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  • Setting up a domain using WAMP and NameCheap's DNS service

    - by Mike Jones
    So, I've been working on this for far longer than I should be and I'm quite thoroughly perplexed and lost. I apologize if this turns out to be a facile question, but I'm entirely befuddled and very much in need of some guidance. Earlier today I registered a cheap .info domain on NameCheap just to play around with as I learn webdev. I have WAMP installed on my computer and I've been testing my projects through localhost. I thought it would be a good idea to have a domain at my disposal in order to understand how it works and better test my work. NameCheap has a complimentary DNS service (not that I entirely understand what DNS is, although I tried), so I'm using that. I direct both the "@" and "www" host names to my IP address, as shown in the below tutorial: https://www.namecheap.com/support/knowledgebase/article.aspx/319/78/how-can-i-setup-an-a-address-record-for-my-domain However, now when I go to the URL of the domain I bought, it confronts me with a login box that seems to be coming from my wifi network. How do I set this up so that it hosts the information in my WAMP server? Thanks in advance for any help, I really appreciate it. And, as a side-note, what should read (print or online) to better understand the structure of the internet? I've been studying HTML/CSS/Javascript, but I'm not sure where to look for pragmatic and comprehensive information on how the internet works and how to utilize it as a website administrator. Thanks so much.

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  • Trouble making login page?

    - by Ken
    Okay, so I want to make a simple login page. I've created a register page successfully, but i can't get the login thing down. login.php: <?php session_start(); include("mainmenu.php"); $usrname = mysql_real_escape_string($_POST['usrname']); $password = md5($_POST['password']); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } mysql_select_db("users", $con) or die(mysql_error()); $login = "SELECT * FROM `users` WHERE (usrname = '$usrname' AND password = '$password')"; $result = mysql_query($login); if(mysql_num_rows($result) == 1 { $_SESSION = true; header('Location: indexlogin.php'); } else { echo = "Wrong username or password." ; } ?> indexlogin.php just echoes "Login successful." What am I doing wrong? Oh, and just FYI- my database is "users" and my table is "data".

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  • using jquery in mysql php

    - by JPro
    I am new to using Jquery using mysql and PHP I am using the following code to pull the data. But there is not data or error displayed. JQUERY: <html> <head> <script> function doAjaxPost() { // get the form values var field_a = $("#field_a").val(); $("#loadthisimage").show(); $.ajax({ type: "POST", url: "serverscript.php", data: "ID="+field_a, success: function(resp){ $("#resposnse").html(resp); $("#loadthisimage").hide(); }, error: function(e){ alert('Error: ' + e); } }); } </script> </head> <body> <select id="field_a"> <option value="data_1">data_1</option> <option value="data_2">data_2</option> </select> <input type="button" value="Ajax Request" onClick="doAjaxPost()"> <a href="#" onClick="doAjaxPost()">Here</a> </form> <div id="resposnse"> <img src="ajax-loader.gif" style="display:none" id="loadthisimage"> </div> </body> and now serverscript.php <?php if(isset($_POST['ID'])) { $nm = $_POST['ID']; echo $nm; //insert your code here for the display. mysql_connect("localhost", "root", "pop") or die(mysql_error()); mysql_select_db("JPro") or die(mysql_error()); $result1 = mysql_query("select Name from results where ID = \"$nm\" ") or die(mysql_error()); // store the record of the "example" table into $row while($row1 = mysql_fetch_array( $result1 )) { $tc = $row1['Name']; echo $tc; } } ?>

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  • JSF works only with the .xhtml ending

    - by ThreeFingerMark
    Hello, i start with the programming of a JSF Website. At the moment all files have the .xhtml ending. When i go to http://localhost:8080/myProject/start.jsf everything is all right. But when i rename the file from start.xhtml to start.jsf i became a NoClassDefFound Error. What is my mistake? <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>*.jsf</url-pattern> </servlet-mapping> <context-param> <param-name>javax.faces.PROJECT_STAGE</param-name> <param-value>Development</param-value> </context-param>

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  • Delphi Client-Server Application using Firebird 2.5 embedded connection error

    - by Japster
    0 down vote favorite 1 share [fb] share [tw] I have got a lengthy question to ask. First of all Im still very new when it comes to Delphi programming and my experience has beem mostly developing small single user database applications using ADO and an Access database. I need to take the transition now to a client server application and this is where the problem starts. I decided to use Firebird 2.5 embeded as my database, as it is open source, and it is can be used with the interbase components in Delphi and that multiple clients can access the database simultanously. So I followed the interbase tutorial in Delphi. I managed to connect the client to the server and see the data in the example (While both are running on my pc), but when i tried to move the client to another pc, keeping the server on mine and running it to see if I can connect to the server it gave me the following error. Exception EIdSocketError in module clientDemo.exe at 0029DCAC. Socket Error # 10061 Connection refused. I understand that this might be because the host is defined as localhost in the client. But here is my first question. In the TSQLConncetion you can set die hostname under Driver-Hostname. The thing I want to know is how do you do this at run time, as I cannot get the property when I try and make an edit box to allow the user to enter the value and then set it via code like for example: SQLConncetion1.Driver.Hostname := edtHost.text; This cannot be done this way and the only way I see you can set the hostname is with the object inspector, but that is not available at runtime and I need to set the hostname on the client when the program is running the first time, so how do you set the hostname/IP address at runtime? Im using Delphi XE2 There is still a lot of questions to come especially when it comes to deployment, but I will take this piece by piece and I appreciate the advice.

