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• Mechanize Submit Form Error: Insufficient items with name '10427'

  - by maneh

  I'm trying to submit a form with Mechanize, I have tried different ways, but the problem persists. Can anyone help me on this. Thank you in advance! This is the form I want to submit: http://www.stpairways.st/ This is the code that I'm using: def stp_airways(url): import re import mechanize br = mechanize.Browser() br.open(url) print br.title() br.select_form(name = "frmbook") br.form['TypeTrajet'] = ["1"] br.form['id_depart'] = ["11967"] br.form['id_arrivee'] = ["10427"] br.form['txtDateAller'] = "5/7/2014" br.form['txtDateRetour'] = "12/7/2014" br.form['TypePassager1u1000r0b1'] = ["1"] br.form['TypePassager2u1000r0b1'] = ["0"] br.form['TypePassager3u1000r0b1'] = ["0"] br.form['CodeIsoDeviseClient'] = ["17,20,23,24,25,26,27,28,29,30,31,33,34,36,37,64,65,67,68,70,73,80,81,95,96,103,147,151,152,159,160,162,169,170TP1TPF"] br.form['CodeIsoDeviseClient'] = ["EUR"] # submit response1 = br.submit() print response1.read()

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• In Python, is it better to use list comprehensions or for-each loops?

  - by froadie

  Which of the following is better to use and why? Method 1: for k, v in os.environ.items() print "%s=%s" % (k, v) Method 2: print "\n".join(["%s=%s" % (k, v) for k,v in os.environ.items()]) I tend to lead towards the first as more understandable, but that might just be because I'm new to Python and list comprehensions are still somewhat foreign to me. Is the second way considered more Pythonic? I'm assuming there's no performance difference, but I may be wrong. What would be the advantages and disadvantages of these 2 techniques? (Code taken from Dive into Python)

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• Why doesn't list.get(0).equals(null) work?

  - by Jessy

  The first index is set to null (empty), but it doesn't print the right output, why? //set the first index as null and the rest as "High" String a []= {null,"High","High","High","High","High"}; //add array to arraylist ArrayList<Object> choice = new ArrayList<Object>(Arrays.asList(a)); for(int i=0; i<choice.size(); i++){ if(i==0){ if(choice.get(0).equals(null)) System.out.println("I am empty"); //it doesn't print this output } }

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• Python Regular Expression TypeError

  - by spaghettiwestern

  I am writing my first python program and I am running into a problem with regex. I am using regular expression to search for a specific value in a registry key. import _winreg import re key = _winreg.OpenKey(_winreg.HKEY_LOCAL_MACHINE,"Software\\Microsoft\\Windows\\CurrentVersion\\Uninstall\\{26A24AE4-039D-4CA4-87B4-2F83216020FF}") results=[] v = re.compile(r"(?i)Java") try: i = 0 while 1: name, value, type = _winreg.EnumValue(key, i) if v.search(value): results.append((name,value,type)) i += 1 except WindowsError: print for x in results: print "%-50s%-80s%-20s" % x I am getting the following error: exceptions.TypeError: expected string or buffer I can use the "name" variable and my regex works fine. For example if I make the following changes regex doesn't complain: v = re.compile(r"(?i)DisplayName") if v.search(name): Thanks for any help.

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• Svn: how to remove all deleted files from repository ?

  - by Patrick

  I have a script in which I add all new files before to commit my working copy to my repository with this line: svn status | grep ^\? | awk '{print $2}' | xargs svn add I now want to add a line that delete from repository all deleted files in my working copy. In other terms, I cannot specify them one by one, and I need to detect them with svn status and then automatically remove them. However the line doesn't work. svn status | grep ^\! | awk '{print $2}' | xargs svn --force delete As you can see I've replaced "?" with "!" and "add" with "--force delete" Could you tell me why it doesn't work ? ps. I know it is a risky procedure. I've already discussed all about it. thanks thanks

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• Converting time period strings to value/unit pair

  - by randomtoor

  I need to parse the contents of a string that represents a time period. The format of the string is value/unit, e.g.: 1s, 60min, 24h. I would separate the actual value (an int) and unit (a str) to separated variables. At the moment I do it like this: def validate_time(time): binsize = time.strip() unit = re.sub('[0-9]','',binsize) if unit not in ['s','m','min','h','l']: print "Error: unit {0} is not valid".format(unit) sys.exit(2) tmp = re.sub('[^0-9]','',binsize) try: value = int(tmp) except ValueError: print "Error: {0} is not valid".format(time) sys.exit(2) return value,unit However, it is not ideal as things like 1m0 are also (wrongly) validated (value=10,unit=m). What is the best way to validate/parse this input?

