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  • php + MySQL editing table data.

    - by Jacksta
    This question is relating to 2 php scripts. The first script is called pick_modcontact.php where I choose a contact (from a contact book like phone book), then posts to the script show_modcontact.php When I click the submit button on the form on pick.modcontact.php. As a result of submitting the form I am then taken to show_modcontact.php. As the variables are not present the user is directed back to pick_modcontact.php I can not work out how to correct the code so that it will show the results of the script show_modcontact.php This script shows all contacts in a database which is an "address book" this part works fine. please see below. Name:pick_modcontact.php if ($_SESSION['valid'] != "yes") { header( "Location: contact_menu.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin", "user") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT id, f_name, l_name FROM $table_name ORDER BY f_name"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = @mysql_num_rows($result); if ($num < 1) { $display_block = "<p><em>Sorry No Results!</em></p>"; } else { while ($row = mysql_fetch_array($result)) { $id = $row['id']; $f_name = $row['f_name']; $l_name = $row['l_name']; $option_block .= "<option value\"$id\">$f_name, $l_name</option>"; } $display_block = "<form method=\"POST\" action=\"show_modcontact.php\"> <p><strong>Contact:</strong> <select name=\"id\">$option_block</select> <input type=\"submit\" name=\"submit\" value=\"Select This Contact\"></p> </form>"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <h1>My Contact Management System</h1> <h2><em>Modify a Contact</em></h2> <p>Select a contact from the list below, to modify the contact's record.</p> <? echo "$display_block"; ?> <br> <p><a href="contact_menu.php">Return to Main Menu</a></p> </body> </html> This script is for modifying the contact: named show_modcontact.php <?php if (!$_POST['id']) { header( "Location: pick_modcontact.php"); exit; } else { session_start(); } if ($_SESSION['valid'] != "yes") { header( "Location: pick_modcontact.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT f_name, l_name, address1, address2, address3, postcode, prim_tel, sec_tel, email, birthday FROM $table_name WHERE id = '" . $_POST['id'] . "'"; $result = @mysql_query($sql, $connection) or die(mysql_error()); while ($row = mysql_fetch_array($result)) { $f_name = $row['f_name']; $l_name = $row['l_name']; $address1 = $row['address1']; $address2 = $row['address2']; $address3 = $row['address3']; $country = $row['country']; $prim_tel = $row['prim_tel']; $sec_tel = $row['sec_tel']; $email = $row['email']; $birthday = $row['birthday']; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <form action="do_modcontact.php" method="post"> <input type="text" name="id" value="<? echo $_POST['id']; ?>" /> <table cellpadding="5" cellspacing="3"> <tr> <th>Name & Address Information</th> <th> Other Contact / Personal Information</th> </tr> <tr> <td align="top"> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name"; ?>" size="35" maxlength="75" /></p> <p><strong>Last Name:</strong><br /> <input type="text" name="l_name" value="<? echo "$l_name"; ?>" size="35" maxlength="75" /></p> <p><strong>Address1:</strong><br /> <input type="text" name="f_name" value="<? echo "$address1"; ?>" size="35" maxlength="75" /></p> <p><strong>Address2:</strong><br /> <input type="text" name="f_name" value="<? echo "$address2"; ?>" size="35" maxlength="75" /></p> <p><strong>Address3:</strong><br /> <input type="text" name="f_name" value="<? echo "$address3"; ?>" size="35" maxlength="75" /> </p> <p><strong>Postcode:</strong><br /> <input type="text" name="f_name" value="<? echo "$postcode"; ?>" size="35" maxlength="75" /></p> <p><strong>Country:</strong><br /> <input type="text" name="f_name" value="<? echo "$country"; ?>" size="35" maxlength="75" /> </p> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name"; ?>" size="35" maxlength="75" /></p> </td> <td align="top"> <p><strong>Prim Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$prim_tel"; ?>" size="35" maxlength="75" /></p> <p><strong>Sec Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$sec_tel"; ?>" size="35" maxlength="75" /></p> <p><strong>Email:</strong><br /> <input type="text" name="f_name" value="<? echo "$email;" ?>" size="35" maxlength="75" /> </p> <p><strong>Birthday:</strong><br /> <input type="text" name="f_name" value="<? echo "$birthday"; ?>" size="35" maxlength="75" /> </p> </td> </tr> <tr> <td align="center"> <p><input type="submit" name="submit" value="Update Contact" /></p> <br /> <p><a href="contact_menu.php">Retuen To Menu</a></p> </td> </tr> </table> </form> </body> </html> note for site admin, I am re posting this question with the hope of someone else reading over it. older questions seem to go dead after a while.

