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  • infix operation to postfix using stacks

    - by Chris De La O
    We are writing a program that needs to convert an infix operation (4 5/3) to postfix (4 5 3 / ) using stacks. however my convert to postfix does not work as it doesnt not output the postFix array that is supposed to store the conversion from infix notation to postfix notation. here is the code for the convertToPostix fuction. //converts infix expression to postfix expression void ArithmeticExpression::convertToPostfix(char *const inFix, char *const postFix) { //create a stack2 object named cow Stack2<char> cow; cout<<postFix; char thing = '('; //push a left parenthesis onto the stack cow.push(thing); //append a right parenthesis to the end of inFix array strcat(inFix, ")"); int i = 0;//declare an int that will control posFix position //if the stack is not empty if (!cow.isEmpty()) { //loop to run until the last character in inFix array for (int x = 0; inFix[x]!= '\0'; x++ ) { //if the inFix element is a digit if (isdigit(inFix[x])) { postFix[i]=inFix[x];//it is assigned to the next element in postFix array i++;//move on to next element in postFix } //if the inFix element is a left parenthesis else if (inFix[x]=='(') { cow.push(inFix[x]);//push it unto the stack } //if the inFix element is an operator else if (isOperator(inFix[x])) { char oper2 = inFix[x];//char variable holds inFix operator if (isOperator(cow.stackTop()))//if the top node in the stack is an operator { while (isOperator(cow.stackTop()))//and while the top node in the stack is an operator { char oper1 = cow.stackTop();//char variable holds node operator if(precedence( oper1, oper2))//if the node operator has higher presedence than node operator { postFix[i] = cow.pop();//we pop such operator and insert it in postFix array's next element cow.push(inFix[x]);//and push inFix operator unto the stack i++;//move to the next element in posFix } } } //if the top node is not an operator //we push the current inFix operator unto the top of the stack else cow.push(inFix[x]); } //if the inFix element is a right parenthesis else if (inFix[x]==')') { //we pop everything in the stack and insert it in postFix //until we arrive at a left paranthesis while (cow.stackTop()!='(') { postFix[i] = cow.pop(); i++; } //we then pop and discard left parenthesis cow.pop(); } } postFix[i]='\0'; //print !!postFix array!! (not stack) print();//code for this is just cout<<postFix; }

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  • Vertical scrolling in silverlight

    - by Mrt
    I have a silverlight application that is set to use 100% browser height. As I dynamically add controls to a canvas (which can be dragged around), I would like the expand the canvas vertically. Ideally show the browser scrollbar so the user can move up or down, if that can't be done, use the scrollbar control. I would also need to handle the user changing the size of the browser. Any suggestions on how to do this ? Cheers,

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  • Looking for a jQuery plugin : sort of bar rating

    - by Tristan
    Hello, i own a website where users can vote/rate things and i want to improve the poor inputbox (from 1 to 10) to improve visual rendering. I was thinking of a bar, which have 10 ' | ' you can move the cursor from one to ten (it doesn't have to be AJAX because the rating is only added at the end of the form) I'm sure you already seend this king of thing but i actually can't find any plugin of it. Any ideas please ?

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  • Disable email when modifying several bugs at once in bugzilla

    - by Jay Paroline
    Where I work, we use Bugzilla extensively for bug and feature tracking. We take advantage of the built in milestones to help us manage our timelines better, but sometimes priorities shift and milestones need to be rearranged. During this time we use the "change several bugs at once" feature to move them around, but the result is a ton of bugspam for everyone involved (except the person actually doing the changing, of course). Is there any way to easily turn off emails if many bugs are being changed at once?

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  • Absolute UriSource of a Resource image

    - by Louis Rhys
    I have a WPF project. If I store image in {ProjectRoot}\Images\image.png, and compile it as Resource then I can access it from a xaml (this xaml is located at Root) as BitmapImage by BitmapImage UriSource="Images/image.png". But if I move the xaml to another folder, say {ProjectRoot}\Xamls, now I have to use BitmapImage UriSource="../Images/image.png". Is there a way to specify an absolute project path, so that I can refer to them with the same path regardless of the location of the xaml?

