Search Results

Search found 18556 results on 743 pages for 'facebook connect'.

Page 215/743 | < Previous Page | 211 212 213 214 215 216 217 218 219 220 221 222  | Next Page >

  • Connecting PC via Bluetooth SNP

    - by Nicholas
    Hi, I have a widcomm example BluChat "WIDCOMM SDK RFComm Service" running on my PC with an USB dongle (BT-2400P). I would like to connect this chat from my HTC Desire. So I stared with the Java example http://developer.android.com/resources/samples/BluetoothChat/index.html. This is also using BT RFComm. If I'm using my HTC as a server it work's fine, but I would like to use my PC as a server. Then .connect() comes back with "Service Discovery Failure". I have modified the UUID string in the Java example to match the PC-application mmSocket = mmDevice.createRfcommSocketToServiceRecord(UUID.fromString("5fc2a42e-144e-4bb5-b43f-4e61711d1c32")); mmSocket.connect(); What is missing? Any help appreciated. Nicholas

    Read the article

  • Active Directory public key use

    - by Chris Meadows
    I have a client who has a requirement to validate users logging into my web application against his active directory using LDAP. In trying to connect using the DirectoryEntry and DirectorySearcher .NET classes, I can connect to his AD Server but not access it. The client's AD server has an SSL Certificate for which he has given me a public key file but I don't know how to use this public key file in my C# code. When I issue the connect command through code, I see, via Wireshark, my application sending the connection request. I then see the server responding with "Server Hello, Certificate, Certificate Request, Server Hello Done". Then my application never responds after that. In using another application, written by somebody else for which I do not have code, I see the same request from the server and then see the application respond with "Certificate, Client Key Exchange" and then the application connects and runs. With that said, my question then becomes, how can I get my C# application to load and send the key file I got from the client?

    Read the article

  • Setting up a SQL server outside the domain

    - by Ben
    Hi, im very new to this. I've set up an account "SQLBOX" thats on the a network, but not connected to the domain. I have installed an instance of SQL Server 2008 and am trying to connect to it from another machine on the network but am getting "Cannot connect to "SQLBOX"". From the "SQLBOX" i can connect to sqlservers on the domain, but not vice-versa. Any help would be greatly appreciated. Sorry if the description isn't great. EDIT I can ping the box from a machine on the domain

    Read the article

  • Reading data from a socket

    - by Bobby
    I am having issues reading data from a socket. Supposedly, there is a server socket that is waiting for clients to connect. When I write a client to connect() to the server socket/port, it appears that I am connected. But when I try to read() data that the server is supposedly writing on the socket, the read() function hangs until the server app is stopped. Why would a read() call ever hang if the socket is connected? I believe that I am not ever really connected to the socket/port but I can't prove it, b/c the connect() call did not return an error. The read() call is not returning an error either, it is just never returning at all.

    Read the article

  • Access Control Service v2: Registering Web Identities in your Applications [concepts]