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  • How to check what goes wrong in $view->render with Zend Framework?

    - by koko
    Hi, I'm working on a CMS with Widgets. On my localhost the followong code works perfect, but I have no idea what I'm doing wrong ... The neede files exist, I think and I get no error message. As far as I can see, the error occurs in the one before last line of code and I get no error message. $view = new Zend_View(); $view->setScriptPath(APPLICATION_PATH . '/../public/websites/' . My_Cookie::get('alpha_key') . '/views'); $view->headScript()->appendFile($vervang['conf']['jqueryJS']); $view->headLink()->appendStylesheet($vervang['conf']['jqueryCSS']); $view->class = $pluginExtraFinal; $view->vervang = $vervang['data']; $view->moduleName = $moduleName; $parsed = $view->render($vervang['conf']['viewFile']); $inhoud = str_replace($plugin, $parsed, $inhoud); Is there a way to troubleshoot this code? How can I get an error message? What can be wrong? Any suggestions please?

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  • Apache gettext windows does not work/translate

    - by Prashant Kandathil
    I am new to gettext. Here is my setup: /Apache 2.2 PHP 5.3.6 Windows 7/ I have following code in the Apache/htdocs/test/index.php <?php $language = 'de_DE'; $translatefile = 'messages'; setlocale(LC_ALL, $language); putenv("LANG=".$language); bindtextdomain($translatefile, 'C:/locale'); textdomain($translatefile); echo gettext("Hello World!"); ?> I used PoEdit to generate the necessary translations under locale/de_DE/LC_MESSAGES/messsages.po & messages.mo The charset I used was UTF-8 When I visit http://localhost/test, the result is Hello World! when it should be Hall Welt! As a test, I opened command prompt and navigated to the test folder. Then I typed in php index.php The result that appeared in the console was Hall Welt! I am not sure why it is not working with Apache.

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  • event listener says NetStream.Play.Start but I see no video

    - by Curtis
    I'm trying to test out the Adobe Media Server, and I'm following some tutorials in order to stream a video. I have a NetConnection which successfully connects to the application on the server, then I have the code below. It looks like it's supposed to play a video, but it doesn't. It creates the video object as a black square in the top left corner, and the event.info.code says NetStream.Play.Start, but I don't see the video playing. case "NetConnection.Connect.Success": var v:Video = new Video(); v.width=200; v.height=200; v.x=0; v.y=0; v.visible=true; v.opaqueBackground=false; stage.addChild(v); var ns:NetStream = new NetStream(nc); ns.addEventListener(NetStatusEvent.NET_STATUS,netStatusHandler); v.attachNetStream(ns); ns.play("mp4:polymorphics.f4v"); I can also try ns.play("rtmp://localhost/vod/mp4:tests/polymorphics.f4v"); but that gives me a Stream Not Found error The lines that begin with "ns" means that they're generated by my NetStream listener, as opposed to my NetConnection listener. Connecting... connected is: true event.info.level: status event.info.code: NetConnection.Connect.Success onReply recieved value: Hello, World! ns connected is: true ns event.info.level: status ns event.info.code: NetStream.Play.Reset ns connected is: true ns event.info.level: status ns event.info.code: NetStream.Play.Start

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  • select option clears when page loads in php

    - by user79685
    Hey guys, the scenario is this: see select below <form name="limit"> <select name="limiter" onChange="limit(this.value)"> <option selected="selected">&nbsp;</option> <option value="5">5</option> <option value="10">10</option> <option value="15">15</option> </select> </form> I want whenever any option is selected for 3 things to happen: 1.) js limit() function is called which all it does its takes current url, adds new query parameter 'limit' with the user selected value eg: http://localhost/blahblah/apps/category.php?pg=1&catId=3021&limit=5 (this will cause the category.php page to be hit and # of product displayed limited to the value selected by user) 2.)Once the url is hit, it reloads but i DONT want the value selected to reset back to the default (which it currently does). I want it to reflect the users selection after page reload. 3.) Also, when i move to the next page (pagination), i would like the state to be carried ova to the next page (ie. remembering the user selection).