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  • How do I write this MySQL query?

    - by CT
    I am working on an Asset DB using a lamp stack. In this example consider the following 5 tables: asset, server, laptop, desktop, software All tables have a primary key of id, which is a unique asset id. Every object has all asset attributes and then depending on type of asset has additional attributes in the corresponding table. If the type is a server, desktop or laptop it also has items in the software table. Here are the table create statements: // connect to mysql server and database "asset_db" mysql_connect("localhost", "asset_db", "asset_db") or die(mysql_error()); mysql_select_db("asset_db") or die(mysql_error()); // create asset table mysql_query("CREATE TABLE asset( id VARCHAR(50) PRIMARY KEY, company VARCHAR(50), location VARCHAR(50), purchase_date VARCHAR(50), purchase_order VARCHAR(50), value VARCHAR(50), type VARCHAR(50), notes VARCHAR(200))") or die(mysql_error()); echo "Asset Table Created.</br />"; // create software table mysql_query("CREATE TABLE software( id VARCHAR(50) PRIMARY KEY, software VARCHAR(50), license VARCHAR(50))") or die(mysql_error()); echo "Software Table Created.</br />"; // create laptop table mysql_query("CREATE TABLE laptop( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), serial_number VARCHAR(50), esc VARCHAR(50), user VARCHAR(50), prev_user VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Laptop Table Created.</br />"; // create desktop table mysql_query("CREATE TABLE desktop( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), serial_number VARCHAR(50), esc VARCHAR(50), user VARCHAR(50), prev_user VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Desktop Table Created.</br />"; // create server table mysql_query("CREATE TABLE server( id VARCHAR(50) PRIMARY KEY, manufacturer VARCHAR(50), model VARCHAR(50), warranty VARCHAR(50))") or die(mysql_error()); echo "Server Table Created.</br />"; ?> How do I query the database so that if I search by id, I receive all related fields to that asset id? Thank you.

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  • POST xml to php with apache2

    - by Berry
    I'm working on an application that receives XML data via POST, processes it with a PHP script, and returns an XML response. I'm getting the XML with this PHP code: $requestStr = file_get_contents('php://input'); $requests = simplexml_load_string($requestStr); which works fine on the Linux-based product hardware using nginx as the server. However, for testing I'd like to be able to run it on my MacBook Pro, so I can avoid the "build image, install on product, reboot product, wait, test change" loop while I do targeted development on this XML processor. I enabled "web sharing" which starts up Apache, added a rewrite rule to point a convenient URI at my development source directory and used curl to send a request to my PHP script thus: curl -H "Content-Type:text/xml" -d @request.xml http://localhost/test/path/testscript "testscript" is handled by the PHP script fine, but when it goes to read "php:://input" I get nothing -- the empty string. Anyone have a clue why this would work under Linux with nginx and not under MacOS with Apache? I've googled and searched stackoverlow.com to no avail. Thanks for any answers. UPDATE: I've discovered that at least in this configuration, reading from php://stdin will work fine, while php://input will not. Who knew?

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  • How to correctly waitFor() a saveScreenShot() end of execution.

    - by Alain
    Here is my full first working test: var expect = require('chai').expect; var assert = require('assert'); var webdriverjs = require('webdriverjs'); var client = {}; var webdriverOptions = { desiredCapabilities: { browserName: 'phantomjs' }, logLevel: 'verbose' }; describe('Test mysite', function(){ before(function() { client = webdriverjs.remote( webdriverOptions ); client.init(); }); var selector = "#mybodybody"; it('should see the correct title', function(done) { client.url('http://localhost/mysite/') .getTitle( function(err, title){ expect(err).to.be.null; assert.strictEqual(title, 'My title page' ); }) .waitFor( selector, 2000, function(){ client.saveScreenshot( "./ExtractScreen.png" ); }) .waitFor( selector, 7000, function(){ }) .call(done); }); after(function(done) { client.end(done); }); }); Ok, it does not do much, but after working many hours to get the environement correctly setup, it passed. Now, the only way I got it working is by playing with the waitFor() method and adjust the delays. It works, but I still do not understand how to surely wait for a png file to be saved on disk. As I will deal with tests orders, I will eventually get hung up from the test script before securely save the file. Now, How can I improve this screen save sequence and avoid loosing my screenshot ? Thanks.

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  • uploading image & getting back from database