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• Why use threading data race will occur, but will not use gevent

  - by onlytiancai

  My test code is as follows, using threading, count is not 5,000,000 , so there has been data race, but using gevent, count is 5,000,000, there was no data race . Is not gevent coroutine execution will atom "count + = 1", rather than split into a one CPU instruction to execute? # -*- coding: utf-8 -*- import threading use_gevent = True use_debug = False cycles_count = 100*10000 if use_gevent: from gevent import monkey monkey.patch_thread() count = 0 class Counter(threading.Thread): def __init__(self, name): self.thread_name = name super(Counter, self).__init__(name=name) def run(self): global count for i in xrange(cycles_count): if use_debug: print '%s:%s' % (self.thread_name, count) count = count + 1 counters = [Counter('thread:%s' % i) for i in range(5)] for counter in counters: counter.start() for counter in counters: counter.join() print 'count=%s' % count

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• My cookies won't stay (PHP).

  - by RemiX

  I'm building an autologin system using cookies, but one fundamental part of the functionality of the cookies fails: they are non-persistent over different sessions - or even pages! In my login script, I set the cookies like this: setcookie('userID', $userID, time()+86400); // (edited after replies) $userID has a value. Then I print the $_COOKIE variable and it says array(['base_usid'] = 1); So that's good, but when I click the home page and print the $_COOKIE variable there, it says NULL. Does anyone see the problem?

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• Mistake in dispaly and insert method (double - ended queue)

  - by MANAL

  1) My problem when i make remove from right or left program will be remove true but when i call diplay method the content wrong like this I insert 12 43 65 23 and when make remove from left program will remove 12 but when call display method show like this 12 43 65 and when make remove from right program will remove 23 but when call display method show like this 12 43 Why ?????? ); and when i try to make insert after remove write this Can not insert right because the queue is full . first remove right and then u can insert right where is the problem ?? Please Help me please 2) My code FIRST CLASS class dqueue { private int fullsize; //number of all cells private int item_num; // number of busy cells only private int front,rear; public int j; private double [] dqarr; //========================================== public dqueue(int s) //constructor { fullsize = s; front = 0; rear = -1; item_num = 0; dqarr = new double[fullsize]; } //========================================== public void insert(double data) { if (rear == fullsize-1) rear = -1; rear++; dqarr[rear] = data; item_num++; } public double removeLeft() // take item from front of queue { double temp = dqarr[front++]; // get value and incr front if(front == fullsize) front = 0; item_num --; // one less item return temp; } public double removeRight() // take item from rear of queue { double temp = dqarr[rear--]; // get value and decr rear if(rear == -1) // rear = item_num -1; item_num --; // one less item return temp; } //========================================= public void display () //display items { for (int j=0;j //========================================= public int size() //number of items in queue { return item_num; } //========================================== public boolean isEmpty() // true if queue is empty { return (item_num ==0); } } SECOND CLASS import java.util.Scanner; class dqueuetest { public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.println(" Welcome here** "); System.out.println(" * Mind Of Programming Group*** "); System.out.println(" _________________________ "); System.out.println("enter size of your dqueue"); int size = input.nextInt(); dqueue mydq = new dqueue(size); System.out.println(""); System.out.println("enter your itemes"); //===================================== for(int i = 0;i<=size-1;i++) { System.out.printf("item %d:",i+1); double item = input.nextDouble(); mydq.insert(item); System.out.println(""); } //===================================== int queue =size ; int c = 0 ; while (c != 6) { System.out.println(""); System.out.println("**************************"); System.out.println(" MAIN MENUE"); System.out.println("1- INSERT RIGHT "); System.out.println("2- REMOVE LEFT"); System.out.println("3- REMOVE RIGHT"); System.out.println("4- DISPLAY"); System.out.println("5- SIZE"); System.out.println("6- EXIT"); System.out.println("**************************"); System.out.println("choose your operation by number(1-6)"); c = input.nextInt(); switch (c) { case 1: if (queue == size) System.out.print("Can not insert right because the queue is full . first remove right and then u can insert right "); else { System.out.print("enter your item: "); double item = input.nextDouble(); mydq.insert(item);} break; case 2: System.out.println("REMOVE FROM REAR :"); if( !mydq.isEmpty() ) { double item = mydq.removeLeft(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 3: System.out.println("REMOVE FROM FRONT :"); if( !mydq.isEmpty() ) { double item = mydq.removeRight(); System.out.print(item + "\t"); } // end while System.out.println(""); mydq.display(); break; case 4: System.out.println("The items in Queue are :"); mydq.display(); break; case 5: System.out.println("The Size of the Queue is :"+mydq.size()); break; case 6: System.out.println("Good Bye"); break; default: System.out.println("wrong chiose enter again"); } //end switch } //end while } // end main }//end class

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• In Python what's the best way to emulate Perl's __END__?