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  • Packet fragmentation when sending data via SSLStream

    - by Ive
    When using an SSLStream to send a 'large' chunk of data (1 meg) to a (already authenticated) client, the packet fragmentation / dissasembly I'm seeing is FAR greater than when using a normal NetworkStream. Using an async read on the client (i.e. BeginRead()), the ReadCallback is repeatedly called with exactly the same size chunk of data up until the final packet (the remainder of the data). With the data I'm sending (it's a zip file), the segments happen to be 16363 bytes long. Note: My receive buffer is much bigger than this and changing it's size has no effect I understand that SSL encrypts data in chunks no bigger than 18Kb, but since SSL sits on top of TCP, I wouldn't think that the number of SSL chunks would have any relevance to the TCP packet fragmentation? Essentially, the data is taking about 20 times longer to be fully read by the client than with a standard NetworkStream (both on localhost!) What am I missing? EDIT: I'm beginning to suspect that the receive (or send) buffer size of an SSLStream is limited. Even if I use synchronous reads (i.e. SSLStream.Read()), no more data ever becomes available, regardless of how long I wait before attempting to read. This would be the same behavior as if I were to limit the receive buffer to 16363 bytes. Setting the Underlying NetworkStream's SendBufferSize (on the server), and ReceiveBufferSize (on the client) has no effect.

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  • Has anyone setup tomcat to run virtual hosts using mod_jk

    - by Adam
    I work in OSX primarily with mostly PHP. Normally I work locally using MAMP and virtual hosts setup in my httpd.conf so that I can point a browser to http://some-project and have as many projects as I need setup. We have a project coming up where we need to serve JSP pages and I would like to set up my local apache server to serve only JSP files to Tomcat and everything else to MAMP using the same virtual hosts setup in: ~/applications/MAMP/conf/apache/httpd.conf So far I have: Successfully installed Tomcat Placed mod_jd.so in ~/applications/MAMP/Library/modules/mod_jk.so Added the module by placing: LoadModule jk_module modules/mod_jk.so in ~/applications/MAMP/conf/apache/httpd.conf Created /Library/Tomcat/Home/conf/jk/workers.properties and added the following lines: workers.tomcat_home=/Library/Tomcat workers.java_home=/System/Library/Frameworks/JavaVM.framework/Versions/1.5.0/Home ps=/ worker.list=ajp12, ajp13 worker.ajp13.port=8009 worker.ajp13.host=localhost worker.ajp12.type=ajp13 worker.ajp13.mount=/*.jsp added the following lines: JkWorkersFile /Library/Tomcat/Home/conf/workers.properties JkLogFile /Library/Tomcat/Home/logs/mod_jk.log JkLogLevel debug to ~/applications/MAMP/conf/apache/httpd.conf I cannot start my MAMP however when these last two lines are present in my httpd.conf. Does anyone work like this? Any tips? Any clear ideas of what I'm doing wrong?

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  • log4j rootLogger seems to inherit log level of other logger. Why?

    - by AndrewR
    I've got a log4J setup in which the root logger is supposed to log ERROR level messages and above to the console and another logger logs everything to syslog. log4j.properties is: # Root logger option log4j.rootLogger=ERROR,R log4j.appender.R=org.apache.log4j.ConsoleAppender log4j.appender.R.layout=org.apache.log4j.PatternLayout log4j.appender.R.layout.ConversionPattern=%d %p %t %c - %m%n log4j.logger.SGSearch=DEBUG,SGSearch log4j.appender.SGSearch=org.apache.log4j.net.SyslogAppender log4j.appender.SGSearch.SyslogHost=localhost log4j.appender.SGSearch.Facility=LOCAL6 log4j.appender.SGSearch.layout=org.apache.log4j.PatternLayout log4j.appender.SGSearch.layout.ConversionPattern=[%-5p] %m%n In code I do private static final Logger logger = Logger.getLogger("SGSearch"); . . . logger.info("Commencing snapshot index [" + args[1] + " -> " + args[2] + "]"); What is happening is that I get the console logging for all logging levels. What seems to be happening is that the level for SGSearch overrides the level set for the root logger somehow. I can't figure it out. I have confirmed that Log4J is reading then properties file I think it is, and no other (via the -Dlog4j.debug option)