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  • Icons/graphics for your applications

    - by rein
    I need to source some graphics/icons for my application I'm writing (Windows WinForms). I need graphics for toolbar buttons, icons for form headers and graphics for wizard dialog boxes. As a last resort I'm willing to create them myself - a move that might make them (and my whole application) look amazingly bad. What are some good sources (free or not) where I can get these kinds of programmer icons? I'd like the icons to be at least 32x32 256 color.

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  • How to identify end of page is reached in pdf file using itextsharp.

    - by user219315
    Hi I am using itextsharp to generate a pdf file.I am placing a backgound image on it and want that image on all the pages .But when the first page is completed the text move to next page automatically so the image is not appearing on the new page. Is there a way to identify the end of page so that we can add a new page and then set the image first so will appear in background and then can add the remaining text. All is i want a image in background on all the pages of pdf file.

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  • Vim: Smart indent when entering insert mode on blank line?

    - by TheDeeno
    When I open a new line (via 'o') my cursor jumps to a correctly indented position on the next line. On the other hand, entering insert mode while my cursor is on a blank line doesn't move my cursor to the correctly indented location. How do I make vim correctly indent my cursor when entering insert mode (via i) on a blank line?

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  • Modify iterator

    - by isola009
    I have a iterator (ite) created from a set (a): var a = Set(1,2,3,4,5) var ite = a.iterator If I remove 2 element of my set: a -= 2 Now, if I move iterator for all elements, I get all elements (2 element included). It's ok, but... How I can tell to iteratator to delete 2 element?

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  • SQL Server 2008 : Standard or SQL Express

    - by dr
    Which is a better choice on a development box if you primarily develop Asp.Net applications and SSRS reports. I have never had to use the Express editions, so I don't really know the pros or cons. The cons I have listed for Standard+ editions are: toll it takes on system resources pain to attach database for projects pain to detach unused databases $$$ Pros: You have everything you need Management Studio features Easy move to production

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  • Focus next textview automatically

    - by Naseer
    I have a TextView with android:maxLength set to 3 and another with android:maxLength set to 7. I want focus to automatically move to the second TextView once the 3 chars of the first TextView are filled up. Is this possible without inheriting TextView and writing a custom implementation ?

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  • if string is alphabetically greater than other string in objective

    - by Jonathan
    I'm trying to use an if statement to work out which of 2 strings comes first alphabetically. Like with numbers and greater and less than: if (1 < 2) { just with strings: if(@"ahello" < @"bhello") { Or would I have to have a string containing all the letters and then check the index of the first char in each string and see which index is greater, and the index that is less than the other comes first in the alphabet and then if they are equal move on to the next char and repeat?

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  • "Use of uninitialised value" despite of memset