  - by FM

  Am I correct in thinking that that Python doesn't have a direct equivalent for Perl's __END__? print "Perl...\n"; __END__ End of code. I can put anything I want here. One thought that occurred to me was to use a triple-quoted string. Is there a better way to achieve this in Python? print "Python..." """ End of code. I can put anything I want here. """

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• Check and avoid if a char is being entered in a int

  - by John

  Hi.... This is a exremely stupid question but i need help with this.... I'm trying to make a small program that i made robust and needed some help with tht.... int num1; int num2 = 0; System.out.print("Enter number 1: "); num1 = kb.nextInt(); while(num2<num1) { System.out.print("Enter number 2: "); num2 = kb.nextInt(); } Number 2 has to be greater than number 1 Also i want the program to automatically check and ignore if the user enters a char instead of an int... Cause right now when a user enters lets say "r" instead of a number the program just exists....

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• The return value should be a list but doesn't return as expected?! - Python newbie

  - by user1432941

  Hi this must be a very simple solution that has eluded me this last hour. I've tried to build this test function where the return value of the test_cases list should match the values in the test_case_answers list but for some reason, test case 1 and test case 2 fail. When i print the return values for the test cases they return the correct answers, but for some reason test case 1 and test case 2 return False. Thanks for your help! import math test_cases = [1, 9, -3] test_case_answers = [1, 3, 0] def custom_sqrt(num): for i in range(len(test_cases)): if test_cases[i] >= 0: return math.sqrt(test_cases[i]) else: return 0 for i in range(len(test_cases)): if custom_sqrt(test_cases[i]) != test_case_answers[i]: print "Test Case #", i, "failed!" custom_sqrt(test_cases)

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• Multi-threading does not work correctly using std::thread (C++ 11)

  - by user1364743

  I coded a small c++ program to try to understand how multi-threading works using std::thread. Here's the step of my program execution : Initialization of a 5x5 matrix of integers with a unique value '42' contained in the class 'Toto' (initialized in the main). I print the initialized 5x5 matrix. Declaration of std::vector of 5 threads. I attach all threads respectively with their task (threadTask method). Each thread will manipulate a std::vector<int> instance. I join all threads. I print the new state of my 5x5 matrix. Here's the output : 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 It should be : 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 42 0 0 0 0 0 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 4 4 4 4 4 Here's the code sample : #include <iostream> #include <vector> #include <thread> class Toto { public: /* ** Initialize a 5x5 matrix with the 42 value. */ void initData(void) { for (int y = 0; y < 5; y++) { std::vector<int> vec; for (int x = 0; x < 5; x++) { vec.push_back(42); } this->m_data.push_back(vec); } } /* ** Display the whole matrix. */ void printData(void) const { for (int y = 0; y < 5; y++) { for (int x = 0; x < 5; x++) { printf("%d ", this->m_data[y][x]); } printf("\n"); } printf("\n"); } /* ** Function attached to the thread (thread task). ** Replace the original '42' value by another one. */ void threadTask(std::vector<int> &list, int value) { for (int x = 0; x < 5; x++) { list[x] = value; } } /* ** Return the m_data instance propertie. */ std::vector<std::vector<int> > &getData(void) { return (this->m_data); } private: std::vector<std::vector<int> > m_data; }; int main(void) { Toto toto; toto.initData(); toto.printData(); //Display the original 5x5 matrix (first display). std::vector<std::thread> threadList(5); //Initialization of vector of 5 threads. for (int i = 0; i < 5; i++) { //Threads initializationss std::vector<int> vec = toto.getData()[i]; //Get each sub-vectors. threadList.at(i) = std::thread(&Toto::threadTask, toto, vec, i); //Each thread will be attached to a specific vector. } for (int j = 0; j < 5; j++) { threadList.at(j).join(); } toto.printData(); //Second display. getchar(); return (0); } However, in the method threadTask, if I print the variable list[x], the output is correct. I think I can't print the correct data in the main because the printData() call is in the main thread and the display in the threadTask function is correct because the method is executed in its own thread (not the main one). It's strange, it means that all threads created in a parent processes can't modified the data in this parent processes ? I think I forget something in my code. I'm really lost. Does anyone can help me, please ? Thank a lot in advance for your help.