    - by Anup Prakash
    Putting a set of code which is pushing image to database and fetching back from database: <!-- <?php error_reporting(0); // Connect to database $errmsg = ""; if (! @mysql_connect("localhost","root","")) { $errmsg = "Cannot connect to database"; } @mysql_select_db("test"); $q = <<<CREATE create table image ( pid int primary key not null auto_increment, title text, imgdata longblob, friend text) CREATE; @mysql_query($q); // Insert any new image into database if (isset($_POST['submit'])) { move_uploaded_file($_FILES['imagefile']['tmp_name'],"latest.img"); $instr = fopen("latest.img","rb"); $image = addslashes(fread($instr,filesize("latest.img"))); if (strlen($instr) < 149000) { $image_query="insert into image (title, imgdata,friend) values (\"". $_REQUEST['title']. "\", \"". $image. "\",'".$_REQUEST['friend']."')"; mysql_query ($image_query) or die("query error"); } else { $errmsg = "Too large!"; } $resultbytes=''; // Find out about latest image $query = "select * from image where pid=1"; $result = @mysql_query("$query"); $resultrow = @mysql_fetch_assoc($result); $gotten = @mysql_query("select * from image order by pid desc limit 1"); if ($row = @mysql_fetch_assoc($gotten)) { $title = htmlspecialchars($row[title]); $bytes = $row[imgdata]; $resultbytes = $row[imgdata]; $friend=$row[friend]; } else { $errmsg = "There is no image in the database yet"; $title = "no database image available"; // Put up a picture of our training centre $instr = fopen("../wellimg/ctco.jpg","rb"); $bytes = fread($instr,filesize("../wellimg/ctco.jpg")); } if ($resultbytes!='') { echo $resultbytes; } } ?> <html> <head> <title>Upload an image to a database</title> </head> <body bgcolor="#FFFF66"> <form enctype="multipart/form-data" name="file_upload" method="post"> <center> <div id="image" align="center"> <h2>Heres the latest picture</h2> <font color=red><?php echo $errmsg; ?></font> <b><?php echo $title ?></center> </div> <hr> <h2>Please upload a new picture and title</h2> <table align="center"> <tr> <td>Select image to upload: </td> <td><input type="file" name="imagefile"></td> </tr> <tr> <td>Enter the title for picture: </td> <td><input type="text" name="title"></td> </tr> <tr> <td>Enter your friend's name:</td> <td><input type="text" name="friend"></td> </tr> <tr> <td><input type="submit" name="submit" value="submit"></td> <td></td> </tr> </table> </form> </body> </html> --> Above set of code has one problem. The problem is whenever i pressing the "submit" button. It is just displaying the image on a page. But it is leaving all the html codes. even any new line message after the // Printing image on browser echo $resultbytes; //************************// So, for this i put this set of code in html tag: This is other sample code: <!-- <?php error_reporting(0); // Connect to database $errmsg = ""; if (! @mysql_connect("localhost","root","")) { $errmsg = "Cannot connect to database"; } @mysql_select_db("test"); $q = <<<CREATE create table image ( pid int primary key not null auto_increment, title text, imgdata longblob, friend text) CREATE; @mysql_query($q); // Insert any new image into database if (isset($_POST['submit'])) { move_uploaded_file($_FILES['imagefile']['tmp_name'],"latest.img"); $instr = fopen("latest.img","rb"); $image = addslashes(fread($instr,filesize("latest.img"))); if (strlen($instr) < 149000) { $image_query="insert into image (title, imgdata,friend) values (\"". $_REQUEST['title']. "\", \"". $image. "\",'".$_REQUEST['friend']."')"; mysql_query ($image_query) or die("query error"); } else { $errmsg = "Too large!"; } $resultbytes=''; // Find out about latest image $query = "select * from image where pid=1"; $result = @mysql_query("$query"); $resultrow = @mysql_fetch_assoc($result); $gotten = @mysql_query("select * from image order by pid desc limit 1"); if ($row = @mysql_fetch_assoc($gotten)) { $title = htmlspecialchars($row[title]); $bytes = $row[imgdata]; $resultbytes = $row[imgdata]; $friend=$row[friend]; } else { $errmsg = "There is no image in the database yet"; $title = "no database image available"; // Put up a picture of our training centre $instr = fopen("../wellimg/ctco.jpg","rb"); $bytes = fread($instr,filesize("../wellimg/ctco.jpg")); } } ?> <html> <head> <title>Upload an image to a database</title> </head> <body bgcolor="#FFFF66"> <form enctype="multipart/form-data" name="file_upload" method="post"> <center> <div id="image" align="center"> <h2>Heres the latest picture</h2> <?php if ($resultbytes!='') { // Printing image on browser echo $resultbytes; } ?> <font color=red><?php echo $errmsg; ?></font> <b><?php echo $title ?></center> </div> <hr> <h2>Please upload a new picture and title</h2> <table align="center"> <tr> <td>Select image to upload: </td> <td><input type="file" name="imagefile"></td> </tr> <tr> <td>Enter the title for picture: </td> <td><input type="text" name="title"></td> </tr> <tr> <td>Enter your friend's name:</td> <td><input type="text" name="friend"></td> </tr> <tr> <td><input type="submit" name="submit" value="submit"></td> <td></td> </tr> </table> </form> </body> </html> --> ** But in this It is showing the image in format of special charaters and digits. 1) So, Please help me to print the image with some HTML code. So that i can print it in my form to display the image. 2) Is there any way to convert the database image into real image, so that i can store it into my hard-disk and call it from tag? Please help me.

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  • How do I get PHP variables from this MySQL query?

