toLowerCase().hashCode(); } public String toString() { return getClass().getName() + "[firstName = " + firstName + '\n' + "lastName = " + lastName + '\n' + "telephone = " + telephone + '\n' + "email = " + email + "]"; } }

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  • Sorting tree with other column in SQL Server 2008

    - by bodziec
    Hi, I have a table which implements a tree using hierarchyid column Sample data: People \ Girls \1\ Zoey \1\1\ Kate \1\2\ Monica \1\3\ Boys \2\ Mark \2\1\ David \2\2\ This is the order using hierarchyid column as sort column I would like to sort data using hierarchyid but also using name so it would look like this: People \ Boys \2\ David \2\2\ Mark \2\1\ Girls \1\ Kate \1\2\ Monica \1\3\ Zoey \1\1\ Is there a simple solution to do this? Czy da sie to zrobic w jednym zapytaniu sql ?

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  • Advanced Array Sorting in Ruby

    - by Ruby Beginner
    I'm currently working on a project in ruby, and I hit a wall on how I should proceed. In the project I'm using Dir.glob to search a directory and all of its subdirectories for certain file types and placing them into an arrays. The type of files I'm working with all have the same file name and are differentiated by their extensions. For example, txt_files = Dir.glob("**/*.txt") doc_files = Dir.glob("**/*.doc") rtf_files = Dir.glob("**/*.rtf") Would return something similar to, FILECON.txt ASSORTED.txt FIRST.txt FILECON.doc ASSORTED.doc FIRST.doc FILECON.rtf ASSORTED.rtf FIRST.rtf So, the question I have is how I could break down these arrays efficiently (dealing with thousands of files) and placing all files with the same filename into an array. The new array would look like, FILECON.txt FILECON.doc FILECON.rtf ASSORTED.txt ASSORTED.doc ASSORTED.rtf etc. etc. I'm not even sure if glob would be the correct way to do this (all the files with the same file name are in the same folders). Any help would be greatly appreciated!

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  • Sorting list of URLs by length in Jython

    - by Eef
    Hi, I am writing a Jython script to sort a list of URLs. I have a list that looks like this: http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/|,1 http://www.domain.com/folder1/folder2/folder3/|,1 http://www.domain.com/folder1/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/folder3/|,1 The pipe and the comma separates the path from the amount of files that are under that path. Is it possible some how use Jython to order the URLs by length, so it would end up look like the below list: http://www.domain.com/folder1/|,1 http://www.domain.com/folder1/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/folder3/|,1 http://www.domain.com/folder1/folder2/folder3/|,1 Hope you guys get what I mean, any help would be appreciated. Cheers

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  • Sorting tree with a materialized path?

    - by Ovid
    I have a tree structure in a table and it uses materialized paths to allow me to find children quickly. However, I also need to sort the results depth-first, as one would expect with threaded forum replies. id | parent_id | matpath | created ----+-----------+---------+---------------------------- 2 | 1 | 1 | 2010-05-08 15:18:37.987544 3 | 1 | 1 | 2010-05-08 17:38:14.125377 4 | 1 | 1 | 2010-05-08 17:38:57.26743 5 | 1 | 1 | 2010-05-08 17:43:28.211708 7 | 1 | 1 | 2010-05-08 18:18:11.849735 6 | 2 | 1.2 | 2010-05-08 17:50:43.288759 9 | 5 | 1.5 | 2010-05-09 14:02:43.818646 8 | 6 | 1.2.6 | 2010-05-09 14:01:17.632695 So the final results should actually be sorted like this: id | parent_id | matpath | created ----+-----------+---------+---------------------------- 2 | 1 | 1 | 2010-05-08 15:18:37.987544 6 | 2 | 1.2 | 2010-05-08 17:50:43.288759 8 | 6 | 1.2.6 | 2010-05-09 14:01:17.632695 3 | 1 | 1 | 2010-05-08 17:38:14.125377 4 | 1 | 1 | 2010-05-08 17:38:57.26743 5 | 1 | 1 | 2010-05-08 17:43:28.211708 9 | 5 | 1.5 | 2010-05-09 14:02:43.818646 7 | 1 | 1 | 2010-05-08 18:18:11.849735 How would I work that out? Can I do that in straight SQL (this is PostgreSQL 8.4) or should additional information be added to this table?

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  • Custom Sorting on Custom Field in Django

    - by RotaJota
    In my app, I have defined a custom field to represent a physical quantity using the quantities package. class AmountField(models.CharField): def __init__(self, *args, **kwargs): ... def to_python(self, value): create_quantities_value(value) Essentially the way it works is it extends CharField to store the value as a string in the database "12 min" and represents it as a quantities object when using the field in a model array(12) * min Then in a model it is used as such: class MyModel(models.Model): group = models.CharField() amount = AmountField() class Meta: ordering = ['group', 'amount'] My issue is that these fields do not seem to sort by the quantity, but instead by the string. So if I have some objects that contain something like {"group":"A", "amount":"12 min"} {"group":"A", "amount":"20 min"} {"group":"A", "amount":"2 min"} {"group":"B", "amount":"20 min"} {"group":"B", "amount":"1 hr"} they end up sorted something like this: >>> MyModel.objects.all() [{A, 12 min}, {A, 2 min}, {A, 20 min}, {B, 1 hr}, {B, 20 min}] essentially alphabetical order. Can I give my custom AmountField a comparison function so that it will compare by the python value instead of the DB value?