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  • How to properly set JavaMail timeout setting

    - by user286149
    I am using JavaMail to connect to a POP3 server. Further, I set the following properties, so that JavaMail won't wait to long if an email server doesn't respond: props.setProperty("mail.pop3.connectionpooltimeout", "3000"); props.setProperty("mail.pop3.connectiontimeout", "3000"); props.setProperty("mail.pop3.timeout", "3000"); However, in some cases the timeout works properly but sometimes JavaMail freezes for minutes(!) with the following debug message: DEBUG POP3: connecting to host "pop3.yahoo.com", port 110, isSSL false Changing ports or protocols (SSL, TLS..) has no effect. I assume that the host simply doesn't exist. For example, if I poll pop3.yahoo.com instead of pop.mail.yahoo.com (which would be the right host name), I have to wait very long til a timeout exception occurs. After several minutes, I get the following exception and the application continues to run: java.net.ConnectException: Operation timed out pop3.yahoo.com seems to exist but won't respond: localhost:~ me$ ping pop3.yahoo.com PING pop3.yahoo.com (206.190.46.10): 56 data bytes Request timeout for icmp_seq 0 Request timeout for icmp_seq 1 Request timeout for icmp_seq 2 Request timeout for icmp_seq 3 ^C You might be asking why I use pop3.yahoo.com instead of pop.mail.yahoo.com. Well, I simply wanted to test what happens if the user of my application inserts a wrong host name. I believe that this issue is related to this report http://www.opensubscriber.com/message/[email protected]/180946.html where the poster claims that the problem occurs if the email server closes the connection. JavaMail then seems to wait very long (don't know why). Since the issue wasn't resolved in the link I posted: Does somebody know how to fix or at least debug this? Any help would be really appreciated!

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  • asp.net on linux/mono broken? weird load then 404/resource error

    - by acidzombie24
    I am testing out my asp.net on mono's VM Ware Image using opensuse From the home page it says Trying out your own code You can test your own applications by connecting with the file manager on this machine to the machine hosting your application, and copying over the directory containing application and its associated files. To test your ASP.NET applications, copy your code to a new directory in /srv/www/htdocs , then visit the following url: http://localhost/directoryname/page.aspx Where directoryname is the directory where you deployed your application, and page.aspx is the initial page for your software, typically Default.aspx. Mirror: http://tortillaflatscafe.com/ I saw my app had errors. After i restarted the VM i can no longer run my app. Instead of getting error messages or anything i get this error instead. Server Error in '/myfoldername' Application The resource cannot be found. Description: HTTP 404. The resource you are looking for (or one of its dependencies) could have been removed, had its name changed, or is temporarily unavailable. Please review the following URL and make sure that it is spelled correctly. Requested URL: /Default.aspx I tried /default.aspx, using sudo to set permissions to 777 recursively, restarting apache via terminal i could not get this error to go away. How do i fix this?

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  • Update graph in real time from server

    - by user1869421
    I'm trying to update a graph with received data, so that the height of the bars increase as more data is received from the server via a websocket. But my code doesn't render a graph in the browser and plot the data points. I cannot see anything wrong with the code. I really need some help here please. ws = new WebSocket("ws://localhost:8888/dh"); var useData = [] //var chart; var chart = d3.select("body") .append("svg:svg") .attr("class", "chart") .attr("width", 420) .attr("height", 200); ws.onmessage = function(evt) { var distances = JSON.parse(evt.data); data = distances.miles; console.log(data); if(useData.length <= 10){ useData.push(data) } else { var draw = function(data){ // Set the width relative to max data value var x = d3.scale.linear() .domain([0, d3.max(useData)]) .range([0, 420]); var y = d3.scale.ordinal() .domain(useData) .rangeBands([0, 120]); var rect = chart.selectAll("rect") .data(useData) // enter rect rect.enter().append("svg:rect") .attr("y", y) .attr("width", x) .attr("height", y.rangeBand()); // update rect rect .attr("y", y) .attr("width", x) .attr("height", y.rangeBand()); var text = chart.selectAll("text") .data(useData) // enter text text.enter().append("svg:text") .attr("x", x) .attr("y", function (d) { return y(d) + y.rangeBand() / 2; }) .attr("dx", -3) // padding-right .attr("dy", ".35em") // vertical-align: middle .attr("text-anchor", "end") // text-align: right .text(String); // update text text .data(useData) .attr("x", x) .text(String); } useData.length = 0; } } Thanks

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  • Why does Rails screw up timezones when I am editing a resource?