    - by CT
    I am working on an Asset Database problem using PHP / MySQL. In this script I would like to search my assets by an asset id and have it return all related fields. First I query the database asset table and find the asset's type. Then depending on the type I run 1 of 3 queries. <?php //make database connect mysql_connect("localhost", "asset_db", "asset_db") or die(mysql_error()); mysql_select_db("asset_db") or die(mysql_error()); //get type of asset $type = mysql_query(" SELECT asset.type From asset WHERE asset.id = 93120 ") or die(mysql_error()); switch ($type){ case "Server": //do some stuff that involves a mysql query mysql_query(" SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serial_number ,server.esc ,server.user ,server.prev_user ,server.warranty FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = 93120 "); break; case "Laptop": //do some stuff that involves a mysql query mysql_query(" SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,laptop.manufacturer ,laptop.model ,laptop.serial_number ,laptop.esc ,laptop.user ,laptop.prev_user ,laptop.warranty FROM asset LEFT JOIN laptop ON laptop.id = asset.id WHERE asset.id = 93120 "); break; case "Desktop": //do some stuff that involves a mysql query mysql_query(" SELECT asset.id ,asset.company ,asset.location ,asset.purchase_date ,asset.purchase_order ,asset.value ,asset.type ,asset.notes ,desktop.manufacturer ,desktop.model ,desktop.serial_number ,desktop.esc ,desktop.user ,desktop.prev_user ,desktop.warranty FROM asset LEFT JOIN desktop ON desktop.id = asset.id WHERE asset.id = 93120 "); break; } ?> So far I am able to get asset.type into $type. How would I go about getting the rest of the variables (laptop.model to $model, asset.notes to $notes and so on)? Thank you.

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  • Android GPS cloud of confusion!

    - by Anthony Forloney
    I am trying to design my first Android application with the use of GPS. As of right now, I have a drawable button that when clicked, alerts a Toast message of the longitude and latitude. I have tried to use the telnet localhost 5554 and then geo fix #number #number to feed in values but no results display just 0 0. I have also tried DDMS way of sending GPS coordinates and I get the same thing. My question is what exactly is the code equivalent to the geo fix and the DDMS way of sending coordinates. I have used Location, LocationManger and LocationListener but I am not sure which is the right choice. Could anyone explain to me what the code-equivalent just so I can get a better understanding of how to fix my application not working. Code is given, just in case if the error exists with the code @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); Button button = (Button) findViewById(R.id.track); button.setOnClickListener(this); LocationManager location =(LocationManager)getSystemService(Context.LOCATION_SERVICE); Location loc = location.getLastKnownLocation(location.GPS_PROVIDER); updateWithNewLocation(loc); } private final LocationListener locationListener = new LocationListener() { public void onLocationChanged(Location location) { updateWithNewLocation(location); } private void updateWithNewLocation(Location l) { longitude = l.getLongitude(); latitude = l.getLatitude(); provider = l.getProvider(); } public void onClick(View v) { Toast.makeText(this, "Your location is " + longitude + " and " + latitude + " provided by: " + provider, Toast.LENGTH_SHORT).show(); } }

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  • Starting with NHibernate

    - by George
    I'm having major difficulties to start off with NHiberante. Main problems: Where my hbm.xml files should reside? I create a Mappings folder but I received an error "Could not find xxx.hbm.xml file." I tried to load the specific class through the dialect cf.AddClass(typeof(xxx)); but it still gives me the same error (the files are marked as embebed resources. Also I'm having major problems in connection to it. I stopped trying to use the cfg xml file and tried a more direct approach with a library I have here. Configuration cfg = new Configuration(); cfg.AddClass(typeof(Tag)); ISessionFactory sessions = cfg.BuildSessionFactory(); AgnosticConnectionHandler agch = new AgnosticConnectionHandler("xxx","xxx","geo_biblio","localhost", 5432,DatabaseInstance.PostgreSQL); ISession sessao = sessions.OpenSession(agch.GetConnection); ITransaction tx = sessao.BeginTransaction(); Tag tag1 = new Tag(); tag1.NomeTag = "Teste Tag NHibernate!!!"; sessao.Save(tag1); tx.Commit(); sessao.Close(); Any tips for me? I'm getting the exception in line 2 of this code, and still not sure what to do. Any help is appreciated. Thanks

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  • How to get database table header information into an CSV File.

    - by Rachel
    I am trying to connect to the database and get current state of a table and update that information into csv file, with below mentioned piece of code, am able to get data information into csv file but am not able to get header information from database table into csv file. So my questions is How can I get Database Table Header information into an CSV File ? $config['database'] = 'sakila'; $config['host'] = 'localhost'; $config['username'] = 'root'; $config['password'] = ''; $d = new PDO('mysql:dbname='.$config['database'].';host='.$config['host'], $config['username'], $config['password']); $query = "SELECT * FROM actor"; $stmt = $d->prepare($query); // Execute the statement $stmt->execute(); var_dump($stmt->fetch(PDO::FETCH_ASSOC)); $data = fopen('file.csv', 'w'); while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo "Hi"; // Export every row to a file fputcsv($data, $row); } Header information meaning: Vehicle Build Model car 2009 Toyota jeep 2007 Mahindra So header information for this would be Vehicle Build Model Any guidance would be highly appreciated.

