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  • WebClient Lost my Session

    - by kamiar3001
    Hi folks I have a problem first of all look at my web service method : [WebMethod(), ScriptMethod(ResponseFormat = ResponseFormat.Json)] public string GetPageContent(string VirtualPath) { WebClient client = new WebClient(); string content=string.Empty; client.Encoding = System.Text.Encoding.UTF8; try { if (VirtualPath.IndexOf("______") > 0) content = client.DownloadString(HttpContext.Current.Request.UrlReferrer.AbsoluteUri.Replace("Main.aspx", VirtualPath.Replace("__", "."))); else content = client.DownloadString(HttpContext.Current.Request.UrlReferrer.AbsoluteUri.Replace("Main.aspx", VirtualPath)); } catch { content = "Not Found"; } return content; } As you can see my web service method read and buffer page from it's localhost it works and I use it to add some ajax functionality to my web site it works fine but my problem is Client.DownloadString(..) lost all session because my sessions are all null which are related to this page for more description. at page-load in the page which I want to load from my web service I set session : HttpContext.Current.Session[E_ShopData.Constants.SessionKey_ItemList] = result; but when I click a button in the page this session is null I mean it can't transfer session. How I can solve this problem ? my web service is handled by some jquery code like following : $.ajax({ type: "Post", url: "Services/NewE_ShopServices.asmx" + "/" + "GetPageContent", data: "{" + "VirtualPath" + ":" + mp + "}", contentType: "application/json; charset=utf-8", dataType: "json", complete: hideBlocker, success: LoadAjaxSucceeded, async: true, cache: false, error: AjaxFailed });

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  • How to run White + SL4 UATs through TeamCity?

    - by Duncan Bayne
    After experiencing a series of unpleasant issues with TFS, including source code orruption and project management inflexibility, we (meaning the project team of which I'm a part) have decided to move from TFS 2010 to TeamCity + SVN + V1. I've managed to get our MSTest component and unit tests running as part of every build. However, our UATs are failing, and I was hoping for some advice from the TeamCity community as to best practices w.r.t. running web servers and interacting with the desktop. Each of our UAT fixtures starts a web server to host the site, like this: public static void StartWebServer() { var pathToSite = @"C:\projects\myproject\FrontEnd\MyProject.FrontEnd.Web"; var webServer = new Process { StartInfo = new ProcessStartInfo { Arguments = string.Format("/port:9150 /path:\"{0}\"", pathToSite), FileName = @"C:\Program Files (x86)\Common Files\microsoft shared\DevServer\10.0\WebDev.WebServer40.EXE" } }; webServer.Start(); } Needless to say, this doesn't work when running through TeamCity, as the pathToSite value is different each time. I'm hoping there is a way of determining the path into which the the code is checked out prior to building? That would allow me to point the web server at the right place. The other issue is that our UATs use White to drive the Silverlight UI through an instance of Internet Explorer: _browserWindow = InternetExplorer.Launch("http://localhost:9150/index.html#/Home", "Home - Windows Internet Explorer"); _document = _browserWindow.SilverlightDocument; I've ensured that the TeamCity service is granted the ability to interact with the desktop, and I've set the build agent machine up to log in automatically (an open session is a pre-requisite for White to work properly). Is that all I need to do or are there additional steps required?

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  • Use Django ORM as standalone [closed]

    - by KeyboardInterrupt
    Possible Duplicates: Use only some parts of Django? Using only the DB part of Django I want to use the Django ORM as standalone. Despite an hour of searching Google, I'm still left with several questions: Does it require me to set up my Python project with a setting.py, /myApp/ directory, and modules.py file? Can I create a new models.py and run syncdb to have it automatically setup the tables and relationships or can I only use models from existing Django projects? There seems to be a lot of questions regarding PYTHONPATH. If you're not calling existing models is this needed? I guess the easiest thing would be for someone to just post a basic template or walkthrough of the process, clarifying the organization of the files e.g.: db/ __init__.py settings.py myScript.py orm/ __init__.py models.py And the basic essentials: # settings.py from django.conf import settings settings.configure( DATABASE_ENGINE = "postgresql_psycopg2", DATABASE_HOST = "localhost", DATABASE_NAME = "dbName", DATABASE_USER = "user", DATABASE_PASSWORD = "pass", DATABASE_PORT = "5432" ) # orm/models.py # ... # myScript.py # import models.. And whether you need to run something like: django-admin.py inspectdb ... (Oh, I'm running Windows if that changes anything regarding command-line arguments.).

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  • How to get database table header information into an CSV File.

    - by Rachel
    I am trying to connect to the database and get current state of a table and update that information into csv file, with below mentioned piece of code, am able to get data information into csv file but am not able to get header information from database table into csv file. So my questions is How can I get Database Table Header information into an CSV File ? $config['database'] = 'sakila'; $config['host'] = 'localhost'; $config['username'] = 'root'; $config['password'] = ''; $d = new PDO('mysql:dbname='.$config['database'].';host='.$config['host'], $config['username'], $config['password']); $query = "SELECT * FROM actor"; $stmt = $d->prepare($query); // Execute the statement $stmt->execute(); var_dump($stmt->fetch(PDO::FETCH_ASSOC)); $data = fopen('file.csv', 'w'); while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo "Hi"; // Export every row to a file fputcsv($data, $row); } Header information meaning: Vehicle Build Model car 2009 Toyota jeep 2007 Mahindra So header information for this would be Vehicle Build Model Any guidance would be highly appreciated.