    - by Framester
    Hi there, I allocate a 2d array and use memset to fill it with zeros. #include<stdio.h> #include<string.h> #include<stdlib.h> void main() { int m=10; int n =10; int **array_2d; array_2d = (int**) malloc(m*sizeof(int*)); if(array_2d==NULL) { printf("\n Could not malloc 2d array \n"); exit(1); } for(int i=0;i<m;i++) { ((array_2d)[i])=malloc(n*sizeof(int)); memset(((array_2d)[i]),0,sizeof(n*sizeof(int))); } for(int i=0; i<10;i++){ for(int j=0; j<10;j++){ printf("(%i,%i)=",i,j); fflush(stdout); printf("%i ", array_2d[i][j]); } printf("\n"); } } Afterwards I use valgrind [1] to check for memory errors. I get following error: Conditional jump or move depends on uninitialised value(s) for line 24 (printf("%i ", array_2d[i][j]);). I always thought memset is the function to initialize arrays. How can I get rid off this error? Thanks! Valgrind output: ==3485== Memcheck, a memory error detector ==3485== Copyright (C) 2002-2009, and GNU GPL'd, by Julian Seward et al. ==3485== Using Valgrind-3.5.0-Debian and LibVEX; rerun with -h for copyright info ==3485== Command: ./a.out ==3485== (0,0)=0 (0,1)===3485== Use of uninitialised value of size 4 ==3485== at 0x409E186: _itoa_word (_itoa.c:195) ==3485== by 0x40A1AD1: vfprintf (vfprintf.c:1613) ==3485== by 0x40A8FFF: printf (printf.c:35) ==3485== by 0x8048724: main (playing_with_valgrind.c:39) ==3485== ==3485== ==3485== ---- Attach to debugger ? --- [Return/N/n/Y/y/C/c] ---- ==3485== Conditional jump or move depends on uninitialised value(s) ==3485== at 0x409E18E: _itoa_word (_itoa.c:195) ==3485== by 0x40A1AD1: vfprintf (vfprintf.c:1613) ==3485== by 0x40A8FFF: printf (printf.c:35) ==3485== by 0x8048724: main (playing_with_valgrind.c:39) [1] valgrind --tool=memcheck --leak-check=yes --show-reachable=yes --num-callers=20 --track-fds=yes --db-attach=yes ./a.out [gcc-cmd] gcc -std=c99 -lm -Wall -g3 playing_with_valgrind.c

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  • Moving mysql files across servers

    - by tesmar
    I have a massive MySQL database (around 10 GB), and I need to copy it to a different server (slicehost). I don't want to do a DB dump and reimport b/c I think that would take forever. Is it possible to just move the raw SQL files from one machine to the next, setup an identical mysql server, and flip the switch?

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  • DRUPAL: replace tags with icons

    - by Patrick
    hi, is there any plugin for Drupal, replacing tags with small icons (see the picture below, the icons are actually small circles, and the different colors are automatically generated. I need to replace the tags with the circles, for each node, and the starting view. Furthermore, when the mouse move over the tags, the tag title should appear as pop-up thanks

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  • Illegal Instruction When Programming C++ on Linux

    - by remagen
    Heyo, My program, which does exactly the same thing every time it runs (moves a point sprite into the distance) will randomly fail with the text on the terminal 'Illegal Instruction'. My googling has found people encountering this when writing assembly which makes sense because assembly throws those kinds of errors. But why would g++ be generating an illegal instruction like this? It's not like I'm compiling for Windows then running on Linux (which even then, as long as both are on x86 shouldn't AFAIK cause an Illegal Instruction). I'll post the main file below. I can't reliably reproduce the error. Although, if I make random changes (add a space here, change a constant there) that force a recompile I can get a binary which will fail with Illegal Instruction every time it is run, until I try setting a break point, which makes the illegal instruction 'dissapear'. :( #include <stdio.h> #include <stdlib.h> #include <GL/gl.h> #include <GL/glu.h> #include <SDL/SDL.h> #include "Screen.h" //Simple SDL wrapper #include "Textures.h" //Simple OpenGL texture wrapper #include "PointSprites.h" //Simple point sprites wrapper double counter = 0; /* Here goes our drawing code */ int drawGLScene() { /* These are to calculate our fps */ static GLint T0 = 0; static GLint Frames = 0; /* Move Left 1.5 Units And Into The Screen 6.0 */ glLoadIdentity(); glTranslatef(0.0f, 0.0f, -6); glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT | GL_STENCIL_BUFFER_BIT); glEnable(GL_POINT_SPRITE_ARB); glTexEnvi(GL_POINT_SPRITE, GL_COORD_REPLACE, GL_TRUE); glBegin( GL_POINTS ); /* Drawing Using Triangles */ glVertex3d(0.0,0.0, 0); glVertex3d(1.0,0.0, 0); glVertex3d(1.0,1.0, counter); glVertex3d(0.0,1.0, 0); glEnd( ); /* Finished Drawing The Triangle */ /* Move Right 3 Units */ /* Draw it to the screen */ SDL_GL_SwapBuffers( ); /* Gather our frames per second */ Frames++; { GLint t = SDL_GetTicks(); if (t - T0 >= 50) { GLfloat seconds = (t - T0) / 1000.0; GLfloat fps = Frames / seconds; printf("%d frames in %g seconds = %g FPS\n", Frames, seconds, fps); T0 = t; Frames = 0; counter -= .1; } } return 1; } GLuint objectID; int main( int argc, char **argv ) { Screen screen; screen.init(); screen.resize(800,600); LoadBMP("./dist/Debug/GNU-Linux-x86/particle.bmp"); InitPointSprites(); while(true){drawGLScene();} }