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• remove the spaces...

  - by tekknolagi

  !/usr/bin/python import random lower_a = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] upper_a = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'] num = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'] all = [] all = " ".join("".join(lower_a) + "".join(upper_a) + "".join(num)) all = all.split() x = 0 while x < 10: for i in range(7): a = random.choice(all) print a, print x += 1 what i want to do is remove the spaces from the output what it gives now is Z 3 a A I K R G B i N 9 c E v g E r A N 8 e B 6 d v H O c a V 8 c x y b g 2 W a T T f 8 H T r 6 E p D K l 5 p u x q 8 P Z 9 T n I W X n B Q

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• Iterating through a range of dates in Python

  - by ShawnMilo

  This is working fine, but I'm looking for any feedback on how to do it better. Right now I think it's better than nested loops, but it starts to get Perl-one-linerish when you have a generator in a list comprehension. Any suggestions are welcome. day_count = (end_date - start_date).days + 1 for single_date in [d for d in (start_date + timedelta(n) for n in range(day_count)) if d <= end_date]: print strftime("%Y-%m-%d", single_date.timetuple()) Notes: I'm not actually using this to print; that's just for demo purposes. The variables start_date and end_date are datetime.date objects, because I don't need the timestamps (they're going to be used to generate a report). I checked the StackOverflow questions which were similar before posting this, but none were exactly the same. Sample Output (for a start date of 2009-05-30 and an end date of 2009-06-09): 2009-05-30 2009-05-31 2009-06-01 2009-06-02 2009-06-03 2009-06-04 2009-06-05 2009-06-06 2009-06-07 2009-06-08 2009-06-09

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• Subtype polymorphism and arrays

  - by user133466

  Computer[] labComputers = new Computer[10]; with public class Computer { ... void toString(){ // print computer specs } } public class Notebook extends Computer{ ... void toString(){ // print computer specs + laptop color } } each subscripted variable labComputers[i] can reference either a Computer object or a Notebook object because Notebook is a subclass of Computer. For the method call labComputers[i].toString(), polymorphism ensures that the correct toString method is called. I wonder what if we do Notebook[] labComputers = new Notebook[10]; what kind or error would I get if I reference with Computer object and a Notebook object

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• Why is Python 3.1 throwing a SyntaxError when printing after loop?

  - by bubersson

  Hi, I'm trying to run this snippet in Python 3.1 console and I'm getting SyntaxError: >>> while True: ... a=5 ... if a<6: ... break ... print("hello") File "<stdin>", line 5 print("hello") ^ SyntaxError: invalid syntax >>> (This is just shortened code to make a point.) Am I missing something? Is there some other Magic I don't know about? Thanks for your help (since this is my first StackOverflow question and I'm not a native English speaker)

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• python compare time

  - by Jesse Siu

  i want to using python create filter for a log file. get recent 7 days record. but when i didn't know how to compare time. like current time is 11/9/2012, i want to get records from 04/9/2012 to now the log file like Sat Sep 2 03:32:13 2012 [pid 12461] CONNECT: Client "66.249.68.236" Sat Sep 2 03:32:13 2012 [pid 12460] [ftp] OK LOGIN: Client "66.249.68.236", anon password "[email protected]" Sat Sep 2 03:32:14 2012 [pid 12462] [ftp] OK DOWNLOAD: Client "66.249.68.236", "/pub/10.5524/100001_101000/100022/readme.txt", 451 i using this one def OnlyRecent(line): print time.strptime(line.split("[")[0].strip(),"%a %b %d %H:%M:%S %Y") print time.time() if time.strptime(line.split("[")[0].strip(),"%a %b %d %H:%M:%S %Y") < time.time(): return True return False But it shows (2012, 9, 2, 3, 32, 13, 5, 246, -1) 1347332968.08 (2012, 9, 2, 3, 32, 13, 5, 246, -1) 1347332968.08 (2012, 9, 2, 3, 32, 14, 5, 246, -1) 1347332968.08 the time format is different, and it can't compare time. So how to set this comparison in 7 days. Thanks