    - by Your DisplayName here!
    ACS v2 support two fundamental types of client identities– I like to call them “enterprise identities” (WS-*) and “web identities” (Google, LiveID, OpenId in general…). I also see two different “mind sets” when it comes to application design using the above identity types: Enterprise identities – often the fact that a client can present a token from a trusted identity provider means he is a legitimate user of the application. Trust relationships and authorization details have been negotiated out of band (often on paper). Web identities – the fact that a user can authenticate with Google et al does not necessarily mean he is a legitimate (or registered) user of an application. Typically additional steps are necessary (like filling out a form, email confirmation etc). Sometimes also a mixture of both approaches exist, for the sake of this post, I will focus on the web identity case. I got a number of questions how to implement the web identity scenario and after some conversations it turns out it is the old authentication vs. authorization problem that gets in the way. Many people use the IsAuthenticated property on IIdentity to make security decisions in their applications (or deny user=”?” in ASP.NET terms). That’s a very natural thing to do, because authentication was done inside the application and we knew exactly when the IsAuthenticated condition is true. Been there, done that. Guilty ;) The fundamental difference between these “old style” apps and federation is, that authentication is not done by the application anymore. It is done by a third party service, and in the case of web identity providers, in services that are not under our control (nor do we have a formal business relationship with these providers). Now the issue is, when you switch to ACS, and someone with a Google account authenticates, indeed IsAuthenticated is true – because that’s what he is! This does not mean, that he is also authorized to use the application. It just proves he was able to authenticate with Google. Now this obviously leads to confusion. How can we solve that? Easy answer: We have to deal with authentication and authorization separately. Job done ;) For many application types I see this general approach: Application uses ACS for authentication (maybe both enterprise and web identities, we focus on web identities but you could easily have a dual approach here) Application offers to authenticate (or sign in) via web identity accounts like LiveID, Google, Facebook etc. Application also maintains a database of its “own” users. Typically you want to store additional information about the user In such an application type it is important to have a unique identifier for your users (think the primary key of your user database). What would that be? Most web identity provider (and all the standard ACS v2 supported ones) emit a NameIdentifier claim. This is a stable ID for the client (scoped to the relying party – more on that later). Furthermore ACS emits a claims identifying the identity provider (like the original issuer concept in WIF). When you combine these two values together, you can be sure to have a unique identifier for the user, e.g.: Facebook-134952459903700\799880347 You can now check on incoming calls, if the user is already registered and if yes, swap the ACS claims with claims coming from your user database. One claims would maybe be a role like “Registered User” which can then be easily used to do authorization checks in the application. The WIF claims authentication manager is a perfect place to do the claims transformation. If the user is not registered, show a register form. Maybe you can use some claims from the identity provider to pre-fill form fields. (see here where I show how to use the Facebook API to fetch additional user properties). After successful registration (which may include other mechanisms like a confirmation email), flip the bit in your database to make the web identity a registered user. This is all very theoretical. In the next post I will show some code and provide a download link for the complete sample. More on NameIdentifier Identity providers “guarantee” that the name identifier for a given user in your application will always be the same. But different applications (in the case of ACS – different ACS namespaces) will see different name identifiers. This is by design to protect the privacy of users because identical name identifiers could be used to create “profiles” of some sort for that user. In technical terms they create the name identifier approximately like this: name identifier = Hash((Provider Internal User ID) + (Relying Party Address)) Why is this important to know? Well – when you change the name of your ACS namespace, the name identifiers will change as well and you will will lose your “connection” to your existing users. Oh an btw – never use any other claims (like email address or name) to form a unique ID – these can often be changed by users.

    Read the article

  • How to replace a Widget with another using Qt ?

    - by Natim
    Hi, I have an QHBoxLayout with a QTreeWidget on the left, a separator on the middle and a widget on the right. When I click on the QTreeWidget, I want to change the widget on the right to modify the QTreeWidgetItem I tried to do this with this code : def new_rendez_vous(self): self.ui.horizontalLayout_4.removeWidget(self.ui.editionFormWidget) del self.ui.editionFormWidget self.ui.editionFormWidget = RendezVousManagerDialog(self.parent) self.ui.editionFormWidget.show() self.ui.horizontalLayout_4.addWidget(self.ui.editionFormWidget) self.connect(self.ui.editionFormWidget, QtCore.SIGNAL('saved'), self.scheduleTreeWidget.updateData) def edit(self, category, rendez_vous): self.ui.horizontalLayout_4.removeWidget(self.ui.editionFormWidget) del self.ui.editionFormWidget self.ui.editionFormWidget = RendezVousManagerDialog(self.parent, category, rendez_vous) self.ui.editionFormWidget.show() self.ui.horizontalLayout_4.addWidget(self.ui.editionFormWidget) self.connect(self.ui.editionFormWidget, QtCore.SIGNAL('saved'), self.scheduleTreeWidget.updateData) def edit_category(self, category): self.ui.horizontalLayout_4.removeWidget(self.ui.editionFormWidget) del self.ui.editionFormWidget self.ui.editionFormWidget = CategoryManagerDialog(self.parent, category) self.ui.editionFormWidget.show() self.ui.horizontalLayout_4.addWidget(self.ui.editionFormWidget) self.connect(self.ui.editionFormWidget, QtCore.SIGNAL('saved'), self.scheduleTreeWidget.updateData) But it doesn't work and all the widgets are stacked up on each other : . Do you know how I can remove the old widget and next display the new one ?