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  • Running router as virtual machine, can it be realible ?

    - by Kr1stian
    Hi all Does anyone here run their routing through virtual machine, have virtual machine setup as main router/getaway etc ? If yes, how many clients are using this kind of setup ? For those who are wondering why I'm asking this. I got assignment for my internship to create all in one "box" which would do routing and be IP PBX in one time ( only open source solutions can be used, expect RouterOS). The routing part is currently done through RouterOS and for VoIP they want to use sipXecs. RouterOS supports virtualization through KVM, but RouterOS itself only supports 2GB of memory ( and wont support more in near future). sipXecs needs allot more than 2GB. I told them that we could solve this problem by putting RouterOS as virtual machine to 64bit hostOS ( e.g. CentOS), and other virtual machine would run sipXecs. By that we would be able to use whole memory. But they told me that it's to risky to do something like that and that they need something with "enterprise stability/reliability". I told them that we could make redundant image of each VM which would automatically start if one VM stop's working, but I was told the same thing. So this is why I asked those question above, to see if I really suggested something that's not good to do, or maybe this is something completely normal and it can be done with "enterprise stability/reliability" :) Thank you for answers, Kristian

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  • questions regarding the use of A* with the 15-square puzzle

    - by Cheeso
    I'm trying to build an A* solver for a 15-square puzzle. The goal is to re-arrange the tiles so that they appear in their natural positions. You can only slide one tile at a time. Each possible state of the puzzle is a node in the search graph. For the h(x) function, I am using an aggregate sum, across all tiles, of the tile's dislocation from the goal state. In the above image, the 5 is at location 0,0, and it belongs at location 1,0, therefore it contributes 1 to the h(x) function. The next tile is the 11, located at 0,1, and belongs at 2,2, therefore it contributes 3 to h(x). And so on. EDIT: I now understand this is what they call "Manhattan distance", or "taxicab distance". I have been using a step count for g(x). In my implementation, for any node in the state graph, g is just +1 from the prior node's g. To find successive nodes, I just examine where I can possibly move the "hole" in the puzzle. There are 3 neighbors for the puzzle state (aka node) that is displayed: the hole can move north, west, or east. My A* search sometimes converges to a solution in 20s, sometimes 180s, and sometimes doesn't converge at all (waited 10 mins or more). I think h is reasonable. I'm wondering if I've modeled g properly. In other words, is it possible that my A* function is reaching a node in the graph via a path that is not the shortest path? Maybe have I not waited long enough? Maybe 10 minutes is not long enough? For a fully random arrangement, (assuming no parity problems), What is the average number of permutations an A* solution will examine? (please show the math) I'm going to look for logic errors in my code, but in the meantime, Any tips? (ps: it's done in Javascript). Also, no, this isn't CompSci homework. It's just a personal exploration thing. I'm just trying to learn Javascript. EDIT: I've found that the run-time is highly depend upon the heuristic. I saw the 10x factor applied to the heuristic from the article someone mentioned, and it made me wonder - why 10x? Why linear? Because this is done in javascript, I could modify the code to dynamically update an html table with the node currently being considered. This allowd me to peek at the algorithm as it was progressing. With a regular taxicab distance heuristic, I watched as it failed to converge. There were 5's and 12's in the top row, and they kept hanging around. I'd see 1,2,3,4 creep into the top row, but then they'd drop out, and