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• can list be converted into string

  - by PARIJAT

  Actually i have extracted some data from the file and want to write it in the file 2 but the program says 'sequence item 1: expected string, list found', I want to know how i can convert buffer[] ie string into sequence, so that it could be saved in file 2...I am new to the python please help* file = open('/ddfs/user/data/k/ktrip_01/hmm.txt','r') file2 = open('/ddfs/user/data/k/ktrip_01/hmm_write.txt','w') buffer = [] rec = file.readlines() for line in rec : field = line.split() print '>',field[0] term = field[0] buffer.append(term) print field[1], field[2], field[6], field[12] term1 = field [1] buffer.append(term1) term2 = field[2] buffer.append[term2] term3 = field[6] buffer.append[term3] term4 = field[12] buffer.append[term4] file2.write(buffer) file.close() file2.close()

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• Printing a list using reflection

  - by TFool

  public class Service{ String serviceName; //setter and getter } public class Version{ String VersionID; //setter and getter } public void test(Object list){ //it shd print the obtained list } List< Service list1; //Service is a Bean List< Version list2; //Version is a Bean test(list1); test(list2); Now the test method shd print the obtained list - (i.e) If the list is of type Service ,then serviceName should be printed using its getter. If the list type is Version versionID should be printed. Is it possible to achieve this without using Interface or abstract class?

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• Regular Expression Program

  - by david robers

  Hi I have the following text: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ This method takes a regex in out by the user and SHOULD print out the Strings it applies to but seems to print out something completely different: private void matchIt(String regex) { Pattern p = Pattern.compile(regex); Matcher m = null; boolean found = false; for(int i = 0; i < data.length; i++){ m = p.matcher(data[i]); if(m.find()){ out.println(data[i]); found = true; } } if(!found){ out.println("Pattern Not Found"); } } When inputting "[C]" It outputs: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ Any ideas why? I think I'm using m.find() improperly...

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• Alternative to css3 not selector

  - by Raynos

  Are there any alternatives to the :not css3 selector that are compliant with IE8 (and quirks mode). Either in css or javascript/jquery that emulates the selector or something similar. I am using *:not as follows below. Feel free to recommend a solution that avoids the use of :not completely. @media screen { #printable { visibility: hidden; } } @media print { *:not(#printable) { visibility: hidden; } #printable { position: absolute; visibility: visible; } } Note that the use of :not is tied to the use of @media print so just using a simple jQuery solution to apply css to $(":not(#printable)") won't work without being clever. Including an entire library like ie9.js or selectivirz isn't an option as it can effect various other parts of the pages and would involve a large section of re-testing. a jsfiddle that shows it working in browsers that support :not http://jsfiddle.net/Raynos/TjKbz/

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• PHP variable question

  - by Kyle Parisi

  This works: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); $customerBox = mysql_query("MY SQL STATEMENT AGAIN"); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } This does not: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } Why? I guess I don't understand how variables work yet.

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• Resetting a while loop

  - by Patrick Beardmore

  I have found a confusing thing in a php script I am writing to generate some javascript. Here it is below, slightly simplified. The second while loop won't run unless I comment out the entire first while loop. Can anyone explain why? Many thanks. <?php $listid = 2; //DEMO ONLY $result1 = mysql_query("SELECT words.wid,words.wordmd5,words.word FROM words,instances WHERE words.wid = instances.wid AND instances.lid = \"$listid\""); $result1copy = $result1; $count1 = 1; while( $row = mysql_fetch_object( $result1 ) ) { print "words_left[$count1] = \"".$row->word."\";\n"; //Increment the array counter (starts at 1) $count1++; } ?> //Some javascript <?php $count2 = 1; while( $row = mysql_fetch_object( $result1copy ) ) { print " $count2 then $row->wordmd5 "; $count2++; } ?>

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• Json request with Javascript

  - by chota

  Hi, I am just beginner on java script and JSON and never had done any work in these before. My employer has just asked me to create the basic POC of these. Scenario: I have a REST API and when i call it, it returns back response in JSON format. Need to To: Create a HTML page and use javascript to call that REST API and capture JSON response and print in the same HTML page. <script type="text/javascript"> function loadMe() { loadJSON('http://myrestAPI'); } function loadJSON(url) { //Help me here to capture the response and print in html page. } </script> I would appreciate your help. This might be simple, but for me i have no idea because i never have done anything similar in java script and json. I goggled but could not find anything. Thanks, chota

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