    - by DJTripleThreat
    Steps to produce this: prompt>rails test_app prompt>cd test_app prompt>script/generate scaffold date_test my_date:datetime prompt>rake db:migrate now edit your app/views/date_tests/edit.html.erb: <h1>Editing date_test</h1> <% form_for(@date_test) do |f| %> <%= f.error_messages %> <p> RIGHT!<br/> <%= text_field_tag @date_test, f.object.my_date %> </p> <p> WRONG!<br /> <%= f.text_field :my_date %> </p> <p> <%= f.submit 'Update' %> </p> <% end %> <%= link_to 'Show', @date_test %> | <%= link_to 'Back', date_tests_path %> now edit your config/environment.rb: #add this config.time_zone = 'Central Time (US & Canada)' This recreates the problem I am having in my actual app. The problem with my app is that I'm storing a date in a hidden field and rendering a "user friendly" version. Creating a resource works fine but as soon as I try to edit it the time changes (it adds the difference between my current time zone configuration and UTC). go to http://localhost:3000/date_tests/new and save the time then go to reedit it and you will have two different representations of the date/time one which will save incorrectly and the other that will.

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  • Secure Copy File from remote server via scp and os module in Python

    - by user1063572
    I'm pretty new to Python and programming. I'm trying to copy a file between two computers via a python script. However the code os.system("ssh " + hostname + " scp " + filepath + " " + user + "@" + localhost + ":" cwd) won't work. I think it needs a password, as descriped in How do I copy a file to a remote server in python using scp or ssh?. I didn't get any error logs, the file just won't show in my current working directory. However every other command with os.system("ssh " + hostname + "command") or os.popen("ssh " + hostname + "command") does work. - command = e.g. ls When I try ssh hostname scp file user@local:directory in the commandline it works without entering a password. I tried to combine os.popen commands with getpass and pxssh module to establish a ssh connection to the remote server and use it to send commands directly (I only tested it for an easy command): import pxssh import getpass ssh = pxssh.pxssh() ssh.force_password = True hostname = raw_input("Hostname: ") user = raw_input("Username: ") password = getpass.getpass("Password: ") ssh.login(hostname, user, password) test = os.popen("hostname") print test But I'm not able to put commands through to the remote server (print test shows, that hostname = local and not the remote server), however I'm sure, the conection is established. I thought it would be easier to establish a connection than always use "ssh " + hostname in the bash commands. I also tried some of the workarounds in How do I copy a file to a remote server in python using scp or ssh?, but I must admit due to lack of expirience I didn't get them to work. Thanks a lot for helping me.

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  • User input in Perl with IO::Socket

    - by David
    I am trying to make a perl program which allows a user to input the host and the port number of a foreign host to connect to using IO::Socket. It allows me to run the program and input a host and a port but it never connects and says "Could not connect to [host] at c:\users\USER\Documents\code\perl\sql.pl line 18, line 2." What am i doing wrong with this code shown below? And also, how can i have input validation on my host, which can either be a host name or an ip address? Thanks a bunch! Code Below use IO::Socket print "Host to connect to: "; chomp ($host = <STDIN>); print "Port to connect with: "; chomp ($port = <STDIN>); while(($port > 65535) || ($port <= 0)){ print "Port to connect with [Port > 0 < 65535] : "; chomp ($port = <STDIN>); } print "\nConnecting to host $host on port $port\n"; $socket = new IO::Socket::INET ( LocalHost => '$host', LocalPort => '$port', Proto => 'tcp', Listen => 5, Reuse => 1 ); die "Could not connect to $host";

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  • VS 2008 debugger: How does it decide what Cassini port to run a web service under?