    Read the article

  • Weird Rails URL issue when rendering a new action

    - by Tony
    I am rendering a new action but somehow getting the "index" URL. To be more specific, my create action looks like this: class ListingsController < ApplicationController def create @listing = Listing.new(params[:listing]) @listing.user = @current_user if @listing.save redirect_to @listing else flash[:error] = "There were errors" render :action => "new" end end end When there are errors, I get the "new" action but my URL is the index URL - http://domain.com/listings Anyone know why this would happen? My routes file is fairly standard: map.connect 'listings/send_message', :controller => 'listings', :action => 'send_message' map.resources :listings map.root :controller => "listings" map.connect ':controller/:action/:id' map.connect ':controller/:action/:id.:format'

    Read the article

  • How Do I insert Data in a table From the Model MVC?

    - by user54197
    I have data coming into my Model, how do I setup to insert the data in a table? public string Name { get; set; } public string Address { get; set; } public string City { get; set; } public string State { get; set; } public string Zip { get; set; } public Info() { using (SqlConnection connect = new SqlConnection(connections)) { string query = "Insert Into Personnel_Data (Name, StreetAddress, City, State, Zip, HomePhone, WorkPhone)" + "Values('" + Name + "','" + Address + "','" + City + "','" + State + "','" + Zip + "','" + ContactHPhone + "','" + ContactWPhone + "')"; SqlCommand command = new SqlCommand(query, connect); connect.Open(); command.ExecuteNonQuery(); } } The Name, Address, City, and so on is null when the query is being run. How do I set this up?

    Read the article

  • Recognition source of event in PyQT

    - by xTrol
    Hi, I`m starting with PyQt4 and right now I have a problem with events. I have one main class let say MainWindow. MainWindow has a list of buttons of type ButtonX (inherence form QPushButton). I would like to achieve one of 2 solutions (depends which is easier). 1) After click one of the button from the list I would like to run a one method of MainWindow. I would like to be able to read a source of event there (recognize clicked button) 2) Second solution is to run a method defined in ButtonX class. What I tried is: QtCore.QObject.connect(self.getButton(0, 0), QtCore.SIGNAL("clicked()"), self.getButton(0, 0).buttonMethod()) QtCore.QObject.connect(self.getButton(0, 0), QtCore.SIGNAL("clicked()"), self.getButton(0, 0), QtCore.SLOT("incrementValue()")) and even this line occure suspend Python interpreter QtCore.QObject.connect(self.getButton(0, 0), QtCore.SIGNAL("clicked()"), self.getButton(0, 0), QtCore.SLOT("incrementValue"))

    Read the article

  • Device Emulator Mananger and ActiveSync

    - by Vaccano
    I use Device Emulator Manager to fire up my Windows Mobile 5 Emulator. I then right click on the device (in the Device Emulator Manager list) and select cradle. ActiveSync then ties to connect. After a few seconds I get this message: Then if I open up the connection options and press connect: Then it works just fine. So, my question is, how can I get it to connect every time. Right as I cradle. I do this enough times that it is annoying to have the extra step. Has anyone ever been able to figure this out? (Does anyone have this problem too?) FYI My co-workers have the same issue Connecting a real device does not have this issue (It is just when I use an emulator)

    Read the article

  • Excel File opened under Ubuntu, read by R, OpenOffice

    - by Vishal Belsare
    I have a bunch of Excel files which are updated on a daily basis on a Windows machine. I transfer them to a Ubuntu machine and want to open them there. Specifically, I want to read the files as a database under R. A couple years ago, I used ODBC under a Windows machine to open Excel files through R. Is there any way, I can do this with R under Ubuntu? I could make a database .ODB file for the corresponding XLS files using OpenOffice, but I don't know of a way to connect to a .ODB database. OpenOffice seems to have ways to connect TO databases, but no way to connect to ODB. Thanks for any potential solutions.