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  • How to return value using ajax

    - by Priyanka
    Hello. I have Ajax file in which code has written to accept values form user and then these values are taken in a Ajax function as follows: $(document).ready(function(){ $("#newsletterform").validate(); $('#Submit').click(function(){ var name = $('#newsletter_name').val(); var email = $('#newsletter_email').val(); sendValue(email,name); }); }); The function for paasing values and getting values from other file: function sendValue(str,name){ $.post( "newsletter/subscribe.php", //Ajax file { sendValue: str, sendVal: name }, function(data2){ $('#display').html(data2.returnValue); }, //How you want the data formated when it is returned from the server. "json" ); } and these values are passed to another file called "subscribe.php" in which insertion code to database is written and again I return the value to my first ajax function as follows: echo json_encode(array("returnValue"=$msg)); The msg is ging to contain my message to be displayed. But now, this works fine on localhost, I get the return values nad message properly but when I upload it on server this gives me an error as: data2 is null [Break on this error] $('#display').html(data2.returnValue); This only gives error for return value but insertion, sending mail functionality works fine. Please provide me with a good solution wherein I can be able to get back the return values without any error. Thanks in advance.

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  • php sessions in database only writing part of information to the table...

    - by Ronedog
    I'm having difficulty figuring out what's going on here, hoping some one can help me out. I have been using php, mysql storing my session information in the database. The app is only running on localhost, vista. In the php.ini file I commented out the "session.save_handler = files" line and am using a php class to handle the session writes/reads, etc. My login process is this: Submit login credentials via login.php. login.php calls loginprocess.php. loginprocess.php verifies user, and if valid starts a new session and adds data to the session vars, then it redirects to index.php. Here's the problem. the loginprocess.php page has a bunch of session vars that get set like $_SESSION['account_id'] = $account_id; etc. but when I go to index.php and do a var_dump($_SESSION) it just says "array() empty". However, if I do a var_dump($_SESSION) in loginprocess.php, just before the redirection line header("Location: ../index.php"); then it shows all the data in the session variable. If I look in the database where the session information is stored, there is data in the session_id field, created_ts field, and expires field, but the session_data field has nothing inside of it and in the past this is the field where all my session data was stored. How could I be able to var_dump the session in loginprocess.php, but the data not exist in the db table, is it using some kind of caching? I cleared my cookies, etc...but no change. Why is the session_id, being written to the table, but the actual session data is not? Any ideas are appreciated. Thanks.

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  • Postback not working with ASP.NET Routing (Validation of viewstate MAC failed)

    - by Robert
    Hi. I'm using the ASP.NET 3.5 SP1 System.Web.Routing with classic WebForms, as described in http://chriscavanagh.wordpress.com/2008/04/25/systemwebrouting-with-webforms-sample/ All works fine, I have custom SEO urls and even the postback works. But there is a case where the postback always fails and I get a: Validation of viewstate MAC failed. If this application is hosted by a Web Farm or cluster, ensure that configuration specifies the same validationKey and validation algorithm. AutoGenerate cannot be used in a cluster. Here is the scenario to reproduce the error: Create a standard webform mypage.aspx with a button Create a Route that maps "a/b/{id}" to "~/mypage.aspx" When you execute the site, you can navigate http://localhost:XXXX/a/b/something the page works. But when you press the button you get the error. The error doen't happen when the Route is just "a/{id}". It seems to be related to the number of sub-paths in the url. If there are at least 2 sub-paths the viewstate validation fails. You get the error even with EnableViewStateMac="false". Any ideas? Is it a bug? Thanks

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  • Fun with "The remote server returned an error: NotFound" - Silverlight4 Out of Browser

    - by Scott Silvi
    Hey all - I'm running SL4 on VS2010. I've got an app that authenticates via a web service to SPROC in my db. Unfortunately this is not WCF/WCF RIA, as I'm inheriting the DB/services from my client. This works perfectly inside of a browser. I'm attempting to move this OOB, and it's at this point that my authentication fails. Here's the steps I took... 1) SL App Properties Enable running app Out of Browser 2) SL App Properties Out of Browser Settings Require elevated trust when running OOB If i set a breakpoint on my logon button click, I see the service call is being made. However, if I step through it (or set a breakpoint on the actual logon web service), the code never gets that far. Here's the block it fails on: public LogonSVC.LogonResponse EndLogon(System.IAsyncResult result) { object[] _args = new object[0]; LogonSVC.LogonResponse _result = ((LogonSVC.LogonResponse)(base.EndInvoke("Logon", _args, result))); return _result; } I know using Elevated Trust means the crossdomain.xml isn't necessary. I dropped one in that allows everything, just to test, and that still fails. here's the code that calls the service: private void loginButton_Click(object sender, RoutedEventArgs e) { string Username = txtUserName.Text; string Password = txtPassword.Password; Uri iSilverlightServiceUriRelative = new Uri(App.Current.Host.Source, "../Services/Logon.asmx"); EndpointAddress iSilverlightServiceEndpoint = new EndpointAddress(iSilverlightServiceUriRelative); BasicHttpBinding iSilverlightServiceBinding = new BasicHttpBinding(BasicHttpSecurityMode.Transport);// Transport if it's HTTPS:// LogonService = new LogonSVC.LogonSoapClient(iSilverlightServiceBinding, iSilverlightServiceEndpoint); LogonService.LogonCompleted += new EventHandler<LogonSVC.LogonCompletedEventArgs>(LogonService_LogonCompleted); LogonService.LogonAsync(Username, Password); } My LogonService_LogonCompleted doesn't fire either (which makes sense, just a heads up). I don't know how to fiddler this, as this is running OOB with the site served via localhost/IIS. I know this works though in browser, so I'm curious what would break it OOB. Thank you, Scott