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  • Cocoa - array not sorting?

    - by Mike
    I have this set NSMutableSet *mySet = [NSMutableSet setWithObjects: @"2", @"8", @"7", @"0", @"3", nil]; I copy the set to an array and sort it using NSArray *sortedArray = [[mySet allObjects] sortedArrayUsingSelector:@selector(compare:)]; The resulting array is in exactly the same order as the set and is not being sorted. Why? thanks for any help. EDIT: CORRECING A TYPO.

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  • Groovy sorting string asc

    - by srinath
    How to sort string names in array on ascending order . I tried sort method but it fails to sort on name basis . def words = ["orange", "blue", "apple", "violet", "green"] I need to achieve like this : ["apple", "blue", "green", "orange", "violet" ] thanks in advance.

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  • Most efficient sorting of calculation on DataTable column calculation

    - by byte
    Lets say you have a DataTable that has columns of "id", "cost", "qty": DataTable dt = new DataTable(); dt.Columns.Add("id", typeof(int)); dt.Columns.Add("cost", typeof(double)); dt.Columns.Add("qty", typeof(int)); And it's keyed on "id": dt.PrimaryKey = new DataColumn[1] { dt.Columns["id"] }; Now what we are interested in is the cost per quantity. So, in other words if you had a row of: id | cost | qty ---------------- 42 | 10.00 | 2 The cost per quantity is 5.00. My question then is, given the preceeding table, assume it's constructed with many thousands of rows, and you're interested in the top 3 cost per quantity rows. The information needed is the id, cost per quantity. You cannot use LINQ. In SQL it would be trivial; how BEST (most efficiently) would you accomplish it in C# without LINQ?

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  • NSFetchedResultsController secondary sorting not working?

    - by binkly
    Hello, I'm using NSFetchedResultsController to fetch Message entities with Core Data. I want my tableview to group the messages by an attribute called ownerName. This works fine in the sense that I get a proper UI dispalying appropriately named sections. I can achieve this with the code below: NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"ownerName" ascending:NO]; NSArray *sortDescriptors = [[NSArray alloc] initWithObjects:sortDescriptor, nil]; [fetchRequest setSortDescriptors:sortDescriptors]; NSFetchedResultsController *fetchedResultsController = nil; fetchedResultsController = [[NSFetchedResultsController alloc] initWithFetchRequest:fetchRequest managedObjectContext:[appDelegate managedObjectContext] sectionNameKeyPath:@"ownerName" cacheName:@"Messages"] What'd I'd like to do now is have the section with the newest message at the top; exactly how it works with the Messages app on iPhone currently. I've tried adding a second sort descriptor and putting it in an array of sort descriptors and passing that to the fetchRequest but it doesn't appear to be affecting anything. Here is the 2nd sort descriptor that I used. NSSortDescriptor *idDescriptor = [[NSSortDescriptor alloc] initWithKey:@"createdAt" ascending:YES]; If anyone could provide some insight into this I would greatly appreciate it.

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  • Sorting an XML in Java

    - by Java Guy
    Hello I have an XML similiar to below, which needed to be sorted using the date field. <root> <Node1><date></date></Node1> <Node1><date></date></Node1> <Node1> <date></date></Node1> <Node1> <date></date></Node1> <Node2> <date></date></Node2> <Node2> <date></date></Node2> <Node2> <date></date></Node2> <Node2> <date></date> </Node2> </root> I would like to sort the XML based on the date(say asc order), irrespective of whether the date is under Node1 or Node2. Actually in Java code I have two seperate lists, one with Node1 objects and other with Node2 obects. I can sort the list in any order sperately inside java. But I need to have the dates sorted irrespective of the nodes it is apperaing on the XML. What is the best approach to sort this way in Java? Actaully I am using Castor for marshalling the java objects to XML. If you know this can be done with Castor, that will be great!

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  • Java : Sorting unsorted array in descending order

    - by Bader
    hi guys i had an array of objects , i need to know how should i sort my unsorted array in descending order according to the highest value inside objects i need this using for loops not the easy way. i had done this but it seems there is a problem code student[] temp=new student[s.length]; for (int i=0;i s[i + 1].GetGpa()) { temp[i] = s[i]; } } how should i do it using for loops

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  • awk + sorting file according to values in the file and write two diffrent files