    - by BDW
    I have a VS 2008 solution that includes a web site and a web service. I'm developing both at once, and it's helpful to be able to debug from one into the other. It occasionally can't find the web service. If I look in the web.config, I find the port number it's looking at is not the port number it auto-runs the service in when I use the debugger. For example, the web.config reference says something like: add key="mynamespace.mywebservice" value="http://localhost:55765/mywebservice.asmx" When I hover over the Cassini port icon, I find that the web service is running in port 55382 (or some other non-55765 port). No wonder it can't find it. Is there a way to enforce that the port number it runs under is the one specified in the web config? And if it's not using the web config port number to figure out where to run it... where does it decide? I know in VS2005, there was a way to specify the port number to use when debugging, but I can't find that anywhere in the web service project in VS 2008. This is really going to cause problems as more developers come on to this project - how can I fix it? Deleting and re-adding the web services to the project fixes it, but I'd literally have to do it a couple times a day, not an ideal solution.

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  • Creating a RESTful service in CakePHP

    - by NathanGaskin
    I'm attempting to create a RESTful service in CakePHP but I've hit a bit of a brick wall. I've enabled the default RESTful routing using Router::mapResources('users') and Router::parseExtensions(). This works well if I make a GET request, and returns some nicely formatted XML. So far so good. The problem is if I want to make a POST or PUT request. CakePHP doesn't seem to be able to read the data from the request. At the moment my add(), edit() and delete() actions don't contain any logic, they're simply setting $this-data to the view. I'm testing with the following cURL command: curl -v -d "<user><username>blahblah</username><password>blahblah</password>" http://localhost/users.xml --header 'content-type: text/xml' Which only returns a 404 header. If I remove the --header parameter then it returns the view but no data is set. It feels like I'm missing something obvious here. Any ideas?

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  • ASP can't connect to SQL Server database

    - by birdus
    I'm trying to get a classic ASP application to connect to a local SQL Server 2008 database. The app and database were built by someone else. I'm just trying to get them installed and running on my machine (Windows 7). I'm getting the following error when when the ASP app tries to connect to the database: Could not connect to database: Error Number: -2147467259 Error Message: [ConnectionOpen (Connect()).] does not exist or access denied. I don't see any messages in the Windows Event Viewer. I'm looking at: Event Viewer-Windows Logs-Application. It's a fresh database install using a simple restore. The SQL Server install uses the default instance. SQL Server and Windows authentication are both allowed. I left the existing connection string (in the ASP code) in tact and just tried adding that to my SQL Server installation. Here's the connection string: strConn = "PROVIDER=SQLOLEDB;SERVER=localhost;UID=TheUser;PWD=ThePassword;DATABASE=TheDatabase;" To add that user to SQL Server, I went to Security/Logins in SSMS and added the user and the password. I selected the database in question as the Default database. I thought that might do the trick, but it didn't. Then, I went into TheDatabase, then went into Security there. I added a new user there, referencing the new user I had already added in server Security. Under Owned Schemas, I clicked db_owner and under Role Members I checked db_accessadmin and db_owner. None of this gave the ASP application access to the database. The sid values match in sys.database_principals and sys.server_principals for the login in question. I am able to login to SSMS using this login. The app needs to execute selects against the database like this: oConn.Execute('select * from someTable') I'm not a DBA and am sort of grasping at straws here. How do I get this thing connected? Thanks, Jay

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  • What could cause xmlrpclib.ResponseError: ResponseError() ?

    - by Tom
    Hi, I am experimenting with XML-RPC. I have the following server script (python): from SimpleXMLRPCServer import SimpleXMLRPCServer server = SimpleXMLRPCServer(('localhost', 9000)) def return_input(someinput): return someinput server.register_function(return_input) try: print 'ctrl-c to stop server' server.serve_forever() except KeyboardInterrupt: print 'stopping' and the following client script: import xmlrpclib server = xmlrpclib.ServerProxy('http://www.example.com/pathto/xmlrpcTester2.py') print server.return_input('some input') I have tested this locally and it works fine. All it does it spit out the input fron the client script, which is right. However, when I try to do it on a remote server I get the following error: Traceback (most recent call last): File "client.py", line 4, in <module> print server.return_input('some input') File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 1199, in __call__ return self.__send(self.__name, args) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 1489, in __request verbose=self.__verbose File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 1253, in request return self._parse_response(h.getfile(), sock) File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 1392, in _parse_response return u.close() File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/xmlrpclib.py", line 836, in close raise ResponseError() xmlrpclib.ResponseError: ResponseError() Any ideas what could cause this? Thanks in advance for your help.