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  • java.io.StreamCorruptedException: invalid stream header: 7371007E

    - by Alex
    Hello, this is pprobably a simple question . I got a client Server application which communicate using objects. when I send only one object from the client to server all works well. when I attempt to send several objects one after another on the same stream I get StreamCorruptedException. can some one direct me to the cause of this error . Thanks client write method private SecMessage[] send(SecMessage[] msgs) { SecMessage result[]=new SecMessage[msgs.length]; Socket s=null; ObjectOutputStream objOut =null; ObjectInputStream objIn=null; try { s=new Socket("localhost",12345); objOut=new ObjectOutputStream( s.getOutputStream()); for (SecMessage msg : msgs) { objOut.writeObject(msg); } objOut.flush(); objIn=new ObjectInputStream(s.getInputStream()); for (int i=0;i<result.length;i++) result[i]=(SecMessage)objIn.readObject(); } catch(java.io.IOException e) { alert(IO_ERROR_MSG+"\n"+e.getMessage()); } catch (ClassNotFoundException e) { alert(INTERNAL_ERROR+"\n"+e.getMessage()); } finally { try {objIn.close();} catch (IOException e) {} try {objOut.close();} catch (IOException e) {} } return result; } server read method //in is an inputStream Defined in the server SecMessage rcvdMsgObj; rcvdMsgObj=(SecMessage)new ObjectInputStream(in).readObject(); return rcvdMsgObj; and the SecMessage Class is public class SecMessage implements java.io.Serializable { private static final long serialVersionUID = 3940341617988134707L; private String cmd; //... nothing interesting here , just a bunch of fields , getter and setters }

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  • upload picture to and send path to database

    - by opa.mido
    I am trying to upload picture and link it to my database and I used the codes below : Upload2.php <?php // Check if a file has been uploaded if(isset($_FILES['uploaded_file'])) { // Make sure the file was sent without errors if($_FILES['uploaded_file']['error'] == 0) { // Connect to the database $dbLink = new mysqli('localhost', 'root', '1234', 'fyp'); if(mysqli_connect_errno()) { die("MySQL connection failed: ". mysqli_connect_error()); } // Gather all required data $name = $dbLink->real_escape_string($_FILES['uploaded_file']['name']); $mime = $dbLink->real_escape_string($_FILES['uploaded_file']['type']); $data = $dbLink->real_escape_string(file_get_contents($_FILES ['uploaded_file']['tmp_name'])); $size = intval($_FILES['uploaded_file']['size']); // Create the SQL query $query = " INSERT INTO `pic` ( `Name`, `size`, `data`, `created` ) VALUES ( '{$name}', '{$mime}', {$size}, '{$data}', NOW() )"; // Execute the query $result = $dbLink->query($query); // Check if it was successfull if($result) { echo 'Success! Your file was successfully added!'; } else { echo 'Error! Failed to insert the file' . "<pre>{$dbLink->error}</pre>"; } } else { echo 'An error accured while the file was being uploaded. ' . 'Error code: '. intval($_FILES['uploaded_file']['error']); } // Close the mysql connection $dbLink->close(); } else { echo 'Error! A file was not sent!'; } // Echo a link back to the main page echo '<p>Click <a href="index.html">here</a> to go back</p>'; ?> I reached the last stage and its give error a file was not sent I don't know where I have missed. thank you

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  • Android GPS cloud of confusion!

    - by Anthony Forloney
    I am trying to design my first Android application with the use of GPS. As of right now, I have a drawable button that when clicked, alerts a Toast message of the longitude and latitude. I have tried to use the telnet localhost 5554 and then geo fix #number #number to feed in values but no results display just 0 0. I have also tried DDMS way of sending GPS coordinates and I get the same thing. My question is what exactly is the code equivalent to the geo fix and the DDMS way of sending coordinates. I have used Location, LocationManger and LocationListener but I am not sure which is the right choice. Could anyone explain to me what the code-equivalent just so I can get a better understanding of how to fix my application not working. Code is given, just in case if the error exists with the code @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); Button button = (Button) findViewById(R.id.track); button.setOnClickListener(this); LocationManager location =(LocationManager)getSystemService(Context.LOCATION_SERVICE); Location loc = location.getLastKnownLocation(location.GPS_PROVIDER); updateWithNewLocation(loc); } private final LocationListener locationListener = new LocationListener() { public void onLocationChanged(Location location) { updateWithNewLocation(location); } private void updateWithNewLocation(Location l) { longitude = l.getLongitude(); latitude = l.getLatitude(); provider = l.getProvider(); } public void onClick(View v) { Toast.makeText(this, "Your location is " + longitude + " and " + latitude + " provided by: " + provider, Toast.LENGTH_SHORT).show(); } }

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  • JQuery object expected error when accessing page via url routing.