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  • Unexpected $end in PHP file

    - by mattbd
    I'm working on a PHP contact form, but I can't get it to work. I get the following error in the Apache server log, running on an Ubuntu Server VM: PHP Parse error: syntax error, unexpected $end in /home/matthew/Sites/contactFormResponse.php on line 75, referer: http://192.168.1.4/contactForm.php From googling this error, it sounds like it's normally caused by either using the short PHP tag when the server's not set up to recognise them, or by having a block of code that isn't closed correctly. But as far as I can see that isn't the case here - as far as I can see it's all closed correctly. Here's the PHP code: <?php error_reporting(E_ALL); // Define variables to hold the name, email address and message, and import the information into the variables $name = $_POST['NameInput']; $email = $_POST['EmailAddress']; $telno = $_POST['ContactNumber']; $querytype = $_POST['QueryType']; $bookingstartdate = $_POST['BookingStartDay'] . $_POST['BookingStartMonth'] . $_POST['BookingStartYear']; $bookingenddate = $_POST['BookingEndDay'] . $_POST['BookingEndMonth'] . $_POST['BookingEndYear']; $message = $_POST['QueryText']; // Validate the inputs - send it if it's OK if(3 < strlen($name) && 3 < strlen($email)) { $email_message = <<< EMAIL Message from contact form at holidaychalet.co.uk Name: $name Email: $email Contact Number: $telno Query Type: $querytype Booking Start Date: $bookingstartdate Booking End Date: $bookingenddate The message: $message EMAIL; $headers = "cc:[email protected]\r\n"; if(mail('matthew@localhost','Contact form email', $email_message, $headers)) { echo "Thanks for completing the form! I'll be in touch shortly!"; } else { echo "Something went wrong - please use the back button and try again"; } } else { echo "You didn't complete the form fully enough! Please use go back using your web browser's back button"; } ?>

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  • drop down and post data to data base

    - by DAFFODIL
    This is a form which retrieves data from db and displays them in table. At the beginning of each row there will be a check box. If there are 10 rows fetched, I ii check 5 rows and insert them in to diff db but here when, I click drop down box data is getting in to db automatically,bcoz I use onchange event. Any alternative to prevent this to happen. Data should be inserted only when, I click submit button. Any help will be appreciated <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("form1", $con); error_reporting(E_ALL ^ E_NOTICE); $nam=$_REQUEST['select1']; $row=mysql_query("select * from inv where name='$nam'"); while($row1=mysql_fetch_array($row)) { $Name=$row1['Name']; $Address =$row1['Address']; $City=$row1['City']; $Pincode=$row1['Pincode']; $No=$row1['No']; $Date=$row1['Date']; $DCNo=$row1['DCNo']; $DcDate=$row1['DcDate']; $YourOrderNo=$row1['YourOrderNo']; $OrderDate=$row1['OrderDate']; $VendorCode=$row1['VendorCode']; $SNo=$row1['SNo']; $descofgoods=$row1['descofgoods']; $Qty=$row1['Qty']; $Rate=$row1['Rate']; $Amount=$row1['Amount']; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> <script type="text/javascript"> function ram(id) { var q=document.getElementById('qty_'+id).value; var r=document.getElementById('rate_'+id).value; document.getElementById('amt_'+id).value=q*r; } </script> </head> <body> <form id="form1" name="form1" method="post" action=""> <table width="1315" border="0"> <script type="text/javascript"> function g() { form1.submit(); } </script> <tr> <th>Name</th> <th align="left"><select name="select1" onchange="g();"> <option value="" selected="selected">select</option> <?php $row=mysql_query("select Name from inv "); while($row1=mysql_fetch_array($row)) { ?> <option value="<?php echo $row1['Name'];?>"><?php echo $row1['Name'];?></option> <?php } ?> </select></th> </tr> <tr> <th>Address</th> <th align="left"><textarea name="Address"><?php echo $Address;?></textarea></th> </tr> <tr> <th>City</th> <th align="left"><input type="text" name="City" value='<?php echo $City;?>' /></th> </tr> <tr> <th>Pincode</th> <th align="left"><input type="text" name="Pincode" value='<?php echo $Pincode;?>'></th> </tr> <tr> <th>No</th> <th align="left"><input type="text" name="No2" value='<?php echo $No;?>' readonly="" /></th> </tr> <tr> <th>Date</th> <th align="left"><input type="text" name="Date" value='<?php echo $Date;?>' /></th> </tr> <tr> <th>DCNo</th> <th align="left"><input type="text" name="DCNo" value='<?php echo $DCNo;?>' readonly="" /></th> </tr> <tr> <th>DcDate:</th> <th align="left"><input type="text" name="DcDate" value='<?php echo $DcDate;?>' /></th> </tr> <tr> <th>YourOrderNo</th> <th align="left"><input type="text" name="YourOrderNo" value='<?php echo $YourOrderNo;?>' readonly="" /></th> </tr> <tr> <th>OrderDate</th> <th align="left"><input type="text" name="OrderDate" value='<?php echo $OrderDate;?>' /></th> </tr> <tr> <th width="80">VendorCode</th> <th width="1225" align="left"><input type="text" name="VendorCode" value='<?php echo $VendorCode;?>' readonly="" /></th> </tr> </table> <table width="1313" border="0"> <tr> <td width="44">&nbsp;</td> <td width="71">SNO</td> <td width="527">DESCRIPTION</td> <td width="214">QUANTITY</td> <td width="214">RATE/UNIT</td> <td width="217">AMOUNT</td> </tr> <?php $i=1; $row=mysql_query("select * from inv where Name='$nam'"); while($row1=mysql_fetch_array($row)) { $SNo=$row1['SNo']; $descofgoods=$row1['descofgoods']; $Qty=$row1['Qty']; $Rate=$row1['Rate']; $Amount=$row1['Amount']; ?> <tr> <td><input type="checkbox" name="checkbox" value="checkbox" checked="checked"/></td> <td><input type="text" name="No[<?php echo $i?>]" value='<?php echo $SNo;?>' readonly=""/></td> <td><input type="text" name="descofgoods[<?php echo $i?>]" value='<?php echo $descofgoods;?>' /></td> <td><input type="text" name="qty[<?php echo $i?>]" maxlength="50000000" id="qty_<?PHP echo($i) ?>"/></td> <td><input type="text" name="Rate[<?php echo $i?>]" value='<?php echo $Rate;?>' id="rate_<?PHP echo($i) ?>" onclick="ram('<?PHP echo($i) ?>')";></td> <td><input type="text" name="Amount[<?php echo $i?>]" id="amt_<?PHP echo($i) ?>"/></td> </tr> <?php $i++;} ?> <tr> <td><input type="submit" value="submit" header("location:values to be brought for print page.php");/></td> </tr> </table> <label></label> </form> </body> </html> <?php /*error_reporting(E_ALL ^ E_NOTICE); $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("form1", $con); /*if(checked=checkbox) { mysql_query="INSERT INTO invo (Name, Address, City, Pincode, No, Date, DCNo, DcDate, YourOrderNo, OrderDate, VendorCode, SNo, descofgoods, Qty, Rate, Amount) VALUES ('$_POST[Name]','$_POST[Address]','$_POST[City]','$_POST[Pincode]','$_POST[No]','$_POST[Date]','$_POST[DCNo]','$_POST[DcDate]','$_POST[YourOrderNo]','$_POST[OrderDate]','$_POST[VendorCode]','$_POST[SNo]','$_POST[descofgoods]','$_POST[qty]','$_POST[Rate]','$_POST[Amount]')"; } else { header("location:values to be brought for print page.php"); }*/ header("ins.php"); ?>