    Read the article

  • iPhone StoreKit development: Can't create a test user?

    - by Cruinh
    I'm trying to get up to speed on how to develop an in-app store using the new 3.0 SDK... but I'm a bit stuck in that I don't seem to be able to create a test account. The iTunes Connect FAQ states "To create test users for your sandbox environment, go to the Manage Users section of iTunes Connect and select In App Purchase Test User. Your test users will not have iTunes Connect access. They will just have access to the sandbox environment." ...but when I go to that Manage Users section, there's no mention of any sort of "In App Purschase Test User" or how to make one. Did I miss doing something to enable that? There is another section of that same FAQ that seems to suggest I need to have a paid app in the store first? Is that the reason I can't even use the test environment?

    Read the article

  • SQL server 2055 remote connection problem, cannot solve it help please thank you

    - by user287745
    note:- if this question does not fit this site please do not just close it but also redirect the question to the fitting sister site, thank you" the steps taken and the error are mentioned please help, i am stuck here! installed sql server 2005 express on both computers installed sql server management studio express on both computers ran each management studio and connect to instance sqlserver using windows authentication ( one computer connection example "A-63A9D4D7E7834\SQLEXPRESS" ) created a database in the databases named as "test1" created a few tables with data saved and exit. did everything what this site says " How to configure SQL Server 2005 to allow remote connections" [add h t t p here as spam prevention] ://support.microsoft.com/kb/914277/en-us" but i have just disable the firewalls completely :turn off connecting to A-63A9D4D7E7834 started "SQL Server Management Studio Express" on computer A-63A9D4D7E7834 sever name: "ALL-E425BE6C41D\SQLEXPRESS" authentication: "windows authentication" and CONNECT I GET THE FOLLOWING ERROR Cannot connect to ALL-E425BE6C41D\SQLEXPRESS. ADDITIONAL INFORMATION: Login failed for user 'ALL-E425BE6C41D\Guest'. (Microsoft SQL Server, Error: 18456) For help, click: http://go.microsoft.com/fwlink?ProdName=Microsoft+SQL+Server&EvtSrc=MSSQLServer&EvtID=18456&LinkId=20476 BUTTONS: OK HELP

    Read the article

  • Obtaining the server IP address in WCF?

    - by chris
    How can I obtain the server IP address that was used to connect to a service? The server has multiple IP addresses and I need to know which one the client is connected to. So far I only found that OperationContext.Current.EndpointDispatcher.EndpointAddress and OperationContext.Current.Channel.LocalAddress contain the address from .config (e.g. localhost) OperationContext.Current.IncomingMessageProperties.Via contains the Url that the client used to connect to the server (but this might just be a name from the clients hosts file). EDIT - Sorry, I wasn't being clear enough: The server needs to know which of its IP addresses were used by the client. E.g. the server has the addresses 10.0.0.1 and 10.0.0.2. when processing the request the server service needs to know if 10.0.0.1 or 10.0.0.2 was used by the client to connect to it.

    Read the article

  • resetting the image in an NSView

    - by Josan
    I think this is a very simple question, but I’m new to programming so I may be going about it in a wrong-headed way. I have a basic understanding of Objective-C writing terminal applications and am teaching myself how to use the Cocoa GUI. I understand how to use IBOutlet and IBAction to connect a simple button to a method that will repeatedly send random numbers to a textfield . I understand how to add a NSView file, connect it to a custom view in interface builder and draw a path through random points in the view when the application launches. (I’ve been putting this code inside the - (void)drawRect:(NSRect)dirtyRect method that is declared when the file is created). What I can’t seem to figure out is how to connect a button to an action that will then ‘refresh’ the view – in this case repopulate it with another set of random points connected with a path. Looking at the documentation, I think I should somehow be using – (void) setNeedsDisplay(BOOL)flag but nothing I have tried so far had worked. Please tell me, what am I missing here?