    - by Andy Evans
    In my global.asax I have url routing setup like below: routes.MapPageRoute("User Logon", "{Vendor}/Logon", "~/Logon.aspx"); In the logon.aspx page, I have a script that "stylizes" the logon button: <link href="jquery/css/flick/jquery-ui-1.8.1.custom.css" rel="stylesheet" type="text/css" /> <link href="images/style.css" rel="stylesheet" type="text/css" /> <script src="jquery/js/jquery-1.4.2.min.js" type="text/javascript"></script> <script src="jquery/js/jquery-ui-1.8.1.custom.min.js" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function () { $('#<%= ButtonLogon.ClientID %>').button(); }); </script> When I access the page us a url (in debug mode) http://localhost/logon.aspx?v=1 the page loads correctly and the jquery button command loads correctly. But then I access the page using the new url route, I get this error. Microsoft JScript runtime error: Object expected Anyone have an idea why this occurs? Thanks.

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  • Static content not displayed with Zend FW

    - by shin
    I am trying to display a static content with Zend framework. When I go to http://square.localhost/content/services, I get an error message. Could anyone tell me how to fix this please? Thanks in advance. application.ini .... .... resources.layout.layoutPath = APPLICATION_PATH "/layouts" resources.layout.layout = "master" resources.router.routes.home.route = /home resources.router.routes.home.defaults.module = default resources.router.routes.home.defaults.controller = index resources.router.routes.home.defaults.action = index resources.router.routes.static-content.route = /content/:page resources.router.routes.static-content.defaults.module = default resources.router.routes.static-content.defaults.controller = static-content resources.router.routes.static-content.defaults.action = display application/modules/default/controllers/StaticContentController.php class StaticContentController extends Zend_Controller_Action { public function init() { } // display static views public function displayAction() { $page = $this->getRequest()->getParam('page'); if (file_exists($this->view->getScriptPath(null) . "/" . $this->getRequest()->getControllerName() . "/$page." . $this->viewSuffix)) { $this->render($page); } else { throw new Zend_Controller_Action_Exception('Page not found', 404); } } } application/modules/default/views/scripts/static-content/services.phtml some html ... ... Error message An error occurred Page not found Exception information: Message: Page not found Stack trace: #0 /var/www/square/library/Zend/Controller/Action.php(513): StaticContentController->displayAction() #1 /var/www/square/library/Zend/Controller/Dispatcher/Standard.php(295): Zend_Controller_Action->dispatch('displayAction') #2 /var/www/square/library/Zend/Controller/Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) #3 /var/www/square/library/Zend/Application/Bootstrap/Bootstrap.php(97): Zend_Controller_Front->dispatch() #4 /var/www/square/library/Zend/Application.php(366): Zend_Application_Bootstrap_Bootstrap->run() #5 /var/www/square/public/index.php(26): Zend_Application->run() #6 {main} Request Parameters: array ( 'page' => 'services', 'module' => 'default', 'controller' => 'static-content', 'action' => 'display', )

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  • gdb: Cannot find new threads: generic error

    - by Alexander Gladysh
    When I run GDB against a program which loads a .so which is linked to pthreads, GDB reports error "Cannot find new threads: generic error". I probably miss something in my Ubuntu configuration (as it was installed from minimal install). Any clues? $ gdb --args lua -lluarocks.require GNU gdb (GDB) 7.0-ubuntu Copyright (C) 2009 Free Software Foundation, Inc. License GPLv3+: GNU GPL version 3 or later This is free software: you are free to change and redistribute it. There is NO WARRANTY, to the extent permitted by law. Type "show copying" and "show warranty" for details. This GDB was configured as "x86_64-linux-gnu". For bug reporting instructions, please see: <http://www.gnu.org/software/gdb/bugs/>... Reading symbols from /usr/bin/lua...(no debugging symbols found)...done. (gdb) run Starting program: /usr/bin/lua -lluarocks.require Lua 5.1.4 Copyright (C) 1994-2008 Lua.org, PUC-Rio require 'ev' [Thread debugging using libthread_db enabled] Cannot find new threads: generic error (gdb) q A debugging session is active. Inferior 1 [process 4986] will be killed. Quit anyway? (y or n) y This function gets called on require 'ev': http://github.com/brimworks/lua-ev/blob/master/lua_ev.c#L25-65 Additional information about my system: $ uname -a Linux localhost 2.6.31-20-generic #58-Ubuntu SMP Fri Mar 12 04:38:19 UTC 2010 x86_64 GNU/Linux $ lsb_release -a No LSB modules are available. Distributor ID: Ubuntu Description: Ubuntu 9.10 Release: 9.10 Codename: karmic

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  • How do I write this MySQL query?