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  • Undefined return value

    - by yynneejj
    what's wrong to my code..where my return value found undefind... var so; var imgid_callback1; const DIV_ID = 'locationsample'; function setup(){ try { so = device.getServiceObject("Service.Location", "ILocation"); } catch (e) { alert('<setup> ' +e); } } function getLocation(imgId) { var updateoptions = new Object(); // Setting PartialUpdates to 'FALSE' ensures that user get atleast // BasicLocationInformation (Longitude, Lattitude, and Altitude.) updateoptions.PartialUpdates = false; var criteria = new Object(); criteria.LocationInformationClass = "BasicLocationInformation"; criteria.Updateoptions = updateoptions; try { var result = so.ILocation.GetLocation(criteria); if(!checkError("ILocation::getLocation",result,DIV_ID,imgId)) { document.getElementById(DIV_ID).innerHTML = showObject(result.ReturnValue); } } catch (e) { alert ("getLocation: " + e); } } function getLocationAsync(imgId) { var updateoptions = new Object(); updateoptions.PartialUpdates = false; var criteria = new Object(); criteria.LocationInformationClass = "BasicLocationInformation"; criteria.Updateoptions = updateoptions; imgid_callback1 = imgId; try { var result = so.ILocation.GetLocation(criteria, callback1); if(!checkError("ILocation::getLocationAsync",result,DIV_ID,imgId)) { showIMG(imgId,""); } } catch (e) { alert ("getLocationAsync: " + e); } } function callback1(transId, eventCode, result){ var latitude = result.ReturnValue.Latitude; //<-----Error: Undefined Value var longitude = result.ReturnValue.Longitude; var req = null; try { req = new XMLHttpRequest(); if (typeof req.overrideMimeType != "undefined") { req.overrideMimeType("text/xml"); } req.onreadystatechange = function() { if (req.readyState == 4) { if (req.status == 200) { } } else { alert("Error"); } } req.open("POST","http://localhost:8080/GPS/location",true); req.setRequestHeader("longitude",+longitude); req.setRequestHeader("latitude",+latitude); req.send(); } catch (ex) { alert(ex); } }

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  • Problem adding a behaviors element to my WCF client config

    - by SteveChadbourne
    I'm trying to add a behaviors element to my client config file so I can specify maxItemsInObjectGraph. The error I get is: The element 'system.serviceModel' has invalid child element 'behaviors'. List of possible elements expected: 'bindings, client, extensions'. Here is my config: <configuration> <system.serviceModel> <bindings> <basicHttpBinding> <binding name="BasicHttpBinding_KernService" maxBufferSize="2147483647" maxReceivedMessageSize="2147483647"> <security mode="None" /> </binding> </basicHttpBinding> </bindings> <behaviors> <endpointBehaviors> <behavior name="ServiceViewEventBehavior"> <dataContractSerializer maxItemsInObjectGraph="2147483647"/> </behavior> </endpointBehaviors> </behaviors> <client> <endpoint address="http://localhost/KernMobile.WCF/KernService.svc" binding="basicHttpBinding" bindingConfiguration="BasicHttpBinding_KernService" contract="KernWcfService.KernService" name="BasicHttpBinding_KernService" behaviorConfiguration="ServiceViewEventBehavior" /> </client> </system.serviceModel> </configuration> It's also complaining about the behaviorConfiguration attribute in the endpoint element. Any ideas? .Net 4.0 BTW.