    Read the article

  • How to make a remote connection to a MySQL Database Server?

    - by MLB
    Hello: I am trying to connect to a MySQL database server (remote), but I can't. I am using an user with grant privileges (not root user). The error message is the following: Can't obtain database list from the server. Access denied for user 'myuser'@'mypcname' (using password: YES) "myuser" is an user I created with grant access. This user allows me to connect locally to every database. I am using the same software versions in both hosts: MySQL Server 4.1 (server) and EMS SQL Manager 2005 for MySQL, edition 3.7.0.1 (client). The point is that I need to connect to the remote server using a different user, not root user. So, how to make the connection? Thanks.

    Read the article

  • PHP fsockopen doesnt return anything

    - by Industrial
    Hi! I am modifying a PHP db wrapper for the redis database. Here's how my function looks: public function connect() { $sock = @fsockopen('localhost', '6379', $errno, $errstr, 2); if ($sock === FALSE) { return FALSE; } else { stream_set_timeout($sock, 2); return $sock; } } What I want to do is to call this function from another part in my wrapper: if ($this->connect() !== FALSE) { // Do stuff } How can I get my connect function to send a FALSE when the fsockopen isn't working? Thanks!

    Read the article

  • mysql_close(): supplied argument is not a valid MySQL-Link resource

    - by Illes Peter
    Here's what I'm trying to do: I've got a db.php file that does all the db manipulation. It has 2 static methods, connect and deconnect. In my other file i simply use db::connect() and db::deconnect(). The mysql_close($con) in the deconnect method just doesn't know who $con is. Since I don't want to instantiate my class static is the only way to go. Declaring 'private $con' in class db doesn't seem to have an effect. Any ideas? class db { public static function connect() { $dbData = parse_ini_file($_SERVER['DOCUMENT_ROOT'].'/config.ini'); $con = mysql_connect($dbData['host'],$dbData['user'],$dbData['pass']); $db = mysql_select_db($dbData['db']); if ((!$con) || (!$db)) return 0; else return 1; } public static function deconnect() { mysql_close($con); } }

    Read the article

  • library interposition with dlsym

    - by ZeeGeek
    I'm writing an interposition library to track the usage of some library functions in libc, such as open(), close(), connect(), etc. It works generally well on most of the applications. However, when I try it with PHP, using PHP's MySQL module in particular, none of the function calls to libc inside this module is been tracked (so no connect(), no socket(), etc.). 'strace' told me that the system calls socket(), connect(), etc., took place. Running 'file' on the module and libmysqlclient.so.16.0.0 said that they are all dynamically linked. So it shouldn't be a problem caused by static linkage. What might be the problem? I'm using Fedora 11 64-bit version. Thank you.

    Read the article

  • How to generate a video signal from Android device via USB?

    - by C.Rivlaldo
    Is it possible to create an application for Android, which can generate a video signal (HDMI or VGA) via USB? Any Android device has miniUSB port. Theoretically it's possible to create a small commutator device on microcontroller or microscheme, which will be a USB-host for Android device. You'll connect Android device with commutator and then connect commutator with monitor. For example, the scheme looks like: Android phone - commutator (USB-host) - TV/Monitor. Summary, I need to connect android phone with TV via miniUSB port. I found soft which can use miniUSB - HDMI cable, but those apps only for Motorolla Droid and HTC Evo. I'll glad to get links to existing apps or projects on that theme, to info about software generation HDMI-signal and connecting Android devices with another devices. Thank you and sorry for my bad english!