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  • Netbeans with Oracle connection java.lang.ClassNotFoundException

    - by Attilah
    I use NetBeans 6.5 . When I try to run the following code : package com.afrikbrain.numeroteur16; import java.sql.Connection; import java.sql.DriverManager; import java.sql.SQLException; import java.util.logging.Level; import java.util.logging.Logger; /** * * @author */ public class NumeroteurTest { public NumeroteurTest() { } public void doIt() throws ClassNotFoundException{ try { Class.forName("oracle.jdbc.OracleDriver"); Connection connection = DriverManager.getConnection("jdbc:oracle:thin:@localhost:1521:XE","user","pwd"); String newNUMERO = new Numeroteur16("MATCLI", connection).numeroter(); System.out.println("NUMERO GENERE : "+newNUMERO.toString()); } catch (SQLException ex) { Logger.getLogger(NumeroteurTest.class.getName()).log(Level.SEVERE, null, ex); ex.printStackTrace(); } catch (NumException ex) { System.out.println(ex.getMessage()); ex.printStackTrace(); } } public static void main(String[] args){ try { new NumeroteurTest().doIt(); } catch (ClassNotFoundException ex) { Logger.getLogger(NumeroteurTest.class.getName()).log(Level.SEVERE, null, ex); System.out.println("Driver not found."); } } } when running it, I get this error : java.lang.ClassNotFoundException: oracle.jdbc.OracleDriver at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:307) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) at java.lang.ClassLoader.loadClass(ClassLoader.java:252) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:169) at com.afrikbrain.numeroteur16.NumeroteurTest.doIt(NumeroteurTest.java:27) at com.afrikbrain.numeroteur16.NumeroteurTest.main(NumeroteurTest.java:45) Driver not found. how do I solve this problem ?

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  • problem with running Servlet on Tomcat: InvocationTargetException

    - by Fahim
    Hi, I am new to Tomcat, and trying to run a simple HelloWorld servlet. I have installed Tomcat 6, and Jdk1.6 on Mandriva Linux, set CLASSPATH and JAVA_HOME. I have the following files and directories: $CATALINA_HOME/webapps/MyApp/WEB_INF/classes/TestServlet.class $CATALINA_HOME/webapps/MyApp/WEB_INF/web.xml My web.xml file contains the following: http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5" <description>ZibJana Localization</description> <display-name>ZibJana Localization</display-name> <!-- Define the servlets for this application--> <servlet> <servlet-name>ZibJana</servlet-name> <servlet-class>TestServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>ZibJana</servlet-name> <url-pattern>*</url-pattern> </servlet-mapping> But when I try to invoke my servlet with url http://localhost:8080/MyApp, tomcat fails to launch launch the servlet. I checked in the $CATALINA_HOME/logs/catalina.out log-file and found the following error, which occurs every time I start tomcat service. INFO: Deploying web application directory MyApp 16-Mar-2010 12:05:38 AM org.apache.tomcat.util.digester.Digester endElement SEVERE: End event threw exception java.lang.reflect.InvocationTargetException at sun.reflect.GeneratedMethodAccessor18.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) Please let me know where my mistake is. Thanks in advance.