other numbers would move up there. What I was hoping to see was 1,2,3,4 sort of creeping up to the top, and then staying there. I thought to myself - this is not the way I solve this personally. Doing this manually, I solve the top row, then the 2ne row, then the 3rd and 4th rows sort of concurrently. So I tweaked the h(x) function to more heavily weight the higher rows and the "lefter" columns. The result was that the A* converged much more quickly. It now runs in 3 minutes instead of "indefinitely". With the "peek" I talked about, I can see the smaller numbers creep up to the higher rows and stay there. Not only does this seem like the right thing, it runs much faster. I'm in the process of trying a bunch of variations. It seems pretty clear that A* runtime is very sensitive to the heuristic. Currently the best heuristic I've found uses the summation of dislocation * ((4-i) + (4-j)) where i and j are the row and column, and dislocation is the taxicab distance. One interesting part of the result I got: with a particular heuristic I find a path very quickly, but it is obviously not the shortest path. I think this is because I am weighting the heuristic. In one case I got a path of 178 steps in 10s. My own manual effort produce a solution in 87 moves. (much more than 10s). More investigation warranted. So the result is I am seeing it converge must faster, and the path is definitely not the shortest. I have to think about this more. Code: var stop = false; function Astar(start, goal, callback) { // start and goal are nodes in the graph, represented by // an array of 16 ints. The goal is: [1,2,3,...14,15,0] // Zero represents the hole. // callback is a method to call when finished. This runs a long time, // therefore we need to use setTimeout() to break it up, to avoid // the browser warning like "Stop running this script?" // g is the actual distance traveled from initial node to current node. // h is the heuristic estimate of distance from current to goal. stop = false; start.g = start.dontgo = 0; // calcHeuristic inserts an .h member into the array calcHeuristicDistance(start); // start the stack with one element var closed = []; // set of nodes already evaluated. var open = [ start ]; // set of nodes to evaluate (start with initial node) var iteration = function() { if (open.length==0) { // no more nodes. Fail. callback(null); return; } var current = open.shift(); // get highest priority node // update the browser with a table representation of the // node being evaluated $("#solution").html(stateToString(current)); // check solution returns true if current == goal if (checkSolution(current,goal)) { // reconstructPath just records the position of the hole // through each node var path= reconstructPath(start,current); callback(path); return; } closed.push(current); // get the set of neighbors. This is 3 or fewer nodes. // (nextStates is optimized to NOT turn directly back on itself) var neighbors = nextStates(current, goal); for (var i=0; i<neighbors.length; i++) { var n = neighbors[i]; // skip this one if we've already visited it if (closed.containsNode(n)) continue; // .g, .h, and .previous get assigned implicitly when // calculating neighbors. n.g is nothing more than // current.g+1 ; // add to the open list if (!open.containsNode(n)) { // slot into the list, in priority order (minimum f first) open.priorityPush(n); n.previous = current; } } if (stop) { callback(null); return; } setTimeout(iteration, 1); }; // kick off the first iteration iteration(); return null; }

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  • about onmouseout event.please help.

    - by lazyanno
    as follow codes: <div id="outerBox" style="border:1px solid red;width:300;height:300" onmouseout="alert('out')"> <div id="innerBox" style="border:1px solid blue;width:50;height:50">inner</div> </div> why when i move mouse on the "innerBox", it was trigger alert('out') ? i want mouse out "outerBox" trigger alert('out') only, mouse on "innerBox" don't trigger alert. hot to do this? thanks all :)

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