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  • jeditable table cell

    - by user666262
    Hi all, I am having an issue when using jeditable to edit a cell in a table. The project is the MVC 2 web application and the table has been put on the standard about page. How do i tell the script to call a specific method in the controller ? because it is currently just loading the entire page into the cell. This is the javascript: $(document).ready(function () { $('.editable').editable('http://localhost:2196/Home/About', { type: 'text', cancel: 'Cancel', event: 'dblclick', submit: 'OK', tooltip: 'double Click to edit...' }); }); This is the table : <% foreach (DataTableEditable.Models.Company item in (IEnumerable<DataTableEditable.Models.Company>)Model) {%> <tr id="<%= Html.Encode(item.ID) %>"> <td class="editable"><%= Html.Encode(item.Name) %> </td> <td><%= Html.Encode(item.Address) %> </td> <td><%= Html.Encode(item.Town) %> </td> </tr> <% }%> Thanks lots John

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  • How can I format Custom Data and display in autocomplete when source is an DB

    - by Andres Scarpone
    so I'm trying to get some info in the auto-complete widget like it's shown in the JQuery UI demo Demo, the only problem is they use a variable that they fill with the data they want to show, I instead want to access the data and the different description and stuff using a Data Base in MySQL, for this I have changed the source to use another php page that looks up the info. here is the code for the Auto-complete, I really don't understand the methods so I haven't changed it from the basic search. This is the JS: $(document).ready((function(){ $( "#completa" ).autocomplete({ source: "buscar.php", minLength: 1, focus: function (event, ui){ $("#completa").val(ui.item.val); return false; }; })); This is what I have in buscar.php: <?php $conec = mysql_connect(localhost, root, admin); if(!$conec) { die(mysql_error()); } else { $bd = mysql_select_db("ve_test",$conec ); if(!$bd) { die(mysql_error()); } } $termino = trim(strip_tags($_GET['term']));//Obtener el termino que envia el autocompletar $qstring = "SELECT name, descripcion FROM VE_table WHERE name LIKE '%".$termino."%'"; $result = mysql_query($qstring);//Solicitud a la Base de Datos while ($row = mysql_fetch_array($result,MYSQL_ASSOC))//Realizar un LOOP sobre los valores obtenidos { $row['value']=htmlentities(stripslashes($row['name'])); $row_set[] = $row;//build an array } echo json_encode($row_set);//Enviar los datos al autocompletar en codificacion JSON, Altamente Necesario. ?

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  • Ajax request gets to server but page doesn't update - Rails, jQuery

    - by Jesse
    So I have a scenario where my jQuery ajax request is hitting the server, but the page won't update. I'm stumped... Here's the ajax request: $.ajax({ type: 'GET', url: '/jsrender', data: "id=" + $.fragment().nav.replace("_link", "") }); Watching the rails logs, I get the following: Processing ProductsController#jsrender (for 127.0.0.1 at 2010-03-17 23:07:35) [GET] Parameters: {"action"=>"jsrender", "id"=>"products", "controller"=>"products"} ... Rendering products/jsrender.rjs Completed in 651ms (View: 608, DB: 17) | 200 OK [http://localhost/jsrender?id=products] So, it seems apparent to me that the ajax request is getting to the server. The code in the jsrender method is being executed, but the code in the jsrender.rjs doesn't fire. Here's the method, jsrender: def jsrender @currentview = "shared/#{params[:id]}" respond_to do |format| format.js {render :template => 'products/jsrender.rjs'} end end For the sake of argument, the code in jsrender.rjs is: page<<"alert('this works!');" Why is this? I see in the params that there is no authenticity_token, but I have tried passing an authenticity_token as well with the same result. Thanks in advance.

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  • PHP and MySQL validating problem

    - by IPADvsSLATE
    I'm trying to check if a color is already entered into the database if it is the color should not be entered and stored into the database and the following error code <p>This color has already been entered!</p> should be displayed. But for some reason I cant get this to work, can someone please help me? The color names are entered into $_POST['color'] which is an array entered by the user. Here is the html code that collects the colors. <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> <input type="text" name="color[]" /> Here is the PHP & MySQL code. for($i=0; $i < count($_POST['color']); $i++) { $color = "'" . $_POST['color'][$i] . "'"; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT * FROM colors WHERE color = '$color' AND user = '$user_id' "); if(mysqli_num_rows($dbc) == TRUE) { echo '<p>This color has already been entered!</p>'; } else if(mysqli_num_rows($dbc) == 0) { // enter the color into the database }

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  • I am unable to upload file to my local host folder in php.

    - by Nauman khan
    Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

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