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  • How to tell when a Socket has been disconnected

    - by BowserKingKoopa
    On the client side I need to know when/if my socket connection has been broken. However the Socket.Connected property always returns true, even after the server side has been disconnected and I've tried sending data through it. Can anyone help me figure out what's going on here. I need to know when a socket has been disconnected. Socket serverSocket = null; TcpListener listener = new TcpListener(1530); listener.Start(); listener.BeginAcceptSocket(new AsyncCallback(delegate(IAsyncResult result) { Debug.WriteLine("ACCEPTING SOCKET CONNECTION"); TcpListener currentListener = (TcpListener)result.AsyncState; serverSocket = currentListener.EndAcceptSocket(result); }), listener); Socket clientSocket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); Debug.WriteLine("client socket connected: " + clientSocket.Connected);//should be FALSE, and it is clientSocket.Connect("localhost", 1530); Debug.WriteLine("client socket connected: " + clientSocket.Connected);//should be TRUE, and it is Thread.Sleep(1000); serverSocket.Close();//closing the server socket here Thread.Sleep(1000); clientSocket.Send(new byte[0]);//sending data should cause the socket to update its Connected property. Debug.WriteLine("client socket connected: " + clientSocket.Connected);//should be FALSE, but its always TRUE

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  • ASP.Net MVC, JS injection and System.ArgumentException - Illegal Characters in path

    - by Mose
    Hi, In my ASP.Net MVC application, I use custom error handling. I want to perform custom actions for each error case I meet in my application. So I override Application_Error, get the Server.GetLastError(); and do my business depending on the exception, the current user, the current URL (the application runs on many domains), the user IP, and many others. Obviousely, the application is often the target of hackers. In almost all the case it's not a problem to detect and manage it, but for some JS URL attacks, my error handling does not perform what I want it to do. Ex (from logs) : http://localhost:1809/Scripts/]||!o.support.htmlSerialize&&[1 When I got such an URL, an exception is raised when accessing the ConnectionStrings section in the web.config, and I can't even redirect to another URL. It leads to a "System.ArgumentException - Illegal Characters in path, etc." The screenshot below shows the problem : http://screencast.com/t/Y2I1YWU4 An obvious solution is to write a HTTP module to filter the urls before they reach my application, but I'd like to avoid it because : I like having the whole security being managed in one place (in the Application_Error() method) In the module I cannot access the whole data I have in the application itself (application specific data I don't want to debate here) Questions : Did you meet this problem ? How did you manage it ? Thanks for you suggestions, Mose

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  • php sessions in database only writing part of information to the table...

    - by Ronedog
    I'm having difficulty figuring out what's going on here, hoping some one can help me out. I have been using php, mysql storing my session information in the database. The app is only running on localhost, vista. In the php.ini file I commented out the "session.save_handler = files" line and am using a php class to handle the session writes/reads, etc. My login process is this: Submit login credentials via login.php. login.php calls loginprocess.php. loginprocess.php verifies user, and if valid starts a new session and adds data to the session vars, then it redirects to index.php. Here's the problem. the loginprocess.php page has a bunch of session vars that get set like $_SESSION['account_id'] = $account_id; etc. but when I go to index.php and do a var_dump($_SESSION) it just says "array() empty". However, if I do a var_dump($_SESSION) in loginprocess.php, just before the redirection line header("Location: ../index.php"); then it shows all the data in the session variable. If I look in the database where the session information is stored, there is data in the session_id field, created_ts field, and expires field, but the session_data field has nothing inside of it and in the past this is the field where all my session data was stored. How could I be able to var_dump the session in loginprocess.php, but the data not exist in the db table, is it using some kind of caching? I cleared my cookies, etc...but no change. Why is the session_id, being written to the table, but the actual session data is not? Any ideas are appreciated. Thanks.

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  • Postback not working with ASP.NET Routing (Validation of viewstate MAC failed)

    - by Robert
    Hi. I'm using the ASP.NET 3.5 SP1 System.Web.Routing with classic WebForms, as described in http://chriscavanagh.wordpress.com/2008/04/25/systemwebrouting-with-webforms-sample/ All works fine, I have custom SEO urls and even the postback works. But there is a case where the postback always fails and I get a: Validation of viewstate MAC failed. If this application is hosted by a Web Farm or cluster, ensure that configuration specifies the same validationKey and validation algorithm. AutoGenerate cannot be used in a cluster. Here is the scenario to reproduce the error: Create a standard webform mypage.aspx with a button Create a Route that maps "a/b/{id}" to "~/mypage.aspx" When you execute the site, you can navigate http://localhost:XXXX/a/b/something the page works. But when you press the button you get the error. The error doen't happen when the Route is just "a/{id}". It seems to be related to the number of sub-paths in the url. If there are at least 2 sub-paths the viewstate validation fails. You get the error even with EnableViewStateMac="false". Any ideas? Is it a bug? Thanks

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  • SQL Server 2005 Reporting Services (x64) on Windows 2K8 -> CleanCurrentUserName() not found

    - by Steven Pardo
    I have installed SQL Server 2005 three times now on the same box. I cleaned up registry settings, files, you name it. All along I have been trying to install SQL Server 2005 Database and Reporting Services (x64) on a Windows 2008 Server. I have also applied the SP3 patch. Installing and Restarting the Server at every point. I have installed multiple instances (SQLDEV64, SQLQA64, SQLSTAGE64) of the Database and Reporting Services. I started to go through the Reporting Services Configuration manager, installing the Reporting Database along with setting up IIS. When I go test the website I get the following and there lies my question. How can I get around this error? http://localhost/reportserver Reporting Services Error -------------------------------------------------------------------------------- An internal error occurred on the report server. See the error log for more details. (rsInternalError) Method not found: 'Void Microsoft.ReportingServices.Diagnostics.UserUtil.CleanCurrentUserName()'. -------------------------------------------------------------------------------- SQL Server Reporting Services Any help would be greatly appreciated.