    - by CT
    I am working on an Asset DB using a lamp stack. In this example consider the following 5 tables: asset, server, laptop, desktop, software All tables have a primary key of id, which is a unique asset id. Every object has all asset attributes and then depending on type of asset has additional attributes in the corresponding table. If the type is a server, desktop or laptop it also has items in the software table. Here are the table create statements: // connect to mysql server and database "asset_db" mysql_connect("localhost", "asset_db", "asset_db") or die(mysql_error()); mysql_select_db("asset_db") or die(mysql_error()); // create asset table mysql_query("CREATE TABLE asset( id VARCHAR(50) PRIMARY KEY, company VARCHAR(50), location VARCHAR(50), purchase_date VARCHAR(50), purchase_order VARCHAR(50), value VARCHAR(50), type VARCHAR(50), notes VARCHAR(200))") or die(mysql_error()); echo "Asset Table Created.</br />"; // create software table mysql_query("CREATE TABLE software( id VARCHAR(50) PRIMARY KEY, software VARCHAR(50), license VARCHAR(50))") or die(mysql_error()); echo "Software Table Created.</br />"; // create laptop table mysql_query("CREATE TABLE laptop( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), serial_number VARCHAR(50), esc VARCHAR(50), user VARCHAR(50), prev_user VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Laptop Table Created.</br />"; // create desktop table mysql_query("CREATE TABLE desktop( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), serial_number VARCHAR(50), esc VARCHAR(50), user VARCHAR(50), prev_user VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Desktop Table Created.</br />"; // create server table mysql_query("CREATE TABLE server( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Server Table Created.</br />"; ?> How do I query the database so that if I search by id, I receive all related fields to that asset id? Thank you.

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  • How do I get PHP variables from this MySQL query?

    - by CT
    I am working on an Asset Database problem using PHP / MySQL. In this script I would like to search my assets by an asset id and have it return all related fields. First I query the database asset table and find the asset's type. Then depending on the type I run 1 of 3 queries. <?php //make database connect mysql_connect("localhost", "asset_db", "asset_db") or die(mysql_error()); mysql_select_db("asset_db") or die(mysql_error()); //get type of asset $type = mysql_query(" SELECT asset.type From asset WHERE asset.id = 93120 ") or die(mysql_error()); switch ($type){ case "Server": //do some stuff that involves a mysql query mysql_query(" SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serial_number ,server.esc ,server.user ,server.prev_user ,server.warranty FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = 93120 "); break; case "Laptop": //do some stuff that involves a mysql query mysql_query(" SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,laptop.manufacturer ,laptop.model ,laptop.serial_number ,laptop.esc ,laptop.user ,laptop.prev_user ,laptop.warranty FROM asset LEFT JOIN laptop ON laptop.id = asset.id WHERE asset.id = 93120 "); break; case "Desktop": //do some stuff that involves a mysql query mysql_query(" SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,desktop.manufacturer ,desktop.model ,desktop.serial_number ,desktop.esc ,desktop.user ,desktop.prev_user ,desktop.warranty FROM asset LEFT JOIN desktop ON desktop.id = asset.id WHERE asset.id = 93120 "); break; } ?> So far I am able to get asset.type into $type. How would I go about getting the rest of the variables (laptop.model to $model, asset.notes to $notes and so on)? Thank you.

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  • Netbeans with Oracle connection java.lang.ClassNotFoundException

    - by Attilah
    I use NetBeans 6.5 . When I try to run the following code : package com.afrikbrain.numeroteur16; import java.sql.Connection; import java.sql.DriverManager; import java.sql.SQLException; import java.util.logging.Level; import java.util.logging.Logger; /** * * @author */ public class NumeroteurTest { public NumeroteurTest() { } public void doIt() throws ClassNotFoundException{ try { Class.forName("oracle.jdbc.OracleDriver"); Connection connection = DriverManager.getConnection("jdbc:oracle:thin:@localhost:1521:XE","user","pwd"); String newNUMERO = new Numeroteur16("MATCLI", connection).numeroter(); System.out.println("NUMERO GENERE : "+newNUMERO.toString()); } catch (SQLException ex) { Logger.getLogger(NumeroteurTest.class.getName()).log(Level.SEVERE, null, ex); ex.printStackTrace(); } catch (NumException ex) { System.out.println(ex.getMessage()); ex.printStackTrace(); } } public static void main(String[] args){ try { new NumeroteurTest().doIt(); } catch (ClassNotFoundException ex) { Logger.getLogger(NumeroteurTest.class.getName()).log(Level.SEVERE, null, ex); System.out.println("Driver not found."); } } } when running it, I get this error : java.lang.ClassNotFoundException: oracle.jdbc.OracleDriver at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:307) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) at java.lang.ClassLoader.loadClass(ClassLoader.java:252) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:169) at com.afrikbrain.numeroteur16.NumeroteurTest.doIt(NumeroteurTest.java:27) at com.afrikbrain.numeroteur16.NumeroteurTest.main(NumeroteurTest.java:45) Driver not found. how do I solve this problem ?