    - by yael
    hi I have in file file_test values of right eye and left eye How to separate the file_test to file1 and file2 by awk in order to write the equal values on file1 and different values on file2 as the following example down THX file_test: NAME: jim LAST NAME: bakker right eye: |5|< left eye VALUE: |5|< NAME: Jorg LAST NAME: mitchel right eye: |3|< left eye VALUE: |5|< NAME: jimmy LAST NAME: kartter right eye: |6|< left eye VALUE: |5|< NAME: david LAST NAME: kann right eye: |9|< left eye VALUE: |9|< file1: NAME: jim LAST NAME: bakker right eye: |5|< left eye VALUE: |5|< NAME: david LAST NAME: kann right eye: |9|< left eye VALUE: |9|< file2: NAME: Jorg LAST NAME: mitchel right eye: |3|< left eye VALUE: |5|< NAME: jimmy LAST NAME: kartter right eye: |6|< left eye VALUE: |5|<

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  • MySQL - How do I inner join sorting the joined data

    - by Gary
    I'm trying to write a report which will join a person, their work, and their hourly wage at the time of work. I cannot seem to figure out the best way to join the person's cost when the date is less than the date of the work. Let's say a person cost $30 per hour at the start of the year then got a $10 raise o Feb 5 and another on Mar 1. 01/01/2010 $30.00 (per hour) 02/05/2010 $40.00 03/01/2010 $45.00 The person put in hours several days which span the rasies. 01/05/2010 10 hours (should be at $30/hr) 01/27/2010 5 hours (again at $30) 02/10/2010 10 hours (at $40/hr) 03/03/2010 5 hours (at $45/hr) I'm trying to write one SQL statement which will pull the hours, the cost per hour, and the hours*cost. The cost is the hourly rate last entered into the system so the cost date is less than the work date, ordered by cost date limit 1. SELECT person.id, person.name, work.hours, person_costs.value, work.hours * person_costs.value AS value FROM person INNER JOIN work ON (person.id = work.person_id) INNER JOIN person_costs ON (person.id = person_costs.person_id AND person_costs.date < work.date) WHERE person.id = 1234 ORDER BY work.date ASC The problem I'm having, the person_costs isn't ordered by date in descending order. It's pulling out "any" value (naturally sorted by record position) which matches the condition. How do I select the first person_cost value which is older than the work date? Thanks!

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  • Thinking Sphinx - sorting by a string attribute gets out of sync when changes are made

    - by Scott Brown
    I have a "restaurants" table with a "name" column. I've defined the following index: indexes "REPLACE(UPPER(restaurants.name), 'THE ', '')", :as => :restaurant_name, :sortable => true ... because I want to sort the restaurant names without respect to the prefix "The ". My problem is that whenever one of these records is updated (in any way) the new record jumps to the top of the sort order. If another record is updated, it also jumps ahead of the rest. I end up with two lists: a list of restaurants that have been updated since the last re-indexing and a list of those that haven't. Each respective list is in alphabetical order, but I don't understand why the overall list is getting segregated this way. I do have a delayed delta index set up, and I assume the issue is related to this.

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  • Sorting Listbox in Silverlight (Sketchflow)

    - by gnitez
    I have a Listbox with multiple columns and bound to a data source (XML) as shown below. <ListBox x:Name="lstBox1" Background="#FFC5EFFD" Margin="7,50,10,15" ItemTemplate="{StaticResource ItemsPanelTemplate1}" ItemsSource="{Binding BPICollection}" BorderThickness="0"/> I'm trying to figure out how to sort a particular column in the listbox.

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  • Sorting manually generated index using perl script

    - by Pradeep Singh
    \item Bernoulli measure, 14 \item cellular automata \subitem Soft, 3, 28 \subitem balance theorem, 23, 45 \item tiles \subitem tiling problem, 19, 58 \subitem aperiodic tile set, 18, 45 \item Garden-of-Eden -theorem, 12 \item Bernoulli measure, 15, 16, 35 \item cellular automata \subitem balance theorem, 9, 11, 14 \subitem blocking word, 22, 32 \item Garden-of-Eden -theorem, 32 I have to sort the above index alphabetically using a perl script. Duplicate item or subitem entries should be merged and their numbers should be sorted. The subitems also should be sorted under respective item and their numbers should be also sorted. If same item is repeated in more than one place with subitems all the subitems should be merged under a single item and also subitems should be sorted

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  • Sorting List which has object that contains two string members that contains numbers

    - by Lemo
    I want to know the best solution for this my case here is that i am taking values from Excel sheet and pushing them to database field, sometimes that field might contain some strings (thats why I cant make my object members int / double) In my class below size is the variable responsible for showing size of files in bytes public class dataNameValue { public string Name { get; set; } public string Count { get; set; } public string Size { get; set; } } I wanted to sort the list by file Size something like List mylist = new List(); mylist = mylist.OrderByDescending(i = i.Size).ToList(); The problem is that if i sorted it without converting it to "int/double" first -- its not giving right results

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  • Scheme sorting a list

    - by John
    Okay so I am trying to take in a list and sort it from greatest to smallest. Example: > (maxheap (list 5 6 2 1 18 7)) ;output: > (18 7 6 5 2 1) So here's what I got so far: (define (mkmaxheap heaplist) (let ((max (mymax(heaplist)))) ;mymax is a func that returns max number, it works (let (( head (car heaplist)) (tail (cdr heaplist))) (if (null? tail) newlist)))) Thats all I could get to compile, all the other code I wrote failed. Any help on solving this would be much appreciated.

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