    Read the article

  • ActionController::RoutingError

    - by Steve
    Hi All, I am just learning Rails. I had encountered a routing error, though I think I have specified the correct rules in the routing.rb. I have attached the code. Please help routing.rb map.connect ':controller/:action' map.connect ':controller/:action/:id' map.connect ':controller/:action/:id.:format' Controller class EntriesController < ApplicationController def sign_in @name = params[:visitor_name] end end View <html> <head><title>Hello <%=h @name %></title></head> <body> <%=h @name %> <% form_tag :action => 'sign_in' do %> <p>Enter your name: <%= text_field_tag 'visitor_name', @name %></p> <%= submit_tag 'Sign in' %> <% end %> </body> </html> Thanks

    Read the article

  • Authentication Failed exception - In the middle of bulk mail sending code.

    - by Ezhil
    We have a thread program that sends bulk mail. The information like 1. To 2. Subject Etc., are fetched from database, mail is composed and pushed to SMTP server. One of our customer sent a bulk mail with 2390 email. After sending 40 emails, suddenly the following exception occurred EXCEPTION javax.mail.AuthenticationFailedException STACKTRACE javax.mail.Service.connect(Service.java:306) javax.mail.Service.connect(Service.java:156) javax.mail.Service.connect(Service.java:105) ............... java.lang.Thread.run(Thread.java:619) and the rest 2350 emails failed. Why does this occur? Thanks for the Suggestions and Help Ezhil

    Read the article

  • Verizon Fivespot firewall exceptions

    - by Patrick
    I have a Verizon Fivespot Wi-Fi router and am having issues connecting to the computer that uses it to get on the internet. I am able to connect to the Fivespot admin pages remotely and I am able to connect to the internet from the computer behind the Fivespot. I've tried asking this on superuser but have gotten nothing, I figure this is pertinent to programmers working on remote computers as well. There are two sections pertinent to this issue, Port Filtering And, Port Forwarding I've tried each individually and both together but cannot access anything through the router except for the admin page. I am trying to connect through SSH on Port 22 to an Ubuntu 10.04 box over wifi. I have called Verizon Tech Support but they were unhelpful, the person essentially read what it says on each screen without any elaboration. Any help is greatly appreciated!

    Read the article

  • global security manager in flex

    - by ron
    hi, I made a swf that interacts with other site on the internet (which has a crossdomainfile for me). in the main.mxml there is a definition of webservice (mx:WebService)(which is not in my domain). Therefore when loading the swf, there is a first call to crossdomainfile.xml. I put this swf on my server so that my clients can get it. When i connect to my server to download the swf, i expect to be asked if i want to allow the swf connect to foreign webservice domain. But i am not being asked. Do i always need to define exception in Global Security Settings panel? I don't want my client do define special things.. Is there a best practice for that? Why when i surfing the net other swf can do this? I read about the FlashPlayerTrust, can i define there a website i trust my swf will connect to? anyone knows?

    Read the article

  • Error #2126: NetConnection object must be connected

    - by Shuo
    Hey guys , I want to count the online user,when each client login the system,it's connecting to the server and increase a variable stored in a remote shared object. But when client connecting server,problems arises:Error #2126: NetConnection object must be connected My web layout: Website --- apps --- userLogin Code snippets: rtmpnc = new NetConnection(); rtmpnc.objectEncoding = ObjectEncoding.AMF0; var uri:String = ServerConfig.getChannel("my-rtmp").endpoint + "/userLogin"; rtmpnc.connect("http://202.206.249.193:2367/userLogin"); rtmpnc.addEventListener(NetStatusEvent.NET_STATUS,onNetStatusHandler); The onNetStatusHander is defined as : switch(event.info.code) { case "NetConnection.Connect.Success":onConnSuccess();break; case "NetConnection.Connect.Failed":onConnError();break; } Could anyoue help me out?Much thanks! Best,Shuo

    Read the article

< Previous Page | 211 212 213 214 215 216 217 218 219 220 221 222  | Next Page >