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  • uploading image & getting back from database

    - by Anup Prakash
    Putting a set of code which is pushing image to database and fetching back from database: <!-- <?php error_reporting(0); // Connect to database $errmsg = ""; if (! @mysql_connect("localhost","root","")) { $errmsg = "Cannot connect to database"; } @mysql_select_db("test"); $q = <<<CREATE create table image ( pid int primary key not null auto_increment, title text, imgdata longblob, friend text) CREATE; @mysql_query($q); // Insert any new image into database if (isset($_POST['submit'])) { move_uploaded_file($_FILES['imagefile']['tmp_name'],"latest.img"); $instr = fopen("latest.img","rb"); $image = addslashes(fread($instr,filesize("latest.img"))); if (strlen($instr) < 149000) { $image_query="insert into image (title, imgdata,friend) values (\"". $_REQUEST['title']. "\", \"". $image. "\",'".$_REQUEST['friend']."')"; mysql_query ($image_query) or die("query error"); } else { $errmsg = "Too large!"; } $resultbytes=''; // Find out about latest image $query = "select * from image where pid=1"; $result = @mysql_query("$query"); $resultrow = @mysql_fetch_assoc($result); $gotten = @mysql_query("select * from image order by pid desc limit 1"); if ($row = @mysql_fetch_assoc($gotten)) { $title = htmlspecialchars($row[title]); $bytes = $row[imgdata]; $resultbytes = $row[imgdata]; $friend=$row[friend]; } else { $errmsg = "There is no image in the database yet"; $title = "no database image available"; // Put up a picture of our training centre $instr = fopen("../wellimg/ctco.jpg","rb"); $bytes = fread($instr,filesize("../wellimg/ctco.jpg")); } if ($resultbytes!='') { echo $resultbytes; } } ?> <html> <head> <title>Upload an image to a database</title> </head> <body bgcolor="#FFFF66"> <form enctype="multipart/form-data" name="file_upload" method="post"> <center> <div id="image" align="center"> <h2>Heres the latest picture</h2> <font color=red><?php echo $errmsg; ?></font> <b><?php echo $title ?></center> </div> <hr> <h2>Please upload a new picture and title</h2> <table align="center"> <tr> <td>Select image to upload: </td> <td><input type="file" name="imagefile"></td> </tr> <tr> <td>Enter the title for picture: </td> <td><input type="text" name="title"></td> </tr> <tr> <td>Enter your friend's name:</td> <td><input type="text" name="friend"></td> </tr> <tr> <td><input type="submit" name="submit" value="submit"></td> <td></td> </tr> </table> </form> </body> </html> --> Above set of code has one problem. The problem is whenever i pressing the "submit" button. It is just displaying the image on a page. But it is leaving all the html codes. even any new line message after the // Printing image on browser echo $resultbytes; //************************// So, for this i put this set of code in html tag: This is other sample code: <!-- <?php error_reporting(0); // Connect to database $errmsg = ""; if (! @mysql_connect("localhost","root","")) { $errmsg = "Cannot connect to database"; } @mysql_select_db("test"); $q = <<<CREATE create table image ( pid int primary key not null auto_increment, title text, imgdata longblob, friend text) CREATE; @mysql_query($q); // Insert any new image into database if (isset($_POST['submit'])) { move_uploaded_file($_FILES['imagefile']['tmp_name'],"latest.img"); $instr = fopen("latest.img","rb"); $image = addslashes(fread($instr,filesize("latest.img"))); if (strlen($instr) < 149000) { $image_query="insert into image (title, imgdata,friend) values (\"". $_REQUEST['title']. "\", \"". $image. "\",'".$_REQUEST['friend']."')"; mysql_query ($image_query) or die("query error"); } else { $errmsg = "Too large!"; } $resultbytes=''; // Find out about latest image $query = "select * from image where pid=1"; $result = @mysql_query("$query"); $resultrow = @mysql_fetch_assoc($result); $gotten = @mysql_query("select * from image order by pid desc limit 1"); if ($row = @mysql_fetch_assoc($gotten)) { $title = htmlspecialchars($row[title]); $bytes = $row[imgdata]; $resultbytes = $row[imgdata]; $friend=$row[friend]; } else { $errmsg = "There is no image in the database yet"; $title = "no database image available"; // Put up a picture of our training centre $instr = fopen("../wellimg/ctco.jpg","rb"); $bytes = fread($instr,filesize("../wellimg/ctco.jpg")); } } ?> <html> <head> <title>Upload an image to a database</title> </head> <body bgcolor="#FFFF66"> <form enctype="multipart/form-data" name="file_upload" method="post"> <center> <div id="image" align="center"> <h2>Heres the latest picture</h2> <?php if ($resultbytes!='') { // Printing image on browser echo $resultbytes; } ?> <font color=red><?php echo $errmsg; ?></font> <b><?php echo $title ?></center> </div> <hr> <h2>Please upload a new picture and title</h2> <table align="center"> <tr> <td>Select image to upload: </td> <td><input type="file" name="imagefile"></td> </tr> <tr> <td>Enter the title for picture: </td> <td><input type="text" name="title"></td> </tr> <tr> <td>Enter your friend's name:</td> <td><input type="text" name="friend"></td> </tr> <tr> <td><input type="submit" name="submit" value="submit"></td> <td></td> </tr> </table> </form> </body> </html> --> ** But in this It is showing the image in format of special charaters and digits. 1) So, Please help me to print the image with some HTML code. So that i can print it in my form to display the image. 2) Is there any way to convert the database image into real image, so that i can store it into my hard-disk and call it from tag? Please help me.