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  • JQuery object expected error when accessing page via url routing.

    - by Andy Evans
    In my global.asax I have url routing setup like below: routes.MapPageRoute("User Logon", "{Vendor}/Logon", "~/Logon.aspx"); In the logon.aspx page, I have a script that "stylizes" the logon button: <link href="jquery/css/flick/jquery-ui-1.8.1.custom.css" rel="stylesheet" type="text/css" /> <link href="images/style.css" rel="stylesheet" type="text/css" /> <script src="jquery/js/jquery-1.4.2.min.js" type="text/javascript"></script> <script src="jquery/js/jquery-ui-1.8.1.custom.min.js" type="text/javascript"></script> <script type="text/javascript"> $(document).ready(function () { $('#<%= ButtonLogon.ClientID %>').button(); }); </script> When I access the page us a url (in debug mode) http://localhost/logon.aspx?v=1 the page loads correctly and the jquery button command loads correctly. But then I access the page using the new url route, I get this error. Microsoft JScript runtime error: Object expected Anyone have an idea why this occurs? Thanks.

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  • Copying contents of a MySQL table to a table in another (local) database

    - by Philip Eve
    I have two MySQL databases for my site - one is for a production environment and the other, much smaller, is for a testing/development environment. Both have identical schemas (except when I am testing something I intend to change, of course). A small number of the tables are for internationalisation purposes: TransLanguage - non-English languages TransModule - modules (bundles of phrases for translation, that can be loaded individually by PHP scripts) TransPhrase - individual phrases, in English, for potential translation TranslatedPhrase - translations of phrases that are submitted by volunteers ChosenTranslatedPhrase - screened translations of phrases. The volunteers who do translation are all working on the production site, as they are regular users. I wanted to create a stored procedure that could be used to synchronise the contents of four of these tables - TransLanguage, TransModule, TransPhrase and ChosenTranslatedPhrase - from the production database to the testing database, so as to keep the test environment up-to-date and prevent "unknown phrase" errors from being in the way while testing. My first effort was to create the following procedure in the test database: CREATE PROCEDURE `SynchroniseTranslations` () LANGUAGE SQL NOT DETERMINISTIC MODIFIES SQL DATA SQL SECURITY DEFINER BEGIN DELETE FROM `TransLanguage`; DELETE FROM `TransModule`; INSERT INTO `TransLanguage` SELECT * FROM `PRODUCTION_DB`.`TransLanguage`; INSERT INTO `TransModule` SELECT * FROM `PRODUCTION_DB`.`TransModule`; INSERT INTO `TransPhrase` SELECT * FROM `PRODUCTION_DB`.`TransPhrase`; INSERT INTO `ChosenTranslatedPhrase` SELECT * FROM `PRODUCTION_DB`.`ChosenTranslatedPhrase`; END When I try to run this, I get an error message: "SELECT command denied to user 'username'@'localhost' for table 'TransLanguage'". I also tried to create the procedure to work the other way around (that is, to exist as part of the data dictionary for the production database rather than the test database). If I do it that, way, I get an identical message except it tells me I'm denied the DELETE command rather than SELECT. I have made sure that my user has INSERT, DELETE, SELECT, UPDATE and CREATE ROUTINE privileges on both databases. However, it seems as though MySQL is reluctant to let this user exercise its privileges on both databases at the same time. How come, and is there a way around this?

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  • [grails] setting cookies when render type is "contentType: text/json"

    - by Robin Jamieson
    Is it possible to set cookies on response when the return render type is set as json? I can set cookies on the response object when returning with a standard render type and later on, I'm able to get it back on the subsequent request. However, if I were to set the cookies while rendering the return values as json, I can't seem to get back the cookie on the next request object. What's happening here? These two actions work as expected with 'basicForm' performing a regular form post to the action, 'withRegularSubmit', when the user clicks submit. // first action set the cookie and second action yields the originally set cookie def regularAction = { // using cookie plugin response.setCookie("username-regular", "regularCookieUser123",604800); return render(view: "basicForm"); } // called by form post def withRegularSubmit = { def myCookie = request.getCookie("username-regular"); // returns the value 'regularCookieUser123' return render(view: "resultView"); } When I switch to setting the cookie just before returning from the response with json, I don't get the cookie back with the post. The request starts by getting an html document that contains a form and when doc load event is fired, the following request is invoked via javascript with jQuery like this: var someUrl = "http://localhost/jsonAction"; $.get(someUrl, function(jsonData) { // do some work with javascript} The controller work: // this action is called initially and returns an html doc with a form. def loadJsonForm = { return render(view: "jsonForm"); } // called via javascript when the document load event is fired def jsonAction = { response.setCookie("username-json", "jsonCookieUser456",604800); // using cookie plugin return render(contentType:'text/json') { 'pair'('myKey': "someValue") }; } // called by form post def withJsonSubmit = { def myCookie = request.getCookie("username-json"); // got null value, expecting: jsonCookieUser456 return render(view: "resultView"); } The data is returned to the server as a result of the user pressing the 'submit' button and not through a script. Prior to the submit of both 'withRegularSubmit' and 'withJsonSubmit', I see the cookies stored in the browser (Firefox) so I know they reached the client.

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