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  • How to tell when a Socket has been disconnected

    - by BowserKingKoopa
    On the client side I need to know when/if my socket connection has been broken. However the Socket.Connected property always returns true, even after the server side has been disconnected and I've tried sending data through it. Can anyone help me figure out what's going on here. I need to know when a socket has been disconnected. Socket serverSocket = null; TcpListener listener = new TcpListener(1530); listener.Start(); listener.BeginAcceptSocket(new AsyncCallback(delegate(IAsyncResult result) { Debug.WriteLine("ACCEPTING SOCKET CONNECTION"); TcpListener currentListener = (TcpListener)result.AsyncState; serverSocket = currentListener.EndAcceptSocket(result); }), listener); Socket clientSocket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); Debug.WriteLine("client socket connected: " + clientSocket.Connected);//should be FALSE, and it is clientSocket.Connect("localhost", 1530); Debug.WriteLine("client socket connected: " + clientSocket.Connected);//should be TRUE, and it is Thread.Sleep(1000); serverSocket.Close();//closing the server socket here Thread.Sleep(1000); clientSocket.Send(new byte[0]);//sending data should cause the socket to update its Connected property. Debug.WriteLine("client socket connected: " + clientSocket.Connected);//should be FALSE, but its always TRUE

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  • How do I test is storage-conf is being loaded in Cassandra 0.7.3?

    - by user657253
    I have installed Cassandra and gotten it working on two machines. I have followed the instructions to hook them up to each other by configuring the storage-conf.xml files. Both machines respond well to thrift and to command line cassandra. This is tutorial I used to setup the storage-conf.xml files. The tutorial says that if I run netstat, I should NOT see Cassandra bound to 127.0.0.1 on my seed node. I should see it bound to my internal IP, which I have configured in the storage-conf.xml file. I have rebooted the servers and relaunched cassandra. Still, I see the localhost address insead of the correct internal IP address. Is it that my .yaml file is overriding the storage-conf.xml file? If so, how do I delete the appropriate things in the .yaml? Or how do I tell Cassandra to look for my storage-conf.xml file? A few things I have tried: renaming the cassandra.yaml file. What happens is that cassandra will not load. If i rename the storage-conf.xml, cassandra does load. When I installed Cassandra, it did not come with a storage-conf.xml file. I had to grab it off the apache wiki.

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  • gpg error - connection already closed?

    - by OopsForgotMyOtherUserName
    omg... hope someone can help me because I am so lost as to what to try next.... I don't know what is causing the error to happen, and I don't see how to figure it out... Keep going between the pgloader.conf examples and what I have, and I don't understand why I keep getting the 'connection already closed' error? The first few lines of my fr.conf is at the very end... I'd really appreciate / love some guidance here... Been trying to get this thing going all morning, and am even getting stuck just on this part... Running this command at the command line: /usr/bin/pgloader -c /var/mybin/pgconfs/fr.conf Yields this in the pgloader.log (with the process just hanging) more /tmp/pgloader.log 27-03-2010 12:22:53 pgloader INFO Logger initialized 27-03-2010 12:22:53 pgloader INFO Reformat path is ['/usr/share/python-support/pgloader/reformat'] 27-03-2010 12:22:53 pgloader INFO Will consider following sections: 27-03-2010 12:22:53 pgloader INFO fixed 27-03-2010 12:22:54 fixed INFO fixed processing 27-03-2010 12:22:54 pgloader INFO All threads are started, wait for them to terminate 27-03-2010 12:22:57 fixed ERROR connection already closed 27-03-2010 12:22:57 fixed INFO closing current database connection [pgsql] host = localhost port = 5432 base = frdb user = username pass = password [fixed] table = fr format = fixed filename = /var/www/fr.txt ...

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  • ASP.Net MVC, JS injection and System.ArgumentException - Illegal Characters in path

    - by Mose
    Hi, In my ASP.Net MVC application, I use custom error handling. I want to perform custom actions for each error case I meet in my application. So I override Application_Error, get the Server.GetLastError(); and do my business depending on the exception, the current user, the current URL (the application runs on many domains), the user IP, and many others. Obviousely, the application is often the target of hackers. In almost all the case it's not a problem to detect and manage it, but for some JS URL attacks, my error handling does not perform what I want it to do. Ex (from logs) : http://localhost:1809/Scripts/]||!o.support.htmlSerialize&&[1 When I got such an URL, an exception is raised when accessing the ConnectionStrings section in the web.config, and I can't even redirect to another URL. It leads to a "System.ArgumentException - Illegal Characters in path, etc." The screenshot below shows the problem : http://screencast.com/t/Y2I1YWU4 An obvious solution is to write a HTTP module to filter the urls before they reach my application, but I'd like to avoid it because : I like having the whole security being managed in one place (in the Application_Error() method) In the module I cannot access the whole data I have in the application itself (application specific data I don't want to debate here) Questions : Did you meet this problem ? How did you manage it ? Thanks for you suggestions, Mose

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  • Why Illegal cookies are send by Browser and received by web servers (rfc2109)?

    - by Artyom
    Hello, According to RFC 2109 cookie's value can be either HTTP token or quoted string, and token can't include non-ASCII characters. Cookie's RFC 2109: http://tools.ietf.org/html/rfc2109#page-3 HTTP's RFC 2068 token definition: http://tools.ietf.org/html/rfc2068#page-16 However I had found that Firefox browser (3.0.6) sends cookies with utf-8 string as-is and three web servers I tested (apache2, lighttpd, nginx) pass this string as-is to the application. For example, raw request from browser: $ nc -l -p 8080 GET /hello HTTP/1.1 Host: localhost:8080 User-Agent: Mozilla/5.0 (X11; U; Linux x86_64; en-US; rv:1.9.0.9) Gecko/2009050519 Firefox/2.0.0.13 (Debian-3.0.6-1) Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Accept-Language: en-us,en;q=0.5 Accept-Encoding: gzip,deflate Accept-Charset: windows-1255,utf-8;q=0.7,*;q=0.7 Keep-Alive: 300 Connection: keep-alive Cookie: wikipp=1234; wikipp_username=?????? Cache-Control: max-age=0 And raw response of apache, nginx and lighttpd HTTP_COOKIE CGI variable: wikipp=1234; wikipp_username=?????? What do I miss? Can somebody explain me?

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  • [grails] setting cookies when render type is "contentType: text/json"

    - by Robin Jamieson
    Is it possible to set cookies on response when the return render type is set as json? I can set cookies on the response object when returning with a standard render type and later on, I'm able to get it back on the subsequent request. However, if I were to set the cookies while rendering the return values as json, I can't seem to get back the cookie on the next request object. What's happening here? These two actions work as expected with 'basicForm' performing a regular form post to the action, 'withRegularSubmit', when the user clicks submit. // first action set the cookie and second action yields the originally set cookie def regularAction = { // using cookie plugin response.setCookie("username-regular", "regularCookieUser123",604800); return render(view: "basicForm"); } // called by form post def withRegularSubmit = { def myCookie = request.getCookie("username-regular"); // returns the value 'regularCookieUser123' return render(view: "resultView"); } When I switch to setting the cookie just before returning from the response with json, I don't get the cookie back with the post. The request starts by getting an html document that contains a form and when doc load event is fired, the following request is invoked via javascript with jQuery like this: var someUrl = "http://localhost/jsonAction"; $.get(someUrl, function(jsonData) { // do some work with javascript} The controller work: // this action is called initially and returns an html doc with a form. def loadJsonForm = { return render(view: "jsonForm"); } // called via javascript when the document load event is fired def jsonAction = { response.setCookie("username-json", "jsonCookieUser456",604800); // using cookie plugin return render(contentType:'text/json') { 'pair'('myKey': "someValue") }; } // called by form post def withJsonSubmit = { def myCookie = request.getCookie("username-json"); // got null value, expecting: jsonCookieUser456 return render(view: "resultView"); } The data is returned to the server as a result of the user pressing the 'submit' button and not through a script. Prior to the submit of both 'withRegularSubmit' and 'withJsonSubmit', I see the cookies stored in the browser (Firefox) so I know they reached the client.

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  • mysql_real_escape_string() just makes an empty string?

    - by James P
    I am using a jQuery AJAX request to a page called like.php that connects to my database and inserts a row. This is the like.php code: <?php // Some config stuff define(DB_HOST, 'localhost'); define(DB_USER, 'root'); define(DB_PASS, ''); define(DB_NAME, 'quicklike'); $link = mysql_connect(DB_HOST, DB_USER, DB_PASS) or die('ERROR: ' . mysql_error()); $sel = mysql_select_db(DB_NAME, $link) or die('ERROR: ' . mysql_error()); $likeMsg = mysql_real_escape_string(trim($_POST['likeMsg'])); $timeStamp = time(); if(empty($likeMsg)) die('ERROR: Message is empty'); $sql = "INSERT INTO `likes` (like_message, timestamp) VALUES ('$likeMsg', $timeStamp)"; $result = mysql_query($sql, $link) or die('ERROR: ' . mysql_error()); echo mysql_insert_id(); mysql_close($link); ?> The problematic line is $likeMsg = mysql_real_escape_string(trim($_POST['likeMsg']));. It seems to just return an empty string, and in my database under the like_message column all I see is blank entries. If I remove mysql_real_escape_string() though, it works fine. Here's my jQuery code if it helps. $('#like').bind('keydown', function(e) { if(e.keyCode == 13) { var likeMessage = $('#changer p').html(); if(likeMessage) { $.ajax({ cache: false, url: 'like.php', type: 'POST', data: { likeMsg: likeMessage }, success: function(data) { $('#like').unbind(); writeLikeButton(data); } }); } else { $('#button_container').html(''); } } }); All this jQuery code works fine, I've tested it myself independently. Any help is greatly appreciated, thanks.

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